Perpetuum Mobile

Guest Post by Willis Eschenbach

Since at least the days of Da Vinci, people have been fascinated by perpetual motion machines. One such “perpetuum mobile” designed around the time of the civil war is shown below. It wasn’t until the development of the science of thermodynamics that it could be proven that all such mechanisms are impossible. For such machines to work, they’d have to create energy, and energy cannot be either created or destroyed, only transformed.

Image Source

I bring this up for a curious reason. I was reading the Jelbring hypothesis this afternoon, which claims that greenhouse gases (GHGs) are not the cause of the warming of the earth above the theoretical temperature it would have without an atmosphere. Jelbring’s hypothesis is one of several “gravito-thermal” theories which say the heating of the planet comes from gravity rather than (or in some theories in addition to) the greenhouse effect. His thought experiment is a planet with an atmosphere. The planet is isolated from the universe by an impervious thermally insulating shell that completely surrounds it, and which prevents any energy exchange with the universe outside. Inside the shell, Jelbring says that gravity makes the upper atmosphere colder and the lower atmosphere warmer. Back around 2004, I had a long discussion on the “climateskeptics” mailing list with Hans Jelbring. I said then that his theory was nothing but a perpetual motion machine, but at the time I didn’t understand why his theory was wrong. Now I do.

Dr. Robert Brown has an fascinating post on WUWT called “Earth’s baseline black-body model – a damn hard problem“. On that thread, I had said that I thought that if there was air in a tall container in a gravity field, the temperature of the air would be highest at the bottom, and lowest at the top. I said that I thought it would follow the “dry adiabatic lapse rate”, the rate at which the temperature of dry air drops with altitude in the earth’s atmosphere.

Dr. Brown said no. He said that at equilibrium, a tall container of air in a gravity field would be the same temperature everywhere—in other words, isothermal.

I couldn’t understand why. I asked Dr. Brown the following question:

Thanks, Robert, With great trepidation, I must disagree with you.

Consider a gas in a kilometre-tall sealed container. You say it will have no lapse rate, so suppose (per your assumption) that it starts out at an even temperature top to bottom.

Now, consider a collision between two of the gas molecules that knocks one molecule straight upwards, and the other straight downwards. The molecule going downwards will accelerate due to gravity, while the one going upwards will slow due to gravity. So the upper one will have less kinetic energy, and the lower one will have more kinetic energy.

After a million such collisions, are you really claiming that the average kinetic energy of the molecules at the top and the bottom of the tall container are going to be the same?

I say no. I say after a million collisions the molecules will sort themselves so that the TOTAL energy at the top and bottom of the container will be the same. In other words, it is the action of gravity on the molecules themselves that creates the lapse rate.

Dr. Brown gave an answer that I couldn’t wrap my head around, and he recommended that I study the excellent paper of Caballero for further insight. Caballero discusses the question in Section 2.17. Thanks to Dr. Browns answer plus Caballero, I finally got the answer to my question. I wrote to Dr. Brown on his thread as follows:

Dr. Brown, thank you so much. After following your suggestion and after much beating of my head against Caballero, I finally got it.

At equilibrium, as you stated, the temperature is indeed uniform. I was totally wrong to state it followed the dry adiabatic lapse rate.

I had asked the following question:

Now, consider a collision between two of the gas molecules that knocks one molecule straight upwards, and the other straight downwards. The molecule going downwards will accelerate due to gravity, while the one going upwards will slow due to gravity. So the upper one will have less kinetic energy, and the lower one will have more kinetic energy.

After a million such collisions, are you really claiming that the average kinetic energy of the molecules at the top and the bottom of the tall container are going to be the same?

What I failed to consider is that there are fewer molecules at altitude because the pressure is lower. When the temperature is uniform from top to bottom, the individual molecules at the top have more total energy (KE + PE) than those at the bottom. I said that led to an uneven distribution in the total energy.

But by exactly the same measure, there are fewer molecules at the top than at the bottom. As a result, the isothermal situation does in fact have the energy evenly distributed. More total energy per molecules times fewer molecules at the top exactly equals less energy per molecule times more molecules at the bottom. Very neat.

