# Another Look at Climate Sensitivity

Guest Post by Willis Eschenbach

OK, a quick pop quiz. The average temperature of the planet is about 14°C (57°F). If the earth had no atmosphere, and if it were a blackbody at the same distance from the sun, how much cooler would it be than at present?

a) 33°C (59°F) cooler

b) 20°C (36°F) cooler

c) 8° C (15°F) cooler

The answer may come as a surprise. If the earth were a blackbody at its present distance from the sun, it would be only 8°C cooler than it is now. That is to say, the net gain from our entire complete system, including clouds, surface albedo, aerosols, evaporation losses, and all the rest, is only 8°C above blackbody no-atmosphere conditions.

Why is the temperature rise so small? Here’s a diagram of what is happening.

Figure 1. Global energy budget, adapted and expanded from Kiehl/Trenberth . Values are in Watts per square metre (W/m2). Note the top of atmosphere (TOA) emission of 147 W/m2. Tropopause is the altitude where temperature stops decreasing with altitude.

As you can see, the temperature doesn’t rise much because there are a variety of losses in the complete system. Some of the incoming solar radiation is absorbed by the atmosphere. Some is radiated into space through the “atmospheric window”. Some is lost through latent heat (evaporation/transpiration), and some is lost as sensible heat (conduction/convection). Finally, some of this loss is due to the surface albedo.

The surface reflects about 29 W/m2 back into space. This means that the surface albedo is about 0.15 (15% of the solar radiation hitting the ground is reflected by the surface back to space). So let’s take that into account. If the earth had no atmosphere and had an average albedo like the present earth of 0.15, it would be about 20°C cooler than it is at present.

This means that the warming due to the complete atmospheric system (greenhouse gases, clouds, aerosols, latent and sensible heat losses, and all the rest) is about 20°C over no-atmosphere earth albedo conditions.

Why is this important? Because it allows us to determine the overall net climate sensitivity of the entire system. Climate sensitivity is defined by the UN IPCC as “the climate system response to sustained radiative forcing.” It is measured as the change in temperature from a given change in TOA atmospheric forcing.

As is shown in the diagram above, the TOA radiation is about 150W/m2. This 150 W/m2 TOA radiation is responsible for the 20°C warming. So the net climate sensitivity is 20°C/150W-m2, or a temperature rise  0.13°C per W/m2. If we assume the UN IPCC canonical value of 3.7 W/m2 for a doubling of CO2, this would mean that a doubling of CO2 would lead to a temperature rise of about half a degree.

The UN IPCC Fourth Assessment Report gives a much higher value for climate sensitivity. They say it is from 2°C to 4.5°C for a CO2 doubling, or from four to nine times higher than what we see in the real climate system. Why is their number so much higher? Inter alia, the reasons are:

1. The climate models assume that there is a large positive feedback as the earth warms. This feedback has never been demonstrated, only assumed.

2. The climate models underestimate the increase in evaporation with temperature.

3. The climate models do not include the effect of thunderstorms, which act to cool the earth in a host of ways .

4. The climate models overestimate the effect of CO2. This is because they are tuned to a historical temperature record which contains a large UHI (urban heat island) component. Since the historical temperature rise is overestimated, the effect of CO2 is overestimated as well.

5. The sensitivity of the climate models depend on the assumed value of the aerosol forcing. This is not measured, but assumed. As in point 4 above, the assumed size depends on the historical record, which is contaminated by UHI. See Kiehl for a full discussion.

6. Wind increases with differential temperature. Increasing wind increases evaporation, ocean albedo, conductive/convective loss, ocean surface area, total evaporative area, and airborne dust and aerosols, all of which cool the system. But thunderstorm winds are not included in any of the models, and many models ignore one or more of the effects of wind.

Note that the climate sensitivity figure of half a degree per W/m2 is an average. It is not the equilibrium sensitivity. The equilibrium sensitivity has to be lower, since losses increase faster than TOA radiation. This is because both parasitic losses and albedo are temperature dependent, and rise faster than the increase in temperature:

a) Evaporation increases roughly exponentially with temperature, and linearly with wind speed.

b) Tropical cumulus clouds increase rapidly with increasing temperature, cutting down the incoming radiation.

c) Tropical thunderstorms also increase rapidly with increasing temperature, cooling the earth.

d) Sensible heat losses increase with the surface temperature.

e) Radiation losses increases proportional to the fourth power of temperature. This means that each additional degree of warming requires more and more input energy to achieve. To warm the earth from 13°C to 14°C requires 20% more energy than to warm it from minus 6°C (the current temperature less 20°C) to minus 5°C.

This means that as the temperature rises, each additional W/m2 added to the system will result in a smaller and smaller temperature increase. As a result, the equilibrium value of the climate sensitivity (as defined by the IPCC) is certain to be smaller, and likely to be much smaller, than the half a degree per CO2 doubling as calculated above.

## 579 thoughts on “Another Look at Climate Sensitivity”

1. dp says:

Hmmm – Isn’t the moon pretty much earth without air? The temperature there is entirely radiative to surface dwellers (the few that have dwelt), and the soil temperature is dependent upon it’s exposure to the sun. In shadows it is damned cold – I’d wager colder than 40 something degrees.

I think your science on this is not robust, or my understanding of what you mean by black body located in our celestial toroid is flawed.

2. enough says:

For a real chart showing thermal balance go look up figure 2.3 Principles of Atmospheric Physics and Chemistry. Goody 1996

The back radiation term is pure bs. It is tied in with the nonsense argument of the atmospheric reradiation of 1/2 up /1/2 down. Absolute rubish

3. Bill Parsons says:

Wiki Answer to: “What is the temperature on the moon?”

The average daytime temperature on the Moon is around 107°C (225°F), but can be as high as 123°C (253°F).

When an area rotates out of the sun, the “nighttime” temperature falls to an average of -153°C (-243°F).

253 F
-243 F
_______
10 F

Don’t know if that helps. 8 degrees is pretty close.

4. Willis Eschenbach says:

dp (20:46:32)

Hmmm – Isn’t the moon pretty much earth without air? The temperature there is entirely radiative to surface dwellers (the few that have dwelt), and the soil temperature is dependent upon it’s exposure to the sun. In shadows it is damned cold – I’d wager colder than 40 something degrees.

I think your science on this is not robust, or my understanding of what you mean by black body located in our celestial toroid is flawed.

I’m not sure what your point is here. The moon experiences huge temperature swings because it rotates so slowly. As a result, the temperatures are very dependent on local topography. Recent results from the Diviner satellite show that there are areas on the moon which never see the sun, and are at a temperature of ~ 40K. None of these are true of the earth.

My calculations are based on a blackbody using the Stefan-Bolzmann equation. This equation allows us to convert between radiation intensity and temperature. If I have made a mistake in my calculations, please let me know.

5. Willis Eschenbach says:

enough (20:51:43)

For a real chart showing thermal balance go look up figure 2.3 Principles of Atmospheric Physics and Chemistry. Goody 1996

The back radiation term is pure bs. It is tied in with the nonsense argument of the atmospheric reradiation of 1/2 up /1/2 down. Absolute rubish

Sorry, you have not given enough information for me to respond … plus you misspelled “rubbish”. If you post and link the figure you refer to, we can discuss it. In the interim, you might read the Kiehl/Trenberth paper referred to above.

6. Jan says:

I find this analysis be very important. Thanx

7. Willis Eschenbach (21:07:38) :

enough (20:51:43) : edit

For a real chart showing thermal balance go look up figure 2.3 Principles of Atmospheric Physics and Chemistry. Goody 1996

The back radiation term is pure bs. It is tied in with the nonsense argument of the atmospheric reradiation of 1/2 up /1/2 down. Absolute rubish

Sorry, you have not given enough information for me to respond … plus you misspelled “rubbish”. If you post and link the figure you refer to, we can discuss it. In the interim, you might read the Kiehl/Trenberth paper referred to above.

Willis, I think he is talking about a figure numbered 2.3 in this book:

Principles of Atmospheric Physics and Chemistry (Hardcover)
~ Richard Goody (Author) “In the longest view, the earth is passing through a series of disequilibrium conditions between the origin of the universe, 15 billion years (By) ago,…”

http://www.amazon.com/Principles-Atmospheric-Physics-Chemistry-Richard/dp/0195093623

