Guest Post by Willis Eschenbach
Since at least the days of Da Vinci, people have been fascinated by perpetual motion machines. One such “perpetuum mobile” designed around the time of the civil war is shown below. It wasn’t until the development of the science of thermodynamics that it could be proven that all such mechanisms are impossible. For such machines to work, they’d have to create energy, and energy cannot be either created or destroyed, only transformed.
I bring this up for a curious reason. I was reading the Jelbring hypothesis this afternoon, which claims that greenhouse gases (GHGs) are not the cause of the warming of the earth above the theoretical temperature it would have without an atmosphere. Jelbring’s hypothesis is one of several “gravito-thermal” theories which say the heating of the planet comes from gravity rather than (or in some theories in addition to) the greenhouse effect. His thought experiment is a planet with an atmosphere. The planet is isolated from the universe by an impervious thermally insulating shell that completely surrounds it, and which prevents any energy exchange with the universe outside. Inside the shell, Jelbring says that gravity makes the upper atmosphere colder and the lower atmosphere warmer. Back around 2004, I had a long discussion on the “climateskeptics” mailing list with Hans Jelbring. I said then that his theory was nothing but a perpetual motion machine, but at the time I didn’t understand why his theory was wrong. Now I do.
Dr. Robert Brown has an fascinating post on WUWT called “Earth’s baseline black-body model – a damn hard problem“. On that thread, I had said that I thought that if there was air in a tall container in a gravity field, the temperature of the air would be highest at the bottom, and lowest at the top. I said that I thought it would follow the “dry adiabatic lapse rate”, the rate at which the temperature of dry air drops with altitude in the earth’s atmosphere.
Dr. Brown said no. He said that at equilibrium, a tall container of air in a gravity field would be the same temperature everywhere—in other words, isothermal.
I couldn’t understand why. I asked Dr. Brown the following question:
Thanks, Robert, With great trepidation, I must disagree with you.
Consider a gas in a kilometre-tall sealed container. You say it will have no lapse rate, so suppose (per your assumption) that it starts out at an even temperature top to bottom.
Now, consider a collision between two of the gas molecules that knocks one molecule straight upwards, and the other straight downwards. The molecule going downwards will accelerate due to gravity, while the one going upwards will slow due to gravity. So the upper one will have less kinetic energy, and the lower one will have more kinetic energy.
After a million such collisions, are you really claiming that the average kinetic energy of the molecules at the top and the bottom of the tall container are going to be the same?
I say no. I say after a million collisions the molecules will sort themselves so that the TOTAL energy at the top and bottom of the container will be the same. In other words, it is the action of gravity on the molecules themselves that creates the lapse rate.
Dr. Brown gave an answer that I couldn’t wrap my head around, and he recommended that I study the excellent paper of Caballero for further insight. Caballero discusses the question in Section 2.17. Thanks to Dr. Browns answer plus Caballero, I finally got the answer to my question. I wrote to Dr. Brown on his thread as follows:
Dr. Brown, thank you so much. After following your suggestion and after much beating of my head against Caballero, I finally got it.
At equilibrium, as you stated, the temperature is indeed uniform. I was totally wrong to state it followed the dry adiabatic lapse rate.
I had asked the following question:
Now, consider a collision between two of the gas molecules that knocks one molecule straight upwards, and the other straight downwards. The molecule going downwards will accelerate due to gravity, while the one going upwards will slow due to gravity. So the upper one will have less kinetic energy, and the lower one will have more kinetic energy.
After a million such collisions, are you really claiming that the average kinetic energy of the molecules at the top and the bottom of the tall container are going to be the same?
What I failed to consider is that there are fewer molecules at altitude because the pressure is lower. When the temperature is uniform from top to bottom, the individual molecules at the top have more total energy (KE + PE) than those at the bottom. I said that led to an uneven distribution in the total energy.
But by exactly the same measure, there are fewer molecules at the top than at the bottom. As a result, the isothermal situation does in fact have the energy evenly distributed. More total energy per molecules times fewer molecules at the top exactly equals less energy per molecule times more molecules at the bottom. Very neat.
Finally, before I posted my reply, Dr. Brown had answered a second time and I hadn’t seen it. His answer follows a very different (and interesting) logical argument to arrive at the same answer. He said in part:
Imagine a plane surface in the gas. In a thin slice of the gas right above the surface, the molecules have some temperature. Right below it, they have some other temperature. Let’s imagine the gas to be monoatomic (no loss of generality) and ideal (ditto). In each layer, the gravitational potential energy is constant. Bear in mind that only changes in potential energy are associated with changes in kinetic energy (work energy theorem), and that temperature only describes the average internal kinetic energy in the gas.
