Foreword – I’ve had this document since January 17th, and it has taken some time to get it properly reproduced here in full due to formatting issues. Some equations have to be converted to images, and I have to double check every superscript, subscript, and symbol for accuracy, then re-insert/re-format many manually since they often don’t reproduce properly in WordPress. WordPress doesn’t manage copy/paste of complex documents well. I hope that I have everything correctly reproduced, if not, please leave a note. A PDF of the original is here: UTC_Blog_Reply_Part1 This is a contentious issue, and while it would be a wonderful revelation if it were proven to be true, I personally cannot see any way it can surmount the law of conservation of energy. That view is shared by others, noted in the opening paragraph below. However, I’m providing this for the educational value it may bring to those who can take it all in and discuss it rationally, with a caution – because this issue is so contentious, I ask readers to self-moderate so that the WUWT moderation team does not have to be heavy handed. I invite you take it all in, and to come to your own conclusion. Thank you for your consideration. – Anthony
Part 1: Magnitude of the Natural ‘Greenhouse’ Effect
Ned Nikolov, Ph.D. and Karl Zeller, Ph.D.
- Introduction
Our recent paper “Unified Theory of Climate: Expanding the Concept of Atmospheric Greenhouse Effect Using Thermodynamic Principles. Implications for Predicting Future Climate Change” spurred intense discussions at WUWT and Tallbloke’s Talkshop websites. Many important questions were raised by bloggers and two online articles by Dr. Ira Glickstein (here) and Dr. Roy Spencer (here). After reading through most responses, it became clear to us that that an expanded explanation is needed. We present our reply in two separate articles that address blog debate foci as well as key aspects of the new paradigm.
Please, consider that understanding this new theory requires a shift in perception! As Albert Einstein once noted, a new paradigm cannot be grasped within the context of an existing mindset; hence, we are constrained by the episteme we are living in. In that light, our concept requires new definitions that may or may not have exact counterparts in the current Greenhouse theory. For example, it is crucial for us to introduce and use the term Atmospheric Thermal Effect (ATE) because: (a) The term Greenhouse Effect (GE) is inherently misleading due to the fact that the free atmosphere, imposing no restriction on convective cooling, does not really work as a closed greenhouse; (b) ATE accurately coveys the physical essence of the phenomenon, which is the temperature boost at the surface due to the presence of atmosphere; (c) Reasoning in terms of ATE vs. GE helps broaden the discussion beyond radiative transfer; and (d) Unlike GE, the term Atmospheric Thermal Effect implies no underlying physical mechanism(s).
We start with the undisputable fact that the atmosphere provides extra warmth to the surface of Earth compared to an airless environment such as on the Moon. This prompts two basic questions: (1) What is the magnitude of this extra warmth, i.e. the size of ATE ? and (2) How does the atmosphere produce it, i.e. what is the physical mechanism of ATE ? In this reply we address the first question, since it appears to be the crux of most people’s difficulty and needs a resolution before proceeding with the rest of the theory (see, for example, Lord Monckton’s WUWT post).
- Magnitude of Earth’s Atmospheric Thermal Effect
We maintain that in order to properly evaluate ATE one must compare Earth’s average near-surface temperature to the temperature of a spherical celestial body with no atmosphere at the same distance from the Sun. Note that, we are not presently concerned with the composition or infrared opacity of the atmosphere. Instead, we are simply trying to quantify the overall effect of our atmosphere on the surface thermal environment; hence the comparison with a similarly illuminated airless planet. We will hereafter refer to such planet as an equivalent Planetary Gray Body (PGB).
Since temperature is proportional (linearly related) to the internal kinetic energy of a system, it is theoretically perfectly justifiable to use meanglobal surface temperatures to quantify the ATE. There are two possible indices one could employ for this:
- The absolute difference between Earth’s mean temperature (Ts) and that of an equivalent PGB (Tgb), i.e. ATE = Ts – Tgb; or
- The ratio of Ts to Tgb. The latter index is particularly attractive, since it normalizes (standardizes) ATE with respect to the top-of-atmosphere (TOA) solar irradiance (So), thus enabling a comparison of ATEs among planets that orbit at various distances from the Sun and receive different amounts of solar radiation. We call this non-dimensional temperature ratio a Near-surface Thermal Enhancement (ATEn) and denote it by NTE = Ts / Tgb. In theory, therefore, NTE should be equal or greater than 1.0 (NTE ≥ 1.0). Please, note that ATEn is a measure of ATE.
It is important to point out that the current GE theory measures ATE not by temperature, but by the amount of absorbed infrared (IR) radiation. Although textbooks often mention that Earth’s surface is 18K-33K warmer than the Moon thanks to the ‘greenhouse effect’ of our atmosphere, in the scientific literature, the actual effect is measured via the amount of outgoing infrared radiation absorbed by the atmosphere (e.g. Stephens et al. 1993; Inamdar & Ramanathan 1997; Ramanathan & Inamdar 2006; Houghton 2009). It is usually calculated as a difference (occasionally a ratio) between the total average infrared flux emanating at the surface and that at the top of the atmosphere. Defined in this way, the average atmospheric GE, according to satellite observations, is between 157 and 161 W m-2 (Ramanathan & Inamdar 2006; Lin et al. 2008; Trenberth et al. 2009). In other words, the current theory uses radiative flux units instead of temperature units to quantify ATE. This approach is based on the preconceived notion that GE works by reducing the rate of surface infrared cooling to space. However, measuring a phenomenon with its presumed cause instead by its manifest effect can be a source of major confusion and error as demonstrated in our study. Hence, we claim that the proper assessment of ATE depends on an accurate estimate of the mean surface temperature of an equivalent PGB (Tgb).
- Estimating the Mean Temperature of an Equivalent Planetary Gray Body
There are two approaches to estimate Tgb – a theoretical one based on known physical relationships between temperature and radiation, and an empirical one relying on observations of the Moon as the closest natural gray body to Earth.
