Perpetuum Mobile

Guest Post by Willis Eschenbach

Since at least the days of Da Vinci, people have been fascinated by perpetual motion machines. One such “perpetuum mobile” designed around the time of the civil war is shown below. It wasn’t until the development of the science of thermodynamics that it could be proven that all such mechanisms are impossible. For such machines to work, they’d have to create energy, and energy cannot be either created or destroyed, only transformed.

Image Source

I bring this up for a curious reason. I was reading the Jelbring hypothesis this afternoon, which claims that greenhouse gases (GHGs) are not the cause of the warming of the earth above the theoretical temperature it would have without an atmosphere. Jelbring’s hypothesis is one of several “gravito-thermal” theories which say the heating of the planet comes from gravity rather than (or in some theories in addition to) the greenhouse effect. His thought experiment is a planet with an atmosphere. The planet is isolated from the universe by an impervious thermally insulating shell that completely surrounds it, and which prevents any energy exchange with the universe outside. Inside the shell, Jelbring says that gravity makes the upper atmosphere colder and the lower atmosphere warmer. Back around 2004, I had a long discussion on the “climateskeptics” mailing list with Hans Jelbring. I said then that his theory was nothing but a perpetual motion machine, but at the time I didn’t understand why his theory was wrong. Now I do.

Dr. Robert Brown has an fascinating post on WUWT called “Earth’s baseline black-body model – a damn hard problem“. On that thread, I had said that I thought that if there was air in a tall container in a gravity field, the temperature of the air would be highest at the bottom, and lowest at the top. I said that I thought it would follow the “dry adiabatic lapse rate”, the rate at which the temperature of dry air drops with altitude in the earth’s atmosphere.

Dr. Brown said no. He said that at equilibrium, a tall container of air in a gravity field would be the same temperature everywhere—in other words, isothermal.

I couldn’t understand why. I asked Dr. Brown the following question:

Thanks, Robert, With great trepidation, I must disagree with you.

Consider a gas in a kilometre-tall sealed container. You say it will have no lapse rate, so suppose (per your assumption) that it starts out at an even temperature top to bottom.

Now, consider a collision between two of the gas molecules that knocks one molecule straight upwards, and the other straight downwards. The molecule going downwards will accelerate due to gravity, while the one going upwards will slow due to gravity. So the upper one will have less kinetic energy, and the lower one will have more kinetic energy.

After a million such collisions, are you really claiming that the average kinetic energy of the molecules at the top and the bottom of the tall container are going to be the same?

I say no. I say after a million collisions the molecules will sort themselves so that the TOTAL energy at the top and bottom of the container will be the same. In other words, it is the action of gravity on the molecules themselves that creates the lapse rate.

Dr. Brown gave an answer that I couldn’t wrap my head around, and he recommended that I study the excellent paper of Caballero for further insight. Caballero discusses the question in Section 2.17. Thanks to Dr. Browns answer plus Caballero, I finally got the answer to my question. I wrote to Dr. Brown on his thread as follows:

Dr. Brown, thank you so much. After following your suggestion and after much beating of my head against Caballero, I finally got it.

At equilibrium, as you stated, the temperature is indeed uniform. I was totally wrong to state it followed the dry adiabatic lapse rate.

I had asked the following question:

Now, consider a collision between two of the gas molecules that knocks one molecule straight upwards, and the other straight downwards. The molecule going downwards will accelerate due to gravity, while the one going upwards will slow due to gravity. So the upper one will have less kinetic energy, and the lower one will have more kinetic energy.

After a million such collisions, are you really claiming that the average kinetic energy of the molecules at the top and the bottom of the tall container are going to be the same?

What I failed to consider is that there are fewer molecules at altitude because the pressure is lower. When the temperature is uniform from top to bottom, the individual molecules at the top have more total energy (KE + PE) than those at the bottom. I said that led to an uneven distribution in the total energy.

But by exactly the same measure, there are fewer molecules at the top than at the bottom. As a result, the isothermal situation does in fact have the energy evenly distributed. More total energy per molecules times fewer molecules at the top exactly equals less energy per molecule times more molecules at the bottom. Very neat.

