Unified Theory of Climate: Reply to Comments

Foreword – I’ve had this document since January 17th, and it has taken some time to get it properly reproduced here in full due to formatting issues. Some equations have to be converted to images, and I have to double check every superscript, subscript, and symbol for accuracy, then re-insert/re-format many manually since they often don’t reproduce properly in WordPress. WordPress doesn’t manage copy/paste of complex documents well. I hope that I have everything correctly reproduced, if not, please leave a note. A PDF of the original is here: UTC_Blog_Reply_Part1 This is a contentious issue, and while it would be a wonderful revelation if it were proven to be true, I personally cannot see any way it can surmount the law of conservation of energy. That view is shared by others, noted in the opening paragraph below. However, I’m providing this for the educational value it may bring to those who can take it all in and discuss it rationally, with a caution – because this issue is so contentious, I ask readers to self-moderate so that the WUWT moderation team does not have to be heavy handed. I invite you take it all in, and to come to your own conclusion. Thank you for your consideration. – Anthony

Part 1: Magnitude of the Natural ‘Greenhouse’ Effect

Ned Nikolov, Ph.D. and Karl Zeller, Ph.D.

  1. Introduction

Our recent paper “Unified Theory of Climate: Expanding the Concept of Atmospheric Greenhouse Effect Using Thermodynamic Principles. Implications for Predicting Future Climate Change” spurred intense discussions at WUWT and Tallbloke’s Talkshop websites. Many important questions were raised by bloggers and two online articles by Dr. Ira Glickstein (here) and Dr. Roy Spencer (here). After reading through most responses, it became clear to us that that an expanded explanation is needed. We present our reply in two separate articles that address blog debate foci as well as key aspects of the new paradigm.

Please, consider that understanding this new theory requires a shift in perception! As Albert Einstein once noted, a new paradigm cannot be grasped within the context of an existing mindset; hence, we are constrained by the episteme we are living in. In that light, our concept requires new definitions that may or may not have exact counterparts in the current Greenhouse theory. For example, it is crucial for us to introduce and use the term Atmospheric Thermal Effect (ATE) because: (a) The term Greenhouse Effect (GE) is inherently misleading due to the fact that the free atmosphere, imposing no restriction on convective cooling, does not really work as a closed greenhouse; (b) ATE accurately coveys the physical essence of the phenomenon, which is the temperature boost at the surface due to the presence of atmosphere; (c) Reasoning in terms of ATE vs. GE helps broaden the discussion beyond radiative transfer; and (d) Unlike GE, the term Atmospheric Thermal Effect implies no underlying physical mechanism(s).

We start with the undisputable fact that the atmosphere provides extra warmth to the surface of Earth compared to an airless environment such as on the Moon. This prompts two basic questions: (1) What is the magnitude of this extra warmth, i.e. the size of ATE ? and (2) How does the atmosphere produce it, i.e. what is the physical mechanism of ATE ? In this reply we address the first question, since it appears to be the crux of most people’s difficulty and needs a resolution before proceeding with the rest of the theory (see, for example, Lord Monckton’s WUWT post).

  1. Magnitude of Earth’s Atmospheric Thermal Effect

We maintain that in order to properly evaluate ATE one must compare Earth’s average near-surface temperature to the temperature of a spherical celestial body with no atmosphere at the same distance from the Sun. Note that, we are not presently concerned with the composition or infrared opacity of the atmosphere. Instead, we are simply trying to quantify the overall effect of our atmosphere on the surface thermal environment; hence the comparison with a similarly illuminated airless planet. We will hereafter refer to such planet as an equivalent Planetary Gray Body (PGB).

Since temperature is proportional (linearly related) to the internal kinetic energy of a system, it is theoretically perfectly justifiable to use meanglobal surface temperatures to quantify the ATE. There are two possible indices one could employ for this:

  1. The absolute difference between Earth’s mean temperature (Ts) and that of an equivalent PGB (Tgb), i.e. ATE = TsTgb; or
  1. The ratio of Ts to Tgb. The latter index is particularly attractive, since it normalizes (standardizes) ATE with respect to the top-of-atmosphere (TOA) solar irradiance (So), thus enabling a comparison of ATEs among planets that orbit at various distances from the Sun and receive different amounts of solar radiation. We call this non-dimensional temperature ratio a Near-surface Thermal Enhancement (ATEn) and denote it by NTE = Ts / Tgb. In theory, therefore, NTE should be equal or greater than 1.0 (NTE ≥ 1.0). Please, note that ATEn is a measure of ATE.

It is important to point out that the current GE theory measures ATE not by temperature, but by the amount of absorbed infrared (IR) radiation. Although textbooks often mention that Earth’s surface is 18K-33K warmer than the Moon thanks to the ‘greenhouse effect’ of our atmosphere, in the scientific literature, the actual effect is measured via the amount of outgoing infrared radiation absorbed by the atmosphere (e.g. Stephens et al. 1993; Inamdar & Ramanathan 1997; Ramanathan & Inamdar 2006; Houghton 2009). It is usually calculated as a difference (occasionally a ratio) between the total average infrared flux emanating at the surface and that at the top of the atmosphere. Defined in this way, the average atmospheric GE, according to satellite observations, is between 157 and 161 W m-2 (Ramanathan & Inamdar 2006; Lin et al. 2008; Trenberth et al. 2009). In other words, the current theory uses radiative flux units instead of temperature units to quantify ATE. This approach is based on the preconceived notion that GE works by reducing the rate of surface infrared cooling to space. However, measuring a phenomenon with its presumed cause instead by its manifest effect can be a source of major confusion and error as demonstrated in our study. Hence, we claim that the proper assessment of ATE depends on an accurate estimate of the mean surface temperature of an equivalent PGB (Tgb).

  1. Estimating the Mean Temperature of an Equivalent Planetary Gray Body

There are two approaches to estimate Tgb – a theoretical one based on known physical relationships between temperature and radiation, and an empirical one relying on observations of the Moon as the closest natural gray body to Earth.