According to the Stefan-Boltzmann (SB) law, any physical object with a temperature (T, oK) above the absolute zero emits radiation with an intensity (I, W m-2) that is proportional to the 4th power of the object’s absolute temperature:
where ϵ is the object’s thermal emissivity/absorptivity (0 ≤ ϵ ≤ 1 ), and σ = 5.6704×10-8 W m-2 K-4 is the SB constant. A theoretical blackbody has ϵ = 1.0, while real solid objects such as rocks usually have ϵ ≈ 0.95. In principle, Eq. (1) allows for an accurate calculation of an object’s equilibrium temperature given the amount of absorbed radiation by the object, i.e.
The spatially averaged amount of solar radiation absorbed by the Earth-Atmosphere system (Sα ̅̅̅, W m-2) can be accurately computed from TOA solar irradiance (Sα ̅̅̅, W m-2) and planetary albedo (αp) as
where the TOA shortwave flux (W m-2) incident on a plane perpendicular to the solar rays. The factor ¼ serves to distribute the solar flux incident on a flat surface to a sphere. It arises from the fact that the surface area of a sphere (4πR2) is 4 times larger than the surface area of a disk (πR2) of the same radius (R). Hence, it appears logical that one could estimate Earth’s average temperature in the absence of ATE from using the SB law. i.e.
Here (TeK) is known as the effective emission temperature of Earth. Employing typical values for S0 =W m-2 and αp = 0.3 and assuming, ϵ = 1.0 Eq. (3) yields 254.6K. This is the basis for the widely quoted 255K (-18C) mean surface temperature of Earth in the absence of a ‘greenhouse effect’, i.e. if the atmosphere were missing or ‘completely transparent’ to IR radiation. This temperature is also used to define the so-called effective emission height in the troposphere (at about 5 km altitude), where the bulk of Earth’s outgoing long-wave radiation to space is assumed to emanate from. Since Earth’s mean surface temperature is 287.6K (+14.4C), the present theory estimates the size of ATE to be 287.6K – 254.6K = 33K. However, as pointed out by other studies, this approach suffers from a serious logical error. Removing the atmosphere (or even just the water vapor in it) would result in a much lower planetary albedo, since clouds are responsible for most of Earth’s shortwave reflectance. Hence, one must use a different albedo (αp) in Eq. (3) that only quantifies the actual surface reflectance. A recent analysis of Earth’s global energy budget by Trenberth et al. (2009) using satellite observations suggests αp≈ 0.12. Serendipitously, this value is quite similar to the Moon bond albedo of 0.11 (see Table 1 in our original paper), thus allowing evaluation of Earth’s ATE using our natural satellite as a suitable PGB proxy. Inserting= 0.12 in Eq. (3) produces Te = 269.6K, which translates into an ATE of only 18K (i.e. 287.6 – 269.6 = 18K).
In summary, the current GE theory employs a simple form of the SB law to estimate the magnitude of Earth’s ATE between 18K and 33K. The theory further asserts that the Moon average temperature is 250K to 255K despite the fact that using the correct lunar albedo (0.11) in Eq. (3) produces ≈270K, i.e. a15K to 20K higher temperature! Furthermore, the application of Eq. (3) to calculate the mean temperature of a sphere runs into a fundamental mathematical problem caused by Hölder’s inequality between non-linear integrals (e.g. Kuptsov 2001). What does this mean? Hölder’s inequality applies to certain non-linear functions and states that, in such functions, the use of an arithmetic average for the independent (input) variable will not produce a correct mean value of the dependent (output) variable. Hence, due to a non-linear relationship between temperature and radiative flux in the SB law (Eq. 3) and the variation of absorbed radiation with latitude on a spherical surface, one cannot correctly calculate the mean temperature of a unidirectionally illuminated planet from the amount of spatially averaged absorbed radiation defined by Eq. (2). According to Hölder’s inequality, the temperature calculated from Eq. (3) will always be significantly higher than the actual mean temperature of an airless planet. We can illustrate this effect with a simple example.
Let’s consider two points on the surface of a PGB, P1 and P2, located at the exact same latitude (say 45oN) but at opposite longitudes so that, when P1 is fully illuminated, P2 is completely shaded and vice versa (see Fig. 1). If the PGB is orbiting at the same distance from the Sun as Earth and solar rays were the only source of heat to it, then the equilibrium temperature at the illuminated point would be (assuming a solar zenith angle θ = 45o), while the temperature at the shaded point would be T2 = 0 (since it receives no radiation due to cosθ < 0). The mean temperature between the two points is then Tm = (T1 + T2)/2 = 174.8K. However, if we try using the average radiation absorbed by the two points W m-2 to calculate a mean temperature, we obtain = 234.2K. Clearly, Te is much greater than Tm (Te ≫ Tm), which is a result of Hölder’s inequality.
Figure 1. Illustration of the effect of Hölder’s inequality on calculating the mean surface temperature of an airless planet. See text for details.
The take-home lesson from the above example is that calculating the actual mean temperature of an airless planet requires explicit integration of the SB law over the planet surface. This implies first taking the 4th root of the absorbed radiative flux at each point on the surface and then averaging the resulting temperature field rather than trying to calculate a mean temperature from a spatially averaged flux as done in Eq. (3).
Thus, we need a new model that is capable of predicting Tgb more robustly than Eq. (3). To derive it, we adopt the following reasoning. The equilibrium temperature at any point on the surface of an airless planet is determined by the incident solar flux, and can be approximated (assuming uniform albedo and ignoring the small heat contributions from tidal forces and interior radioactive decay) as
where is the solar zenith angle (radian) at point , which is the angle between solar rays and the axis normal to the surface at that point (see Fig. 1). Upon substituting , the planet’s mean temperature () is thus given by the spherical integral of , i.e.
Comparing the final form of Eq. (5) with Eq. (3) shows that Tgb << Te in accordance with Hölder’s inequality. To make the above expression physically more realistic, we add a small constant Cs =0.0001325 W m-2 to So, so that when So = 0.0, Eq. (5) yields Tgb = 2.72K (the irreducible temperature of Deep Space), i.e:
In a recent analytical study, Smith (2008) argued that Eq. (5) only describes the mean temperature of a non-rotating planet and that, if axial rotation and thermal capacity of the surface are explicitly accounted for, the average temperature of an airless planet would approach the effective emission temperature. It is beyond the scope of the current article to mathematically prove the fallacy of this argument. However, we will point out that increasing the mean equilibrium temperature of a physical body always requires a net input of extra energy. Adding axial rotation to a stationary planet residing in a vacuum, where there is no friction with the external environment does not provide any additional heat energy to the planet surface. Faster rotation and/or higher thermal inertia of the ground would only facilitate a more efficient spatial distribution of the absorbed solar energy, thus increasing the uniformity of the resulting temperature field across the planet surface, but could not affect the average surface temperature. Hence, Eq. (6) correctly describe (within the assumption of albedo uniformity) the global mean temperature of any airless planet, be it rotating or non-rotating.
