The Moon is a Cold Mistress

Guest Post by Willis Eschenbach

I’ve been considering the effect that temperature swings have on the average temperature of a planet. It comes up regarding the question of why the moon is so much colder than you’d expect. The albedo (reflectivity) of the moon is less than that of the Earth. You can see the difference in albedo in Figure 1. There are lots of parts of the Earth that are white from clouds, snow, and ice. But the moon is mostly gray. As a result, the Earth’s albedo is about 0.30, while the Moon’s albedo is only about 0.11. So the moon should be absorbing more energy than the Earth. And as a result, the surface of the moon should be just below the freezing temperature of water. But it’s not, it’s much colder.

Figure 1. Lunar surface temperature observations from the Apollo 15 mission. Red and yellow-green short horizontal bars on the left show the theoretical (red) and actual (yellow-green) lunar average temperatures. The violet and blue horizontal bars on the right show the theoretical Stefan-Boltzmann temperature of the Earth with no atmosphere (violet), and an approximation of how much such an Earth’s temperature would be lowered by a ± 50°C swing caused by the rotation of the Earth (light blue). Sunset temperature fluctuations omitted for clarity. DATA SOURCE

Like the Earth, averaged over its whole surface the moon receives about 342 watts per square metre (W/m2) of solar energy. We’re the same average distance from the sun, after all. The Earth reflects 30% of that back into space (albedo of 0.30), leaving about 240 W/m2. The moon, with a lower albedo, reflects less and absorbs more energy, about 304 W/m2.

And since the moon is in thermal equilibrium, it must radiate the same amount it receives from the sun, ~ 304 W/m2.

There is something called the “Stefan Boltzmann equation” (which I’ll call the “S-B equation” or simply “S-B”) that relates temperature (in kelvins) to thermal radiation (in watts per square metre). It says that radiation is proportional to the fourth power of the temperature.

Given that the moon must be radiating about 304 W/m2 of energy to space to balance the incoming energy, the corresponding blackbody lunar temperature given by the S-B equation is about half a degree Celsius. It is shown in Figure 1 by the short horizontal red line. This shows that theoretically the moon should be just below freezing.

But the measured actual average temperature of the lunar surface shown in Figure 1 is minus 77°C, way below freezing, as shown by the short horizontal yellow-green line …

So what’s going on? Does this mean that the S-B equation is incorrect, or that it doesn’t apply to the moon?

The key to the puzzle is that the average temperature doesn’t matter. It only matters that the average radiation is 304 W/m2. That is the absolute requirement set by thermodynamics—the average radiation emitted by the moon must equal the radiation the moon receives from the sun, 304 W/m2.

But the radiation is proportional to the fourth power of temperature. This means when the temperature is high, there is a whole lot more radiation, but when it is low, the reduction in radiation is not as great. As a result, if there are temperature swings, they always make the surface radiate more energy. As a result of radiating more energy, the surface temperature cools. So in an equilibrium situation like the moon, where the amount of emitted radiation is fixed, temperature swings always lower the average surface temperature.

For confirmation, in Figure 1 above, if we first convert the moment-by-moment lunar surface temperatures to the corresponding amounts of radiation and then average them, the average is 313 W/m2. This is only trivially different from the 304 W/m2 we got from the first-principles calculation involving the incoming sunlight and the lunar albedo. And while this precise an agreement is somewhat coincidental (given that our data is from one single lunar location), it certainly explains the large difference between simplistic theory and actual observations.

So there is no contradiction at all between the lunar temperature and the S-B calculation. The average temperature is lowered by the swings, while the average radiation stays the same. The actual lunar temperature pattern is one of the many possible temperature variations that could give the same average radiation, 304 W/m2.

Now, here’s an oddity. The low average lunar temperature is a consequence of the size of the temperature swings. The bigger the temperature swings, the lower the average temperature. If the moon rotated faster, the swings would be smaller, and the average temperature would be warmer. If there were no swings in temperature at all and the lunar surface were somehow evenly warmed all over, the moon would be just barely below freezing. In fact, anything that reduces the variations in temperature would raise the average temperature of the moon.

