'Correcting' Trenberth et al.

(See the note below before taking this post seriously – Anthony)

Guest essay by Steven Wilde

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Here we see the classic energy budget analysis supporting the hypothesis that the surface of the Earth is warmer than the S-B equation would predict due to 324 Wm2 of ‘Back Radiation’ from the atmosphere to the surface.

It is proposed that it is Back Radiation that lifts the surface temperature from 255K, as predicted by S-B, to the 288K actually observed because the 324 Back Radiation exceeds the surface radiation to the air of 222 Wm2 ( 390 Wm2 less 168 Wm2) by 102 Wm2. It is suggested that there is a net radiative flow from atmosphere to surface of 102 Wm2.

I now discuss an alternative possibility.

The portions I wish to focus on are:

i) 390 Wm2 Surface Radiation to atmosphere

ii) 78 Wm2 Evapo-transpiration surface to atmosphere

iii) 24 Thermals surface to atmosphere

iv) 324 Back Radiation atmosphere to surface

The budget needs to be amended as follows:

The 78 Wm2 needs to be corrected to zero because the moist adiabatic lapse rate during ascent is less than the dry lapse rate on adiabatic descent which ensures that after the first convective cycle there is as much energy back at the surface as before Evapo-transpiration began.

The 24 Wm2 for thermals needs to be corrected to zero because dry air that rises in thermals then warms back up to the original temperature on descent.

Therefore neither ii) nor iii) should be included in the radiative budget at all. They involve purely non radiative means of energy transfer and have no place in the radiative budget since, being net zero, they do not cool the surface. AGW theory and the Trenberth diagram incorrectly include them as a net surface cooling influence.

Furthermore, they cannot reduce Earth’s surface temperature below 255K because both conduction and convection are slower methods of energy transmission than radiation. To reduce the surface temperature below 255K they would have to work faster than radiation which is obviously not so.

They can only raise a surface temperature above the S-B expectation and for Earth that is 33K.

Once the first convective overturning cycle has been completed neither Thermals nor Evapo-transpiration can have any additional warming effect at the surface provided mass, gravity and insolation remain constant.

As regards iv) the correct figure for the radiative flux from atmosphere to surface should be 222 Wm2 because items ii) and iii) should not have been included.

That also leaves the surface to atmosphere radiative flux at 222 Wm2 which taken with the 168 Wm2 absorbed directly by the surface comes to the 390 Wm2 required for radiation from the surface.

The rest of the energy budget diagram appears to be correct.

So, how to decide whether my interpretation is accurate?

I think it is generally accepted that the lapse rate slope marks the points in the atmosphere where there is energy balance within molecules that are at the correct height for their temperature.

Since the lapse rate slope intersects with the surface it follows that DWIR equals UWIR for a zero net radiative balance if a molecule at the surface is at the correct temperature for its height. If it is not at the correct surface temperature it will simply move towards the correct height by virtue of density variations in the horizontal plane (convection).

Thus, 222 UWIR at the surface should equal 222 DWIR at the surface AND 222 plus 168 should add up to 390 and, of course, it does.

AGW theory erroneously assumes that Thermals and Evapo-transpiration have a net cooling effect on the surface and so they have to uplift the radiative exchange at the surface from 222 Wm2 to 324 Wm2 and additionally they assume that the extra 102 Wm2 is attributable to a net radiative flux towards the surface from the atmosphere.

The truth is that there is no net flow of radiation in any direction at the surface once the air at the surface is at its correct temperature for its height, which is 288K and not 255K. The lapse rate intersecting at the surface tells us that there can be no net radiative flux at the surface when surface temperature is at 288K.

A rise in surface temperature above the S-B prediction is inevitable for an atmosphere capable of conducting and convection because those two processes introduce a delay in the transmission of radiative energy through the system. Conduction and convection are a function of mass held within a gravity field.

Energy being used to hold up the weight of an atmosphere via conduction and convection is no longer available for radiation to space since energy cannot be in two places at once.

The greenhouse effect is therefore a product of atmospheric mass rather than radiative characteristics of constituent molecules as is clearly seen when the Trenberth diagram is corrected and the lapse rate considered.

Since one can never have more than 390 Wm2 at the surface without increasing conduction and convection via changes in mass, gravity or insolation a change in the quantity of GHGs cannot make any difference. All they can do is redistribute energy within the atmosphere.

There is a climate effect from the air circulation changes but, due to the tiny proportion of Earth’s atmospheric mass comprised of GHGs, too small to measure compared to natural variability.

What Happens When Radiative Gases Increase Or Decrease?

Applying the above correction to the Trenberth figures we can now see that 222 Wm2 radiation from the surface to the atmosphere is simply balanced by 222 Wm2 radiation from the atmosphere to the surface. That is the energy being constantly expended by the surface via conduction and convection to keep the weight of the atmosphere off the surface. We must ignore it for the purpose of energy transmission to space since the same energy cannot be in two places at once.

We then have 168 Wm2 left over at the surface which represents energy absorbed by the surface after 30 Wm2 has been reflected from the surface , 77 Wm2 has been reflected by the atmosphere and 67 Wm2 has been absorbed by the atmosphere before it reaches the surface.