Inserting typical values for Earth and Moon into Eq. (6), i.e. So = 1,362 W m-2, αo = 0.11, and ϵ = 0.955, produces Tgb = 154.7K. This estimate is about 100K lower than the conventional black-body temperature derived from Eq. (3) implying that Earth’s ATE (i.e. the GE) is several times larger than currently believed! Such a result, although mathematically justified, requires independent empirical verification due to its profound implications for the current GE theory. As noted earlier, the Moon constitutes an ideal proxy PGB in terms of its location, albedo, and airless environment, against which the thermal effect of Earth’s atmosphere could be accurately assessed. Hence, we now turn our attention to the latest temperature observations of the Moon.
- NASA’s Diviner Lunar Radiometer Experiment
In June 2009, NASA launched its Lunar Reconnaissance Orbiter (LRO), which carries (among other instruments) a Radiometer called Diviner. The purpose of Diviner is to map the temperature of the Moon surface in unprecedented detail employing measurements in 7 IR channels that span wavelengths from 7.6 to 400 μm. Diviner is the first instrument designed to measure the full range of lunar surface temperatures, from the hottest to the coldest. It also includes two solar channels that measure the intensity of reflected solar radiation enabling a mapping of the lunar shortwave albedo as well (for details, see the Diviner Official Website at http://www.diviner.ucla.edu/).
Although the Diviner Experiment is still in progress, most thermal mapping of the Moon surface has been completed and data are available online. Due to time constraints of this article, we did not have a chance to analyze Diviner’s temperature data ourselves. Instead, we elected to rely on information reported by the Diviner Science Team in peer-reviewed publications and at the Diviner website.
Data obtained during the LRO commissioning phase reveal that the Moon has one of the most extreme thermal environments in the solar system. Surface temperatures at low latitudes soar to 390K (+117C) around noon while plummeting to 90-95K (-181C), i.e. almost to the boiling point of liquid oxygen, during the long lunar night (Fig. 2). Remotely sensed temperatures in the equatorial region agree very well with direct measurement conducted on the lunar surface at 26.1o N by the Apollo 15 mission in early 1970s (see Huang 2008). In the polar regions, within permanently shadowed areas of large impact craters, Diviner has measured some of the coldest temperatures ever observed on a celestial body, i.e. down to 25K-35K (-238C to -248C). It is important to note that planetary scientists have developed detailed process-based models of the surface temperatures of Moon and Mercury some 13 years ago (e.g. Vasavada et al. 1999). These models are now being successfully validated against Diviner measurements (Paige et al. 2010b; Dr. M. Siegler at UCLA, personal communication).
What is most interesting to our discussion, however, are the mean temperatures at various lunar latitudes, for these could be compared to temperatures in similar regions on Earth to evaluate the size of ATE and to verify our calculations. Figure 3 depicts typical diurnal courses of surface temperature on the Moon at four latitudes (adopted from Paige et. al 2010a).
Figure 2. Thermal maps of the Moon surface based on NASA’s Diviner infrared measurements showing daytime maximum and nighttime minimum temperature fields (Source: Diviner Web Site).
Figure 3. Typical diurnal variations of the Moon surface temperature at various latitudes. Local time is expressed in lunar hours which correspond to 1/24 of a lunar month. At 89◦ latitude, diurnal temperature variations are shown at summer and winter solstices (adopted from Paige et al. 2010a). Dashed lines indicate annual means at the lunar equator and at the poles.
Figure 4. Temperature maps of the South Pole of the Moon and Earth: (A) Daytime temperature field at peak illumination on the Moon; (B) Nighttime temperature field on the Moon; (C) Mean summer temperatures over Antarctica; (D) Mean winter temperatures over Antarctica. Numbers shown in bold on panels (C) and (D) are temperatures in oK. Panels (A) and (B) are produced by the Diviner Lunar Radiometer Experiment (Paige et al. 2010b). Antarctica maps are from Wikipedia (http://en.wikipedia.org/wiki/Antarctic_climate). Comparison of surface temperatures between Moon’s South Pole and Antarctica suggests a thermal enhancement by the Earth atmosphere (i.e. a ‘Greenhouse Effect’) of about 107K in the summer and 178K in the winter for this part of the Globe.
Figures 4A & 4B display temperature maps of the Moon South Pole during daytime peak illumination and at night (Paige et. al 2010b). Since the Moon has a small obliquity (axial tilt) of only 1.54o and a slow rotation, the average diurnal temperatures are similar to seasonal temperature means. These data along with information posted at the Diviner Science webpage indicate that mean temperature at the lunar-surface ranges from 98K (-175C) at the poles to 206K (-67C) at the equator. This encompasses pretty well our theoretical estimate of 154.7K for the Moon mean global temperature produced by Eq. (6). In the coming months, we will attempt to calculate more precisely Moon’s actual mean temperature from Diviner measurements. Meanwhile, data published by NASA planetary scientists clearly show that the value 250K-255K adopted by the current GE theory as Moon’s average global temperature is grossly exaggerated, since such high temperature means do not occur at any lunar latitude! Even the Moon equator is 44K – 49K cooler than that estimate. This value is inaccurate, because it is the result of an improper application of the SB law to a sphere while assuming the wrong albedo (see discussion in Section 2.1 above)!