According to the Stefan-Boltzmann (SB) law, any physical object with a temperature (T, oK) above the absolute zero emits radiation with an intensity (I, W m-2) that is proportional to the 4th power of the object’s absolute temperature:

image

where ϵ is the object’s thermal emissivity/absorptivity (0 ≤ ϵ ≤ 1 ), and σ = 5.6704×10-8 W m-2 K-4 is the SB constant. A theoretical blackbody has ϵ = 1.0, while real solid objects such as rocks usually have ϵ ≈ 0.95. In principle, Eq. (1) allows for an accurate calculation of an object’s equilibrium temperature given the amount of absorbed radiation by the object, i.e.

image

The spatially averaged amount of solar radiation absorbed by the Earth-Atmosphere system (Sα ̅̅̅, W m-2) can be accurately computed from TOA solar irradiance (Sα ̅̅̅, W m-2) and planetary albedo (αp) as

image

where the TOA shortwave flux (W m-2) incident on a plane perpendicular to the solar rays. The factor ¼ serves to distribute the solar flux incident on a flat surface to a sphere. It arises from the fact that the surface area of a sphere (4πR2) is 4 times larger than the surface area of a disk (πR2) of the same radius (R). Hence, it appears logical that one could estimate Earth’s average temperature in the absence of ATE from using the SB law. i.e.

image

Here (TeK) is known as the effective emission temperature of Earth. Employing typical values for S0 =W m-2 and αp = 0.3 and assuming, ϵ  = 1.0 Eq. (3) yields 254.6K. This is the basis for the widely quoted 255K (-18C) mean surface temperature of Earth in the absence of a ‘greenhouse effect’, i.e. if the atmosphere were missing or ‘completely transparent’ to IR radiation. This temperature is also used to define the so-called effective emission height in the troposphere (at about 5 km altitude), where the bulk of Earth’s outgoing long-wave radiation to space is assumed to emanate from. Since Earth’s mean surface temperature is 287.6K (+14.4C), the present theory estimates the size of ATE to be 287.6K – 254.6K = 33K. However, as pointed out by other studies, this approach suffers from a serious logical error. Removing the atmosphere (or even just the water vapor in it) would result in a much lower planetary albedo, since clouds are responsible for most of Earth’s shortwave reflectance. Hence, one must use a different albedo (αp) in Eq. (3) that only quantifies the actual surface reflectance. A recent analysis of Earth’s global energy budget by Trenberth et al. (2009) using satellite observations suggests αp≈ 0.12. Serendipitously, this value is quite similar to the Moon bond albedo of 0.11 (see Table 1 in our original paper), thus allowing evaluation of Earth’s ATE using our natural satellite as a suitable PGB proxy. Inserting= 0.12 in Eq. (3) produces Te = 269.6K, which translates into an ATE of only 18K (i.e. 287.6 – 269.6 = 18K).

In summary, the current GE theory employs a simple form of the SB law to estimate the magnitude of Earth’s ATE between 18K and 33K. The theory further asserts that the Moon average temperature is 250K to 255K despite the fact that using the correct lunar albedo (0.11) in Eq. (3) produces ≈270K, i.e. a15K to 20K higher temperature! Furthermore, the application of Eq. (3) to calculate the mean temperature of a sphere runs into a fundamental mathematical problem caused by Hölder’s inequality between non-linear integrals (e.g. Kuptsov 2001). What does this mean? Hölder’s inequality applies to certain non-linear functions and states that, in such functions, the use of an arithmetic average for the independent (input) variable will not produce a correct mean value of the dependent (output) variable. Hence, due to a non-linear relationship between temperature and radiative flux in the SB law (Eq. 3) and the variation of absorbed radiation with latitude on a spherical surface, one cannot correctly calculate the mean temperature of a unidirectionally illuminated planet from the amount of spatially averaged absorbed radiation defined by Eq. (2). According to Hölder’s inequality, the temperature calculated from Eq. (3) will always be significantly higher than the actual mean temperature of an airless planet. We can illustrate this effect with a simple example.

Let’s consider two points on the surface of a PGB, P1 and P2, located at the exact same latitude (say 45oN) but at opposite longitudes so that, when P1 is fully illuminated, P2 is completely shaded and vice versa (see Fig. 1). If the PGB is orbiting at the same distance from the Sun as Earth and solar rays were the only source of heat to it, then the equilibrium temperature at the illuminated point would be (assuming a solar zenith angle θ = 45o), while the temperature at the shaded point would be T2 = 0 (since it receives no radiation due to cosθ < 0). The mean temperature between the two points is then Tm = (T1 + T2)/2 = 174.8K. However, if we try using the average radiation absorbed by the two points W m-2 to calculate a mean temperature, we obtain = 234.2K. Clearly, Te is much greater than Tm (TeTm), which is a result of Hölder’s inequality.

image

Figure 1. Illustration of the effect of Hölder’s inequality on calculating the mean surface temperature of an airless planet. See text for details.

The take-home lesson from the above example is that calculating the actual mean temperature of an airless planet requires explicit integration of the SB law over the planet surface. This implies first taking the 4th root of the absorbed radiative flux at each point on the surface and then averaging the resulting temperature field rather than trying to calculate a mean temperature from a spatially averaged flux as done in Eq. (3).

Thus, we need a new model that is capable of predicting Tgb more robustly than Eq. (3). To derive it, we adopt the following reasoning. The equilibrium temperature at any point on the surface of an airless planet is determined by the incident solar flux, and can be approximated (assuming uniform albedo and ignoring the small heat contributions from tidal forces and interior radioactive decay) as

image

where is the solar zenith angle (radian) at point , which is the angle between solar rays and the axis normal to the surface at that point (see Fig. 1). Upon substituting , the planet’s mean temperature () is thus given by the spherical integral of , i.e.

image

Comparing the final form of Eq. (5) with Eq. (3) shows that Tgb << Te in accordance with Hölder’s inequality. To make the above expression physically more realistic, we add a small constant Cs =0.0001325 W m-2 to So, so that when So = 0.0, Eq. (5) yields Tgb = 2.72K (the irreducible temperature of Deep Space), i.e:

image

In a recent analytical study, Smith (2008) argued that Eq. (5) only describes the mean temperature of a non-rotating planet and that, if axial rotation and thermal capacity of the surface are explicitly accounted for, the average temperature of an airless planet would approach the effective emission temperature. It is beyond the scope of the current article to mathematically prove the fallacy of this argument. However, we will point out that increasing the mean equilibrium temperature of a physical body always requires a net input of extra energy. Adding axial rotation to a stationary planet residing in a vacuum, where there is no friction with the external environment does not provide any additional heat energy to the planet surface. Faster rotation and/or higher thermal inertia of the ground would only facilitate a more efficient spatial distribution of the absorbed solar energy, thus increasing the uniformity of the resulting temperature field across the planet surface, but could not affect the average surface temperature. Hence, Eq. (6) correctly describe (within the assumption of albedo uniformity) the global mean temperature of any airless planet, be it rotating or non-rotating.