Finally, before I posted my reply, Dr. Brown had answered a second time and I hadn’t seen it. His answer follows a very different (and interesting) logical argument to arrive at the same answer. He said in part:

Imagine a plane surface in the gas. In a thin slice of the gas right above the surface, the molecules have some temperature. Right below it, they have some other temperature. Let’s imagine the gas to be monoatomic (no loss of generality) and ideal (ditto). In each layer, the gravitational potential energy is constant. Bear in mind that only changes in potential energy are associated with changes in kinetic energy (work energy theorem), and that temperature only describes the average internal kinetic energy in the gas.

Here’s the tricky part. In equilibrium, the density of the upper and lower layers, while not equal, cannot vary. Right? Which means that however many molecules move from the lower slice to the upper slice, exactly the same number of molecules must move from the upper slice to the lower slice. They have to have exactly the same velocity distribution moving in either direction. If the molecules below had a higher temperature, they’d have a different MB [Maxwell-Boltzmann] distribution, with more molecules moving faster. Some of those faster moving molecules would have the right trajectory to rise to the interface (slowing, sure) and carry energy from the lower slice to the upper. The upper slice (lower temperature) has fewer molecules moving faster — the entire MB distribution is shifted to the left a bit. There are therefore fewer molecules that move the other way at the speeds that the molecules from the lower slice deliver (allowing for gravity). This increases the number of fast moving molecules in the upper slice and decreases it in the lower slice until the MB distributions are the same in the two slices and one accomplishes detailed balance across the interface. On average, just as many molecules move up, with exactly the same velocity/kinetic energy profile, as move down, with zero energy transport, zero mass transport, and zero alteration of the MB profiles above and below, only when the two slices have the same temperature. Otherwise heat will flow from the hotter (right-shifted MB distribution) to the colder (left-shifted MB distribution) slice until the temperatures are equal.

It’s an interesting argument. Here’s my elevator speech version.

• Suppose we have an isolated container of air which is warmer at the bottom and cooler at the top. Any random movement of air from above to below a horizontal slice through the container must be matched by an equal amount going the other way.

• On average, that exchange equalizes temperature, moving slightly warmer air up and slightly cooler air down.

• Eventually this gradual exchange must lead to an isothermal condition.

I encourage people to read the rest of his comment.

Now, I see where I went wrong. Following the logic of my question to Dr. Brown, I incorrectly thought the final equilibrium arrangement would be where the average energy per molecule was evenly spread out from top to bottom, with the molecules having the same average total energy everywhere. This leads to warmer temperature at the bottom and colder temperature at elevation. Instead, at thermal equilibrium, the average energy per volume is the same from top to bottom, with every cubic metre having the same total energy. To do that, the gas needs to be isothermal, with the same temperature in every part.

Yesterday, I read the Jelbring hypothesis again. As I was reading it, I wondered by what logic Jelbring had come to the conclusion that the atmosphere would not be isothermal. I noticed the following sentence in Section 2.2 C (emphasis mine):

The energy content in the model atmosphere is fixed and constant since no energy can enter or leave the closed space. Nature will redistribute the contained atmospheric energy (using both convective and radiative processes) until each molecule, in an average sense, will have the same total energy. In this situation the atmosphere has reached energetic equilibrium. 

He goes on to describe the atmosphere in that situation as taking up the dry adiabatic lapse rate temperature profile, warm on the bottom, cold on top. I had to laugh. Jelbring made the exact same dang mistake I made. He thinks total energy evenly distributed per molecule is the final state of energetic equilibrium, whereas the equilibrium state is when the energy is evenly distributed per volume and not per molecule. This is the isothermal state. In Jelbrings thought experiment, contrary to what he claims, the entire atmosphere of the planet would end up at the same temperature.

In any case, there’s another way to show that the Jelbring hypothesis violates conservation of energy. Again it is a proof by contradiction, and it is the same argument that I presented to Jelbring years ago. At that time, I couldn’t say why his “gravito-thermal” hypothesis didn’t work … but I knew that it couldn’t work. Now, I can see why, for the reasons adduced above. In addition, in his thread Dr. Brown independently used the same argument in his discussion of the Jelbring hypothesis. The proof by contradiction goes like this:

Suppose Jelbring is right, and the temperature in the atmosphere inside the shell is warmer at the bottom and cooler at the top. Then the people living in the stygian darkness inside that impervious shell could use that temperature difference to drive a heat engine. Power from the heat engine could light up the dark, and provide electricity  for cities and farms. The good news for perpetual motion fans is that as fast as the operation of the heat engine would warm the upper atmosphere and cool the lower atmosphere, gravity would re-arrange the molecules once again so the prior temperature profile would be restored, warm on the bottom and cold on the top, and the machine would produce light for the good citizens of Stygia   … forever.