Similarly, the mean global temperatures of Mercury (440K) and Mars (210K) reported on the NASA Planetary Fact Sheet are also incorrect, since they have been calculated from the same Eq. (3) used to produce the 255K temperature for the Moon. We urge the reader to verify this claim by applying Eq. (3) with data for solar irradiance (So) and bond albedo (αo) listed on the fact sheet of each planet while setting ϵ = 1. This is the reason that, in our original paper, we used 248.2K for Mercury, since that temperature was obtained from the theoretically correct Eq. (6). For Mars, we adopted means calculated from regional data of near-surface temperature and pressure retrieved by the Radio Science Team at Stanford University employing remote observations by the Mars Global Surveyor spacecraft. It is odd to say the least that the author of NASA’s Planetary Fact Sheets, Dr. David R. Williams, has chosen Eq. (3) to calculate Mars’ average surface temperature while ignoring the large body of high-quality direct measurements available for the Red Planet!?
So, what is the real magnitude of Earth’s Atmospheric Thermal Effect?
Table 1. Estimated Atmospheric Thermal Effect for equator and the poles based on observed surface temperatures on Earth and the Moon and using the lunar surface as a proxy for Earth’s theoretical gray body. Data obtained from Diviner’s Science webpage, Paige at al. (2010b), Figure 4, and Wikipedia:Oymyakon.
Figure 5. Earth’s mean annual near-surface temperature according to Wikipedia (Geographic Zones: http://en.wikipedia.org/wiki/Geographical_zone).
Table 1 shows observed mean and record-low surface temperatures at similar latitudes on Earth and on the Moon. The ATE is calculated as a difference between Earth and Moon temperatures assuming that the Moon represents a perfect PGB proxy for Earth. Figure 5 displays a global map of Earth’s mean annual surface temperatures to help the reader visually verify some of the values listed in Table 1. The results of the comparison can be summarized as follows:
The Atmospheric Thermal Effect, presently known as the natural Greenhouse Effect, varies from 93K at the equator to about 150K at the poles (the latter number represents an average between North- and South- Pole ATE mean values, i.e. (158+143)/2 =150.5. This range encompasses quite well our theoretical estimate of 133K for the Earth’s overall ATE derived from Eq. (6), i.e. 287.6K – 154.7K = 132.9K.
Of course, further analysis of the Diviner data is needed to derive a more precise estimate of Moon’s mean surface temperature and verify our model prediction. However, given the published Moon measurements, it is clear that the widely quoted value of 33K for Earth’s mean ATE (GE) is profoundly misleading and wrong!
- Conclusion
We have shown that the SB Law relating radiation intensity to temperature (Eq. 1 & 3) has been incorrectly applied in the past to predict mean surface temperatures of celestial bodies including Mars, Mercury, and the Moon. Due to Hölder’s inequality between non-linear integrals, the effective emission temperature computed from Eq. (3) is always significantly higher than the actual (arithmetic) mean temperature of an airless planet. This makes the planetary emission temperature Te produced by Eq. (3) physically incompatible with any real measured temperatures on Earth’s surface or in the atmosphere. By using a proper integration of the SB Law over a sphere, we derived a new formula (Eq. 6) for estimating the average temperature of a planetary gray body (subject to some assumptions). We then compared the Moon mean temperature predicted by this formula to recent thermal observations and detailed energy budget calculation of the lunar surface conducted by the NASA Diviner Radiometer Experiment. Results indicate that Moon’s average temperature is likely very close to the estimate produced by our Eq. (6). At the same time, Moon measurements also show that the current estimate of 255K for the lunar average surface temperature widely used in climate science is unrealistically high; hence, further demonstrating the inadequacy of Eq. (3). The main result from the Earth-Moon comparison (assuming the Moon is a perfect gray-body proxy of Earth) is that the Earth’s ATE, also known as natural Greenhouse Effect, is 3 to 7 times larger than currently assumed. In other words, the current GE theory underestimates the extra atmospheric warmth by about 100K! In terms of relative thermal enhancement, the ATE translates into NTE = 287.6/154.7 = 1.86.
This finding invites the question: How could such a huge (> 80%) thermal enhancement be the result of a handful of IR-absorbing gases that collectively amount to less than 0.5% of total atmospheric mass? We recall from our earlier discussion that, according to observations, the atmosphere only absorbs 157 – 161 W m-2 long-wave radiation from the surface. Can this small flux increase the temperature of the lower troposphere by more than 100K compared to an airless environment? The answer obviously is that the observed temperature boost near the surface cannot be possibly due to that atmospheric IR absorption! Hence, the evidence suggests that the lower troposphere contains much more kinetic energy than radiative transfer alone can account for! The thermodynamics of the atmosphere is governed by the Gas Law, which states that the internal kinetic energy and temperature of a gas mixture is also a function of pressure (among other things, of course). In the case of an isobaric process, where pressure is constant and independent of temperature such as the one operating at the Earth surface, it is the physical force of atmospheric pressure that can only fully explain the observed near-surface thermal enhancement (NTE). But that is the topic of our next paper… Stay tuned!
- References
Inamdar, A.K. and V. Ramanathan (1997) On monitoring the atmospheric greenhouse effect from space. Tellus 49B, 216-230.
Houghton, J.T. (2009). Global Warming: The Complete Briefing (4th Edition). Cambridge University Press, 456 pp.
Huang, S. (2008). Surface temperatures at the nearside of the Moon as a record of the radiation budget of Earth’s climate system. Advances in Space Research 41:1853–1860 (http://www.geo.lsa.umich.edu/~shaopeng/Huang07ASR.pdf)
Kuptsov, L. P. (2001) Hölder inequality. In: Encyclopedia of Mathematics, Hazewinkel and Michiel, Springer, ISBN 978-1556080104.
Lin, B., P. W. Stackhouse Jr., P. Minnis, B. A. Wielicki, Y. Hu, W. Sun, Tai-Fang Fan, and L. M. Hinkelman (2008). Assessment of global annual atmospheric energy balance from satellite observations. J. Geoph. Res. Vol. 113, p. D16114.