That 168 Wm2 is then transferred to the atmosphere by conduction and convection leaving a total of 235 Wm2 in the atmosphere (168 plus 67).

It is that 235 Wm2 that must escape to space if radiative balance is to be maintained.

Now, remember that the lapse rate slope represents the positions in the atmosphere where molecules are at their correct temperature for their height.

At any given moment convection arranges that half the mass of the atmosphere is too warm for its height and half the mass is too cold for its height.

The reason for that is that the convective process runs out of energy to lift the atmosphere any higher against gravity when the two halves equalise.

It must follow that at any given time half of the GHGs must be too warm for their height and the other half too cold for their height.

That results in density differentials that cause the warm molecules to rise and the cold molecules to fall.

If a GHG molecule is too warm for its height then DWIR back to the surface dominates but the molecule rises away from the surface and cools until DWIR again equals UWIR.

If a GHG molecule is too cold for its height then UWIR to space dominates but the molecule then falls until DWIR again equals UWIR.

The net effect is that any potential for GHGs to warm or cool the surface is negated by the height changes relative to the slope of the adiabatic lapse rate.

Let’s now look at how that outgoing 235 Wm2 is dealt with if radiative gas concentrations change.

It is recognised that radiative gases tend to reduce the size of the Atmospheric Window (40 Wm2) so we will assume a reduction from 40 Wm2 to 35 Wm2 by way of example.

If that happens then DWIR for molecules that are too warm for their height will increase but the subsequent rise in height will cause the molecule to rise above its correct position along the lapse rate slope with UWIR to space increasing at the expense of DWIR back to the surface and rising will only stop when DWIR again equals UWIR.

Since UWIR to space increases to compensate for the shrinking of the atmospheric window (from 40 Wm2 to 35 Wm2) the figure for radiative emission from the atmosphere will increase from 165 to 170 which keeps the system in balance with 235 Wm2 still outgoing.

If the atmosphere had no radiative capability at all then radiative emission from the atmosphere would be zero but the Atmospheric Window would release 235 Wm2 from the surface.

If the atmosphere were 100% radiative then the Atmospheric Window from the surface would be zero and the atmosphere would radiate the entire 235 Wm2.

==============================================================

Note: I’m glad to see a number of people pointing out how flawed the argument is. Every once in awhile we need to take a look at the ‘Slayer’ mentality of thinking about radiative balance, just to keep sharp on the topic. At first I thought this should go straight into the hopper, and then I thought it might make some good target practice, so I published it without any caveat.

Readers did not disappoint.

Now you can watch the fun as they react over at PSI.  – Anthony

P.S. Readers might also enjoy my experiment on debunking the PSI light bulb experiment, and note the reactions in comments, entirely opposite to this one. New WUWT-TV segment: Slaying the ‘slayers’ with Watts

Update: Let me add that the author assuredly should have included a link to the underlying document, Earth’s Global Energy Budget by Kiehl and Trenberth …

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April 10, 2014 11:16 pm

The replies relating to clouds and water vapour and droplets don’t work for two reasons:
i) Their effect is already in the radiative figures as 30 to space and included in the 222 radiation to the surface.
ii) Latent heat is a form of potential energy just like PE so neither register on thermometers nor radiate. When latent heat is released it goes to the non radiative bulk atmosphere via conduction and cannot be released as radiation by non radative molecules so it goes quickly to PE. It can only be ‘recovered’ as heat energy on the next descent.
Curt said:
“(Hint: the atmosphere has already fallen to the ground.)”
Try telling that to every molecule that floats above the surface 🙂

April 10, 2014 11:29 pm

Curt said:
“The question is so nonsensical that it is impossible to answer. Potential energy does not radiate, substances radiate.”
So you agree with me ?
“And substances radiate as a function of their temperature and their emissivity at that temperature. Period. Earth’s atmosphere has radiatively active gases that do radiate significantly in all directions at their temperatures.”
Lifting a gaseous substance to height via an internal circulation requires work to be done as does moving it back down again. The energy required for that adiabatic process takes the form of gravitational potential energy and as I explained to Joel it cannot participate in the radiative exchange whilst in potential form.
K&T and the rest of the objectors here have worked the calculations on the basis that potential energy can participate in the radiative exchange.
You have admitted that it cannot by confirming that “Potential energy does not radiate, substances radiate.”
How does the K&T diagram deal with the fund of non radiative gravitational potential energy within the atmosphere?
It shows it as sending down 102 W m2 as extra DWIR magically produced from nowhere.
Checkmate ?
Eric Barnes gets it and by now I imagine that lots of other non contributors do as well.