As this is a clear violation of conservation of energy, the proof by contradiction that the Jelbring hypothesis violates the conservation of energy is complete.

Let me close by giving my elevator speech about the Jelbring hypothesis. Hans vigorously argues that no such speech is possible, saying

There certainly are no “Elevator version” of my paper which is based on first principal physics. It means that what I have written is either true or false. There is nothing inbetween.

Another “gravito-thermal” theorist, Ned Nikolov, says the same thing:

About the ‘elevator speech’ – that was given in our first paper! However, you apparently did not get it. So, it will take far more explanation to convey the basic idea, which we will try to do in Part 2 of our reply.

I don’t have an elevator speech for the Nikolov & Zeller theory (here, rebuttal here) yet, because I can’t understand it. My elevator speech for the Jelbring hypothesis, however, goes like this:

• If left undisturbed in a gravity field, a tall container of air will stratify vertically, with the coolest air at the top and the warmest air at the bottom.

• This also is happening with the Earth’s atmosphere.

• Since the top of the atmosphere cannot be below a certain temperature, and the lower atmosphere must be a certain amount warmer than the upper, this warms the lower atmosphere and thus the planetary surface to a much higher temperature than it would be in the absence of the atmosphere.

• This is the cause of what we erroneously refer to as the “greenhouse effect”

Now, was that so hard? It may not be the best, I’m happy to have someone improve on it, but it covers all the main points. The claim that “gravito-thermal” theories are too complex for a simple “elevator speech” explanation doesn’t hold water.

But you can see why such an elevator speech is like garlic to a vampire, it is anathema to the “gravito-thermal” theorists—it makes spotting their mistakes far too easy.

w.

Get notified when a new post is published.
Subscribe today!
5 1 vote
Article Rating
911 Comments
Inline Feedbacks
View all comments
A physicist
January 20, 2012 8:53 am

Yet another elevator argument for isothermal (same temperature) atmospheric equilibrium is as follows: we imagine a very tall (10 km tall) thermopile column (a device that converts temperature differences to electricity), and we insulate the body thermopile column so that only its top and bottom exchange heat with the atmosphere.
Now supposing that the upper air is colder than the lower air, our thermopile generates electric power continuously and forever, with no external source of power. Which is impossible. And so we conclude that, at equilibrium, the entire atmosphere must be at one temperature.
Of course, in the real world, such a thermopile column would generate electricity. And this electricity would constitute (ultimately) a form of solar power, deriving from sunlight acting to warm the earth, thus creating rising thermals that stir the atmosphere, creating a temperature gradient that the thermopile can exploit.
This is one more line of reasoning showing that the isothermal folks have got the thermodynamics right.

Hans Jelbring
January 20, 2012 9:03 am

Tim Folkerts says:
January 20, 2012 at 6:20 am
“You are starting from a wrong hypothesis. My first thought was also that this might be the equilibrium condition, but a bit of actual study of the issue made it clear this is wrong”
If you read my E&E, 2003 carefully you will realize that it is based on two major assumptions and these are:
1) The first law of thermodynamics and
2) Second law of thermodynamics.
The application of these laws in the thought experiments leads to a constant energy content in any two equal submasses of the inclosed insulated atmospherea after relaxation time has passed (approximately 2 weeks).
This was not declared explicitly in the text since it was a topic I wanted to debate but few scientists wanted such a debate. It took 8 eyars for the debate to flourish. Do notice that these laws apply to energy and not temperature.

Man_Tran
January 20, 2012 9:04 am

In all the posts I have scanned, with the possible exception of Joe Born, no one seems to be looking at the extreme case of the very top of the air column. Pick an arbitrary altitude where one N2 diatom is occupying one cubic meter of near vacuum (1 km^3?). What is its PE, KE, freq, temperature? Does it just pop off to space? I think that coming from that direction the argument quickly gets to ‘turtles all the way down.’