Here’s the tricky part. In equilibrium, the density of the upper and lower layers, while not equal, cannot vary. Right? Which means that however many molecules move from the lower slice to the upper slice, exactly the same number of molecules must move from the upper slice to the lower slice. They have to have exactly the same velocity distribution moving in either direction. If the molecules below had a higher temperature, they’d have a different MB [Maxwell-Boltzmann] distribution, with more molecules moving faster. Some of those faster moving molecules would have the right trajectory to rise to the interface (slowing, sure) and carry energy from the lower slice to the upper. The upper slice (lower temperature) has fewer molecules moving faster — the entire MB distribution is shifted to the left a bit. There are therefore fewer molecules that move the other way at the speeds that the molecules from the lower slice deliver (allowing for gravity). This increases the number of fast moving molecules in the upper slice and decreases it in the lower slice until the MB distributions are the same in the two slices and one accomplishes detailed balance across the interface. On average, just as many molecules move up, with exactly the same velocity/kinetic energy profile, as move down, with zero energy transport, zero mass transport, and zero alteration of the MB profiles above and below, only when the two slices have the same temperature. Otherwise heat will flow from the hotter (right-shifted MB distribution) to the colder (left-shifted MB distribution) slice until the temperatures are equal.
It’s an interesting argument. Here’s my elevator speech version.
• Suppose we have an isolated container of air which is warmer at the bottom and cooler at the top. Any random movement of air from above to below a horizontal slice through the container must be matched by an equal amount going the other way.
• On average, that exchange equalizes temperature, moving slightly warmer air up and slightly cooler air down.
• Eventually this gradual exchange must lead to an isothermal condition.
I encourage people to read the rest of his comment.
Now, I see where I went wrong. Following the logic of my question to Dr. Brown, I incorrectly thought the final equilibrium arrangement would be where the average energy per molecule was evenly spread out from top to bottom, with the molecules having the same average total energy everywhere. This leads to warmer temperature at the bottom and colder temperature at elevation. Instead, at thermal equilibrium, the average energy per volume is the same from top to bottom, with every cubic metre having the same total energy. To do that, the gas needs to be isothermal, with the same temperature in every part.
Yesterday, I read the Jelbring hypothesis again. As I was reading it, I wondered by what logic Jelbring had come to the conclusion that the atmosphere would not be isothermal. I noticed the following sentence in Section 2.2 C (emphasis mine):
The energy content in the model atmosphere is fixed and constant since no energy can enter or leave the closed space. Nature will redistribute the contained atmospheric energy (using both convective and radiative processes) until each molecule, in an average sense, will have the same total energy. In this situation the atmosphere has reached energetic equilibrium.
He goes on to describe the atmosphere in that situation as taking up the dry adiabatic lapse rate temperature profile, warm on the bottom, cold on top. I had to laugh. Jelbring made the exact same dang mistake I made. He thinks total energy evenly distributed per molecule is the final state of energetic equilibrium, whereas the equilibrium state is when the energy is evenly distributed per volume and not per molecule. This is the isothermal state. In Jelbrings thought experiment, contrary to what he claims, the entire atmosphere of the planet would end up at the same temperature.
In any case, there’s another way to show that the Jelbring hypothesis violates conservation of energy. Again it is a proof by contradiction, and it is the same argument that I presented to Jelbring years ago. At that time, I couldn’t say why his “gravito-thermal” hypothesis didn’t work … but I knew that it couldn’t work. Now, I can see why, for the reasons adduced above. In addition, in his thread Dr. Brown independently used the same argument in his discussion of the Jelbring hypothesis. The proof by contradiction goes like this:
Suppose Jelbring is right, and the temperature in the atmosphere inside the shell is warmer at the bottom and cooler at the top. Then the people living in the stygian darkness inside that impervious shell could use that temperature difference to drive a heat engine. Power from the heat engine could light up the dark, and provide electricity for cities and farms. The good news for perpetual motion fans is that as fast as the operation of the heat engine would warm the upper atmosphere and cool the lower atmosphere, gravity would re-arrange the molecules once again so the prior temperature profile would be restored, warm on the bottom and cold on the top, and the machine would produce light for the good citizens of Stygia … forever.