John of Kent
April 11, 2014 1:49 am

Stephen Wilde is not as has never been a “Slayer”, more greenhouse propaganda from WUWT!

david(swuk)
April 11, 2014 3:38 am

Curt says:
April 10, 2014 at 6:26 pm
“coherent discussion”
……or peering into the darkness your adopted postures so permit more like……might one opine.
….and, as interesting as it might be poking around in that other World, what K-T et al is using to spin the Warmist Tale just gets chivvied around instead of being soundly challenged as a total load of Established Law-breaking tosh.
The bootlace-free twin-Sun postulation somewhere not far above surely debunks the candle and flame etc. fancifications and with it much of K-T interchanges of radiative energy which may well excite their brethren, including water vapour, until enough of it has found its way to Space to maintain the balance but not terra firma where it has warmer potential (or, perhaps, equal as with the twin Suns).
Otherwise I would surely expect to see clouds as diffusers (H.S?) of sunlight and not simple reflectors as they can be seen from below and can only but guess the Tren`s 67 represents the Solar IR absorbed thereby whilst the other ~half of it either bounces off the oceans surface or cuts through to warm the Core as 168 doesn`t seem enough to drive the climate to me.
But The World does need its boffins at levels below the eclectic as well and so the shakers and makers do have to see that they don`t go bumping into things that might hurt too bad as they burrow deep into the relevant Sciences and be ever ready to do a Rule of Thumb over their product before making any bid or spending money.- because, like lawyers, they seldom agree on exactly what is right.

April 11, 2014 4:31 am

Note: I’m glad to see a number of people pointing out how flawed the argument is. Every once in awhile we need to take a look at the ‘Slayer’ mentality of thinking about radiative balance, just to keep sharp on the topic. At first I thought this should go straight into the hopper, and then I thought it might make some good target practice, so I published it without any caveat.
Readers did not disappoint.
Now you can watch the fun as they react over at PSI. – Anthony

Uh, small question, since when is Stephen a Slayer?
He’s a talkshop regular, they don’t like Slayer stuff over there much either.

david(swuk)
April 11, 2014 8:25 am

david(swuk) says:
April 11, 2014 at 3:38 am
Curt says:
April 10, 2014 at 6:26 pm
“coherent discussion”
Oh – and I think I made it clear that I too was of the opinion that the Thermal issues resulted in carrying HEAT (not just wafty energy) to the higher atmosphere from where it can be self ejected into Space….it seems to me too that near Solar IR needs better attention.

Frank
April 11, 2014 11:24 am

Steve wrote: “There is still 102 Wm2 leaving the surface in adiabatic uplift and 102 Wm2 returning to the surface in adiabatic descent.”
When water evaporates from the surface and later condenses in the atmosphere, the heat of evaporation has been lost from the surface and gained by the atmosphere. The energy gained by the atmosphere makes it warmer. It doesn’t return only by adiabatic descent. The warmer air radiates in all directions (more than it would if it were cooler). Some of the radiated photons reach the surface as DLR, some escape to space, and some are absorbed. Being warmer, it will expand and possibly rise higher. ALL of these processes are represented on Trenberth’s diagram – it shows the energy balance for the surface AND the energy balance for the atmosphere. All fluxes are accounted for – you want to count some of them twice.
We can monitor the upwards and downwards radiation fluxes and identify their sources by wavelength: SWR, OLR, and DLR. Trenberth’s diagram shows all three of these separately. Sensible heat in the descending branch of the Hadley and Ferrell cells warms the subtropics and poles, while sensible heat is lost through their ascending branches. We can’t monitor sensible heat fluxes accurately, so Trenberth shows us only the NET FLUX produced by these upward and downward flows. It’s the same as combining surface upward radiation and DLR to produce a net upward LWR flux of 66 W/m2. The NET flux of sensible heat shown was chosen so that the surface is in equilibrium with the atmosphere – except for a tiny difference (less than 1 W/m2) that is warming the surface (mostly the ocean). In his latest diagram, the difference was chosen to agree with the increase in ocean heat content measure by Argo. If you like, replace Trenberth’s single arrow for upward flux of sensible heat with two arrows, one downward and one upward. We don’t have a good idea of how big either of those arrows are, but we know that the difference is about 24 W/m2. If it weren’t, the earth would be warming or cooling much more rapidly than it is. If future research showed that mean global DLR were 314 or 334 W/m2 instead of 324 W/m2, the value for NET sensible heat flux presumably would be changed to 34 or 14 W/m2.
Steve also wrote: “It may be comprised of ever changing parcels of energy as energy flows through and it may be incorporated within the general upward flow but it is still there and it raises surface temperature from 255K to 288K.”
Since about 90% of the photons escaping to space are emitted by the atmosphere, the atmosphere needs to be warm enough to emit OLR amounting to 90% of the SWR (239 W/m2) that is absorbed below the tropopause. Since 70% of incoming SWR reaches the surface, there needs to be a large flux of energy from the surface to the atmosphere. 288 degK happens to be the surface temperature where the NET upward flux of heat from the surface to the atmosphere (by a combination of radiation and convection) that keeps that atmosphere at the appropriate temperature (and provides 10% of OLR). The earth’s blackbody equivalent temperature (255 degK) ignores that the emissivity of the atmosphere is less than 1, the temperature gradient in the troposphere, and a number of other awkward problems. IMO, the 33 degK difference isn’t a sensible way to quantify of the greenhouse effect.