Finally, before I posted my reply, Dr. Brown had answered a second time and I hadn’t seen it. His answer follows a very different (and interesting) logical argument to arrive at the same answer. He said in part:

Imagine a plane surface in the gas. In a thin slice of the gas right above the surface, the molecules have some temperature. Right below it, they have some other temperature. Let’s imagine the gas to be monoatomic (no loss of generality) and ideal (ditto). In each layer, the gravitational potential energy is constant. Bear in mind that only changes in potential energy are associated with changes in kinetic energy (work energy theorem), and that temperature only describes the average internal kinetic energy in the gas.

Here’s the tricky part. In equilibrium, the density of the upper and lower layers, while not equal, cannot vary. Right? Which means that however many molecules move from the lower slice to the upper slice, exactly the same number of molecules must move from the upper slice to the lower slice. They have to have exactly the same velocity distribution moving in either direction. If the molecules below had a higher temperature, they’d have a different MB [Maxwell-Boltzmann] distribution, with more molecules moving faster. Some of those faster moving molecules would have the right trajectory to rise to the interface (slowing, sure) and carry energy from the lower slice to the upper. The upper slice (lower temperature) has fewer molecules moving faster — the entire MB distribution is shifted to the left a bit. There are therefore fewer molecules that move the other way at the speeds that the molecules from the lower slice deliver (allowing for gravity). This increases the number of fast moving molecules in the upper slice and decreases it in the lower slice until the MB distributions are the same in the two slices and one accomplishes detailed balance across the interface. On average, just as many molecules move up, with exactly the same velocity/kinetic energy profile, as move down, with zero energy transport, zero mass transport, and zero alteration of the MB profiles above and below, only when the two slices have the same temperature. Otherwise heat will flow from the hotter (right-shifted MB distribution) to the colder (left-shifted MB distribution) slice until the temperatures are equal.

It’s an interesting argument. Here’s my elevator speech version.

• Suppose we have an isolated container of air which is warmer at the bottom and cooler at the top. Any random movement of air from above to below a horizontal slice through the container must be matched by an equal amount going the other way.

• On average, that exchange equalizes temperature, moving slightly warmer air up and slightly cooler air down.

• Eventually this gradual exchange must lead to an isothermal condition.

I encourage people to read the rest of his comment.

Now, I see where I went wrong. Following the logic of my question to Dr. Brown, I incorrectly thought the final equilibrium arrangement would be where the average energy per molecule was evenly spread out from top to bottom, with the molecules having the same average total energy everywhere. This leads to warmer temperature at the bottom and colder temperature at elevation. Instead, at thermal equilibrium, the average energy per volume is the same from top to bottom, with every cubic metre having the same total energy. To do that, the gas needs to be isothermal, with the same temperature in every part.

Yesterday, I read the Jelbring hypothesis again. As I was reading it, I wondered by what logic Jelbring had come to the conclusion that the atmosphere would not be isothermal. I noticed the following sentence in Section 2.2 C (emphasis mine):

The energy content in the model atmosphere is fixed and constant since no energy can enter or leave the closed space. Nature will redistribute the contained atmospheric energy (using both convective and radiative processes) until each molecule, in an average sense, will have the same total energy. In this situation the atmosphere has reached energetic equilibrium. 

He goes on to describe the atmosphere in that situation as taking up the dry adiabatic lapse rate temperature profile, warm on the bottom, cold on top. I had to laugh. Jelbring made the exact same dang mistake I made. He thinks total energy evenly distributed per molecule is the final state of energetic equilibrium, whereas the equilibrium state is when the energy is evenly distributed per volume and not per molecule. This is the isothermal state. In Jelbrings thought experiment, contrary to what he claims, the entire atmosphere of the planet would end up at the same temperature.