You can get it used for only $50.00! 8. B. Smith says: Without an atmosphere there would be no oceans, ice, snow or plant life to affect albedo, so the albedo of the Earth should be more similar to that of the barren Moon. It would seem reasonable and logical to expect the high and low temperature variations on an atmosphere-less, barren, waterless Earth to more closely resemble those of the Moon. Am I missing something here? “Lunar Surface Temperatures Temperatures on the Lunar surface vary widely on location. Although beyond the first few centimeters of the regolith the temperature is a nearly constant -35 C (at a depth of 1 meter), the surface is influenced widely by the day-night cycle. The average temperature on the surface is about 40-45 C lower than it is just below the surface. In the day, the temperature of the Moon averages 107 C, although it rises as high as 123 C. The night cools the surface to an average of -153 C, or -233 C in the permanently shaded south polar basin. A typical non-polar minimum temperature is -181 C (at the Apollo 15 site). The Lunar temperature increases about 280 C from just before dawn to Lunar noon. Average temperature also changes about 6 C between aphelion and perihelion. Marvin Ostrega Reference: Heiken et al. Lunar Sourcebook: A User’s Guide to the Moon. Cambridge: University of Cambridge Press, 1991.” 9. Willis Eschenbach (21:04:42) : My calculations are based on a blackbody using the Stefan-Bolzmann equation. This equation allows us to convert between radiation intensity and temperature. I would have said 20C, not 8C… 10. Matt says: The link about the manifold ways in which thunderstorms cool the earth appears not to be working. Pity – I really wanted to read it. 11. Jim Masterson says: >> In the interim, you might read the Kiehl/Trenberth paper referred to above. << The link isn’t working (for me). Which paper? KT1997? Or the update, TFK2009? I made an infinite layer model and the back radiation doesn’t match KT1997, but it comes close. That 40 W/m^2 for the atmospheric window may be bogus. KT1997 doesn’t calculate it correctly. It may be 80 W/m^2 or 87 W/m^2, depending on how you define “cloudy.” Jim 12. Willis Eschenbach says: enough (20:51:43) For a real chart showing thermal balance go look up figure 2.3 Principles of Atmospheric Physics and Chemistry. Goody 1996 The back radiation term is pure bs. It is tied in with the nonsense argument of the atmospheric reradiation of 1/2 up /1/2 down. Absolute rubish Ok, I found the Figure 2.3 you referenced: Other than minor differences, my numbers agree with that figure. The difference is that your diagram only shows the net flows, while mine shows all flows. In other words, both are correct, and they don’t disagree with each other. I don’t want this to devolve into an argument about the global energy budget. For my purposes, I’m only using two figures from the diagram, the TOA radiation and the surface albedo. Your diagram is not detailed enough to show either of those. So although it is interesting and correct as a diagram of net flows, it is not relevant to my calculations. 13. I keep reading a number of .05-.09C of CO2 warming and that may indeed be right. less than .5C or a factor of TEN! decade vs century? Thanks for the post, id bet is was a lot of work! You will note that the closer we come to the TRUTH the more they attack, without sources, or logic. Tim L 14. John A says: How of the incoming energy from the Sun is converted into atmospheric and oceanic convection? None, according to Kielh and Trenberth. Which is amazing. Climate physics is a fascinating subject. 15. jorgekafkazar says: dp (20:46:32) : “Hmmm – Isn’t the moon pretty much earth without air? The temperature there is entirely radiative to surface dwellers (the few that have dwelt), and the soil temperature is dependent upon it’s [sic] exposure to the sun. In shadows it is damned cold – I’d wager colder than 40 something degrees. “I think your science on this is not robust, or my understanding of what you mean by black body located in our celestial toroid is flawed.” Your understanding is flawed across the board, and your prose is impenetrable. What do you mean by “radiative to surface dwellers?” Where did you come up with “our celestial toroid?” 16. dp says: A thing you’ve raised to ponder is does the moon radiate solar heat as fast as it absorbs it? Well, obviously yes, at some temperature it does, and necessarily into that part of the sky not filled with sunlight. (And I’m perfectly happy to accept regional variances in temperature owing to maria vs disrupted lunar surfaces.) As would an airless earth. Actually, so too would an atmospheric earth as Venus demonstrates. Since we’re talking about energy balance here – clearly the moon is now radiating back to space as much energy as it receives after all these billions of years, there being no mechanism for storage and transport as there is on earth, the current energy level, the black body temperature of the moon, allowing for the rotational gradient, is it really that close to earth’s temperature which is moderated by atmospheric and oceanic energy distribution? My problem is I don’t see how black body temperature translates to an embracing thermal experience as provided to living things by the atmosphere and oceans. If what you say is true it is really quite profound as it suggests our global temperature is a matter of albedo, no? 17. As is shown in the diagram above, the TOA radiation is about 150W/m2. This 150 W/m2 TOA radiation is responsible for the 20°C warming. So the net climate sensitivity is 20°C/150W-m2, or a temperature rise 0.13°C per W/m2. If we assume the UN IPCC canonical value of 3.7 W/m2 for a doubling of CO2, this would mean that a doubling of CO2 would lead to a temperature rise of about half a degree. I think this first part is questionable. Nothing wrong with your division of 20/150 mathematically, just whether it means anything. If you take a fixed albedo and increase the radiative forcing at the surface you can calculate the increase in temperature without feedbacks. You obviously know how to do this.. (For people who don’t, you can see more at The Earth’s Energy Budget – Part One and at the end of CO2 – An Insignificant Trace Gas – Part Seven ) So your calculation is basically saying that the response of the climate system from no atmosphere to current status is a linear model. I know that of course, we can’t assume the same albedo. I see your comments on the various aspects of climate response, don’t know what to think about those yet. Rightly or wrongly to assume no climate through to current climate is linear seems way way out there! Perhaps you are aiming at a parody of GCMs producing a linear response? I find their linear response hard to believe but perhaps you could say that if you look at one small part of a big curve, the slope is linear or can be approximated linear close to that area.. 18. Willis Eschenbach says: Jim Masterson (21:31:33) >> In the interim, you might read the Kiehl/Trenberth paper referred to above. << The link isn’t working (for me). Which paper? KT1997? Or the update, TFK2009? I made an infinite layer model and the back radiation doesn’t match KT1997, but it comes close. That 40 W/m^2 for the atmospheric window may be bogus. KT1997 doesn’t calculate it correctly. It may be 80 W/m^2 or 87 W/m^2, depending on how you define “cloudy.” Jim Link fixed, thanks for alerting me. w. 19. savethesharks says: Great post, Willis. Maybe I missed it, but it should also be stated that, as a new point number 7, the general circulation models are also woefully lacking in accounting for the multi-decadal oscillations of the oceans, including, but not limited to the PDO and the AMO, among many others. But that point on the importance of cooling with tropical thunderstorms, poorly understood, can not be overemphasized! Dr. Spencer and Lindzen and others are cracking that block….and so little is known. But you could not be more right. Thunderstorms…are magnificent (albeit ephemeral) players in the earth’s climate. They boil in atomic-bomb-scale local and mesoscale fury…to heights up to the tropopause…and we wonder how they can bring down airlines (Brazil to France, last year). Then they fade away in cirrus wisps the next day….all of that heat escaping through an open “window” in the atmosphere… Thanks again for this post. Chris Norfolk, VA, USA 20. Brian W says: enough (20:51:43) Bingo! Spot On. Willis Eschenbach It’s pretty late here and I would like to debate your so called diagram. So a couple of things now and more tomorrow. Backradiation as well as feedbacks are pseudoscience. There is no real physical basis for back radiation. As enough(my feelings exactly) stated it’s nonsense and simply not true. The holy grail of the black/grey body is inadequate to analyse the earth’s weather and climate. Does the earth look like a black/grey body? The warmers have concocted a heady brew from this as the diagram shows. Forget Kiehl/Trenberth they are climate quacks. Take clouds for example, according to the diagram 76w/m2 is not only reflected by the clouds, but also by aerosols and the atmosphere. Really? How is the number 76 arrived at? Clouds most certainly absorb the suns energy. Where is the figure for that? Another thing, with clouds constantly forming and dissipating across the planet, is this an averaged figure for the entire surface? Are all the numbers in the diagram static and unchanging or subject to WIDE variations? It all looks like an add up the numbers exercise. My BS detector goes off the charts whenever I look at that diagram. Its a mess. So please explain to me your understanding of backradiation and how it occurs and I’ll debunk it. By the way, in your post at 21:04:42 you misspelled Boltzman. Pretty easy to leave a letter out, eh. 21. JDN says: Let’s try it and find out. :) 22. Willis Eschenbach says: scienceofdoom (22:09:37) Rightly or wrongly to assume no climate through to current climate is linear seems way way out there! Perhaps you are aiming at a parody of GCMs producing a linear response? I find their linear response hard to believe but perhaps you could say that if you look at one small part of a big curve, the slope is linear or can be approximated linear close to that area. I make no assumption of linearity at all. What I’m doing is figuring the average sensitivity of the system as a whole. In fact, I point out that the equilibrium sensitivity is going to be different from the average sensitivity, and list some reasons why the equilibrium sensitivity will be smaller than the average. 23. stan stendera says: Sometimes my birdfeeder has hawks circling above it looking for easy pray. One is them is Eschenbach’s hawk. a subspecies of Cooper’s hawk; both of which are far too uncommen 24. JinOH says: ‘Sometimes my birdfeeder has hawks circling above it looking for easy pray. One is them is Eschenbach’s hawk. a subspecies of Cooper’s hawk; both of which are far too uncommen’ LOL – I have hawks visiting my feeders too at times. Nature is a bummer for science. 25. Ray Boorman says: The Moon is very different to Earth, which makes the simple comparisons of pundits above worthless. 1) It is 3,743 km in diameter versus earth’s 12,756 km; 2) Earth is over 1000 deg C at the top of the mantle, which is a mere 5km below the seabed in the deep ocean, & about 50km under the land surface. 3) Moon rotates once each 27 & a bit days, Earth rotates every 24 hours. 4) Earth has lots of volcanic activity, which brings heat to the surface. None has been detected on the Moon, yet. 26. Willis Eschenbach says: Brian W (22:14:31) enough (20:51:43) Bingo! Spot On. Willis Eschenbach It’s pretty late here and I would like to debate your so called diagram. So a couple of things now and more tomorrow. Backradiation as well as feedbacks are pseudoscience. There is no real physical basis for back radiation. As enough(my feelings exactly) stated it’s nonsense and simply not true. I am not interested in debating my diagram, or the reality of downwelling longwave radiation, on this thread. Those are subjects for some other thread, not here. Do a google search for “measured downwelling longwave radiation” (usually called DLR). There are hundreds of measurements of DLR made all the time. There are companies who make instruments specifically for measuring DLR. There are scientists who spend their lives studying the actual measurements of DLR. The idea that it doesn’t exist is a joke that is not worth debating. A good place to start fighting your lack of knowledge on this subject is here. But please, this is not the place to discuss it. It is a good topic … but this is not the right thread for it. This thread is about climate sensitivity. Thanks, w. 27. Brian W: Backradiation as well as feedbacks are pseudoscience. There is no real physical basis for back radiation How about measurement of it? We can measure longwave radiation (>4um) downward at the earth’s surface. It’s not coming from the sun which radiates 99% of its radiation 4um coming from? You can see one example of some specific measurements at CO2 – An Insignificant Gas? Part Six – Visualization Strangely enough the peak radiation of this downwards radiation occurs in those wavelengths that match the absorption spectra of CO2, CH4, water vapor, ozone. And at the top of the atmosphere the outgoing (upward) longwave radiation has a “notch” in those same wavelengths. 28. Willis Eschenbach says: B. Smith (21:16:39) Without an atmosphere there would be no oceans, ice, snow or plant life to affect albedo, so the albedo of the Earth should be more similar to that of the barren Moon. It would seem reasonable and logical to expect the high and low temperature variations on an atmosphere-less, barren, waterless Earth to more closely resemble those of the Moon. Am I missing something here? Yes. I’m looking to find out the total effect of the atmosphere (GHGs, clouds, aerosols, etc.) on the temperature of the earth. So I’m taking the theoretical temperature of the earth without an atmosphere, but with the same albedo as the earth. I’m comparing that to the current conditions on the earth. As regards your question about temperature variations, the high and low temperature variations of the moon and an atmosphere-less earth would be very different, because the earth cools at night for only 12 hours, while the moon cools during the lunar night for 14 days, and the same is true of the warming during an earth day and a lunar day. So it is a good question, but that is not the point of this thread. 29. Willis Eschenbach says: Matt (21:31:17) The link about the manifold ways in which thunderstorms cool the earth appears not to be working. Pity – I really wanted to read it. Fixed, thanks. w. 30. Willis Eschenbach says: dp (21:52:12) If what you say is true it is really quite profound as it suggests our global temperature is a matter of albedo, no? Yes and no. Surface albedo just sets the base temperature. Cloud albedo has a huge effect on the temperature, as it reflects some 70 W/m2 of the suns energy back into space. But there are a host of processes that affect the temperature, among them thunderstorms, cosmic rays, wind strength, the list is long. w. 31. Brian Johnson uk says: dp…. “I think your science on this is not robust, or my understanding of what you mean by black body located in our celestial toroid is flawed.” dp, Homer Simpson rules – we live on a celestial donut! “Donuts. Is there anything they can’t do?” 32. stan stendera says: Way, way, way off topic! for JinOH I will never forget this: I put birdseed on my deckrail. And of course the squirrels get into it. I was playing on the compute , came to a stopping point,and glanced out the sliding door to the deck. The squirrel, stealing birdseed, suddently started running back and forth then leapt off the deck. Out of nowhere came a Cooper’s hawk and snatched it out of the air. That is why Altamonte is such a crime. MODERATORS! I know this is off topic. You have my complete permission to forward it to jinOH including my E-mail!!!! 33. (Something funny happened to my last post, I think because I used a less than sign..) Brian W: Backradiation as well as feedbacks are pseudoscience. There is no real physical basis for back radiation How about measurement of it? We can measure downward longwave radiation (greater than 4um) at the earth’s surface. It’s not coming from the sun which radiates 99% of its radiation less than 4um. Where is this radiation coming from? You can see one example of some specific measurements at CO2 – An Insignificant Gas? Part Six – Visualization Strangely enough the peak radiation of this downwards radiation occurs in those wavelengths that match the absorption spectra of CO2, CH4, water vapor, ozone. And at the top of the atmosphere the outgoing (upward) longwave radiation has a “notch” in those same wavelengths. 34. Steve Goddard says: Venus is the same size as earth and has a fairly uniform temperature of over 400C across the entire planet (day or night equator or pole) This is because of their atmosphere. Sunlight on Mercury is four times stronger than Venus, yet temperatures average much cooler, because of the lack of an atmosphere. My plane flight on Saturday descended 35,000 ft. and temperatures warmed by 150 degrees F as we descended – because of the blanket generated by the atmosphere. 35. anna v says: Willis, All the temperatures we have are in the air , and there is a large difference between ground and air. I do not know of any measured ground temperatures. Where do you take the 14C from? SSTs might be OK, so maybe you should take the SST average temperature as the 0 atmosphere temperature. Earth is 75% ocean after all. the AMSU plots give a scale from -2 to 30, that would give 14, but I would think a true average would come higher. The albedo of the moon is around 0.1 so it is not a good analogue for your purposes. 36. Spence_UK says: The figure of 0.13 K per W/m^2 is interesting. Spencer and Christy found that the LT temperature varies by 2.3K over the year due to the eccentricity of the orbit of the earth. There is little or no perceptible phase lag in this variation wrt the orbital pattern, suggesting this is a full figure and there is no “warming in the pipeline”. The orbital eccentricity results in a variation of solar radiance of 90 W/m^2. Of course, this arrives over a pi*r disc and is spread over 4*pi*r surface of the sphere, resulting in an equivalent of 17 W/m^2 averaged over the surface of the earth. This yields a climate sensitivity of 2.3/17 = 0.135 K per W/m^2, entirely independently of Willis’ calculation. Coincidence? 37. Sou says: Is this post meant to be parody, or is the humour unintentional? 38. Spence_UK says: re: my 23:59 Good grief, why don’t I check my posts before pressing submit :) Firstly, the area of a circle is pi*r^2 and the surface of a sphere is 4*pi*r^2. Secondly, 90/4 is 22.5 not 17. I’m sure I got that number from somewhere, just can’t remember where… This yields a climate sensitivity *lower* than Willis at 0.1 K per W/m^2. Not such a coincidence, but at least in the same ball park… 39. B. Smith says: Thank you for clarifying, WE. 40. wayne says: Willis : enough (20:51:43) : I follow you Willis. Good point and well done! And as ‘enough’ pointed out about the 1/2 up and 1/2 down being rubbish, he is right. All of these energy balance charts are basically wrong, misleading, or incomplete but that doesn’t take one iota away from what you have just have shown us on the sensitivity. The one thing they all do agree on is output equal input. You see, none of them take into account the dip of the horizon correction or just “the dip”. Any good sailor who knows celestial navigation is well aware of that factor and it applies whether radiation is inbound from stars or outbound from CO2 molecules. Half up and half down can only occur exactly at the sea’s surface and ALL radiation leaving randomly from atoms or molecules in the atmosphere must account for the dip factor. If you even stand up and are 5 feet above sea level it is no longer half up and half down however tiny. At 20,000 feet it is sizeable. There is now much more going up to space and much less going down back to warm the surface and this factor increases with the height above sea level quickly at first and slower near satellite altitudes. At high tropic cloud top levels this imbalance can get rather large, shunting heat directly to space. If you want the equations, holler. I learned celestial navigation from a captain right out of college (had a dream of circumnavigating when young). That reinforces your statements about the mention of wind speed on evaporation rates which feed the clouds which shunt the heat to space, but you can’t if “half is up and half is down” and that often used term IS rubbish. This is only my opinion, wink. 41. kevoka says: I am missing something. Everywhere I have read the calculations result in a blackbody temp of 255K. No atmosphere , no blanket, the temp would be 255K. About 30K less than it is. 1C = 1K. 42. anna v: You have a point when you say: All the temperatures we have are in the air , and there is a large difference between ground and air. I do not know of any measured ground temperatures. The air temperature is taken as the closest proxy to the land surface temperature. During the day it is a reasonably close value because the land heats up, heats the air directly over it and this air then expands and rises. The result is convective mixing which means that the air temperature six feet off the ground is a reasonable estimate. At night it’s a different story. The temperature can vary significantly in the first few feet because the bottom layer is now colder and there is no convective mixing. “No wind” conditions give very different results from wind conditions. For this reason and UHI issues we should just give up on trying to measure land temperatures But given what we do have our best estimate of annual average global surface temperature is around 15’C. 43. Hi Willis, great post for opening up discussion. The ‘atmospheric window’ is only 13W/M^2 according to Trenberth. You commented that thunderstorms would increase with increasing temperature. Presumably that would widen the window quite a bit. Would it also stick quite a lot more water vapour into the higher part of the troposphere? What effect would that have? 44. Nylo says: You should not compare to a black body of an homogeneus temperature. Because of the emisivity dependence on t^4, two black bodies with the same average temperature but different distribution of it along their surface radiate different ammounts of energy. For a given average temperature, the more temperature differences you have along the surface, the more you radiate to space. To continue with the moon example, if the average of the moon’s daily temperature is 107C and the average night temperature is -153C, you can be sure that the emisivity total is quite higher than that of a black body with a uniform average temperature of -23C, i.e. the same average temperature. That’s because the emisivity you gain with the +130C of the illuminated side is much bigger than the emisivity you lose with the -130C of the dark side. Actually, it would be equivalent to a black body with a uniform temperature of 320K (47C). Quite hot huh? But this is considering a moon with one half at some uniform 107C and the other half at some uniform -153C. In reality, there are also differences of temperature along both surfaces leading to those averages. And remember: any inhomogeneity in the temperature leads to more emisivity than that of a black body of the same average temperature. So the equivalence of the emisivity would be to a black body of even more than 47C average temperature. Calculations: Daily temperature = 107C = 380K Night temperature = -153C = 120K The black body with equivalent emisivity would have a temperature equal to the 4th root of ((380^4+120^4)/2) = 320K = 47C (The day side, with 3.16 times the temperature of the night side, radiates more than 3.16^4= 100.5 times the energy radiated by the night side. 45. Willis Eschenbach says: anna v (23:48:31) Willis, All the temperatures we have are in the air , and there is a large difference between ground and air. I do not know of any measured ground temperatures. Where do you take the 14C from? SSTs might be OK, so maybe you should take the SST average temperature as the 0 atmosphere temperature. Earth is 75% ocean after all. the AMSU plots give a scale from -2 to 30, that would give 14, but I would think a true average would come higher. The albedo of the moon is around 0.1 so it is not a good analogue for your purposes. HadCRUT absolute temperatures (averages 1961-1990). 3 Mb zipped ascii file. Regarding the moon, I’m not the one who brought it up. 46. Brian W says: Willis Eschenbach (22:57:51) Well, lets see, you used the diagram to show us that “this is what’s happening”. I and many others do not agree. If the diagram is wrong then using w/m2 and blackbody physics will not give you the right answer. If the numbers are wrong then how do you calculate anything? Yes indeed a very impressive link but since incoming sunlight is comprised of 10% ultraviolet, 44.8% visible (shortwave) and 45.2% INFRARED how is it these wonderful scientists can accurately separate upwelling from downwelling without proper hard experiments in the atmosphere? Sensitivity based on what, fancy algorithms with built in beliefs. Explaining part or all of the diagram shows me that you know what you are talking about, and you avoided it so I’m dubious. As to the sensitivity. CO2 with a specific heat less than N2, O2 and even aluminum, poor absorption compared to air, fast emission and most importantly a concentration of .038% by volume contributes NO sensible (usable) heat to our atmosphere. A doubling of CO2 will not give even .1 degree increase. I wish people would stop fixating on CO2. So the models do overestimate sensitivity by a huge amount. The whole AGW/CO2 thing is a stinking scientific fraud. Period. 47. Willis Eschenbach says: Sou (00:09:06) Is this post meant to be parody, or is the humour unintentional? Not a parody. What humour? 48. stan stendera says: It was not a Cooper’s hawk. it was an Eschwnbach hawl! 49. stan stendera says: It was not a Cooper’s hawk. it was an Eschenbach hawk! 50. Willis, you are only looking at the high frequency end of an amplifying process, there is definetely a frequency dependency in climate sensititivity noticable, although not as high on a century timespan as IPCC models make of it.. http://members.casema.nl/errenwijlens/co2/howmuch.htm See also Pelletier for a temperature power spectrum Jon D. Pelletier, 2002, Natural variability of atmospheric temperatures and geomagnetic intensity over a wide range of time scales, doi:10.1073/pnas.022582599 PNAS February 19, 2002 vol. 99 no. Suppl 1 2546-2553 Link 51. Willis Eschenbach says: kevoka (00:24:44) I am missing something. Everywhere I have read the calculations result in a blackbody temp of 255K. No atmosphere , no blanket, the temp would be 255K. About 30K less than it is. 1C = 1K. That would be the temperature of a blackbody earth if it only received the amount of energy that is not reflected by the earth’s albedo, or about 235 W/m2. But that assumes clouds and surface albedo, neither of which exist on a blackbody. On a blackbody earth the current distance from the sun, it would only be 8°C cooler. w. 52. Willis Eschenbach says: tallbloke (00:35:35) Hi Willis, great post for opening up discussion. The ‘atmospheric window’ is only 13W/M^2 according to Trenberth. You commented that thunderstorms would increase with increasing temperature. Presumably that would widen the window quite a bit. Would it also stick quite a lot more water vapour into the higher part of the troposphere? What effect would that have? Hey, tallbloke, always good to hear from you. If you look at the Kiehl/Trenberth paper cited above under Figure 1, he says 40 W/m2 for the radiation loss through the window. I’ve never considered the question of the atmospheric window and thunderstorms, not sure what the answer is. Thunderstorms definitely put more moisture into the high troposphere over the tropics. Always more to learn, and more to think about. w. 53. Brian W (00:44:44) : but since incoming sunlight is comprised of 10% ultraviolet, 44.8% visible (shortwave) and 45.2% INFRARED how is it these wonderful scientists can accurately separate upwelling from downwelling without proper hard experiments in the atmosphere? It’s easy. Incoming sunlight is 99% less than 4um in wavelength. Climate science calls this conventionally “shortwave”. Radiation from the surface of the earth is 99.9% greater than 4um in wavelength. Climate science calls this conventionally “longwave”. Which means solar and terrestrial radiation can be easily distinguished and lots can be learnt even without “fancy algorithms with built in beliefs. 54. Surprisingly, new NASA diagram shows no back-radiation.. If Kiehl-Trenberth diagram is correct and backradiation of 321W/m2 is responsible for the hypothetical +33K effect, it means additional 3.7W/m2 will cause 0.38°C net warming. 55. kevoka (00:24:44) : Everywhere I have read the calculations result in a blackbody temp of 255K. This calculation is wrong, since it is calculated with present albedo of 0.3. 2/3 of this albedo is made by clouds, which should actually not be there if there are no GH gases or atmosphere. More, much colder Earth with (frozen) oceans would turn partially to white snowball and its albedo would be mightily increased. 56. Nylo says: Re: Willis Eschenbach (00:44:35) : “Regarding the moon, I’m not the one who brought it up”. I know. I have used the moon as an example only because it is easy to see the implications as the temperaure swings are so huge. But the same idea could be applied to the Earth. The energy radiated by the Earth is not the same as the energy radiated by a black body of the same average but homogeneous temperature. It is quite bigger, because also the Earth has noticeable swings in the temperature between night and day (especially in the deserts), or the poles and the ecuator, or the summer and the winter hemispheres. The hottest parts radiate sooo much more. 57. Lindsay H says: interesting::: I have a problem with your black body figures for the earth http://en.wikipedia.org/wiki/Black_body  Temperature of Earth If we substitute in the measured values for the Sun and Earth: If we set the average emissivity to unity, we calculate the “effective temperature” of the Earth to be: TE = 254.356 K or -18.8 C. This is the temperature that the Earth would be at if it radiated as a perfect black body in the infrared, ignoring greenhouse effects, and assuming an unchanging albedo. The Earth in fact radiates almost as a perfect black body in the infrared which will raise the estimated temperature a few degrees above the effective temperature. If we wish to estimate what the temperature of the Earth would be if it had no atmosphere, then we could take the albedo and emissivity of the moon as a good estimate. The albedo and emissivity of the moon are about 0.1054[20] and 0.95[21] respectively, yielding an estimated temperature of about 1.36 C. Estimates of the Earth’s average albedo vary in the range 0.3–0.4, resulting in different estimated effective temperatures. Estimates are often based on the solar constant (total insolation power density) rather than the temperature, size, and distance of the sun. For example, using 0.4 for albedo, and an insolation of 1400 W m−2), one obtains an effective temperature of about 245 K.[22] Similarly using albedo 0.3 and solar constant of 1372 W m−2), one obtains an effective temperature of 255 K.[23][24] this is substantially different from your estimates is the author of the wiki misleading us? the earth atmosphere albido is in the order of 30% based on satelliteMODIS values. so the greengouse effect plus .3 albido gives an average temp of 14 deg c , a difference of 32deg c from the theoretical black body temp. I’m scratching my ancient head a bit ! applying the albido of 30% should give the planet a temp of 279 deg k = 5.85 deg C meaning the greenhouse effect adds 8 deg c. confusion abounds! 58. Brian W says: Steve Goddard (23:47:55) The shell of your airplane heated due to air friction! Blankets indeed! Science of Doom (23:43:15) “We can measure downward longwave radiation (greater than 4um) at the earth’s surface. It’s not coming from the sun which radiates 99% of its radiation less than 4um.” The sun is a “broadband radiator” it radiates at ALL frequencies. Since everyone likes w/m2 here is some watts for you. Bright sunlight provides an irradiance of just over 1 kilowatt per square meter at sea level. Of this energy, 527 watts is INFRARED light, 445 watts is visible light, and 32 watts is ultraviolet light(wiki). And these are only three tiny bands of frequencies in a much larger spectrum. So good luck with your pseudoscience of doom. You are just another warmist site promulgating calculated nonsense. 59. Ronaldo says: scienceofdoom (23:43:15) : “Strangely enough the peak radiation of this downwards radiation occurs in those wavelengths that match the absorption spectra of CO2, CH4, water vapor, ozone. And at the top of the atmosphere the outgoing (upward) longwave radiation has a “notch” in those same wavelengths.” Isn’t this because the absorption of IR at specific wavelengths raises the internal (vibrational) energy of the molecule (of CO2, H2O), which then promptly re-emits energy at the same wavelength but in a random direction, hence the notches in the upwelling radiation? The absorption is an internal process, not a thermal process. 60. Frozen man says: Hi Willis, good post i think. I’ve been studying some time this kind of radiation balances, So some things can be added for further knowledge: 1. The graph is old in this authors (Trenberth et altea, 2008), the new one is clearly unbalanced to warm ( i couldn’t see clear what was based on) 2. I think they don’t have applied some basic laws of energy and thermodynamics like: internal energy of the system (U), all the kinds of energy that the earth also receipt, f. e., magnetic, gravitational, etc…. Also thety didnt take into account the effect of winds as cinetic energy, etc… this graph suffers from too much simplicity (only radiation). 61. Willis Eschenbach says: Juraj V. (01:34:32) Surprisingly, new NASA diagram shows no back-radiation. http://eosweb.larc.nasa.gov/EDDOCS/images/Erb/components2.gif Once again, people are confusing net radiation flows with the individual radiation flows. Suppose I give you a hundred dollars, and you give me seventy-five dollars. There are two equally valid and accurate ways of representing this transaction: Figure 3. Two different ways of correctly illustrating the same transaction. 3(a) shows the two individual transactions. 3(b) shows the net effect of the two transactions. Now, if we look at Figure 3(b) above, does the lack of an arrow from you to me mean that you didn’t give me$75? No, of course not. But since your $75 is smaller than the amount I gave you, it does not show up in the net flow diagram. What the new Nasa diagram is showing is net flows. What Figure 2.3 above is showing is net flows. But as my drawing above illustrates, that doesn’t mean that the individual flows don’t exist. Downwelling radiation is real. But since it is smaller than the upwelling radiation, it doesn’t show up in the net flow diagram. This does not mean that it doesn’t exist … If Kiehl-Trenberth diagram is correct and backradiation of 321W/m2 is responsible for the hypothetical +33K effect, it means additional 3.7W/m2 will cause 0.38°C net warming. Not true by the UN IPCC definition. That definition relates warming to top of atmosphere (TOA) radiation, not to downwelling radiation from the bottom of the atmosphere. 62. Willis Eschenbach says: Lindsay H (01:49:50) interesting::: I have a problem with your black body figures for the earth http://en.wikipedia.org/wiki/Black_body  Temperature of Earth If we substitute in the measured values for the Sun and Earth: If we set the average emissivity to unity, we calculate the “effective temperature” of the Earth to be: TE = 254.356 K or -18.8 C. Blackbody earth calculations: Insolation: 345 W/m2 Stefan-Boltzmann Constant (S): 5.67 E -8 Equation: R = S T^4 where R is radiation (W/m2) and T is temperature (K) Solving for T, we get: T = (R/S) ^ (1/4) = (345 / 5.67 E-8) ^ (1/4) = 279K = 6°C The Wikipedia article is using the amount of sun after albedo losses, which is about 235 W/m2. That gives the colder value you quote above. But I’m interested in what happens without the albedo (or to be more accurate, without the cloud albedo). Calculating the temperature with only the surface albedo shows the change that is due to the atmosphere with all its components (GHGs, aerosols, clouds, dust, and all the rest). What it shows is that the addition of an atmosphere gives us a TOA radiation of ~ 150 W/m2, and a temperature rise of ~ 20°C. This gives the average climate sensitivity shown above. 63. Dermot O'Logical says: I thought incoming solar radiation was about 1400W/m^2 i.e. the TSI figure. Why is it 342 W/m^2 in the diagram? Or is it a different physical quantity? Thanks Dermot 64. Louis Hissink says: Willis You might have fun adding a graph showing the Earth’s temperature profile up to 500km above surface – it might surprise quite a few that the temperature does not continue dropping the further from Earth but actually rises significantly into the thermosphere. So which temperature would be representative of the Earth’s temperature, and does the temperature at the thermosphere change diurnally etc etc etc. The climate people are waxing thermally over the bottom part of the plot – but presumably remain ignorant of what causes the rest of the profile up to 500 km etc. http://www.windows.ucar.edu/tour/link=/earth/images/profile_jpg_image.html Have fun folks – I am bush till Easter drilling holes in the ground testing scientific hypotheses in situ. 65. John A says: Steve Goddard: My plane flight on Saturday descended 35,000 ft. and temperatures warmed by 150 degrees F as we descended – because of the blanket generated by the atmosphere. But blankets don’t warm by suppressing radiation. 66. I think that in time the Kiehl/Trenberth diagram will be considered an even bigger joke than the Mann hockey stick. Proof The hockey stick had at least a possibility of being correct, if the predictions turned out to true. Its a travesty for him that reality dealt a massive raspberry. The Kiehl/Trenberth diagram is wrong from the start Just two points 1. They seem at great pains to show that the radiation intensity is conserved. There is no such conservation law in Physics. 2. The magnitude of so called back radiation from the trace gasses co2 and water vapour is shown as almost twice the total solar radiation must be physical nonsense. 67. Willis Eschenbach says: Brian W (01:59:09) Science of Doom (23:43:15) “We can measure downward longwave radiation (greater than 4um) at the earth’s surface. It’s not coming from the sun which radiates 99% of its radiation less than 4um.” The sun is a “broadband radiator” it radiates at ALL frequencies. Since everyone likes w/m2 here is some watts for you. Bright sunlight provides an irradiance of just over 1 kilowatt per square meter at sea level. Of this energy, 527 watts is INFRARED light, 445 watts is visible light, and 32 watts is ultraviolet light(wiki). And these are only three tiny bands of frequencies in a much larger spectrum. So good luck with your pseudoscience of doom. You are just another warmist site promulgating calculated nonsense. Brian, there is infrared and there is infrared. ScienceOfDoom points out that 99% of the sun’s radiation is at less than 4um wavelength. While (as you point out) this contains UV, visible, and infrared, it is not infrared in the frequency range of the downwelling longwave “greenhouse” infrared radiation, which is all greater than 4um wavelength. So ScienceOfDoom is correct, they can easily be distinguished. It is also the reason that the infrared from the sun passes through the atmosphere, because the atmosphere is basically transparent to IR in the solar wavelengths, but absorbs in the “greenhouse” wavelengths. Finally, a “warmist” site??? I think that downwelling IR exists because PEOPLE MEASURE IT ALL THE TIME, ALL OVER THE WORLD. That doesn’t make me a “warmist” … it makes me a realist. So I ask again, if you want to argue that downwelling IR doesn’t exist, please do so elsewhere. This is not the site for that discussion. Here, we believe in things that can be measured scientifically, and downwelling IR is one of them. I have neither the time nor the inclination to argue with people who think that things that can be measured don’t exist. 68. Willis Eschenbach says: Dermot O’Logical (02:29:29) I thought incoming solar radiation was about 1400W/m^2 i.e. the TSI figure. Why is it 342 W/m^2 in the diagram? Or is it a different physical quantity? Thanks Dermot Excellent question. If the earth was a flat disk (area of pi R^2), one side of it would receive the 1372 W/m2 from the sun. But the area of the earth is much larger than that. It is 4 pi R^2. So we need to divide the solar radiation by the ratio of the surface areas, which gives us 1372/4 = ~ 345 W/m2. 69. Toho says: Juraj V. (01:42:28) : “More, much colder Earth with (frozen) oceans would turn partially to white snowball and its albedo would be mightily increased.” There can’t be exposed ice if there is no atmosphere. Ice without an atmosphere vaporizes. That is why there is no exposed ice on Mars or the Moon. 70. Cement a friend says: Willis, Another consideration of the energy budget is in figure 2 of http://physicsworld.com/cws/article/print/17402 . You will need to log in to physicsworld.com (IOP website)but it is free. As far as I know has discredited this assessment and the work of Ahilleas Maurellis. In my assessment (from texts books on heat transfer and personal experience and measurement) if there are two molecules of CO2 near each other in the atmosphere and they are at the same temperature there will be no heat transfer them because both molecules will be saturated at the wavelengths of absorption and emission. If the temperature is different, heat flux will be from the higher to the lower temperature and never the reverse. The same thing applies to applies to the earth’s surface which is about 70% water with an emissivity of about 0.95 (almost a black body). If the surface temperature is above that of the atmosphere, which is the case due to due the the lapse rate and radiation from H2O and CO2 heat will only from the surface. In my assessment the water vapor (and water and ice in clouds) and to a minor extent CO2 can be compared to a perforated wide spaced sieve. A large quantity of heat flows straight through while some is absorbed and re-radiated upwards reducing the overall heat flux (or heat flow rate). The heat flux will vary considerable around the globe and at different times of the various cycles which affect the earth. I have no respect for the Kiehl and Trenberth paper. However, I do not dispute (more correctly agree) some of the other points you make such as about evaporation and forced (wind) convective heat transfer. 71. Nylo says: Dermot O’Logical (02:29:29) : “I thought incoming solar radiation was about 1400W/m^2 i.e. the TSI figure. Why is it 342 W/m^2 in the diagram? Or is it a different physical quantity?” 1400W/m2 is what you would get in space, in a surface perpendicular to the incident light. 