Perpetuum Mobile

Guest Post by Willis Eschenbach

Since at least the days of Da Vinci, people have been fascinated by perpetual motion machines. One such “perpetuum mobile” designed around the time of the civil war is shown below. It wasn’t until the development of the science of thermodynamics that it could be proven that all such mechanisms are impossible. For such machines to work, they’d have to create energy, and energy cannot be either created or destroyed, only transformed.

Image Source

I bring this up for a curious reason. I was reading the Jelbring hypothesis this afternoon, which claims that greenhouse gases (GHGs) are not the cause of the warming of the earth above the theoretical temperature it would have without an atmosphere. Jelbring’s hypothesis is one of several “gravito-thermal” theories which say the heating of the planet comes from gravity rather than (or in some theories in addition to) the greenhouse effect. His thought experiment is a planet with an atmosphere. The planet is isolated from the universe by an impervious thermally insulating shell that completely surrounds it, and which prevents any energy exchange with the universe outside. Inside the shell, Jelbring says that gravity makes the upper atmosphere colder and the lower atmosphere warmer. Back around 2004, I had a long discussion on the “climateskeptics” mailing list with Hans Jelbring. I said then that his theory was nothing but a perpetual motion machine, but at the time I didn’t understand why his theory was wrong. Now I do.

Dr. Robert Brown has an fascinating post on WUWT called “Earth’s baseline black-body model – a damn hard problem“. On that thread, I had said that I thought that if there was air in a tall container in a gravity field, the temperature of the air would be highest at the bottom, and lowest at the top. I said that I thought it would follow the “dry adiabatic lapse rate”, the rate at which the temperature of dry air drops with altitude in the earth’s atmosphere.

Dr. Brown said no. He said that at equilibrium, a tall container of air in a gravity field would be the same temperature everywhere—in other words, isothermal.

I couldn’t understand why. I asked Dr. Brown the following question:

Thanks, Robert, With great trepidation, I must disagree with you.

Consider a gas in a kilometre-tall sealed container. You say it will have no lapse rate, so suppose (per your assumption) that it starts out at an even temperature top to bottom.

Now, consider a collision between two of the gas molecules that knocks one molecule straight upwards, and the other straight downwards. The molecule going downwards will accelerate due to gravity, while the one going upwards will slow due to gravity. So the upper one will have less kinetic energy, and the lower one will have more kinetic energy.

After a million such collisions, are you really claiming that the average kinetic energy of the molecules at the top and the bottom of the tall container are going to be the same?

I say no. I say after a million collisions the molecules will sort themselves so that the TOTAL energy at the top and bottom of the container will be the same. In other words, it is the action of gravity on the molecules themselves that creates the lapse rate.

Dr. Brown gave an answer that I couldn’t wrap my head around, and he recommended that I study the excellent paper of Caballero for further insight. Caballero discusses the question in Section 2.17. Thanks to Dr. Browns answer plus Caballero, I finally got the answer to my question. I wrote to Dr. Brown on his thread as follows:

Dr. Brown, thank you so much. After following your suggestion and after much beating of my head against Caballero, I finally got it.

At equilibrium, as you stated, the temperature is indeed uniform. I was totally wrong to state it followed the dry adiabatic lapse rate.

I had asked the following question:

Now, consider a collision between two of the gas molecules that knocks one molecule straight upwards, and the other straight downwards. The molecule going downwards will accelerate due to gravity, while the one going upwards will slow due to gravity. So the upper one will have less kinetic energy, and the lower one will have more kinetic energy.

After a million such collisions, are you really claiming that the average kinetic energy of the molecules at the top and the bottom of the tall container are going to be the same?

What I failed to consider is that there are fewer molecules at altitude because the pressure is lower. When the temperature is uniform from top to bottom, the individual molecules at the top have more total energy (KE + PE) than those at the bottom. I said that led to an uneven distribution in the total energy.

