Perpetuum Mobile

Guest Post by Willis Eschenbach

Since at least the days of Da Vinci, people have been fascinated by perpetual motion machines. One such “perpetuum mobile” designed around the time of the civil war is shown below. It wasn’t until the development of the science of thermodynamics that it could be proven that all such mechanisms are impossible. For such machines to work, they’d have to create energy, and energy cannot be either created or destroyed, only transformed.

Image Source

I bring this up for a curious reason. I was reading the Jelbring hypothesis this afternoon, which claims that greenhouse gases (GHGs) are not the cause of the warming of the earth above the theoretical temperature it would have without an atmosphere. Jelbring’s hypothesis is one of several “gravito-thermal” theories which say the heating of the planet comes from gravity rather than (or in some theories in addition to) the greenhouse effect. His thought experiment is a planet with an atmosphere. The planet is isolated from the universe by an impervious thermally insulating shell that completely surrounds it, and which prevents any energy exchange with the universe outside. Inside the shell, Jelbring says that gravity makes the upper atmosphere colder and the lower atmosphere warmer. Back around 2004, I had a long discussion on the “climateskeptics” mailing list with Hans Jelbring. I said then that his theory was nothing but a perpetual motion machine, but at the time I didn’t understand why his theory was wrong. Now I do.

Dr. Robert Brown has an fascinating post on WUWT called “Earth’s baseline black-body model – a damn hard problem“. On that thread, I had said that I thought that if there was air in a tall container in a gravity field, the temperature of the air would be highest at the bottom, and lowest at the top. I said that I thought it would follow the “dry adiabatic lapse rate”, the rate at which the temperature of dry air drops with altitude in the earth’s atmosphere.

Dr. Brown said no. He said that at equilibrium, a tall container of air in a gravity field would be the same temperature everywhere—in other words, isothermal.

I couldn’t understand why. I asked Dr. Brown the following question:

Thanks, Robert, With great trepidation, I must disagree with you.

Consider a gas in a kilometre-tall sealed container. You say it will have no lapse rate, so suppose (per your assumption) that it starts out at an even temperature top to bottom.

Now, consider a collision between two of the gas molecules that knocks one molecule straight upwards, and the other straight downwards. The molecule going downwards will accelerate due to gravity, while the one going upwards will slow due to gravity. So the upper one will have less kinetic energy, and the lower one will have more kinetic energy.

After a million such collisions, are you really claiming that the average kinetic energy of the molecules at the top and the bottom of the tall container are going to be the same?

I say no. I say after a million collisions the molecules will sort themselves so that the TOTAL energy at the top and bottom of the container will be the same. In other words, it is the action of gravity on the molecules themselves that creates the lapse rate.

Dr. Brown gave an answer that I couldn’t wrap my head around, and he recommended that I study the excellent paper of Caballero for further insight. Caballero discusses the question in Section 2.17. Thanks to Dr. Browns answer plus Caballero, I finally got the answer to my question. I wrote to Dr. Brown on his thread as follows:

Dr. Brown, thank you so much. After following your suggestion and after much beating of my head against Caballero, I finally got it.

At equilibrium, as you stated, the temperature is indeed uniform. I was totally wrong to state it followed the dry adiabatic lapse rate.

I had asked the following question:

Now, consider a collision between two of the gas molecules that knocks one molecule straight upwards, and the other straight downwards. The molecule going downwards will accelerate due to gravity, while the one going upwards will slow due to gravity. So the upper one will have less kinetic energy, and the lower one will have more kinetic energy.

After a million such collisions, are you really claiming that the average kinetic energy of the molecules at the top and the bottom of the tall container are going to be the same?

What I failed to consider is that there are fewer molecules at altitude because the pressure is lower. When the temperature is uniform from top to bottom, the individual molecules at the top have more total energy (KE + PE) than those at the bottom. I said that led to an uneven distribution in the total energy.

But by exactly the same measure, there are fewer molecules at the top than at the bottom. As a result, the isothermal situation does in fact have the energy evenly distributed. More total energy per molecules times fewer molecules at the top exactly equals less energy per molecule times more molecules at the bottom. Very neat.