Kristian
April 11, 2014 12:17 pm

Frank says, April 11, 2014 at 11:24 am:
“When water evaporates from the surface and later condenses in the atmosphere, the heat of evaporation has been lost from the surface and gained by the atmosphere. The energy gained by the atmosphere makes it warmer. It doesn’t return only by adiabatic descent.”
What Stephen doesn’t seem to understand is the route the solar heat takes through the earth system (well, the devout believers in the ‘atmospheric radiative greenhouse effect’ doesn’t seem to get it either).
It is first (mostly) absorbed by the surface, warming it. From there it is released into the atmosphere (mostly) through convective processes (conduction/convection/evaporation), brought up towards the tropopause, warming the troposphere on its way. On the way (and mostly from the cloud/convection top) it is then released back out to space through radiation. It is trivial to follow this route in the available observational data from the real world: First surface temps change, then tropospheric temps, then OLR from ToA.
NO heat is globally radiated or convected/conducted back to the surface! It is simply IN and OUT. From hot to cold all the way. The atmosphere CANNOT make the surface (its heat source) warmer than what the sun makes it by transferring back (recycling) energy already emitted from it as thermal loss! This would violate both the 1st and the 2nd Laws of Thermodynamics.
How people don’t see this is a mystery to me …

Kristian
April 11, 2014 12:39 pm

I’ve already pointed out how Willis Eschenbach on this thread states the following:
“… but it doesn’t return energy to the surface, that would be a violation of the Second Law.”
He’s quite correct, of course. It’s a trivial point. Yet, when it comes to radiation, he’s perfectly willing to let energy previously emitted from the surface as thermal loss return from the atmosphere to warm it a second time. THEN it’s somehow ok. THEN it somehow doesn’t violate the 2nd (and the 1st) Law of Thermodynamic.
Go figure.

Curt
April 11, 2014 1:36 pm

Stephen, you say: “So you agree with me ?”
Absolutely not! You don’t even understand the arguments or even the terminology. No one is claiming that “potential energy radiates”, whatever that nonsense would possibly mean. That strawman is a product of your profound confusion.
I repeat what I said before: “Substances radiate as a function of their temperature and their emissivity at that temperature. Period. Earth’s atmosphere has radiatively active gases that do radiate significantly in all directions at their temperatures.”
Now, as gases rise, their temperature gets lower, and that affects how much they radiate, but how much they radiate is a function of the resultant temperature at any point and the emissivity of that temperature. It is simply not true that “K&T and the rest of the objectors here have worked the calculations on the basis that potential energy can participate in the radiative exchange.”
You also say, “Lifting a gaseous substance to height via an internal circulation requires work to be done as does moving it back down again. The energy required for that adiabatic process takes the form of gravitational potential energy and as I explained to Joel it cannot participate in the radiative exchange whilst in potential form.”
Now in this nonsensical statement, what I think you may be trying to say is that as the gas rises, some of the kinetic energy of the molecules is converted to gravitational potential energy, and therefore its temperature decreases, and that as the temperature decreases, it radiates less. No one is arguing otherwise (and certainly no one is arguing that “potential energy radiates” – that is a figment of your fevered imagination). But what you are missing is that the higher the gas is, the more of the energy is radiated to space, where it is lost to the cycle, instead of the nearby atmosphere, where it is not.
You continue to call the process adiabatic, no matter how many times people point out to you that it is not. Do you even understand what “adiabatic” means?
You ask, “How does the K&T diagram deal with the fund of non radiative gravitational potential energy within the atmosphere? It shows it as sending down 102 W m2 as extra DWIR magically produced from nowhere.”
The “fund” of gravitational potential energy in the atmosphere is fundamentally constant. Some parcels of air move up, some move down, but it all has to balance out. By the 102 W/m2 that you are asserting is “magically produced”, I believe you are referring to the net (78+42) upward of thermals and evapo-transpiration in the diagram, that you believe is unbalanced. But as has been explained to you multiple times, because of the radiatively active gases, energy is lost on the way up (past what is converted to gravitational potential energy), so that on the return down, it does not transfer as much energy back to the surface, so there is a net upward transfer from surface to atmosphere due to these mechanisms.
You ask, “Checkmate ?” Only in the sense that Charlie Sheen yells “Winner!”