One thing that could reduce the swings would be if the moon had an atmosphere, even if that atmosphere had no greenhouse gases (“GHGs”) and was perfectly transparent to infrared. In general, one effect of even a perfectly transparent atmosphere is that it transports energy from where it is warm to where it is cold. Of course, this reduces the temperature swings and differences. And that in turn would slightly warm the moon.

A second way that even a perfectly transparent GHG-free atmosphere would warm the moon is that the atmosphere adds thermal mass to the system. Because the atmosphere needs to be heated and cooled as well as the surface, this will also reduce the temperature swings, and again will slightly warm the surface in consequence. It’s not a lot of thermal mass, however, and only the lowest part has a significant diurnal temperature fluctuation. Finally, the specific heat of the atmosphere is only about a quarter that of the water. As a result of this combination of factors, this is a fairly minor effect.

Now, I want to stop here and make a very important point. These last two phenomena mean that the moon with a perfectly transparent GHG-free atmosphere would be warmer than the moon without such an atmosphere. But a transparent atmosphere could never raise the moon’s temperature above the S-B blackbody temperature of half a degree Celsius.

The proof of this is trivially simple, and is done by contradiction. Suppose a perfectly transparent atmosphere could raise the average temperature of the moon above the blackbody temperature, which is the temperature at which it emits 304 W/m2.

But the lunar surface is the only thing that can emit energy in the system, because the atmosphere is transparent and has no GHGs. So if the surface were warmer than the S-B theoretical temperature, the surface would be emitting more than 304 W/m2 to space, while only absorbing 304 W/m2, and that would make it into a perpetual motion machine. Q.E.D.

So while a perfectly transparent atmosphere with no GHGs can reduce the amount of cooling that results from temperature swings, it cannot do more than reduce the cooling. There is a physical limit to how much it can warm the planet. At a maximum, if all the temperature swings were perfectly evened out, we can only get back to S-B temperature, not above it. This means that for example, a transparent atmosphere could not be responsible for the Earth’s current temperature, because the Earth’s temperature is well above the S-B theoretical temperature of ~ -18°C.

Having gotten that far, I wanted to consider what the temperature swings of the Earth might be like without an atmosphere. Basic calculations show that with the current albedo, the Earth with no atmosphere would be at a blackbody temperature of 240 W/m2 ≈ -18°C. But how much would the rotation cool the planet?

Unfortunately, the moon rotates so slowly that it is not a good analogue to the Earth. There is one bit of lunar information we can use, however. This is how fast the moon cools after dark. In that case the moon and the Earth without atmosphere would be roughly equivalent, both simply radiating to outer space. At lunar sunset, the moon’s surface temperature shown in Figure 1 is about -60°C. Over the next 30 hours, it drops steadily at a rate of about 4°C per hour. At that point the temperature is about -180°C. From there it only cools slightly for the next two weeks, because the radiation is so low. For example, at its coolest the lunar surface is at about -191°C, and at that point it is radiating a whopping two and a half watts per square metre … and as a result the radiative cooling is very, very slow.

So … for a back of the envelope calculation, we might estimate that the Earth would cool at about the lunar rate of 4°C per hour for 12 hours. During that time, it would drop by about 50°C (90°F). During the day, it might warm about the same above the average. So, we might figure that the temperature swings on the Earth without an atmosphere might be on the order of ± 50°C. (As we would expect, actual temperature swings on Earth are much smaller, with a maximum of about ± 20-25 °C, usually in the desert regions.)

How much would this ±50° swing with no atmosphere cool the planet?

Thanks to a bit of nice math from Dr. Robert Brown (here), we know that if dT is the size of the swing in temperature above and below the average, and T is the temperature of the center of the swing, the radiation varies by 1 + 6 * (dT/T)^2. With some more math (see the appendix), this would indicate that if the amount of solar energy hitting the planet is 240 W/m2 (≈ -18°C) and the swings were ± 50°C, the average temperature would be – 33°C. Some of the warming from that chilly temperature is from the atmosphere itself, and some is from the greenhouse effect.