Finally, before I posted my reply, Dr. Brown had answered a second time and I hadn’t seen it. His answer follows a very different (and interesting) logical argument to arrive at the same answer. He said in part:

Imagine a plane surface in the gas. In a thin slice of the gas right above the surface, the molecules have some temperature. Right below it, they have some other temperature. Let’s imagine the gas to be monoatomic (no loss of generality) and ideal (ditto). In each layer, the gravitational potential energy is constant. Bear in mind that only changes in potential energy are associated with changes in kinetic energy (work energy theorem), and that temperature only describes the average internal kinetic energy in the gas.

Here’s the tricky part. In equilibrium, the density of the upper and lower layers, while not equal, cannot vary. Right? Which means that however many molecules move from the lower slice to the upper slice, exactly the same number of molecules must move from the upper slice to the lower slice. They have to have exactly the same velocity distribution moving in either direction. If the molecules below had a higher temperature, they’d have a different MB [Maxwell-Boltzmann] distribution, with more molecules moving faster. Some of those faster moving molecules would have the right trajectory to rise to the interface (slowing, sure) and carry energy from the lower slice to the upper. The upper slice (lower temperature) has fewer molecules moving faster — the entire MB distribution is shifted to the left a bit. There are therefore fewer molecules that move the other way at the speeds that the molecules from the lower slice deliver (allowing for gravity). This increases the number of fast moving molecules in the upper slice and decreases it in the lower slice until the MB distributions are the same in the two slices and one accomplishes detailed balance across the interface. On average, just as many molecules move up, with exactly the same velocity/kinetic energy profile, as move down, with zero energy transport, zero mass transport, and zero alteration of the MB profiles above and below, only when the two slices have the same temperature. Otherwise heat will flow from the hotter (right-shifted MB distribution) to the colder (left-shifted MB distribution) slice until the temperatures are equal.

It’s an interesting argument. Here’s my elevator speech version.

• Suppose we have an isolated container of air which is warmer at the bottom and cooler at the top. Any random movement of air from above to below a horizontal slice through the container must be matched by an equal amount going the other way.

• On average, that exchange equalizes temperature, moving slightly warmer air up and slightly cooler air down.

• Eventually this gradual exchange must lead to an isothermal condition.

I encourage people to read the rest of his comment.

Now, I see where I went wrong. Following the logic of my question to Dr. Brown, I incorrectly thought the final equilibrium arrangement would be where the average energy per molecule was evenly spread out from top to bottom, with the molecules having the same average total energy everywhere. This leads to warmer temperature at the bottom and colder temperature at elevation. Instead, at thermal equilibrium, the average energy per volume is the same from top to bottom, with every cubic metre having the same total energy. To do that, the gas needs to be isothermal, with the same temperature in every part.

Yesterday, I read the Jelbring hypothesis again. As I was reading it, I wondered by what logic Jelbring had come to the conclusion that the atmosphere would not be isothermal. I noticed the following sentence in Section 2.2 C (emphasis mine):

The energy content in the model atmosphere is fixed and constant since no energy can enter or leave the closed space. Nature will redistribute the contained atmospheric energy (using both convective and radiative processes) until each molecule, in an average sense, will have the same total energy. In this situation the atmosphere has reached energetic equilibrium. 

He goes on to describe the atmosphere in that situation as taking up the dry adiabatic lapse rate temperature profile, warm on the bottom, cold on top. I had to laugh. Jelbring made the exact same dang mistake I made. He thinks total energy evenly distributed per molecule is the final state of energetic equilibrium, whereas the equilibrium state is when the energy is evenly distributed per volume and not per molecule. This is the isothermal state. In Jelbrings thought experiment, contrary to what he claims, the entire atmosphere of the planet would end up at the same temperature.

In any case, there’s another way to show that the Jelbring hypothesis violates conservation of energy. Again it is a proof by contradiction, and it is the same argument that I presented to Jelbring years ago. At that time, I couldn’t say why his “gravito-thermal” hypothesis didn’t work … but I knew that it couldn’t work. Now, I can see why, for the reasons adduced above. In addition, in his thread Dr. Brown independently used the same argument in his discussion of the Jelbring hypothesis. The proof by contradiction goes like this:

Suppose Jelbring is right, and the temperature in the atmosphere inside the shell is warmer at the bottom and cooler at the top. Then the people living in the stygian darkness inside that impervious shell could use that temperature difference to drive a heat engine. Power from the heat engine could light up the dark, and provide electricity  for cities and farms. The good news for perpetual motion fans is that as fast as the operation of the heat engine would warm the upper atmosphere and cool the lower atmosphere, gravity would re-arrange the molecules once again so the prior temperature profile would be restored, warm on the bottom and cold on the top, and the machine would produce light for the good citizens of Stygia   … forever.