Frank
April 11, 2014 3:16 pm

Trick said (April 10, 2014 at 12:40 pm)
“Correct; the graphs show real bodies reflect some of the incident photonic energy unlike a theoretical black body which doesn’t reflect at all. Planck function posted above 4/9 12:57pm is never 0.0, so radiation is emitted by all bodies regardless of temperature, although to varying degrees at different frequencies.
The part of the incident photonic energy not reflected is absorbed/emitted in a hemisphere of directions is occurring in nature by Planck function at all frequencies all the time at all equilibrium temperatures for solid/liquid/gas – no hedging here “all” means ALL – no exceptions, the integral of which across the spectrum is the irradiance.”
Trick, the physics you cite isn’t adequate for describing all of the interactions between radiation and matter, including gases. You need to go deeper into the real physics, not just apply laws work to special situations. Unfortunately, the complete physics isn’t taught in many courses.
For solid objects, we usually assess the radiation they absorb by measuring the radiation they reflect/scatter. For visible wavelengths, it is easy to measure what solids scatter; just take a color picture. If you are interested in infrared wavelengths, it is a non-trivial task to discriminate between the infrared radiation emitted by the solid object itself, the equipment being used to detect radiation and the rest of the surroundings. (Night vision glasses detect the increase in radiation with temperature and work best identifying warm people against a cold sky.) It is even more difficult to study the infrared emission from gases.
However, we can learn about the radiation EMITTED by a gas by studying the radiation ABSORBED by a gas. A single absorption “cross-section” or coefficient (for each wavelength) determines how much radiation is absorbed AND emitted (at that wavelength). Unlike solids, it is trivial to study absorption by shining infrared radiation through a gas. By using an infrared light source with a 4000 degK filament, we can overwhelm the much weaker radiation emitted by the gas and its surroundings in the lab, and measure absorption without interference from emission. So infrared spectra of gases are a convenient way to learn about their emission spectra. The absorption spectra of gases are INCOMPATIBLE with the idea they always emit blackbody radiation.
A more complete picture: The following equations refer to radiation at a single wavelength, so I don’t have to type a subscript lamba on every term. To obtain total intensity, you need to integrate these eqns over all wavelengths. Written in differential form the radiation ABSORBED (lost) by a gas (dI_a) as it passes an incremental distance (ds) through a gas is given by:
dI_a/ds = n*o*I_0
where n is the density of absorbing molecules in the path, o is the absorption cross-section or absorption coefficient for that wavelength, and I_0 is the intensity of the incoming light. Integrating this equation gives Beers Law for the intensity of light (I) passing through a distance s. I/I_0 = exp(-nos)
The radiation EMITED by the gas molecules (dI_e) along an incremental distance (ds) is given by:
dI_e/ds = n*o*B(T)
where B(T) is the Planck function for that temperature and wavelength, and the same o is used for both absorption and emission. B(T) sometimes refers to light emitted in all directions (per unit solid angle), but it can be converted to intensity normal to a plane and moving in both directions. We use the flux perpendicular to a surface for simple problems. If you combine these two equations, you get the Schwarzschild eqn, which describes how radiation changes (dI) upon passing an incremental distance (ds) through a gas:
dI/ds = dI_e/ds – dI_a/ds = n*o*{ B(T) – I_0 }
When radiation passes though a homogenous gas FAR ENOUGH so that emission and absorption have come into equilibrium, then dI/ds = 0 and I_0 = B(T). The intensity of the light will be that of a Blackbody at temperature T – IF the absorption coefficient is NOT ZERO. If the absorption coefficient is zero, the gas is TRANSPARENT at that wavelength, doesn’t change the intensity of the radiation passing through it, and certainly doesn’t emit at that wavelength. The absorption cross-section o tells you how rapidly with distance the intensity of radiation approaches blackbody intensity for a given density of absorbing/emitting molecules (GHG’s). The more absorbing/emitting molecules there are and the bigger their cross-section, the more likely it will be that the radiation leaving a gas will be nearly blackbody. At transparent wavelengths, however, any light coming out of the gas must have originated from BEHIND the gas (the surface of the earth, empty space = afterglow from the big bang, the sun, etc). Note that the Planck function (B(lamba,T)) is built into the Schwarzschild equation, so that blackbody radiation will be produced whenever emission and absorption have come into equilibrium. In the absence of equilibrium, the radiation will not exhibit blackbody intensity. Black boxes with a tiny pinhole in them were first used to study blackbody radiation – neat devices for emitting radiation with absorption and emission in equilibrium.
If you accept that radiation travels through solids and liquids and obeys the Schwarzschild eqn, then solids and liquids emit blackbody radiation for exactly the same reasons that a gas does – emission and absorbing have come into equilibrium by the time the radiation leaves the surface. Being much denser than gases, solids and liquids don’t have to be very thick for their internal radiation to reach equilibrium before exiting the surface, but thin films of solids and liquids do not emit blackbody radiation! (The thin coatings on low emissivity glass work because they don’t emit blackbody radiation.) Just like gases, solids and liquids are transparent at wavelengths they don’t absorb. Transparent objects don’t emit blackbody radiation – that is why they aren’t black. When radiation exiting a solid is scattered or reflected back into the solid by the surface, then that surface has an emissivity less than 1. Radiation traveling into a solid or liquid can also be scattered/reflected; producing absorptivity less than 1. Absorptivity = emissivity.
Planck’s Law and the S-B law are special cases that can be derived from the Schwarzschild eqn assuming that the absorption and emission have reached equilibrium before radiation leaves
When scientists want to know how radiation changes as it passes through the atmosphere (which changes composition, density and temperature with altitude), they numerically integrate the Schwarzschild equation over distance and wavelength, and that process radiation transfer (equations). When the B(T) term – emitted in all directions is converted to a flux perpendicular to the earth’s surface, surface upward radiation acquires two components, OLR and DLR, from emission.

Frank
April 11, 2014 3:27 pm

Kristian: Individual molecules and photons appear “violate” the 2LoT all of the time through collisions, absorption and emission. Individual molecules and photons have kinetic energy (or E = hv), but they don’t have a temperature – a mean kinetic energy. Temperature is a concept that applies to large groups of frequently-colliding molecules. Statistical mechanics has shown that heat will always flow from the hotter group to the colder group even though some slower-moving molecules collide and transfer kinetic energy to faster-moving molecules. Warmer gases emit more photons that cooler gases, but some photons go from cold to hot. Only the NET flux is from hot to cold.

Max
April 11, 2014 4:37 pm

Small correction, Stephen Wilde is not a Slayer, he posts over at the talkshop and they aren’t big on Slayer type stuff either.
Nor are the Connollys associated with them.

