Guest Post by Willis Eschenbach
Since at least the days of Da Vinci, people have been fascinated by perpetual motion machines. One such “perpetuum mobile” designed around the time of the civil war is shown below. It wasn’t until the development of the science of thermodynamics that it could be proven that all such mechanisms are impossible. For such machines to work, they’d have to create energy, and energy cannot be either created or destroyed, only transformed.
I bring this up for a curious reason. I was reading the Jelbring hypothesis this afternoon, which claims that greenhouse gases (GHGs) are not the cause of the warming of the earth above the theoretical temperature it would have without an atmosphere. Jelbring’s hypothesis is one of several “gravito-thermal” theories which say the heating of the planet comes from gravity rather than (or in some theories in addition to) the greenhouse effect. His thought experiment is a planet with an atmosphere. The planet is isolated from the universe by an impervious thermally insulating shell that completely surrounds it, and which prevents any energy exchange with the universe outside. Inside the shell, Jelbring says that gravity makes the upper atmosphere colder and the lower atmosphere warmer. Back around 2004, I had a long discussion on the “climateskeptics” mailing list with Hans Jelbring. I said then that his theory was nothing but a perpetual motion machine, but at the time I didn’t understand why his theory was wrong. Now I do.
Dr. Robert Brown has an fascinating post on WUWT called “Earth’s baseline black-body model – a damn hard problem“. On that thread, I had said that I thought that if there was air in a tall container in a gravity field, the temperature of the air would be highest at the bottom, and lowest at the top. I said that I thought it would follow the “dry adiabatic lapse rate”, the rate at which the temperature of dry air drops with altitude in the earth’s atmosphere.
Dr. Brown said no. He said that at equilibrium, a tall container of air in a gravity field would be the same temperature everywhere—in other words, isothermal.
I couldn’t understand why. I asked Dr. Brown the following question:
Thanks, Robert, With great trepidation, I must disagree with you.
Consider a gas in a kilometre-tall sealed container. You say it will have no lapse rate, so suppose (per your assumption) that it starts out at an even temperature top to bottom.
Now, consider a collision between two of the gas molecules that knocks one molecule straight upwards, and the other straight downwards. The molecule going downwards will accelerate due to gravity, while the one going upwards will slow due to gravity. So the upper one will have less kinetic energy, and the lower one will have more kinetic energy.
After a million such collisions, are you really claiming that the average kinetic energy of the molecules at the top and the bottom of the tall container are going to be the same?
I say no. I say after a million collisions the molecules will sort themselves so that the TOTAL energy at the top and bottom of the container will be the same. In other words, it is the action of gravity on the molecules themselves that creates the lapse rate.
Dr. Brown gave an answer that I couldn’t wrap my head around, and he recommended that I study the excellent paper of Caballero for further insight. Caballero discusses the question in Section 2.17. Thanks to Dr. Browns answer plus Caballero, I finally got the answer to my question. I wrote to Dr. Brown on his thread as follows:
Dr. Brown, thank you so much. After following your suggestion and after much beating of my head against Caballero, I finally got it.
At equilibrium, as you stated, the temperature is indeed uniform. I was totally wrong to state it followed the dry adiabatic lapse rate.
I had asked the following question:
Now, consider a collision between two of the gas molecules that knocks one molecule straight upwards, and the other straight downwards. The molecule going downwards will accelerate due to gravity, while the one going upwards will slow due to gravity. So the upper one will have less kinetic energy, and the lower one will have more kinetic energy.
After a million such collisions, are you really claiming that the average kinetic energy of the molecules at the top and the bottom of the tall container are going to be the same?
What I failed to consider is that there are fewer molecules at altitude because the pressure is lower. When the temperature is uniform from top to bottom, the individual molecules at the top have more total energy (KE + PE) than those at the bottom. I said that led to an uneven distribution in the total energy.