As this is a clear violation of conservation of energy, the proof by contradiction that the Jelbring hypothesis violates the conservation of energy is complete.
Let me close by giving my elevator speech about the Jelbring hypothesis. Hans vigorously argues that no such speech is possible, saying
There certainly are no “Elevator version” of my paper which is based on first principal physics. It means that what I have written is either true or false. There is nothing inbetween.
Another “gravito-thermal” theorist, Ned Nikolov, says the same thing:
About the ‘elevator speech’ – that was given in our first paper! However, you apparently did not get it. So, it will take far more explanation to convey the basic idea, which we will try to do in Part 2 of our reply.
I don’t have an elevator speech for the Nikolov & Zeller theory (here, rebuttal here) yet, because I can’t understand it. My elevator speech for the Jelbring hypothesis, however, goes like this:
• If left undisturbed in a gravity field, a tall container of air will stratify vertically, with the coolest air at the top and the warmest air at the bottom.
• This also is happening with the Earth’s atmosphere.
• Since the top of the atmosphere cannot be below a certain temperature, and the lower atmosphere must be a certain amount warmer than the upper, this warms the lower atmosphere and thus the planetary surface to a much higher temperature than it would be in the absence of the atmosphere.
• This is the cause of what we erroneously refer to as the “greenhouse effect”
Now, was that so hard? It may not be the best, I’m happy to have someone improve on it, but it covers all the main points. The claim that “gravito-thermal” theories are too complex for a simple “elevator speech” explanation doesn’t hold water.
But you can see why such an elevator speech is like garlic to a vampire, it is anathema to the “gravito-thermal” theorists—it makes spotting their mistakes far too easy.
w.

Willis (or Dr Brown) the case for the isothermal cylinder seems to be fairly well established.
But on Earth, any given area on the surface has a conical section of atmosphere above it, and by my sums, I’d expect that if you have 15C at the surface, you’d expect to see about 13C at 15km simply due to the larger volume.
Not sure this has any implications for the overall argument or not.
Rob said, “(1) Were there is no greenhouse effect, the lapse rate in a planetary atmosphere would be isothermal (i.e., temperature would not change with height. In this case, the dry adiabatic lapse rate would be unchanged from its present value, but it would be completely irrelevant to the interpretation of the observed lapse rate.”
That is not entirely true. The lapse rate would attempt to approach isothermal. Even without “greenhouse effects” there is conductive heat transfer. The viscosity of the lower atmosphere would increase to improve conductive heat transfer reducing convection. Gravity would limit the amount of energy that could be contained in the atmosphere. The energy of the upper most molecules in steady state would be less than gravity imposes for the escape velocity of the planet. This is another, “all things being equal” example.
“(2) Greenhouse gas concentrations have no effect on the adiabatic lapse rate in the lower “convective” layer, but they determine the depth of that layer: increasing greenhouse gases increases the surface temperature of the planet not by changing the lapse rate, but by deepening the convective layer. “.
Another all things being equal example. “Greenhouse Gases” have differing thermal conductive properties, molecular weights and heat capacities. The “mix” in a mixed gases environment has more than just radiant effects.
Conductivity is generally assumed negligible in radiant atmospheric physics. The possibility that it is not negligible, reflects poorly on the estimates of the “radiant” portion of the ATMOSPHERIC EFFECT.
Willis,
I think Dr. Brown’s thought experiment makes a mistake by linking the temperature to the vertical component of the molecule speed, only, when he says: “On average, just as many molecules move up, with exactly the same velocity/kinetic energy profile, as move down, with zero energy transport, zero mass transport, and zero alteration of the MB profiles above and below, only when the two slices have the same temperature”.
If there is a difference in horizontal speed (i.e. wind) between the layers, the temperatures can be different while the layers do adhere to all of the conditions mentioned in the quote.
On another note, Willis, when you tell Jeremy: “You are a hundred percent correct, gravity can’t do ongoing work to change the temperature”, I hope you’re not forgetting that the Earth does negative work on the molecules going up, which in equilibrium cancels out the positive work being done on the molecules going down, the net energy effect being zero.