But by exactly the same measure, there are fewer molecules at the top than at the bottom. As a result, the isothermal situation does in fact have the energy evenly distributed. More total energy per molecules times fewer molecules at the top exactly equals less energy per molecule times more molecules at the bottom. Very neat.

Finally, before I posted my reply, Dr. Brown had answered a second time and I hadn’t seen it. His answer follows a very different (and interesting) logical argument to arrive at the same answer. He said in part:

Imagine a plane surface in the gas. In a thin slice of the gas right above the surface, the molecules have some temperature. Right below it, they have some other temperature. Let’s imagine the gas to be monoatomic (no loss of generality) and ideal (ditto). In each layer, the gravitational potential energy is constant. Bear in mind that only changes in potential energy are associated with changes in kinetic energy (work energy theorem), and that temperature only describes the average internal kinetic energy in the gas.

Here’s the tricky part. In equilibrium, the density of the upper and lower layers, while not equal, cannot vary. Right? Which means that however many molecules move from the lower slice to the upper slice, exactly the same number of molecules must move from the upper slice to the lower slice. They have to have exactly the same velocity distribution moving in either direction. If the molecules below had a higher temperature, they’d have a different MB [Maxwell-Boltzmann] distribution, with more molecules moving faster. Some of those faster moving molecules would have the right trajectory to rise to the interface (slowing, sure) and carry energy from the lower slice to the upper. The upper slice (lower temperature) has fewer molecules moving faster — the entire MB distribution is shifted to the left a bit. There are therefore fewer molecules that move the other way at the speeds that the molecules from the lower slice deliver (allowing for gravity). This increases the number of fast moving molecules in the upper slice and decreases it in the lower slice until the MB distributions are the same in the two slices and one accomplishes detailed balance across the interface. On average, just as many molecules move up, with exactly the same velocity/kinetic energy profile, as move down, with zero energy transport, zero mass transport, and zero alteration of the MB profiles above and below, only when the two slices have the same temperature. Otherwise heat will flow from the hotter (right-shifted MB distribution) to the colder (left-shifted MB distribution) slice until the temperatures are equal.

It’s an interesting argument. Here’s my elevator speech version.

• Suppose we have an isolated container of air which is warmer at the bottom and cooler at the top. Any random movement of air from above to below a horizontal slice through the container must be matched by an equal amount going the other way.

• On average, that exchange equalizes temperature, moving slightly warmer air up and slightly cooler air down.

• Eventually this gradual exchange must lead to an isothermal condition.

I encourage people to read the rest of his comment.

Now, I see where I went wrong. Following the logic of my question to Dr. Brown, I incorrectly thought the final equilibrium arrangement would be where the average energy per molecule was evenly spread out from top to bottom, with the molecules having the same average total energy everywhere. This leads to warmer temperature at the bottom and colder temperature at elevation. Instead, at thermal equilibrium, the average energy per volume is the same from top to bottom, with every cubic metre having the same total energy. To do that, the gas needs to be isothermal, with the same temperature in every part.

Yesterday, I read the Jelbring hypothesis again. As I was reading it, I wondered by what logic Jelbring had come to the conclusion that the atmosphere would not be isothermal. I noticed the following sentence in Section 2.2 C (emphasis mine):

The energy content in the model atmosphere is fixed and constant since no energy can enter or leave the closed space. Nature will redistribute the contained atmospheric energy (using both convective and radiative processes) until each molecule, in an average sense, will have the same total energy. In this situation the atmosphere has reached energetic equilibrium. 

He goes on to describe the atmosphere in that situation as taking up the dry adiabatic lapse rate temperature profile, warm on the bottom, cold on top. I had to laugh. Jelbring made the exact same dang mistake I made. He thinks total energy evenly distributed per molecule is the final state of energetic equilibrium, whereas the equilibrium state is when the energy is evenly distributed per volume and not per molecule. This is the isothermal state. In Jelbrings thought experiment, contrary to what he claims, the entire atmosphere of the planet would end up at the same temperature.