But by exactly the same measure, there are fewer molecules at the top than at the bottom. As a result, the isothermal situation does in fact have the energy evenly distributed. More total energy per molecules times fewer molecules at the top exactly equals less energy per molecule times more molecules at the bottom. Very neat.
Finally, before I posted my reply, Dr. Brown had answered a second time and I hadn’t seen it. His answer follows a very different (and interesting) logical argument to arrive at the same answer. He said in part:
Imagine a plane surface in the gas. In a thin slice of the gas right above the surface, the molecules have some temperature. Right below it, they have some other temperature. Let’s imagine the gas to be monoatomic (no loss of generality) and ideal (ditto). In each layer, the gravitational potential energy is constant. Bear in mind that only changes in potential energy are associated with changes in kinetic energy (work energy theorem), and that temperature only describes the average internal kinetic energy in the gas.
Here’s the tricky part. In equilibrium, the density of the upper and lower layers, while not equal, cannot vary. Right? Which means that however many molecules move from the lower slice to the upper slice, exactly the same number of molecules must move from the upper slice to the lower slice. They have to have exactly the same velocity distribution moving in either direction. If the molecules below had a higher temperature, they’d have a different MB [Maxwell-Boltzmann] distribution, with more molecules moving faster. Some of those faster moving molecules would have the right trajectory to rise to the interface (slowing, sure) and carry energy from the lower slice to the upper. The upper slice (lower temperature) has fewer molecules moving faster — the entire MB distribution is shifted to the left a bit. There are therefore fewer molecules that move the other way at the speeds that the molecules from the lower slice deliver (allowing for gravity). This increases the number of fast moving molecules in the upper slice and decreases it in the lower slice until the MB distributions are the same in the two slices and one accomplishes detailed balance across the interface. On average, just as many molecules move up, with exactly the same velocity/kinetic energy profile, as move down, with zero energy transport, zero mass transport, and zero alteration of the MB profiles above and below, only when the two slices have the same temperature. Otherwise heat will flow from the hotter (right-shifted MB distribution) to the colder (left-shifted MB distribution) slice until the temperatures are equal.
It’s an interesting argument. Here’s my elevator speech version.
• Suppose we have an isolated container of air which is warmer at the bottom and cooler at the top. Any random movement of air from above to below a horizontal slice through the container must be matched by an equal amount going the other way.
• On average, that exchange equalizes temperature, moving slightly warmer air up and slightly cooler air down.
• Eventually this gradual exchange must lead to an isothermal condition.
I encourage people to read the rest of his comment.
Now, I see where I went wrong. Following the logic of my question to Dr. Brown, I incorrectly thought the final equilibrium arrangement would be where the average energy per molecule was evenly spread out from top to bottom, with the molecules having the same average total energy everywhere. This leads to warmer temperature at the bottom and colder temperature at elevation. Instead, at thermal equilibrium, the average energy per volume is the same from top to bottom, with every cubic metre having the same total energy. To do that, the gas needs to be isothermal, with the same temperature in every part.
Yesterday, I read the Jelbring hypothesis again. As I was reading it, I wondered by what logic Jelbring had come to the conclusion that the atmosphere would not be isothermal. I noticed the following sentence in Section 2.2 C (emphasis mine):
The energy content in the model atmosphere is fixed and constant since no energy can enter or leave the closed space. Nature will redistribute the contained atmospheric energy (using both convective and radiative processes) until each molecule, in an average sense, will have the same total energy. In this situation the atmosphere has reached energetic equilibrium.
He goes on to describe the atmosphere in that situation as taking up the dry adiabatic lapse rate temperature profile, warm on the bottom, cold on top. I had to laugh. Jelbring made the exact same dang mistake I made. He thinks total energy evenly distributed per molecule is the final state of energetic equilibrium, whereas the equilibrium state is when the energy is evenly distributed per volume and not per molecule. This is the isothermal state. In Jelbrings thought experiment, contrary to what he claims, the entire atmosphere of the planet would end up at the same temperature.