Jim G
January 20, 2012 9:06 am

” For such machines to work, they’d have to create energy, and energy cannot be either created or destroyed, only transformed.”
This is another conventional wisdom based upon the incomplete information available at this time. Where did all the matter and energy that exists today come from? I guess if you buy one of the oscillating universe theories, it has always existed. Or in the multiple universe theories it may have been “transferred” through collision with another universe or leaked into our universe. But it could have been created as well. The how or from where or Whom of the potential “big bang” is as yet not explained by science.

pochas
January 20, 2012 9:08 am

Tim Folkerts says:
January 20, 2012 at 8:43 am
“Process 2 [thermal conduction] will continue as long as there is any temperature gradient.”
Well said, Tim

January 20, 2012 9:11 am

“More total energy per molecules times fewer molecules at the top exactly equals less energy per molecule times more molecules at the bottom. Very neat.”

Except that more of the total energy of the molecules at the top is locked up in gravitational potential as opposed to being available as kinetic energy capable of generating heat in collisions.

Except that you meant to say not. Not locked up. How can I put this gently, firmly, and understandably.
How about temperature has nothing to do with gravitational potential energy.
Look, if you want to comment on thermodynamics and temperature, learn what temperature is and what it isn’t.
As far as an ideal gas — the kind considered throughout this discussion, including by Jelbring and N&Z — is concerned, temperature is a direct measure of the average kinetic energy of a molecule of the gas. Note well, I did not say average potential energy and I certainly did not say average total energy or a jar of matter would get hotter or colder every time we lift it or lower it. Here, let me chill my beer by picking it up off of the table and lifting it to my mouth. No.
Please, please, please. Buy an introductory physics textbook that has a halfway decent thermodynamics section. Pretty please with sugar on top. I beg you. Read it.
Look, you have a choice. Either you can pretend that the Laws of Thermodynamics don’t exist and reinvent them at will, making up a brand new definition of the word “temperature” and pretending that your definition will still work to describe things like equilibrium, the flow of heat and entropy, ideal gases, and so on, or you can learn the ones that we already have. Personally, I think your contributions to the discussion would be better if you did the latter, but suit yourself.
Note well, however, that you will not, and should not, be taken seriously if you assert that temperature of a monatomic ideal gas is related to anything but:
U = 3/2 NkT = 1/2 Nm v^2_avg.
or, “the total internal energy of the gas is equal to the number of degrees of freedom times kT per molecule”, for three — note well, three degrees of freedom. Gravitational potential energy is not a degree of freedom, and if it were it still wouldn’t affect equipartition of energy so kinetic energy is a different one.
rgb

Hans Jelbring
January 20, 2012 9:13 am

Paolo M. says:
January 20, 2012 at 6:40 am
I am not sure you understand what “potential temperature” actually means. It is a misnomer, at least within the science of meteorology. The meaning is actually constant total energy per mass unit. This state will be be found almost every sunny day above land from the surface up to 1000-4000 m or more. It is best devoloped about 1 hour before sunset. The observational evidence for its existence is just overwhelming.
Another way to put is that at such occations the measured dry adiabatic temperature lapse rate will be very close to -g/Cp or -9.8 K/km (no clouds allowed).

Robany
January 20, 2012 9:20 am

I’ve been trying to wrap my head around the thermodynamic arguments for the last few days. The isothermal column of air argument seems to have some problems:
1) The atmosphere has a measurable temperature gradient. An argument that suggests it should be isothermal seems to immediately be falsified by contradiction.
2) Although it’s an equilibrium system overall it is not in thermal equilibrium. We are discussing a system that has a constant energy input (insolation through a transparent atmosphere) at the bottom where the planet’s surface forces a boundary condition on the temperature of the air at sea level. If the planet/atmosphere system is not to heat up then the energy output at the top of atmosphere must match the input. Therefore there must be a flow of energy from the planet’s surface to the TOA and this can only occur if the atmosphere has a temperature gradient and thus is not in thermal equilibrium.
Or have I missed something basic?