342W/m2 represents an average in the surface of the Earth between night and day zones as well as the different angles of the incident light wrt the Earth’s surface. That is, if you multiply 342 times the area of the surface of the Earth you would get the total energy we receive from the Sun at any given time. 72. rbateman says: So, Willis, if a station is located where it is naturally near maximum for it’s latitude (due to phsyical geography and circulation), then UHI from any C02 increase will be negligible. Give me a day or so, I am almost done with just such a station. 73. Dermot O'Logical says: Willis Eschenbach (02:51:43) Much obliged. Kind of obvious when you…. think… about…. it. I must learn to do that. But why divide by the _whole_ surface area of the Earth? We are only getting sunlight on half of the surface area i.e. the daylight side. It seems invalid to average the incoming insolation over the whole surface area, as that would imply complete absorption of the energy, then being evenly distributed across the whole surface, _before_ being re-radiated away. Stefans law would suggest the daylight side radiates away significantly more energy that the night side, and that’s non-linear, at T^4. (Please forgive amateur analysis of a physics graduate 20 years out of University – the day job doesn’t require me to keep up to speed with thermodynamics and statistics) Dermot. 74. anna v says: It is not only in the night that the ground temperature is different than the air. I live in Greece, in the summer the ground in sunlight is more than 50C, the air temperature may be anywhere from 38 to 42, not higher. One could fry eggs on the rocks. Searching for ground temperatures, I found one study in Puerto Rico where they measured in the ground in the sun for planting studies, and the temperature 20cm in the ground was the same as the air temperature ( in that particular study 22C). This means that the surface, which is the radiator, would be much higher, as soil is not a good conductor. That is why I think that average SST temperatures would be more realistic, since they are being measured. 75. Willis: Do the models take account of the endothermic photosynthesis process? The vegetation on the earth is cooling the surrounding air because conversion of CO2 and water through photosynthesis is an endothermic reaction. When biomass is burned, liberating CO2 and water again, this energy is released. As CO2 concentration increases the rate of photosynthesis of plants using the C3 photosynthetic pathway (trees, most grasses, most plants) increases much more rapidly than the increase in CO2 concentration. 76. Ronaldo asked: On my comment about downward longwave radiation in the bands of various “greenhouse” gases and outgoing longwave radiation with an equivalent “notch” in it Isn’t this because the absorption of IR at specific wavelengths raises the internal (vibrational) energy of the molecule (of CO2, H2O), which then promptly re-emits energy at the same wavelength but in a random direction, hence the notches in the upwelling radiation? The absorption is an internal process, not a thermal process. It’s both. When a “greenhouse” gas absorbs energy there is the possibility that it will reradiate this same energy in a very short space of time in a random direction. But especially in the troposphere and generally in the first 100km of the atmosphere, the gas in the excited state is rapidly deactivated by collisions and the energy absorbed from the original photon is distributed thermally. This layer of the atmosphere therefore warms up and radiates energy both up and down. This process is the dominant one. 77. dr.bill says: Willis is just “testing the class” by changing horses a little bit with the answers to his pop quiz. Using 342 W/m&sup2; and 14°C, here’s the “point spread”: The 8°C cooler is correct if comparing “now” to a blackbody (albedo = 0), but if comparing “now” to a denuded Earth with its current average surface albedo (≈ 0.16), the 20°C is correct. If we turn the Earth into a “big Moon” (albedo ≈ 0.12), we get 17°C. In any case, it’s nice to have our cosy blanket, and even nicer for it to be so stable. :-) /dr.bill 78. Recipy says: Willis . You are confusing things. Is it deliberate? 1) You do not define which temperature you are talking about. From the 14degC average you’d think it was surface temperature, but then you stumble by looking at TOA fluxes. Try looking at the total non-reflected downwelling fluxes at the surface instead and apply stefan-boltzman to that. In that case you’d get an earth which is ~50 degC warmer than a blackbody. This is reduced to ~33C, if you account for non-radiative heat loss terms accounting for the mixing in the atmosphere (i.e. sensible and latent). 2) Wikipedia says: the surface temperature of Earth as a blackbody would be -19C. That is 33C colder than you 14C with an atmosphere. See T_E calculation here: http://en.wikipedia.org/wiki/Black_body. 79. Brian W said: The sun is a “broadband radiator” it radiates at ALL frequencies. Since everyone likes w/m2 here is some watts for you. Bright sunlight provides an irradiance of just over 1 kilowatt per square meter at sea level. Of this energy, 527 watts is INFRARED light, 445 watts is visible light, and 32 watts is ultraviolet light(wiki). And these are only three tiny bands of frequencies in a much larger spectrum. So good luck with your pseudoscience of doom. You are just another warmist site promulgating calculated nonsense. I don’t expect to convince Brian W. Max Planck was the original promulgator of this “nonsense”. Born 1858, won the Nobel prize for physics in 1918. Many people know his name. He found the equation that described radiation from a body according to its temperature, and the shape of the waveform. You can see the formula here: http://en.wikipedia.org/wiki/Planck's_law – along with typical radiation vs wavelength curves. The energy from the sun, as measured by satellite, amazingly follows this curve. So misguided, that sun.. It’s sad when so little is understood of the absolute basics and yet the passion and the belief is so strong. Of course, Brian W. can win the Nobel prize by showing that Max Planck – and the sun – are wrong. 80. jmrSudbury says: The http://www.worldscinet.com/cgi-bin/details.cgi?id=pii:S021797920904984X&type=html paper disagrees with the idea of back radiation too. The net is not equivalent to 50/50. The atmosphere is not made up of a single atom re-emitting half of what it absorbed back to earth. For air particles that are 1km up, the earth would be about 170 degrees of the field of view. For those that are 10km up, the earth would be something like 80 degrees of the field of view. This is just an example. I made up the numbers, but the fact there is a big difference is what is important. John M Reynolds 81. My quick 2 cents on this is I’m not sure Trenberth’s energy balance is accurate. It ignores readings we get from satellites and thermometers in favor of equations taken from Hansen’s climate model. I’m not going to call Trenberth a quack, as someone else did, but I will say it’s not clear to me that we have the technology needed to build an accurate energy balance model at this time. Which means it’s not clear to me that anything build upon a foundation of our current energy models is accurate. 82. Allen63 says: I seem to remember reading that Earth’s atmosphere causes 33C heat up vs no atmosphere. Sometimes writers say the “greenhouse effect” for earth is 33C. Was 33C wrong? Guess this echos a post just above. 83. wayne says: Willis, I have a question for you. Want to see if this seems real to you. You say they measure the down dwelling LW and I assume you are speaking of 321 W/m2 but I can’t get the math to jive. Using their numbers I always come up with the surface being too hot. If you take all radiation absorbed by the ground, 169 for SW Absorbed By Surface and 321 for LW Back Radiation Absorbed By Surface, you get 490 W/m2. That is the radiation from the sun the chart says you would need to warm the earth to 14 C as if there was no atmosphere at all, right? Take (490/SB)^0.25 = 304.9 K or 89 F for surface temperature according to the chart. Does that seem correct to you? Am I viewing it wrong? To me it seems too hot and the back radiation is way too high. To correct that would recalculate to SB*(14+273.15)^4 – 169 = 216.5 for the LW back radiation absorbed by the surface. That is where I don’t connect right to K&T math. Seems 216 not 321, or 105 Wm-2 too high. Don’t think this would affect your sensitivity logic at all, just the internal numbers. 84. jmrSudbury: Which one are you going with? No “back-radiation” according to the entertaining Gerlich and Tscheuschner or back-radiation but modified by the volume integral? Equally divided up and down is just a useful approximation to explain the basic principles to people who are starting out. Mathematic treatments take this effect into account. The Planck formula for radiance is in units of W/m^2/sr. “sr” is steradians, or solid angle, i.e. the energy is radiated in all directions. 85. Basil says: I’m confused. At the beginning, the answer to the Quiz is said to be (c), 8° C cooler. But latter on, I read “If the earth had no atmosphere and had an average albedo like the present earth of 0.16, it would be about 20°C cooler than it is at present.” And Leif chose (b). So which is it? (b) or (c)? While I don’t see eye to eye with Leif on some things, the “smart money” would bet (b). 86. 1DandyTroll says: Has anyone actually measured the incoming wattage per square meter? 87. [quote anna v (03:24:15) :] Searching for ground temperatures, I found one study in Puerto Rico where they measured in the ground in the sun for planting studies, and the temperature 20cm in the ground was the same as the air temperature ( in that particular study 22C). This means that the surface, which is the radiator, would be much higher, as soil is not a good conductor. That is why I think that average SST temperatures would be more realistic, since they are being measured. [/quote] I’m not sure if this is what you’re looking for, but the ISCCP does produce surface skin temperatures (as opposed to surface air temperatures). Just follow the link below, select “Mean Surface Skin Temperatures” from the “Select a variable:” dropdown, select a time period, and click the “View” button to see a picture. http://isccp.giss.nasa.gov/products/browsesurf1.html 88. magicjava: I’m not sure Trenberth’s energy balance is accurate. It ignores readings we get from satellites and thermometers in favor of equations taken from Hansen’s climate model. Which page on Kiehl and Trenberth’s 1997 paper are you referring to? 89. [quote Allen63 (04:21:29) :] I seem to remember reading that Earth’s atmosphere causes 33C heat up vs no atmosphere. Sometimes writers say the “greenhouse effect” for earth is 33C. Was 33C wrong? [/quote] The “greenhouse effect” isn’t going to be the same as “effect of greenhouse gasses”. The greenhouse effect is always a warming effect. The effect of greenhouse gasses can be warming or cooling. An example of a cooling effect created by greenhouse gasses is water vapor becoming clouds. Overall, clouds cool the Earth by about 20 degrees, even though they’re made from what started out as a greenhouse gas. 90. [quote: scienceofdoom (04:48:54) :] magicjava: I’m not sure Trenberth’s energy balance is accurate. It ignores readings we get from satellites and thermometers in favor of equations taken from Hansen’s climate model. Which page on Kiehl and Trenberth’s 1997 paper are you referring to? [/quote] It’s not the 1997 paper. It’s the updated paper (2005 I believe). The exact quote is: [quote: Trenberth :] The TOA energy imbalance can probably be most accurately determined from climate models and is estimated to be 8.5 +/-0.15 Wm-2 by Hansen, et. al. [/quote] I’d consider any earlier paper to be even less accurate than this one. 91. dr.bill says: Recipy (03:39:01) : Allen63 (04:21:29) : Regarding the 33°C issue: That value comes from using an albedo of ≈ 0.31, which is roughly what you get with the atmosphere, clouds, etc, left intact. In that case, the 342 W/m² available for absorption by the surface becomes 236 W/m² (= 0.69×342), Willis’ values (and mine a little further up the page) are found by elimininating the atmosphere altogether. If you don’t have an atmosphere, you can’t have clouds, and you wouldn’t have such a high albedo, so the comparison is between “everything in place as now” versus “bare planet like the Moon”. You can’t logically use the albedo that one gets with the clouds and such if you don’t have an atmosphere to produce them. /dr.bill 92. What about internal warming due to radioactivity and tidal forces (although, I guess those are mitigated by the fact that the oceans can move in response to the forces)? My understanding is that Lord Kelvin’s thermodynamic calculation of the age of the earth, which was based on a black-body irradiated by the Sun, failed to produce the correct age because he was unaware of the concept of radioactivity. 93. Kay says: @ Bill Parsons (21:03:27) : Wiki Answer to: “What is the temperature on the moon?” The average daytime temperature on the Moon is around 107°C (225°F), but can be as high as 123°C (253°F). When an area rotates out of the sun, the “nighttime” temperature falls to an average of -153°C (-243°F). 253 F -243 F _______ 10 F” ============================= For a range of 496 degrees between the light and dark sides. That’s pretty extreme. What is the range on Earth? Thanks to the atmosphere, its nowhere near close to that. 94. Trenberth is far less certain than he used to be about the energy budget. Remember he said it was a ‘travesty’ that he couldn’t account for the lack of warming in the last decade. One of his recent papers talks about ‘missing energy’ that he simply can’t account for: ‘Tracking Earth’s energy: From El Niño to global warming’ (February 8, 2010, submitted to ‘Science’) http://www.cgd.ucar.edu/cas/Trenberth/trenberth.papers/Tracking%20Energyv5.pdf “Increasing concentrations of carbon dioxide and other greenhouse gases have led to a post-2000 imbalance at the top-of–atmosphere (TOA) of 0.9±0.5 W m-2 that produces “global warming”. Tracking how much extra energy has gone back to space and where this energy has accumulated is possible, with reasonable agreement between model and observational results for 1993 to 2003…Because carbon dioxide concentrations have further increased since 2003 the amount of heat subsequently being accumulated should be even greater.” “…although some heat has gone into the record breaking loss of Arctic sea ice, and some has undoubtedly contributed to unprecedented melting of Greenland and Antarctica, it does not add up to be anywhere near enough to account for the measured TOA energy. Closure of the energy budget over the past 5 years is elusive. Thus state-of-the-art observations are unable to fully account for recent energy variability implying error bars too large to make the products useful.” [“not…anywhere near enough”, “elusive”, “unable to fully account” “too large to make the products useful” etc: read: we’re at a loss to know what’s going on – it’s a travesty.] “After 2000, observations from TOA…referenced to the 2000 values, show an increasing discrepancy…relative to the total warming observed…The quiet sun changes in total solar irradiance reduce the net heating slightly …but a large energy component is missing…” “A large energy component is missing” – you can say that again! The discrepancy is huge and increasing by the year – this is the ‘travesty’ because it is a mysterious component that Trenberth knows nothing about, so for five years he’s been unable to ‘close’ the energy budget. Big problem! The contributions from melting glaciers, ice caps, Greenland, Antarctica and Arctic sea ice plus contributions from land and atmosphere warming and changes in solar irradiance all taken together are completely swamped by the “missing energy” due to an energy flux that is not in any way understood. Of course, it’s only ‘missing’ on the assumption that the greenhouse effect is working as it is alleged to, with positive feedbacks. Lindzen and Choi (though rubbished by Trenberth) showed that, far from positive feedback, there may even be negative feedback – the surface temperature increased AND the escaping IR was increasing just as fast (this is probably Trenberth’s TOA discrepancy, and where the ‘missing energy flux’ is going). This seems to suggest that surface warming through the 1990s was NOT largely due to greenhouse warming, and with increasing CO2 concentration year by year the effect is considerably less than assumed by IPCC. Wind out the positive feedbacks and this ‘missing energy’ component disappears and things start to look sensible again. 95. The label “back- radiation “Is causing needless confusion. I take it to mean that all of the 321w/m2 has come “back” from somewhere. The somewhere must be the atmosphere. This label seems to separate it from all other IR and long wave from scattering and direct to surface by whatever means EM radiation. “No “back-radiation” according to the entertaining Gerlich and Tscheuschner” In fact what G&T say is no HEAT from back radiation which they further state is so small that it can be ignored. Wayne ….If you take all radiation absorbed by the ground, 169 for SW Absorbed By Surface and 321 for LW Back Radiation Absorbed By Surface,……. I agree with Wayne does all the 321 come back from somewhere? This diagram was meant to educate but instead it seems full of obvious ambiguities 96. [quote Kay (05:30:20) :] For a range of 496 degrees between the light and dark sides. That’s pretty extreme. What is the range on Earth? Thanks to the atmosphere, its nowhere near close to that. [/quote] Looking at the raw data for the aqua satellite from the last 13 months, it gives a high of 274.18 K and a low of 197.06 K, for a difference of 77.12 K. Obviously, the Earth’s experienced greater extremes than what it’s seen in the last 13 month, but 77.12 K is a decent enough rough estimate. 97. David L says: “What is the temperature on the moon?” First, remember that heat is the thermal unit of measure that “flows”, not temperature. Temperature is a result of heat content, defined as the average translational kinetic energy of atoms and molecules, and is dependent on the mass and specific heat of the object (such as air). There is less specific heat (and less mass) for a planet with no atmosphere than one with atmosphere. So if the amount of energy were the same for both cases, the temperature would be higher for the planet with no atmosphere. But heat is lost radiatively (black body radiation) and the atmosphere will prevent some of this loss, but itself also radiates it’s heat back to the earth and out to space. Quite a complicated system to figure out exactly as Willis nicely shows in his graphic. There is no atmosphere on the moon, so there’s no air temperature (there’s no air to absorb heat), only surface temperature (the surface absorbs heat). When the sun is hitting the surface, it’s very hot. When the sun isn’t hitting the surface, it’s very cold because, having lost whatever heat it had by radiation. One side is hot, the other cold, and the average works out to be about -10F. This illustrates the problem I have with a single term like average global temperature. Statistically if I put one foot in boiling water and one foot in ice water, the average is luke warm and I should feel fine. Some stations show an increase in temperture, others show a decrease. What’s the average? If North America becomes an ice sheet but Antarctica melts and becomes a jungle, and the average global temperature is still zero, should we be concerned? Is this global climate change? It’s certainly local climate change!!!! Scientists should be focussed on the thermal budget and not a meaningless average global temperature that is dependant on so many other factors. I guess thermometers are cheap and everyone can read them…it’s harder to track the energy. But that’s the core of the problem. Is the earth retaining too much of the solar energy it receives and not allowing the proper balance to radiate back into space? When a climate scientist shows me these fundamental calulations and experiments on the heat budget then I’ll believe we have a problem. In closing, a guy who lived in my neighborhood in 1902 wrote in his diary that yesterday (in 1902) was 58F….Today (2010) the high is 47F……not warmer for you climate scientists keeping score at home. 98. Willis Eschenbach (01:08:38) : On a blackbody earth the current distance from the sun, it would only be 8°C cooler. You are misunderstanding this. There is a difference between a ‘blackbody’ [20C cooler] and a ‘black body’ [8C cooler]. The correct answer to your question as stated is 20C cooler. 99. [quote ScientistForTruth (05:42:08) :] [Quoting Trenberth] “Increasing concentrations of carbon dioxide and other greenhouse gases have led to a post-2000 imbalance at the top-of–atmosphere (TOA) of 0.9±0.5 W m-2 that produces “global warming” [/quote] I’ll just add that the 0.9 Wm-2 Trenberth uses _does not_ come from measurements. It comes from Hansen’s climate model. Actual measurements give a higher or lower number than 0.9, depending on what measurement you use. So, Trenberth is basically saying “Global Warming is 0.9 Wm-2 because Hensen’s climate models say it is so.” 100. David L says: This is an excellent website that explains the fundamental concepts of Physics for those of you new or “rusty” on these concepts. http://hyperphysics.phy-astr.gsu.edu/hbase/hframe.html Click on “Heat and Thermodynamics” for links to those concepts, under that link click on “Radiation” to read about Stefan-Boltzman. 101. Bill Illis says: I think you are right Willis. They have actually calculated the 33K greenhouse effect wrong. The Albedo figure used in the 33K calculation is 0.3 which includes the effects of solar reflection by clouds. But then the calculation excludes the positive greenhouse contribution of those same clouds. You can’t include one without the other. So everything should start over at the beginning and say an atmosphere without any greenhouse gases would be 20K cooler. Put water vapour/clouds back in, and you have -13K from cloud Albedo and something around +17K to +25K from the water vapour/cloud greenhouse effect so you do get something like +16K to +8K greenhouse effect from CO2/non-water vapour GHGs. After that, the Stefan Boltzmann equations are logarithmic so one needs to calculate the K/W/m2 impact at each individual differential rather than take the total temperature K / total forcing change [which is one of the problems with the greenhouse theory – they stop using the differential]. Once you get close to the 390 watts/m2 total forcing, the differential is 0.18K / W/m2. 102. Basil says: “The surface reflects about 29 W/m2 back into space. This means that the surface albedo is about 0.16 (16% of the solar radiation hitting the ground is reflected by the surface back to space). ” Another question. 29/.16 = 181.25. I don’t see ~181 in the diagram. I do see 29+169=198 (168 absorbed, and 29 reflected). Is this CBO scoring, or .gov accounting? I.e. 181 is close enough to 198 for government work? 103. Bill Illis (06:15:41) : I think you are right Willis. I think he is not. 104. Anders L. says: “If the earth had no atmosphere, and if it were a blackbody …” Yes, but it does have an atmosphere, and it most certainly is not a blackbody, so why is this entire exercise relevant? 105. “The Wikipedia article is using the amount of sun after albedo losses, which is about 235 W/m2. That gives the colder value you quote above.” Just a simple question. The wikipedia equations regarding radiating in all directions and receiving only in one direction seem to suggest the calculation assumes the sun is a point source, and the earth a hard disk. In actual fact, the sun has a finite size and slightly more than half the earth’s surface is being irradiated at any time. In addition, the atmosphere itself tends to increase the size of the cross sectional area – which could both increase and decrease the temperature of the earth. Finally, I really wish people would stop reproducing these rubbish static models of the atmosphere. The atmosphere is a dynamic system with convectional currents taking heat from the surface up above otherwise blocking layers. The hysteria about global warming, is essentially a static view of the atmosphere (both in terms of time and space), in contrast I would suggest the sceptic view is a dynamic view whereby the climate not only varies in time, but it doesn’t stick around the surface but in contrast there are dynamic convective currents taking hot air high into the atmosphere where gases with a high emissivity (CO2!) enable the heat to escape. Think about it this way Why does hot air rise to create thermals …. it is because cold air descends! (Ha ha got you!) OK, a bit flippant, but if cold air didn’t descend, then we’d be left with a vacuum at the surface much like the space between Al Gore’s ears. Hot air rises because cold air descends and so we should stop focussing on what is heating the air, and start asking the question: What is cooling the air? Now, the answer is pretty obvious: the heated air is loosing its heat by the emission of IR, and therefore anything that helps to increase the emission of IR … like e.g. a complex molecule with a high IR interaction … what could that be? CO2? helps to cool the planet! That is to say, any molecule able to absorb IR is also (at the same temperatures) able to emit CO2 and so is just as capable of being a global cooler as being a global warmer! The warmists see the atmosphere as a big blanket keeping us warm. In contrast I think the sceptical view should be to see the atmosphere as a huge cooling system taking heat from the surface of the earth up into space. The more CO2, the better the cooling system, and if like the warmists, we were to ignore the other effects of CO2, we also could create a hysteria that adding CO2 will dramatically increase the effectiveness of the world’s cooling system and lead to runaway global cooling. OK, that’s far too simplistic but no less simplistic than the rubbish about CO2 causing runaway warming! 106. David L says: Anders L. (06:43:13) : ““If the earth had no atmosphere, and if it were a blackbody …” Yes, but it does have an atmosphere, and it most certainly is not a blackbody, so why is this entire exercise relevant?” Understanding if the earth is warming due to greenhouse gases has everything to do with the thermodynamics of the system. If you can’t explain the heat gain and the heat loss of this system then you don’t understand the system and shouldn’t be scaring people into doom and gloom scenarios. Consider this, satellites orbiting the earth are in “vacuum” and being irradiated by the sun. Plus they contain electronics that generate heat. Here on earth my Pentium stays cool because air circualtes around it. How do you cool a pentium in a vaccum??? I’ll give you a hint “Black Body Radiation”. You ever see those giant sails on the space station? Some are solar panels, some are cooling radiators. Now if scientists and engineers can use the basic concepts of physics to allow satellites to work in orbit, the Rover drive all over Mars, and the hubble space telescope develop great images, and in every case without freezing or melting down in a vacuum, then those same concepts should be able to explain the temperature on earth and it’s response to solar flux, greenhouse gases, and radiative cooling to name just a few. Comparing the system with an atmosphere and without leads to a basic understanding of the maximum and minimum of the system. In calculus it’s understanding the limits of the equation. This helps in framing what’s going on in the middle. 107. [quote Leif Svalgaard (06:36:25) :] Bill Illis (06:15:41) : I think you are right Willis. I think he is not. [/quote] I think the skeptic community would be well served if we built out own energy balance model, rather than using one based on numbers James Hansen pulled out of his ass, which is all Trenberth’s model is. Starting with data from the CERES satellite would be a good idea, IMHO. Building a model that changes with conditions rather than just giving a hard-coded answer would be a good idea too. And being honest about things we don’t know, like where extra energy is going, would also be a plus. 108. Claude Harvey says: Willis: According to the chart of the past 450,000 years of reconstructed global temperatures for planet earth (the one The Goracle likes to wave about), the last Ice Age saw temperatures of at least 9 to 10 degrees C below today’s. I believe we had an atmosphere back then. I think your “black body” calculation is off by a country mile. I admire much of your work, but suspect you got wrapped around your own axle on this one. 109. Frank Schroeder says: >Leif Svalgaard (05:59:34) : >>Willis Eschenbach (01:08:38) : >>On a blackbody earth the current distance from the sun, it would only be >>8°C cooler. >You are misunderstanding this. There is a difference between a ‘blackbody’ >[20C cooler] and a ‘black body’ [8C cooler]. The correct answer to your >question as stated is 20C cooler. Yes, this distinction is important – as I understand it, a “black” blackbody earth would be 8 degrees colder, whereas a blackbody earth would be 20 degrees colder. However, does this matter for the energy flux diagram and Willis’ conclusions? 110. harrywr2 says: Anders L. (06:43:13) : ““If the earth had no atmosphere, and if it were a blackbody …” Yes, but it does have an atmosphere, and it most certainly is not a blackbody, so why is this entire exercise relevant?” Because it’s a discussion on how sensitive the earths climate is. One set of scientists says that if you modify one little part of the atmosphere there are going to be gigantic changes the climate. I believe Willis is attempting to show if you just completely got rid of the atmosphere altogether the climate wouldn’t change that much. Of course it would be hard to breath and the polar bears would surely die in Willis’s example. 111. Enneagram says: Basil (06:33:41) : This means that the surface albedo is about 0.16 (16% of the solar radiation hitting the ground is reflected by the surface back to space). ” Should we thank the chinese for so kindly lowering that albedo?..with Carbon soot they lower it but with SO2 they increase it. But all this is nonsense as just one humble volcano will surpass any amount of anthropogenic “forcings”. 112. Ryan Stephenson says: Interestingly I don’t see any part of this diagram to account for geothermal heat from underground. Even under the UK (not known for its volcanic activity) the ground at 3000meters depth is about 90Celsius. That underground heat energy must be percolating up to the surface eventually and contributing to the background temperature at sea level. Interestingly, the bottom of the ocean cannot be lower than 4Celsius. If it fell below this it would freeze, and then the ice, being less dense than water, would float to the surface, where it would then melt in the sun. So the deepest ocean trenches cannot be lower than 4Celsius, even though in principle they can be getting almost no energy directly from the sun. Complicated isn’t it? The Moon doesn’t have a lot of geothermal energy or ocean’s that refuse to freeze. It is relatively easy to understand why it gets close to absolute zero at night and above boiling point during the day. Fortunately we are well insulated from such extremes. 113. mkelly says: Why is it that PV=nRT is never considered when figuring a surface temperature of the earth. It is a valid scientific formula. It explains the normal use of STP when saying under what conditions you did your test etc. As such 0 deg C is what the earth with an atmosphere has as a temperature and the 33 deg C warm up from GHG is really only 15 deg. at max. Also if IR goes from 4-60 micro and the band for CO2 is 14-15&16 accounting for any over absorbtion then all CO2 can only get 5.4% of total reradiation. Of that 5.4% human input to CO2 is roughly 3% ergo 3% of 5.4% is .0016. The best that human CO2 can do is .0016 of any longwave radiation. If you use TOA of 247 W/m2 then .4 W/m2 is max for human input. It is probably less than that. 114. Frank Schroeder (07:19:28) : Yes, this distinction is important – as I understand it, a “black” blackbody earth would be 8 degrees colder, whereas a blackbody earth would be 20 degrees colder. However, does this matter for the energy flux diagram and Willis’ conclusions? To be frank, I can’t tell what his conclusions are. 115. David L says: mkelly (07:28:59) : “Why is it that PV=nRT is never considered when figuring a surface ” I don’t believe it applies in any significant way. Gas temperature by this equation changes given a change in volume, moles of gas, or pressure. but it says nothing of surface temperature. In the earth’s atmoshere there is no change of volume (it’s the boundless sky..bounded only by gravity), no change in pressure (except small barometric changes when fronts move around) and there’s really no change in moles of gas (unless you consider the tiny fractional increase in CO2). Plus the ideal gas law only applies in the ideal cases…in this marginal increases in moles of CO2 it wouldn’t be an accurate equation anyhow. 116. Jim says: ****************** David L (07:50:25) : mkelly (07:28:59) : “Why is it that PV=nRT is never considered when figuring a surface ” I don’t believe it applies in any significant way. Gas temperature by this equation changes given a change in volume, moles of gas, or pressure. but it says nothing of surface temperature. In the earth’s atmoshere there is no change of volume (it’s the boundless sky..bounded only by gravity), no change in pressure (except small barometric changes when fronts move around) and there’s really no change in moles of gas (unless you consider the tiny fractional increase in CO2). Plus the ideal gas law only applies in the ideal cases…in this marginal increases in moles of CO2 it wouldn’t be an accurate equation anyhow. ************** Isn’t the ideal gas law used to calculate the adiabatic lapse rate? 117. mkelly says: David L (07:50:25) : Are you saying that the 5.3million giga tons of atmosphere has no effect on the earth’s temperature? If I leave T as an unknown in the formula and use standard pressure for P and figure for a volume up to say 100km I get a temperature of 0 deg C. The term STP means standard temperture and pressure. If it is standard to have 0 deg C at one atm then that should apply to the surface of the earth also. I realize air is not an ideal gas but then again we use radiation formula that were meant for cavities and black bodies with no depth. 118. Is anyone going to consider the second law of thermodynamics and “back radiation” supposedly “warming” the earth’s surface. ? Quite simply anything based off the bunkum IR budgets, is bunkum itself. That is a shame Willis because your recent post(s) regarding thunderstorms (atmospheric heat pipes) is damned excellent, and a great leap forward in our understanding. I particularly have to mention the illuminating “sun’s eye view” you used, brilliant. Excellant posts by Brian W, Ryan Stephenson, David Haseler and David L. to mention only a few. The rest, this place is becoming a warmists site. 119. Richard M says: As a corollary it would be interesting to look at historic situations. For example, when the Earth had no ice caps what was the sensitivity? At the height of glaciation what was the sensitivity? That might put some bounds on the problem. 120. Bill DiPuccio says: “1. The climate models assume that there is a large positive feedback as the earth warms. This feedback has never been demonstrated, only assumed.” I would agree with this statement as it applies to a global scale. But positive water vapor feedbacks do occur on smaller spatial and temporal scales (Dessler, Lindzen, Pielke). The error occurs in trying to generalize these situations to the entire atmosphere. As you point out, all the negative feedbacks come into play canceling or even reversing the potential effect. 121. OceanTwo says: harrywr2 (07:21:49) : Anders L. (06:43:13) : ““If the earth had no atmosphere, and if it were a blackbody …” Yes, but it does have an atmosphere, and it most certainly is not a blackbody, so why is this entire exercise relevant?” Because it’s a discussion on how sensitive the earths climate is. One set of scientists says that if you modify one little part of the atmosphere there are going to be gigantic changes the climate. I believe Willis is attempting to show if you just completely got rid of the atmosphere altogether the climate wouldn’t change that much. Of course it would be hard to breath and the polar bears would surely die in Willis’s example. That’s essentially what I got out of it, also. The actual energy flows in the atmosphere in this case are (mostly) irrelevant. The linearity is irrelevant. It seems we are trying to determine what the (theoretical) temperature of the earth is without an atmosphere. And honestly, even at 20 degrees, it seems like you’d need a radical atmospheric change to significantly alter the atmospheric contribution. (Of course some people claim that the current and predicted CO2 change is a ‘radical’ change). Maybe Willis *does* hate polar bears, who knows? they aren’t particularly friendly creatures, after all. :P 122. Charles Higley says: Tempest in a teapot when you realize that there is not enough carbon out there for us to burn to double the CO2 in the atmosphere. Why? Good question. CO2 partitions 50 to 1 between water and air. It would take 50 times the CO2 that the atmosphere contains to double the CO2 in the atmosphere. One estimate is that, if we really tried, we might be able to raise the CO2 by 20%. We are fighting against a partition coefficient. 123. Alan D McIntire says: The temperature for a blackbody earth should be T = (1368 watts/square meter)/(4* 5.67*10^-8 watts/square meter K^4) gives a temperature of 278.683 K- Willis Eschenbach’s figure. What you’re all arguing about is whether or not you should throw the factor (1 – albedo) into the numerator. If you throw in the clouds, you throw a (1-.3) into the numerator, you decrease the prior figure of 278.683 to 278.683 * (0.7^.25) = 254.909 -blackbody earth without greenhouse gases but with clouds 124. mkelly says: Derek (08:46:04) : No warmist I. For anyone a question. If CO2 can cause an increase in temperature based on reradiation of IR then why are thermos bottles not filled with 100% CO2 instead of using a vacuum? By the IPCC formula of 5.35ln(C/CO) you could get up to 75 W/m2 of extra “heat” going back into your coffee. OUCH! Someone should patent this. 125. Allen63 says: dr.bill, Thanks for the clear response. Choice of albedo it is, then. 126. Alan D McIntire (09:00:18) : The temperature for a blackbody earth should be […] a temperature of 278.683 K- Willis Eschenbach’s figure. No, this is for a black blackbody, but the Earth is not black. It is very nearly a blackbody, but the albedo of the Earth without atmosphere [and clouds] is not zero, it is [as Willis points out] more like 0.15, thus a real Earth with atmosphere removed would be 20C cooler, not 8C. 127. Alan D McIntire (09:00:18) : The temperature for a blackbody earth should be […] a temperature of 278.683 K- Willis Eschenbach’s figure. No, this is for a black blackbody, but the Earth is not black. It is very nearly a blackbody, but the albedo of the Earth without atmosphere [and clouds] is not zero, it is [as Willis points out] more like 0.15, thus a real Earth with atmosphere removed would be 20C cooler, not 8C. 128. Steve Goddard says: Using this logic, Mt. Everest should be only four or five degrees cooler than Saudi Arabia. Another example of the misuse of mathematics. 129. David L (07:50:25) : mkelly (07:28:59) : “Why is it that PV=nRT is never considered when figuring a surface ” I’m afraid mkelly is quite correct. The atmosphere is subject to the Earths Gravitational Field This causes gravitational compression of the gases. High school physics student would be expected to answer question below. Typical HSPQuestion is” using the kinetic theory of gases a/calculate the rms speed of a N2 molecule at STP b/If this molecule moved vertically upward and had no further interactions how high would it get c/ What would happen to the temperature as it went higher” (Answers 517m/s,13.6Km,drops constantly) 130. lgl says: Close enough for the black-body sensitivity which is 0.18 °C per W/m2, but we want to know the ‘climate-body’ sensitivity, and then you have to include the feedbacks. Trenberth’s diagram shows that the system amplifies the external input (sun) by 2.4 so the resulting sensitivity is somewhere around 0.43 °C per W/m2, or 1,6 C per CO2 doubling. This assumes todays gain of 2.4 will not change if the forcing increases, but it probably will, probably not linear. But since a 3.7 W/m2 increase is <1% of the initial, setting a 2.2-2.6 boundary should be safe (+/- 8% of initial) and then the sensitivity range becomes 0.40-0.47 or 1.48-1.73 C per CO2 doubling. calcs: Solar input to surface: 169 + (58+10)/2=203 W/m2 (/2 because only 1/2 downward) Total to surface: 321+169=490 Gain: 490/203=2.41 Black-body sensitivity: (289^4-288^4)*5.678*10^-8=5.45 W/C=0.18 C/W/m2 This holds if we do not reach a Tipping Point, but the good thing is we already reached the cold-to-warm TP 10000 years ago, so the next TP will be a warm-to-cold TP. 131. brent says: Willis, Thanks for your superb efforts and excellent way to get open discussion I’m a little wary should we ourselves draw overly firm conclusions/convictions in the sense of taking the Kiehl/Trenberth graph figures as a given, and then drawing some overly firm conclusions therefrom (All sorts of conjecture is absolutely warranted ) Isn’t this the same Kevin Trenberth referred to below? I.E. Who admits in a private email we are not close to balancing the earths energy budget (and agreed by Tom Wigley) and therefore geoengineering would be hopeless, as we would not be in a position to evaluate it’s effect If so what is the level of confidence in all the various fluxes shown in that diagram in the first place.? It may well be that it’s just that I’ve not taken the time myself to study these particular aspects in depth required to get a personal comfort level The Warmers are absolutely open to highly warranted criticism on multiple levels. I thought your robust :) comments to Judith Curry and Ravetz were spot on. They reflected my views exactly. Just a word of caution (very slight) that we not get ahead ourselves in term conviction/confidence Warm Regards brent http://www.eastangliaemails.com/emails.php?eid=1056&filename=1255550975.txt Kevin, I didn’t mean to offend you. But what you said was “we can’t account for the lack of warming at the moment”. Now you say “we are no where close to knowing where energy is going”. In my eyes these are two different things — the second relates to our level of understanding, and I agree that this is still lacking. Tom. ++++++++++++++++++ Kevin Trenberth wrote: > Hi Tom > How come you do not agree with a statement that says we are no where > close to knowing where energy is going or whether clouds are changing to > make the planet brighter. We are not close to balancing the energy > budget. The fact that we can not account for what is happening in the > climate system makes any consideration of geoengineering quite hopeless > as we will never be able to tell if it is successful or not! It is a > travesty! > Kevin > 132. An argument that is made on the basis of a Kiehl-Trenberth diagram makes me nervous for this type of diagram makes a muddle of thermodynamics. In the language of thermodynamics, there is no such thing as an “energy flow.” The only energy that “flows” is heat. In a Kiehl-Trenberth diagram, some of the “flows” are heat. Others are radiation intensities. It is clear that the “back radiation” is not heat for it “flows” from cold to hot matter; if it were heat, it could not flow in this manner, under the second law of thermodynamics. However, while we have a conservation principle for heat flows, we do not have one for radiation intensities. Thus, the proposition that the K-T diagram portrays some kind of “balance” is false. 