Guest Post by Willis Eschenbach
Since at least the days of Da Vinci, people have been fascinated by perpetual motion machines. One such “perpetuum mobile” designed around the time of the civil war is shown below. It wasn’t until the development of the science of thermodynamics that it could be proven that all such mechanisms are impossible. For such machines to work, they’d have to create energy, and energy cannot be either created or destroyed, only transformed.
I bring this up for a curious reason. I was reading the Jelbring hypothesis this afternoon, which claims that greenhouse gases (GHGs) are not the cause of the warming of the earth above the theoretical temperature it would have without an atmosphere. Jelbring’s hypothesis is one of several “gravito-thermal” theories which say the heating of the planet comes from gravity rather than (or in some theories in addition to) the greenhouse effect. His thought experiment is a planet with an atmosphere. The planet is isolated from the universe by an impervious thermally insulating shell that completely surrounds it, and which prevents any energy exchange with the universe outside. Inside the shell, Jelbring says that gravity makes the upper atmosphere colder and the lower atmosphere warmer. Back around 2004, I had a long discussion on the “climateskeptics” mailing list with Hans Jelbring. I said then that his theory was nothing but a perpetual motion machine, but at the time I didn’t understand why his theory was wrong. Now I do.
Dr. Robert Brown has an fascinating post on WUWT called “Earth’s baseline black-body model – a damn hard problem“. On that thread, I had said that I thought that if there was air in a tall container in a gravity field, the temperature of the air would be highest at the bottom, and lowest at the top. I said that I thought it would follow the “dry adiabatic lapse rate”, the rate at which the temperature of dry air drops with altitude in the earth’s atmosphere.
Dr. Brown said no. He said that at equilibrium, a tall container of air in a gravity field would be the same temperature everywhere—in other words, isothermal.
I couldn’t understand why. I asked Dr. Brown the following question:
Thanks, Robert, With great trepidation, I must disagree with you.
Consider a gas in a kilometre-tall sealed container. You say it will have no lapse rate, so suppose (per your assumption) that it starts out at an even temperature top to bottom.
Now, consider a collision between two of the gas molecules that knocks one molecule straight upwards, and the other straight downwards. The molecule going downwards will accelerate due to gravity, while the one going upwards will slow due to gravity. So the upper one will have less kinetic energy, and the lower one will have more kinetic energy.
After a million such collisions, are you really claiming that the average kinetic energy of the molecules at the top and the bottom of the tall container are going to be the same?
I say no. I say after a million collisions the molecules will sort themselves so that the TOTAL energy at the top and bottom of the container will be the same. In other words, it is the action of gravity on the molecules themselves that creates the lapse rate.
Dr. Brown gave an answer that I couldn’t wrap my head around, and he recommended that I study the excellent paper of Caballero for further insight. Caballero discusses the question in Section 2.17. Thanks to Dr. Browns answer plus Caballero, I finally got the answer to my question. I wrote to Dr. Brown on his thread as follows:
Dr. Brown, thank you so much. After following your suggestion and after much beating of my head against Caballero, I finally got it.
At equilibrium, as you stated, the temperature is indeed uniform. I was totally wrong to state it followed the dry adiabatic lapse rate.
I had asked the following question:
Now, consider a collision between two of the gas molecules that knocks one molecule straight upwards, and the other straight downwards. The molecule going downwards will accelerate due to gravity, while the one going upwards will slow due to gravity. So the upper one will have less kinetic energy, and the lower one will have more kinetic energy.
After a million such collisions, are you really claiming that the average kinetic energy of the molecules at the top and the bottom of the tall container are going to be the same?
What I failed to consider is that there are fewer molecules at altitude because the pressure is lower. When the temperature is uniform from top to bottom, the individual molecules at the top have more total energy (KE + PE) than those at the bottom. I said that led to an uneven distribution in the total energy.
But by exactly the same measure, there are fewer molecules at the top than at the bottom. As a result, the isothermal situation does in fact have the energy evenly distributed. More total energy per molecules times fewer molecules at the top exactly equals less energy per molecule times more molecules at the bottom. Very neat.