Kristian
April 11, 2014 4:45 pm

Frank says, April 11, 2014 at 3:27 pm:
But Frank, this is not the issue. The whole ‘heating by back radiation’ concept rests upon HEAT moving ALSO from cold to hot. Only HEAT (and work) can directly raise the temperature of (increase the internal energy of) a system. It is by ADDING ‘extra’ energy (energy that was previously emitted from hot to cold as thermal loss) that earth’s surface temperature allegedly rises, NOT by obstructing energy from leaving (being emitted from) the surface. This is per definition direct heating, whatever you choose to CALL it.

joeldshore
April 11, 2014 5:50 pm

Kristian says:

But Frank, this is not the issue. The whole ‘heating by back radiation’ concept rests upon HEAT moving ALSO from cold to hot.

No, it doesn’t. It rests on the concept that the steady-state temperature of an object is determined by the balance between what it absorbs and what it emits, something that is only controversial among the scientifically-ignorant.

Trick
April 11, 2014 6:26 pm

Frank 3:16pm: “Trick, the physics you cite isn’t adequate for describing all of the interactions between radiation and matter, including gases.”
Concur, I will expand little more w/o try teaching or editor (per Curt); a whole text book can be written on the interactions of radiation & matter. Nice work though Frank, fun talking some actual text book physics for once – usually if go in too deep lose many readers like Stephen who won’t consult a text just consults his imagination. Thanks for not using the word “heat” in confusion like Kristian does.
Emission is the birth of a photon, absorption is photon death and reflection/scattering is the life of a photon. Scattering is not a transformation of radiant energy into other forms but rather into different directions; radiant energy is always conserved as it is absorbed into the L&O earth surface from whatever indistinguishable source (atm., sun, bird, cabbage).
Here is a short list of what Stephen misses in these processes per Bohren 2006:
“What once was, and perhaps still is, the standard treatise on atomic spectra, by Condon and Shortley, fills 432 pages of text. Herzberg’s treatises fill 581 pages for diatomic molecules, 538 pages for polyatomic molecules, and 670 pages for the electronic spectra of polyatomic molecules. Townes and Schawlow devote 648 pages to microwave spectroscopy. And the physical strain of just lifting these nearly 3000 pages is as nothing compared to the mental strain of absorbing them”… as Stephen often writes he hasn’t read a one since the early ’60s.
Think it was R.Feynman said something like “Nobody understands all that”.
Real matter continuously emits & absorbs radiation. All wavelengths, all the time, at all temperatures as entropy can not remain constant in nature. I often see around here that bodies are “heated” – about “heat” radiation (no such thing) or “heat rises”, just drop “heat” as a noun (as Frank does) and reduce confusion. Maxwell would have been more clear with the “Theory of Energy” and Planck with “Theory of Radiation”. Cold bodies radiate too, even when bodies are cooled they radiate. Blackbody radiation existence does not hinge on the existence of a blackbody. Real bodies (large compared with the wavelength) are characterized by (dimensionless) absorptivities less than or equal to 1.
“In general, the absorptivity (and hence emissivity) of a body depends on the direction and state of polarization of the incident radiation as well as its frequency, caveats often omitted. We would not have to worry about this if all bodies were always illuminated by blackbody radiation (unpolarized and isotropic). But alas, this is not true, and real bodies when removed from cavities are illuminated by radiation that usually is not the same in all directions and may be partially polarized.”
“Just like gases, solids and liquids are transparent at wavelengths they don’t absorb.”
Here Frank in part confuses real objects with ideal black or ideal transparent bodies:
No real object is transparent (absorptivity=0.0) at any wavelength at any time at any temperature – only ideal objects can be transparent in theory (entropy constant) since all real processes increase entropy, again: “All matter – gaseous, liquid, or solid – at all temperatures emits radiation of all frequencies at all times, although in varying amounts, possibly so small at some frequencies, for some materials, and at some temperatures as to be undetectable with today’s instruments (tomorrow’s, who knows?).” Bohren 2006 p. 4 right up front.
”…Planck’s Law and the S-B law are special cases that can be derived from the Schwarzschild eqn.”
No. Planck’s distribution function is fundamental, it is contained IN the Schwarzschild eqn. for the transmission of radiation of a particular frequency through an absorbing medium.
”…we usually assess the radiation they absorb by measuring the radiation they reflect/scatter.”
A mirror illuminated by an incident beam gives rise to a reflected beam. Is this reflected beam redirected incident photons? Alas, we cannot do an experiment to answer this question. To determine if reflected photons are measured the same as incident photons would require us to be able to identify them. But photons are indistinguishable. We cannot tell one from another. We cannot tag a photon with GPS and follow its life line progress like a bird.
Thus if you want to believe that you measure reflected photons being the same as incident photons, you may do so. No one can prove you wrong. But you cannot prove you are right. When faced with an un-decidable proposition, you may believe whatever you wish just like Stephen top post & Kristian 4:45pm: “The whole ‘heating by back radiation’ concept rests upon HEAT moving…” No. How can anyone identify a heat photon was over there to know the photon moved over here? Can’t. So Kristian can believe what he wishes.
Note that in the wave language we would not likely even ask if the reflected wave is the same as the incident wave. Kristian should learn to write his thoughts w/o using the “heat” word to reduce & in some cases eliminate confusion as Frank does.