Bart: “Without radiating gasses to draw the heat energy away, the atmosphere of a planet is like an ideal electrical capacitor hooked up to a constant voltage source”
I know you changed this to “constant-current source,” but, actually, you had it right the first time If voltage is temperature and the earth’s surface is the voltage source. An atmosphere of the type you describe would acquire energy from its source only when its temperature is less than the surface’s. Of course, the earth’s “voltage” isn’t constant, and its outgoing radiation provides a (highly nonlinear) parallel conductance, but that doesn’t detract from the point: the capacitor won’t pop.
AusieDan says:
January 19, 2012 at 8:14 pm
We need a theory to explain why the surface temperature of the various solar bodies can be derived as a function of distance from the sun (solar radiance) plus near surface atmospheric pressure.
I’ve given it several times now. It’s called the standard GHE at its maximum. That maximum effect is determined by atmospheric pressure. Nothing else is needed. This conjecture explains all the data.
Now, why is there a maximum? I’m not sure, but it could be where the “cooling effect” of GHGs exactly matches the “warming effect”. The latter one is the only one climate scientists look at. The former one is what you get when a GHG extracts energy from the atmosphere and radiates that energy to space.
All right, here is my attempt at the elevator speech for what I understand the Jelbrings paper to be, based on the discussions here. I’m sure someone will find something wrong with it. It’s a little bit longer than Willis’ elevator speech, but I believe that his misses some crucial pieces.
* If left undisturbed in a gravity field, a tall container of air will stratify vertically, with the coolest temperature at the top and the warmest temperature at the bottom.
* In an undisturbed environment that column of air will eventually reach energetic equilibrium, meaning that any given cube of air will contain exactly the same amount of energy, whether at the top or the bottom.
* Because an air molecule at the top of the column (gravitational body) is further away from the earth (gravitational body) than a molecule at the bottom of the column, by the universal law of gravitation less force is being exerted on the molecule at the top of the column.
* Therefore the pressure at the top of the column will be higher than the pressure at the bottom of the column.
* It also then follows, according to the ideal gas law, that P1 * V1 / T1 = P2 * V2 / T2 where 1 is the top of the column and 2 is the bottom of the column.
* Therefore, when examining two identical volumes of air, one at the top of the column and one at the bottom of the column, the one with the greater pressure (bottom of the column) must also have a greater temperature for energetic equilibrium to have been reached.
* This property of an undisturbed column of air in a gravity field, is the cause of what we erroneously refer to as the “greenhouse effect”.
Willis, such a column would never be isothermic throughout the whole column of air. Instead, it would be isothermic at any given layer of the column. In other words any given horizontal slice parallel to the earth would be isothermic, but they would not be isothermic from one layer to the next. The faulty assumption necessary to yield an isothermic column is that the strength of gravity field acting upon any given molecule in the column is uniform throughout the column. It clearly is not, both theoretically and empirically.
Bomber Cat:
Real oceans and lakes are not a good facsimile for this thought experiment. The reason, their primary thermal input comes from the top of the ocean (i.e. the warming rays of the sun) because the depth of water does not allow the sun’s radiation to reach the bottom of the ocean floor to be absorbed and redistributed back upwards.
If you look at how a solar pond works (when the sun can penetrate to the black bottom) you see the warmer water at the bottom and the colder water at the top. The problem in your example is the lack of transparency of the ocean and an energy source at the top.
Why is the N Z paper called a gravity model? I always interpreted their model as a delay model. Sun heats the surface through a largely transparent medium. The surface heats this transparent medium though particle contact. Eventually this distributes through the transparent medium.
The delay in the heated surface to lose it’s temp because of the transparent medium allows the surface to heat more than it would without the transparent medium.
I read what was posted in this article that ignores any of the above as completely missing the point.
Consider a 10km long box 1m x 1m cross section of perfect insulating material (aerogel?). Coat the outside with 100% reflective material (to stop the aeogel radiating it will not conduct)
Fill it with argon.
Lay it horizontally 5km above ground level. It will of course be perfectly balanced
Leave it for a few days.
The temperature must stabilise so that all the gas is at the same temperature – there are no external influences on the gas and it cannot radiate and cannot conduct out of the box
Rotate it 90 degrees. (it will do some of the work itself as the argon compresses in the lower end and decompresses in the higher unbalancing the system.
When vertical the argon will be heavily compressed in the lower end and therefore much hotter and very decompressed and therefore cooler in the high end. In fact it will have the profie dictated by the lapse rate.
Leave this for a few months. Those warm and cool atoms of argon will be wizzing about in the box but they will be loosing no energy. All that wizzing eventually equalizes the temperature throughout the gas – the low pressure gas will have the same temperature as the high pressure gas.