In any case, there’s another way to show that the Jelbring hypothesis violates conservation of energy. Again it is a proof by contradiction, and it is the same argument that I presented to Jelbring years ago. At that time, I couldn’t say why his “gravito-thermal” hypothesis didn’t work … but I knew that it couldn’t work. Now, I can see why, for the reasons adduced above. In addition, in his thread Dr. Brown independently used the same argument in his discussion of the Jelbring hypothesis. The proof by contradiction goes like this:

Suppose Jelbring is right, and the temperature in the atmosphere inside the shell is warmer at the bottom and cooler at the top. Then the people living in the stygian darkness inside that impervious shell could use that temperature difference to drive a heat engine. Power from the heat engine could light up the dark, and provide electricity  for cities and farms. The good news for perpetual motion fans is that as fast as the operation of the heat engine would warm the upper atmosphere and cool the lower atmosphere, gravity would re-arrange the molecules once again so the prior temperature profile would be restored, warm on the bottom and cold on the top, and the machine would produce light for the good citizens of Stygia   … forever.

As this is a clear violation of conservation of energy, the proof by contradiction that the Jelbring hypothesis violates the conservation of energy is complete.

Let me close by giving my elevator speech about the Jelbring hypothesis. Hans vigorously argues that no such speech is possible, saying

There certainly are no “Elevator version” of my paper which is based on first principal physics. It means that what I have written is either true or false. There is nothing inbetween.

Another “gravito-thermal” theorist, Ned Nikolov, says the same thing:

About the ‘elevator speech’ – that was given in our first paper! However, you apparently did not get it. So, it will take far more explanation to convey the basic idea, which we will try to do in Part 2 of our reply.

I don’t have an elevator speech for the Nikolov & Zeller theory (here, rebuttal here) yet, because I can’t understand it. My elevator speech for the Jelbring hypothesis, however, goes like this:

• If left undisturbed in a gravity field, a tall container of air will stratify vertically, with the coolest air at the top and the warmest air at the bottom.

• This also is happening with the Earth’s atmosphere.

• Since the top of the atmosphere cannot be below a certain temperature, and the lower atmosphere must be a certain amount warmer than the upper, this warms the lower atmosphere and thus the planetary surface to a much higher temperature than it would be in the absence of the atmosphere.

• This is the cause of what we erroneously refer to as the “greenhouse effect”

Now, was that so hard? It may not be the best, I’m happy to have someone improve on it, but it covers all the main points. The claim that “gravito-thermal” theories are too complex for a simple “elevator speech” explanation doesn’t hold water.

But you can see why such an elevator speech is like garlic to a vampire, it is anathema to the “gravito-thermal” theorists—it makes spotting their mistakes far too easy.

w.

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January 21, 2012 9:22 am

After reading many comments, my elevator speech is:
The troposphere is a giant heat engine with energy input from the sun heating the lower part and the upper part being the condenser dumping energy to outer space.
Energy emission from the the top of the troposphere is a thermodynamic requirement for the engine to run.
Gravity is necessary for the function of the engine but does not in itself cause the thermal gradient.
Greenhouse gases must be present in the upper troposphere as this is the only significant mechanism available for energy to be removed from the upper troposphere.
The lapse rate is a thermodynamic manifestation of the heat engine at work.
In conclusion, I side with Willis and Dr. Brown on this thread.

DeWitt Payne
January 21, 2012 9:22 am

Bart says:
January 20, 2012 at 11:00 pm

I was speaking of a temperature limit.

OK. The upper temperature limit is the surface temperature. Assuming an emissivity of 1 as specified, the surface temperature will be 255K. The surface temperature cannot increase without limit without violating the Second Law.

I am saying that, on this hypothetical planet, the surface is a blackbody, but its emissions are suppressed while massive amounts of heat are being drawn out of it to feed an ever hungrier atmosphere.