133. KDK says: Amazing to see so many using ‘wiki’… LOL What is truly amazing is this: So many of you consider yourself scientists but, as seen in many, if not all posts, is that you cannot agree on actual numbers. I thought sciences, like mathematics, uses numbers that have been accepted by measurements that can be validated. How is it that there are so many theories and only a few datasets to use? How can we almost NEVER agree on an answer? Why so many theories? Can’t someone just factually prove what is being presented… ever? Certainly, I am not saying we shouldn’t continue to push forward as new and enlightening evidence is brought forth via discovery, but, damn, I didn’t know science was so grey… shouldn’t it be either black or white, one or the other? I realize that some of these are just theories and can never be proven, but like AGW, the one’s claiming to KNOW MUST prove it via facts, or it should just be academia speaking for the sake of spurring on innovation/discovery and NOT be presented like it is the end all–unless it truly is. Again, I am not saying that because Joe, Jim, Janet, and Jomojo all say it is fact, that one should stop looking, but let’s find out which measurements are the best, accurate and then all use the same info after analysis. How are there so many theories surrounding supposed fact-based research? 134. Steve Goddard (09:19:41) : Another example of the misuse of mathematics. Nonsense, it is of misuse of the physics. 135. renminbi says: If the earth’s atmosphere were only N2 and O2 would either of these gases absorb or emit radiation from the sun or earth. Sorry to expose my ignorance,but it is better to ask than to remain ignorant. This is a great blog,with great comments. 136. Richard Sharpe says: mkelly (09:08:39) said: Derek (08:46:04) : No warmist I. For anyone a question. If CO2 can cause an increase in temperature based on reradiation of IR then why are thermos bottles not filled with 100% CO2 instead of using a vacuum? By the IPCC formula of 5.35ln(C/CO) you could get up to 75 W/m2 of extra “heat” going back into your coffee. OUCH! Someone should patent this. I don’t think this is a good argument. The devil is in the details. 1. Coffee is normally at a temperature that is outside the frequency range that CO2 efficiently absorbs. 2. Evacuating the thermos shell is to prevent conduction between the inner part of the shell and the outer part of the shell. CO2 will conduct much better than a vacuum. So, it really depends on whether the losses due to conduction are higher or lower than the reduction in losses due to radiation. 137. Willis Eschenbach says: Basil (04:38:24) I’m confused. At the beginning, the answer to the Quiz is said to be (c), 8° C cooler. But latter on, I read “If the earth had no atmosphere and had an average albedo like the present earth of 0.16, it would be about 20°C cooler than it is at present.” And Leif chose (b). So which is it? (b) or (c)? While I don’t see eye to eye with Leif on some things, the “smart money” would bet (b). 8°C if the no-atmosphere earth is considered to be a blackbody. 20°C if the no-atmosphere earth is considered to have present day surface albedo. w. 138. Willis Eschenbach says: Leif Svalgaard (05:59:34) Willis Eschenbach (01:08:38) : On a blackbody earth the current distance from the sun, it would only be 8°C cooler. You are misunderstanding this. There is a difference between a ‘blackbody’ [20C cooler] and a ‘black body’ [8C cooler]. The correct answer to your question as stated is 20C cooler. Leif, forgive me, but I’ve never heard a blackbody referred to as anything but a blackbody. What is the difference you speak of? For a blackbody (which absorbs 100% of the energy that falls on it) the answer is 8°C. I’ve shown my work above. If you disagree, please show yours … 139. Willis Eschenbach (10:09:49) : 8°C if the no-atmosphere earth is considered to be a blackbody. You do not understand what a blackbody is. The 8C is for a black blackbody. The Earth is not black, but is nevertheless very close to a blackbody. Take a white sphere and heat it to 400C, then take a black sphere and heat it to 400C, they both radiate the same amount. If not, we would violate the thermodynamics, where we could get work out of the radiative difference [use it to power a steam engine] between two bodies at the same temperature. 140. Willis Eschenbach says: Basil (06:33:41) “The surface reflects about 29 W/m2 back into space. This means that the surface albedo is about 0.16 (16% of the solar radiation hitting the ground is reflected by the surface back to space). ” Another question. 29/.16 = 181.25. I don’t see ~181 in the diagram. I do see 29+169=198 (168 absorbed, and 29 reflected). Is this CBO scoring, or .gov accounting? I.e. 181 is close enough to 198 for government work? My bad, surface albedo should be 0.15 rather than 0.16. Good catch. Makes no difference to the calculations in any case, which are not intended nor claimed to be more than a first-order estimate. I’ve changed it in the head post. Thanks for checking. 141. Willis Eschenbach says: Anders L. (06:43:13) “If the earth had no atmosphere, and if it were a blackbody …” Yes, but it does have an atmosphere, and it most certainly is not a blackbody, so why is this entire exercise relevant? “Thought experiments” have a long and proud history in science. They are widely used to examine conditions that we cannot replicate in a laboratory. 142. Willis Eschenbach – Do you think you’re up to creating an energy balance diagram from scratch using actual data rather than James Hansen’s climate model the way Trenberth did? Somebody with motivation has to do it and my plate is full at the moment with the Aqua satellite. 143. Willis Eschenbach says: Claude Harvey (07:16:14) Willis: According to the chart of the past 450,000 years of reconstructed global temperatures for planet earth (the one The Goracle likes to wave about), the last Ice Age saw temperatures of at least 9 to 10 degrees C below today’s. I believe we had an atmosphere back then. I think your “black body” calculation is off by a country mile. I admire much of your work, but suspect you got wrapped around your own axle on this one. Lots of people “suspect” I’m wrong about various things … but math beats suspicion every time. Yes, the earth can be colder than it is now and still have an atmosphere. That is something entirely different from what I’m discussing, and is immaterial to my conclusions. If you think my blackbody calculations are off, show us the math. I’ve shown mine … your turn. 144. Willis Eschenbach says: Ryan Stephenson (07:28:41) Interestingly I don’t see any part of this diagram to account for geothermal heat from underground. Even under the UK (not known for its volcanic activity) the ground at 3000meters depth is about 90Celsius. That underground heat energy must be percolating up to the surface eventually and contributing to the background temperature at sea level. Every calculation I’ve either seen or done has put geothermal heat a couple orders of magnitude smaller than the other flows, on the order of a tenth of a Watt per square metre. If you have other numbers, I’d like to see them. 145. Willis Eschenbach says: Leif Svalgaard (07:43:34) Frank Schroeder (07:19:28) : Yes, this distinction is important – as I understand it, a “black” blackbody earth would be 8 degrees colder, whereas a blackbody earth would be 20 degrees colder. However, does this matter for the energy flux diagram and Willis’ conclusions? To be frank, I can’t tell what his conclusions are. Is my writing really that opaque? My conclusion is that the climate sensitivity is on the order of half a degree C per doubling of CO2, and the equilibrium sensitivity is much less than that. 146. Willis Eschenbach says: blackswhitewash.com (07:45:35) Your theory seems to be Swiss cheese on this one Willis. Oh, please. If you have something substantial to say, bring on the math. Otherwise, keep lurking and wait until we see if it is Swiss cheese or not. Are there any substantive claims that I have not disputed? 147. Willis Eschenbach says: mkelly (09:08:39) For anyone a question. If CO2 can cause an increase in temperature based on reradiation of IR then why are thermos bottles not filled with 100% CO2 instead of using a vacuum? By the IPCC formula of 5.35ln(C/CO) you could get up to 75 W/m2 of extra “heat” going back into your coffee. OUCH! Someone should patent this. Please see my post called “The Steel Greenhouse” which answers your question. 148. Willis Eschenbach says: brent (09:34:26) … If so what is the level of confidence in all the various fluxes shown in that [Trenberth] diagram in the first place.? I view them as a first order approximation, which is quite adequate for the purposes of my analysis. 149. [quote Willis Eschenbach (10:35:46) :] Are there any substantive claims that I have not disputed? [/quote] Well, um, yes. Mine. Trenberth’s model uses made up numbers and ignores real life measurements. Using his work to check your results means you’re comparing your results to made up numbers. That’s not a flaw in your line of reasoning, but it is a flaw with what you’re using for a sanity check on your results. Which is why I was wondering if you feel up to the task of creating a more realistic energy balance. One that uses real-world numbers. 150. Willis Eschenbach (10:34:11) : Is my writing really that opaque? My conclusion is that the climate sensitivity is on the order of half a degree C per doubling of CO2, and the equilibrium sensitivity is much less than that. As far as I can see you concluded that based on the 20C figure. You never used the 8C figure for anything, which is good because it is wrong. 151. scienceofdoom (23:02:15) Thanks for the response to brian W. I find your blog a wonderful resource for people get an understanding of things like back radiation. There is enough detail there for those with technical backgrounds and your way of explaining things to those with “not so technical” backgrounds is very good. I often wonder what the blog wars would have been like if reasonable voices like yours had been in charge of real climate. Scienceofdoom: WRT Willis contention. It seems a first good guess that the first order effect of albedo is linear, it’s effectively a TSI knob, but one thing that bothers me about the diagram is what happens to the 29W/sq meter that get reflected from the surface. Shouldnt some portion of that be absorbed by trop and lower strat ( as is the case with that same radition when it is incoming)? And shouldnt some be relected back down by clouds and aerosals? is the 29 a net net net. Let me put it this way. Short wave reflected at the surface has to travel back through the same phyiscal medium it took to get to the earth.. probably should not read too much into the cartoon I suppose. 152. Steve Goddard says: Willis, There is no need for laboratory experiments. The earth itself is the laboratory, with some locations having much less atmosphere than others. Temperatures in the upper elevations of the Himalayas average 40-50C cooler than similar latitudes at lower elevations, because of the lack of atmosphere. Your claim below is simply incorrect. This means that the warming due to the complete atmospheric system (greenhouse gases, clouds, aerosols, latent and sensible heat losses, and all the rest) is about 20°C over no-atmosphere earth albedo conditions. 153. Kevin says: WTF? Environment Canada says that this winter was 4.0°C above average? http://www.msc.ec.gc.ca/ccrm/bulletin/national_e.cfm The national average temperature for the winter 2009/2010 was 4.0°C above normal, based on preliminary data, which makes this the warmest winter on record since nationwide records began in 1948. The previous record was 2005/2006 which was 3.9°C above normal. At 3.2°C below normal, the winter of 1971/1972 remains the coolest. As the mean temperature departures map shows all of the country, but for a small area over the southern Prairies, was above normal, with some areas of the arctic and northern Quebec more than 6°C above normal. Southern Saskatchewan did have a cooler than normal winter, with temperatures more than 1°C below normal. This past spring was the first season in the past 5 years with temperatures below normal, as shown in the consecutive seasons graph. 154. Willis Eschenbach says: Leif Svalgaard (10:20:53) Willis Eschenbach (10:09:49) : 8°C if the no-atmosphere earth is considered to be a blackbody. You do not understand what a blackbody is. The 8C is for a black blackbody. The Earth is not black, but is nevertheless very close to a blackbody. Take a white sphere and heat it to 400C, then take a black sphere and heat it to 400C, they both radiate the same amount. If not, we would violate the thermodynamics, where we could get work out of the radiative difference [use it to power a steam engine] between two bodies at the same temperature. I’ve never heard of a “white blackbody”. I’m using the standard definition of a blackbody. Here’s one, from Mathworld: A hypothetic body that completely absorbs all wavelengths of thermal radiation incident on it. Such bodies do not reflect light, and therefore appear black if their temperatures are low enough so as not to be self-luminous. All blackbodies heated to a given temperature emit thermal radiation with the same spectrum, as required by arguments of classical physics involving thermal equilibrium. Here are the only numbers of interest in my discussion above: Temperature of a body at the distance of the earth from the sun, with an albedo equal to that of the earth: about 20°C cooler than the present earth. TOA radiation from the present earth: about 150 W/m2 Since 150 W/m2 TOA radiation gives a warming of about 20°C, this gives a climate sensitivity of about half a degree for a doubling of CO2. This is only one-sixth of the UN IPCC canonical value of 3°C. I don’t care if I’m off by 10%, this is a first-order analysis. My answer is way below the IPCC answer, that’s the issue, not the exact details. I greatly regret putting up the global energy budget diagram, as people are overlooking the subject of the thread, which is climate sensitivity. I invite everyone to discuss whether this method of calculating climate sensitivity is valid and whether those numbers are correct, and leave downwelling radiation and pV=nRT and “white blackbodies” for another thread. 155. Willis Eschenbach says: Leif Svalgaard (10:42:01) As far as I can see you concluded that based on the 20C figure. You never used the 8C figure for anything, which is good because it is wrong. Leif Svalgaard (10:20:53) You do not understand what a blackbody is. The 8C is for a black blackbody. Can’t have it both ways … the 8C is right for a black blackbody. Since I was not talking about a white blackbody, the 8C figure is not wrong. 156. Willis Eschenbach (10:34:11) : Is my writing really that opaque? The initial quiz was a bit opaque. I would have agreed completely if the premises were ‘no atmosphere and totally black’. The ‘blackbody’ bit is somewhat off, because in the infrared, the Earth is an almost perfect blackbody and that is where it radiates. 157. Willis Eschenbach (10:59:56) : Can’t have it both ways … the 8C is right for a black blackbody. Since I was not talking about a white blackbody, the 8C figure is not wrong. But you were not explicitly talking about a ‘black’ blackbody either so the built-in assumption is that you were talking about a blackbody with an albedo [0.15] as that the surface actually has… But perhaps we have generated enough heat by now without much new light. :-) 158. David L says: mkelly (08:33:01) : David L (07:50:25) : “Are you saying that the 5.3million giga tons of atmosphere has no effect on the earth’s temperature? If I leave T as an unknown in the formula and use standard pressure for P and figure for a volume up to say 100km I get a temperature of 0 deg C. ” Not due to PV=nRT realistically. Are you saying that because there’s pressure and gas molecules and a volume (what’s the volume of the earth’s atmosphere by the way?) then we have a temperature? Turn off the sun, shut down the geothermal heat, and see how long it takes for the atmosphere to become pools of liquid N2 on a frozen ocean. Pressure is not driving temperature here. It’s the other way around. Classic example of mixing up Causation with Correlation. Temperature and Pressure are correlated…but which causes which? If your highschool student compresses air, the compressed air temp changes….but that temperature is soon absorbed by the surroundings. Ever touch a high pressure gas cylinder? How hot is it? It’s room temperature…But it’s under high pressure? how can that be? Now put that tank in the sunlight….guess what…temp goes up AND pressure goes up. So why would the amount of air, the earths atmospheric volume, and pressure have anything to do with global temperatures according to PV=nRT? Look up R….what are the terms? J/K mol. It’s the amount of energy per temperture per mole….it’s all about the energy folks Know the energy flow and you’ll know all the temperatures!!!!!! If you’re not doing work on the system you aren’t moving energy around!! Just having an atmosphere is not doing work!!!! You have to do something to it…like heat it up with sunlight!!!!!! 159. “Take a white sphere and heat it to 400C, then take a black sphere and heat it to 400C, they both radiate the same amount. If not, we would violate the thermodynamics, where we could get work out of the radiative difference [use it to power a steam engine] between two bodies at the same temperature.” This warmist logic! The body with the lower emissivity will radiate less, that is what emissivity means: it radiates less at the same temperature. As for breaking fundamental laws of thermodynamics, if that were true, then thermos flasks and space blankets both break your “fundamental” laws as the low emissivity material prevents irradiation of heat compared to similar “blackbody” materials at the same temperature. 160. Willis Eschenbach says: magicjava (10:25:39) Willis Eschenbach – Do you think you’re up to creating an energy balance diagram from scratch using actual data rather than James Hansen’s climate model the way Trenberth did? Somebody with motivation has to do it and my plate is full at the moment with the Aqua satellite. The balance shown in the head post is my own. Much of it is based on actual data, just as much of Trenberth’s is based on actual data. I used my own simple radiation/convection/evaporation model available here to calculate the values. Unlike Trenberth’s model, however, mine actually works. His cannot work, as it shows different fluxes up and down from the atmosphere, which is not physically possible. For the reasons I lay out in The Steel Greenhouse, a model of the earth’s greenhouse system has to have two physically isolated radiating layers to concentrate enough energy to equal earth conditions. The upper of these is just above the tropopause. These layers must be physically separated from each other, because if there is more than a very small amount of thermal leakage between them, the efficiency of the system drops below that which is required to model the earth. These constraints limit the possible solutions to the problem. I have used my model to fit the known parameters. One of these is the temperature of the TOA, which is on the order of -50C, or on the order of 150 W/m2. So the number I am using to calculate the sensitivity is not supported by my/Trenberth’s model alone. w. 161. mkelly says: Richard Sharpe (10:01:57) : I don’t have “smiley” faces to put at the end of sentences, but you it the nail on the head. It was a rhetorical question. Most of the people on the earth live in areas that get above the temperature of where CO2 radiates. That’s part of the point. If CO2 would not warm up coffee or keep gespacho luke warm how is it able to warm up an entire global. The atmosphere has conduction and convection. Gases dissipate heat. My frozen turkey will warm to room temperature but no more. No amount of CO2 in my house will heat the turkey higher than what the room temperature is. Is there a ratio of convection/conduction by CO2 versus radiation by CO2 when dissipating heat? If I remember my heat transfer class when two discs at different temperatures radiate at each other the lower will rise to the higher then it becomes a push/pull and nothing further happens. So the best that could happen with CO2, is it could rise to the temperature of the earth and then all stops. The pot does not warm the burner. 162. Micky C says: Willis, I think inadvertently you have stumbled upon the key wrong assumption in this whole AGW debacle. The value for Trenberth back radiation is very wrong. In the paper they show the upward radiation from the surface and then from the top of the atmosphere. At the TOA we can see the absorption peaks and how there is a reduction in the spectra. The difference in W/m2 is the difference in the integrals of these curves i.e. what does not come out of the TOA is the difference in the integrals. If those curves are integrated an eyeball estimate is about 10 to 15% difference. If we have 339 going up how can we then have 321 coming back? Secondly using the same curves, and using the measured CO2 15 µm band, which is heavily saturated for the current ppm of CO2. Any increase in ‘the wings’ is 4 orders of magnitude different than the main peak. This puts any decrease in transmissivity of that order of magnitude. Now considering that the difference in back radiation is around 30 to 50 W, how exactly is a doubling of CO2 going to produce 3W/m2 extra forcing. The simple answer is it can’t hence the assumption that water vapour increases; an assumption that as yet has not been tested. 163. Just realised, when I mentioned thermos flasks, I forgot to mention I was referring to the silver coating used to reduce heat loss. 164. anna v says: groundRe: magicjava (Mar 17 04:43), Thanks for the link. One can see the difference between air and skin surface. in the maps. 165. mkelly (09:08:39) For anyone a question. If CO2 can cause an increase in temperature based on reradiation of IR then why are thermos bottles not filled with 100% CO2 instead of using a vacuum? By the IPCC formula of 5.35ln(C/CO) you could get up to 75 W/m2 of extra “heat” going back into your coffee. OUCH! Let’s see if I can explain. Heat is transferred by Convection, Conduction and radiation. See the sun? It’s in a vacuum. There is a lot of nothing around it. So the heat of the sun get here by radiation. Take a metal rod in your hand hold it in a fire. That’s conduction. In a thermos you build a vacuum chamber. You try to get as few as particles in there as possible to prevent conduction. Filling that chamber with anything would defeat the purpose of reducing the heat transfered by CONDUCTION. How do you prevent radiation through this vacuum? Easy, you put a SILVERED LINING on the metal. That shiny metal “blocks” or reflects the IR. It does this much better than C02 does. C02 only “blocks” certain regions of Longwave. When you look at how radiation move through a material you have to look at all the ‘windows’ in the material. . This may help: http://www.crisp.nus.edu.sg/~research/tutorial/atmoseff.htm Then go google radiative transfer equations. 166. Bill Illis says: Technically, if we have now reduced the greenhouse effect/atmospheric pressure impact to 20K, the TOA forcing relative to that figure is not 150 W/m2 anymore – it would only be about 95 W/m2. The equilibrium emission temperature would now be 268K rather than 255K and 95 W/m2 gets you up to the surface temperature of 287K or 14C. So the average over the entire 95 W/m2 would be 0.21K /W/m2. [As I said the first part of the 95 watts would have more impact than the last one which is just 0.18K /W/m2]. Technically, it also wouldn’t be the TOA forcing either but just the 3.1 km high forcing. 167. [quote Willis Eschenbach (10:57:20) :] I greatly regret putting up the global energy budget diagram, as people are overlooking the subject of the thread, which is climate sensitivity. [/quote. My apologies for being one of those people. When I see Trenberth’s diagram, it just sets off a giant red flag for me. There are so many topics covered in the post that it’s difficult for me to find the core substance of it all. I _think_ the point to the entire thing is: [quote Willis Eschenbach: This means that as the temperature rises, each additional W/m2 added to the system will result in a smaller and smaller temperature increase. [/quote] … but that was saved until the next-to-last sentence. Also, you’re tossing around a lot of unsubstantiated claims. Examples include almost everything you say about the IPCC. For example, does the IPCC really calculate the effects of Evaporation incorrectly? And no one ever noticed this? With all the things coming out about the IPCC lately, this may very well be the case, but statements like this need some supporting evidence. The use of 20°/8° is also very confusing to me. It’s not clear when one or the other applies to what you’re saying. I’d suggest stripping out as many non-essential points as possible, so folks like me don’t get tripped up over Trenbreth, and folks like Lief don’t nit-pick you to death on black blackbody and white blackbody stuff. If your main point is the increase in temperature due to increase in W/m-2 is logarithmic, start with that and make it clear. 168. Willis Eschenbach (10:35:46) : Are there any substantive claims that I have not disputed? Derek says – Well, yes actually, for instance see the below. AND my own post elsewhere. http://www.globalwarmingskeptics.info/forums/thread-609.html Terry Oldberg (09:44:22) : In the language of thermodynamics, there is no such thing as an “energy flow.” The only energy that “flows” is heat. In a Kiehl-Trenberth diagram, some of the “flows” are heat. Others are radiation intensities. It is clear that the “back radiation” is not heat for it “flows” from cold to hot matter; if it were heat, it could not flow in this manner, under the second law of thermodynamics. However, while we have a conservation principle for heat flows, we do not have one for radiation intensities. Thus, the proposition that the K-T diagram portrays some kind of “balance” is false. 169. Frank says: John A wrote (21:46:51): How of the incoming energy from the Sun is converted into atmospheric and oceanic convection? None, according to Kielh and Trenberth. Which is amazing. Climate physics is a fascinating subject. What causes atmospheric and oceanic convection to slow down (the only reason solar energy would be needed to keep them going)? Friction. Where does the energy consumed in overcoming friction appear? As heat. Physics is a fascinating subject. 170. magicjava I’m not sure Trenberth’s energy balance is accurate. It ignores readings we get from satellites and thermometers in favor of equations taken from Hansen’s climate model. And in response to my question.. It’s not the 1997 paper. It’s the updated paper (2005 I believe). The exact quote is: [quote: Trenberth :] The TOA energy imbalance can probably be most accurately determined from climate models and is estimated to be 8.5 +/-0.15 Wm-2 by Hansen, et. al. [/quote] I’d consider any earlier paper to be even less accurate than this one. The updated paper is 2008. In fact, Kiehl and Trenberth don’t throw out any measurements in favor of climate models. In the 1997 paper they assume that incoming and outgoing energy balances. Why? Because the instrument error means the measurement results are not accurate enough to be able to say whether energy in = energy out. In a non-warming and non-cooling world this would be true. And there is a small challenge of whether the measurements of solar energy in is more accurate than the measurement of terrestrial energy leaving and reflected solar energy. So there is an uncertainty around 5-10W/m^2. In the updated 2008 paper, being good scientists they attempt to provide better numbers all around. In the case of the instrument error, there are still the same unknowns. So rather than fix energy in=energy out, they say, “well, the earth is warming up, how much by?”. Anyhow, for those for whom the word “model” causes outrage.. look at the statement which was inaccurately quoted: The TOA energy imbalance can probably be most accurately determined from climate models and is estimated to be 0.85±0.15 W m-2 by Hansen et al. (2005) and is supported by estimated recent changes in ocean heat content (Willis et al. 2004; Hansen et al. 2005). As you can see -first the number is pretty small, and second, the calculation is supported by the measurement of the increase in ocean heat (as you can see in The Real Measure of Global Warming ). 1W/m^2 out of 240W/m^2 – and you want to throw out the results? For anyone wanting to learn a little about climate basics, read the whole original 1997 paper. 171. Frank says: Willis: Technically speaking, climate sensitivity is the partial derivative of temperature with respect to energy (probably both incoming energy from the sun and energy radiated downwards by the atmosphere and clouds). Your post may be assuming that temperature is a linear function with respect to incoming energy. The relationship between T and W is certainly a very complicated one if conditions are dramatically different from today – a snowball earth or even an ice-age where the relative proportions of land and ocean change. For small changes in W and T, the relative is approximately linear and climate sensitivity can be treated as a constant. The IPCC also worries about the time-scale associated with estimates of climate sensitivity. For a given dW, how long does it take for T to come to equilibrium? Does equilibrium include changes in the deep oceans and ice-caps? For models with the highest climate sensitivity, equilibrium of the atmosphere and upper ocean apparently requires decades. 172. Joel Shore says: Willis: I am confused as to where you have gotten the 150 W/m^2 figure that you quote. I also think, in line with what scienceofdoom said, that what you have essentially calculated here is not the climate sensitivity but the sensitivity in the absence of feedbacks. In particular, what you have to recognize is that the distinction between forcings and feedbacks is somewhat arbitrary. For example, CO2 change is, in some sense, a feedback in the glacial – interglacial cycles but is a forcing in our current predicament. The thing is that you have to be consistent. What you have done is not consistent because you have presumably counted everything, e.g., including the water vapor, as a forcing in getting that 150 W/m^2 figure but then you have not counted any change in water vapor as a forcing in computing the resulting climate sensitivity. Another way of putting it is this: If the warming due to the change in CO2 causes additional water vapor to go into the atmosphere, this water vapor will produce an additional radiative forcing…and if the additional warming causes ice melt that changes the earth’s surface albedo, this will also produce an additional radiative forcing. (And, the change in clouds would also produce an additional radiative forcing whose magnitude, and even admittingly, sign are uncertain.) Now, we usually call all of these things feedbacks instead of forcings and that is fine if we do so consistently. The problem is that I don’t think you have done so consistently…i.e., as near as I can tell, your “150 W/m^2” (which I don’t really understand anyway) counts everything as a forcing, not a feedback. By the way, Jim Hansen has made a similar point recently about being consistent with what you call a feedback and a forcing…And, in fact, he has argued that what he calls the Charney sensitivity derived from the glacial – interglacial cycles considers changes in albedo due to changes in ice sheets as a forcing whereas any such changes in our current discussions are considered to be a feedback. Hence, he argues that the 3 C climate sensitivity for doubling CO2 is probably too small for our current “experiment”…and says it is more like 6 C when you properly consider the effects of the albedo changes due to changes in ice sheets. (Others question whether the ice sheet albedo effects would really be that large in our current climate and also how fast the ice sheet changes can occur…so, I am not saying his 6 C estimate is correct, but I think that his basic point about being careful what you consider to be forcings and feedbacks is.) 173. mkelly says: steven mosher (11:39:03) : Steve I guess you missed reading the part about patenting the idea. It was a rhetorical question. I cannot put smiley face at the end of the sentences. However, it is possible to construct an idealized thermos floating in space, with an inside chamber transparent to IR but infinite R value, and an outside surface that blocks incoming radiation whose inside surface is a perfect reflector of IR. So no conduction no convection only IR from the soup, coffee whatever to the next chamber. Fill the space where the vacuum would normally be with CO2. The IPCC formula makes no difference as to anything except the forcing of the log of (C/CO). So with that in mind using the IPCC 5.35ln(C/CO) we get ln 1000000 is 13.81 times 5.35 for 73.91 W/m2. According to IPCC whatever you have in the thermos will heat by 74 W/m2 indefinitly to vaporization and explosion. Please don’t miss the point Steve I don’t think CO2 can do what is claimed and none of the information I have read demonstrates via physics, math, chemisty etc or whatever, over turns my understanding of the laws of thermodymanics, heat transfer etc. My ultimate point is that if CO2 could increase heat energy through radiation then someone somewhere would have found a way to make money off the idea. But as of yet nothing even though we are told this has been know for a 100 years. Hog wash. 174. OceanTwo says: Honestly, I can’t find anything about a ‘colored’ black body. A Black body is a black body (or blackbody if you are so inclined). Either way, anything which as an emissivity (not equal to 1) is not a black body. Unless there’s something changed in the last 20 years. Maybe: they are teaching all sorts of funky stuff these days (perhaps an object with a specific emissivity is classified as a specific ‘black body’ color? ). Even so, it’s an irrelevant argument: as I understand it, based on what had been demonstrated, if earth was a black body it [surface] would be 8 degrees cooler; as it has an emissivity, it is theorized to be 20 degrees cooler than what we measure today. It seems like the prosecution is stating that the perpetrator accelerated from a stand still to 100mph when they breezed through the red light. The defense [Willis] is arguing that it’s only 50 yards from where the perpetrator started to the red light, so how can they be going 100 mph? Weather it’s 50 yards, or 60, or 20, or 70.235 is quite irrelevant; or what the shade of the red light is, or even the decimal accuracy of the radar gun used for measurement. Does the theory hold? Are the results of Willis calculation so far off ? Is the principle employed sound? If not, why not? Can it be demonstrated that his theory is false? Are there any significant factors not accounted for? In other words… 175. OceanTwo (12:58:04) : if earth was a black body it [surface] would be 8 degrees cooler; as it has an emissivity, it is theorized to be 20 degrees cooler than what we measure today. albedo, perhaps, rather than emissivity. The 8C was not really used by Willis for anything, so it is perhaps not worth harping too much on it. There is also a possible confusion because you can talk of blackbody radiation as that which has a blackbody spectrum without the body be required to be black [the Sun is not black, for example]. More confusion comes from the statement: “That is to say, the net gain from our entire complete system, including clouds, surface albedo, etc..” where the clouds and surface albedo are not gains but deficits. Anyway, I may just have been too pedantic about this, but I was disappointed that the lead paragraphs were on something not actually used further on. The important things was the 20C difference. 176. wayne says: Willis: Re: wayne (04:27:21) : I may have answered my own question to you. Seems the 105 W/m2 might very well come from the 22 for Sensible Heat and 76 for Latent Heat. Those total 98, close but not exact to the 105. Seems the K/T chart is organized in a confusing manner. Their fault, not yours. It should have been broken in three sections. The Input, the internal flows, and the output. That would tie the back radiation to the back radiation mathematically. On the left, the SW radiation from the sun, the input, and it is pretty clear, then a dashed light gray vertical division. Next is the internal energy flows. That is the atmosphere, clouds, the two upper pointing heats, sensible and latent, and the down dwelling back radiation on the far right. Then another vertical dashed light gray line. What remains on the far right is the output section. That is all of the up dwelling radiation that gathers from the ground and from the center internal section. That would de-mystify it a bit, mathematically anyway. Willis, somewhat OT: Some of your graphs are coming out vary fuzzy on this end. If you are getting these via screen captures, this might help. It works on xp anyway. Before capturing, turn the screen font edge smoothing off. On xp it’s standard or ClearType. Capture the picture then turn the smoothing back on. It does wonders on my machine, no more fuzziness! You get am exact pixel for pixel copy. 177. Anders L. says: Willis Eschenbach (10:25:22) : Anders L. (06:43:13) “If the earth had no atmosphere, and if it were a blackbody …” Yes, but it does have an atmosphere, and it most certainly is not a blackbody, so why is this entire exercise relevant? “Thought experiments” have a long and proud history in science. They are widely used to examine conditions that we cannot replicate in a laboratory. I agree wholeheartedly, but I am not convinced that anything meaningful about the detailed properties of our climate system can be inferred by thinking about a planet completely devoid of a climate system. 178. [quote scienceofdoom (12:30:53) :] In fact, Kiehl and Trenberth don’t throw out any measurements in favor of climate models. [/quote] They do, readings that are more than 6 times higher than their estimate of 0.9. The CERES satellite shows an imbalance of 6.4 W/m-2. It’s right there in the paper. The sentence before the one I quoted. So is the reason why they threw it out: because it’s not expected by their models. And yes, I think Trenberth’s model needs to be redone. I’ve given reasons why on this thread. Willis Eschenbach has given reasons why he believes the model can’t even work. In a nutshell, we need to start looking at reality rather than models. Anyway, Willis has stated that Trenberth’s energy budget is not central to what he was trying to say, so I don’t want to clog up this thread with debates over it. If you’d like to respond to what I’ve posted here, I’ll let you have the last word on the matter. 179. DavidB says: Just curious (really) about one point. If the average temperature of the moon in sunlight is about 225F, how come the average temp of the earth in sunlight is so much lower? As far as I can see from the energy budget diagram, about half of the incoming radiation is either reflected by the atmosphere or the earth’s surface itself, or absorbed by the atmosphere on the way in (and some of the latter would be radiated down to the surface). So it seems that we should expect the average surface temp of the earth in sunlight to be not less than about 110F, i.e. about half that of the moon. True, this is reached or exceeded in the middle of the Sahara or Death Valley, but it seems very high for a global average. Am I wrong about this, or is there something wrong in my reasoning? 180. DavidB says: ….maybe cooling by evaporation of water accounts for the apparent shortfall? 181. Richard Sharpe says: steven mosher (11:39:03) said: In a thermos you build a vacuum chamber. You try to get as few as particles in there as possible to prevent conduction. Filling that chamber with anything would defeat the purpose of reducing the heat transfered by CONDUCTION. How do you prevent radiation through this vacuum? Easy, you put a SILVERED LINING on the metal. That shiny metal “blocks” or reflects the IR. It does this much better than C02 does. C02 only “blocks” certain regions of Longwave. Ahhh, that’s a much better explanation than I managed to produce. I forgot about the silver coating on the inside side of the outer sleeve … and yes, almost complete reflection is much better than 50% reflection. Looks like I didn’t get my invite from CTM. Was hoping to meet you. 182. Joel Shore says: mkelly says: However, it is possible to construct an idealized thermos floating in space, with an inside chamber transparent to IR but infinite R value, and an outside surface that blocks incoming radiation whose inside surface is a perfect reflector of IR. So no conduction no convection only IR from the soup, coffee whatever to the next chamber. Fill the space where the vacuum would normally be with CO2. The IPCC formula makes no difference as to anything except the forcing of the log of (C/CO). So with that in mind using the IPCC 5.35ln(C/CO) we get ln 1000000 is 13.81 times 5.35 for 73.91 W/m2. According to IPCC whatever you have in the thermos will heat by 74 W/m2 indefinitly to vaporization and explosion. There’s an awful lot of confusion in these couple of paragraphs but I’ll try to point out some of the major problems: (1) In fact, if you postulate a system where incoming radiation gets in and (at least some of it) gets absorbed but any outgoing radiation cannot escape then indeed that system will keep heating up indefinitely. That’s what energy balance (essentially the 1st Law of Thermodynamics) says it has to do! (2) In reality, in the case that you described, the system could never get hotter than the surface of the sun because, as the temperature rises, its emission of radiation will shift toward the shorter wavelengths and eventually it won’t be emitting mainly in the IR but rather in the visible where, by the assumptions of the problem (e.g, such radiation is able to get into the system), the radiation is able to escape. (3) The IPCC formula is not a magical formula that holds for any container with a concentration of CO2 in it. It is a formula obtained from detailed line-by-line radiative (or even radiative-convective) transfer calculations in the actual earth’s atmosphere. Among other things, the actual temperature profile of the atmosphere with height and the other IR-active constituents like water vapor play an important role. See here for further discussion: http://www.aip.org/history/climate/simple.htm#L_0623 183. daniel says: I have one question regarding the Kiehl/Trenbeth radiation budget scheme : I have the understanding that since some quite extraordinary papers Gerlich & Treuschchner (1989), Robitaille, etc. this kind of ‘budget’ was heavily falsified for basic physics reasons ? I’m wondering whether these papers had eventually to face rebuttals in peer reviewed papers… Ar this stage I’m not aware of any, and would just conclude that they represent the current stage of physics, which mean that next IPCC report’s science basis would be interesting to draft 184. Joel Shore says: DavidB says: Just curious (really) about one point. If the average temperature of the moon in sunlight is about 225F, how come the average temp of the earth in sunlight is so much lower? It is the global radiation in and out that half to balance, not the local one. The heat transport in the earth’s atmosphere and the thermal inertia relative to the diurnal variation means that the earth’s temperature goes through less extreme ranges. If the earth rotated much slower and/or if there was less thermal inertia (e.g., not so much ocean) and/or if there was less convective processes in the atmosphere to mix things then there would be more extreme temperature ranges. 