In any case, there’s another way to show that the Jelbring hypothesis violates conservation of energy. Again it is a proof by contradiction, and it is the same argument that I presented to Jelbring years ago. At that time, I couldn’t say why his “gravito-thermal” hypothesis didn’t work … but I knew that it couldn’t work. Now, I can see why, for the reasons adduced above. In addition, in his thread Dr. Brown independently used the same argument in his discussion of the Jelbring hypothesis. The proof by contradiction goes like this:
Suppose Jelbring is right, and the temperature in the atmosphere inside the shell is warmer at the bottom and cooler at the top. Then the people living in the stygian darkness inside that impervious shell could use that temperature difference to drive a heat engine. Power from the heat engine could light up the dark, and provide electricity for cities and farms. The good news for perpetual motion fans is that as fast as the operation of the heat engine would warm the upper atmosphere and cool the lower atmosphere, gravity would re-arrange the molecules once again so the prior temperature profile would be restored, warm on the bottom and cold on the top, and the machine would produce light for the good citizens of Stygia … forever.
As this is a clear violation of conservation of energy, the proof by contradiction that the Jelbring hypothesis violates the conservation of energy is complete.
Let me close by giving my elevator speech about the Jelbring hypothesis. Hans vigorously argues that no such speech is possible, saying
There certainly are no “Elevator version” of my paper which is based on first principal physics. It means that what I have written is either true or false. There is nothing inbetween.
Another “gravito-thermal” theorist, Ned Nikolov, says the same thing:
About the ‘elevator speech’ – that was given in our first paper! However, you apparently did not get it. So, it will take far more explanation to convey the basic idea, which we will try to do in Part 2 of our reply.
I don’t have an elevator speech for the Nikolov & Zeller theory (here, rebuttal here) yet, because I can’t understand it. My elevator speech for the Jelbring hypothesis, however, goes like this:
• If left undisturbed in a gravity field, a tall container of air will stratify vertically, with the coolest air at the top and the warmest air at the bottom.
• This also is happening with the Earth’s atmosphere.
• Since the top of the atmosphere cannot be below a certain temperature, and the lower atmosphere must be a certain amount warmer than the upper, this warms the lower atmosphere and thus the planetary surface to a much higher temperature than it would be in the absence of the atmosphere.
• This is the cause of what we erroneously refer to as the “greenhouse effect”
Now, was that so hard? It may not be the best, I’m happy to have someone improve on it, but it covers all the main points. The claim that “gravito-thermal” theories are too complex for a simple “elevator speech” explanation doesn’t hold water.
But you can see why such an elevator speech is like garlic to a vampire, it is anathema to the “gravito-thermal” theorists—it makes spotting their mistakes far too easy.
w.
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However, we do have a real heat source in the earth’s core with the fission of heavy nuclei. Not perhaps a lot, but some. I never have gotten any really good estimates of how large the effect is, and I am not enough of a geologist to derive it. Anyone around have an idea??
I have a partner who has been taken in by the Thrive Movement and especially the Free energy -torus machine I have tried to explain about nergy to no avail. The Thrive promoters are linking their philosphy to climate change and saving the planet by promoting their device as a saviour.
I think Hans uses a definition which is ‘per unit area’
There is more room at the top of the atmosphere for more thinly spread molecules. More area per isobar as altitude increases. Needs thinking about.
I’ll sleep on it.
ShrNfr:
http://en.wikipedia.org/wiki/Geothermal_gradient
Per Wikipedia “Heat flows constantly from its sources within the Earth to the surface. Total heat loss from the earth is 44.2 TW (4.42 × 1013 watts).[12] Mean heat flow is 65 mW/m2 over continental crust and 101 mW/m2 over oceanic crust.[12] This is approximately 1/10 watt/square meter on average, (about 1/10,000 of solar irradiation,)”
“More total energy per molecules times fewer molecules at the top exactly equals less energy per molecule times more molecules at the bottom. Very neat.”
Except that more of the total energy of the molecules at the top is locked up in gravitational potential as opposed to being available as kinetic energy capable of generating heat in collisions.