In any case, there’s another way to show that the Jelbring hypothesis violates conservation of energy. Again it is a proof by contradiction, and it is the same argument that I presented to Jelbring years ago. At that time, I couldn’t say why his “gravito-thermal” hypothesis didn’t work … but I knew that it couldn’t work. Now, I can see why, for the reasons adduced above. In addition, in his thread Dr. Brown independently used the same argument in his discussion of the Jelbring hypothesis. The proof by contradiction goes like this:

Suppose Jelbring is right, and the temperature in the atmosphere inside the shell is warmer at the bottom and cooler at the top. Then the people living in the stygian darkness inside that impervious shell could use that temperature difference to drive a heat engine. Power from the heat engine could light up the dark, and provide electricity  for cities and farms. The good news for perpetual motion fans is that as fast as the operation of the heat engine would warm the upper atmosphere and cool the lower atmosphere, gravity would re-arrange the molecules once again so the prior temperature profile would be restored, warm on the bottom and cold on the top, and the machine would produce light for the good citizens of Stygia   … forever.

As this is a clear violation of conservation of energy, the proof by contradiction that the Jelbring hypothesis violates the conservation of energy is complete.

Let me close by giving my elevator speech about the Jelbring hypothesis. Hans vigorously argues that no such speech is possible, saying

There certainly are no “Elevator version” of my paper which is based on first principal physics. It means that what I have written is either true or false. There is nothing inbetween.

Another “gravito-thermal” theorist, Ned Nikolov, says the same thing:

About the ‘elevator speech’ – that was given in our first paper! However, you apparently did not get it. So, it will take far more explanation to convey the basic idea, which we will try to do in Part 2 of our reply.

I don’t have an elevator speech for the Nikolov & Zeller theory (here, rebuttal here) yet, because I can’t understand it. My elevator speech for the Jelbring hypothesis, however, goes like this:

• If left undisturbed in a gravity field, a tall container of air will stratify vertically, with the coolest air at the top and the warmest air at the bottom.

• This also is happening with the Earth’s atmosphere.

• Since the top of the atmosphere cannot be below a certain temperature, and the lower atmosphere must be a certain amount warmer than the upper, this warms the lower atmosphere and thus the planetary surface to a much higher temperature than it would be in the absence of the atmosphere.

• This is the cause of what we erroneously refer to as the “greenhouse effect”

Now, was that so hard? It may not be the best, I’m happy to have someone improve on it, but it covers all the main points. The claim that “gravito-thermal” theories are too complex for a simple “elevator speech” explanation doesn’t hold water.

But you can see why such an elevator speech is like garlic to a vampire, it is anathema to the “gravito-thermal” theorists—it makes spotting their mistakes far too easy.

w.

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January 20, 2012 12:06 am

Let us forget gases for a moment and consider golf ball size particles made from lead, as our atmosphere, closely packed near the surface and twenty miles above loosely packed.
The potential energy of the balls at twenty miles up is huge. Consider these as cold molecules falling under gravity and impacting other molecules. Other molecules heated by conduction from the Earth by the sun are rising to meet them, and meet them they do head on. Thus slowing the transfer of Sol’s heat, graciously given to the world back into space. This is the major part of the misnamed green house effect. The rest of the green house nonsense can be explained by compression of the atmosphere close to the surface, where the molecules are elbowing for room.
The modulation to all this is water in it’s various phases, that gives us a livable planet, chaotic as it is.

joshua Corning
January 20, 2012 12:08 am

For such machines to work, they’d have to create energy, and energy cannot be either created or destroyed, only transformed.
So the earth can’t orbit around the sun because that would break the laws of thermodynamics?
I hate to break it to you Willis but you have gone off the deep end.
The reason that gasses in an atmosphere are of higher temperature then if they were floating around in a vacuum are the same reasons why the earth can continue to orbit the sun without constantly being pushed.
i will restate my thought experiment again.
Imagine gas floating around in a cloud in the vacuum of space. it is spread out and the interactions between the atoms in the cloud are sparse…now imagine that cloud being pulled down a gravity well of a planet. the gas gains no energy yet it is now under pressure….now the atoms are all close together and colliding and doing what atoms do when they are forced to be in close proximity to one another. Again the atoms energy has not changed. yet their temperature is higher.
see how that works?
And it can be proven. Take the temperature of any old room….now compress air from that room into a container…now measure the temperature of the compressed air in that container…..guess what the air inside the container is hotter then the air in the room.
now i know what you are going to say “you used energy to compress that air” you are correct i did…but when atoms are compressed by gravity as in an atmosphere then no energy is used to compress it.
anyway i just thought of how this can balance thermodynamics….think of school teacher holding a ball in the air then he drops it. the teacher then says the ball while he held it had potential energy and when he released it it had kinetic energy. Think of the gas floating around in space as potential energy and when they are pulled down a gravity well of a planet as kinetic energy….you see they had that potential energy from when the universe was created and now that they are compressed by the planet’s gravity they have kinetic energy.
I really cannot explain it simpler then this…..if you cannot grasp it i have to suspect it is from willful ignorance.