185. It's always Marcia, Marcia says: Roy Spencer on clouds and negative feedback. May be evidence for Lindzens’ Ifrared Iris Part 1 186. It's always Marcia, Marcia says: Part 2 187. Brian G Valentine says: Thank you, Willis, this is interesting. It’s a common calculation in the senior-level course of radiation heat transfer to show the Earth’s radiation exchange temperature with the Sun is (about) 280K, then the extra 8K are observed from satellites In other words, isn’t this pretty common knowledge to people with a BS in mechanical engineering etc? 188. Brian P says: Willis A bit old but I really liked your thunderstorm post from some months ago 189. DavidB says: To Joel Shore: Thanks. Those are good points. The influence of the oceans as a heat store is probably the key factor. In the interior of the continents there is a much larger diurnal range than over or near the oceans, and even there convection currents must carry the extremes of daytime heat away from the surface. I’m just a curious newbie to these subjects, so please forgive my errors and oversights. 190. Alan D McIntire says: You’ve also got to adjust for emissivity. The earth’s albedo would be maybe 0.15 without clouds, but it would also would not emit as a black body- what would the emissivity be? I’ve read estimates that the oceans’ emissivity is about 0.94, what would it be for land only, about 0.9? in that case, you’d figure in a correction of ( 1 – 085/.9)^0.25 191. DocMartyn says: ‘David L (07:50:25) : mkelly (07:28:59) : “Why is it that PV=nRT is never considered when figuring a surface ” I don’t believe it applies in any significant way. Gas temperature by this equation changes given a change in volume, moles of gas, or pressure. but it says nothing of surface temperature.’ One liter of liquid water contains 55.56 moles of water molecules and occupies 1000 mls or one litre. At STP, as a gas, this would generate a volume of 1244.544 liters; giving a ratio of 1,244.544:1. The globally-averaged annual precipitation is 990 millimetres (39 in), or 0.27 mls/cm2 per day; so that during the day/night cycle, on average, each cm2 of the planet generates and then collapses one third of a liter of volume, or an ingot 336 cm or 3.36 meters. 192. Colin Davidson says: I think Willis’s estimate makes sense on other grounds. Using the diagram the atmosphere receives its energy primarily from the Surface. If you look at the Surface energy flux balance, you get a sensitivity between 0.095 and 0.15 DegC/W/m^2, depending on what assumption is made on evaporation. (This number makes no allowance for “feedbacks” eg greater back-radiation due to increased CO2 and water vapour concentrations, or lesser solar radiation absorbed into the surface due to increased cloud cover. However it is interesting that if the surface temperature rises by the median IPCC estimate of 3 DegC for a doubling of CO2, the 3.7W/m^2 “radiative forcing” at the top of the atmosphere would necessarily need to be a huge “surface forcing” of between 22 and 32 W/m^2 at the surface. ) The usual IPCC calculations, without feedbacks, use a TOA sensitivity of around 0.3. This is then assumed to apply throughout the troposphere, right down to ground level. But that sensitivity is between twice and thrice the surface sensitivity, and I reckon that the assumption that the temperature change at TOA translates to the same temperature change at the surface cannot be sustained without invoking magic, or unless the sensitivities are in fact similar. Willis’s calculation brings the TOA sensitivity in line with the surface. 193. Alex Heyworth says: magicjava (07:06:00) : [quote] I think the skeptic community would be well served if we built out own energy balance model, rather than using one based on numbers James Hansen pulled out of his ass, which is all Trenberth’s model is. Starting with data from the CERES satellite would be a good idea, IMHO. Building a model that changes with conditions rather than just giving a hard-coded answer would be a good idea too. And being honest about things we don’t know, like where extra energy is going, would also be a plus. [/quote] You mean something like this? http://www.palisad.com/co2/eb/eb.html 194. Alan D McIntire says: Sorry, that should be a correction factor of roughly (albedo/emissivity) ^0.25 = (.85/,9)^.25 times the original temperature. Another point, Using Trenbeth ballpark figures, if we get 240 watts from the sun, and the greenhouse effect makes that an effective 390 watts and a 33 C increase, isn’t the increase in temperature per delta watt increase in the ballpark of 33 C/(390-240) = about 0.22C per watt increase? A thrid point using Trenbeth ballpark figures. The surface flux is about 490 rather than 390 watts, with 100 watts going into conduction and convection rather than sensible heat. Figuring that half of that is radiated to space, half back to earth, about half of 100 watts or 50 watts is removed from sensible heat by convection and conduction. 50 watts latent heat + 150 watt sensible heat implies that 25% of any past wattage increase has gone into latent heat. Shouldn’t that apply to the 3.8 watt increase for a doubling of CO2? Shouldn’t at least 0.95 watts go into latent heat, only 2.85 watts or less go into sensible heat? A fourth point, since emissivity is less than 1, assuming it’s about 0.9, isn’t the actual greenhouse effect something like 100 latent+ 150*.9 = 135 watts sensible heat? 195. Brian G Valentine says: On a “small” climate sensitivity: Estimates from Lindzen, Shaviv, Monckton, Schwarz, others, put the value BELOW what is known to be “natural” variability – partly stochastic, partly determinate. My question is: if there is no way to observe a physical quantity, does it have meaning at all? I can construct a thousand quantities that I can calculate in some way (e.g, change in Earth’s rotational angular momentum from buildings, transportation, etc) but the construct is entirely meaningless because there is no way to physically measure it 196. cba says: Willis, there are some significant problems with the albedo numbers. If you go by K&T, it would seem the 0.3 total albedo is 0.22 for clouds and 0.08 for surface with about 0.62 cloud cover fraction. In essence, the 0.08 is the average albedo where there are no clouds present. Your number of 0.15 would be fairly reasonable based upon the Moon and Mars. It is not reasonable for Earth as over 70% of the surface is covered by oceans and the oceans have less than 0.04 albedo for incoming solar radiation, at least for high angles of incidence (wrt horizon where the incoming flux is most significant). Try these numbers: surface (ocean – use 0.7 ocean fraction) 0.04 surface( land) 0.19 (includes snow cover, forests, sand etc) average surface albedo 0.085 (corresponds to 29/342 on chart ) the land albedo is calculated from the 0.085 total surface and the 0.04 ocean. clouds (62% cover, averaged value) 0.36 this corresponds to the assumption of 0.22 for cloud albedo and fractional contribution. NOTE that these numbers do not add up. The weighted average for 0.62 cloud cover leaves 0.38 surface contribution. Using the 0.085 overall surface albedo and fraction visible, one gets 0.38*0.085 = 0.032 contribution to the overall albedo which conflicts with the chart. Since the overall albedo listed is 0.307, the cloud contribution would actually be 0.307 – 0.032 = 0.275 at a 0.62 fractional cover. That puts the cloud albedo at 0.275/0.62 = 0.44 Note that this leaves the clouds with what would seem a more realistic albedo value than the original 0.38 albedo value. Your question of temperature drop really depends upon the conditions. if the surface is stripped of ocean and ice and vegetation, then it’s going to have an albedo of around 0.17 or 0.15. That’s around 265K or -8 deg C or 22 C less (20 C less if 0.15). If the surface stayed the same, the drop would be 15 deg C. If the cloud albedo somehow stayed along with the surface albedo so that the total was 0.307 the temperature drop would be 34 deg. lower. 197. Joel Shore says: daniel says: I have one question regarding the Kiehl/Trenbeth radiation budget scheme : I have the understanding that since some quite extraordinary papers Gerlich & Treuschchner (1989), Robitaille, etc. this kind of ‘budget’ was heavily falsified for basic physics reasons ? I’m wondering whether these papers had eventually to face rebuttals in peer reviewed papers… That Gerlich & Treuschchner saw the light of day in even a second-rate physics journal is extremely embarrassing, as its fundamental error regarding the 2nd Law of Thermodynamics is basic enough that one could lead a group of bright first-year physics students through the logic. (And, some of its other arguments are just plain bizarre.) A comment on G&T that I am a party to and that will essentially trash it completely has been accepted by the journal and should appear within the next few months. 198. Brian G Valentine says: Thank you, Mister Troll Shore, for your erudite analysis of Gerlich and Tscheuschner’s paper, whether you believe it or not, the analysis is correct, and if you think Phys B is second rate, don’t look at it, read some first rate stuff like “Scientific American” instead, the favored bedtime reading material of the first-rate watermelon 199. Willis Eschenbach says: Joel Shore (17:26:23) : edit daniel says: I have one question regarding the Kiehl/Trenbeth radiation budget scheme : I have the understanding that since some quite extraordinary papers Gerlich & Treuschchner (1989), Robitaille, etc. this kind of ‘budget’ was heavily falsified for basic physics reasons ? I’m wondering whether these papers had eventually to face rebuttals in peer reviewed papers… That Gerlich & Treuschchner saw the light of day in even a second-rate physics journal is extremely embarrassing, as its fundamental error regarding the 2nd Law of Thermodynamics is basic enough that one could lead a group of bright first-year physics students through the logic. (And, some of its other arguments are just plain bizarre.) A comment on G&T that I am a party to and that will essentially trash it completely has been accepted by the journal and should appear within the next few months. Dang, here I am agreeing with Joel again … will wonders never cease? G&T is bad, bad, bad. w. 200. Joel Shore says: Alan DMcIntyre says: Shouldn’t that apply to the 3.8 watt increase for a doubling of CO2? Shouldn’t at least 0.95 watts go into latent heat, only 2.85 watts or less go into sensible heat? Well, the issue of latent heat is really one of distribution of the temperature change with height in the atmosphere since what evaporates at the surface has to condense higher in the atmosphere, and this in turn can affect the radiative balance since most of the emission back out into space escapes from the upper troposphere. But, now the punchline: What you are describing is, I believe, just another way of talking about the (negative) lapse rate feedback, i.e., the notion that because of the condensation of water vapor, the upper troposphere tends to warm faster than the surface. This is a feedback that is already included in all the climate models…and, in fact, because much of the physics governing this feedback also governs the (positive) water vapor feedback, models that have a higher magnitude for the water vapor feedback tend to have a higher magnitude for the lapse rate feedback…and hence the sum of these two feedbacks tends to vary less from model-to-model than each of them individually. 201. Willis Eschenbach (17:36:52) : G&T is bad, bad, bad. I’ll agree with that. 202. Joel Shore says: Willis says: Dang, here I am agreeing with Joel again … will wonders never cease? Watch out…It could be addicting! ;-) 203. Francisco says: yan Stephenson (07:28:41) : Interestingly I don’t see any part of this diagram to account for geothermal heat from underground. Even under the UK (not known for its volcanic activity) the ground at 3000meters depth is about 90Celsius. —————– Geothermal is supposed to play its biggest role in warming the bottom of the oceans, as the crust under the ocean floor is much thinner than under most land. The amounts of geothermal energy and its variations and distributions are largely unknown. Considering how close it is from us, it’s amazing how little we really know about what is going on at the earth’s core. Some interesting new theories are emerging: http://tinyurl.com/y8pguwr Beginning in 1969, astronomers discovered that three of the giant planets, Jupiter, Saturn, and Neptune, each radiate about twice as much energy as they receive from the Sun. Those planets each contain a powerful energy source which was inexplicable until J. Marvin Herndon, pictured at left, demonstrated in 1992 the feasibility of natural, nuclear fission reactors as the energy source for those planets http://tinyurl.com/y8pguwr 204. Harry Lu says: Leif Svalgaard (13:23:50) : A questions perhaps you could answer please? Albedo refers to reflectivity. The normally referred albedo is to the visible light reflectance. But surely the reflectance in the LW IR will be different. Is this known? Emissivity of a surface is not he same as albedo. Having used an IR camera a few times I know that the IR temperature of an object changes with emissivity. and corrections can be incorporated in the IR to temp conversion (this is why Mr Watts IR photos in his surface station project are not very valid – he need to correct for surface emissivity.) When using IR cameras one usually coats the objects with a thin layer of mat paint to equalise (approx) emissivity. Surely albedo controls the absorbed solar radiation, but emissivity controls the radiated LW energy. If so then one needs to know the emissivity of the earth in the 4u range not its albedo. /harry 205. Leif Svalgaard (10:20:53) : You do not understand what a blackbody is. … Take a white sphere and heat it to 400C, then take a black sphere and heat it to 400C, they both radiate … “Surface emissivity” must be considered; both may not have equal emissivity figures … which will affect radiation. Emissivity Coefficients of some common Materials Examples, emissivity: Aluminum Foil – 0.04 Beryllium —- 0.18 Granite —– 0.45 Sand —- 0.76 Wrought Iron – 0.94 Plaster —– 0.98 . . 206. Francisco (17:52:28) : J. Marvin Herndon, pictured at left, demonstrated in 1992 the feasibility of natural, nuclear fission reactors as the energy source Recent measurements of geo-neutrinos rule out the hypothesis that most of the planet’s internal heat is generated by a uranium-fuelled nuclear geo-reactor in the Earth’s core.: http://www.physorg.com/news187946006.html 207. Francisco says: yan Stephenson (07:28:41) : Interestingly I don’t see any part of this diagram to account for geothermal heat from underground. Even under the UK (not known for its volcanic activity) the ground at 3000meters depth is about 90Celsius. ———————- See also letter by Herndon in Current Science, titled “Variables unaccounted for…” http://tinyurl.com/yfx4dax 208. sky says: Nothing impedes clear physical reasoning than a wrong conceptual model. A blackbody Earth without an atmosphere might be a good starting point for teaching students, but no realistic analysis of actual temperatures can be made without fully mastering the implications of enthalpy. That atmospheric pressure is a vital variable seems to have been forgotten. 209. Harry Lu says: Thermal imaging and emissivity here http://en.wikipedia.org/wiki/Thermal_imaging “Since there is no such thing as a perfect black body, the infrared radiation of normal objects will appear to be less than the contact temperature. The rate (percentage) of emission of infrared radiation will thus be a fraction of the true contact temperature. This fraction is called emissivity. Some objects have different emissivities in long wave as compared to mid wave emissions. ” /harry 210. Update, pls: Joel Shore (17:38:05) : Well, the issue of latent heat is really one of distribution of the temperature change with height in the atmosphere since what evaporates at the surface has to condense higher in the atmosphere, and this in turn can affect the radiative balance since most of the emission back out into space escapes from the upper troposphere. Hmmm … which space-based sensor (and what wavelength) can allow measurement, can allow this to be actively seen during convective T-storm activity? I’m going to posit the theory that a largish amount of thermal energy is _not_ radiated directly from the troposphere (from the gases constituting the air e.g. CO2 which are *capable* of EM radiation) into space, but rather becomes part of Hadley Cell circulation and the bulk of that sensible heat is released back into space is at latitudes greater than ~45 degrees due to *surface cooling* … Also note that thermal budgets show a ‘deficit’ of incoming solar energy at those latitudes (for the average temps seen), so it is circulation from the lower latitudes that keeps those temperatures elevated relative to what might otherwise be experienced over ~50 latitude. . . 211. HankHenry says: Willis tells us “The average temperature of the planet is about 14°C.” Of course that’s disregarding the massive cold of the ocean which is more like 4°C – averaged out. What is it that makes the oceans so cold? Two miles down on the continents the earth is quite warm, but two miles down in the oceans it’s quite cold. It suggests to me there is a refrigeration process of some sort extracting heat from the depths. Also, do I remember my grade school science correctly when I say the total mass of the atmosphere is represented by the mass of just 33 feet of water – the theoretical lifting limit of a suction pump? 212. Willis Eschenbach says: cba (17:25:23) Willis, there are some significant problems with the albedo numbers. If you go by K&T, it would seem the 0.3 total albedo is 0.22 for clouds and 0.08 for surface with about 0.62 cloud cover fraction. In essence, the 0.08 is the average albedo where there are no clouds present. Your number of 0.15 would be fairly reasonable based upon the Moon and Mars. It is not reasonable for Earth as over 70% of the surface is covered by oceans and the oceans have less than 0.04 albedo for incoming solar radiation, at least for high angles of incidence (wrt horizon where the incoming flux is most significant). Try these numbers: surface (ocean – use 0.7 ocean fraction) 0.04 surface( land) 0.19 (includes snow cover, forests, sand etc) average surface albedo 0.085 (corresponds to 29/342 on chart ) I love posting here, people always force me to refine my figures. I went and got the ERBE figures for clear-sky albedo here (Table 1). They give the clear sky albedo as 0.123. Using this figure instead of the 0.15 I used earlier gives a warming from a no-atmosphere situation of ~ 18°C rather than the ~ 20°C I used above. This changes the climate sensitivity 0.43°C per doubling, rather than the 0.5°C per doubling I quoted in the lead post. Which, of course, makes absolutely no difference to my argument, which is that the average climate sensitivity is much, much lower than the canonical IPCC value, and that the equilibrium sensitivity is lower yet. That’s why I’m not particularly concerned about the final digits in my estimates for TOA radiation. My calculations shown graphically above put it at 147 W/m2. Kiehl/Trenberth put it at 169 W/m2. ERBE satellite data puts it at around 170 W/m2. But none of these change my point. Use whichever TOA and albedo figures you want, you won’t get anything near the UN IPCC canonical sensitivity of 3°C per doubling. Instead, you’ll get something well below their lowest estimate of 1.5°C per doubling, and the IPCC says sensitivity is very unlikely to be less than 1.5°C. 213. Willis Eschenbach (19:16:37) : a warming from a no-atmosphere situation of ~ 18°C rather than the ~ 20°C I used above. I like your number now. 214. Brian G Valentine says: Willis and Leif think Gerlich & Tscheuschner’s analysis is bad. Sorry folks, it’s good. Two legitimate criticisms leveled at it: it does not account for convection heat transfer in the atmosphere (considers conduction only), and it does not consider clouds. But “convection” heat transfer is nothing more than conduction heat transfer (through a thermal boundary layer), and all radiation in the atmosphere is eventually lost via degradation to 20+ micrometer wavelengths, for which everything in the lower atmosphere is transparent – or it increases the internal energy of the atmosphere, the contribution (via increasing the average k.e. of molecules) is negligible. Ladies and Gentlemen: Either Gerlich and Tschneuschner are correct, or the atmosphere is a perpetual motion machine. If it is, then copy the principle with a scale model and make yourself wealthy. Power your invention up a little bit with cold fusion. 215. Joel Shore says: Brian G Valentine says: Ladies and Gentlemen: Either Gerlich and Tschneuschner are correct, or the atmosphere is a perpetual motion machine. That’s a “head-I-win, tails-you-lose” style of argumentation. Actually, either Gerlich and Tschneuschner are correct and the greenhouse effect describes a perpetual motion machine or they are wrong and it doesn’t. It is very easy to show that the second of these possibilities is in fact the case…And, I think Brian that you are intelligent enough to comprehend this. 216. Joel Shore says: Willis Eschenbach says: But none of these change my point. Use whichever TOA and albedo figures you want, you won’t get anything near the UN IPCC canonical sensitivity of 3°C per doubling. But, I’d like to see you address the more fundamental objections that I raised in my post of (12:34:08), namely that I don’t see how your calculation includes feedback effects. I think you are just calculating the sensitivity before feedbacks and somehow getting the wrong number (as I don’t understand where the 150 W/m^2 value you use comes from). 217. Brian G Valentine (19:25:34) : But “convection” heat transfer is nothing more than conduction heat transfer (through a thermal boundary layer) It is a lot more. Conduction is mediated by micro-scale vibration without any bulk transfer of matter, while convection is macro-scale movements of matter. 218. Tsk Tsk says: Leif, I don’t buy the white 400C sphere and the black 400C sphere radiating the same. The fact that the white sphere is white has altered its emissivity and its radiation. It’s no longer a black body but a grey body. You can’t extract energy from the two spheres initially as the white sphere will also have lower absorption to go with the lower emissivity and so you won’t get a net flow of heat from the black sphere to the white. Maxwell’s demon still naps even though the total radiation from the two spheres initially is not the same. Willis, Yes, your post was a bit confusing because you didn’t show the math for the two cases until your follow up comments. I originally agreed with Leif until I re-read your post a couple of times to get your point. And, as others have pointed out, why didn’t you use the derivative with respect to power of S-B at mean global temp to get your sensitivity? The error is relatively small (0.18 vs. 0.13 K(C)/W) but it’s still a bug, or were you claiming that the sensitivity is something other than black body? 219. cba says: Willis, to measure the actual sensitivity of the atmospheric absorption you’re going to have to have similar albedo, despite its unreal conditions. That means before and after albedo of 0.307 despite a lack of atmosphere or of atmospheric absorption. The numbers are an average temperature of 288K with the associated surface radiation of 390 w/m^2. Balance occurs with about 239w/m^2 making it out of the atmosphere – leaving 150 w/m^2 to be absorbed in the atmosphere or blocked in the atmosphere. Note that some of this is due to ghgs and some due to cloud blocking. doing the comparisons for various warming values: 33 deg C = 34/ 150 = 0.23 18 deg C = 18/150 = 0.12 8 deg C = 8/150 = 0.05 deg C rise per W/m^2 power increase keeping albedo constant means we have 342 W/m^2 – 107 = 235 w/m^2 which corresponds to a bb temperature of 254 or about 34 deg C. Note that even the 34 deg C rise due to the current atmosphere corresponds to only 0.8 deg C rise for a 3.7 w/m^2 forcing increase due to a co2 doubling. Applying an increase in absolute humidity based on constant RH and a 2 deg C increase in temperature, one finds that h2o vapor (ignoring cloud formation) results in only about 1/3 of the power increase due to the co2 doubling (it’s about 3.1 w/m^2 for an increase of 30% based on a 5 deg C rise)which means that most of such a 2 deg C rise doesn’t have a mechanism to cause the increase. That is even assuming the rise of 5 deg. C, the co2 + h2o vapor increase doesn’t have enough forcing to generate even a 2 deg. C rise. Less warming results in even lower forcing from h2o vapor. 220. Glenn Tamblyn says: Willis A few points Your TOA figure of 147 seems wrong, from the diagram. You seem to be using the radiation that ORIGINATES at the TOA and not including the radiation making it THROUGH FROM LOWER LEVELS – 237 w/M^2 on the diagram “1. The climate models assume that there is a large positive feedback as the earth warms. This feedback has never been demonstrated, only assumed.” Well I would say rather estimated from calculations. Just because it may not have been adequately demonstrated does not automatically mean it isn’t valid “2. The climate models underestimate the increase in evaporation with temperature.” I can’t comment on whether they do but the question is what impact does this have on energy balance. What altitude does this additional heat get transported to before it condenses out? “3. The climate models do not include the effect of thunderstorms, which act to cool the earth in a host of ways . “. Yes, conceivably they do, but what is the quantitative impact of that? What percentage of the energy transport in the atmosphere could be attributed to Thunderstorms. Is it a significant percentage or small enough that it can be ignored as a 2nd or 3rd order effect. Or simply subsumed into the general circulation within a cell in the model. A qualitative idea about a possible factor is only useful if you can get a handle on how important that factor is quantitatively. “4. The climate models overestimate the effect of CO2. This is because they are tuned to a historical temperature record which contains a large UHI (urban heat island) component. Since the historical temperature rise is overestimated, the effect of CO2 is overestimated as well.”. How can the effect of CO2 be ‘tuned to the temperature record’? Surely the effect of CO2 is used to estimate the radiative balance consequences. Any tuning to the temperature record is then about relating radiative balance to temperature change. And the UHI effect won’t be that big. 70% of the surface temperature is oceans – no UHI. Most of the worlds land area isn’t in cities, no UHI. If it is the historical record being used, even in cities, UHI was much lower in the past. “5. The sensitivity of the climate models depend on the assumed value of the aerosol forcing. This is not measured, but assumed. As in point 4 above, the assumed size depends on the historical record, which is contaminated by UHI. See Kiehl for a full discussion.” See my comments at 4 about UHI. Also isn’t aerosol effects also analysed by modelling and measuring the optical properties aerosols? “6. Wind increases with differential temperature. Increasing wind increases evaporation, ocean albedo, conductive/convective loss, ocean surface area, total evaporative area, and airborne dust and aerosols, all of which cool the system. But thunderstorm winds are not included in any of the models, and many models ignore one or more of the effects of wind” See my comments at 3 about quantifying such statements. How much do winds speeds increase relative to the current speed of the Jet Stream for example. Also, what if any impact does any of this have on vertical mixing and energy transport to higher altitudes which could increase outgoing radiation. Greater mixing at one altitude does not necesarily result in changing the vertical heat balance for that level, just the horizontal distribution of that heat. You don’t mention increasing contributions from Methane, Ozone, Nox. You don’t discuss long term albedo change due to decline of ice coverage or vegetation change. You don’t discuss the consequences if cooling due to aerosols declines due to humanity trying to clean up our emissions. You don’t mention that the capacity of the air to hold water vapour does not go up exponentially with temperature, so increased evaporation will be balanced by increased precipitation. There is a lot you don’t mention Willis 221. HankHenry: What is it that makes the oceans so cold? Two miles down on the continents the earth is quite warm, but two miles down in the oceans it’s quite cold. It suggests to me there is a refrigeration process of some sort extracting heat from the depths. The sun warms the bottom of the atmosphere and the top of the oceans. When a gas or liquid warms it expands and so rises because it is less dense. So the oceans are very stratified in temperature – because the top is warmer and gets further warmed by the sun. But the atmosphere experiences a lot of convective overturning as the warmed air at the bottom rises up. So the atmosphere is more mixed. You can see more about this at Why Global Mean Surface Temperature Should be Relegated, Or Mostly Ignored PS More technical note, yes the top of the stratosphere gets warmed as well due to the O2-O3 process. But most of the sun’s energy then travels through the “transparent” atmosphere and so warms the surface of the earth and the surface of the oceans. 222. Tsk Tsk (20:11:34) : I don’t buy the white 400C sphere and the black 400C sphere radiating the same. My argument goes like this: Consider a solid white sphere with an opaque interior in empty space far from everything. In its interior it has a nuclear reactor that heats the sphere [by conduction] to a temperature of 400C. This means that the electrons just inside the surface due to thermal jiggling will be accelerated constantly [in random directions]. Accelerated charges radiate determined by their acceleration. Since we stipulate that the sphere stays at the same temperature it must radiate corresponding to the thermal jiggling determined by that temperature. The same must hold for a black sphere, or a green sphere, etc. The radiating, accelerated electrons don’t know what color the sphere has. The energy emitted must equal that generated by the reactor. 223. gbaikie says: “Temperature of a body at the distance of the earth from the sun, with an albedo equal to that of the earth: about 20°C cooler than the present earth. TOA radiation from the present earth: about 150 W/m2 Since 150 W/m2 TOA radiation gives a warming of about 20°C, this gives a climate sensitivity of about half a degree for a doubling of CO2. This is only one-sixth of the UN IPCC canonical value of 3°C. I don’t care if I’m off by 10%, this is a first-order analysis. My answer is way below the IPCC answer, that’s the issue, not the exact details.” Couple questions. First, it’s well known that earth’s average temperature is about 15 C. Is that suppose to be air temperature or temperature of the ground or surface of oceans. I assume it’s air temperature in the shade and on sea level elevation. Or simply the average air temperature of the ocean [since a large part of the surface of the Earth is covered by oceans- and therefore one can basically ignore all the land with it’s all of varying elevation. Now you talking about an imagined airless world with the same albedo as earth. It seems then that you talking about the surface temperature- as you have removed the air. Take Mars [a nearly airless world] it’s “air temperature” varies widely depending upon whether it is a meter or two above the surface: “The daytime SURFACE temperature is about 80 F during rare summer days, to -200 F at the poles in winter. The AIR temperature, however, rarely gets much above 32 F. ” http://www.astronomycafe.net/qadir/q2681.html “The problem with measuring the temperatures on Mars is that they change in time and space in radical ways,” he said. “On Mars Pathfinder, for example, over a distance of only 40 centimeters (about 16 inches) up and down a little mast, we had three temperature sensors. They often measured temperatures that differed by about 15 degrees Celsius — that’s about 25 degrees Fahrenheit.” http://www.space.com/news/mplmet_991201.html 224. anna v says: A contributor posted the following link http://isccp.giss.nasa.gov/products/browsesurf1.html where one can find the “surface skin temperature”. It is higher than the air at 2meters temperature that is used in all the calculations. Mind you, it is the surface skin temperature that should be used in black body formulae, because it is the solids/liquids that radiate as T^4.( I think the atmosphere is something like a T^6 and in any case has small heat capacity with respect to the surface). Nobody uses the “surface skin temperature” in all these radiation budgets. In any case, my physicist trained brain gives up with all the hand waving and double counting that goes on in “climate science”. 225. LightRain says: Why are we worried about a black body earth when there is, and never will be such a thing. I see the point, saying a perfect black body would only be 8°C colder doesn’t allow the tiny CO2 increase much latitude to increase temperatures. But in reality we have a 30°C difference caused by our atmospheric blanket, therefore a 3-4°C increase is less impossible, and at the same time quite significant. 226. Willis Eschenbach says: Joel Shore (12:34:08) Willis: I am confused as to where you have gotten the 150 W/m^2 figure that you quote. I also think, in line with what scienceofdoom said, that what you have essentially calculated here is not the climate sensitivity but the sensitivity in the absence of feedbacks. In particular, what you have to recognize is that the distinction between forcings and feedbacks is somewhat arbitrary. For example, CO2 change is, in some sense, a feedback in the glacial – interglacial cycles but is a forcing in our current predicament. The thing is that you have to be consistent. What you have done is not consistent because you have presumably counted everything, e.g., including the water vapor, as a forcing in getting that 150 W/m^2 figure but then you have not counted any change in water vapor as a forcing in computing the resulting climate sensitivity. Joel Shore (20:05:18) Willis Eschenbach says: But none of these change my point. Use whichever TOA and albedo figures you want, you won’t get anything near the UN IPCC canonical sensitivity of 3°C per doubling. But, I’d like to see you address the more fundamental objections that I raised in my post of (12:34:08), namely that I don’t see how your calculation includes feedback effects. I think you are just calculating the sensitivity before feedbacks and somehow getting the wrong number (as I don’t understand where the 150 W/m^2 value you use comes from). Much as I’d like to do this all the time, I do have a life. Anyhow, 11 PM here, I’m back in the saddle. Joel, the 150 W/m2 is what I estimate as the TOA downwelling forcing. See Figure 1 above. Kiehl/Trenberth give a higher figure, but their diagram is not physically possible. But use either number, it doesn’t matter. This number perforce includes everything. It includes whatever water vapor feedback (or forcing) exists at the current earth temperature. It includes the cloud feedbacks (or forcings) that exist at the current earth temperature. By definition, it includes each and every feedback that exists, known and unknown, measured and unmeasured. Now, the combination of all of those forcings and feedbacks keep our lovely planet about 18 above what it would be if the atmosphere disappeared. So ~ 18C is the ∆T in the equation. And without an atmosphere, the TOA forcing would obviously be zero, so 150W/m2 is the ∆F in the equation. Since the sensitivity for a doubling of CO2 is 3.7*∆T/∆F, that gives on the order of half a degree for a doubling of CO2. Now, if you have an explanation for why 150 W/m2 of downwelling TOA longwave radiation gives us on the order of 20°C of warming, but another 3.7W/m2 might give us 4.5°C of warming as the UN IPCC claims, I’m more than happy to listen. w. PS – I note that someone above called you “Troll Shore”. Folks, I’ve got good news and bad news. Joel is a physicist, understands the math, and is one of the few AGW supporting trained scientists with the balls to post here. So cut out the personal attacks. They are repulsive in any case, and totally unmerited in Joel’s case. I disagree with him a lot, but he is absolutely not a troll. 227. Willis Eschenbach says: mkelly (12:51:59) steven mosher (11:39:03) : Steve I guess you missed reading the part about patenting the idea. It was a rhetorical question. I cannot put smiley face at the end of the sentences. However, it is possible to construct an idealized thermos floating in space, with an inside chamber transparent to IR but infinite R value, and an outside surface that blocks incoming radiation whose inside surface is a perfect reflector of IR. So no conduction no convection only IR from the soup, coffee whatever to the next chamber. Fill the space where the vacuum would normally be with CO2. Filling a thermos with CO2 (or any other gas) increases the heat loss in a thermos. In just the same way, conduction/convection by the atmosphere of sensible heat in the climate system increases the heat loss. Sorry, your idea doesn’t work, it makes the thermos bottle (also called a “Dewar flask” or a “vacuum flask”) less efficient. That’s why it’s a vacuum flask … see my post called The Steel Greenhouse for further discussion. 228. Willis Eschenbach says: Mattias, Sweden (13:09:09) 8 degrees cooler? That contradicts what can be found using Stefan-Boltzmann law, 255K or -18C. Or have I missed something? http://answers.yahoo.com/question/index?qid=20090408183916AASBK1D http://en.wikipedia.org/wiki/Black_body#Temperature_of_Earth Yes. They are using the amount of sunlight remaining after cloud albedo and surface albedo. I’m using the full amount of sunlight that would shine on a black body at the distance from the sun of the earth. 229. anna v says: They are repulsive in any case, and totally unmerited in Joel’s case. I disagree with him a lot, but he is absolutely not a troll. Truly said. I have had interactions with Joel and I confirm this. 230. Willis Eschenbach says: pochas (15:07:53) Also recommended: Nir Shaviv: “On Climate Sensitivity and Why it is Probably Small” http://www.sciencebits.com/OnClimateSensitivity Interesting, thanks for the link. Shaviv uses an entirely different empirical measurement technique over six time periods to estimate the climate sensitivity, and gets numbers that center around 0.5W/m2 … doesn’t mean he or I are right, but it is of interest. 231. Willis Eschenbach says: Brian P (15:29:16) Willis A bit old but I really liked your thunderstorm post from some months ago Thanks. I consider it my most insightful piece of scientific work. It’s here if someone hasn’t read it. 232. Willis Eschenbach says: Alan D McIntire (15:31:54) You’ve also got to adjust for emissivity. The earth’s albedo would be maybe 0.15 without clouds, but it would also would not emit as a black body- what would the emissivity be? I’ve read estimates that the oceans’ emissivity is about 0.94, what would it be for land only, about 0.9? in that case, you’d figure in a correction of ( 1 – 085/.9)^0.25 My bible, Geiger’s “Climate Near The Ground”, puts the IR emissivity of the earth at around 0.95. Geiger also says “The surface will be treated as a blackbody [for longwave emission/absorption] throughout the remainder of the book since, for the range of natural surface emissivities, the departure of Tr [blackbody radiation temperature] from Ts [true surface temperature] is small.” To calculate the difference, if we take the albedo as 0.15 and TOA insolation as 342W/m2, for a blackbody we get a temperature of -5.6°C. Using an emissivity of 0.95 we get -2.1°C. Since using the emissivity makes the calculated climate sensitivity even smaller, I have taken the blackbody figures as the conservative route, to avoid people saying I was picking the numbers to favour my argument. 233. Willis Eschenbach says: Alan D McIntire (16:21:39) Sorry, that should be a correction factor of roughly (albedo/emissivity) ^0.25 = (.85/,9)^.25 times the original temperature. Another point, Using Trenbeth ballpark figures, if we get 240 watts from the sun, and the greenhouse effect makes that an effective 390 watts and a 33 C increase, isn’t the increase in temperature per delta watt increase in the ballpark of 33 C/(390-240) = about 0.22C per watt increase? No, no, no. I’ll keep going over this until everyone gets it. According to the UN IPCC, climate sensitivity is the change in surface temperature divided by the change in TOA forcing … yes, I know, it’s a really dumb measurement, but there it is. I suspect it was specifically chosen by AGW supporters because downwelling TOA radiation can’t be measured directly … but perhaps that’s just my paranoia speaking. 234. Willis Eschenbach says: cba (17:25:23) Willis, there are some significant problems with the albedo numbers. If you go by K&T, it would seem the 0.3 total albedo is 0.22 for clouds and 0.08 for surface with about 0.62 cloud cover fraction. In essence, the 0.08 is the average albedo where there are no clouds present. Your number of 0.15 would be fairly reasonable based upon the Moon and Mars. It is not reasonable for Earth as over 70% of the surface is covered by oceans and the oceans have less than 0.04 albedo for incoming solar radiation, at least for high angles of incidence (wrt horizon where the incoming flux is most significant). Above I cited the ERBE satellite measurement for clear-sky albedo of 0.123. And I recalculated the sensitivity using that number. If you don’t like that surface albedo estimate, I fear you’ll have to take it up with the ERBE folks. 