As this is a clear violation of conservation of energy, the proof by contradiction that the Jelbring hypothesis violates the conservation of energy is complete.

Let me close by giving my elevator speech about the Jelbring hypothesis. Hans vigorously argues that no such speech is possible, saying

There certainly are no “Elevator version” of my paper which is based on first principal physics. It means that what I have written is either true or false. There is nothing inbetween.

Another “gravito-thermal” theorist, Ned Nikolov, says the same thing:

About the ‘elevator speech’ – that was given in our first paper! However, you apparently did not get it. So, it will take far more explanation to convey the basic idea, which we will try to do in Part 2 of our reply.

I don’t have an elevator speech for the Nikolov & Zeller theory (here, rebuttal here) yet, because I can’t understand it. My elevator speech for the Jelbring hypothesis, however, goes like this:

• If left undisturbed in a gravity field, a tall container of air will stratify vertically, with the coolest air at the top and the warmest air at the bottom.

• This also is happening with the Earth’s atmosphere.

• Since the top of the atmosphere cannot be below a certain temperature, and the lower atmosphere must be a certain amount warmer than the upper, this warms the lower atmosphere and thus the planetary surface to a much higher temperature than it would be in the absence of the atmosphere.

• This is the cause of what we erroneously refer to as the “greenhouse effect”

Now, was that so hard? It may not be the best, I’m happy to have someone improve on it, but it covers all the main points. The claim that “gravito-thermal” theories are too complex for a simple “elevator speech” explanation doesn’t hold water.

But you can see why such an elevator speech is like garlic to a vampire, it is anathema to the “gravito-thermal” theorists—it makes spotting their mistakes far too easy.

w.

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KevinK
January 19, 2012 8:56 pm

Richard, yes I also get silence from Willis regarding any of my comments. I think that this is his loss…
I still think that if the “greenhouse effect” had any merit a whole bunch of engineers would have JUMPED on it a long time ago. BTW I am an engineer and I always JUMP on any “effect” that helps me solve a problem.
Cheers, Kevin.

January 19, 2012 8:57 pm

Willis,
I was in the same boat as you, thinking that the equilibrium temperature profile of an insulated column of air would be warmer at the bottom than the top. Like you, I changed my mind.
I discusses the topic with a few bright physicists. We bandied back and forth several ideas. There are a few convincing (but wrong) arguments that a lapse rate is the expected result. Eventually we concluded that the equilibrium profile must indeed to isothermal, because the arguments for that were more convincing (and right).
The simplest and most convincing argument ended up being your same perpetual motion approach. You could run an insulated copper bar from bottom to top. This bar does not have the lapse rate effect. (Or use another gas that would have a different lapse rate because it has a different heat capacity). The copper should have the same temperature at top and bottom. If the gas had a different temperature, would could use this temperature difference to continually run the sort of heat engine you suggested.
And that is how theoretical science is supposed to work. You come up with a couple different ideas about the some new situation. You apply fundamental, laboratory-tested principles and discuss it with others. When several different people who understand the science agree, then you have your conclusion.
PS A “back of the envelope” calculation suggests the “time constant” for this process would be weeks. Reaching something close to uniform temperature could takes months. But in the real world, there would be other processes to remix the air long before that.
PPS. This whole gedanken experiment was, of course, predicated on perfect insulation and a constant temperature at the bottom. The same “back of the envelope” calculation suggests that heat flows involved in conduction are less and 1 mW/m^2. Even a tiny amount of GHG at the top of the atmosphere would radiate a 1,000 times more energy, meaning that conduction would never actually achieve a uniform profile.