joshua Corning
January 20, 2012 12:22 am

“If left undisturbed in a gravity field, a tall container of air will stratify vertically, with the coolest air at the top and the warmest air at the bottom.”
Note that the atoms at the top have the highest energy and the lower ones the lowest.
The reason the temperatures are reversed is simply because at the top of the column you have less atoms hitting the side of your thermometer then you do at the bottom.
I think part of the problem is that although you understand that hot air moves to cold air i think you either are forgetting or don’t understand why atoms do that.

Editor
January 20, 2012 12:30 am

Willis replied to Ferds comment;
‘Temperatures have leveled. Sea levels have stabilized. CO2 has not. These events contradict GHG theory predictions, which in science is a strong indication the GHG theory is wrong.’
By remarking;
‘Thanks, ferd. I come to a very different conclusion from the same facts. I say that the greenhouse effect has done the heavy lifting of bringing us to our warm current temperature….’
Temperatures have been slightly higher than today and sea levels also higher on several ocassions during the last 5000 years. Self evidently that wasn’t due to raised co2 levels (according to the stated records)
What did the ‘heavy lifting on those occasions? Natural variability? if so couldn’t that be the cause again today?
tonyb

January 20, 2012 12:30 am

Willis Eschenbach says: January 19, 2012 at 11:52 pm
“I don’t see why you say Dr. Brown is wrong.”

In the quote that I cited, it explicitly says that motion of the air equalizes temperature. And it doesn’t, for the reasons that I gave.
But I was more concerned to say what it does do. It provides the heat pump which counters conduction and radiative transfer down the gradient.
And still air is impossible. You need a heat source to prevent liquefaction (from radiative loss), and that in practice will create temperature differences and motion, which in turn pushes toward the adiabatic lapse rate.

alex
January 20, 2012 12:31 am

What the guys makea big tohuwabohu out of a very simple problem?
What is all this poetic story about?
Willi, it’s trivial as a nutshell.
1. There is a big difference between a tall air “container” and an atmosphere: the atmosphere is MIXING (troposphere = mixing sphere), your “tall container” is not.
2. If there is mxing, the only equilibium is very simple: ds/dz=0, where s is the entropy density. You have the thermal source at the bottom – the Earth surface heated by the Sun, and the thermal sink at the top – radiation to the space by the GHGs or clouds. In between you automatically get ds/dz=0. This is the adiabate that gives you the temperature lapse.
3. In your non-mixing “tall container”, there is no energy sink at the top. Thus, the temperature is constant. T=const. Very simple.
4. The temperature at the Earth’s surface is NOT defined by the GHG concentration, if the GHGs screen the Earth’s IR radiation completely. In this case, you must calculate the energy balance AT THE RADIATING SURFACE that is special for every wavelength: it is the altitude, where the atmosphere becomes transparent for the radiation. In this way you obtain the temperature up there.
5. Now you start your adiabate from this radiation surface at the top of the troposphere (the energy sink) and go down to the planet surface. Here you use the adiabate with its temperature lapse rate. The higher the atmospheric pressure at the bottom, the higher the temperature. Has nothing to do with “perpetuum mobile”.
6. For the reason discused above, Venus is hot as a hell due to the high atmospheric pressure (NOT GHG “concentration”), Mars with its low atmospheric pressure (although 20x more CO2 than the Earth!) is freesing and we have the comfortable climate.
Alex.
5.

January 20, 2012 12:36 am

Thomas L said:

Nice try. Before you rotate the cylinder, the air at the top of the cylinder has lower pressure than the air at the bottom of the cylinder, and therefore the density at the top is less than the density at the bottom. So when you turn the cylinder over, you are doing work, as moving the bottom up takes more energy in a gravity field than you get from moving the top down.