235. Willis Eschenbach says: Harry Lu (17:59:59) Leif Svalgaard (13:23:50) : A questions perhaps you could answer please? Albedo refers to reflectivity. The normally referred albedo is to the visible light reflectance. But surely the reflectance in the LW IR will be different. Is this known? Emissivity of a surface is not he same as albedo. Having used an IR camera a few times I know that the IR temperature of an object changes with emissivity. and corrections can be incorporated in the IR to temp conversion (this is why Mr Watts IR photos in his surface station project are not very valid – he need to correct for surface emissivity.) When using IR cameras one usually coats the objects with a thin layer of mat paint to equalise (approx) emissivity. Surely albedo controls the absorbed solar radiation, but emissivity controls the radiated LW energy. If so then one needs to know the emissivity of the earth in the 4u range not its albedo. /harry The emissivity of the earth in the less than 4um range is generally taken to be 1. Most natural substances (including bright white things like snow) have IR emissivities of around 0.95 or higher. Geiger gives inter alia fresh snow 0.986, cotton 0.980, water 0.960, coniferous forest 0.970, etc. Human skin is 0.98 … 236. Willis Eschenbach says: sky (18:15:08) Nothing impedes clear physical reasoning than a wrong conceptual model. A blackbody Earth without an atmosphere might be a good starting point for teaching students, but no realistic analysis of actual temperatures can be made without fully mastering the implications of enthalpy. That atmospheric pressure is a vital variable seems to have been forgotten. As I pointed out above, the change from blackbody conditions to current earth conditions includes every known and unknown variable … so no, I have not forgotten atmospheric pressure. 237. Willis Eschenbach says: Brian G Valentine (19:25:34) Ladies and Gentlemen: Either Gerlich and Tschneuschner are correct, or the atmosphere is a perpetual motion machine. Fallacy of the false dilemma. There are lots of other possibilities. They might be partly right. Their facts might be right but their conclusions wrong. Their being wrong might not imply a perpetual motion machine. 238. Willis Eschenbach says: cba (20:14:47) Willis, to measure the actual sensitivity of the atmospheric absorption you’re going to have to have similar albedo, despite its unreal conditions. That means before and after albedo of 0.307 despite a lack of atmosphere or of atmospheric absorption. No. I am trying to figure out the changes relating to the atmosphere. To do this, I have to see what the temperature would be without the atmosphere. Accordingly, I have to remove the cloud albedo (which is part of the atmosphere). 239. HankHenry says: scienceofdoom, ok but my question still stands. On the continents temperatures at a depth of a few feet below the frost line will represent something pretty close to the annual average surface temperature (but no colder) while the temperature in the depths of the ocean is *colder* than the average surface temperature. (Remember that the geothermal gradient of the earth is something like 25-30 C per kilometer so by this extrapolation the bottoms of the oceans with an average depth of 3.7 km should be very very warm). This is the main point I am trying to drive home, namely, that on the continents the earth below the frost line (or at comparable depths for tropical latitudes) is no cooler than the average surface temperature while in the oceans most of the ocean is cooler than the average surface temperature. Once one starts thinking about temperatures a short distance beneath the surface of the earth it strikes one as quite surprising. I believe that so much cold ocean water (3.9 C overall average according to my encyclopedia) suggests that the earth is really quite different than a simple black body model. Rather there must be substantial movement by advection of heat along and across the surface of the globe; otherwise there would not be so much of the ocean’s water at the same average temperatures as polar or sub polar regions. My guess is that on the earth there is a general motion of heat poleward (at the surface but not at oceanic depths) and further that because air is dryer in cold polar regions, heat is radiated away more effectively in those regions. The Earth is much different than the idealized black body radiator of our imaginations. I am suggesting that the earth with its oceans is probably better at radiating than a true black body with a strictly solid stable surface and that the prime evidence of this is the great coldness of the subsurface ocean. 240. Willis Eschenbach says: Glenn Tamblyn (20:44:12) Willis A few points Your TOA figure of 147 seems wrong, from the diagram. You seem to be using the radiation that ORIGINATES at the TOA and not including the radiation making it THROUGH FROM LOWER LEVELS – 237 w/M^2 on the diagram The UN IPCC says that the climate sensitivity is the temperature change divided by the change in downwelling TOA longwave radiation. That is to say, radiation that ORIGINATES at the TOA. So that’s what I have used. If you want to use the upwelling radiation as well you are free to do so … but then you are not measuring climate sensitivity as defined by the IPCC. “1. The climate models assume that there is a large positive feedback as the earth warms. This feedback has never been demonstrated, only assumed.” Well I would say rather estimated from calculations. Just because it may not have been adequately demonstrated does not automatically mean it isn’t valid You are right, that does not mean it is not valid. However, call me crazy, but I tend to put more stock in things that have been demonstrated to exist … “2. The climate models underestimate the increase in evaporation with temperature.” I can’t comment on whether they do but the question is what impact does this have on energy balance. What altitude does this additional heat get transported to before it condenses out? If the evaporation is underestimated, their cooling effect on the surface is underestimated. How much? I don’t know, and it’s very hard to measure. But we know that the effect is to increases the calculated climate sensitivity. Wind cools the surface, look into your own experience if you doubt this. “3. The climate models do not include the effect of thunderstorms, which act to cool the earth in a host of ways . “. Yes, conceivably they do, but what is the quantitative impact of that? What percentage of the energy transport in the atmosphere could be attributed to Thunderstorms. Is it a significant percentage or small enough that it can be ignored as a 2nd or 3rd order effect. Or simply subsumed into the general circulation within a cell in the model. A qualitative idea about a possible factor is only useful if you can get a handle on how important that factor is quantitatively. I give some numbers on this here. I don’t know if you’ve ever lived in the tropics, but if you, you would not say they were a third order effect … “4. The climate models overestimate the effect of CO2. This is because they are tuned to a historical temperature record which contains a large UHI (urban heat island) component. Since the historical temperature rise is overestimated, the effect of CO2 is overestimated as well.”. How can the effect of CO2 be ‘tuned to the temperature record’? Surely the effect of CO2 is used to estimate the radiative balance consequences. Any tuning to the temperature record is then about relating radiative balance to temperature change. And the UHI effect won’t be that big. 70% of the surface temperature is oceans – no UHI. Most of the worlds land area isn’t in cities, no UHI. If it is the historical record being used, even in cities, UHI was much lower in the past. CO2 is the only thing in the models that provides a mechanism for gradual modeled warming. Since the models are tuned to the past, if the temperature rise is overestimated, the effect of CO2 needs to be larger to mimic the temperature rise. This is true no matter the size of the UHI effect. Also, GISS estimates the temperature of large parts of e.g. the Arctic Ocean (where there is no temperature data) from the surrounding land. “5. The sensitivity of the climate models depend on the assumed value of the aerosol forcing. This is not measured, but assumed. As in point 4 above, the assumed size depends on the historical record, which is contaminated by UHI. See Kiehl for a full discussion.” See my comments at 4 about UHI. Also isn’t aerosol effects also analysed by modelling and measuring the optical properties aerosols? Did you bother to read Kiehl? “6. Wind increases with differential temperature. Increasing wind increases evaporation, ocean albedo, conductive/convective loss, ocean surface area, total evaporative area, and airborne dust and aerosols, all of which cool the system. But thunderstorm winds are not included in any of the models, and many models ignore one or more of the effects of wind” See my comments at 3 about quantifying such statements. How much do winds speeds increase relative to the current speed of the Jet Stream for example. Also, what if any impact does any of this have on vertical mixing and energy transport to higher altitudes which could increase outgoing radiation. Greater mixing at one altitude does not necesarily result in changing the vertical heat balance for that level, just the horizontal distribution of that heat. My point is that regardless of the size of all of those effects, they all tend to increase the calculated climate sensitivity. I listed them as some of the possible explanations for why the models come up with huge sensitivities. You don’t like them, fine … what’s your explanation? You don’t mention increasing contributions from Methane, Ozone, Nox. You don’t discuss long term albedo change due to decline of ice coverage or vegetation change. You don’t discuss the consequences if cooling due to aerosols declines due to humanity trying to clean up our emissions. You don’t mention that the capacity of the air to hold water vapour does not go up exponentially with temperature, so increased evaporation will be balanced by increased precipitation. There is a lot you don’t mention Willis As I have mentioned several times, the current state of the earth includes all forcings, known and unknown, measured and unmeasured, the ones you mention and more. All of them are reflected in the surface temperature and the TOA forcing. So you are right, I didn’t mention cosmic rays or CMEs or planktonic sulfur compound emission that increases clouds when plankton get too hot or a host of other things … and it makes no difference to my estimate of climate sensitivity. The net result of all of them is a warming of about 20°C and a downwelling TOA radiation of about 150W/m2. 241. anna v says: It is infrared that is important at these temperatures. various emissivities: http://www.icess.ucsb.edu/modis/EMIS/html/em.html 0.95 is closer for soils. .985 for oceans. Sand can go as low as o.75 ( think deserts). There is still the assumption that average air temperature at 2 meters is the same as average surface skin temperature. It is not. http://isccp.giss.nasa.gov/products/browsesurf1.html It is obvious in Africa, and also the changes when one blinks from surface to air. look at the antarctic. These are the average mean annual. they have options per month also. They have the data there also but I do not have the tools to use it ( ftp, Fortran) 242. Willis Eschenbach says: gbaikie (21:53:59) First, it’s well known that earth’s average temperature is about 15 C. Is that suppose to be air temperature or temperature of the ground or surface of oceans. I assume it’s air temperature in the shade and on sea level elevation. Or simply the average air temperature of the ocean [since a large part of the surface of the Earth is covered by oceans- and therefore one can basically ignore all the land with it’s all of varying elevation. Now you talking about an imagined airless world with the same albedo as earth. It seems then that you talking about the surface temperature- as you have removed the air. You raise an interesting point. The average surface air temperature is generally considered to be a reasonable approximation of the actual surface temperature. In general the surface is warmer than the air during the day, and cooler than the air during the night. So for the purpose of this first-order analysis, the difference in the averages doesn’t make a difference. 243. Recipy says: Dr.Bill (&Willis): Agreed. The earth would not have clouds without an atmosphere. But the surface albedo would be higher than that of the moon. Presumably we would have more snow and ice in a colder world. Since Earth is ~70% covered by water at the moment i would argue that the albedo would be closer to that of Jupiters moon Europa than that of the moon. Perhaps an albedo of 0.5 would be a nice round guess (that is actually higher than it is today.). In that case i get a difference 54degC. 244. HelmutU says: Dear Dr.Eschenbach, as Prof. Dr. G. Gerlich at the Technical Univerity of Braunschweig has shown in his Paper “Falosificartion of the Atmospheric CO2 Greenhouse Effects wirthin the Frame of Physics” that diagrams like the one of Kiehl and Trenberth are contradict to physics for the following reasons: 1. they connot represent radiation intensities, 2. they connot represent sourceless fluxes, i.e. divergence free vector fields in three dimensions, sice avanishing three-dimensional divergence still allows that aportion of the field goes sidewards, 3. thes do not fit in the framework of Feynman diagrams, which represent mathematical expressions clearly defined in quantum field theory, they do not fir in the standard language of system theory. Further if the calculation of the earth without atmosphere is done in the correct way (first take the 4th root of every temperature and than calculated the mean temperature), the mean temperature is -129° Celsius for 0,7 as usally assumed. 245. Willis Eschenbach says: HelmutU (02:40:16) Dear Dr.Eschenbach, as Prof. Dr. G. Gerlich at the Technical Univerity of Braunschweig has shown in his Paper “Falosificartion of the Atmospheric CO2 Greenhouse Effects wirthin the Frame of Physics” that diagrams like the one of Kiehl and Trenberth are contradict to physics for the following reasons: 1. they connot represent radiation intensities, 2. they connot represent sourceless fluxes, i.e. divergence free vector fields in three dimensions, since a vanishing three-dimensional divergence still allows that aportion of the field goes sidewards, 3. thes do not fit in the framework of Feynman diagrams, which represent mathematical expressions clearly defined in quantum field theory, they do not fit in the standard language of system theory. Further if the calculation of the earth without atmosphere is done in the correct way (first take the 4th root of every temperature and than calculated the mean temperature), the mean temperature is -129° Celsius for 0,7 as usally assumed. Helmut, we’ve already discussed this paper upthread. 246. Francisco says: Leif Svalgaard (18:02:49) : Francisco (17:52:28) : J. Marvin Herndon, pictured at left, demonstrated in 1992 the feasibility of natural, nuclear fission reactors as the energy source Recent measurements of geo-neutrinos rule out the hypothesis that most of the planet’s internal heat is generated by a uranium-fuelled nuclear geo-reactor in the Earth’s core.: http://www.physorg.com/news187946006.html ======================== I’ve asked Marvin Herndon how he interprets those measurements, and below is his reply. Herndon continues to be adamant about the physical impossibility of convection in the earth’s core and mantle as a source of the earth’s magnetic field in the current standard earth model, as explained by him here: http://tinyurl.com/ylnjzur Home page with links to much of his work is here: http://www.nuclearplanet.com/ This was his reply to my inquiry: “No, those measurements do not [rule out the georeactor]. The last measurements said it ruled out georeactor energy output above 3 terawatts. From KAMland data, the limit was 6 terawatts. They only detected a small number of events (signals in their detector), from which they had to subtract estimates of background and signals caused by man-made nuclear reactors. There will have to be many, many more measurements before any statement can be made with confidence.” “There is much wrong with textbook geoscience. I have now shown conclusively that convection in the Earth’s core and in the Earth’s mantle is physically impossible. If fact I have a new paper coming out soon.” 247. Willis Eschenbach What would you expect a thermopile or some other radiation detector pointed vertically upwards to read(average ball park figure) given these conditions. a. Radiatively insulated to exclude upward radiation. b. In the middle of a desert. c. Two hours before dawn. d. Gentle or stronger wind. 248. Brian G Valentine says: I have always referred to it as the “fallacy of the false dichotomy,” Willis. The “CO2 in the air from people is causing something to happen” concept is abysmally poor science, for which there is no evidence (and evidently impossible); anybody who believes otherwise has absolutely no comprehension of “geological time” 249. Ryan Stephenson says: Willis: It is interesting that one branch of taxpayer funded science woul dhave us believe that geothermel heating has no impact on a planetary body’s surface temperature, whilst another would have you believe that it is sufficient to maintain life on distant moons. http://www.sciencedaily.com/releases/2009/12/091215141510.htm Excuses, excuses…. to spend other people’s money. By the way, the mid-ocean ridges are 40,000km long, are spewing out lava at 1300Celsius along their entire length and have an efficient heat-exchange system called water to distribute the heat evenly over the planet. 250. Glenn Tamblyn says: Willis “The UN IPCC says that the climate sensitivity is the temperature change divided by the change in downwelling TOA longwave radiation. That is to say, radiation that ORIGINATES at the TOA. So that’s what I have used. If you want to use the upwelling radiation as well you are free to do so … but then you are not measuring climate sensitivity as defined by the IPCC. What is your source for this. The only definition I am aware of for Climate Sensitivity. whether it be the Charney Sensitivity or others is Temperature change per Doubling of CO2. Basing seisitivity on downwelling radiation levels seems strange. Source please. If there are differing definitions then how are these differing definitions related so that we can compare Apples with Apples. From the diagram above, total downwelling is 321 w/M^2 251. Glenn Tamblyn says: Willis “I don’t know if you’ve ever lived in the tropics, but if you, you would not say they were a third order effect “. Yes, I have lived in a semi tropical environment and locally a Thunderstorm is impressive, visceral, quite emotional. Which is all irrelevent. The question is what percentage transports due to thunderstorms contribute to the total transport over the entire globe. Again, quantitative assessments rather than emotive, local or qualitative ones. 252. gbaikie says: “You raise an interesting point. The average surface air temperature is generally considered to be a reasonable approximation of the actual surface temperature. In general the surface is warmer than the air during the day, and cooler than the air during the night. So for the purpose of this first-order analysis, the difference in the averages doesn’t make a difference.” I would say loosely, that the top surface of ground at nite should be about the same temperature as the air. And on the top surface of the ground [or tree top] in sunlight is much warmer than the air. But as I said before, since about 70% of the surface of earth is covered by water*, one could almost not even bother considering land temperatures. BUT if we are essentially measuring ocean temperature instead of land temperatures, there obvious a limits to how warm the water can get in terms of higher temperatures [and that will affect this whole blackbody type calculations]. E.g. The top surface of the sand of a desert could reach somewhere around 160 F during the day- such temperature aren’t possible in a ocean. One factor being that even though it’s not at the boiling point such higher temperatures have significant increases in the evaporation rate of water. So in regard to a ocean the surface temperature I would say that it is normally about the same temperature as air temperature regardless of whether it’s day or day. But then again, what is meant by ocean surface temperature- are we talking about to first 2 mm of ocean OR the top layer of the ocean thermocline. Because when I say there are about the same temperature I mean the top 2mm of water rather than the top say, 10 or 20 meters of water. * It should noted that as far the average temperature of earth the tropical region is the most important “in getting an average global temperature”- and I don’t have an reference or know off hand, what the percent of land vs ocean is in tropical region. 253. Francisco says: Ryan Stephenson (04:33:23) : Willis: It is interesting that one branch of taxpayer funded science would have us believe that geothermal heating has no impact on a planetary body’s surface temperature, whilst another would have you believe that it is sufficient to maintain life on distant moons. http://www.sciencedaily.com/releases/2009/12/091215141510.htm Excuses, excuses…. to spend other people’s money. By the way, the mid-ocean ridges are 40,000km long, are spewing out lava at 1300Celsius along their entire length and have an efficient heat-exchange system called water to distribute the heat evenly over the planet. ======================= I agree. Never understood how this is so trivial. http://en.wikipedia.org/wiki/Geothermal_power “The Earth’s internal heat naturally flows to the surface by conduction at a rate of 44.2 terawatts, (TW,)[20] and is replenished by radioactive decay of minerals at a rate of 30 TW.[21] These power rates are more than double humanity’s current energy consumption from all primary sources” 254. yusuke says: Your argument is wrong!! You can never assume that the downward radiation at TOA and temerparature rise are proportional. It is proven that they are not!! Well, IPCC says that (radiative forcing)*(climate sensitivity) = (temperature rise), but this is because this equation is a first-order equation, which is applicable only when radiative forcing and temperature rise are both small compared to their base values (150W/m^2 and 300 kelvin, in this case). “Well, my body temperature decreased by 2 degrees after taking 2 tablets of medicine, so my body temp. should reduce by 10 after taking 10 tablets”. You made exactly same mistake as this statement!! Please do not decieve innocent people!! 255. anna v says: Terra watts sound grand, but in the context of the earths area, and the language of climatology, geothermal only amounts to something like 0.075/m^2. I checked it when I first got involved in this AGW stuff. http://geophysics.ou.edu/geomechanics/notes/heatflow/global_heat_flow.htm Not a player in the game. CO2 though coming out of vents etc is another story. 256. yusuke says: In addition, all of the effects you mentioned are actually “included” in models referred to by IPCC. 257. anna v says: E.g. The top surface of the sand of a desert could reach somewhere around 160 F during the day- such temperature aren’t possible in a ocean. One factor being that even though it’s not at the boiling point such higher temperatures have significant increases in the evaporation rate of water. I live by the sea. In the summer air temperatures can be for a month from 37C to 40C the water is below 25C. At night it is the opposite, particularly in autumn, when the water may be a steady20C while the air drops to 12 and 14C. In spring, the air may be 23C and the water 13C. Even in the oceans, winds from the land blow hot or cold and are not reflected in the surface skin temperature by several degrees. Again I refer to the surface skin temperatures in http://isccp.giss.nasa.gov/products/browsesurf1.html they are different than the air temperatures. Unless one does the calculation, i.e. integrate over the provided data, one cannot assert that there is no global difference by handwaving. But then again, what is meant by ocean surface temperature- are we talking about to first 2 mm of ocean OR the top layer of the ocean thermocline. It is infrared at these temperatures that are being radiated, and the first mms of ocean or soil or vegetation is the important one. 258. Francisco (03:22:49) : I’ve asked Marvin Herndon how he interprets those measurements, […] Herndon continues to be adamant There will have to be many, many more measurements before any statement can be made with confidence. Fair enough, such measurements are continuing. I wonder what he would say if the continue to give the same result… His statement: “I have now shown conclusively that convection in the Earth’s core and in the Earth’s mantle is physically impossible” rubs me the wrong way. 259. Francisco says: anna v (06:31:47) : Re: Francisco (Mar 18 06:10), Terra watts sound grand, but in the context of the earths area, and the language of climatology, geothermal only amounts to something like 0.075/m^2. I checked it when I first got involved in this AGW stuff. ============== yes, I am aware of those figures. An often-quoted one is 0.9 (at realclimate). I have also seen much larger figures given at physics forums. I suppose it is small, but at a purely intuitive level, the notion that more than twice the total human energy consumption is coming at us from underneath sounds significant at least at first sight. I find a lot of the approaches puzzling. For example, the following paper. They observe an increase of 24 mW/m2 in ground heat flux from Canada’s geothermal database over the last 200 years, and they attribute all that to changes in surface temperature, and apparently none of it to changes in geothermal heat flux coming up. http://esrc.stfx.ca/pdf/halifaxtalk.pdf From the abstract: “Results from the analysis of Canada’s geothermal database indicate that the ground heat flux has increased an average of 24 mW/m2 over the last 200 years. Application of this method to the global geothermal data base allowed for a quantification of the global ground energy balance at the Earth’s surface for the past few centuries. Preliminary global ground surface emperature and surface heat flux histories indicate that the Earth’s continents have warmed by about 0.5 K and received an additional 26 mW/m2 of energy in the last 100 years.” 260. Ryan Stephenson says: “geothermal only amounts to something like 0.075/m^2. I checked it when I first got involved in this AGW stuff.” This calculation is clearly wrong. If it were true then there would be no possibility of lakes under Antartica, but there are. These lakes are created by geothermal heat counteracting the freezing effect of the overlying super-cooled ice. Here’s another one for you. Every day massive volumes of water are hauled from one end of the earth to the other by the tides. This massive kinetic energy – where does it go? The laws of entropy tell you. Did you know that tidal forces due to the moon also cause the land to be pulled upward by as much as a meter too? It is these forces that cause heating on moons like Europa which orbits Jupiter. It causes heating on the earth too, but your article only mentions nuclear fission. 261. anna v says: Tides also within the vocabulary of climate science give fractions of a Watt/m^2. The link I found by googling, I had not saved my calculations. Certainly over direct flues the heating will be important, but that is another story. Averaged over the area of the earth it is small. 262. Francisco (08:02:39) : they attribute all that to changes in surface temperature, and apparently none of it to changes in geothermal heat flux coming up. And that is correct. If you heat the surface, the heat will propagate downwards too. In fact, one can see the MWP in borehole temperatures as well: http://www.leif.org/research/T-Boreholes.png 263. Brian G Valentine (19:25:34) : But “convection” heat transfer is nothing more than conduction heat transfer (through a thermal boundary layer), and all radiation in the atmosphere is eventually lost via degradation to 20+ micrometer wavelengths, for which everything in the lower atmosphere is transparent … (Emphasis mine) Can you point to an article or source where this is actually measured (the quantitative measurement of atmospheric radiation of ‘heat’ energy ostensibly removed from the surface via convection)? Joel Shore could not … . . 264. mkelly says: Willis Eschenbach (23:21:59)Sir, with all respect a thought process of constructing an idealized thermos is possible since you can imagine a material with an infinite R value, etc. I know it won’t work that is the point. The earth and the thermos are in someways the same. A heated body surrounded by gas surrounded by a vacuum, as I tried to describe. If CO2 cannot heat or keep something warm via a thermos then heating an entire globe is utter nonsense. Again, as I pointed out if CO2 could increase heat in some object then (and we have known this for over a hundred years) why has no body found a way to make money off the idea. A CO2 coat, a wrap for your house etc. Because it is a false idea. CO2 will not increase the heat in anything. As I said my thawed turkey will not get warmer than room temperature no matter how much CO2 is in my house. I don’t know the patent process but if someone made a claim such as a product that with the aid of CO2 you got extra heat it would sure bring this to a head. I wish I could put a smiley face on things so folks would know when I am pointing out what I think is a false hood in the CO2 causes warming theory. Or I could just say that I guess. Enjoy your work very much. Thank you for it. Regards, MKelly 265. Brian W says: Brian G. Valentine (17:07:48) (17:36:44) (19:25:34) (04:22:43) Willis Eschenbach & others I concur 100%. Gerlich & Tscheuschner are correct in their analysis. One of the best overviews of anything I have seen. A “must” read. Physics rooted in real testable observations. There is a lot in this paper there for anyone in any discipline. I am a Ham Radio Operator. I have been one for 37 years and the first at age 13 to get the basic licence here in Canada and Willis I will tell you that this paper is good I’d give it a 5 star rating with ease. The bits about electromagnetic radiation and the atmosphere are spot on the money. Above roughly the 10 meter band or 30 megahertz the atmosphere becomes transparent to radio waves. This is called “line of sight” communications.The wavelength becomes short enough that the ionisphere allows them to pass through unobstructed. Below 30 mhz you enter shortwave radio territory, the wavelength becomes long enough that the ionisphere reflects radio waves. IR’s wavelength is above 30mhz and since IR is electromagnetic radiation it to will also pass through the atmosphere unobstructed. There is no reflection. So called radiating layers are only implied and cannot be physically observed(two eyes). Gases by their nature disperse and diffuse. Whatever the scientists are measuring is not what they think it is. Backradiation is falsified and thus falls into the realm of pseudoscience. I’m callin ’em as I see ’em. Now back to my family. 266. Francisco says: mkelly I wonder if someone can point to references to specific lab experiments attempting to measure the amount of surface warming caused by a given increase in CO2 in a column of air that is receiving infrared radiation from below. Do the IPCC reports give references to these kinds of experiments? If no such experiments have been made, how feasible would they be? If they are feasible, how expensive would they be in comparison with the total amount of money dedicated to fund AGW science? Are any such tests being made at all? 267. JAE says: Hmmm. Bill Parsons commented (third comment): “Wiki Answer to: “What is the temperature on the moon?” The average daytime temperature on the Moon is around 107°C (225°F), but can be as high as 123°C (253°F). When an area rotates out of the sun, the “nighttime” temperature falls to an average of -153°C (-243°F).” Now, note that the average daytime temperature on the moon is not that far from what is reached by the soil in a low-altitude desert on Earth. Even a greenhouse easily attains 170 F. It is interesting that that even with the slow rotation of the moon, “nighttime” temperatures don’t go anywhere near 3 K (-270 C), which is the temp of space. Ergo, the moon stores a lot of heat “overnight.” Without the aid of any “greenhouse gases.” Or without any water. This heat is stored in rocks and dust. “Moon-Day” length is 29 earth days (14.5 earth days in light; 14.5 earth days in darkness). http://www.solarviews.com/eng/moon.htm As indicated above, there is a 260 degree change between the moon’s “night” and “daytime” average temperatures. Assuming a linear loss of heat (bad assumption, but I don’t know how to do the proper T^4 math), the moon loses 260/14.5 = 17.9 deg/earthday. Or only 17.9/24 = 0.75 deg/hr. Therefore, crudely, if the moon had only a 24 hour day like earth, its temperature would only vary something like 17.9 degrees. So, it might be 123 C during the day and 105 C at night. Without any greenhouse effect. The temperature of the earth could easily be a function of heat storage and have nothing to do with “greenhouse gases,” except that they aid in thermalization. ?? 268. Brian W says: mkelly Sorry dude, almost forgot about you. You also understand physics. 269. Ryan Stephenson says: “Tides also within the vocabulary of climate science give fractions of a Watt/m^2.” You are thinking only of tides in terms of ocean movements. When the moon and the earth rotate around each other they both get deformed like a squash ball and the area of most deformity travels around the earth at 1000 miles per hour. This happens to the whole of planet earth, not just the oceans. Thus the planet warms, just like it has been discovered that Europa is warmer than it should be for a body with no obvious source of external heating and too small for internal fission. Meanwhile, the earth is 4000Celsius at its core which is similar to the surface temperature of the sun, only its not 93million miles away. “The link I found by googling, I had not saved my calculations. Certainly over direct flues the heating will be important, but that is another story. Averaged over the area of the earth it is small.” Flues on land pump heat into the air and most of that is lost into space. Flues under the sea do not lose their heat to space. The specific heat capacity of water if very high, so the ocean simply stores the heat, then convection ensures fresh colder water gets a chance of further heating. The flues can be over 1000Celsius. By the way, at some points the earths crust is very thin, and at others huge magma chambers are very close to the surface. There is much more of this volcanic activity under the oceans than on land. The average heat flux is not important if you have an efficient heat exchange mechanism in an area of very high heat flux – which you do. 270. Dave Springer says: Willis, I believe you need to explain lunar regolith temperatures a bit more. The temperature of lunar regolith at the Apollo 15 site was measured at an almost constant -23C (day or night) at a depth of 50cm (1). Apollo 15 landed at 26 degrees latitude (2) so it is roughly equidistant from polar and equatorial extremes of solar irradiance. Internal heating is almost nil so the regolith temperature is almost solely reflective (pun intended) of the intensity of solar irradiance and surface albedo. Lunar albedo averages 12% (3) which is lower than the figure you give for the earth of 15% so we should expect the regolith temperature at depth would be even cooler if the surface albedo was the same as the earth. Could you please explain the large discrepancy between average temperatures actually measured on the earth’s airless moon and your theoretical prediction of the earth’s temperature sans atmosphere? Disclosures: I believe the experimental evidence is overwhelmingly against anthropogenic global warming of any adverse significance and what actual AGW there is has a net beneficial effect which in combination with increased CO2 makes for longer growing seasons and higher crop yields. Sure, there are winners and losers on a slightly warmer earth as climate patterns change the winners far outnumber the losers. What is really deserving of alarm is a cooling earth – crops don’t grow well in ice and snow. references: 271. Steve Goddard says: A more realistic view of the amount of warming produced by the atmosphere is closer to 70C – not the 20C claimed in this article. Temperatures in the atmosphere drop linearly from about 280K to 210K as we rise from sea level to 10km, and then remain constant at higher elevations. http://mtp.jpl.nasa.gov/missions/cirex/results.html This gives a lapse rate of 2.1C/1000ft. I remember one summer day in Arizona where I was hiking on dark colored rock in a snowstorm at the top of Humphrey’s peak at 12,000 ft, and later in the day was in 105 F weather in Phoenix. Temperatures varied by about 40C between the two locations, mainly because of the amount of atmosphere above the ground surface at the two locations. Cloud cover also played a role. Planes flying overhead at 35,000 feet would have been in temperatures close to minus 70 F. 272. gbaikie says: “I live by the sea. In the summer air temperatures can be for a month from 37C to 40C the water is below 25C.” I assume you mean the summer high temperatures for a month can reach 37 to 40 C. I live a few miles from the beach- near LA. I used to live in British Columbia on Vancouver Island- there ocean water was well below 25 C- probably something like 10 C. One couldn’t really swim in the ocean [though my uncle and others did a lot of scuba diving in this water]- and there were some beaches where was warm enough- basically the water would warm up when the tide came in. In Canada I lived right on the beach and few times did swim briefly in the ocean at low tide between the shore and the kelp bed- I could feel a sharp difference between the very top layer of water and the rest of the water. Of course having the very top part of the water warm didn’t change the fact that the water was too cold to swim in for any amount of time- unless you worn a wet suit [though I think dry suits were mostly used for scuba diving in this area]. Though swimming in lakes was a different matter- depending the lake but in the summer a lot of them were warm enough. Though with most coastal water the wave action will mix the water temperature- I lived on the east coast of Vancouver Island and if it wasn’t stormy weather the Georgia Straits could be fairly calm water. “At night it is the opposite, particularly in autumn, when the water may be a steady20C while the air drops to 12 and 14C.” There is no doubt there is a difference between ocean temperature and land temperature. Most of Europe and the place I grew up is milder and warmer because of the influence of the Ocean temperatures. Or the place where live now is cooler then say 10 or 20 miles inland- because of the ocean’s influence. And it can get considerably warmer here when there are what’s called Santa Anna wind- a constant air flow lasting for days coming from a land area instead of normal pattern daily ebbing back and forth from ocean to land. “Again I refer to the surface skin temperatures in I went over there, but I don’t know what exactly you referring to. I selected annual and both surface skin and air temperature, but it doesn’t seem to tell exactly what temperature each of the color represent [obviously it’s in Kelvin- that’s not a problem- but they have 12 colors and 4 numbers- I suppose you can sort of get that the global average temperature per that map seemed to be somewhere around 289 K? [[16 C]] but it shows up on my computer as a small map and at pretty coarse scale. 273. Willis Eschenbach says: Glenn Tamblyn (05:13:30) : edit Willis “I don’t know if you’ve ever lived in the tropics, but if you, you would not say they were a third order effect “. Yes, I have lived in a semi tropical environment and locally a Thunderstorm is impressive, visceral, quite emotional. Which is all irrelevent. The question is what percentage transports due to thunderstorms contribute to the total transport over the entire globe. Again, quantitative assessments rather than emotive, local or qualitative ones. Numbers on this one are hard to come by. However, it is known that thunderstorms are what drive the circulation in the Hadley cells, that is to say the global circulation, so your claim that they are a third order effect is risible. 274. Willis Eschenbach says: Bryan (03:25:22) : edit Willis Eschenbach What would you expect a thermopile or some other radiation detector pointed vertically upwards to read(average ball park figure) given these conditions. a. Radiatively insulated to exclude upward radiation. b. In the middle of a desert. c. Two hours before dawn. d. Gentle or stronger wind. This is far from having enough information to answer. What is your point? 275. mkelly says: Francisco (09:31:15) : I know of no experiment done under STP conditions (0 deg C at 1 atm) or standard conditions (59 deg F at 1 atm) that has demonstrated CO2 could increase the temperature of anything. 276. mkelly says: anna v (09:23:56) : Thank you. I got a chuckle from it. That goes along with my CO2 thermos bottle. We should be able to come up with all sorts of CO2 heat increasing items. “Save electricity throw out your old electric blanket and purchase a new CO2 filled comforter. Depending on per cent of fill you can have up to 74 additional watts of heating power per square meter. With a fleece cover that is washable this blanket will be the one you want when winter chill sets in. Purchase now for$29.99 for one but if you order now get two for $45.00. State tax not included.” There is big opportunity out there. 277. James F. Evans says: Brian W (00:44:44) wrote: “As to the sensitivity. CO2 with a specific heat less than N2, O2 and even aluminum, poor absorption compared to air, fast emission and most importantly a concentration of .038% by volume contributes NO sensible (usable) heat to our atmosphere. A doubling of CO2 will not give even .1 degree increase. I wish people would stop fixating on CO2. So the models do overestimate sensitivity by a huge amount. The whole AGW/CO2 thing is a stinking scientific fraud. Period.” Brian W, thank you, in my opinion this is the salient analysis with regards to CO2 in the atmosphere (I’ve raised it here before). There is only one problem with it. It’s too simple and straight-forward: It ends the argument and obviates any reason for further study of the issue. All that is left to study is fixing an upper limit of CO2 animals can properly and healthily respirate over the long term (which in all likelyhood would be rather simple and not require public funding, the life-blood of “modern science”). Even scientists on the sceptical side of the argument seemingly don’t want to acknowledge this undeniable physical reality because all their angles of disputation (and funding) become unnecessary. Needless to say, AGW scientists don’t want to acknowledge this physical constraint, either, as it defeats their arguments in total — no passing “GO”, no collecting$200 (government funding).