joeldshore
April 11, 2014 7:32 pm

Curt says:

Now in this nonsensical statement, what I think you may be trying to say is that as the gas rises, some of the kinetic energy of the molecules is converted to gravitational potential energy, and therefore its temperature decreases, and that as the temperature decreases, it radiates less. No one is arguing otherwise

Actually, I would argue otherwise. There are serious problems with this viewpoint:
(1) It ignores the fact that the buoyant force is doing positive work on the gas as it rises. So, for example, if the parcel of gas is neutrally buoyant, then no, there won’t be any loss of the kinetic energy of the molecules because of an increase in gravitational potential energy, i.e., the negative work that the gravitational force does on the parcel will be exactly offset by the positive work that the buoyant force does on the parcel.
(2) The reasons parcels cool when they rise in the atmosphere (even on timescales where we can see the process is adiabatic, i.e., ignoring any loses of heat to radiation) is that the gas expands as it rises and this means the gas parcel is doing work on its surroundings.
This distinction might seem nitpicky, but I think it is actually quite important. Stephen’s misunderstanding leads to a lot of nonsense, such as the incorrect notion that the equilibrium state of a gas in a gravitational field is not isothermal and to an idea that the adiabatic lapse rate is some sort of natural state of the system, rather than the truth which is that it is a stability limit.
I.e., much of the atmosphere ends up with a lapse rate close to the adiabatic lapse rate because the solution to the problem of purely radiative equilibrium would lead to even larger lapse rates, which are unstable to convection and it is convection that drives the environmental lapse rate down to the appropriate (dry or saturated) adiabatic lapse rate. And, of course, it does so by transporting energy up in the atmosphere.

Kristian
April 12, 2014 6:36 am

joeldshore says, April 11, 2014 at 5:50 pm:
“No, it doesn’t. It rests on the concept that the steady-state temperature of an object is determined by the balance between what it absorbs and what it emits, something that is only controversial among the scientifically-ignorant.”
No, Joel. The steady-state temperature of a real-world object is determined by how much energy has been accumulated at/below its surface upon balance between incoming and outgoing energy. The instantaneous fluxes themselves do not set the steady-state temperature. The steady-state internal energy of the object does.
Atmospheric IR is not incoming energy for the surface. It is not an extra input of energy. An input of energy to a system (like the surface) would come from its heat reservoir (like the sun), not its cold sink (like the atmosphere). The atmospheric energy came from the surface in the first place (an input), warming the atmosphere. It has only one way to go from there: towards colder, ultimately to space.
If you want to return (recycle) this previously thermally ejected energy to the surface ejecting it, the heat source of the atmosphere, to raise its temperature a second time, then you are relying on a concept where HEAT is also going separately/independently from cold to hot, an impossible situation in nature. I know you would never admit to this, because you know it violates all thermodynamic laws. But that is what you’re in fact doing.

Trick
April 12, 2014 6:52 am

Kristian 6:36am: “Atmospheric IR is not incoming energy for the surface.”
In your view, what happens (in basic science terms) to the incoming energy at the incoming terrestrial photon’s death upon being annihilated at the surface?

joeldshore
April 12, 2014 7:14 am

As Kristian has well demonstrated, if you just rewrite the laws of physics to suit your prejudices, then you can believe anything you want to and remain safely behind your own self-imposed veil of ignorance.

Kristian
April 12, 2014 9:29 am

joeldshore says, April 12, 2014 at 7:14 am:
“As Kristian has well demonstrated, if you just rewrite the laws of physics to suit your prejudices, then you can believe anything you want to and remain safely behind your own self-imposed veil of ignorance.”
Yes, that’s a good summary of how you and your kind operate, Joel. Rewriting the laws of physics, that’s what you do best, after all. As I’ve demonstrated.

Kristian
April 12, 2014 9:34 am

Trick says, April 12, 2014 at 6:52 am:
“In your view, what happens (in basic science terms) to the incoming energy at the incoming terrestrial photon’s death upon being annihilated at the surface?”
What ‘incoming’ energy? The incoming energy comes from the sun. This energy then goes OUT from the surface to the atmosphere as thermal loss, because of the former (hot reservoir) being warmer than the latter (cold reservoir). As described by the radiative heat transfer equation. There is no extra energy input from the cooler atmosphere to the warmer surface. You’re double counting the energy.