Finally, before I posted my reply, Dr. Brown had answered a second time and I hadn’t seen it. His answer follows a very different (and interesting) logical argument to arrive at the same answer. He said in part:
Imagine a plane surface in the gas. In a thin slice of the gas right above the surface, the molecules have some temperature. Right below it, they have some other temperature. Let’s imagine the gas to be monoatomic (no loss of generality) and ideal (ditto). In each layer, the gravitational potential energy is constant. Bear in mind that only changes in potential energy are associated with changes in kinetic energy (work energy theorem), and that temperature only describes the average internal kinetic energy in the gas.
Here’s the tricky part. In equilibrium, the density of the upper and lower layers, while not equal, cannot vary. Right? Which means that however many molecules move from the lower slice to the upper slice, exactly the same number of molecules must move from the upper slice to the lower slice. They have to have exactly the same velocity distribution moving in either direction. If the molecules below had a higher temperature, they’d have a different MB [Maxwell-Boltzmann] distribution, with more molecules moving faster. Some of those faster moving molecules would have the right trajectory to rise to the interface (slowing, sure) and carry energy from the lower slice to the upper. The upper slice (lower temperature) has fewer molecules moving faster — the entire MB distribution is shifted to the left a bit. There are therefore fewer molecules that move the other way at the speeds that the molecules from the lower slice deliver (allowing for gravity). This increases the number of fast moving molecules in the upper slice and decreases it in the lower slice until the MB distributions are the same in the two slices and one accomplishes detailed balance across the interface. On average, just as many molecules move up, with exactly the same velocity/kinetic energy profile, as move down, with zero energy transport, zero mass transport, and zero alteration of the MB profiles above and below, only when the two slices have the same temperature. Otherwise heat will flow from the hotter (right-shifted MB distribution) to the colder (left-shifted MB distribution) slice until the temperatures are equal.
It’s an interesting argument. Here’s my elevator speech version.
• Suppose we have an isolated container of air which is warmer at the bottom and cooler at the top. Any random movement of air from above to below a horizontal slice through the container must be matched by an equal amount going the other way.
• On average, that exchange equalizes temperature, moving slightly warmer air up and slightly cooler air down.
• Eventually this gradual exchange must lead to an isothermal condition.
I encourage people to read the rest of his comment.
Now, I see where I went wrong. Following the logic of my question to Dr. Brown, I incorrectly thought the final equilibrium arrangement would be where the average energy per molecule was evenly spread out from top to bottom, with the molecules having the same average total energy everywhere. This leads to warmer temperature at the bottom and colder temperature at elevation. Instead, at thermal equilibrium, the average energy per volume is the same from top to bottom, with every cubic metre having the same total energy. To do that, the gas needs to be isothermal, with the same temperature in every part.
Yesterday, I read the Jelbring hypothesis again. As I was reading it, I wondered by what logic Jelbring had come to the conclusion that the atmosphere would not be isothermal. I noticed the following sentence in Section 2.2 C (emphasis mine):
The energy content in the model atmosphere is fixed and constant since no energy can enter or leave the closed space. Nature will redistribute the contained atmospheric energy (using both convective and radiative processes) until each molecule, in an average sense, will have the same total energy. In this situation the atmosphere has reached energetic equilibrium.
He goes on to describe the atmosphere in that situation as taking up the dry adiabatic lapse rate temperature profile, warm on the bottom, cold on top. I had to laugh. Jelbring made the exact same dang mistake I made. He thinks total energy evenly distributed per molecule is the final state of energetic equilibrium, whereas the equilibrium state is when the energy is evenly distributed per volume and not per molecule. This is the isothermal state. In Jelbrings thought experiment, contrary to what he claims, the entire atmosphere of the planet would end up at the same temperature.
In any case, there’s another way to show that the Jelbring hypothesis violates conservation of energy. Again it is a proof by contradiction, and it is the same argument that I presented to Jelbring years ago. At that time, I couldn’t say why his “gravito-thermal” hypothesis didn’t work … but I knew that it couldn’t work. Now, I can see why, for the reasons adduced above. In addition, in his thread Dr. Brown independently used the same argument in his discussion of the Jelbring hypothesis. The proof by contradiction goes like this:
Suppose Jelbring is right, and the temperature in the atmosphere inside the shell is warmer at the bottom and cooler at the top. Then the people living in the stygian darkness inside that impervious shell could use that temperature difference to drive a heat engine. Power from the heat engine could light up the dark, and provide electricity for cities and farms. The good news for perpetual motion fans is that as fast as the operation of the heat engine would warm the upper atmosphere and cool the lower atmosphere, gravity would re-arrange the molecules once again so the prior temperature profile would be restored, warm on the bottom and cold on the top, and the machine would produce light for the good citizens of Stygia … forever.