Tim Folkerts
January 20, 2012 9:20 am

Hans asks me “Do you recognize your fallacy? ”
I recognize your point. But I think it is not quite the fallacy you think it is. I am saying that even a single person who knows what they are doing has applied the principles of known science. He/she has a “proof” (actually several proofs) that the temperature profile must be uniform for the conditions given (and assuming that “textbook thermodynamics” is correct) . That proof has been checked by others to make sure there is no error. This is more akin to “spell-checking” than “consensus”. We now have a new addition to “textbook physics”. (Actually, this is very OLD textbook physics.)
To counter this proof, you need to show a specific error. Maybe there was a sign error. Maybe they took a partial derivative incorrectly. Maybe you can show that a perpetual motion machine IS possible and the 2nd law of thermodynamics IS NOT correct. But if we simply throw back and forth intuition or soundbites, this will not cut it (from either side).
PS This is precisely why “consensus” in climate science is NOT so useful. In the case of the column of air, the situation is very well-defined, so it is easy to apply basic physics and come to a clear solution. For climate science, the situation is very poorly defined. There are sources and sinks of energy all over the place; there are feedbacks; there are continuing subtle changes in orbits, the initial conditions are not well known, etc. All of these mean that you have to include MANY factors in the calculations. This means a computer to determine the predicted affect.
And now there are MANY places for problems. Basically, each person studying climate can only say “I took into account as many of the affects as I could, and here is what I found”. There are (nearly) endless “what if” questions. There are (nearly) endless lines of code to check. This means that there will be considerable uncertainly in the results.
So it is “settled science” that “CO2 radiates IR well and will warm the surface”, because short, easily verified theories (and repeatable experiments) lead inexorably to that conclusion.
It is “settled science” that the air column will be isothermal, because short, easily verified theories (and repeatable experiments) lead inexorably to that conclusion.
It is not “settled science” that “doubling the CO2 levels will cause a 3.7 K increase in temperature” because there are so many other factors and feedbacks that nailing this number down precisely is a damn difficult problem.
PPS Of course, no science is ever 100% “settled”. Relativity showed that newtonian mechanics was not quite right. But overturning “settled science” requires extraordinary evidence. So far I have seen no “extraordinary evidence” that a perpetual motion machine is actually possible and that there could be a continued temperature gradient in a perfectly insulated air column.

Hans Jelbring
January 20, 2012 9:27 am

DR says:
January 20, 2012 at 6:58 am
” Does anyone else feel like they’ve been sold a lemon? Even here on WUWT,with the arguing going back and forth, the “theory” is no better explained or proven than it was 25 years ago. ”
No, I don´t feel like that since I have been fighting IPCC and its unscientifc statements since it was created. However, Willis is good at keeping the confusion alive which favours the IPCC organization.

Bryan
January 20, 2012 9:29 am

A physicist says:
“Yet another elevator argument for isothermal (same temperature) atmospheric equilibrium is as follows: we imagine a very tall (10 km tall) thermopile column (a device that converts temperature differences to electricity), and we insulate the body thermopile column so that only its top and bottom exchange heat with the atmosphere.”
Have you factored in the resistance of the 10km copper(lets say) leads to your thermopiles?
Once you use real thermopiles and realistic conductors you will realise why this experiment will not work.

January 20, 2012 9:34 am

Final overall comment and off to work.
First, there are actually two kinds of perpetual motion machines that people propose. They are called perpetual motion machines of the first and second kind.
Perpetual motion machines of the first kind violate the first law of thermodynamics. The perform work with no (net) input of energy at all, and thereby increase the mass-energy content of the Universe as they function. They thus violate a very, very basic physical principle as well as a law of thermodynamics.
Perpetual motion machines of second kind violate the second law of thermodynamics. No energy is created or destroyed, it is just moved around so it can be reused again and again.
Both are magic, and actual mythological magic can be classified identically — magic of the first kind is responsible for creating Universes out of nothing, turning lead into gold, and so on. Mass-energy violating magic. Magic of the second kind is more subtle — rising from the dead, healing the sick, walking on water. No energy is created or destroyed, these things are all technically possible, they are just enormously improbable.
Jelbring’s hypothesis enables one to create a perpetual motion machine of the second kind to light stygia. The work done by their Carnot cycle engine and turned into light eventually turns back into heat, so the total energy of Stygia remains unchanged. It is just re-sorted by gravity acting as a Maxwell’s Demon into separated hot and cold reservoirs so that it can be used once again to drive the generator to make more light. The same energy is made available over and over again.
It is this that should make your “horseshit” detectors give a ring. You would have to have been born yesterday to think that Nature gives you any sort of free lunch like that. That hasn’t stopped optimists from seeking PMMs of type 1 or 2, or physicists from proposing theories that violate the laws of thermodynamics, imagining that they are more like “suggestions” than actual laws. But they aren’t suggestions. They are common sense.
* Fact 1: One can run a heat engine between any two reservoirs of energy maintained at different temperatures. Proof: Every heat engine in the world, all of thermodynamic theory, massive engineering…
* Fact 2: Heat engines cannot run indefinitely. In a closed system, they cannot just take random energy in a complex environment and continuously turn it into work. Proof: It’s the second law of thermodynamics Kelvin statement, supported by enormous amounts of evidence and common sense. So much so that if anyone doubts it, I have a bridge that I’d like to sell them in Brooklyn, it should be worth a lot.
* Assertion Gravity sorts air in an adiabatically isolated environment out into hot air at the bottom and cold air at the top. This arrangement is thermodynamically stable and will spontaneously occur and be sustained.
* Argument If the assertion were true, then due to Fact 1, a heat engine placed in the container and run between the top and the bottom would run forever. As fast as it made the air at the top warmer, the heat would somehow “fall” back to the bottom, re-creating the thermal gradient that we know can drive all sorts of heat engines. This violates Fact 2.
* Conclusion The assertion is therefore false. It contradicts two everyday, well-known facts. Anybody who believes Jelbring’s conclusions is invited to make themselves infinitely wealthy, as they have just solved the energy crisis. Just don’t ask me to invest.