You’ve got to be kidding. That makes no sense at all. How is emission being suppressed? If the surface has a temperature above absolute zero and the emissivity is 1, it will emit radiation. Period. Molecular collisions with the surface cannot suppress emission, they can only raise or lower the temperature. You can’t keep pumping heat into the atmosphere and maintain a negative temperature gradient if there’s no heat sink at the top of the atmosphere. You can assert that this could happen all you want, but your assertions are unphysical, and quite frankly, absurd.

January 21, 2012 9:23 am

tallbloke:
I wouldn’t read anything nefarious into Brown & Eschenbach’s failure to engage on the issue of what proves that equilibrium implies isothermality. To them, one who questions the proposition that it does no doubt appears to be just as much a crank as someone who questions conservation of energy would appear to you or me. And have I proved conservation of energy or had it proved to me? I don’t think so. It’s just that I know all the technology around us was designed by people who counted on that law, and they seem never to have met a counterexample. Brown & Eschenbach no doubt accept the equilibrium -> isothermal thing for the same reason. And would you or I waste much time on someone who professes to believe that conservation of energy does not apply in a particular situation? I probably wouldn’t.
To them it no doubt seems pointless to take the time to look deeply into a “law” they think is supported by the experience of hundreds of thousands of engineers over centuries. And why should they listen to an uncredentialed layman like me about how likely it is that a serious paper actually does say that the “law” is not exactly what they think it is?
Still, it is frustrating.

Bryan
January 21, 2012 9:24 am

Robert
I forgot to link the paper in my last post
http://www-as.harvard.edu/education/brasseur_jacob/ch2_brasseurjacob_Jan11.pdf

tallbloke
January 21, 2012 9:25 am

A physicist says:
January 21, 2012 at 8:12 am
tallbloke says: Willis, the rules for falsifying a proposition by appeal to the constructability of a perpetual motion machine of the second kind are very clear. You have to specify the machine and demonstrate that it will produce work.
Armwaving is insufficient. I made this point a lot earlier in this thread and you ignored it.
Tallbloke, your statement is wrong-on-the-facts: Willis (and I) did describe a perpetual motion of the second kind, namely a thermopile column, said column having its warm end at ground-level and its cold end at altitude.

In comparison the the machine described in email to me by Peter Berenyi, this is an incomplete and inadequate description. Try harder.
And the mistake in “gravito-thermal” theories is evident too: these theories include a thermodynamic potential (namely the temperature) together with a gravitational potential, and yet they (wrongly) neglecting the chemical potential.
Yes, I read your reply to anther comment about this. However, the argument fails because the chemical potential is at equilibrium in the Jelbring thought experiment. The Gibbs free energy is zero.

tallbloke
January 21, 2012 9:31 am

gnomish says:
January 21, 2012 at 9:13 am
“If there is a temperature gradient between two parts of a system, net heat flows from the warmer part to the cooler part. If there is net heat flow within the system, it is not in equilibrium.”
this is a definition.

It is a definition. One that is severely lacking in universality. It fails as a general law as soon as it is placed orthogonally to a gravitational field.

January 21, 2012 9:34 am

We know that gravity exists but not one acedemic has managed to explain with any confidence why our boots are attracted to the Earth’s core.
Your point being? Or if you prefer, exactly what would you consider an answer?
Science consists of observing the world, noting regularities, proposing hypotheses to explain those regularities, and fitting all of the competing sets of hypotheses into a coherent, mostly consistent whole. The whole set of your beliefs about the world is called your worldview. Nothing in your worldview except the empirical ongoing experience of your own existence is certain (see e.g. the movie The Matrix, or Plato’s parable of The Cave for ways — however implausible or plausible you might think them — that we could be mistaken even about the external reality we infer on the basis of our sense data including our memory).
In that context, knowing why is impossible. The best we can do is have a set of well-founded beliefs, the beliefs that are in some sense the best things to believe, given the data and our experience.
Gravity is very much in that category. We know that all the mass we can see appears to move as if Newton’s Law of Gravitation is correct, subject to minor tweaks associated with relativity (which we believe for a variety of equally good reasons). There are a very few astronomical observations where we cannot verify gravity — but where the assumption of Newton’s Law requires an “odd” distribution of mass we cannot see, so called “dark matter”. We do not yet know enough to be certain what the explanation of the deviation is. We also do not yet have a completely consistent theory of everything yet, and the transition between quantum theory and general relativity is not yet well-understood.
So what? Gravity could be caused by invisible fairies and it would still be the case that the invisible fairies make masses accelerate pretty much as if Newton’s Law of Gravitation is true. Or are you just trying to assert something childish, like “you physics guys don’t know everything, look, you don’t even know why gravity exists, so that means when you say thermal equilibrium is isothermal you could be wrong, you just don’t know”?
The number of logical fallacies in such an assertion is left as an exercise for the reader. Of course, you didn’t make that assertion, so I don’t really know what your point is. If you have one, please express it clearly.
rgb