Paige, D.A., Foote, M.C., Greenhagen, B.T., Schofield, J.T., Calcutt, S., Vasavada, A.R., Preston, D.J., Taylor, F.W., Allen, C.C., Snook, K.J., Jakosky, B.M., Murray, B.C., Soderblom, L.A., Jau, B., Loring, S., Bulharowski J., Bowles, N.E., Thomas, I.R., Sullivan, M.T., Avis, C., De Jong, E.M., Hartford, W., McCleese, D.J. (2010a). The Lunar Reconnaissance Orbiter Diviner Lunar Radiometer Experiment. Space Science Reviews, Vol 150, Num 1-4, p125-16 (http://www.diviner.ucla.edu/docs/fulltext.pdf)
Paige, D.A., Siegler, M.A., Zhang, J.A., Hayne, P.O., Foote, E.J., Bennett, K.A., Vasavada, A.R., Greenhagen, B.T, Schofield, J.T., McCleese, D.J., Foote, M.C., De Jong, E.M., Bills, B.G., Hartford, W., Murray, B.C., Allen, C.C., Snook, K.J., Soderblom, L.A., Calcutt, S., Taylor, F.W., Bowles, N.E., Bandfield, J.L., Elphic, R.C., Ghent, R.R., Glotch, T.D., Wyatt, M.B., Lucey, P.G. (2010b). Diviner Lunar Radiometer Observations of Cold Traps in the Moon’s South Polar Region. Science, Vol 330, p479-482. (http://www.diviner.ucla.edu/docs/paige_2010.pdf)
Ramanathan, V. and A. Inamdar (2006). The Radiative Forcing due to Clouds and Water Vapor. In: Frontiers of Climate Modeling, J. T. Kiehl and V. Ramanthan, Editors, (Cambridge University Press 2006), pp. 119-151.
Smith, A. 2008. Proof of the atmospheric greenhouse effect. Atmos. Oceanic Phys. arXiv:0802.4324v1 [physics.ao-ph] (http://arxiv.org/PS_cache/arxiv/pdf/0802/0802.4324v1.pdf ).
Stephens, G.L., A. Slingo, and M. Webb (1993) On measuring the greenhouse effect of Earth. NATO ASI Series, Vol. 19, 395-417.
Trenberth, K.E., J.T. Fasullo, and J. Kiehl (2009). Earth’s global energy budget. BAMS, March:311-323
Vasavada, A. R., D. A. Paige and S. E. Wood (1999). Near-surface temperatures on Mercury and the Moon and the stability of polar ice deposits. Icarus 141:179–193 (http://www.gps.caltech.edu/classes/ge151/references/vasavada_et_al_1999.pdf)

Dan in Nevada says:
January 23, 2012 at 3:25 pm
P = T / V
Yes but the atmosphere’s volume is not fixed. The pressure is fixed. If you heat or cool the atmosphere the pressure doesn’t change – the volume changes instead. If temperature doesn’t control pressure then it follows that pressure doesn’t control temperature. The author’s contention that pressure sets temperature is thus disproven. QED
Are you sure about that?
You could have the cause and effect inverted.
Perhaps the clouds exist because the ground is warmer and the atmospheric moisture profile allows the clouds to form.
If you had a dry atmosphere you would have the air cooling at the dry adiabatic lapse rate as you go up in altitude.
The dry adiabatic lapse rate is one degree Celsius of cooling for every 100 meters (1°C/100m, 10°C/kilometer or 5.5°F/1000 feet
How ever if the air column is not dry, than you can have any lapse rate between the dry adiabatic lapse rate and the wet adiabatic lapse rate.
wet adiabatic lapse rate is 0.5°C/100 m (5°C/kilometer or 3.3°F/1000 feet). The saturated adiabatic lapse rate does vary with temperature.
In conditions that allow clouds to form, the lower air below the cloud deck will cool at some rate between the dry adiabatic lapse rate and the wet adiabatic lapse rate of 3.3 degF per 1000 ft until the air reaches the lifted condensation level (LCL) {if it is mechanically lifted} where it becomes saturated and the water vapor condenses liberating all its latent heat of evaporation, warming the air it is mixed with. Other wise condensation will release this latent heat at the convective condensation level (CCL). This can cap off convection if the warmed air does not reach the conditions to begin free convection and is too dense to continue rising buoyantly.
This can cap off the convective lifting as that layer of air warmed by the condensing water vapor is warmer and less dense than the air below it. But once it is shed of its water load, and dry it is not hot enough and too dense to continue rising through the dryer layers above.
You have created a thermal inversion layer that cuts off convection cooling to high altitude. You can see this on a skew T chart under conditions of a cloud deck forming.
http://www.theweatherprediction.com/thermo/qanda/
http://geog-www.sbs.ohio-state.edu/courses/G620/jrogers/L12ThermoDiag.pdf
It is this liberated energy and the fact that in the cases of low level clouds, indicates that convection is capped that are actually causing the warm nights. The clouds are the symptom not the cause of the warming. The cause of the warm night and lack of cooling is the lack of convective transport to higher altitudes and liberated latent heat of evaporation of water contained in the local air mass.
Larry
A better discussion of the Skew T chart and what all the lines mean.
http://www.met.tamu.edu/class/atmo251/Skew-T.pdf
Larry
thepompousgit;
How long has temperature been energy? Or am I misreading Ned’s comment>>>
Methinks he is simply responding to poor wording on my part.
I said that a “degree” is worth more “watts” in the tropics than in the arctic. That’s true, but it conveys the suggestion that by moving a “degree” from the tropics to the arctic I’m creating watts. That wasn’t my intention.
Better would have been to not that if I take a given number of w/m2 from the tropics, and via conduction and convection, move it to high latitudes where it is then radiated away, I do not create any additional energy, but I do create additional “degrees”.
For example, if conduction/convection/whatever cools the tropics from 40C to 39C, that’s a reduction of about 7 w/m2. If that 7 w/m2 gets moved to the arctic where it is -40C, it will increase the surface temperature of one square meter of arctic by 2.4 degrees. If we just consider the one square meter in each region, +40 and -40 have the same total radiance as +39 and -37.6 which averages to 0.7 degrees instead of 0 degrees. The more energy is moved from tropics to poles, the higher the “average” temperature is.
How efficiently energy gets moved from tropics to poles is going to be governed by a variety of factors, but two factors will dominate.
1. The higher the surface pressure, the more efficient the tansport will be, the more efficient the transport, the more uniform the temperature, and the more uniform the temperature, the higher the “average” temperature. Other processes such as GHG’s get to play, but they are dominated by surface pressure to the point of being negligible.