Inserting typical values for Earth and Moon into Eq. (6), i.e. So = 1,362 W m-2, αo = 0.11, and ϵ = 0.955, produces Tgb = 154.7K. This estimate is about 100K lower than the conventional black-body temperature derived from Eq. (3) implying that Earth’s ATE (i.e. the GE) is several times larger than currently believed! Such a result, although mathematically justified, requires independent empirical verification due to its profound implications for the current GE theory. As noted earlier, the Moon constitutes an ideal proxy PGB in terms of its location, albedo, and airless environment, against which the thermal effect of Earth’s atmosphere could be accurately assessed. Hence, we now turn our attention to the latest temperature observations of the Moon.

  1. NASA’s Diviner Lunar Radiometer Experiment

In June 2009, NASA launched its Lunar Reconnaissance Orbiter (LRO), which carries (among other instruments) a Radiometer called Diviner. The purpose of Diviner is to map the temperature of the Moon surface in unprecedented detail employing measurements in 7 IR channels that span wavelengths from 7.6 to 400 μm. Diviner is the first instrument designed to measure the full range of lunar surface temperatures, from the hottest to the coldest. It also includes two solar channels that measure the intensity of reflected solar radiation enabling a mapping of the lunar shortwave albedo as well (for details, see the Diviner Official Website at http://www.diviner.ucla.edu/).

Although the Diviner Experiment is still in progress, most thermal mapping of the Moon surface has been completed and data are available online. Due to time constraints of this article, we did not have a chance to analyze Diviner’s temperature data ourselves. Instead, we elected to rely on information reported by the Diviner Science Team in peer-reviewed publications and at the Diviner website.

Data obtained during the LRO commissioning phase reveal that the Moon has one of the most extreme thermal environments in the solar system. Surface temperatures at low latitudes soar to 390K (+117C) around noon while plummeting to 90-95K (-181C), i.e. almost to the boiling point of liquid oxygen, during the long lunar night (Fig. 2). Remotely sensed temperatures in the equatorial region agree very well with direct measurement conducted on the lunar surface at 26.1o N by the Apollo 15 mission in early 1970s (see Huang 2008). In the polar regions, within permanently shadowed areas of large impact craters, Diviner has measured some of the coldest temperatures ever observed on a celestial body, i.e. down to 25K-35K (-238C to -248C). It is important to note that planetary scientists have developed detailed process-based models of the surface temperatures of Moon and Mercury some 13 years ago (e.g. Vasavada et al. 1999). These models are now being successfully validated against Diviner measurements (Paige et al. 2010b; Dr. M. Siegler at UCLA, personal communication).

What is most interesting to our discussion, however, are the mean temperatures at various lunar latitudes, for these could be compared to temperatures in similar regions on Earth to evaluate the size of ATE and to verify our calculations. Figure 3 depicts typical diurnal courses of surface temperature on the Moon at four latitudes (adopted from Paige et. al 2010a).

image

Figure 2. Thermal maps of the Moon surface based on NASA’s Diviner infrared measurements showing daytime maximum and nighttime minimum temperature fields (Source: Diviner Web Site).

image

Figure 3. Typical diurnal variations of the Moon surface temperature at various latitudes. Local time is expressed in lunar hours which correspond to 1/24 of a lunar month. At 89◦ latitude, diurnal temperature variations are shown at summer and winter solstices (adopted from Paige et al. 2010a). Dashed lines indicate annual means at the lunar equator and at the poles.

image

image

Figure 4. Temperature maps of the South Pole of the Moon and Earth: (A) Daytime temperature field at peak illumination on the Moon; (B) Nighttime temperature field on the Moon; (C) Mean summer temperatures over Antarctica; (D) Mean winter temperatures over Antarctica. Numbers shown in bold on panels (C) and (D) are temperatures in oK. Panels (A) and (B) are produced by the Diviner Lunar Radiometer Experiment (Paige et al. 2010b). Antarctica maps are from Wikipedia (http://en.wikipedia.org/wiki/Antarctic_climate). Comparison of surface temperatures between Moon’s South Pole and Antarctica suggests a thermal enhancement by the Earth atmosphere (i.e. a ‘Greenhouse Effect’) of about 107K in the summer and 178K in the winter for this part of the Globe.

Figures 4A & 4B display temperature maps of the Moon South Pole during daytime peak illumination and at night (Paige et. al 2010b). Since the Moon has a small obliquity (axial tilt) of only 1.54o and a slow rotation, the average diurnal temperatures are similar to seasonal temperature means. These data along with information posted at the Diviner Science webpage indicate that mean temperature at the lunar-surface ranges from 98K (-175C) at the poles to 206K (-67C) at the equator. This encompasses pretty well our theoretical estimate of 154.7K for the Moon mean global temperature produced by Eq. (6). In the coming months, we will attempt to calculate more precisely Moon’s actual mean temperature from Diviner measurements. Meanwhile, data published by NASA planetary scientists clearly show that the value 250K-255K adopted by the current GE theory as Moon’s average global temperature is grossly exaggerated, since such high temperature means do not occur at any lunar latitude! Even the Moon equator is 44K – 49K cooler than that estimate. This value is inaccurate, because it is the result of an improper application of the SB law to a sphere while assuming the wrong albedo (see discussion in Section 2.1 above)!

Similarly, the mean global temperatures of Mercury (440K) and Mars (210K) reported on the NASA Planetary Fact Sheet are also incorrect, since they have been calculated from the same Eq. (3) used to produce the 255K temperature for the Moon. We urge the reader to verify this claim by applying Eq. (3) with data for solar irradiance (So) and bond albedo (αo) listed on the fact sheet of each planet while setting ϵ = 1. This is the reason that, in our original paper, we used 248.2K for Mercury, since that temperature was obtained from the theoretically correct Eq. (6). For Mars, we adopted means calculated from regional data of near-surface temperature and pressure retrieved by the Radio Science Team at Stanford University employing remote observations by the Mars Global Surveyor spacecraft. It is odd to say the least that the author of NASA’s Planetary Fact Sheets, Dr. David R. Williams, has chosen Eq. (3) to calculate Mars’ average surface temperature while ignoring the large body of high-quality direct measurements available for the Red Planet!?

So, what is the real magnitude of Earth’s Atmospheric Thermal Effect?