January 21, 2012 9:35 am

The kinetic energy of mass is the mechanism that enhances its employment of energy.
Which means, would that be, nothing at all?
It would.
rgb

tallbloke
January 21, 2012 9:45 am

Joe Born says:
January 21, 2012 at 9:23 am
tallbloke:
I wouldn’t read anything nefarious into Brown & Eschenbach’s failure to engage on the issue of what proves that equilibrium implies isothermality. To them, one who questions the proposition that it does no doubt appears to be just as much a crank as someone who questions conservation of energy would appear to you or me. And have I proved conservation of energy or had it proved to me? I don’t think so. It’s just that I know all the technology around us was designed by people who counted on that law, and they seem never to have met a counterexample. Brown & Eschenbach no doubt accept the equilibrium -> isothermal thing for the same reason. And would you or I waste much time on someone who professes to believe that conservation of energy does not apply in a particular situation? I probably wouldn’t.
To them it no doubt seems pointless to take the time to look deeply into a “law” they think is supported by the experience of hundreds of thousands of engineers over centuries. And why should they listen to an uncredentialed layman like me about how likely it is that a serious paper actually does say that the “law” is not exactly what they think it is?
Still, it is frustrating.

Joe, I think you have got to the heart of the matter.
I doubt that the physicists ever got the engineers to build anything tall enough or sufficiently sensitive or well insulated enough for them to spot the gradient and wonder what caused it.
It’s easy enough to derive from formulations of the thermodynamics laws which concentrate on energy rather than heat. I guess we’ll have to let the old school labour under their two dimensional delusions and just get on with testing predictions of planetary surface temperatures against empirical measurements. It seems Nikolov and Zeller are streets ahead using the gravito-thermal theory on that front already.
I’ll abandon attempts to get Dr Brown and Willis to engage for now and write up the unanswered proofs for the blog.

January 21, 2012 9:46 am

All sounds like my first year university Physics lectures.
Perhaps a few more Physicists need to read and understand and comment.
Where’s Richard Feynman when we really need him?

Dead. I’m doing my best, but it is difficult to teach a full year of intro physics in a blog, and between people who are clueless about work, energy, gravity, Newton’s Laws, fluids, and thermodynamics my hands are full.
What would really help would be more people going back to that first year physics textbook and reading it. Then if they would simply stop making posts that are the equivalent of “introductory physics is all wrong”. It just makes them sound very silly. It’s fine to discuss, debate, and learn, but if one wants the debate to be useful, it really helps if both sides do their homework.
I’ve done my homework, so to speak, from 1973 up to the present. Climate physics per se I’m working on, but physics itself from intro stuff that I teach a full course of twice a year these days through graduate level E&M and quantum and research level condensed matter physics. I make no pretense to being as good as Feynman — he was truly exceptional — but as the author of an online physics textbook and teacher of all this stuff to hundreds of very smart students a year, I’m not terrible — if anyone will listen to me.
rgb

January 21, 2012 9:50 am

Ref Earth’s Heat
Don’t forget that we still quite a bit left from the accretion of the planet.