Problem: Until, heavy-hitter sceptical scientists write papers outlining this physical reality, AGW scientist won’t bargain against themselves and raise the issue on their own accord.

I’ve stated this issue before here on previous posts, asking to be corrected if I’m wrong, so far no-takers (that I’m aware of).

And, as I’ve stated before, hair-splitting on this parts per million or that parts per million CO2 concentration, is conceding over half the scientific battle and is akin to arguments about the arrangement of deck chairs on the Titanic.

(Just where the AGW proponents want the “game” to be played.)

But that’s where we find most sceptical scientists — arguing about deck chairs on the Titanic.

And, frankly, beyond my suspicions about funding dollars, it’s perplexing.

An old lawyer joke: “One lawyer in the town starves, two lawyers do a thriving business.”

Sure, I maybe wrong — but I’m from Missouri, “show me”.

And, until it is explained why I’m wrong, I’ll keep banging the drum and encourage others to do the same.

278. Willis Eschenbach says:

Glenn Tamblyn (05:08:52) : edit

Willis

“The UN IPCC says that the climate sensitivity is the temperature change divided by the change in downwelling TOA longwave radiation. That is to say, radiation that ORIGINATES at the TOA. So that’s what I have used. If you want to use the upwelling radiation as well you are free to do so … but then you are not measuring climate sensitivity as defined by the IPCC.

What is your source for this. The only definition I am aware of for Climate Sensitivity. whether it be the Charney Sensitivity or others is Temperature change per Doubling of CO2. Basing seisitivity on downwelling radiation levels seems strange. Source please.

Good question, took me a while to dig up the references. You are 100% correct that it seems strange, but there it is. The UN IPCC TAR says (emphasis mine):

Note: In IPCC reports, climate sensitivity usually refers to the long- term or equilibrium, change in global mean surface temperature following a doubling of CO2-equivalent atmospheric concentrations. More generally, it refers to the equilibrium change in surface air temperature following a unit change in radiative forcing (°C/Wm-2).

“Radiative forcing”, in turn, is defined by the IPCC as:

Radiative forcing is the change in the net vertical irradiance (expressed in Watts per square metre: Wm-2) ZMore generally, it refers to the equilibrium change in surface air temperature following a unit change in radiative forcing (°C/Wm-2). due to an internal change or a change in the external forcing of the climate system, such as, for example, a change in the concentration of carbon dioxide or the output of the Sun.

Put them together and you get change in temperature divided by change in downwelling TOA irradiance.

279. Willis Eschenbach

….This is far from having enough information to answer. What is your point?

The conditions add up to eliminating any direct to surface from Sun radiation.
That should then mean that any radiation being measured would be back radiation from the atmosphere.
I’m not looking for an accurate figure just a very rough estimate.

280. Willis Eschenbach says:

Ryan Stephenson (04:33:23) : edit

Willis: It is interesting that one branch of taxpayer funded science woul dhave us believe that geothermel heating has no impact on a planetary body’s surface temperature, whilst another would have you believe that it is sufficient to maintain life on distant moons.

http://www.sciencedaily.com/releases/2009/12/091215141510.htm

Excuses, excuses…. to spend other people’s money.

By the way, the mid-ocean ridges are 40,000km long, are spewing out lava at 1300Celsius along their entire length and have an efficient heat-exchange system called water to distribute the heat evenly over the planet.

Estimates of the total amount of geothermal heat coming through the surface are on the order of 4.2 x 10^13 Watts. However, the surface of the earth is about 5.1 x 10^14 square metres.

This gives a flux of about .1 W/m2. Even if this estimate were out by an order of magnitude, it would still be two orders of magnitude smaller than the solar and “greenhouse” contributions … in other words, a third-order forcing.

281. Willis Eschenbach says:

Francisco (06:10:54)

… I agree. Never understood how this is so trivial.

http://en.wikipedia.org/wiki/Geothermal_power
“The Earth’s internal heat naturally flows to the surface by conduction at a rate of 44.2 terawatts, (TW,)[20] and is replenished by radioactive decay of minerals at a rate of 30 TW.[21] These power rates are more than double humanity’s current energy consumption from all primary sources”

44.2 terawatts = 4.4 * 10^13 watts
Earth’s surface = 5.1 * 10^14 square metres

Heat flux = ~ 0.1 W/m2

282. Willis Eschenbach says:

yusuke (06:30:01)

You can never assume that the downward radiation at TOA and temerparature rise are proportional. It is proven that they are not!!

Well, IPCC says that

(radiative forcing)*(climate sensitivity) = (temperature rise),

but this is because this equation is a first-order equation, which is applicable only when radiative forcing and temperature rise are both small compared to their base values (150W/m^2 and 300 kelvin, in this case).

“Well, my body temperature decreased by 2 degrees after taking 2 tablets of medicine, so my body temp. should reduce by 10 after taking 10 tablets”.

You made exactly same mistake as this statement!!

Please do not decieve innocent people!!

First, if you leave out the exclamation marks!! and the accusations of deception, you are more likely to gain traction.

Next, I am going the opposite direction, from big to small rather than from small to big. To use your example, if my body temp went down 2° after taking 10 tablets, we will likely not be far wrong if we say that two tablets will take it down on the order of 0.2°.

283. Willis Eschenbach says:

Ryan Stephenson (08:05:27)

“geothermal only amounts to something like 0.075/m^2. I checked it when I first got involved in this AGW stuff.”

This calculation is clearly wrong. If it were true then there would be no possibility of lakes under Antartica, but there are. These lakes are created by geothermal heat counteracting the freezing effect of the overlying super-cooled ice.

You are confusing average geothermal heat with the amount of heat directly over some geothermal hot spot. Your claim makes as much sense as saying “The lava coming from Mauna Kea volcano is at 1200°F, so global geothermal heat flux averages must be wrong.”

284. Willis Eschenbach says:

anna v (06:53:24)

Again I refer to the surface skin temperatures in

http://isccp.giss.nasa.gov/products/browsesurf1.html

they are different than the air temperatures. Unless one does the calculation, i.e. integrate over the provided data, one cannot assert that there is no global difference by handwaving.

Anna, thanks for the interesting reference. Unfortunately, their “download data” doesn’t work for me. But by inspection of the graphics, over most of the planet there is very little difference between skin temperature and surface air temperature.

If you can download the gridded data from them, let me know how, and I’ll do the analysis. For now, given the graphics, I say that the difference will only be on the order of a degree or so.

285. Francisco says:

mkelly (11:33:35) : I know of no experiment done under STP conditions (0 deg C at 1 atm) or standard conditions (59 deg F at 1 atm) that has demonstrated CO2 could increase the temperature of anything.
==================

For such a controversial matter as this, the lack of such experiments is appalling. Some may argue they are impossible, but I don’t think so. You don’t need to reproduce the entire atmosphere, or anything remotely resembling that, to get an idea of how doubling or tripling or quadrupling CO2 concentrations in an isolated, open-top column of sunlit (or man-lit) air inside a controlled environment, affects its temperature near the bottom. Or any number of variations along that kind of setup. It cannot be that hard. It seems to me that infinitely more complicated experiments are routinely carried out in other fields.

It also seems to me that if we cannot detect any clear effect on air temperature under such easily measurable conditions, then what on earth are we talking about when we presume that little fluctuations in a quantity called “global mean surface temperature” (which is measured in grotesquely primitive fashion and using impenetrable methods) are the result of significantly smaller increases in CO2 concentration than the ones I mentioned??? None of this makes any sense.

I imagine those kinds of experiments must have been attempted, and if they had yielded any clear results in the desired direction, they would be routinely mentioned by the climate establishment as the empirical anchor to its fantasies. But we don’t see any of that. Nor do we see any attempt to set up such experiments. I wonder why that is.

286. Nemesis says:

O/T but Ive just been watching a re-run of Jeremy Clarkson’s ‘Inventions that changed the world’. In the one about jet engines, he claims that for 3 days after 9/11 when there were no areoplanes in the sky, the earth warmed 1degree during the day and cooled one degree at night. Does this mean that areoplanes rather than cause global warming actually causes cooling ?

287. Willis Eschenbach says:

Leif Svalgaard (08:42:40)

Francisco (08:02:39) :
they attribute all that to changes in surface temperature, and apparently none of it to changes in geothermal heat flux coming up.
And that is correct. If you heat the surface, the heat will propagate downwards too. In fact, one can see the MWP in borehole temperatures as well: http://www.leif.org/research/T-Boreholes.png

Leif, boreholes are an abysmal proxy for temperature. See my post on this question here, and the comments as well, where I show further problems. In particular, see my comment here, where I show boreholes a few miles apart that show radically different temperature histories.

288. daniel says:

This tread is amazing as most interveants are spending so much time making some more or less warranted maths in order to make the so-called consensus model work, whereas this model a) appear flawed from a theretical point of view (Gerlich & T, Robitaille, ) b) is no longer ‘alone’ (Miszolczi, the russian school…), c) so many predictions according to the model are just not to be found in the true life; it’s sad to see so little time spent on the respective merits of Miskolczi or the Russian
Anothe interesting point for the near future is how the contributions of Gerlich & T, Robitaille, Miszolczi, the russian school, the Galactic Cosmic rays assumption (CERN’s CLOUD experience which should fascinate anybody seriously interested in doing physics through acual experiences) will be treated in the frame of IPCC’s AR5, as it’s no longer possible to just ignore all these alternatives to the IPCC’s affirmation that CO2 is responsible because volcanoes and the sun’s irradiance are not
As to Joel Shore announcement of a peer reviewed “comment on G&T” paper, will this be more successful that Smith tentative ? anyway is the paper already available through Arxiv ?

289. Willis Eschenbach (13:38:27) :
where I show boreholes a few miles apart that show radically different temperature histories.
I know, I know, just like temperatures…
But when you average over thousands of them, the statistics gets a bit better.

290. Spector says:

I do not know how valid the 30 percent reflectivity figure is — I would assume it would be measured from space as a long-term average of that fraction of the radiation from the Earth that had the same signature as direct solar radiation without regard for the source of that reflected energy. As such, I presume this is a measure of that fraction the incoming solar radiation that is returned directly to outer space and plays no role in determining the Earth’s climate.

Thus, after reflection, we have an average level of about 239 W/m2 that must be emitted after becoming involved with the thermodynamics of the Earth. Perhaps this could be further reduced by including energy that is captured and released by the upper atmosphere without affecting conditions on the ground. In any case, the Stefan-Boltzmann equation yields a temperature of 255 K or -18 C for this energy flow per unit area. As I see it, this is a reference temperature only — it does not imply what conditions might produce it.