This in turn indicates another curiosity. I’ve always assumed that the warming from the GHGs was due solely to the direct warming effects of the radiation. But a characteristic of the greenhouse radiation (downwelling longwave radiation, also called DLR) is that it is there both day and night, and from equator to poles. Oh, there are certainly differences in radiation from different locations and times. But overall, one of the big effects of the greenhouse radiation is that it greatly reduces the temperature swings because it provides extra energy in the times and places where the solar energy is not present or is greatly reduced.

This means that the greenhouse effect warms the earth in two ways—directly, and also indirectly by reducing the temperature swings. That’s news to me, and it reminds me that the best thing about studying the climate is that there is always more for me to learn.

Finally, as the planetary system warms, each additional degree of warming comes at a greater and greater cost in terms of the energy needed to warm the planet that one degree.

Part of this effect is because the cooling radiation is rising as the fourth power of the temperature. Part of the effect is because Murphy never sleeps, so that just like with your car engine, parasitic losses (losses of sensible and latent heat from the surface) go up faster than the increase in driving energy. And lastly, there are a number of homeostatic mechanisms in the natural climate system that work together to keep the earth from overheating.

These thermostatic mechanisms include, among others,

• the daily timing and number of tropical thunderstorms.

• the fact that clouds warm the Earth in the winter and cool it in the summer.

• the El Niño/La Niña ocean energy release mechanism.

These work together with other such mechanisms to maintain the whole system stable to within about half a degree per century. This is a variation in temperature of less than 0.2%. Note that doesn’t mean less than two percent. The global average temperature has changed less than two tenths of a percent in a century, an amazing stability for such an incredibly complex system ruled by something as ethereal as clouds and water vapor … I can only ascribe that temperature stability to the existence of such multiple, overlapping, redundant thermostatic mechanisms.

As a result, while the greenhouse effect has done the heavy lifting to get the planet up to its current temperature, at the present equilibrium condition the effect of variations in forcing is counterbalanced by changes in albedo and cloud composition and energy throughput, with very little resulting change in temperature.

Best to all, full moon tonight, crisp and crystalline, I’m going outside for some moon-viewing.

O beautiful full moon!

Circling the pond all night

even to the end

Matsuo Basho, 1644-1694

w.

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steveta_uk
January 9, 2012 3:58 am

Alexander Feht says: January 9, 2012 at 12:30 am

Clear presentation, very poor physics.The surface of the Moon is colder than the surface (and lower layer of the atmosphere) of the Earth for the same reason a man without a blanket, during a cold night, is colder than a man under a blanket.

I assume you are referring to a dead man – since any fool would realize that a living man has an internal heat source that makes your comparison completely irrelevant.
So do you have details of the experiment performed on two dead bodies left out overnight, one with a blanket and one without? If so, please quote a reference.
If not, please apologize for calling Willis “senile”.

January 9, 2012 4:03 am

Bryan says:
January 9, 2012 at 1:15
1. why after 14 Earth days does the dark side never reach absolute zero but stays some 90K above?
—————————–
The Cosmic Background Radiation is about 2.76 K, so you can rule out reaching absolute zero, or 0 K.

kadaka (KD Knoebel)
January 9, 2012 4:05 am

From David on January 9, 2012 at 12:26 am:

Wow… as an aside, imagine if we could increase the Moon’s rotation to about the same as Earth’s – perhaps by a deliberate glancing meteor blow. The faster rotation would reduce the temperature swings to about the same as Earth’s, thank to the calculations above…
Then we could terraform the Moon. One speculative proposal is here: http://www.lunar-union.org/planetary-engineering/terraforming_moon.html. If this is combined with a faster rotation then it would be much better.