As this is a clear violation of conservation of energy, the proof by contradiction that the Jelbring hypothesis violates the conservation of energy is complete.
Let me close by giving my elevator speech about the Jelbring hypothesis. Hans vigorously argues that no such speech is possible, saying
There certainly are no “Elevator version” of my paper which is based on first principal physics. It means that what I have written is either true or false. There is nothing inbetween.
Another “gravito-thermal” theorist, Ned Nikolov, says the same thing:
About the ‘elevator speech’ – that was given in our first paper! However, you apparently did not get it. So, it will take far more explanation to convey the basic idea, which we will try to do in Part 2 of our reply.
I don’t have an elevator speech for the Nikolov & Zeller theory (here, rebuttal here) yet, because I can’t understand it. My elevator speech for the Jelbring hypothesis, however, goes like this:
• If left undisturbed in a gravity field, a tall container of air will stratify vertically, with the coolest air at the top and the warmest air at the bottom.
• This also is happening with the Earth’s atmosphere.
• Since the top of the atmosphere cannot be below a certain temperature, and the lower atmosphere must be a certain amount warmer than the upper, this warms the lower atmosphere and thus the planetary surface to a much higher temperature than it would be in the absence of the atmosphere.
• This is the cause of what we erroneously refer to as the “greenhouse effect”
Now, was that so hard? It may not be the best, I’m happy to have someone improve on it, but it covers all the main points. The claim that “gravito-thermal” theories are too complex for a simple “elevator speech” explanation doesn’t hold water.
But you can see why such an elevator speech is like garlic to a vampire, it is anathema to the “gravito-thermal” theorists—it makes spotting their mistakes far too easy.
w.

Willis Eschenbach says:
January 20, 2012 at 3:18 pm
Does anyone really, in their heart of hearts, regardless of the logic of any and all arguments, believe that we can constantly and unceasingly pull energy out of a thermally insulated column of air?
Because make no mistake about it. That is what Hans Jelbring is claiming
Gravity != energy
Einstein! Help!
Houston, we have a problem. A quick trawl around the net reveals at least five conflicting second laws of thermodynamics.
Science != Settled
rwemyss says:
January 20, 2012 at 1:29 pm
“@Hans Willis is NOT indicating the heat engine will REMOVE energy from the system! He is indicating that the temperature difference used to run the heat engine can do work on the fluid in the system, and infinitely do so per the theory. Hence the theory fails.”
My paper deals with the properties of ideal gases inclosed in two sperical shells. I don´t know how Willis is going to construct a perpetuum mobile with the aid of ideal gases only since he has never told me. Ask him that.
I have already pointed out that a “perpetuum mobile” is possible to construct in our real atmosphere since the cold air at the top of Mount Everest for sure is colder than air at the surface.
Elevator speech.
An atmosphere currently in motion driven by solar surface radiance and TOA atmosphere radiance. Lots of convection. Seeking equilibrium
Night comes convection greatly slows but does not stop because TOA atmosphere radiance continues.
You also get an inversion layer at the surface due to the surface being a better radiator and cooling the atmosphere some by conduction without the aid of convection but with the aid of residuals of convection, the wind.
Enter Jelbring and and he waves his magic wand and stops the TOA atmosphere radiance to space. He also stops surface interactions with the bottom of the atmosphere or any input or output to the atmosphere.
He is allowed to do this by virtue of basic math where you are allowed to do this conceptually by subtracting equal amounts from both sides of an equation and the laws of thermodynamics specifies incoming must equal outgoing.
Now with nothing to drive it convection rapidly stops probably within hours. The atmosphere is left with a temperature gradient.
So if this is wrong evidence should be given of a force to continue convection without cooling going up or warming going down, or alternatively if it is acknowledged that no force exists to continue convection; where does the energy go or come from to cool the lower atmosphere and warm the upper atmosphere to an isothermal equilibrium.