PeterGeorge
January 20, 2012 9:35 am

“Then the people living in the stygian darkness inside that impervious shell could use that temperature difference to drive a heat engine.”
Wrong. If this argument were correct we wouldn’t need to care about temperature differences. The perpetual motion machine could be driven be the pressure difference alone.
The people would create a massless container to send up and grab some of the low pressure air and bring it down to where the air is is at higher pressure. Then, they could use the pressure difference to drive an engine and do work. Right?
No, of course not. As they bring the massless container of lower pressure (and lower density) air from above it would become a lighter than air balloon. So, it would take work to force it down to the level of the high pressure air. That would negate work done by the pressure difference. No perpetual motion machine.
Couching the argument in terms of temperature doesn’t change the result.
IMhO, there is no way to answer this question about gravity and lapse rates without discussing entropy. Entropy is king. Every other result in thermodynamics – including Boltzman distributions and all the rest, derive from the principle of Equal Apriori Probabilities and the consequence that a system will, in time, inevitably migrate to the macrostate with maximum entropy.
If the isothermal macrostate has higher entropy, that’s where it will go. If a macrostate with a lapse rate has higher entropy, that is where the system will go.

Hans Jelbring
January 20, 2012 9:37 am

Spector says:
January 20, 2012 at 7:34 am
“For me this is a very simple issue:
4. An average surface power radiation of 396 W/m² can only continue with an atmosphere that can absorb a net 156 W/m² from the outgoing radiated power and return it to the surface.”
Any surface radiation power exceeding 100 W/m^2 is bull regardless if it is from equatorial, midlatitude or polar regions during days or night. Just show how this fantasy power radiation changes between day and night in polar regions as an exsample.

DeWitt Payne
January 20, 2012 9:39 am

Bart,
Your argument begs the question. Your postulate that the atmosphere must decrease in temperature with altitude assumes your conclusion. But it doesn’t have to decrease in temperature. The pressure and the density must decrease with altitude. But a transparent atmosphere is perfectly thermally insulated at the top. It can’t lose energy to space. If the surface is at constant temperature, then eventually, so will be the entire volume.
In the other thread you asked how to define the top of the atmosphere. Here’s a definition: The top of the atmosphere is the altitude which includes 99.9998% of the total mass of the atmosphere. That’s ~100km.
As pointed out above, your first crack at the capacitor example was correct. It’s a constant voltage source. Even a constant current source reverts to a constant voltage source at some voltage.

Joel Shore
January 20, 2012 9:40 am

OzWizard says:

N & Z have indeed produced a game-changer here and no thought experiment is needed to understand their ‘Unified Theory of Climate’. Simply stated, their hypothesis consists of their two key equations, (7) and (8).

All they have done is fit some data using a form with many free parameters: There are 4 free parameters in Equation (7) and that is not even including any freedom they may have exercised in choosing the fitting form, choosing how to define T_gb, or even which estimates of the average surface pressure and temperature of various bodies to use.
Hence, it is not surprising that they have fit the data. I got almost as good a fit to the data restricting myself to their particular fitting form when I change 3 of the data points (basically by changing the average temperature of the 3 planets that have a substantial radiative greenhouse effect so that their average temperature is taken to be the conventionally-determined blackbody temperature instead of the observed temperature).
And, that’s another point: Only 3 of the 8 celestial bodies they fit to have a significant radiative greenhouse effect and only for one of them, Venus, is it large enough to be the majority of their calculated surface temperature enhancement. Hence, they are not even fitting data for the greenhouse effect…They are mainly fitting to the effect that a planet can have a number of different average temperatures that are compatible with radiative balance…with airless planets having low average temperatures because of a wide temperature distribution and planets with more atmosphere having higher average temperatures.
One of the strange things about N&Z is how few people have investigated it well enough to even have the most primitive understanding of what they have done!