That could be problematic. The Moon is phase locked (aka tidally locked) to the Earth. As it is too solid, hard, and rocky to deform, even if its rotation around its axis could be sped up then it would want to return to the preferred state, with the same face always facing the Earth.
You could try speeding up the revolution of the Moon around the Earth to shorten the day/night transition period on the Moon. With simple Newtonian physics and a two-body problem, for a stable orbit the force of gravitation must equal the centripetal force.
Gravitational force: F=GMm / r^2, F=Force, G=gravitational constant, M=mass of Earth, m=mass of Moon, r=radius of orbit (distance between centers of mass)
Centripetal force: F=mv^2 / r, v=speed (technically scalar component of the velocity).
GMm / r^2 = mv^2 / r – divide both sides by m
GM / r^2 = v^2 / r – multiply both sides by r^2
GM = rv^2
Thus radius times velocity squared equals a constant (G times mass of Earth). Quick and dirty, since it takes about 4 weeks (28 days) for the Moon to revolve around the Earth, a lunar day is around 28 days, we want to shorten that to around 1/28 of current amount, the Moon would have to revolve around the Earth about 28 times faster. To keep it in orbit the radius would shorten by the square of that factor, 28^2=784, current radius divided by 784. The average distance between the centers of mass of the Earth and the Moon (called a lunar distance) is 384,400 kilometers. 384,400/784=490 kilometers, the approximate radius needed for a lunar day of around an Earth day.
However as the mean radius of the Moon is 1,737 km, and that of the Earth is 6,371 km, this method of shortening the lunar day should not be recommended.
So basically we’re stuck with the current length of a lunar day. When we get around to colonizing the Moon, if we’re going to grow plants by daylight then we’ll need something that’ll work with 2 week long on/off cycles. But since algae will get boring quickly, we’ll likely be using artificial lighting as well.

PeterF
January 9, 2012 4:21 am

Willis, thanks for pointing out what impact temperature swings have on the average temperature through the T^4 relationship from S-B. This nicely extends previous discussion here and elsewhere, e.g. at Roy Spencer’s blog (http://www.drroyspencer.com/2011/12/why-atmospheric-pressure-cannot-explain-the-elevated-surface-temperature-of-the-earth/) .
So, you cannot only show the impact of rotational speed of a celestial body to its average surface temperature, but the presence of an atmosphere, be it a “normal” one with GHGs, or a theoretical one completely void of GHGs, will raise average surface temp through smoothing out the temp swings over the surface through redistribution of heat vertically via convection and horizontally via wind from pressure gradients.
Wouldn’t that imply that even a perfect non-GHGs atmosphere would exhibit an adiabatic temp profile? I think it would, however, Roy expects an isothermal atmosphere. This question remains unanswered. Any reasoning from you towards either direction?

January 9, 2012 4:28 am

Nice analysis but you’ve ignored at least 99% of the moon and 99% of the Earth both of which little to nothing is known. Sure vulcanologists etc. have some information about the centre of the Earth but they infer far too much from far too little information.

Bryan
January 9, 2012 4:51 am

Markus says of the Ground Heat Flux
” I’ve run the numbers myself from a couple of directions, and it’s just not all that large. Even assuming that there are many more deep sea vents than are generally thought, there still isn’t enough heat coming from the inside of the planet to make much difference.”
I think you have a different definition of ground heat flux to that used by Gerhard Kramm and Ralph Dlugi.
See Fig 12
http://www.scirp.org/journal/PaperInformation.aspx?paperID=9233

Peter
January 9, 2012 4:54 am

Willis wrote:

But a transparent atmosphere could never raise the moon’s temperature above the S-B blackbody temperature of half a degree Celsius.

Small point, shouldn’t that be average temperature?

DirkH
January 9, 2012 5:00 am

Alexander Feht says:
January 9, 2012 at 3:57 am
“One of the main conclusions in the above article is as follows: “This means that the greenhouse effect warms the earth in two ways—directly, and also indirectly by reducing the temperature swings. That’s news to me, and it reminds me that the best thing about studying the climate is that there is always more for me to learn.” Really? My reading skills are developed enough to see that Mr. Eschenbach is talking about atmospheric effects again.”
No, Alexander, try again. Willis talks about the effect that the T^4 term has when the temperature varies drastically, as in the case of the moon, compared to the effect it has when the temperature varies less, as in the case of the Earth. In the case of the drastic variation, a lower average temperature is necessary to allow the planetary body to radiate enough. It’s a mathematical thing.

January 9, 2012 5:02 am

steveta_uk says:
January 9, 2012 at 3:58 am
I assume you are referring to a dead man – since any fool would realize that a living man has an internal heat source that makes your comparison completely irrelevant.