I am curious about this force. What is it and where does it come from?
Robert Clemenzi says:
January 20, 2012 at 1:36 pm
” The only way to transfer heat to space is via radiation, and the only way for the atmosphere to loose heat to space is to have greenhouse gases that radiate energy”.
Wrong. Don´t you think that salt particles, droplets (clouds), and dust particles emits IR from the atmosphere. You might also have heard about lightning.
Certainly gravity does not produce thermal energy per se. But it behooves those who contend that a gravity-bound atmosphere devoid of GHGs would be completely isothermal to explain what then happens to temperature at TOA. Sound physics is not just a simple matter of mathematically pursuing a priori concepts to logical extremes. I’m throwing this on the pile for discussion by others, because I’ll not have any free time next week.
small correction to above elevator speech. The sun stops shining and an inversion layer comes to the cusp of forming when Jelbring waves his magic wand. I want to avoid having a layer actually form and then have to wait for the inversion layer to conduct through the atmosphere which would be a lot more than a few hours.
Stephen Rasey says:
January 20, 2012 at 2:01 pm
RE: Jelbring at 12:15 pm
“You criticize my use of elevator speech (or verbal proof, take your pick) without addressing its conclusion. You say that there should be two different lapse rates, then go on to say something about equal masses. I never specified equal masses, in fact with two different gasses, with different Cp and probably ….”
The ponit is that an adiabatic lapse rate is equivalent to the statement “that any two arbitrarily choosen equal massues” wihtion the closed sysem will contain equal energy regardless at which altitude they are situated.
I am sorry if I have been unclear in my wording.
Bart,
You mean besides every textbook in the world about atmospheric radiation? Let’s look at two examples:
Atmospheric Radiation: Theoretical Basis, Goody, R.M. & Yung, Y.L. p31.
A First Course in Atmospheric Radiation, Second Edition, Petty, G.W. , p126
What you have asserted and both references reject is that LTE does not exist for any real object. If LTE did not exist, the the Planck source function would not apply. But you have only asserted this with absolutely no evidence or support. If you were correct, then buying an IR thermometer would be pointless. But you’re wrong and IR thermometers, which use SB, work.
Stephen Wilde says:
January 20, 2012 at 3:25 pm
Gravity does not separate by temperature. It separates by mass.
This is what I meant, but here said more succinctly..
Jelbring, Nikolov and Zeller (and me) accept that in the absence of an energy source the column will become isothermal.
It is only when energy is added that the temperature gradient forms as a result of more densely packed molecules converting a greater proportion of the incoming radiation to kinetic energy.
But, gravity here is the energy source if pressure is an energy creating heat, if pressure is energy and gravity creates it, then as long as there is gravity, which has different pressures at different heights, then there is a temp differential and if there is a temp differential we get movement, right?.
As colder molecules at the top cool down they will sink, not because they are colder, but because they are now more dense and heavier than the molecules beneath which are hotter, and which being hotter are rising anyway. The pull of gravity now on the denser colder causes them to heat up, there are winds which show this principle, they are also increasing pressure on the warmer beneath which will warm them further/ displace them.
It seems to me that it is only a matter of getting the balance right, the colder top has to be cold enough and at the optimum height re the amount of gravity available not to warm up to a degree that will upset the cooling and sinking as molecules give up their heat to become colder and denser.
Gravity, it seems to me, is as near dammit perpetual motion as long as the optimum conditions can be maintained because it is then a constant force as source of energy, is energy since energy does work – just ‘cos it sits around looking as if its not doing anything…
And I’ve just had a thought, much like those sealed terrariums – the water recycles.
I’ve just had a look to see what I could find on pressure and compression and found this:
“You’ll find an equation used to relate temperature and pressure, which is the 3’rd equation under the heading. Temperature is in absolute (ie: Rankin or Kelvin) and pressure is also absolute, not gage pressure. The exponent n should be 1 for a case where there is so much heat transfer that the air stays at constant temperature, and 1.4 for a case where there is no heat transfer at all. The real case of compressing air in a cylinder by applying a piston and doing work on the air will be somewhere in between because there will be some heat transfer, but not isothermal conditions. ” http://www.physicsforums.com/showthread.php?t=212327
Isn’t that what the force of gravity is doing just by being itself?