The isothermal/adiabatic distribution for an isolated ideal gas in a gravitational field has long been debated.
For the isothermal distribution we have Maxwell, Boltzmann and Clausius.
For the adiabatic distribution we have Loschmidt, Laplace and Lagrange.
The smart money must be with the isothermal advocates but I would not regard this as a debate of which was settled and of historical interest only.
Clausius clincher argument of the perpetual motion machine being possible for the adiabatic distribution turns out to be very hard to prove with real components given 9.8K/km scale.
Perhaps Willis will suggest a real experiment with real materials to test the alternative conjectures.
Say with a thermoelectric device to make use of the temperature difference.
A computer simulation program would not be any kind of proof
I think he will find with real materials that this is beyond him
Perhaps this is why there has never been an experiment to settle the matter!
If the adiabatic conjecture turned out to be correct I’m sure there would be an explanation that did not conflict with the second law.
Here for instance is a member of the physics department of the University of California making a very up to date case for the adiabatic distribution.
http://arxiv.org/PS_cache/arxiv/pdf/0812/0812.4990v3.pdf
Some Qs:
1. can the same result be found using gas laws, i.e., as P drops, so drops n thus leaving T unchanged? Seems reasonable.
2. do P and n necessarily change 1:1? I do not know this answer.
3. in light of 1., what if the total volume of the cylinder is not fixed?
4. in light of 2., what if they do not change 1:1?
Both 3. and 4. seem like complications beyond my reach.
Mark
Final thought for the night. Here’s the reply I gave Robert Brown on my site Earlier today:
Robert Brown says:
Second, my comment about egregious violation of the laws of thermodynamics were specific to Jelbring, who (IIRC, I’m not looking at his article again as I type this) explicitly asserted a column of fluid with no energy inputs, and then claimed that in equilibrium it would exhibit a thermal gradient. No, it wouldn’t.
Hi Robert,
I think the laws of thermodynamics talk about energy, rather than temperature or heat, but there are several formulations of them, so maybe we’d better discover who is using which definitions. We’d better do this, because in the application of classical mechanics to energy distribution in the model atmosphere, as defined by Hans Jelbring, there will indeed be a thermal gradient, as confirmed by Graeff’s empirical experimental data (Which should be replicated by an accredited laboratory).
“if A and B are placed in thermal contact, they will be in mutual thermal equilibrium, specifically no net heat will flow from A to B or B to A.” That’s the zeroth law.
Assuming your A and B have at least some dimension, then a thermal gradient across them would mean that the top surface of A will be at the same temperature as the bottom surface of B where they contact. Therefore no heat will flow. Even so, the average temperature of the whole of body A will be higher than that of B. QED.
http://www.emc.maricopa.edu/faculty/farabee/biobk/biobookener1.html
Laws of Thermodynamics
Energy exists in many forms, such as heat, light, chemical energy, and electrical energy. Energy is the ability to bring about change or to do work. Thermodynamics is the study of energy.
First Law of Thermodynamics: Energy can be changed from one form to another, but it cannot be created or destroyed. The total amount of energy and matter in the Universe remains constant, merely changing from one form to another. The First Law of Thermodynamics (Conservation) states that energy is always conserved, it cannot be created or destroyed. In essence, energy can be converted from one form into another. Click here for another page (developed by Dr. John Pratte, Clayton State Univ., GA) covering thermodynamics.
The Second Law of Thermodynamics states that “in all energy exchanges, if no energy enters or leaves the system, the potential energy of the state will always be less than that of the initial state.” This is also commonly referred to as entropy. A watchspring-driven watch will run until the potential energy in the spring is converted, and not again until energy is reapplied to the spring to rewind it.
———————-
I’m not seeing the words ‘heat’ or ‘temperature’ in these definitions, so please could you clarify. Thanks.
I’m not looking at his article again as I type this
Maybe you should. This is one of Jelbring’s chief complaints. People answer what they think he said, instead of answering what he actually said.