But that’s also true if the air was already at the adiabatic lapse rate. In that case, when I flip the cylinder, the end state will be exactly the same as the initial state, so no net work was performed. I lift the air, I lower the air. I do work lifting, then have work done to me as I set it down. I do work tilting the cylinder 90 degrees, then have work done to me as I resist the further rotation as the dense air pours to the other end to try and complete the flip. It’s the same as pendular motion.
Back to Willis’s original thought experiment (and perhaps its key point) I’m not sure you can pull work out of the adiabatic atmosphere with a thermocouple, as I’m not sure anyone has dug that deeply into heat transfer in a solid in a gravitational field. For example, the thermocouple has to conduct the energy (as heat) along its length. If we pick the best standard material for heat conduction, silver, and work at the Earth’s adiabatic lapse rate of about 2 degrees C per thousand feet, we can only conduct about 2.4 Watts per square meter of silver conductor, even horizontally. Such low levels of heat transfer over such vertical distances might require the inclusion of effects that are irrelevant in most applications. putting us below the round-off error in the equations that work acceptably well in other applications. I’m pretty sure nobody has tried to use 2 degrees C to move only 2.4 watts upward through a silver or copper slab a thousand feet tall and a square meter in cross section, which is the same as using 160,000 tons of silver, the weight of almost four Iowa class battleships, to cool a 200 Watt CPU by just 2 degrees.
We could sidestep the question by positing that solid masses are allowed to reach thermal equilibrium at the top and bottom of the atmosphere, then are insulated and moved into contact with the thermocouple. I don’t know if this would raise questions about KE and PE of the solid bodies, though, or whether moving them that distance without losses would itself be a perpetual motion machine.

Colonial
January 20, 2012 12:43 am

Joe Born (January 19, 2012 at 5:42 pm) wrote:
[If the] … Velasco et al. paper is correct, its Equation 8, a result of statistical mechanics, dictates that average kinetic energy decreases with height even at equilibrium.
I’m not an atmospheric scientist, just an electrical engineer who had a single thermodynamics class 40+ years ago, but the comment above matches my reservations. Let’s postulate a sealed container filled with a perfect gas (defined as an ideal gas which additionally is completely transparent to radiation), similar to that proposed by Willis. The container begins at ground level, where the pressure is 1,000 millibars, and extends to the altitude at which the pressure would be 500 millibars if the gas were isothermal. Let’s grab a small amount of gas at ground level and raise it (without disturbing any other molecules) to the top. When we do that, we add potential energy of position to the gas molecules that rode the elevator to the top.
Where did that energy come from? Unless there’s another source of energy that can be tapped (a violation of the assumed equilibrium conditions in our sealed container), the energy has to come from the kinetic energy of the molecules that were raised from bottom to top. If it comes from anywhere else, we’ve added extra energy to the molecules that were raised that can then be used to perform work, creating yet another perpetual motion machine!
If we take the sealed container postulated above and evacuate it until there’s only a single gas molecule left, it’s clearly true that the total energy of that lonely gas molecule is the sum of its potential energy of position and its kinetic energy. When the molecule is at ground level, it will have the highest possible kinetic energy (implying a higher temperature), and zero potential energy of position. If it travels straight upward until it reaches the top of the sealed container, it will have the highest possible potential energy of position for that system, and correspondingly lower kinetic energy (implying a lower temperature).
When the sealed container has the normal complement of perfect gas within it, the mean free path of any given gas molecule will be very short (Wikipedia says 68 nanometers for air at 1013 millibars). However, between collisions, the vertical component of each molecule’s velocity will be affected by gravity, just as in the case where only a single molecule is present. If the vertical component is upward, it will trade kinetic energy for energy of position, cooling slightly in the process. If the vertical component is downward, it will trade energy of position for kinetic energy, warming slightly in the process.
So, the heresy, spoken aloud: A perfect gas within a sealed container will exhibit a temperature gradient in a gravitational field. This is not, however, a substrate for a perpetual motion machine. The total energy (kinetic plus potential energy of position) of each molecule is the same. Any attempt to extract energy from the difference in temperature between the top and bottom will founder on the reality that entropy has already been maximized for the gas within the sealed container. There’s nothing left to get.
You’ll note that at the beginning, I specified that the sealed container had a pressure of 1,000 millibars at the bottom and 500 millibars at the top. It’s been too many years since I took physics to allow me to easily perform the calculations, but someone who performs such calculations regularly should be able to calculate the energy required to raise a molecule from the bottom to the top, subtract it from the assumed kinetic energy of a molecule at 1000 millibars, and determine the remaining kinetic energy for that molecule. This would allow calculation of the actual pressure at the top (nominally 500 millibars), and the temperature gradient that would exist in the sealed container because of gravity.