PeterGeorge says:
January 20, 2012 at 3:06 pm
You seem to be religous pretending to be reasoning by a chain of unvalid logic. Please, read the G&T falsification paper or Willian Gilbert on the Tallbloke blog.
Would Jelbring’s theory predict a measurable difference in temperature for a feasible version of the following setup? Take a tube of gas, place a thermometer at the bottom and at the top, place it in a centrifuge with the bottom facing outwards, and spin it up.
p.s. meant to say Ta, Mods!
Willis:
Your initial statement: ‘Consider a gas in a kilometre-tall sealed container.” Assuming a tall, sealed container that is not free to expand, it makes no difference whether it is laid on its side or vertical. The pressure will be the same throughout the container: top to bottom, regardless of gravity. Assuming no outside input and at equilibrium, then according to the equation: P1V1/T1 = P2V2/T2, then the temperature would be the same throughout as well. It cannot possibly be anything else. The pressure at the bottom of the container will be no different to the pressure at the top. In this situation, pressure differential between the inside and outside of the container will increase with vertical height, but the pressure inside the sealed container will not change. So a tall, sealed container might sound reasonable, but cannot be representative of the atmospheric situation. For imaginative purposes, the container needs to be free to expand over its entire length.
Assume the container weighs nothing, contains a portion of atmosphere and is free to expand and contract thoughout its entire length. In this case, the result will look something like a huge weather balloon prior to launch with the dense gas towards the end closest to the gravity source and the expanded end furthest from the gravity. If position 1 is at the lowest end of the bag and position 2 is at the highest end of the bag, then I would assume that without outside input, the reduction of pressure from P1 to P2 would be negated by an equal increase in volume from V1 to V2. There would be no change in temperature…isothermal. In the situation of the sun heating the earth’s surface…well that is a subject for another discussion.
Myrrh says:
January 20, 2012 at 3:03 pm
And therein lies the problem, that you’re talking about perpetual motion and you don’t know it. Hans, you are indeed proposing perpetual motion. You are saying that gravity separates the warm and cold molecules.
Your lasr sentence is correct. The reason is that maximum entropy or the second law of thermodynamics has to be applied when a gravity field is at work and we are studying a insulated inclosed atmosphere as defined in my E&E paper. Yes, the consequences are tremendous.
Hans Jelbring said @ur momisugly January 20, 2012 at 4:43 pm
I get my suntan from UV radiation. Where is this fairytale land that enables one to get a suntan from IR radiation? Or are you just saying whatever pops into your head because you know the ignoramuses will believe whatever you say? Sorry if this is rude, but the difference between UV & IR is really basic stuff!
[Mods, you overworked & underpaid paragons of all that is virtuous, this is my third attempt at posting. If the two previous are stuck in the spam filter, please delete them]
Stephen Wilde says:
January 20, 2012 at 3:25 pm
Gravity does not separate by temperature. It separates by mass.
“Jelbring, Nikolov and Zeller (and me) accept that in the absence of an energy source the column will become isothermal.”
I certainly disagree. The temperature lapse rate will be DALR which is equivalent to equal amount of energy in arbrarily equal masses if the system is insulated.
Bart,
A lone molecule that isn’t colliding with other molecules isn’t in LTE and would most likely be in the ground state so of course it wouldn’t emit. A satellite, if charged, would only emit cyclotron radiation based on its velocity and radial acceleration. That wouldn’t be much because the acceleration is low. The molecules in the atmosphere it collides with. though, is a different matter entirely. Satellites re-entering the atmosphere create temperatures high enough to ionize the air and create a plasma.
Trick says:
January 20, 2012 at 3:33 pm
Willis says at 1/20 2:19pm:
“I say the column will be isothermal, meaning all at the same temperature top to bottom.”
“This violates the 2nd law, KE + PE = constant at each h in the presence of an inexplicable gravity field in the gaseous cv of interest, namely an adiabatic (no gain or loss of heat from CV) GHG-free air column.”
Many thanks for your insight.
.
DeWitt says at 1/20 4:51pm –
“That doesn’t look like the Second Law to me.”