I think there is still a bit of a fudge factor in that elevator speech.
“Since the top of the atmosphere cannot be below a certain temperature…”
Why? It can’t be below absolute zero but that isn’t relevant here.
Willis Eschenbach wrote:
Yes, it was a long discussion and my, how time flies when you’re having fun. It’s even more fun when you finally “get it”, whatever the “it” is that’s been bugging you.
And thanks again for your help around that time and continuing pedagogy. Yer blood’s worth bottlin’ Willis.
I think I need to hear an elevator speech for why “same total energy per unit volume is a physical necessity. That is not obvious at all.
Here is another elevator speech for why in the constant insolation example you get an Isothermal atmosphere.
You have a fixed amount of energy per unit (Eg) area received by the ground. This is a experiment in spherical symmetry. Things like temperature, pressure, potential energy only vary by r (radius). So at the ground, at equilibrium, you have some temperature Tg = T(r=ground) that we will constrain by the SB law of a black-body ground. The catch is that in order to radiate the ground with Eg, you must have a uniform shell at r=(very large) also radiating Eg uniformly over its entire area. When you dissipate the energy per area by 1/r^2, you also increase the area of the shell radiating the ground by r^2. But if the shell is radiating at Eg, as a black body, then the temperature of the shell is Tg, the same temperature as the ground. So T(r) = Tg at r=ground and Tg at r=(very large). But (very large) is arbitrary, so it can be any value between ground and infinity. Therefore, T(r) = Tg at all r. Isothermal regardless of pressure and gravitational potential energy.
So I can get to Isothermal with the completely artificial initial conditions of uniform insolation. If and only If. Does that tell us anything useful about the real world? I’m skeptical. We need day and night.
ShrNfr says:
January 19, 2012 at 4:03 pm
ShrNfr, thanks for a good question. I ran the numbers in the past. I don’t have them in front of me, but it is very small, less than a tenth of a watt per square metre from memory.
There are a variety of geothermal regions, and hot vents under the sea, and hot springs and pools on land. But you have to consider—for every hot springs you know of, there are thousands of square miles of land with no hot springs, where if you go to sleep in the morning, you wake up very cold.
So yes, you are right, there is a heat source down under. But it is very small, even if we have greatly underestimated it. That’s why sleeping on the bare ground is dang chilly.
All the best,
w.
> If left undisturbed in a gravity field, a tall container of air will stratify vertically,
> with the coolest air at the top and the warmest air at the bottom.
My thermodynamics is a bit rusty, but I am fairly sure that warm air always rises to the top.
It is called the “adiabatic” lapse rate for a reason. It arises from adiabatic processes. What you are describing is the exact opposite of adiabatic. Your atmosphere is static and you allow it to reach a static thermal equilibrium over a very long period of time. Under those conditions you will indeed see equal temperatures everywhere. Hey – it isn’t at all surprising that you can get rid of the adiabatic lapse rate if your model eliminates all possibility of adiabatic processes.
But add in some adiabatic action – a nice little bit of vigorous vertical mixing – and the temperature gradient reappears. The elevator speech goes thus: “When air moves in a vertical airflow from the top to the bottom it is compressed and thus heats. When air moves in a vertical airflow from the bottom to the top it is decompressed and thus cools. In an atmosphere with a lot of vertical mixing you therefore will see a temperature gradient.”
Our atmosphere has such a temperature gradient.
I am skeptical of both the gravitaional model and the GHG model.
With respect to the former, i think that there are a number of factors overlooked, the extent to which they may be material is moot.
First, gravity is not a constant force acting on the atmosphere in the sense that the atmosphere is not subject to only the force resulting from the mass of the Earth. The atmosphere is constantly being flexed by the Sun and the Moon (and even to a small extent by the Gas Giants). The diurnal bulge/atmospheric bulge is the consequence of this and is well known and this means that work is constantly being inputted into the atmosphere and as one knows a by product of work is heat. One can see the effect (an extreme example admittedly) of gravitaional pull on Io which is the most geologically active body in the solar system and this is due to the gravitational pull imposed by Jupiter and the other Galean moons. Thus there is a top down force (gravity from the Sun, Moon etc) in addition to the bottom up force of the gravity from the Earth all working on the atmosphere.