Neil
January 20, 2012 12:46 am

I have never seen so much ignorance in one blog
Does no one understand the dry adiabat for the atmosphere on Earth (DALR=9 degrees per Km)?
This is entirely controlled by gravity and by the mass of the atmosphere– nothing else.
(hence it varies for other planets)
It applys to the larger atmosphere in exactly the same way it it does in an insulated cylinder of dry air
Does no one here understand the TePhigram which plots equal lines of equal entropy against air pressure (altitude)?
Why not take 5 minutes and get out of this ignorance
Neil

Bryan
January 20, 2012 1:03 am

Tim Folkerts says
“The simplest and most convincing argument ended up being your same perpetual motion approach. You could run an insulated copper bar from bottom to top. This bar does not have the lapse rate effect. (Or use another gas that would have a different lapse rate because it has a different heat capacity). The copper should have the same temperature at top and bottom. If the gas had a different temperature, would could use this temperature difference to continually run the sort of heat engine you suggested.”
Tim go one stage further and source any real heat engine connected by real copper connections of one kilometer in length for a 9.8K temperature difference.
Factor in the resistance of the copper.
Who’s to say that one kilometer of copper will not have its own gravitational/thermal effect with its own value?
Indeed perhaps all this is in accordance with the second law
Maybe you can now see why an experiment to settle the isothermal/adiabatic distribution has never been attempted.
Its interesting that Claudius (who supported the isothermal conjecture) dropped the second law proof later on in life

jorgekafkazar
January 20, 2012 1:03 am

Willis: Sorry to have confused you. WordPress doesn’t allow the use of symbolic logic symbols here. I thought you’d immediately see the problem. In essence, you state:
1. “If [the isolated system is in its lowest energy state]{B} THEN [it cannot perform work]{not W}”
2. “If [the isolated system…is warm at the bottom and cold at the top]{D} THEN [it can perform work]{W}”
3. “[The isolated system cannot perform work]”{not W}
4. “therefore [the isothermal state…is the lower of the two energy states,]{J}”
Simplified even more, your argument boils down to:
1, if B THEN not W
2. if D THEN W
3. not W,
4. therefore J
But what you’ve proved, so far, is simply “not D.” (I can think of another state which can’t perform work.) For the argument to be valid, you must establish
1a. if not D THEN B, as well as
1b. if B THEN J, and so forth, 2., 3., 4., as you state.
Sorry for the confusion. I looked for the symbols for quite a while before giving up.

joshua Corning
January 20, 2012 1:04 am

“The Jelbring thought experiment concerns a closed system, with no energy going either in or out. I don’t recall saying the earth could not orbit the sun, you’ll have to cite that. In any case, that’s an open system.”
Atoms of high energy will be able to climb higher against gravity in the column then atoms of low energy. Energy is not going in and out but atoms still run into one another within the system right? and at any given time some atoms will whack into each other harder, simply by virtue of angle and velocity, then other atoms right?
If low energy atoms can only be at the bottom and high energy atoms can be anywhere in the column simple addition should tell you there will be more atoms at the bottom then on the top.
If there are more atoms on the bottom then the likelihood of those atoms (even though on average they are of a lower energy then the top) hitting your thermometer at the bottom then there is of them hitting the thermometer at the top. ie the temperature will be higher on the bottom then on the top.
You are confusing temperature with heat.