Table 1. Estimated Atmospheric Thermal Effect for equator and the poles based on observed surface temperatures on Earth and the Moon and using the lunar surface as a proxy for Earth’s theoretical gray body. Data obtained from Diviner’s Science webpage, Paige at al. (2010b), Figure 4, and Wikipedia:Oymyakon.

image

Figure 5. Earth’s mean annual near-surface temperature according to Wikipedia (Geographic Zones: http://en.wikipedia.org/wiki/Geographical_zone).

Table 1 shows observed mean and record-low surface temperatures at similar latitudes on Earth and on the Moon. The ATE is calculated as a difference between Earth and Moon temperatures assuming that the Moon represents a perfect PGB proxy for Earth. Figure 5 displays a global map of Earth’s mean annual surface temperatures to help the reader visually verify some of the values listed in Table 1. The results of the comparison can be summarized as follows:

The Atmospheric Thermal Effect, presently known as the natural Greenhouse Effect, varies from 93K at the equator to about 150K at the poles (the latter number represents an average between North- and South- Pole ATE mean values, i.e. (158+143)/2 =150.5. This range encompasses quite well our theoretical estimate of 133K for the Earth’s overall ATE derived from Eq. (6), i.e. 287.6K – 154.7K = 132.9K.

Of course, further analysis of the Diviner data is needed to derive a more precise estimate of Moon’s mean surface temperature and verify our model prediction. However, given the published Moon measurements, it is clear that the widely quoted value of 33K for Earth’s mean ATE (GE) is profoundly misleading and wrong!

  1. Conclusion

We have shown that the SB Law relating radiation intensity to temperature (Eq. 1 & 3) has been incorrectly applied in the past to predict mean surface temperatures of celestial bodies including Mars, Mercury, and the Moon. Due to Hölder’s inequality between non-linear integrals, the effective emission temperature computed from Eq. (3) is always significantly higher than the actual (arithmetic) mean temperature of an airless planet. This makes the planetary emission temperature Te produced by Eq. (3) physically incompatible with any real measured temperatures on Earth’s surface or in the atmosphere. By using a proper integration of the SB Law over a sphere, we derived a new formula (Eq. 6) for estimating the average temperature of a planetary gray body (subject to some assumptions). We then compared the Moon mean temperature predicted by this formula to recent thermal observations and detailed energy budget calculation of the lunar surface conducted by the NASA Diviner Radiometer Experiment. Results indicate that Moon’s average temperature is likely very close to the estimate produced by our Eq. (6). At the same time, Moon measurements also show that the current estimate of 255K for the lunar average surface temperature widely used in climate science is unrealistically high; hence, further demonstrating the inadequacy of Eq. (3). The main result from the Earth-Moon comparison (assuming the Moon is a perfect gray-body proxy of Earth) is that the Earth’s ATE, also known as natural Greenhouse Effect, is 3 to 7 times larger than currently assumed. In other words, the current GE theory underestimates the extra atmospheric warmth by about 100K! In terms of relative thermal enhancement, the ATE translates into NTE = 287.6/154.7 = 1.86.

This finding invites the question: How could such a huge (> 80%) thermal enhancement be the result of a handful of IR-absorbing gases that collectively amount to less than 0.5% of total atmospheric mass? We recall from our earlier discussion that, according to observations, the atmosphere only absorbs 157 – 161 W m-2 long-wave radiation from the surface. Can this small flux increase the temperature of the lower troposphere by more than 100K compared to an airless environment? The answer obviously is that the observed temperature boost near the surface cannot be possibly due to that atmospheric IR absorption! Hence, the evidence suggests that the lower troposphere contains much more kinetic energy than radiative transfer alone can account for! The thermodynamics of the atmosphere is governed by the Gas Law, which states that the internal kinetic energy and temperature of a gas mixture is also a function of pressure (among other things, of course). In the case of an isobaric process, where pressure is constant and independent of temperature such as the one operating at the Earth surface, it is the physical force of atmospheric pressure that can only fully explain the observed near-surface thermal enhancement (NTE). But that is the topic of our next paper… Stay tuned!

  1. References

Inamdar, A.K. and V. Ramanathan (1997) On monitoring the atmospheric greenhouse effect from space. Tellus 49B, 216-230.

Houghton, J.T. (2009). Global Warming: The Complete Briefing (4th Edition). Cambridge University Press, 456 pp.

Huang, S. (2008). Surface temperatures at the nearside of the Moon as a record of the radiation budget of Earth’s climate system. Advances in Space Research 41:1853–1860 (http://www.geo.lsa.umich.edu/~shaopeng/Huang07ASR.pdf)

Kuptsov, L. P. (2001) Hölder inequality. In: Encyclopedia of Mathematics, Hazewinkel and Michiel, Springer, ISBN 978-1556080104.

Lin, B., P. W. Stackhouse Jr., P. Minnis, B. A. Wielicki, Y. Hu, W. Sun, Tai-Fang Fan, and L. M. Hinkelman (2008). Assessment of global annual atmospheric energy balance from satellite observations. J. Geoph. Res. Vol. 113, p. D16114.

Paige, D.A., Foote, M.C., Greenhagen, B.T., Schofield, J.T., Calcutt, S., Vasavada, A.R., Preston, D.J., Taylor, F.W., Allen, C.C., Snook, K.J., Jakosky, B.M., Murray, B.C., Soderblom, L.A., Jau, B., Loring, S., Bulharowski J., Bowles, N.E., Thomas, I.R., Sullivan, M.T., Avis, C., De Jong, E.M., Hartford, W., McCleese, D.J. (2010a). The Lunar Reconnaissance Orbiter Diviner Lunar Radiometer Experiment. Space Science Reviews, Vol 150, Num 1-4, p125-16 (http://www.diviner.ucla.edu/docs/fulltext.pdf)

Paige, D.A., Siegler, M.A., Zhang, J.A., Hayne, P.O., Foote, E.J., Bennett, K.A., Vasavada, A.R., Greenhagen, B.T, Schofield, J.T., McCleese, D.J., Foote, M.C., De Jong, E.M., Bills, B.G., Hartford, W., Murray, B.C., Allen, C.C., Snook, K.J., Soderblom, L.A., Calcutt, S., Taylor, F.W., Bowles, N.E., Bandfield, J.L., Elphic, R.C., Ghent, R.R., Glotch, T.D., Wyatt, M.B., Lucey, P.G. (2010b). Diviner Lunar Radiometer Observations of Cold Traps in the Moon’s South Polar Region. Science, Vol 330, p479-482. (http://www.diviner.ucla.edu/docs/paige_2010.pdf)

Ramanathan, V. and A. Inamdar (2006). The Radiative Forcing due to Clouds and Water Vapor. In: Frontiers of Climate Modeling, J. T. Kiehl and V. Ramanthan, Editors, (Cambridge University Press 2006), pp. 119-151.