Earth has an internal heat source. Which makes your comment completely irrelevant.

Stephen Wilde
January 9, 2012 5:05 am

“It shows up the warming from atmospheric pressure nonsense for what it is, it is the equalising effect on the temperature range from a energy transporting atmsophere that raises the average temperature.”
As I understand it the gravitational pull on the mass of the atmosphere whether containing GHGs or not sets up the baseline lapse rate via compression of the atmosphere. Simply put, the solar energy passing through is slowed down by the compression due to the greater opportunity for collisions between more densely packed molecules.
In principle that is no different from the Radiative GHE because both methods achieve their heating effect by slowing down the flow of solar energy through the atmosphere. Neither scenario is a breach of the Laws of Thermodynamics.
GHGs can try to alter that gravitationally induced lapse rate but in fact changes in the non radiative processes will work as a negative system response.
Additionally, non radiative energy transfer processes can temporarily cause a different lapse rate (either steeper or shallower) from the gravitationally induced one by redistributing energy across the surface but not for long.
The strange thing is that I’m sure that in my schooldays it was the gravitational effect that was termed the Greenhouse Effect and it applied to every planet with an atmosphere whether with or without GHGs.
The term ‘Greenhouse Effect’ has only more recently become identified solely with radiative processes.
As regards the S-B equation that isn’t really relevant because it is only applied after the surface temperature has been set by the combination of the Gravitational GHE (which is fixed) and any net Radiative GHE after the negative system responses to the latter have been played through.
The gravitational effect involves the total mass of the entire planet including atmosphere whether GHGs or not whereas the radiative effect on Earth only involves water vapour plus a miniscule amount of non condensing GHGs. Thus one would expect the radiative component to be far smaller than the gravitational component.
The AGW viewpoint needs to recognise the gravitational component and properly quantify it as compared to the net (after negative system responses) effect of the radiative component and furthermore limit the figure to that attributable to the non condensing GHGs alone.
The condensing GHGs (water vapour) seem to neutralise their own effects via the negative system response of the water cycle and might well deal with the non condensing portion too.
I do not accept the proposition that there can be a positive system response to non condensing GHGs from the water cycle. No evidence has come to light supporting that assumption and with evaporation having a net cooling effect it is implausible to my mind.
Furthermore, adding non condensing GHGs to a transparent relatively non radiative atmosphere such as one containing mostly Oxygen and Nitrogen like Earth’s actually increases the ability of that atmosphere to radiate out to space. Oxygen and Nitrogen cannot do that to any significant degree so in theory they should produce an even hotter surface temperaure. Oxygen and Nitrogen conduct 100% of their energy downward because they cannot radiate to space. In contrast, non condensing GHGs radiate 50% of their energy out to space.

David
January 9, 2012 5:10 am

Willis says…”As a result, while the greenhouse effect has done the heavy lifting to get the planet up to its current temperature,…”
How much of the GHE on earth is actually due to the oceans where the residence time of energy is far far longer then any GHG? Also, although the average albedo of earth is higher then the moon’s, is it higher at laditudes where TSI is stongest?

gnarf
January 9, 2012 5:12 am

Here a nice article showing influence of heat capacity, applied to moon.
You can get average temperatures from 169K to 291K.
http://scienceofdoom.com/2010/06/03/lunar-madness-and-physics-basics/
The real problem is that averaging temperatures over time and/or space has no meaning. As you say, averaging T^4 and later take the fourth root gives you something more coherent.
If you consider a cold earth with a short temperature range (min and max close from each other) then average temperature is MORE than for a hot earth with a wide temperature range!
In a similar way, if you reduce the number of weather stations and keep only stations close from towns, you reduce the measured temperature range-> you increase the average temperature!