2. Re-distribution of energy from tropics to poles must increase until thermal equilibrium is reached. Once the high latitudes have warmed sufficiently that their net loss to space equals the net gain in the low latitudes, the planet is in thermal equilibrium. Low pressure means inefficient movement and hence a very hot tropics and not so much warmer high latititudes. High pressure means more efficient movement which means cooler tropics and warmer high lats. Both have the same net radiance to space, but the average T of the latter is higher.
“”””” Ralph says:
January 23, 2012 at 3:21 pm
>>>>kdk33 says: January 23, 2012 at 10:09 am
KDK, the warming of the atmosphere cannot be solely due to conduction and convection, and we know this because when it is cloudy overnight, even a thin layer of cloud can ‘warm’ the atmosphere by 10 – 15 oc. The cloud layer is acting like GHGs, and reraditing the LW back to the surface, reducing the heat-loss to space, making the surface warmer than it would be otherwise.
If clouds can do this, and we know they can, then so can GHGs, because we know that (like clouds), they can absob and reemit LW radiation.
We don’t notice the GHGs doing this, because they do it all the time. But the intermittent appearance of clouds and their huge effect on night temperatures proves that an ‘insulator’ (an absorber and reemitter) can reduce surface and atmospheric heat loss.
Note also that clouds can do this at a very low level. An ‘insulating’ cloud layer at just 1,500 ft can keep the surfsce much warmer, and so this is not simply a matter of increasing the emmision height in the atmosphere. “””””
I’d like a dollar for every time somebody says that clouds warm the surface or keep the surface warmer, and the higher the cloud, the warmer they keep the surface.
I’ve been watching clouds for the better part of a century, and I’ve never yet seen one that warmed me up. A cloud gets between me and the sun, and I get colder, instantaneously, no matter what species of cloud it is, and no matter how high or low it is.
As a practical matter; as far as “reflection”, or “re-emission” from a cloud, of the surface emitting (right under my feet (nearly)) LWIR, the reflection / re-emission from the cloud; back to my feet (nearly) diminishes as the fourth power of the cloud altitude; in fact worse, because the cloud also emits isotropically, so half goes up, and half comes back down, and the lower moisture density of the higher cloud absorbs less LWIR energy.
Now the interesting thing is that the surface is mostly lower in Temperature than my body is at, and I can’t even sense the LWIR from the surface (near my feet) , so how could I possibly detect the miniscule portion of that undetectable radiation that finally makes it back down from the cloud.
But I can detect the near IR radiation from the sun, that is strongly absorbed in the water in my skin, so it heats my skin, and often that solar radiation also evaporates moisture and heats the ground and the air, so that it feels hotter than usual, since my skin can’t sweat into that high humidity warm air. And when the sun finally does go down or set, the warm moist air which is constantly rising moves into a cooler upper air layer, until the Temperature drops to the dew point and that magic “warming” cloud appears. Funny thing is, despite the appearance of that cloud, the surface continues to cool after sunset; it never warms up again; and the hotter it was during the day, the higher that moist air has to go for the normal Temperature lapse rate drops it to the dew point, so the cloud forms higher in altitude. And if the amount of moisture was lower during the day, the relative humidity will be lower, and the dew point will be even colder, so the clouds form higher still; but they still don’t warm the surface; the SUN did that during the day.
Bob Fernley-Jones says:
You are still not getting it. How is it possible to have 150 W/m^2 leaving the surface as radiation than leaving the TOA unless some of that radiation is getting absorbed (or reflected), i.e., unless there is a greenhouse effect? Air pressure does not absorb electromagnetic radiation….You are simply talking nonsense.
Nikolov does not have a PhD in physics…His PhD is in Forest Ecology ( http://www.fs.fed.us/rm/analytics/staff/nikolov.html ) Zeller does not have a PhD in physics…His PhD is in fluid mechanics and wind engineering ( http://www.fs.fed.us/rm/analytics/staff/zeller.html ). In fact, neither of them have any sort of degree (e.g., even a B.S.) in physics.
Robert Brown and I have PhD’s in physics. That doesn’t make us right but what does make us right is that we have simple compelling arguments and nobody has been able to refute our arguments using correct physics principles.
Nick Stokes says:
January 23, 2012 at 1:47 pm
Indeed, you are correct. My bad, moving too fast. The problem remains, let me illustrate it correctly. To integrate over the entire surface, mu has to go from -1 to 1. N&Z only integrate from 0 to 1.

Shouldn’t the answer for the whole surface be the average of those two?
My point exactly. N&Z didn’t do that. They made one conversion but not the other.
They started out with a function in theta, equation 4. Theta is the zenith angle. That is the function they are integrating for all possible angles of theta and phi.
So when they replace it with mu, as you point out, they have to make the corresponding change in d(theta) d(phi). But they haven’t. They are integrating straight d(mu) d(phi).
Hope that is clearer.
Regards,
w.
OzWizard says:
January 23, 2012 at 1:50 pm
Can’t be, because theta is the zenith angle of the sun (the angle the sun makes with the point overhead. So it’s from sun overhead to sun at the horizon.
w.
Willis Eschenbach says:
Willis: What you are missing is what I explained to you before. To integrate a function f(theta,phi) over a sphere, you don’t integrate f(theta,phi)*d(theta)*d(phi). You integrate f(theta,phi)*sin(theta)*d(theta)*d(phi), which can be rewritten as -f(mu,phi)*d(mu)*d(phi) where mu = cos(theta).
N&Z have done the math correctly. It is the physics that is completely wrong.
Joel Shore says:
January 23, 2012 at 2:56 pm
Ned Nikolov says:
……………………………..
And, any elementary book on climate science will tell you that the effective radiating layer being at a lower temperature than the surface is a necessary condition for there to be a radiative greenhouse effect. For example, Ray Pierrehumbert’s book (p. 148) says: “The key insight to be taken from this discussion is that the greenhouse effect only works to the extent that the atmosphere is colder at the radiating level than it is at the ground.”
Joel,
As I understand what you just excerpted from Peter Humbug’s book, “the radiating level”, is the apparent level in the atmosphere, that is ACTUALLY EMITTING the LWIR radiation that finally cools the planet, and the Temperature at that level in the atmosphere is LOWER THAN THE SURFACE TEMPERATURE which was the ORIGINAL source of the LWIR emission.