Smith, A. 2008. Proof of the atmospheric greenhouse effect. Atmos. Oceanic Phys. arXiv:0802.4324v1 [physics.ao-ph] (http://arxiv.org/PS_cache/arxiv/pdf/0802/0802.4324v1.pdf ).

Stephens, G.L., A. Slingo, and M. Webb (1993) On measuring the greenhouse effect of Earth. NATO ASI Series, Vol. 19, 395-417.

Trenberth, K.E., J.T. Fasullo, and J. Kiehl (2009). Earth’s global energy budget. BAMS, March:311-323

Vasavada, A. R., D. A. Paige and S. E. Wood (1999). Near-surface temperatures on Mercury and the Moon and the stability of polar ice deposits. Icarus 141:179–193 (http://www.gps.caltech.edu/classes/ge151/references/vasavada_et_al_1999.pdf)

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David A
January 22, 2012 5:20 pm

Tim Folkerts says: January 22, 2012 at 3:58 pm
R. Gates,
I often agree with you, but not here: “This difference is due to the Earth’s internal energy, some of which is emitted at the surface, and is not insubstantial. ”
The internal energy is mostly “insubstantial”. The flow of geothermal energy is typically estimated as ~ 0.1 W/m^2. Even if this was as high as 1 W/m^2, this is fairly small compared to the 240 W/m^2 from the sun. The moon would be 240 W/m^2, while earth would be 241 W/m^2, which would be a small difference (assuming both have the same albedo). Different albedos between the two would have a much bigger effect than any geothermal energy flows.
====================================================
Thanks Tim, is that flow based on land borehole data? Does it include the thinner ocean crust? Does it include volcanic and active geo thermal flows? Does it include oceanic volcanic and geo thermal flows? Does it include the residence time of heat in the ocean depths which may be centuries? How much heat is in the oceans from 500 years of continues flow into the oceans from geo thermal energy?

jorgekafkazar
January 22, 2012 5:23 pm

Nick Stokes says: “…The GHE is that difference between air with and without GHG. Your ATE is something else.”
In my solar system astronomy course in the sixties, we talked about the GHE as due to the presence of an atmosphere containing CO2. The calculation was not based on removing the atmosphere, not just taking out the CO2. But if you really want to slice your definition that thin, how about looking at the AGHE, the amount of warming due to only the greenhouse gases of anthropogenic origin?

Bill Hunter
January 22, 2012 5:28 pm

Nick Stokes says:
January 22, 2012 at 2:50 pm
“This is really nuts, and is being repeated. No-one claims that the atmosphere boosts surface temperature by 18K-33K. Some say that the GHG fraction of the atmosphere has that effect, relative to an atmosphere with no GHG.
But to then say that the 133K is due to a handful of trace gases when you’ve removed the whole atmosphere????”
Technically you are correct at least about what has been claimed by the current climate science establishment. But here comes what has not been said.
This is important information because the initial calculation appears based upon comparison to the moon without an atmosphere. Since establishment climate science can’t seem to relate the earth to Venus except in terms of some completely vague, opaque, and unquantified, lacking a mechanism runaway greenhouse effect; (OKA quackery) that would seem to highly elevate this approach.
So it is a “net” figure! I don’t know what there next step is but as I see it, it should have to have something to do with heat gain and loss calculations using primarily emissivity numbers. Since the temperature of a poorly emissive atmosphere is going to be a lot higher (if it has access to pulse heat of a sufficient magnitude) than a highly emissive PGB. . . .just like you find in building energy loss calculations. In other words the 240watts/m2 now used only applies to a blackbody with no atmosphere, no storage capacity, and with uniform incoming radiation. Our planet has none of those conditions. They have stated and quantified the problems with trying to average temperatures using radiation that has a 4th power relationship to temperature already.
The figure I suspect they will be working with will be the full 1365 watts, possibly modified down in minor ways by some factors (like the conduction vs convection ratio which I think is only about 5%) then applied to greybody properties. All this is common sense to a passive solar designer, assuming I am right of course. Guess we will have to wait and see.

Alan Millar
January 22, 2012 5:38 pm

R. Gates says:
January 22, 2012 at 4:49 pm
Thanks for the feedback. I am wondering how even that 0.1 – 1 W/m2 would change the radiation profile considering the Moon is no doubt much less than this (as it has less internal heat and no convection).
The Moon’s heat flow per sq/m is less than a quarter of the Earth’s.
However, because heat flow, from the interior, is such a small component of the total energy budget, I wouldn’t concern yourself with it.
Alan

January 22, 2012 5:43 pm

Big improvement Ned – now I can understand this part of the N&Z theory.
I agree that what N&Z call the “Atmospheric Thermal Effect” (ATE) should encompass ALL the effects that make a barren planet colder than a similar planet with an Earth-like Atmosphere and Earth-like oceans and rivers and water-based clouds and snow and ice.
However, as I explain below, the N&Z estimate that ATE = 133K is faulty. But, neither do I agree that the 33K of the conventional accounting for the so-called “Greenhouse” Effect (GHE) accounts for the full warming effect of an Earth-like Atmosphere with so-called “Greenhouse” Gases (GHG). The value of the N&Z theory, and of Anthony’s decision to publish it, is that it made it clear to me and I hope others that the conventional 33K accounting is not the whole story of the contribution of an Earth-like Atmosphere to warming.
I think the true ATE lies somewhere between the N&Z 133K and the conventional 33K.
By the conventional accounting (as I wrote here the GHG of 33K is based on comparison of our actual Earth with a totally imaginary Earth that has a non-GHG atmosphere of the same mass as the Atmosphere of the Earth. To achieve a non-GHG condition, that imaginary Earth must lack water, and thus have no clouds or ice. Therefore the surface must be painted to raise the albedo from 0.11 to the 0.3 of our actual Earth. For that imaginary situation, and that alone, 33K may be a good estimate. (However, it may be off by some amount due to the absence on the imaginary Earth of normal atmospheric effects such as precipitation, winds, and storms.)
The N&Z posting illustrates the ATE in their Table 1 by comparison of various latitudes of the Earth and the Moon. They subtract mean temperatures, getting values of 93K, 143K and 158K which average out to 131K which is almost identical to their original 133K.
However, as N&Z acknowledge but fail to properly account for, the Moon rotates at a small fraction (1/28 = 3.6%) of the rate of the Earth. As PeterF noted in his comment above:

…I cannot accept your reasoning for being allowed to ignore rotation of a planetary body. Imagine an infinitely fast rotating body. It would be the equivalent of incoming radiation falling on the whole surface of the planet, and not just half of it. This would result in the “shaded” side having a higher, and the “lit” side a lower temperature. And because of the 4th power law and Hölder’s inequality you would get a higher average temperature….