gbaikie
January 19, 2012 9:09 pm

“• If left undisturbed in a gravity field, a tall container of air will stratify vertically, with the coolest air at the top and the warmest air at the bottom.
• This also is happening with the Earth’s atmosphere.
• Since the top of the atmosphere cannot be below a certain temperature, and the lower atmosphere must be a certain amount warmer than the upper, this warms the lower atmosphere and thus the planetary surface to a much higher temperature than it would be in the absence of the atmosphere.”
Strange as seems I would say it’s it’s true. We are assuming the gas that we talking about can’t freeze or liquify.
Nitrogen in near vacuum pressure can be close to absolute zero. And Helium:
“All known liquids, except liquid helium, freeze when the temperature is lowered enough. Liquid helium remains liquid at atmospheric pressure even at absolute zero, and can be solidified only under pressure.”
Liquid helium: Boiling point at 1 atm: 4.2 K 3.2 K
http://en.wikipedia.org/wiki/Liquid_helium
So certainly true if you are talking about a helium atmosphere.
Of course to have gravity you need mass- something which is giving 1/10th of gee will have internal heat.
Question is would work with artificial gravity.
I think there some thought experiment which says under certain you can’t tell the differences between acceleration and gravity, perhaps this would be a way to tell the difference, and maybe not.
• This is the cause of what we erroneously refer to as the “greenhouse effect””
Hmm, don’t think this explains everything in regards to the “greenhouse effect”.
If include the sun’s energy, the heat capacity of atmosphere, water vapor, clouds, ocean temperature, and land temperature, then yeah, most of the greenhouse effect.
And I don’t think it explain stratosphere and higher.

mondo
January 19, 2012 9:12 pm

A question about the diameter of the column of air extending upwards 1km. If the column were small diameter (say 5m across at ground level – expanding as it rises) would we not get different conditions/events than if it were, say, 1 km diameter? At some point, won’t we see convective effects happening? With hot air rising as it would in a hot air balloon? As Willis has so convincingly explained with his thunderstorm arguments (or did I miss something somewhere?).
And, further demonstrating my lack of knowledge, if warmer air rises due to convective effects, how come we notice that air temperatures are (generally) warmer at lower altitudes? Is that to do with the relatively greater air density at surface than at altitude.
Clearly I must do more reading to keep up.

January 19, 2012 9:12 pm

the universe is a perpetual motion system, expanding and contracting simultaneously in patterned ways, ad infinitum.
the universe is matter and space. temperature is associated with matter. it seems that a critical amount of matter determins black hole versus supernova outcomes for astronomical bodies.
what is the trigger for a big bang ? an accumulation of matter.
given that time is a measure, we could describe the life cycle of big bang as how many years ?
my point is that entropy is the normal condition.
more specific phenomena are contextual. our entropy is affected by local conditions, but in the end physical constructions return to matter and space.
my miniscule understanding of the topic under question favours the idea of gravity increasing temperature. where are the hottest places in our environments ? the centres of our astronomical bodies ?
ergo gravity wins up to the point of bigbang initiation, which may well be another gravitational effect.
of course I’m brain-sailing, surmising, and thinking aloud.

January 19, 2012 9:20 pm

I have a follow-up thought experiment to my previous comment.
If flipping the air column upside down doesn’t require an input of work and returns the column to the dry adiabatic lapse rate, then the dry adiabatic lapse rate must be the column’s thermal equilibrium because a system cannot be shifted from thermal equilibrium without an input of work.
If the adiabatic lapse rate is the thermal equilibrium then it should be impossible to devise a heat engine driven by a column of air whose temperature varies with the adiabatic lapse rate. If the isothermal condition is the thermal equilibrium then the same should apply, because a system in thermal equilibrium can’t drive a heat engine.
If I take a tall column of isothermal air in a gravitational field and exchange a pair of parcels from top to bottom, the descending parsel warms up and the ascending parcel cools down, with no change in energy and no net work. Yet in their new positions both these parcels have a large delta T relative to the surrounding air, and that delta T can drive a heat engine such as a Stirling cycle.
If I try moving parcels within a column whose temperature follows the adiabatic lapse rate, each parcel always stays at the same temperature as the surrounding air, so I cannot drive a heat engine. From that I conclude that an isothermal column of air in a gravitational field is not in thermal equilibrium, and a column of air at the adiabatic lapse rate is.
So if the column of air is isothermal, I can drive lots of little heat engines until it reaches the adiabatic lapse rate, after which I can extract no more energy from the system.
On caveat is that if the system is at the adiabatic lapse rate then the bottom air is warmer, and thus less dense, raising the center of mass of the entire column in slightly increasing its potential energy, so perhaps flipping the column does involve an input of work. Perhaps a more detailed analysis would take this into account and provide a slightly shifted equilibrium point.