Robert L
January 20, 2012 1:04 am

Hi Willis,
I think the thermocouple analogy is broken. In order to extract energy from a thermocouple, it is true there has to be a temperature difference, but there has to be heat to operate the thermocouple pair. The top thermo has no ‘sink’ and as a result would simply get warm by conduction, from the lower thermocouple.
It your hypothetical isolated planet the atmosphere would become Isothermic. My reading of N&Z is that an input of energy is required to maintain the gradient. The mechanism is unclear, however ignoring KE, PE and convection is as foolish as expecting gravity to do all the work (pun intended)
Cheers
Robert

Bryan
January 20, 2012 1:07 am

Willis says
“To the contrary. Thermal equilibrium simply means that the objects have stopped exchanging energy because they are at the same temperature. This happens all the time.”
No at equilibrium they exchange equal quantities of energy

joshua Corning
January 20, 2012 1:15 am

“But you cannot get continuous work out of that. ”
yes you can. An object in motion will to stay in motion. Atoms don’t stop…they don’t have wind resistance, they don’t get tired, they just keep going and going and going, and as you stated no energy comes in and no energy goes out. So those atoms cannot transfer energy out…ever. they will bounce around in your column until the end of the universe and they will segregate out into a pressure gradient simply by virtue of the fact that at any given time some atoms will have low energy and some will have high energy…the low energy atoms stay close to the bottom while higher energy ones will be everywhere….thus you get high pressure at the bottom and low pressure near the top….a thermometer will measure this gravity induced pressure gradient as hot below and cold on top simply because more atoms will hit the thermometer on the bottom then will hit it on top.

tallbloke
January 20, 2012 1:28 am

Willis,
Firstly, thank you for the courtesy of your response. It is encouraging that we are able to set aside non-scientific issues that hang between us and conduct scientific debate rationally and reasonably.
Some preamble, and then some science.
You said to Lucy that
“time is what you don’t have. The clock is running, the elevator speech for N&Z is way overdue.”
Nobody is king of the clocks. Lucy and I are not sales people with obligations to meet targets within timeframes or elevators. Paradigms don’t change overnight. Resistance to the theory of plate tectonics continued for as long as the old guard were in tenure at their institutions. Time must be spent in evaluating new theories properly, not concertina’d into a gish gallop of instant rebuttal and ‘counterproof’.
A more relevant example than plate tectonics is the Loschmidt vs Maxwell and Boltzmann debate regarding thermal gradients matching the theoretical dry adiabatic lapse rate in equilibrium atmospheres subject to a gravitational field. It’s been going on for over a hundred years without resolution and we don’t need to force a conclusion within the next few days just because it has been thrust to the centre of the stage at the moment.
OK thanks for reading that, lets address some science.
Willis Eschenbach says:
January 19, 2012 at 6:26 pm
If an energetically isolated system is in its lowest energy state, it cannot perform work.

Agreed
If the isolated atmosphere in Jelbring’s thought experiment is warm at the bottom and cold at the top, I can stick a thermocouple into it and use the temperature differential to generate electricity to perform work.
Excellent, a proposed experiment. Let us know the result. I think you’ll find that even as a thought experiment it doesn’t work out though. Peter Berenyi emailed me that argument and I sent him my disproof. He hasn’t got back to me in the two days since. I’ll post it in a separate comment if you are interested in defining your setup.
As Tallbloke points out, the second law says an isolated system can only move towards a lower energy state. That means Jelbring’s thought experiment must inexorably move towards the isothermal condition as its equilibrium state.
No, as we’ve been saying all along, as have other people on this thread, at the lowest energy state, molecules at the top of the atmosphere have the same total energy as those at the bottom, but less of the total is available as kinetic energy which manifests as heat via collisions because more of the total energy is locked up as gravitational potential energy.
Since Jelbring claims an adiabatic state will obtain at equilibrium, his hypothesis is falsified.
If my statement above is correct, or if the equivalent macroscopic arguments provided on this thread and by Jelbrings 2003 paper are correct, then this statement is false.
Willis Eschenbach says:
January 19, 2012 at 9:21 pm
Jeremy says:
Gravity has NO AFFECT ON TEMPERATURE.
How many times must it be said.
You people are reading science fiction.
You have to do WORK to create a change in temperature – this is basic thermodynamics!!!!
If an object falls in a gravitational field then potential energy will be converted to kinetic energy which will create heat. However a stable column of air in equilibrium does not create any energy or heat.
Thanks, Jeremy. You are a hundred percent correct, gravity can’t do ongoing work to change the temperature