There is no energy in or out to disturb this. Maxwells deamon is not in the box to sort the hot from the cold! the gas is isothermal.
It will stay in this state forever.
Now rotate the box through 180 degrees and magically the low pressure end becomes the high pressure end and therefore the lapse rate is re-established.
HOWEVER
You have just turned a box that is heavy at the lower end. raising it 10km up in the air, working against gravity. There has been much work done.
Leave the box for a few more months and the gas will again become isothermal.
BUT
The temperature will now be hotter than before because you put all that work in rotating the box.
You can continue this rotation untill the argon is white hot of course!
BUT
it only gets hotter because you put in work
Leave the box vertical for as long as you like and no work will be done. Gravity is static it does no work. If gravity maintained the adiabatic lapse rate temperatures the it would be magically operatinhg as a maxwell deamon.
By the way look up “vortex tube” for a way of separating hot and cold air! A maxwell deamon powered by compressed air.
As a follow-on to the solar pond comment I just left, I do not consider it a reasonable facsimile of the experiment either. I was only pointing out that there are bodies of water that violate the example of oceans and lakes. In order for it to be a reasonable facsimile, there would have to be no light source, i.e no sun.
Tallbloke says: “No, as we’ve been saying all along, as have other people on this thread, at the lowest energy state, molecules at the top of the atmosphere have the same total energy as those at the bottom, but less of the total is available as kinetic energy …”
As has been stated many times in many way, science is not decided by consensus, and science is certainly not by consensus of non-experts. Of the people on this list who seem to have formal training in physics, the agreement seems quite strong that isothermal is the the equilibrium condition for the given thought experiment.
Among OTHER trained physicists I have consulted, that is ALSO the agreement for isothermal rather than a lapse rate.
For instance, they say:
“all of the following are true:
— Boltzmann distribution of kinetic energy
— Boltzmann distribution of potential energy
— Boltzmann distribution of total energy.”
This is in contrast to Tallbloke’s claim that ONLY total energy follows the Boltzmann distribution.
EACH of these separately will have the same distribution and the same temperature. I could also go into the rather involved discussion of the partial derivatives involved, like
∂S β = -------- ∂E | Nbut I don’t think it would help much in this discussion.
[COMMENT: I fixed the formatting, Tim, using the “pre” tags (for “preformatted”). WordPress ignores leading blank spaces. —w.]
Oops… I reversed on point in my elevator speech…
* Therefore the pressure at the bottom of the column will be higher than the pressure at the top of the column.
The whole thing should read:
* If left undisturbed in a gravity field, a tall container of air will stratify vertically, with the coolest temperature at the top and the warmest temperature at the bottom.
* In an undisturbed environment that column of air will eventually reach energetic equilibrium, meaning that any given cube of air will contain exactly the same amount of energy, whether at the top or the bottom.
* Because an air molecule at the top of the column (gravitational body) is further away from the earth (gravitational body) than a molecule at the bottom of the column, by the universal law of gravitation less force is being exerted on the molecule at the top of the column.
* Therefore the pressure at the bottom of the column will be higher than the pressure at the top of the column.
* It also then follows, according to the ideal gas law, that P1 * V1 / T1 = P2 * V2 / T2 where 1 is the top of the column and 2 is the bottom of the column.
* Therefore, when examining two identical volumes of air, one at the top of the column and one at the bottom of the column, the one with the greater pressure (bottom of the column) must also have a greater temperature for energetic equilibrium to have been reached.
* This property of an undisturbed column of air in a gravity field, is the cause of what we erroneously refer to as the “greenhouse effect”.
There must be some Peter Principle corollary or perhaps Parkinson’s Law of Triviality corollary with this discussion.
Luke says:
January 20, 2012 at 5:41 am
“* This property of an undisturbed column of air in a gravity field, is the cause of what we erroneously refer to as the “greenhouse effect”.”
This conclusion is not supported. The temperature at the bottom of the column would be the same with or without gravity! Gravity merely trades off temperature for gravitational potential energy with increasing column height. That’s all it does. It can’t add or substract energy from the column, it can’t change the distribution of energy in the column, but it CAN change the distribution of sensible/insensible energy and that distinction is important because potential energy won’t save any brass monkeys from disfigurement.
Here is a Car-Talk Puzzler-type question that (hopefully) will illuminate why Luke and other posters are mistaken.