gbaikie
January 19, 2012 9:33 pm

“Temperature at both top and bottom would be the same despite the higher energy content per unit volume at the bottom.”
The “higher energy content” seems to mean it’s hotter.
It seems the gas molecules would all have same average velocity- with exception that faster molecules would tend to be higher and slow molecules would be lower. This tendency- depends upon the amount of gravity- 10 gees would more of tendency than 1 gee. But this means more fast molecules could found and average speed isn’t different, the gravity sort them more. If follow a molecule it tends to stay lower, and spend less time higher.
Or the gas molecules are always varying velocities, the velocity is random, but is averaged by the zillion of molecules. If heads is faster, molecules with 10 heads in a row are tend to be higher, those with 10 tails in row tend to be lower.
In gravity field the average molecule speed will lower in the higher density.
Put 1 cubic meter of 1 atm gas, into another 1 cubic meter of 1 atm gas- doubles pressure to 2 atm, and is hotter, when cools to “room temperature” the 2 atm gas will have more density and less velocity.
“Energy content” to me suggests density and/or higher velocity of gas molecules- *either one or both” are higher temperature.

January 19, 2012 9:33 pm

Willis says:

You have not allowed for the fact that the atmosphere in the cylinder is mostly at the bottom. As a result, you have to move much more air up than down when you flip it. So it does involve a large input of work, despite the fact that its height did not change.

But I get all that work back when it passes the tipping point and the air rushes back to the bottom, just like flipping over a half-full bottle. The kinetic and potential energy in the final state is the same as in the initial state (except, in the case of a gas, for that thermally induced change in the center of mass I mentioned above), so there is no net input of work. You could drive the bottle flip with a spring and make a cute perpetual motion machine whose only flaw would be internal friction.

TimC
January 19, 2012 9:37 pm

David says “To resolve this requires the question to be formulated as simply as possible. So to understand how gravity affects temperature distribution we [should] ignore – for the time being – anything extraneous. No sun, no rotation of the Earth, no surface or sub-surface effects. Simply a column of gas in a gravity field. Nothing more.”
But this then considers only the local effect of gravity on the planet itself – not the effect of the gravitational fields of other bodies. The second law (and gravity) applies universally – you must take into account that no known planet simply wanders about the universe as an orphan; all known planets (and moons) are under the control of some greater external gravitational force (unless perhaps caught in a supernova explosion – but that would be a special case!). This implies rotation (Keplerian orbits, axial rotation by conservation of momentum or gravitational/ tidal coupling), therefore nights and days, atmospheric mixing, heating, and radiation by the atmosphere itself.
Part of the problem with Jelbring is the assumptions applying to the model planet. Interestingly the same applied to Willis’s orphan planet with the non-GHG atmosphere (in his original Some Gravity “trap” thread) – perhaps in the hypothetical world we will find some form of paradox applying until it is accepted that all known planets rotate.

bones
January 19, 2012 9:49 pm

The actual atmosphere temperature distribution cannot be modeled in terms of random molecular motions alone. The atmosphere is heated at the base by the absorption of UV and visible light. It warms to the point of hydrodynamic instability in the day and there is bulk flow energy transport from the warm base to higher elevations. Even without water vapor, CO2, methane or other greenhouse gases, ozone would absorb some of the outgoing IR. Without attributing either validity or falsity to any of the theories of atmosphere heat transport in discussion here, this is a complicated problem that is not going to be settled by simple arguments. Do the diurnal fluid mechanics problem along with atmospheric circulation and pole-equator insolation differences and then try to explain it in simple terms if you can.

dp
January 19, 2012 9:58 pm

Willis – at some point I got lost and it was at the molecular replacement part. A highly energized molecule takes up more space than a lesser energized molecule. For there to be a one-to-one replacement of a displaced (convected) molecule, the molecule replacing it has to consume the same volume. Meaning it has to be at the same energy level. What compels molecules at the same energy level to swap chairs? Describe what happens to a lesser energized molecule when it drops into the hole left by a more energized molecule. And I know you know.
Then we will need to talk about gradients where all gradient elements are very close to every other gradient element. This gets to a very earthly feature known as long runout earth slides such as that which buried Pompeii. But first things first. Please give me the elevator speech description of why molecules of identical energy levels would swap chairs. I will snip your posts if you go off topic.

johnpb
January 19, 2012 10:01 pm

Willis, It is hard to argue with your thought experiment due to your requirement of equalibrium which excludes convection. Once convection is allowed then adiabatic temperature differences will result.