A barren Earth rotating at the same rate as our actual Earth would have a considerably higher mean temperature than the Moon, because, on the day side, it would absorb and, due to heat capacity, store much of the incoming Solar energy, and release it on the night-side. As a result, the daytime temperatures would be less than on a body rotating at 3.6% of the rate, and the nightime temperatures would be greater, and by the T^4 averaging, the net mean would be higher. Thus, the N&Z Table 1 values are considerably higher than the actual ATE.
I understand that the above N&Z posting is only the first of two parts, and that it does not get into the “gravitational” aspects of the original N&Z paper, which is the most unconventional aspect. I eagerly await the second part.

Bill Hunter
January 22, 2012 5:44 pm

The 1365 watts is the relevant figure to work with.
Note they mention the moon surface soars to 390K. For a .89 emissive PBG thats the equivalent of 1365 watts solar with about 50 watts still be absorbed by storage.

richard verney
January 22, 2012 5:47 pm

Kev-in-UK says:
January 22, 2012 at 1:53 pm
/////////////////////////
Doesn’t it depend upon whether the ‘dark’ side has sufficient time to comduct and/or radiate away the heat that it gained when on the daylight side?
Imagine a planet rotating once every 100 years and then consider what it would be like if instead it rotated at 100rpm. In the latter case, the surface never gets time to cool when on the ‘dark’ side so its average temperature is nearly equivalent to that of the ‘daylight’ side. Very different to the slowly rotating planet.

Bob Fernley-Jones
January 22, 2012 5:48 pm

Anthony,
In your introduction, you said in part:

…This is a contentious issue, and while it would be a wonderful revelation if it were proven to be true, I personally cannot see any way it can surmount the law of conservation of energy. That view is shared by others, noted in the opening paragraph below. However, I’m providing this for the educational value it may bring to those who can take…

It does seem surprising that two PhD’s in physics could not be aware of Conservation of Energy or between them not have noticed a red flag, whilst at the same time probably having awareness that the establishment would try hard to tear it to shreds.
I seem to remember that their fundamental claim is NOT that gravitational pressure CAUSES heating, but that pressure ENHANCES energy input. As far as I can see, they have not claimed to surmount Conservation of Energy as you claim, but that the surface temperature will be higher as a consequence of the enhancement effect of P, for the same amount of energy input. Others have elaborated this including Richard Courtney.
It will be interesting to see if some queries above on the maths will be resolved, and what Part 2 will say.
BTW, Ira’s analogy using two pressure vessels looks rather faulty. See a detailed more balanced 1-off experiment by Konrad Hartmann that gives some initial empirical data, supporting N&Z here:
http://tallbloke.wordpress.com/2012/01/22/konrad-hartmann-experiment-to-determine-the-effect-of-pressure-on-temperature-in-earths-atmosphere/#more-4431
A work in progress I trust.

A physicist
January 22, 2012 5:59 pm

A Physicist wrote “NASA asked the question in an engineering context: “Can a huge (> 80%) improvement in thermal insulation [in a rocket stage] be the result of a few grams of reflective plastic foil, that collectively amount to less than 0.0001% of total cryogenic booster mass? …”

KevinK asks: I do wonder why they didn’t just wrap the Space Shuttle Fuel tank with a few grams of reflective plastic foil ? Seems they could have avoided that whole foam falling off problem.

Kevin, NASA’s multilayer reflective foil trick works only if there is a vacuum between the sheets, and it just wasn’t practical to provide vacuum insulation for the whole external tank. Here’s a picture of a NASA tank that *does* use multilayer reflective foil: the 650 liter dewar of Gravity Probe B, which kept its liquid helium cold in-orbit for more a year.
Whether the insulating layers are made of metal foil, or whether they’re made of CO2, that multilayer insulation trick works *really* well!

markus
January 22, 2012 6:04 pm

Gentlemen,
Please refrain from the term GHGs, and get back to reality.
The gases known by their names on the periodical table, PLEASE.

jorgekafkazar
January 22, 2012 6:05 pm

R. Gates says: January 22, 2012 at 5:09 pm
I would like to see this [internal energy] quantified, as “insubstantial” was admittedly a poor choice of words on my part.
Then I’ll try to answer your comment. I believe the previous thread had several numbers. I’d track down the links, but I’m short of time. I did look for my early calculations on conducted internal heat, but can’t find them. Sorry.
Would it make a difference in the kinds [of] radiation profile that each had?
Doubtful. The core heat would be combined with geothermal/radioactive heat AND the solar heating, which is orders of magnitude larger than the former. The emission spectrum would follow the surface characteristic emissivity vs. wavelength for the resulting temperature of the rocks, or whatever. Agreed?
Then, combining whatever difference that is, with the differences in albedo, is it still accurate to say the Moon is a good gray-body proxy for Earth? If find it very difficult to believe that the Earth, with an outer core temperature of at least 5000C and lots of convection from there to the surface, wouldn’t have a different enough radiation curve (if measured simply as rocks in space without oceans and atmosphere) from the Moon, to say that the Moon is not a very good gray-body proxy for the Earth.
You may be right, but I think the fairly close numbers used in the post are representative. You’d still be looking at differences in albedo of +/- 0.02 or less. As you well know, this topic of this post is intended to present a simple model of a complex planet, so the numbers need not be nailed down any further than necessary.
Finally, the 0.1 W/m2 of “average” geothermal energy over the Earth’s surface is quite misleading, as some areas, such as around volcanos and plate boundaries will have much more than this, and considering the Moon has none of these, there is a lot of heat coming from the interior of the Earth and ending up at the surface.
Well, yes, volcanic and tectonic areas abound, and you might be able to detect eruptions from space in the IR. There are about 3 million subsea volcanoes and a few of them may present a distinguishable image, though the nature of the signal might be hard to identify. Globally speaking, these are not huge areas. I doubt if they’re extensive enough to affect our estimates of the with-atmosphere albedo.
The difference in their overall radiation profiles between an essentially dead and inert Moon and a geologically and thermally active Earth would seem to me to be likely something more than insubstantial.
More like negligible, but again the differences would be more due to surface type (boulders, schist, mountain sides, dirt, gravel, sand, etc.) than heat source, assuming you mean profile and not map. The major difference is the lack of an ocean. That said, I must agree that we don’t know everything about the earth that we’d like to, and a better estimate of the airless Earth albedo might be helpful.
Best regards, Jorge..