Bomber_the_Cat
January 9, 2012 5:24 am

Willis, I’ve added this to my archive of informative articles. The cooling rate of the moon is useful; I’ve never seen it used to calculate what the earth temperature might be without an atmosphere. As Izen says (January 9, 2012 at 3:36 am), Science of Doom also has an article on Lunar temperatures but from a different perspective. He(she) takes into account various hypothetical heat capacities of the Moon.
Don’t you always find that when you post a straightforward article like this that you get a lot of flack from the anti-science brigade who insists on misreading or misinterpreting what has been said. Well maybe not misreading – some of them don’t appear to have read it.
But take heart from the poem:
“If you can bear to hear the words you’ve spoken, twisted by knaves to set a trap for fools….”
.

cal
January 9, 2012 5:26 am

It always amazes me how rude ignorant people are! About 2 years ago I entered into a discussion on the temperature of the moon on this blog. Armed with just the albedo of the moon and the peak daytime temperature I estimated cooling rates etc to come to a temperature profile that would be consistent with the SB laws. I was met with a barrage of abuse until someone put up the actual figures which were within a couple of degrees of mine (so I was a bit lucky!).
Willis has come at it from the opposite direction and come to the same picture, as one might expect. I think he did a really good job. How anyone can argue with the Physics is a bit beyond me.
A couple of things that Willis did not emphasise.
The profile would be different it there was a liquid surface with a high thermal capacity. This would also flatten the profile just as it does on earth.
I think it is also worth clarifying the reason why the SB equation appears to favour the less dramatic profile. To make it simple: if the surface were at an average of 150K a drop of 50K would take it to 100K and an increase of 50 would take it to 200K. Because of the fourth power law the relative rates of radiation would be 1:16 at the extremes giving you an average of just over 8 over the cycle (assuming a square wave). A constant temperature of 150K would only give you relative figure of about 5 so the temperature would have to increase in order to radiate at 8.5 average. Willis makes this point but uses a formula which may not make it absolutely clear what is going on.
Thanks again Willis. I enjoyed your post as I normally do. Congratulations on not losing your temper (too much!). I would not be so patient.

January 9, 2012 5:31 am

If daylight on earth lasted 14.5 days, instead of 12 hours, there would be huge temperature swings on earth that I would like someone to calculate.
Similarly, if daylight on the moon lasted 12 hours instead of 14.5 days, temperature swings on the moon would be much smaller.
The different lengths of a day on the moon and on the earth probably account for more of the temperature swings than the presence or not of an atmosphere. How much more? Could someone tell me?

Spector
January 9, 2012 5:40 am

Fourth Root of the Mean Fourth Powers
The important thing to keep in mind here is that 304 W/m² is a measure of average energy flow. Thus the ‘characteristic temperature’ calculated by the Stefan-Boltzmann equation is not an average temperature, it is a special average based on the fact that energy flow is proportional to the fourth power (T⁴) of the absolute temperature. Thus the characteristic temperature is equivalent to a fourth root of the mean fourth powers average. This might be considered analogous to an RMS average except fourth powers are involved instead of squares. An average of this type tends to emphasize higher values and thus will yield a higher result than a simple average of surface temperatures. Of course, this only makes sense when using absolute temperatures.

David
January 9, 2012 5:44 am

markus says:
January 9, 2012 at 2:58 am
“If you are talking about the earth, as far as I know the ground heat flux is on the order of a tenth of a watt per square metre. I’ve run the numbers myself from a couple of directions, and it’s just not all that large. Even assuming that there are many more deep sea vents than are generally thought, there still isn’t enough heat coming from the inside of the planet to make much difference. If there were, we could sleep on the ground to stay warm.”
Am I OK to assume there is no heat transfer, other than the .1 Wm/2, between the oceans waters and the ocean floor, either way?
————————————————-
Markus, I think this is a good question. Of course the crustal thickness in the oceans is reduced relative to the land, therefore one would assume a higher heat flux. When discussing the affect of a small incidence of energy one must consider that energy is never lost, therfore one must consider the residence time of the material recieving that influx. The law is very simple. At its most basic only two things can effect the energy content of any system in a radiative balance. Either a change in the input, or a change in the “residence time” of some aspect of those energies within the system. The residence time of the earths energy flux into the ocean depths is likely thosands of years, so I suspect it is not properly appreciated.