James of the West
January 19, 2012 10:10 pm

Temperature vs Energy of a gas.
What is the temperature of a gas? It is proportional to the *average* kinetic energy of the gas molelules whose temperature you are trying to measure but then we must always define which molecules are and are not included for the temperature measurement. We can do this by defining a region in space – a volume with x,y and z dimensions. The gas molecules in our region of interest don’t all have to have the same kinetic energy – as long as the average kinetic energy of the molecules in a given region of gas is the same it has the same temperature.
The total Energy (kinetic plus potential energy) can be very different in a cubic meter of gas at sea level to the same volume of a gas at the same temperature at altitude. The density (and mass) of gas in a given unit of volume also changes with altitude. It is simplistic to think of one molecule of gas as it turns potential energy into kinetic as it falls, when you consider a given volume of gas as it falls the number of gas molecules per unit volume increases this means that the potential energy of 1 unit of volume of a gas does not decrease simply as a function of altitude but also of density (mass per unit voume).
At altitude the number of gas molecules per unit volume is less than at the planets surface so that means the total kinetic energy (sum of the kinetic energy for each gas molecule) is declining with altitude even if the gases have the same temperature (average kinetic energy of the molecules). Again the Potential energy of the unit of volume of gas at altitude is higher per molecule but there are less molecules per unit volume so the sum total of the potential energy for a unit of volume of the atmosphere is also a function not only of gravity but also of the number of molecules in a unit of volume.
My hat goes off to those who delve into this further! Good luck to all of the smart people thinking about these matters.

jorgekafkazar
January 19, 2012 10:14 pm

Willis-san: Here’s your logic, above, with the symbolic logic thereof:
“If an energetically isolated system is in its lowest energy state, it cannot perform work”
If EIS = LES THEN -W
“If the isolated atmosphere in Jelbring’s thought experiment is warm at the bottom and cold at the top, I can stick a thermocouple into it and use the temperature differential to generate electricity to perform work.”
If EIS = HBCT THEN W
“Therefore, the isothermal state…is the lower of the two energy states, since I cannot use it to do work.”
-W THEREFORE EIS = LES
Do you see what you’ve done, Willis?
If Roger is a goose, I can’t ride him like a bicycle.
If Roger is a Schwinn, I can ride him like a bicycle.
I can’t ride Roger like a bicycle, therefore he is a goose.

January 19, 2012 10:18 pm

We seem to be in the same boat Willis.
* We both thought that the lapse rate might be the equilibrium condition in this thought experiment.
* We both discussed it with other smart, informed people and decided the equilibrium condition is isothermal.
* We both realized a perpetual motion machine was the simplest argument against the permanent lapse rate situation.
That is how science should be done. I hate to admit I was wrong about physics, but there is no other conclusion possible here about the answer to this question. In our defense, there are arguments that sound very convincing that the temperature should drop as it go up. You REALLY have to know thermodynamics to avoid getting sucked in by those alluring arguments.
PS. The thought experiment is a very specific situation, not likely to be seen in the real world. Thermal conduction through the atmosphere is less than 1 mW/m^2 if the lapse rate is the maximum stable amount of 10 K/km. This number is SO much smaller that other energies involved (convection, incoming solar, GHG radiation, evaporation) that such an isothermal condition would never be realized in real life.

January 19, 2012 10:20 pm

For those of you that believe empiricism trumps thought experiment, consider the following, attributed to Galileo, though it was also recorded ~1,000 years before Galileo by John Philoponus and also Oresme (IIRC) more than a century before.
Galileo asked us to consider what would happen if two iron balls were tied together as one by an iron rod. The smaller and lighter ball, according to Aristotelian physics, would slow down the ascent of the larger, heavier ball. Yet the combined weight, being greater than either ball alone, meant that they would fall faster when tied together, as well as slower. Since a contradiction was (and remains) not allowed, the answer to the problem was that objects necessarily fall at the same rate, regardless of their weight. Galileo had successfully demonstrated that Aristotle had been wrong about falling weights.
While Galileo is widely (and incorrectly) believed to have performed the experiment of dropping two cannonballs of differing weight from the tower at Pisa, this cannot be the case. In his record of the experiment, Galileo refers to the height from which a wooden and iron cannonball were dropped: 300 feet. This would make his assistant the tallest man in the world — ever!
In the event, Galileo recorded that the wooden cannonball initially fell faster than the iron cannonball, and that the iron cannonball overtook the wooden cannonball, beating it to the ground by a measurable margin.
Think about what we are doing when we attempt to reconcile the empirical result withe the deductive result.