wayne
January 22, 2012 6:13 pm

BenAW, as to your remarks about the ‘latitude 89 winter’, this may help; the very coldest spot at Hermite Crater at 25 K has a radiative equivalent to a mere ~0.022 W/m2 which is not too far off from what one half of the mean earthshine value is at the lunar surface. The 90 K is 3.7 W/m2 and you seem right there, seems to show about 3.5 W/m2 of thermal inertia.
Just realized this, if you have a surface receiving just 1 W/m2 the equivalent temperature would be right at 65 K. That sure highlights the fourth power effects.

richard verney
January 22, 2012 6:13 pm

@R. Gates says:
January 22, 2012 at 5:09 pm
////////////////////////////
I am still thinking about this but although I accept that the mantle temperature (for the sake of a better expression) does not contibute much in radiative terms, I am not convinced that the fact that the Earth is still geologically warm is not an important factor and explaims in part why the Earth and moon are different..
On the moon there is a large diurnal range partly because the moon is geologically dead. When the sun rises, it initially has to heat up the surface from a very cold starting point. However, if the moon was geologically active like the Earth, the dark side would not have been quite so cold and the solar irradiance would not have had to have done so much heavy lifting.
Of course much depends upon the latent heat capacity of the surface in question and its arbsorptive and emissitivity characterisrics. This effect may come to the fore in large areas of damp soil, eg vegetated areas. In these areas there is sufficient conductivity to effectively allow geothernal heat to contribute signicantly to the surface temperature. In some densely packed forest areas, the tree canopy is such that the surface may see all but no sunlight. However, the ground does not freeze.

gnomish
January 22, 2012 6:13 pm

it looks like the point of the exercise is simply to replace an obnoxious meme with anything else at all. if so, fine – let the propaganda wars continue – but if it’s about getting a paradigm shift toward improved conceptualization, then Bart is already at the goal line.
the atmosphere is to be considered a refrigeration system and all the engineering principles that are well known and used apply. that’s the proper identification of its nature.

Editor
January 22, 2012 6:24 pm

Joel Shore says:
January 22, 2012 at 2:56 pm

Willis Eschenbach says:

Ned (or anyone) I think there is an error between equation 4 and equation 5.
In equation 4 you have correctly indicated that when the sun is below the horizon, the value of Ti is zero.
However, in equation 5 you have only integrated that over half of the surface of the sphere, the sunlit half. This is indicated by mu (the cosine of the zenith angle) varying from 0 to 1, rather than -1 to 1.

No, Willis. They have just used the fact that the integral of an integrand that is zero (as it is over the dark half) is zero. I think for the approximation that they are making (i.e., that the local temperature is determined by radiative balance with the local insolation), their calculation is correct.

But they are not integrating over the dark half, as near as I can tell. What am I missing? You can’t just ignore half of the planet like that.
w.

Editor
January 22, 2012 6:34 pm

Oh, and Joel, what was your opinion of them substituting
mu = cos(theta)
into equation 7, and then integrating over mu? That seems like an incorrect procedure to me.
w.

Gregory Ludvigsen
January 22, 2012 6:49 pm

One question that puzzles me. The magnetic field and core differ greatly between the earth and the moon. The earth’s is much stonger. It would seem that the earth would generate more energy and heat internally than the moon. This, it would seem would heat the surface of the earth more that the moon. How has this been factored in in calculating the gray body temperature comparison between the eath and the moon?

January 22, 2012 7:07 pm

gnarf:
I had the same difficulty with the integral initially as you’re having, but I may have figured out a way for it to make sense.
Turn the earth on its end so that the sun is shining directly onto the North Pole, placing the whole Southern Hemisphere in niight. If phi is latitude, theta is longitude, and we define mu = sin phi, the radiation intensity at any location in the Northern Hemisphere is S_0 (1 – alpha_0) sin phi = (1 – alpha_0) S_0 mu, and the equivalent temperature is the fourth root of that value divided by epsilon sigma. To get the area-average temperature, integrate the product of that temperature and differential area over the Northern Hemisphere
The differential area is a latitudewise arc R d phi swept through a longitudewise arc R cos phi d theta, where R is the earth’s radius. No loss of generality for present purposes results if we assign R a value of unity, so lose the Rs.
Now convert the integration variable from phi to mu = sin phi: d phi = d mu / sqrt(1-mu^2) and cos phi = sqrt(1 – mu^2). With those substitutions, you simply end up with a constant times mu^(1/4) as the integrand. Unless I’ve made a further mistake myself, that should make it straightforward, with the appropriate integration-limit changes, to reach the result at the end of Equation 5.

Bob Fernley-Jones
January 22, 2012 7:14 pm

jorgekafkazar January 22, 6:05 pm
Jorge, you wrote in part in your interchange with R. Gates:

R.Gates: Finally, the 0.1 W/m2 of “average” geothermal energy over the Earth’s surface is quite misleading, as some areas, such as around volcanos and plate boundaries will have much more than this, and considering the Moon has none of these, there is a lot of heat coming from the interior of the Earth and ending up at the surface.
Jorge: Well, yes, volcanic and tectonic areas abound, and you might be able to detect eruptions from space in the IR. There are about 3 million subsea volcanoes and a few of them may present a distinguishable image, though the nature of the signal might be hard to identify. Globally speaking, these are not huge areas. I doubt if they’re extensive enough to affect our estimates of the with-atmosphere albedo.

I hypothesize briefly that the most important and underestimated geothermal consideration is that the oceanic crust is generally much thinner than the continental crust, and since the ocean is a massive very dynamic highly conductive heat sink, a much more rapid heat transfer is undetectable, over ~70% of the Earth’s surface. Not only is the continental crust much thicker but it arguably has lower thermal conductivity because of much layering including limestones and sandstones that contain micro-macro conductive interfaces.

Joel Shore
January 22, 2012 7:28 pm

Willis says:

But they are not integrating over the dark half, as near as I can tell. What am I missing? You can’t just ignore half of the planet like that.