Nicely locked up inside an insulating crust. The average outward flux of heat has been posted repeatedly. It hasn’t been forgotten, it is just negligible, completely inadequate as an explanation of “warming”. If it weren’t for the sun, oceans and the atmosphere, the Earth would be warm like the moon is warm, which is pretty much “not”. And even the heat that is in there is at least partially due to tidal heating from the moon.
I’m happy to hear a quantitative assertion of a significant contribution from geothermal energy, but it would have to be backed by references and data.
rgb

January 21, 2012 10:01 am

100 kg of gas 100 kms from Earth will e have 98,000,000 less joules of energy than 100 kg of gas at the surface.
Gravitation potential energy actually turns into real thermal energy for a mass that is falling through a gravity field or objects with mass that are closer/farther from the centre of the gravity field.
GPE = Mass * Gravity * Height

100 kg of gas 100 kms from Earth at 100C will have the exact same kinetic energy per molecule, independent of the volume it occupies (as long as it remains at least dense enough to be in thermal equilibrium).
As you drop the container of gas from the upper height to the lower, the temperature inside will remain the same. Sure, the gas gains KE, but not heat — all of the KE is organized and associated with one very non-thermal direction. The kinetic energy per molecule in the gas in container-centered coordinates will make only tiny changes as the fluid density redistributes during the fall.
The gas gets hot when it hits something and abruptly comes to rest. This basically slams all the molecules into the walls of the container, and transfers all that KE they accumulated into random motion, that is, “heat”.
The problem with a static column of gas is that it isn’t falling. Get it? It’s not moving up or down. The density/pressure is constant as a function of height. Gravity isn’t releasing more energy or absorbing more energy. Gravity is doing no net work on the system. Consequently, the molecules can share their kinetic energy around and come to thermal equilibrium without moving up or down and involving gravity.
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Jim D
January 21, 2012 10:18 am

The isothermal atmosphere is not the maximum entropy state. If you start with an isothermal atmosphere and exchange two parcels of air in the vertical direction, the one you bring down becomes warmer than its environment (due to compression at a higher pressure) and the one you bring up becomes cooler. Now mix those exchanged parcels at their new level and keep doing this, and you are making lower levels warmer and upper levels cooler.
In an isentropic atmosphere (meaning constant potential temperature and adiabatic temperature lapse rate), exchanging two parcels in this way results in no temperature change because the lapse rate cancels the compression effect. However much you mix adiabatic-lapse-rate air you won’t alter its temperature profile. This is the well-mixed maximum entropy state.

Scot Allen
January 21, 2012 10:19 am

Robert Brown says:
January 21, 2012 at 10:01 am

The problem with a static column of gas is that it isn’t falling. Get it? It’s not moving up or down.

But IT is made of particles that are moving up and down within the column.
Imagine one molecule at the bottom of the column made energetic by contact with the surface of the Earth hitting another molecule 10^-5cm above it (average distance between particles) and so on through the layers as the atmosphere tries to reach equilibrium. Each time a lower molecule loses some kinetic energy to gravitational potential energy as it travels across the current layer before it strikes a molecule in the next layer above it. At 10km, 4.56×10^-21 J has been converted to gravitational potential energy — a significant amount when compared with the 5.81×10^-21 J at the start. The reverse is true, too. Molecules propelled upward are matched by molecules falling downward and each downward falling molecule gains 4.56×10^-32 J of kinetic energy as it falls through a 10^-5cm layer.
These differences in kinetic energy in each layer must translate into different temperatures in each layer.

DeWitt Payne
January 21, 2012 10:21 am

Hans Jelbring says:
January 21, 2012 at 8:53 am

I am interested how you are going to construct your perpetuum mobile out of ideal gases.