Second, and this is a factor of the first point, the atmosphere is constantly being displaced at the bottom with the ebb and flow of the tides. Again, although this is obviously weak, this too results in work being exerted on the atmosphere, the by product of which is heat,
The result of these two factors is that the atmosphere is being squeezed much like the walls of a car tyre and any motorsport fan will know that this flexing generates heat in the tyre. It is very effective at heating up the air in a tyre or at any rate maintaining the heat generated by inflating the tyre to the desired pressure.
Third, the Earth itself is a heat source and imports heat into the atmosphere. The Earth is geologically active such that the ground is well above absolute zero. Indeed, even if the sun was to stop shinning, unlike the moon, the temperature of the ground would take a long time to cool to levels seen on the dark side of the Moon. Further, we know little of the deep ocean and there is every likelihood that the amount of thermal energy being inputted into the oceans is considerably under-assessed.
Fourth, the sun warms the atmosphere irrespective of GHGs simply because of aerosol particulate matter in the atmosphere which then warms surrounding gases by conduction/thermalisation
;
May be all of this does not add up to all that much. However, the atompsphere was obviously born warm (being the left over from what was in effect a condensing fireball and the out pourings of volcanoes etc) and one only needs it to add up to the amount of energy that the system is net losing to space to maintain an equalibrium balance.
I think that there may be more to the gravitational theory than you presently give it credit. .
I must modify my isothermal elevator speech with a slight complication. I said that to have Eg insolation at the ground, the black body shell at r=(very large) must also be at Eg. That would only be true if the index of refraction of the ideal gas is 1.000 at all pressures (r). I don’t think it is reasonable to assume index of refraction for a compressing ideal gas does not increase with pressure. Assuming that Index of refraction (Ir(r=ground) is higher near the ground than at high altitude Ir(r=large), then there is a focusing of energy. Therefore, the energy radiated per unit area by the shell must be Es < Eg. therefore T(r=very large) < Tg. But we still have an arbibrary "very large", so I'm talking myself into a slight decrease in T(r), as r increased from "ground" to "very large". Likewise, Es(r) also must = Eg at r=ground, but decrease as r increases as the Index of refraction decreases as r increases.
tallbloke says:
January 19, 2012 at 4:34 pm
Hans Jelbring, on the other hand, proposes a model earth with an impenetrable shell around it that does not allow energy to enter or leave the system, op. cit.:
In other words, no energy can get into or out of Jelbring’s system.
It seems to me that you just proved that Jelbring’s hypothesis can’t work, Tallbloke. If the potential energy of the state inside the shell can only move to where it is less than the initial state, as your quote clearly states … then how can the gravity possibly separate a low-energy, isothermal atmosphere into a higher energy state of cold at the top and warm at the bottom?
My best regards to you,
w.
Many people added comments, presumably physicists and engineers, indicating they had a huge problem with the Nikolov & Zeller theory. I think the issue is dead. There is no such thing as gravity creating higher temperatures.
Deep in the earth, radioactive decay (fission) of higher elements converts mass into energy. In extreme cases, larger bodies like our Sun, the gravitational pressures and heat can result in fusion, which creates even more energy by converting even more mass. The reality is that the center of our planet is well insulated from the near -273 C of space and it therefore remains hot as it is unable to dissipate the heat generated from radioactive decay quick enough to cool down. It has little to do with gravity and everything to do with fission heat and insulating properties of hundreds of miles of rock. What ultimately happens is what we call “steady state” (not the same as equilibrium).