They did integrate over the dark half…and the value they get is zero because that is what the insolation is over that half. (They then add something back in to account for the fact that the temperature on the dark side would not really be 0 K but the 3 K background. I haven’t really paid attention to whether they did that correctly because the power due to the 3 K background is so ridiculously small as to be inconsequential.)

Oh, and Joel, what was your opinion of them substituting
mu = cos(theta)
into equation 7, and then integrating over mu? That seems like an incorrect procedure to me.

It is fine. The integral of the polar coordinate for a function f over a spherical surface is integral of f*sin(theta)*d(theta) but sin(theta)*d(theta) = -d(cos(theta)) = -d(mu) where mu = cos(theta). [The negative sign is accounted for by switching the limits of integration, i.e., 0 deg to 90 deg becomes mu = 0 to mu = 1.]
Like I said in my first post, as near as I can see, their mathematical calculations are fine. Their errors here are conceptual ones.

Edim
January 22, 2012 7:33 pm

Joel Shore says:
“Try as one might, one is not going to explain the fact that the Earth’s surface emits an average of 390 W/m^2 while the Earth + atmosphere absorb an average of 240 W/m^2 without acknowledging that the atmosphere must absorb some of the terrestrial radiation emitted, i.e., that there is a radiative greenhouse effect.”
Here’s the Trenberth’s global energy balance:
http://theinconvenientskeptic.com/wp-content/uploads/2010/11/FT08-Raw.png
Earth’s surface emits in average ~396 W/m2, but it receives ~333 W/m2 from the atmosphere and ~161 W/m2 solar. Net radiative heat transfer at the surface is:
396 – 333 – 161 = -98 W/m2 (downwelling).
There’s no radiative balance, just like there shouldn’t be! Only in outer space, where the only heat transfer is radiative, but not in the atmosphere. To complete the energy balance, non-radiative heat transfer (outgoing) is added (17 + 80 = 97). So, it balances out.
It’s wrong to claim that Earth’s surface emits an average of 390 W/m2, implying that it’s the heat flux of 390 W/m2. Earth’s surface net radiative loss is:
396 – 333 = 63 W/m2 (if the Trenberth’s numbers are correct).

January 22, 2012 7:39 pm

Baa Humbug said January 22, 2012 at 3:27 pm

Anthony Watts.
Having just read the foreword, I paused before getting in to the main post because the only thing going through my mind was “what a gentleman Anthony is.
He is obviously hard working and intelligent, but he is also polite, courteous and considerate of others, hence the foreword.”
Anthony, you’re a credit to yourself and your family. I’d like to meet you one day, maybe the next time you come to Australia. I’d like to shake your hand.

Beat you to the handshake Baa 🙂 Anthony even came to deepest, darkest Tasmania, a place few bother to visit unpaid. I would go further and say that Anthony is a credit to the human race.

Tim Folkerts
January 22, 2012 7:47 pm

Your new terminology of ATE itself needs clarifying. In fact, most of what you are discussing seems to actually be GERE (global energy redistribution effect).
Futhermore, GERE is composed of sub-effects — notably:
* GERE-A (global energy redistribution effect due to the Atmosphere),
* GERE-O (global energy redistribution effect due to the Oceans), and
* GERE-R (global energy redistribution effect due to Rotation of the earth).
These are all distinct from GHE, which I will indeed call the Greenhouse Effect. I (and I think most others) consider the GHE to be due only to IR radiation to/from certain gases.
So off the bat, the “Atmospheric Thermal Effect” as defined in the paper includes the non-atmospheric effects of the oceans and rotation, and thus is poorly named and potentially misleading.
——————————————————————
If all the forms of GERE are removed, along with removing the GHE, then we get your average temperature of ~ 155 K for a non-rotating world (assuming the integration is correct — and it seems in the right ballpark). The “effective temperature” that you call T_gb would still be ~ 255 K. So far so good.
Anything that redistributes energy around the world from warm areas to cooler area will lead to a higher average temperature (but a constant T_gb)
The atmosphere achieves this by large-scale convection (eg Hadley Cells)
The oceans achieve this by large-scale currents (eg the Gulf Stream)
Rotation achieves this by turning the cold night side into the light, and turning the warm day side into the darkness.
In principle, GERE could, by itself, raise the surface to an average of 255 K if these effects were strong enough and fast enough to create a uniform global temperature. Of course, in reality, there would always be some temperature differences (the poles will always be colder than the equator; the night side will always be colder than the day side). So in reality, GERE will only get us CLOSE to 255 K.
On the earth, GERE seems to be fairly effective. Rather than the temperature range of about 360 K (2.7 K to 360 K on the hypothetical planet in the paper), we have a range of only ~ 120 K (from ~ -70C to ~ 50 C). And most of the earth is in a much narrower range.
But GERE will never get the planet above an average temperature of T_gb = 255 K. Getting above this temperature requires something other than redistributing energy around the surface of the globe.
One well-known and well-established possibility is the GHE.

tchannon
January 22, 2012 7:47 pm

Albedo has been mentioned for a body without atmosphere.
I have a problem with albedo because my understanding and the usage by climatic folks seems to differ.
My understanding is albedo has no effect on the temperature assumed by a body in a flux field isolated in space. (excluding zero, time constants etc.). The reason is reciprocity, in and out are the same (same resistance to heat in and to heat out). The effect is the albedo value cancels to unity.
Note: we can have a body painted half white, half black but planets don’t do that, they spin on their axis averaging.
Where am I wrong?

January 22, 2012 7:49 pm

KevinK said January 22, 2012 at 4:57 pm

The reflective plastic foil (aka MLI; Multi Layer Insulation) only works in a vacuum (sans conduction and convection). That’s why you can’t buy it at your typical neighborhood hardware store. Yes, they do sell some air cell stuff with foil facing, but the foil facing has almost no effect here on Earth. Does anybody remember when fiberglass insulation for your house had an aluminum foil facing (back in the 70’s and 80’s) ? I don’t think they stopped that because of the high price of aluminum foil. They stopped it because; it doesn’t achieve much insulation effectiveness, and if you happen to staple it down and contact a live electrical wire you create a fire and/or electrocution hazard. I seem to remember some recent problems in Australia regarding that.
Cheers, Kevin.

The problem with foil batts in Australia was down to multilayer foil batts — not foil-faced fibreglass batts. The foil batts consist of two, or three layers of aluminium foil 25mm apart with paper webbing to hold the layers apart. No vacuum reuired. They are widely used in the tropics and sub-tropics. And yes, untrained workers installing them were electrocuted and some caused housefires. All in the name of government mandated Saving the Planet of course.