It’s already been described up thread, but I’ll do it again. Take two vertical cylinders 100 m tall. Fill one with helium and the other with xenon at 1 atmosphere. Thermally couple the bottom of each cylinder to the other and insulate the rest of the cylinders. The DALR for helium is 0.001888 K/m and 0.061 K/m for xenon. If gravity causes the DALR to be established in both cylinders, the temperature difference at the top of the cylinders would be 6K. If we then run a heat engine from that temperature difference, the xenon will warm and the helium cool until there is no temperature difference at the top. The cylinders will then be isothermal. We disconnect the heat engine. If gravity then re-establishes the DALR, we can run the heat engine again, and again, and again. When the DALR is re-established, the heat that was moved from the helium to the xenon will move back again. The total energy content of the two cylinders won’t change. Energy conservation is violated. But of course, there won’t actually be a temperature difference between the tops of the two cylinders.

jjthoms
January 21, 2012 10:25 am

Hans Jelbring says: January 21, 2012 at 8:42 am
Since there is nothing more unphysical than 390 W/m^2 backradiation. … I would glacly examine all påredtended measurements if I get information of the instrument and their constructions. This fraud is just passing any limits and is degrading science to superstition.
It is good to know that you and willis are great IPCC supporters.
=======================
Please see my post above:
jjthoms says: January 21, 2012 at 7:49 am
http://www.patarnott.com/atms749/pdf/LongWaveIrradianceMeas.pdf
Atmospheric longwave irradiance uncertainty: Pyrgeometers compared to an absolute sky-scanning radiometer, atmospheric emitted radiance interferometer, and radiative transfer model calculations Rolf Philipona, etal.
Please check out fig 3:
Figure 3. Longwave downward irradiance measured with all
pyrgeometers and the absolute sky-scanning radiometer from
September 22 to 29, 1999, at SGP. Field calibration and Albrecht
et al. formula with C, k2, and K is used for all pyrgeometers.
Nighttime and daytime slots are used for the analysis
of nighttime and daytime measurements.
If I read this correctly there is not much difference in LW IR between day and night.
Around 20 to 50%

Only downward radiation here BUT in this document slide 9 toa and ground are compared.
http://www.patarnott.com/atms749/powerpoint/ch6_GP.ppt
Where the GHG emissions are obvious.
they are reduced in TOA flux and increased in down welling flux.

January 21, 2012 10:25 am

Crispin in Waterloo says:
January 21, 2012 at 1:58 am

If you say that the atmosphere will not re-stratify, that is a contradiction of the Universal Gas Law.

There are 3 ways to move heat – radiation, convection, conduction
In an atmosphere without any IR active substances (such as greenhouse gases), radiation is not a factor. Using only convection, the Universal Gas Law applies and, in a gravitational field, the dry adiabatic lapse rate (DALR) is produced. However, conduction must also be considered. It is conduction (much slower than convection) that produces the isothermal atmosphere.
Basically, the Universal Gas Law assumes that no energy enters or leaves the system. This is referred to as adiabatic. Conduction allows energy to move from one part of the system to another and, therefore, allows the atmosphere to have a lapse rate different than described by the DALR.

gnomish
January 21, 2012 10:30 am

“It is a definition. One that is severely lacking in universality. It fails as a general law as soon as it is placed orthogonally to a gravitational field.”
t.b – the definition of a definition is something for you to understand. definitions don’t possess the characteristic of universality. they limit. the latin ‘fin’ does not mean universal.
if you redefine the context, you are changing the definition.
the laws of thermodynamics do NOT require ‘gravity’. mass is not a property of heat. you may as well speak of age, length and color effects on temperature. it’s not even good nonsense.
density is not heat. god, man – temperature is not heat. i can have gas at any temperature and density i please. there is no state equation of gas laws that infers, implies or has anything to do with gravity or density.
bad physics is a direct consequence of the abuse of language.
dude- take out one of the several torches you own and heat some things. if you heat a spot of anything at all, you have a hot spot. if the whole thing is not hot, therefore you have a gradient because things have a property called ‘thermal conductivity’. every single bit of mass in the universal universe does that. the dynamic gradient is produced it is not static. it has nothing to do with gravity.
if i understand the proposition, gravity is supposed to increase density which increases thermal capacity. this is as much sense as i can extract so far from the gibberish.
in fact, the take home lesson i am getting from this is that people who can’t use language properly can’t think properly and are busily truncating the ‘iens’ offa our species name.