Jeremy and you are 100% wrong. Work is done by energy. Gravity is not a type of energy, it is a force. It cannot and does not need to “do ongoing work”. Nor is a change in temperature under discussion. Gravity, via the pressure profile it induces in an atmosphere, and considering the compressibility of the medium, causes the denser per unit area of the atmosphere near the surface to be warmer than it is at higher altitudes. g/Cp
If you are fighting basic ignorance of science, you will be deluged with ignorant people. Not much I can do but just keep putting the facts out there.
Certainly there are a host of much more sophisticated threads, and those tend to attract a more scientifically literate commenter. But when you are discussing “gravito-thermal” theories …

This is an ad hominem attack which has no place in scientific discourse.

markus
January 20, 2012 1:28 am

“joshua Corning says:
January 20, 2012 at 12:08 am
but when atoms are compressed by gravity as in an atmosphere then no energy is used to compress it”.
Probably be better to say, “then no energy is used to compress it, other than the potential energy of its mass.”
IR is (forced) employed into potential energy viz conduction of paired electrons around a molecules covalent bond, heating its chemicals, and adding kinetic energy to its energy budget
.
The adding of kinetic energy to mass causes heat, because of the collisions and transfer of the Atmospherically Thermally Enhanced kinetic energy that has been temporarily employed by the energy of mass.This heat is enhanced at higher pressures.
The energy budget of atmospheric trace chemicals should equal the square of its mass plus its employed kinetic energy.
And all the UW IR, DW IR, IR from enhanced mass, are just mixing gases in a pot up to re-radiation when kinetic energy of mass returns the employed energy to space
I have confidence in the N&K equation describing this phenomenon.
..

Michelangelo
January 20, 2012 1:28 am

Fascinating stuff in all these comments ..As a reader I especially liked the ones posted by ed_b , Ian H and I found the intriguing question why there are no PV-cells exploiting the energy supposedly radiated from the GHG:s during night by Richard Vernay very reveiling.

Bryan
January 20, 2012 1:33 am

Nick Stokes say
“When the lapse rate is below the dry adiabat (toward isothermal) it is referred to as convectively stable. Above the adiabat, it is unstable. At the adiabat, it is neutrally stable. ”
At the adiabat the parcel of air has no unbalanced force.
It can move up or down at constant speed or stay stationary.
This condition is called the neutral atmosphere and it can be surprisingly stable at night.
In dry conditions the gradient will be – 9.8K/km.
So its not correct to say that in OUR troposphere, the air will become isothermal if still.

Hoser
January 20, 2012 1:37 am

That’s an awful lot of talking people. So? What did you come up with?
Let’s try this again.
1) Sun heats surface. Some heat goes into land and sea, below the surface.
2) If an atmosphere is present, hotter areas are cooled and the heat is transported elsewhere and not radiated away as quickly.
3) After the sun goes down, the latent heat begins to radiate away. However a lot of energy remains below the surface and takes time to reach the surface.
4) If not all of the energy absorbed during the day is radiated away, then the surface will start off warmer the next day.
5) The average surface temperature continues to rise until the surface is able to radiate in 24 hours the same energy it absorbs during the day.
At least on land, the key difference between the Earth and the Moon is the atmosphere. On Earth the hot surface is cooled by air and therefore is unable to radiate as efficiently (because it was cooled). Cooler (shaded) areas are warmed by the heat transferred to the air by conduction from the warmer locations. On the Moon, shadowed areas radiate to 3K and are very cold. The Sun can heat surface rocks and these will get hotter until they are able to radiate efficiently the same amount of energy they absorb. No heat is transfered from one location to other places on the Moon. It should be no surprise the Moon’s surface cools rapidly after sunset. Although water is interesting, it seems not the driving factor given the data from planets and moons we saw a few weeks ago.

January 20, 2012 1:51 am

A recent BBC TV programme on the Earth’s core featured a claim by some scientist that the strength of the planet’s magnetic field has been falling significantly for the past 170 years. If true, might this tie in with the Svensmark hypothesis that changes in cosmic rays hitting the atmosphere affect cloud cover? Might one of WUWT’s resident brainboxes look into this and see if it has legs?

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