Frank
January 20, 2012 9:42 am

George Turner and WIllis: I’m interested in the idea of turning the tall cylinder of gas, but let’s start with a horizontal cylinder of gas, which should have the same temperature and pressure throughout its length. Let’s say the cylinder is 1 m2 in diameter, contains 10^4 kg of ideal gas (the same weight of gas as above ever m2 of the earth’s surface), and is 20 km/10 mb tall (99% of the atmosphere). Let’s imagine that there are barriers every meter that are closed during rotation and later opened, so we don’t have to worry about what happens during rotation. Alternatively. we can imagine piston barriers that will allow changes to be made reversibly or irreversibly before opening the barriers. What happens when we rotate the cylinder to vertical and open the barriers reversibly or irreversibly?
Based on what we know about our atmosphere, we can be confident that most of the gas will “fall” to the bottom of the cylinder, increasing the kinetic energy/temperature of the gas at the bottom of the cylinder and therefore it’s pressure (ideal gas law). It certainly seems to me that the cylinder MUST be cold on top and hot at the bottom after rotating. If we didn’t just violate the 2LoT by transferring heat by spontaneously creating a temperature gradient where one didn’t exist before (and I assume we didn’t), then we need to be careful about how we describe entropy in this system.
Alternatively, we could say that the gas at the high end expands under reduced pressure and the gas at the lower end is compressed under higher pressure. However, first we need to explain why the pressure on the gas has changed in these regions. We say the weight of the gas above contributed to the pressure on the gas below, but the gas in this cylinder HAD a pressure before it was rotated. Why is pressure in the vertical position defined by the weight of the gas above while pressure in the horizontal position was not? The answer is that pressure is not really created by the weight of the gas above, it arises (according to the kinetic theory of gases) from momentum transferred by collisions (to the walls of a container or whatever is measuring the pressure). We usually assume that motion in all three directions is ISOTROPIC, but in a gravitational field the speed of the molecules moving upward is slightly less that the speed of the molecules moving downward. The “weight of the gas above” appears to transferred downward by non-isotropic motion of the gas molecules in a gravitational field. (See Section 2.3 of your Caballero reference.)
In Brown’s explanation of molecules crossing a plane, he says that the molecules moving up and down :
“have to have exactly the same velocity distribution moving in either direction”
This statement appears to be incorrect. If there weren’t a velocity difference, the pressure at the top and bottom of the atmosphere would be identical. The molecules moving upward have very slightly less energy that the average for their altitude (given the local temperature) and those moving downward have slightly more energy. As they move past each other, they will create a temperature gradient.

DeWitt Payne
January 20, 2012 9:47 am

Can we lose the argument that the collision rate, i.e. pressure, has an effect on measured temperature. It doesn’t. A thermometer in contact with a gas at temperature T at low pressure will simply take longer to equilibrate than a thermometer in contact with a gas at the same temperature but higher pressure.
For a gravitationally bound atmosphere at constant temperature, the total energy content per cubic meter decreases exponentially with altitude. The density drops much faster with altitude than the gravitational potential energy increases. See graph here.

January 20, 2012 9:51 am

mkelly said, “Gravity has NO AFFECT ON TEMPERATURE.”
Everything is relative 🙂
http://redneckphysics.blogspot.com/2012/01/that-dang-cartoon-again.html

DeWitt Payne
January 20, 2012 9:59 am

Hans Jellbring,

Any surface radiation power exceeding 100 W/m^2 is bull regardless if it is from equatorial, midlatitude or polar regions during days or night. Just show how this fantasy power radiation changes between day and night in polar regions as an exsample.

Here’s a plot of upwelling IR radiation measured over 24 hours at Desert Rock, NV by a SURFRAD station there. It looks to be more than 100W/m² to me. Note that the time axis is UTC. Desert Rock is -8 hours from UTC so local noon would be 2000 on the time axis.
There are seven SURFRAD stations in the US. You can access the data here.

1 8 9 10 11 12 37