My view is you’re right DeWitt, I’m mixing my metaphors – taking a mechanical conservation of energy knife into a thermo gun fight. My view is employing conservation of energy works here in thermo, I think of 2nd law as conservation of energy. Violating energy conservation whatsoever to create energy collapses a thermo or mechanical issue – especially useful to collapse proposals for perpetual motion machines of the 2nd kind.
DeWitt continues –
“So the Second Law requires that when work isn’t being done on the atmosphere by circulation between areas on the surface at different temperature (ruled out by the definition of the problem), it becomes isothermal.”
This might be true! – & you’re right, ruled out here since it expands the cv of interest to include a surface at different temperature. For the adiabatic GHG-gas column in the presence of gravity, there is no cooler surface exchanging heat with it. That’s where this gun fight might need to go once the simple adiabatic GHG-free gas column in the presence of inexplicable gravity gets general agreement about whether or not it is isothermal (if ever, the age of the universe may come into play). If it does, some agreement will no doubt be grudging, esp. me if isothermal! Then progress discussion to add a surface conducting & radiating heat into the CV with a radiating sink to space.
Turn off the inexplicable gravity in the cv of interest, no pressure stratification occurs and get isothermal PV=nRT everywhere in the gas. KE + 0 = constant everywhere. Turn on inexplicable gravity field and the pesky PE (n*g*h) term inexplicably appears & need to show KE + PE = constant everywhere in the cv or machine of interest.
Phil. says:
January 20, 2012 at 5:02 pm
“…the only way that conduction can reduce the radiation loss from the surface is by cooling the surface.”
No, that is not the only way. Stefan-Boltzmann is an equilibrium relationship. You do not know the radiation loss from the surface in non-equilibrium conditions.
You know, it is really annoying when someone proclaims they know everything about a phenomenon which is actively under investigation.
Bill Hunter says:
January 20, 2012 at 5:20 pm
“I am curious about this force. What is it and where does it come from?”
Let´s say that you inclose and isoöate the atmosphere at an arbirary time when there is wind, lightning, rain tornados etc.
Agree with me that there is a certain total energy inclosed that is constant (1:st law)
Wait a month to see what happens. The second law of thremodynamics will make sure that the entropy get maximised. At that moment the adiabatic temperature has to be -g/Cp.
It is simple!
With respect, Fred, your starting statement is just plain mistaken.
Ask yourself, what Newtonian force exerts lift upon a helium-filled balloon? Neglecting the weight of the helium (which is far lighter than the air it displaces), the net force on the balloon simply the (lesser) downward force exerted by the lower atmospheric pressure at the top surface of the balloon, relative to the (greater) upward force exerted by the larger atmospheric pressure at the bottom surface of the balloon. After all, what other force is acting upon the balloon?
More generally, what is dismaying about the WUWT posts on this topic is not the errors, but rather the wholly misplaced confidence of many WUWT posters in their erroneous reasoning; a misplaced confidence that dismayingly tends to persist even when serious mistakes in physical reasoning are pointed out.
WUWT has begun to attract criticism in this regard, see for example the scathing editorial Climate Warming Skeptics Ditch the Second Law of Thermodynamics.
It’s time for WUWT folks to accept the possibility — so great as to amount to an plain fact — that “gravito-thermal” theories have just plain got their thermodynamics wrong.
Bart,
Sorry, it isn’t equally plausible. The surface temperature would be limited by the brightness temperature of the incoming radiation or you violate the Second Law. You don’t get to have high absorptivity and low emissivity at the same wavelength. The only way that a surface couldn’t be in LTE is if the temperature is increasing (or decreasing) extremely rapidly. Not to mention that the original problem in A Matter of Some Gravity stated that the surface of the ‘planet’ was a blackbody.
If it’s plausible, then you should be able to provide examples of solid or liquid materials that don’t obey a Planck source function at 255K and above rather than just postulate their existence.
DeWitt Payne says:
January 20, 2012 at 5:34 pm
“…is obeyed for the levels under consideration.”
“For all common applications in atmospheric radiation…”
“But you’re wrong and IR thermometers, which use SB, work [on the Earth in normal conditions].”
So, all of these things hold in a quasi-equlibrium environment. Who’da thunk it?