A WUWT Puzzler
Alice has a cannon that shoots vertically, with a random initial vertical velocity, whose root-mean-square initial value is 100 meters/second, whose mean value is zero, and which is normally distributed (a Bell-shape curve).
Puzzler Remarks:
(1) on half of the firings, Alice’s shell shoots down into the dirt
(2) the other half of the firings, Alice’s shell shoots up-in-the-air
(3) a typical maximal height is (100^2)/(2*10) = 500 meters
(4) some shells fly higher, others lower
Puzzler Question: Of all the shells that pass the “X” meter height, what is their mean square velocity, as measured at “X” meters altitude?
Asserted Puzzler Answer: No matter what the value of height “X”, the shells that pass through height “X” have a root-mean-square velocity of 100 meters/second.
So amazingly, our “Puzzler Shells” do not “cool off” as they fly to higher altitudes. Rather, there are simply fewer-and-fewer of them.
As with “Puzzler Shells”, so with gas molecules: their temperature is independent of elevation, but their density decreases.
And that is my “elevator explanation” of Willis’ problem.
John Mason says: January 20, 2012 at 5:56 am
… The faulty assumption necessary to yield an isothermic column is that the strength of gravity field acting upon any given molecule in the column is uniform throughout the column. It clearly is not, both theoretically and empirically.
============
The force of gravity changes little over a 10km distance above the earth:
http://en.wikipedia.org/wiki/File:Erdgvarp.png
Surface g=9.81
10km g=9.78
less than 0.5% change
Luke says: January 20, 2012 at 5:41 am
All right, here is my attempt at the elevator speech…
* If left undisturbed in a gravity field, a tall container of air will stratify vertically, with the coolest temperature at the top and the warmest temperature at the bottom.
You are starting from a wrong hypothesis. My first thought was also that this might be the equilibrium condition, but a bit of actual study of the issue made it clear this is wrong
“* This property of an undisturbed column of air in a gravity field, is the cause of what we erroneously refer to as the “greenhouse effect”.
If you start with a wrong postulate, then is is easy to come to all sorts of incorrect conclusions. For example, this property of an undisturbed column is ALSO what allows you to run a perpetual motion machine from this air column.
I recently made a very relevant comment to Dr. Robert Brown on one of his past threads. Maybe some here might also read and consider the topic on multiple horizontal Boltzmann distributions at each and every level upward a tall gravitationally held column under an actual DALR. See: http://wattsupwiththat.com/2012/01/12/earths-baseline-black-body-model-a-damn-hard-problem/#comment-870527
John Marshall says:
Because Jupiter is a gas giant undergoing slow gravitational collapse. I.e., the thermal energy is generated by the conversion of gravitational potential energy. See for example the discussion here http://nineplanets.org/jupiter.html :
This is not happening for the Earth.
“Gravity has NO AFFECT ON TEMPERATURE.”
As far as planet Earth is concerned, the correct statement would be:
Gravity has NO EFFECT ON POTENTIAL TEMPERATURE!
In a gravity field, with a costant source of energy (the Sun), in presence of two sinks (the Poles), the vertical profile of temperature would be that of the adiabatic lapse rate.
The presence of water, other GHGs and ozone makes the thinks more complicated, but vertical mixing can’t be ignored.
Of course gravity doesn’t make the difference between two planet, one with GHGs and the other without. It just rearranges the vertical distribution of absolute temperature (thanks to density), but not that of POTENTIAL temperature that would be costant. Actualy, potential temperature in our troposphere is higher aloft due to the release of latent heat after (mainly) wet convection has occurred
Willis,
N & Z have indeed produced a game-changer here and no thought experiment is needed to understand their ‘Unified Theory of Climate’. Simply stated, their hypothesis consists of their two key equations, (7) and (8).
The existence of a dimensionless ATE ‘factor’ does not imply that “gravity causes heating of the lower atmosphere”, in defiance of the 2nd Law of Thermodynamics. I believe the relevant science is nicely encapsulated in their (non-linear) equation (8),
Ts = 25.3966 (So + 0.0001325)^0.25 NTE(Ps).
That equation enables them to calculate the surface temperature (Ts) of ‘any planet with an atmosphere’, knowing only the TOA TSI (So), the surface pressure (Ps) on the planet and the dimensionless Atmospheric Temperature Enhancement factor (NTE).