Bill Illis
January 9, 2012 5:45 am

The darkside of the Moon does receive reflected sunlight and thermal radiation from the Earth. It is estimated to be about 0.095 W/m2 so a tiny amount, but enough to raise the Moon’s darkside temperature about 32C above the cosmic background radiation level. That still leaves lots of unaccounted for energy in the Moon’s darkside temperature.
Converting some of this data from W/m2 to Joules/second/m2 helps some in the understanding. There are accumulation rates and rates of energy loss. The numbers for the Moon are different than the Earth but not that much different.

Owen
January 9, 2012 6:22 am

Willis,
I love your work and the uncomplicated way you present it so even people like myself can understand what you are talking about. Anthony Watts has the best climate site on the internet because of contributors like yourself. Thanks for sharing your thoughts and ideas with the world.

January 9, 2012 6:22 am

I no longer bother studying long-winded theoretical articles that miss the most basic reality. The lack of real understanding, in this article, of the thermodynamics of the atmosphere is well brought out in the admission at the end:
“The global average temperature has changed less than two tenths of a percent in a century, an amazing stability for such an incredibly complex system ruled by something as ethereal as clouds and water vapor … I can only ascribe that temperature stability to the existence of such multiple, overlapping, redundant thermostatic mechanisms.”
Those who respect the Standard Atmosphere (which my Venus/Earth temperature comparison confirmed as the equilibrium state of the atmosphere), are not so easily flummoxed by the supposedly “incredibly complex system”. The stability is clearly, even obviously, due to the weight of the atmosphere itself, in hydrostatic condition and thus exhibiting a stable, negative vertical temperature lapse rate with altitude throughout the troposphere. That stable thermal condition predominates over all other atmospheric processes, conditions or mechanisms, including the difference between night and day. Clouds and water vapor don’t rule, the hydrostatic condition does (transient and local deviations like temperature inversions notwithstanding).

David
January 9, 2012 6:30 am

I thought the lunar discussion was very good, and credit to Willis for the article. Didn’t feel it followed through though when the greenhouse subject came into the piece. Why is the average higher with greenhouse warming? Explaining that in terms of the still constant energy emission would have polished it off nicely.

Alan D McIntire
January 9, 2012 6:30 am

gnomish says:
January 9, 2012 at 3:43 am
“but: ” the bigger the temperature swings, the lower the average temperature.”
an average is an average. extremities don’t change the average by any mathematical process.”
There are different averages here. Bigger temp swings do not change average radiation, but radiation is not proportional to temperature, it’s proportional to the 4th power of temperature.
.
distribute radiation
16 16 16 16 and you get temp 16^0.25 16^0.25 16^0.25 16^0.25 = 2 2 2 2 for an average of 2.
Take the same radiation and distribute it
31 31 1 1 and you get temps of 31^0.25 31^0.25 1^0.25 and 1^0.25 = 2.36 2.36 1 1 with and
arithmetical average of 1.68, a 16% drop in average absolute temperature .
Another point that could be addressed- in the real universe nothing acts like a black body when radiation is constantly changing, as on all rotating planets. A blackbody at earth distance would absorb and radiate 1368 watts at the equivalent of the equator at noon, for an equivalent temperature of 394 K, and would radiate at 2.7 watts- the temp of the “big bang” at night. For real bodies you need to also apply Newton’s law of heating/cooling.

January 9, 2012 6:35 am

Alexander Feht says:
Alexander I cannot see what you are referring to even I (uneducated save for a high school diploma) can see throughout that he is comparing the moon and the earth without an atmosphere the only atmosphere he really goes into detail about is the imaginary one he introduces in the thought experiment I think you are letting a strong dislike for Willis get in the way of reading his posts objectively.

John Marshall
January 9, 2012 6:46 am

I do not think that Lunar gravity is sufficient to hold an atmosphere. Increasing rotational speed only makes it worse. Apart from that the above thoughts will work (?).

adolfogiurfa
January 9, 2012 6:59 am

So the moon should be absorbing more energy than the Earth..
You are absolutely right!, but it is not only about “temperature”:
Prof.Piers Corbyn uses the Sun-Moon-earth relation in his forecasting method:
http://www.weatheraction.com/
Richard Holle too:
http://research.aerology.com/aerology-analog-weather-forecasting-method/

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