tallbloke
January 21, 2012 10:50 am

DeWitt Payne says:
January 21, 2012 at 10:21 am
Take two vertical cylinders 100 m tall. Fill one with helium and the other with xenon at 1 atmosphere. Thermally couple the bottom of each cylinder to the other and insulate the rest of the cylinders. The DALR for helium is 0.001888 K/m and 0.061 K/m for xenon. If gravity causes the DALR to be established in both cylinders, the temperature difference at the top of the cylinders would be 6K. If we then run a heat engine from that temperature difference, the xenon will warm and the helium cool until there is no temperature difference at the top. The cylinders will then be isothermal. We disconnect the heat engine. If gravity then re-establishes the DALR, we can run the heat engine again, and again, and again.

Thanks DeWitt, this sounds more promising. So for a 1m^2 column we could generate how much power? According to Graeff’s experiments, the gradient was re-established within 36 hours with water diffusing through ground glass particles when he turned the columns end for end. I expect the gas would re-organise itself more quickly.
But wait, the extraction of energy will cool the Helium gas overall. Where is the energy going to come from to warm it up again? Can’t come from outside the machine or it’s not a perpetuum mobile, so it has to be perfectly insulated. Or if you think that all that is required is to have a differential, how is the heat engine going to continue running once the temperature approaches absolute zero? Or if you are going to use the generated energy to warm the gas again, how do we tell it is working at all?

January 21, 2012 10:55 am

Tallbloke, simpler it better!
You didn’t tell us what amazing, complicated machine your friend imagined, but the simple machine that has been described (the thermopile) does exactly break the 2nd law of thermodynamics if a lapse rate is the equilibrium condition.

tallbloke
January 21, 2012 11:07 am

Thinking about DeWitt’s machine some more, I think I’ll think about DeWitt’s machine some more, before I try to evaluate it in a summary, so scrub that second paragraph for now.
Good puzzle! Thanks DeWitt.

tallbloke
January 21, 2012 11:10 am

Tim,
Peter’s machine wasn’t complicated, just better specified than the previous attempts I’d seen on this thread. I missed DeWitt’s earlier post.

Stephen Wilde
January 21, 2012 11:11 am

The atmosphere ALWAYS reconfigures its energy distribution so that the Atmospheric Thermal Effect/Adiabatic Lapse Rate is maintained.
Wilde’s Law.

A physicist
January 21, 2012 11:22 am

A physicist says: The mistake in “gravito-thermal” theories is evident too: these theories include a thermodynamic potential (namely the temperature) together with a gravitational potential, and yet they (wrongly) neglecting the chemical potential.

Tallbloke says: Yes, I read your reply to another comment about this. However, the argument fails because the chemical potential is at equilibrium in the Jelbring thought experiment. The Gibbs free energy is zero.

Tallbloke, this is a case where “handwaving is not enough”, and in fact your assertion is flat-out wrong.
Please consult a kinetic theory textbook that gives the (simple) expression for the chemical potential of an ideal gas in a gravitational potential. Like this one, for example.

January 21, 2012 11:23 am

davidmhoffer says:
January 21, 2012 at 8:41 am
“BenAW, the one quibble I have with your comment is that N&Z missed this. My reading of N&Z is that it is founded upon this (amongst several other things)”.
I’m trying to engage in a discussion, but they seem to busy at the moment.
See eg.
http://tallbloke.wordpress.com/2012/01/01/hans-jelbring-the-greenhouse-effect-as-a-function-of-atmospheric-mass/#comment-13485
or
http://tallbloke.wordpress.com/2012/01/17/nikolov-and-zeller-reply-to-comments-on-the-utc-part-1/#comment-14747
or
http://tallbloke.wordpress.com/2012/01/17/nikolov-and-zeller-reply-to-comments-on-the-utc-part-1/#comment-14848
Would be interested in at least some reaction.
Ben Wouters

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