It is the same for the atmosphere – it has energy sources from above (Sun) and from below (Earth black body & some reflected Sun) and ultimately our atmosphere has also reached a quasi-steady state which only fluctuates in response to the changes in energy gained and energy lost. Water being a huge stabilizer of our atmospheric temperature by virtue that it can store energy as it converts from water to a vapor and vice-versa. Anyone can see that after the sun’s radiative energy, water is the single biggest factor in the highly stable behavior of our atmosphere and finally orbital parameters and albedo play a small role to.
This atmospheric gravity thing is complete and utter codswallop.
Here’s a shorter elevator speech:
If there is a temperature gradient between two parts of a system, net heat flows from the warmer part to the cooler part. If there is net heat flow within the system, it is not in equilibrium.
Give us time Willis.
I’ve now read and understood N&Z, and their first reply at TT to commenters from WUWT and TT. I now think their work is a paradigm-shifting cracker, but I also realize that paradigm-shifters, while ultimately incredibly simple, need to do a lot of background detail work to answer all significant details AND eliminate all possible scientific stupidities of one’s own AND cope with the psychological challenge of answering classy experts without letting one’s scientific immaturity, feyness or hippiedom lose one the necessary credibility, AND provide an FAQ-type approach to those who’ve found something to doubt and given up on the spot. Like I was sure your elevator speech last time was flawed but my answer, though still IMHO denting your thesis, didn’t really deal with it properly. And I just haven’t yet read Jellbring at all. I might find I agree with you, re Jellbring, for all I know.
Give us time, and we will repay our debts, I mean explain the new paradigm in acceptable ways and with sufficient evidence from data in the public domain. There really is a lot of stunning high quality evidence now available.
The problem is that GHGs and back radiation does not explain the vertical temperature of the atmosphere. The inescapable conclusion of this is that the GHG model is not capable of explaining our atmosphere and that there is more at ‘play’ than the GHG model would suggest.
The vertiacal temperature profile of Earth’s atmosphere is not fully explained by the gravitational model but there does appear to be, for the main part some, causal connection. Ditto, other celestral bodies that we know of.
Presently, we do not know enough, or understand enough to fully evaluate either model. When you neither know or understand enough thought experiments invariably lead to flawed conclusions. Testing and the accumulation of observational data is required to take the matter forward/
Your elevator speech:
Here’s my elevator speech version.
• Suppose we have an isolated container of air which is warmer at the bottom and cooler at the top. Any random movement of air from above to below a horizontal slice through the container must be matched by an equal amount going the other way.
• On average, that exchange equalizes temperature, moving slightly warmer air up and slightly cooler air down.
• Eventually this gradual exchange must lead to an isothermal condition.
The air moving up and down exchanges potential energy (PE) for kinetic energy (KE). The air moving down loses PE but gains KE, and vice versa for the air moving up. A higher KE means a higher temperature, a lower KE means a lower temperature. So the air moving down increases in temperature (KE), while the air moving up decreases in temperature (KE). This will maintain the adiabatic lapse rate, warmer air at the bottom of the column and cooler air at the top.
Your second point is wrong, there is no equalisation of temperature. Therefore, your conclusion in the third point of your elevator speech is also wrong.
@Josh C Thanks.
To test any theory i like to look at the extremes and see if they work. So with this theory in mind, what temperature would the planet be left at if the sun were to switch off?
Should i now blame air pressure for my sunburn?
More briefly, one might refute the gravitational theory of atmospheric warming by reference to the empirical fact that at the top of the Earth’s atmosphere, outgoing radiant flux is closely similar to incoming radiant flux, whereas, if gravity contributed significantly to warming at the surface, Earth would be luminous, i.e., have a positive net outgoing radiant flux.
The only time gravity causes a net increase in the thermal energy content of the atmosphere is during the process of atmosphere formation, e.g., when an airless planet passes through a gas cloud. Then, gravitational compression of the gas will cause heating, the greatest effect being at the surface. However, the heat added to the atmosphere during gravitational compression will warm the surface, the added energy being then radiated to space until equilibrium is reached.