Frank
April 12, 2014 9:54 am

Thanks for the reply, Trick. We are now mostly in agreement. In the real world, o may always be slightly greater than zero. Lines are broadened by collisions and the Doppler effect. However, from a practical point of view, n*o can be effectively zero. You might need a spectrophotometer with a path length of a hundred meters to measure effectively zero absorption (say by pure nitrogen gas) accurately enough to be sure that nitrogen absorption/emission is low enough at a particular wavelength to not be changed significantly passing through our atmosphere. However, one paper I read used an experimental set up that reflect the beam enough times to produce a 193 m path length through a gas at low pressure to create conditions similar to the stratosphere. It think the spectral data we have is accurate enough to do a decent job modeling radiation passing through our atmosphere, but there may be some controversy about line shape distant from the center of very strong bands.
What happens when molten glass is heated hot enough to emit visible light? Does it emit light of blackbody intensity or not emit at all because it is transparent? Sodium glass emits a bright yellow light that requires glass blowers to wear special goggle that filter out the yellow. That doesn’t sound like blackbody radiation. Hot borosilicate glass doesn’t emit that yellow light. In the ideal world, I’d find a picture of borosilicate glass emitting very little light being held by a pair of tongs that were glowing red hot; “proof” that visibly transparent materials don’t emit blackbody radiation at several thousand degrees. In reality, most pictures show hot glass being dull red. When a glass begins to melt, some of the covalent bonds are breaking, thereby changing the optical properties of the material.
People keep making mistakes about the emission from gases because they think Planck and S-B are fundamental laws that applies to everything. Even when corrected for emissivity, they provide the correct answer for radiation leaving an object ONLY when absorption and emission have come into equilibrium. The Schwarzschild eqn is correct for all situations and Planck’s law can be derived from it. The Planck function B(T) is essential to both.

Bart
April 12, 2014 11:46 am

Kristian says:
April 12, 2014 at 9:34 am
“There is no extra energy input from the cooler atmosphere to the warmer surface.”
This is such an elementary mischaracterization which causes so much unwarrented confusion. It is not your fault, but the fault of those who use such sloppy language.
The atmosphere does not produce “energy”. Energy is an absolute quantity which can be neither created nor destroyed, merely converted from one form to another. What we are talking about here is flows of energy per unit of time, which is power.
The GHGs in the atmosphere do not heat the surface. The Sun does that. Every second it shines upon the Earth, it is heating it. How hot the Earth’s surface gets depends on how efficiently it can rid itself of one batch of solar powered heat before the next batch of solar radiation comes in.
The GHGs impede the outward transport of that heat through radiation. Enough that, all things being equal, the surface temperature would rise until it reached a level to overcome the impedance of the GHGs.
It is analogous to putting a dam across a stream. The dam does not create water. It simply impedes the flow so that the water pools up behind it until it can flow over the top. Increase the height of the dam, and the depth of the water behind it increases, until it can spill over the top again.
At least, that would be the case if there were no other means of transferring heat to the GHGs than radiation.
But, that is not the case. Atmospheric convection also transfers heat to the GHGs, so that it can be radiated away into space. It is like having a spillway beside the dam which prevents the water from overflowing the top of the dam in the first place. You can build the dam higher, but the spillway is still going to keep the flow going just as it was before, and the extra height of the dam has no effect.
That is the point I have made in preceding comments on this page. I believe it is why we currently observe essentially no surface temperature to CO2 concentration sensitivity at all.

Editor
April 12, 2014 12:07 pm

Lawrence13 says:
April 10, 2014 at 1:19 pm

Willis Eschenbach says

“In short, Anthony just published the piece, and did nothing else. He did nothing blameworthy at all … and in any case, blaming the publisher when a newly launched scientific post goes hard aground on a reef of ugly facts is merely an attempt to divert attention from the wreck.”

I don’t agree with that at all. If Anthony had said I’ll feature your article but be warned I myself will call it a load of ld B0^&ocks for starters and I’m sure other replies will be less forgiving; then if Stephen still went ahead well he couldn’t complain.

If Stephen didn’t know what Anthony would think about his piece, he’s an idiot … and whatever Stephen is, he is far from an idiot.
It seems that what you are proposing is that before Anthony publishes any piece, he should warn the author in advance as to what he (Anthony) might say about the piece … he doesn’t do that with me, why should he do that with anyone?
Anthony in the past has disagreed very strongly with my position. Did he tell me that before he published my piece? Heck, no. THAT’S NOT HIS JOB. This is science. He just posts up pieces, and then sometimes comments on them himself. So what?

Anyway Willis are you and Roy Spencer talking again and that was only one persons criticism and you were seemingly mortally wounded.

I was not “mortally wounded”. I was falsely accused of plagiarism. Roy and I are still friends. What does that have to do with this situation?

No it could have been handled far better . This thread is now about two issues the scientific argument and the dreadful behaviour on many now trying to look like scientist-well 3% of scientist.

My goodness, we’re back to the “97% consensus”? Really? And in fact, only a few of the comments have been about how this was handled. Most of the discussion has been about the science, or more accurately, Stephan Wilde’s lack thereof …

Sorry Anthony and Willis but I found this disturbingly cruel

Look, Laurence13, you’re just an anonymous “concern troll”. I never believe someone like you who is bitching and moaning on behalf of someone who is perfectly capable of defending themself. Stephen responded to me above. He said he would have preferred if Anthony warned him that he (Anthony) was going to disagree … and heck, I’d prefer it too but THAT’S NOT HIS JOB.
The sad truth is that science is a blood sport. You put your heart-felt truths and your research out on the table, hand around the sledgehammers, and see if someone can destroy it. Stephen seems to understand that perfectly, as does anyone involved in science. It’s not a game for wimps, people are trying to cut up and destroy someone else’s precious scientific work.
So you clutching your pearls and complaining that it looks like an abattoir around here doesn’t bring tears of compassion to my eyes for poor Stephen. He’s a grown man, he doesn’t need you to whimper on his behalf.
w.

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