The molecular absorption bands of the common GHG species are functions of the electron structure of the emitting molecules; they are NOT first order functions of Temperature.
Therefore any radiation being emitted from GHG molecules rather than the surface (ground or ocean), must have a Temperature independent emission spectrum.
The only sort of radiation which has a primary dependence on the Temperature of the emitting medium, is thermal Planckian style radiation, which has a spectrum given by the Planck formula, and a total radiant emittance that depends on the emissivity of the emitting material.
And we have it beaten into us every day, that this source cannot be the atmosphere principal gases, N2, O2, and Ar, sincer they can’t emit black body style radiation, having no electric dipole moment.
So how can the upper atmosphere be emitting a Temperature dependant emission spectrum, since neither the main atmospheric gases, nor the GHGs are capable of doing that (so they say)
The ground (solid or liquid) is the only thing capable of emitting a BB like spectrum; so the outgoing LWIR from the atmosphere, should have a spectrum depending on the ground Temperature, less the holes carved by the GHG trace gases.
Joules Verne says:
January 23, 2012 at 4:33 pm
“Dan in Nevada says:
January 23, 2012 at 3:25 pm
P = T / V
Yes but the atmosphere’s volume is not fixed. The pressure is fixed. If you heat or cool the atmosphere the pressure doesn’t change – the volume changes instead. If temperature doesn’t control pressure then it follows that pressure doesn’t control temperature. The author’s contention that pressure sets temperature is thus disproven. QED”
Joules, You didn’t read very carefully. I stipulated that pressure is fixed. That’s what I meant by “a pressure P will develop and remain constant because the planet’s gravity is constant and n does not change”. “Constant” and “fixed” are synonymous for purposes of my example. That being the case, only V and T can vary AND according to the ideal gas law they will vary proportionate to each other, i.e. if V doubles then T must double.
For you to say that is wrong, you have to be saying that a heated atmosphere will neither be warmer (have a higher temperature) or occupy more volume than the same atmosphere at absolute zero. If you argue that the volume WILL be greater, then the ideal gas law apparently requires the temperature will be greater also.
Dan
Joel Shore;
You are still not getting it. How is it possible to have 150 W/m^2 leaving the surface as radiation than leaving the TOA unless some of that radiation is getting absorbed (or reflected), i.e., unless there is a greenhouse effect?>>>
It isn’t and it doesn’t. You keep averaging things that should not be averaged and then drawing false conclusions from them. Here is the ERBE image of net radiance of the earth:
http://eos.atmos.washington.edu/cgi-bin/erbe/disp.pl?net.ann.
Note that the tropics are net absorbers of energy, and hence radiating at a temperature well below their SB Law equilibrium temperature for the amount of radiance they receive.
Note that the high latitudes are net losers of energy, and hence radiating at a temperature well above their SB Law equilibrium temperature for the amount of radiance they receive.
Note that for the planet to be in thermal equilibrium, the net loss from the high latitudes must equal exactly the net gain from the low latitudes.
Note that there are multiple mechanisms by which energy is moved from the tropics to the high latitudes, and note further that it matters not in the slightest what they are, only that thermal equilibrium is achieved.
Now for the hard part that requires that you STOP averaging things that should not be averaged.
Note that the increase in the number of degrees above SB Law of the high latitudes is in excess of the decrease in the number of degrees of the low latitudes despite. Despite the amount of energy being moved FROM the tropics being exactly equal to the amount of energy being moved TO the high latitudes, the TEMPERATURE of the high latitudes increases MORE than the temperature that the low latitudes decrease by.
Hence, the “average” temperature of the earth with an atmosphere is higher than the average temperature of the earth with no atmosphere because the atmosphere enables the movement of energy from tropics to high latitudes, and while doing so does NOT change the total amount of energy radiated to space, it DOES increase the average temperature of the earth.
This is not to say that GHG’s do not also alter surface temperature, but it does show that the surface temperature can be raised, and raised significantly, simply through conduction and convection moving energy from the hottest part of the planet to the colder parts. Every watt moved from tropics to artic and then radiated out raises the temperature of the arctic more than it cools the tropics.
That is why if you ignore SB Law which states that P varies with T^4 and instead average just P and compare to averae of just T, you get wrong answers.
Willis,
“My point exactly. N&Z didn’t do that.”
I think they just skipped explanation. The area element that you need for sphere with θ, φ surface integration is sin(θ) dθ dφ. They have gone straight to the μ form, but I think correctly.
In this context, if you start getting gamma functions of fractional arguments, something has gone wrong.
Willis,
I should have added that their changing the range of integration from (-1,1) to (0,1) is OK, because their integrand as defined is zero on (-1,0).
davidmhoffer says:
[A bunch of repetitive stuff that doesn’t at all address the issue.]
Dave: We all understand the difference between averaging T^4 and T. That doesn’t get you around having to explain how the Earth’s surface can emit an average of 390 W/m^2 at the surface and 240 W/m^2 at the top of the atmosphere. The only explanation of that is that there is a greenhouse effect.
(For those incapable of understanding how averages work, not to mention any names, you can multiply all my numbers by the surface area of the earth and then you just get power.)
George E. Smith; said @ur momisugly January 23, 2012 at 5:37 pm
I rather thought GHGs are capable of emitting IR and do so in the boundary layer (rather than the upper atmosphere). My reference is Oke’s Boundary Layer Climates (1987) rather than Humbert. I have been feverishly rereading Oke rather than attempting to follow most of the er… convoluted arguments here recently.
“”””” Joel Shore
Robert Brown
………………………..
Robert: I would strongly suggest you read more about how the radiative-convective transport problem is solved before you hook yourself to the “CO2 effect is saturated” wagon! This is a point that no serious climate scientist believes…Roy Spencer and Richard Lindzen both acknowledge that the radiative forcing due to doubling CO2 levels is about 4 W/m^2. Why CO2 continues to be important is well-understood and the lack of saturation emerges in everything from simple “toy” models to the most sophisticated radiative-convective calculations.
The basic things to recognize are these:
(1) It is a multiple absorption-emission problem, not an issue of whether or not the CO2 can absorb the terrestrial emission once…….”””””