The NTE factor for any planet is derived from observations already made (see N & Z, Table 1) and a thorough reassessment of the physics of what they term ‘grey body’ temperature (Tgb) of a real, airless planetary object (our own moon) – a conceptual physical model which is used in equation (7) to derive their NTE values.
The experiments have been done, the data have been analyzed; their ‘grey body’ temperature model and their simple regression are now out there to be pondered for veracity and significance.
The fact that nobody can explain “how it works” (to your satisfaction) is not a valid reason to try to demolish their hypothesis by thought experiments (which include unproven assumptions).
Try to understand it Willis, please. All your thought experiments are irrelevant unless you can demonstrate where their math, or their data, or their ‘grey body’ model, or their regression is wrong. To do that you need to understand what they have done and, by your own admission, you do not yet understand what they have done.
Tim Folkerts says:
January 20, 2012 at 6:06 am
Of the people on this list who seem to have formal training in physics, the agreement seems quite strong that isothermal is the the equilibrium condition for the given thought experiment.
Whereas the engineers and meteorologists tend the other way. And this is interesting, because it shows who has more common sense. 🙂
Tim, it’s no good appealing to Boltzmann when he is one of the protagonists in the unresolved dispute.
Loschmidt, Lagrange, Laplace, Jelbring and me vs Willis, you, Jeremy, Boltzmann and Maxwell
Outside, now!
lol.
I’m reading up on what happened between Maxwell’s formative thinking about classical molecular mechanics (engineers and meteorologists) and his part in the development of statistical mechanics (physicists and mathematicians) to see if I can find the key to this fascinating puzzle.
Last year this was discussed in a Climate Etc. thread. Perhaps a conceptually simpler Perpetuum Mobile machine can be constructed from two identical vertical columns of gases of different heat capacity, e.g. helium and argon thermally connected at their bases and totally insulated otherwise. If the lapse rate is an equilibrium property, there will be a constant temperature difference at the tops of these two columns. Making identical thermocouple connections between these points at the same gravitational potential, one has an electric potential difference and can then use this to dissipate energy. Energy is being extracted from both columns, cooling both while a constant temperature difference persists at the thermocouples.
If one is mathematically inclined, it is not a difficult exercise to start with a fixed volume of an isothermal, ideal gas and show that any perturbation of its density and thermal profiles leads to reduced configurational entropy, total energy held constant.
When one sees the expression “radiative-convective equilibrium” employed, it’s a giveaway that the writer is unconditionally misinformed. There can be radiative-convective steady-states, but any steady-state requires a constant dissipation of either mass or energy for maintenance. That the troposphere might be described as a steady-state implies such an energy of dissipation and, perhaps not too surprisingly, convective stirring takes a steady input ca. 240W/m^2 to be dissipated, but that’s reverting to pre-postnormal science.
DirkH says:
January 20, 2012 at 3:54 am
“And that is the stable configuration, not the isothermal one.”
Looks like I misunderstood the definition of “isothermal” – and my explanation is in no contradiction to Willis’ isothermal configuration. So it seems Willis and I agree that we will observe the lapse rate as defined by the Ideal Gas Law. Sorry for any confusion.
After 24 years of being inundated with “greenhouse effect” theory lectures, first from James Hansen in 1988 which those of us old enough to remember was quite a display of fear mongering (very convincingly so I might add), multiple documentaries on television and never ending use of the term since then in the media and science publications, the whole damn thing has evolved into an unfalsifiable hypothesis . Anyone can use the internet to find these “high school physics” descriptions of how the GHE works.
All I would like an answer to is why the very basic tenet of the GHE, that being the tropical troposphere should be warming at a faster rate than the surface, is unsupported by observational evidence. This was culminated by the debunking of Santer 08, perhaps the most dubious peer reviewed material released for public and scientific consumption since MBH 98. To keep the pseudoscience alive, scientists promoting the failed experiment tell us the observations must be wrong, not the “theory”.
I was fully convinced in 1988 of the “greenhouse effect” and it’s deleterious effects it would have on the earth, yet here it is 24 years later and it isn’t working as advertised. If anything, it is upside down.
There is something wrong with the GHE hypothesis as it has been promoted lo these many years.. I’m not qualified to enunciate what it is in technical jargon, but I don’t need to be an atmospheric scientist or physicist to know something is wrong. Does anyone else feel like they’ve been sold a lemon? Even here on WUWT,with the arguing going back and forth, the “theory” is no better explained or proven than it was 25 years ago.
“If it disagrees with experiment, it’s wrong”.