Gotta agree with you there Joel; “CO2 is saturated” is not a good hill to die on. Throughout the bulk of the atmosphere, as Phil has pointed out on many occasions, the mean time between molecular collisions is a lot less, than the mean lifetime of the CO2 excited states (in the 15 micron band), so upon capturing a 15 micron photon, the CO2 quickly loses the enrgy to collisions with other gas moleculesd, N2, O2, and Ar. The CO2 molecules think they are one of a kind, and have no knowledge of a kindred molecule since the nearest one is on average about 13 molecular layers removed. So the captured LWIR energy is quickly thermalized, and the CO2 is reset for its next victim.
I keep thinking that some terraflop computer jockey must have rigorously simulated this cascade absorption / thermalization /absorption process for CO2; maybe Peter Humbug; and if he hasn’t, why hasn’t he done it?
He reported on a simulation where he took ALL of the H2O out of the atmosphere, and he said he got it all back in just three months (I believe him). I wish he had taken ALL the CO2 out as well. I believe he would at least get all the H2O back in about three months; might have to wait a good while for his CO2.
Time to hit the books again Robert .
@ur momisugly Bob_FJ
Bob, don’t let Joel Shore throw you, he’s trying to be his dishonest self, but don’t let him do that. He shows with every word how little he knows of physics in the real world. He lives in books. If his books never say it, to him it does not exist. He says:
BS! Bob, you are not talking nonsense, Joel is. Some of it is absorbed, a lot, depending on the pressure and density. It is this horizontal resonance, the passing of the same energy back and forth horizontally, that it what keeps us warm at the surface. In a way you can call IT radiation trapping. Not specifically GHGs but any gas depending on it’s molar mass and the total mass as I explained last night.
Thick gases of any type absorb radiation. This absorption varies from gas to gas; even which multiple gas species are present in the composition, for you have gas-gas interactions, which even modify that. Think once again of your ‘horizontal radiation’ thread. Great insight. Look at some ground based astronomy sites and read how they must always allow for this absorption (mass extinction coefficient), especially at any angle except straight up at the zenith where the minimal occurs. The thicker the gas, the greater the density and pressure and the greater this absorption occurs, any frequency.
Bob, you still have never acknowledged that you understand this real world aspect. Please let me know if that occurs so I can stop repeating this to you and start repeating it to some others. You are the closest that shows the insight to ‘see’ it. That is key to really understanding how N&Z’s physically manifests itself in real parameters.
I believe the correct way to integrate equation 4 over the sphere is:
T.gb = ∫[-½π,½π] ∫[-½π,½π] root4( S.0 (1-α.0) / (εσ) ) root4 (cos(x)) root4 (cos(φ)) dx dφ
with x and φ being the angle of incidence in both directions,
or more simply:
T.gb = C ∫[-½π,½π] ∫[-½π,½π] root4 (cos(x)) root4 (cos(φ)) dx dφ
where C is the constant root4( S.0 (1-α.0) / (εσ) ).
Anyway, that’s the way I see it according to the argument in the article, as the incident solar flux striking the sphere.
Why is it that people keep explaining that the sun is heating the ground and the ocean during the day, and then during the night everything reverts to radiating energy away to cool things.
The earth COOLS much faster during the day, than it does during the night. In the hottest tropical deserts, the earth cools during the day at over twice the global average cooling rate. If it didn’t then the earth would be very much hotter than it is.
On the other hand the cooling rate at the poles is more than ten times lower than it is during the day in the tropical deserts; so the polar regions serve very little to cool this planet.
In addition the surface emission in the tropical deserts moves even further into the atmospheric window, getting further away from the 15 micron CO2 absorption band, and even dodging much of the Ozone block. And of course with very little moisture in the tropical deserts, the atmosphere never had it so good in passing most of the surface LWIR radiation energy through to space.
Mike Monce says:
January 23, 2012 at 3:44 pm
Finally, someone explains the question. You are right, I was 100% wrong. I just ran through it and it makes perfect sense now. I had neglected the Sin[theta] term necessary for the spherical integration. Many, many thanks for clearing that up for me.

However, I’m still perplexed about them only integrating over half the sphere. In equation (5) they only integrate mu for the interval zero to one … what about the dark half of the globe? Shouldn’t the final integral be the average of the two halves?
Thanks again,
w.
Tilo Reber says:
The gradient is not always in the same direction…When it is daytime, the surface is warmer than the subsurface. When it is nighttime, the surface is colder than the subsurface. The subsurface averages out the variations that occur at the surface.
Willis Eschenbach says:
I thought I explained that last night: http://wattsupwiththat.com/2012/01/22/unified-theory-of-climate-reply-to-comments/#comment-872924
To get the average temperature, they are integrating the temperature over the surface area of the sphere (i.e., the integral of T*dA where dA is the surface area element for a surface of radius 1) and dividing by the surface area (i.e., the integral of dA). The surface area is 4*pi, thus the 1/(4*pi) factor. The integral of T*dA consists of the integral over the day side plus the integral over the night side. HOWEVER, THE INTEGRAL OVER THE NIGHTSIDE IS ZERO (BECAUSE THE INTEGRAND IS ZERO) AND HENCE IT DOESN’T CONTRIBUTE.
Tallbloke,
here is the link to one of the Nagihara papers detailing the surface and subsurface temps for the Apollos 15 and 17 landing sites http://adsabs.harvard.edu/abs/2010LPICo1530.3008N
The subsurface temps 0.5 to 1.0 metre down are very close to 255K
Regards dlb
“davidmhoffer says:
January 23, 2012 at 11:18 am
Ned Nikolov;
Re-distribution of energy CANNOT create additional energy.>>>
I never said it did.
I said that re-distribution of energy from the warmer tropics to the cooler high latitudes creates more DEGREES.”
You are saying the joules of energy from tropics gives more increase the cooler temperate zones.
You sort of saying it’s harder for temperate zone to get warmer from every watt from the sun.
Or if dial up the watts- the tropics get 1 watt per watt and temperature get 1/2 watt per watt- not necessarily that ratio.
I would say something slightly different, the tropics has excessive amount money and if gives some away it can get more energy easier than temperate zones.
So not only is it’s money worth more, but tropic as much higher income, and gets substantial tax break for charity.