In the presentation of Dr. Miskolczi’s new greenhouse theory, Dr. Zagoni says the difference between this reference temperature and the Earth’s average surface temperature (+15C) is called the Greenhouse Temperature G (33 degrees C.) As such, he appears to be using this as a measure of the current effective thermal resistance or R-factor of the atmosphere.

Dr. Miskolczi has developed a new theory that includes a maximum limit to the greenhouse effect. He is reported to have discovered that the original work on this theory used equations only applied to planets with infinitely thick atmospheres.

291. Willis Eschenbach says:

anna v (13:59:37) : edit

Re: Willis Eschenbach (Mar 18 12:57),

in http://isccp.giss.nasa.gov/products/browsefmt.html they describe the various data

and on the main page next to the download data button they have choice of format, so choosing ASCII one gets a table .

I tried that before. All that it downloads is a page saying

“This script should be referenced with a METHOD of POST.
If you don’t understand this, see this Forms overview.”

An attempt to go to the referenced web page gives me a 404 error.

I tried with both Safari and Firefox and I get nothing … what’s your secret?

w.

292. James F. Evans says:

In this thread there has been reference to IPCC definitions like ‘radiative forcing’ and ‘climate sensitivity’ and some values attached to those definitions, therefore, those definitions and values have been incorporated in various papers.

But there is a problem with that: Namely, that a presupposition exists that these are accurate and useful definitions and values.

Given the track record of the IPCC and it’s agenda & outcome driven processes, one is left to question that accuracy of such standards.

Sure, don’t use or abide by what the IPCC sets up and your paper won’t get into the IPCC report, but if they are flawed requirements then being constrained by these requirements garantees the papers, while jumping through the IPCC’s hoops, won’t reflect actual physical reality:

And, isn’t reporting on what is actually happening more important than being properly constrained by arbitrary IPCC standards?

Or is it simply about playing the game as the rule master dictates…damn the reality?

293. Willis Eschenbach says:

Leif Svalgaard (14:24:31)

Willis Eschenbach (13:38:27) :
where I show boreholes a few miles apart that show radically different temperature histories.

I know, I know, just like temperatures…
But when you average over thousands of them, the statistics gets a bit better.

1. Contrary to your claim, temperatures are well correlated, particularly over short distances. It is very unusual to find two sites a mile apart where one is cooling and one is warming.

2. While the theory that “the data is wildly differing over short spatial scales but the average is valid” is an interesting one and is sometimes true, we cannot assume that it is true. I encourage people to take a look at the five adjacent Czechoslovakian boreholes here, and think about whether averaging those and a hundred more like them will give a valuable answer …

294. Francisco says:

Willis Eschenbach (12:26:45) :
44.2 terawatts = 4.4 * 10^13 watts
Earth’s surface = 5.1 * 10^14 square metres
Heat flux = ~ 0.1 W/m2
================

Yes, assuming the 44 terawats are right. I have no idea how that is measured.

However that may be, the above conversion has lead me to another surprising perspective.

If total human energy consumption is about 15 terawatts, then this would translate to ~ 0.3 W/m2.

So let’s think about the meaning of this. If we dedicated ALL the energy we consume to the exclusive purpose of heating the earth’s surface *permanently* from underneath using the most efficient means at our disposal — the warming effect would be barely noticeable.

On the other hand, if we just take a gas that happens to be released as a byproduct of our energy use — the same gas that is exhaled by the biosphere and and the oceans in quantities that are orders of magnitude larger than our contribution — and let it go in the air, the result of the concentration increase in this gas putatively attributed to our modest exhalations, is supposed to be a surface warming many, many, many times larger than what we could ever achieve by using all that energy permanently and directly for heating the surface as hard as we could.

When I look at it in this perspective, I find that extremely bizarre. Which is why I would like to see some piece of empirical evidence, no matter how primitive, of this marvel at work.

295. Francisco says:

Francisco (16:25:37)
Of course I meant 0.03 (not 0.3) W/m2.
Sorry.

296. brent says:

The science of climate change
The clouds of unknowing
There are lots of uncertainties in climate science. But that does not mean it is fundamentally wrong
http://www.economist.com/displayStory.cfm?story_id=15719298

The Economist should reflect on the Wegman equation:

Of course “answer correct” in this context means “politically correct”

brent’s amendment to the Wegman Equation follows”

Method Wrong + Answer (Politically) Correct =”Post Normal Science”

Post Normal Science = Sceance

cheers
brent

297. Alan D McIntire says:

“Another point, Using Trenbeth ballpark figures, if we get 240 watts from the sun, and the greenhouse effect makes that an effective 390 watts and a 33 C increase, isn’t the increase in temperature per delta watt increase in the ballpark of
33 C/(390-240) = about 0.22C per watt increase?”- AMC

“No, no, no. I’ll keep going over this until everyone gets it. According to the UN IPCC, climate sensitivity is the change in surface temperature divided by the change in TOA forcing … yes, I know, it’s a really dumb measurement, but there it is. I suspect it was specifically chosen by AGW supporters because downwelling TOA radiation can’t be measured directly … but perhaps that’s just my paranoia speaking.”- Willis Eschenbach

I REALIZE climate sensitivity would be delta surface temperature divided by delta watts at surface, but I believe the 33c/150 watts gives an upper limit ballpark figure.

With NO forcing, the earth’s temperature would be 33 C lower, radiating at 240 watts. Those additonal 150 watts have been pumped into earth’s atmosphere, gradually warming the earth at a lower and lower rate. The total warming was 33C, the total additional sensible wattage was 150 watts, so the average sensitivity over the full range of 240 to 390 watts was
33C/150 watts = 0.22C. It stands to reason that ACTUAL climate sensitivity should be less.

The Stefan-Boltzmann equation for a blackbody goes

T(degrees Kelvin) = S(constant)*(watts/square meter)^0.25. Our first step is to find that S constant.

Doing a google search, I find 1000 K implies a blackbody flux of 56790 watts/square meter.

1000K = S* (56790 watts/square meter)^ 0.25. Click on your calculator and use the scientific view. Plug in 56790
X^Y
0.25
=
and you get 15.43718 Divide 1000K by 15.43718 and you get S = 64.77867

We now know
T(kelvin) = 64.77867 ( watts/square meter)^0.25.

Let’s plug in some numbers.

At 100 watts per square meter flux,

T = 64.77867 * 100^0.25 = 204.848 K, at 400 watts per square meter,
T = 64.77867 * 400^0.25 = 289.699 K

T = 64.77867 W^0.25. From elementary calculus, the derivative of that
equation will give you the sensitivity.

dT/dW = 64.77867* 1/4 * (W^(-3/4)) = 64.77867*1/4 * (1/(W^0.75)).

At 100 watts/sq meter, you get a sensitivity of
64.77867*1/4*(100^-0.75) = 64.77867*0.25* 0.0316228= 0.512121 K/watt per meter squared

At 400 watts/sq meter, you get a sensitivity of
64.77867*1/4 *0.01118034 = 0.181062 degrees K per watt per meter squared.

My above example was equivalent to
taking (289.699-204.848)/(400-100) and getting an “AVERAGE” sensitivity of 0.283 K/watt- note that this is higher than the “actual” sensitivity of 0.181 once we’ve reached 400 watts. The earth is not a blackbody, but the reasoning should be the same, that “AVERAGE” sensitivity of 0.22 C must be larger than the current sensitivity with a surface 390 watts.

298. sky says:

Willis Eschenbach (00:03:04):

You claim to have accounted for atmoshperic pressure. I’d like to see where! All the cartoonish schematics (not just yours) show only power fluxes–not enthalpy calculations–presented in an disconnected way, contradicting Kirchhoff’s current law. Furthermore, the figures for the flux of latent heat seem to be land-based, rather than accounting for the oceans, where evaporation exceeds upwelling IR radiation and conduction combined. Sorry, but that’s just not a physically cogent exposition of the “budget” of the Earth’s climate sytem.

299. Joel Shore says:

daniel says:

As to Joel Shore announcement of a peer reviewed “comment on G&T” paper, will this be more successful that Smith tentative ? anyway is the paper already available through Arxiv ?

I am not sure what you mean about “more successful” in regards to Arthur Smith’s paper. I think that his paper was very nice, but because at the time that he wrote it G&T had not yet gotten their paper published in a peer-reviewed journal, Arthur did not even try to submit his. (It is very hard to get a paper published in a peer reviewed journal that just rebuts nonsense floating around on the internet. Arthur pretty much admits in the introduction that his paper does not really break significant new ground but just clarifies well-understood science in light of G&T’s confusions.)

Also, Arthur focused on one aspect of G&T’s claims (the supposed “fictitiousness” of the calculation that the greenhouse effect warms the earth’s surface by about 33 C), whereas our comment on G&T addresses a broader array of aspects of their paper, including the central claim that the atmospheric greenhouse effect somehow violates the 2nd Law of Thermodynamics. Our paper is not yet available on the Arxiv although it may be up there before too long.

300. Alan D McIntire says:

Sorry, I meant to agree with W.E. and state, “I realize forcing shold be delta T at surface divided by delta watts at TOP of atmosphere.

301. Willis Eschenbach (16:16:56) :
1. Contrary to your claim, temperatures are well correlated, particularly over short distances. It is very unusual to find two sites a mile apart where one is cooling and one is warming.
That’s where careful cherry picking comes in.

Boreholes: I saw this guy’s presentation: http://adsabs.harvard.edu/abs/2009AGUFMPP53A..10C
And couldn’t put a finger on where it was wrong, so he convinced me.
This study looks solid too: http://home.badc.rl.ac.uk/mjuckes/mitrie_files/docs/mitrie_borehole.pdf
Unfortunately it shows global warming so many would reject it just on that, regardless of the merit of the method.

302. Brian W (09:20:12) :

The bits about electromagnetic radiation and the atmosphere are spot on the money. Above roughly the 10 meter band or 30 megahertz the atmosphere becomes transparent to radio waves.

To a point; even energy in the 52 or 146 or 432 MHz ranges can become affected or susceptible to ‘action’ by the atmosphere *and* the ionosphere. I won’t go into other effects e.g. Faraday rotation: rotation of the plane of polarization of a linearly polarized wave propagating through a magnetized dielectric medium – that can be seen at GPS frequencies in the L-band (1.2 and 1.5 GHz) .

THEN there is an ‘opaqueness’ in the atmosphere that sets in at wavelengths shorter than 1 cm (above about 30 GHz) .

Click my name to see a chart.

.
.

303. Tsk Tsk says:

Leif,

You’ve over constrained the system or at least implied that the emissivity of the two objects is identical even though one of them clearly isn’t a black body. Take out the nuclear reactor and start with identical temperature spheres but with different emissivities because one of the spheres is not a black body. We’ll return to the case where there’s internal heat generation, but for now simply rely on the internal energy of the two spheres giving them equal temperatures. BTW, I don’t really understand the electron acceleration comment. That sounds like bremsstrahlung to me which isn’t black body radiation at all. Anyway…

Here’s a simple way to look at the problem. Let’s turn the spheres into two parallel semi-infinite walls separated by a vacuum. The only way these walls can lose heat is to radiate it to each other. Let’s also say that the white wall has an emissivity and therefore absorptivity of 0.5 and the black wall is a perfect black body with emissivity of 1. And yes, let’s make the emissivity a wavelength independent quantity because I’m lazy. To avoid messing around with constants and T^4 let’s also say that the black wall is of such a temperature as to radiate 10 W/m^2 at its initial state. Since the white wall has the same temperature but half the emissivity, it emits 5W/m^2. Now let’s look at the energy balance for the two walls. The white wall is exposed to 10W/m^2 incoming radiation of which it absorbs half, 5W/m^2. The other half is reflected back toward the black wall It also emits 5W/m^2 of its own radiation for a net heat transfer of: 5-5=0W/m^2. The black wall emits 10W/m^2. It receives 5W/m^2 generated from the white wall and 5W/m^2 of its own radiation reflected back for a net heat transfer of: 5+5-10=0W/m^2. So, two bodies at the same temperature and different emissivities do not have to radiate the same amount and can still be in radiative equilibrium at the same temperature. No work can be done. Entropy is constant. Carnot is happy. Maxwell is happy. And his demon sleeps.

To return to your example, unless the emissivities are the same, then the problem you framed is not in steady state. If the same amount of energy is being produced in both spheres and they have different emissivities, which they will since they are different colors and hence absorb/emit differently, then the white sphere is only temporarily at 400C on its way to its final temperature. Put another way your white/green/blue sphere can’t be a black body, but it will still emit according to Planck’s law albeit with a sub-black body emissivity.

304. Joel Shore says:

Francisco says:

So let’s think about the meaning of this. If we dedicated ALL the energy we consume to the exclusive purpose of heating the earth’s surface *permanently* from underneath using the most efficient means at our disposal — the warming effect would be barely noticeable.

On the other hand, if we just take a gas that happens to be released as a byproduct of our energy use — the same gas that is exhaled by the biosphere and and the oceans in quantities that are orders of magnitude larger than our contribution — and let it go in the air, the result of the concentration increase in this gas putatively attributed to our modest exhalations, is supposed to be a surface warming many, many, many times larger than what we could ever achieve by using all that energy permanently and directly for heating the surface as hard as we could.

Why is that all that surprising? As many people have noted, the amount of energy that we use in miniscule compared to that supplied by the sun. Hence, a much more efficient way of causing heating of the earth is to change the atmospheric chemistry so that more of that energy from the sun is retained, rather than simply heating it directly ourselves.

By the way, when you say, “the same gas that is exhaled by the biosphere and and the oceans in quantities that are orders of magnitude larger than our contribution”, you are neglecting the other side of the equation – that it is also inhaled by the biosphere and oceans in these large quantities. And, the exchange is only large with the mixed layer of the ocean. The exchange between the mixed layer and the deep ocean is quite a bit smaller…and that is the rate-limiting step. The mixed layer + biosphere + atmosphere are just passing the same carbon around and around. We are taking a quantity of carbon that has long been locked away from the atmosphere and rapidly liberating it into this system.

305. cba says:

willis,

sorry but i’m out of town again and have limitations on access to things. I tried to go through the erbe etc. paper you referenced looking for the 0.123 clear ssky albedo. It occurred to me that perhaps there is more clear sky over land than ocean or something to that effect. Putting the number 0.123 in to the spread sheet indicates essentially a requirement of 0.32 land surface albedo and a 0.38 cloud albedo. 0.32 seems rather high, only snow and sand produce this and there’s not that much of those around. the 0.38 (or even 0.44 assuming surface is 0.085 or so) seems rather realistic. Hopefully, I can get some time to go through that erbe paper in detail.

306. Joel Shore says:

Much as I’d like to do this all the time, I do have a life. Anyhow, 11 PM here, I’m back in the saddle.

Sorry…I didn’t mean to be impatient. I just wanted to make sure that you saw my post amidst everything else.

Joel, the 150 W/m2 is what I estimate as the TOA downwelling forcing. See Figure 1 above. Kiehl/Trenberth give a higher figure, but their diagram is not physically possible. But use either number, it doesn’t matter.

This number perforce includes everything. It includes whatever water vapor feedback (or forcing) exists at the current earth temperature. It includes the cloud feedbacks (or forcings) that exist at the current earth temperature. By definition, it includes each and every feedback that exists, known and unknown, measured and unmeasured.

Since the sensitivity for a doubling of CO2 is 3.7*?T/?F, that gives on the order of half a degree for a doubling of CO2.

Ah…but therein lies the problem. All those enter into what you are saying the forcing is…but then when it comes time to calculate how this relates to CO2, you say that doubling CO2 produces a forcing of 3.7 W/m^2. That is not correct. In your first calculation (the 20 C divided by 150 W/m^2), you have called everything a forcing whereas in the second calculation you have called everything a feedback except for the change in CO2.

Let me give you a concrete example: Suppose that the increase in CO2 directly is responsible for 30 W/m^2 of forcing in the current climate due to CO2’s IR absorption and the water vapor is responsible for the other 120 W/m^2 due to its IR absorption (and, for simplicity, we just ignore everything else). Now, suppose that the water vapor feedback works in such a way that if we removed all the CO2, the feedback processes would be such that all of the water vapor also disappears (again, I am not claiming this is true…but just supposing so).

In that case, then to get the climate sensitivity due to changing CO2, I think you would agree that you should divide the 20 C change by 30 W/m^2, not the full 150 W/m^2. But, alas, that is not what you have done.

To put it another way, when the IPCC says that the central estimate for climate sensitivity is 3.0 C (with an assumption that doubling CO2 produces a TOA forcing of 3.7 W/m^2), they are not predicting that the TOA downwelling radiation will be increased by only 3.7 W/m^2 if you double CO2. What they are saying is that the direct effect of the IR absorption by CO2 will be to increase the TOA downwelling radiation by 3.7 W/m^2 but that the total increase, once you consider all the feedback effects will be an increase in the TOA downwelling radiation by almost 3 times this (where I am using the result that a 3.7 W/m^2 increase in TOA downwelling radiation produces a temperature rise of about 1 C, as calculated by the S-B Equation).

It would be a violation of radiative balance to claim that a 3.7 W/m^2 increase in downwelling radiation would produce a 3 C increase in temperature! We know from the S-B Equation that this is not the case.

The one thing that admittedly remains a mystery to me is why your calculation of the climate sensitivity in the way that you did it does not just come up with the value for climate sensitivity determined by the S-B Equation in the absence of any feedbacks, which is what I think it ought to get. So, I am still confused about whether the 150 W/m^2 is what you actually wanted to use, but I will have to think more about that.

PS – I note that someone above called you “Troll Shore”. Folks, I’ve got good news and bad news. Joel is a physicist, understands the math, and is one of the few AGW supporting trained scientists with the balls to post here. So cut out the personal attacks. They are repulsive in any case, and totally unmerited in Joel’s case. I disagree with him a lot, but he is absolutely not a troll.

Thanks, Willis (and anna v). I appreciate it.

307. Tsk Tsk (18:34:25) :
then the white sphere is only temporarily at 400C on its way to its final temperature.
The 400C is its final temperature, once the white and the black sphere have reached a final same temperature, they both have the same thermal spectrum. Every opaque body radiates a thermal spectrum determined by its temperature. The balls are in empty space far VERY from each other and from anything else. And do not exchange [measurable] radiation with each other or with anything else.

308. Tsk Tsk (18:34:25) :
I don’t really understand the electron acceleration comment
From a different view [more modern and more ‘correct’ view], electrons in atoms are ‘excited’ by thermal motions; when the atom relaxes [excited states have finite – short – life times], the electrons return to a lower state emitting photons in the process.

309. Brian G Valentine says:

Jim writes, “Can you point to an article or source where this is actually measured (the quantitative measurement of atmospheric radiation of ‘heat’ energy ostensibly removed from the surface via convection)?”

Thank you for pointing that out, Jim, I have been trying myself to address that, I am sorry I don’t have a reference for you. That’s a good observation

Brian W, that’s a good comparison. Note that the ionosphere (Kenelly-Heaviside layer) acts as a deus ex machina to overcome the curvature of the Earth so far as short wave radio transmission is described by the laws of electromagnetic propagation; there’s no such associated “outside influence” as far as thermal IR transmission is concerned (1-30 micrometer radiation), and Gerlich and Tscheushner must be correct. (Look at the “wrong” description of how the “greenhouse” effect supposedly “works”.)

The Trenberth “analysis” is nothing more than some Enron-type bookkeeping to give an extra 1 w/m**2 or so (on the disc) that he wants to present as “overheating” the world from Greenhouse gases. It isn’t observed by satellites measuring incoming and outgoing radiation (which balance), but what the hell. It serves the purpose of overheating some temperaments and some egos, which the what the construct was really ever designed for

310. Dave Springer says:

The moon couldn’t possibly be a better experimental setup for isolating the atmosphere as a variable in average surface temperature, we put temperature sensing instruments on it decades ago, have years of data from them, and yet almost everyone here is ignoring this hard data.

Would someone please put forward an hypothesis which explains subsurface lunar regolith temperature. Any hypothesis must explain these observed temperatures to be at all credible. From what I can determine from experimental evidence the earth’s atmosphere accounts for a minimum of 30C warmer surface temperature.

311. Brian G Valentine says:

The Moon’s reflectivity is known to be partly specular in the visible, since the Moon appears uniformly bright from center to limb as viewed from the Earth. Is it this reflectivity in the visible is the same reflectivity through the thermal IR? I don’t know.

I can’t answer your question about the Moon, Dave, but I can give you a calculation that shows the thermal exchange temperature of the Earth with the Sun is about 279.5K, and and we also know that the Earth may be viewed as a radiator at a temperature of about 288K, other than that, I don’t know what to say about the 30K warmer figure

312. Tsk Tsk says:

Leif,

Again, you’ve over constrained the problem. The ball cannot be white and a black body. What makes it white? Clearly it does not absorb all incident light and therefore it cannot emit perfect black body radiation. You’re right that every body radiates a spectrum based on its temperature and based on its emissivity. You keep leaving that part out. By your definition every object is a perfect black body (emissivity of 1) and the only thing that matters is its temperature. That’s simply not correct. Fluke has some pretty graphs to demonstrate the impact of emissivity on measured temperatures using an IR thermometer: http://www.hartscientific.com/publications/pdfs/3187781_A_w.pdf

I placed the two spheres/walls in proximity to counter your claim that different amounts of radiation from the two objects would allow you to extract work and therefore that proved that the two objects must be emitting the same amount of radiation. What I showed was that there is no net heat transfer and no way to extract work from the transfer of heat from two bodies at the same temperature but different emissivities emitting different amounts of radiation.

I understand the emission of photons comes from electrons transitioning between different states. I’ve just never heard acceleration used to describe the process, but then again quantum was a long time ago and I spend most of my time on magnons and not phonons these days.

313. Bill Illis says:

The 3.0C per doubling sensitivity comes from the following:

– doubled CO2/GHGs add 3.7 to 4.0 W/m2 of forcing at the tropopause emission layer where it is 255K (sometimes they call this the TOA forcing but the top of the atmosphere is much warmer than this level – it is really the tropopause at about 5 kms up but they often mix this up to keep people off balance);

– then there is feedbacks from increased water vapour and albedo which add another 6.5 to 7.4 W/m^2 after this initial forcing;

– the layer now increases in temperature by 3.0C (11.5 extra watts on top of the original 240 watts).

– the layer where the equilibrium emission temperature of 255K occurs is now 461 Metres higher.

– the adiabatic lapse rate of 6.5C/km stays intact and the surface warms by the same 3.0C.

So, the sensivitiy is calculated as 4.0 extra watts of GHG forcing eventually results in an increase of 11.5 watts (once all feedbacks occur) and temperatures at the surface rise 3.0C.

So, the theory calculates 0.75C/W/m2. It takes the Planck Response of 0.265C/W/m2 (the Stefan-Boltzmann Dtemp/Dforcing for 255K or 240 W/m2) at the tropopause and multiplies it by another 134% in feedbacks to arrive at the final sensitivity.

Its a theory based on some principles. But theories need to have factual empirical data behind them.

314. anna v says:

The two links connecting directly to the images I gave in my first post give this message you quote. I did not put a correction because the main page was linked also in the same post.

anyway:

I use Firefox with windows XP

“select variable” example: mean surface skin

select a time period : Mean annual

select a format: EQ grid; Ascii text

I find the file in my download area labeled with sequential numbers.

No other secret except in persisting if I get a “not found”.

the differences. between skin and air are large in the cold and hot places. I do not know if they would integrate out. I have not learned to use EXCEL for plot making :( . Maybe I should start.

315. Tsk Tsk (21:25:20) :
By your definition every object is a perfect black body (emissivity of 1) and the only thing that matters is its temperature.
Did not say that, I said that maintained at the same temperature the radiations would be the same.

I’ve just never heard acceleration used to describe the process, but then again quantum was a long time ago
Since we were talking blackbody and S-B laws in a 19th Century [pre-quantum] setting I stayed in that framework. You can even say that electron transitioning [to stay in a Bohr model] from one orbital to another is a change of velocity and hence an acceleration, but hose details are not really necessary and at a deeper level that is not how it works anyway [but we often use pictures based on incomplete models if they are useful]

316. Brian G Valentine says:

I understand where this is coming from, Bill, but where I (and apparently Gerlich and Tscheuscher and a lot of others) have the worst difficulty, is accepting the idea that the “atmosphere” is “warming” the “surface”.

Either that idea violates the Second Law or it doesn’t. If someone could just present ONE parallel example to show this is at least possible, then I would not say that Gerlich and Tscheusher’s analysis is as good as anyother application of the Second Law

317. F. Ross says:

Very interesting post Mr. Eschenbach; it is great to see the varied, open air give and take between you and and the variety of posters who question several of your points.

I enjoyed reading, if not fully understanding, nearly all the posts and your responses to them.

Infinitely more interesting than anything on the boob tube. Thanks.

318. Mike McMillan says:

Brian W (01:59:09) :
Steve Goddard (23:47:55)
The shell of your airplane heated due to air friction! Blankets indeed!

Blankets. The air friction at 35000 ft is the same as 5000 ft is the airplane is flying at the same indicated airspeed, and airliners do stay in a fairly small range of indicated airspeeds. The thinner air up high requires they fly a much faster true airspeed for the wings to generate the lift, but the dynamic pressure the airplane feels is about the same.

319. anna v says:

I understand where this is coming from, Bill, but where I (and apparently Gerlich and Tscheuscher and a lot of others) have the worst difficulty, is accepting the idea that the “atmosphere” is “warming” the “surface”.
Yes.

http://discover.itsc.uah.edu/amsutemps/execute.csh?amsutemps+001

At 36000 feet (15km) temperatures play between -47.5 to -46.5.
at 14000 feet (5km) -21.5 to -19.5
near surface 20.8 to 21.5

Now basic thermodynamics says heat is not transferred from a cold body to a hot body without work being done. That is elementary . CO2 is not doing any work ( running a compressor circuit, at least it has not been shown as such).

The earth is a macroscopic body. There is absolutely no reason not to calculate everything within classical thermodynamics : there are no coherent phenomena and radiation is included in classical thermodynamics. If one wants to calculate the effect of a change in the composition of the gas, one has to calculate the effect of the change in the heat capacity of the medium, to see what happens in the heat transports.

The confusion with the quantum mechanical guts of the molecules of the atmosphere is what , in my opinion, makes for double counting.
One can work with quantum statistical mechanics, but then one should use that formulation throughout, making statistical ensembles and studying their evolution etc. Mixing two techniques over the same material creates the contradiction.

320. Spector says:

Perhaps one method of calculating climate sensitivity to some parameter, like increasing CO2 concentration, would be to calculate how much a very small step change in the controlling parameter would change the effective Stefan-Boltzmann temperature of the total energy that escapes from the top of the atmosphere. I suspect the negative of this change might give the surface temperature change required to make up the difference.

Of course this would all assume that we knew how to make such calculations in the first place.

321. cal says:

Lief
Tsk Tsk

Tsk Tsk has my vote on this one. Lief, you define the two spheres as having a temperature of 400 but you also imply that the spheres as have equal power generation. If these two are defined then they must have identical heat losses equal to the power generated, for the temperature to remain constant. But you also define them as having different emmissivities (one is black and one is white). You cannot define all these three as being true. As Tsk Tsk says the system is overdefined. Tsk Tsk also clarified the point that good absorbers are good emmitters and vice versa so that energy laws are not violated.

322. Willis Eschenbach says:

Leif Svalgaard (18:03:44)

Willis Eschenbach (16:16:56) :
1. Contrary to your claim, temperatures are well correlated, particularly over short distances. It is very unusual to find two sites a mile apart where one is cooling and one is warming.

That’s where careful cherry picking comes in.

I don’t know if that’s humor or not … I hope it is.

Boreholes: I saw this guy’s presentation: http://adsabs.harvard.edu/abs/2009AGUFMPP53A..10C
And couldn’t put a finger on where it was wrong, so he convinced me.

Perhaps you could explain what he means by:

(5) The synthetic borehole-temperature calculation requires a precondition temperature prior to the start of the proxy information that we designate as the pre-proxy mean (PPM) temperature. PPMs, representing baseline temperatures prior to the beginning of the reconstruction, are between 0.7 and 0.9 K below the year 2000 temperature.

Also, I looked at the site he discusses, the University of Michigan Boring Hole Site or whatever it’s called. Here’s what they say:

Now, the error given for the HadCRUT3 dataset, which uses actual temperatures, is about two tenths of a degree in 1850 … and these guys want me to believe that they can look in boreholes that have wildly varying temperature profiles and give us the temperature 500 years ago with an error of a tenth of a degree???

You’re welcome to believe that, Leif, perhaps you’re like the Red Queen who believes six impossible things before breakfast. I’m not that skilled, I’ll pass.

This study looks solid too: http://home.badc.rl.ac.uk/mjuckes/mitrie_files/docs/mitrie_borehole.pdf
Unfortunately it shows global warming so many would reject it just on that, regardless of the merit of the method.

It appears that you believe the canard that skeptics don’t think the earth is warming. Most skeptics I know and respect believe it is warming. So why would we reject something that shows the earth is warming? I reject it for other reasons.

Juckes and the Mitrie project are unethical imitations of scientists. Inter alia, they put up a paper and invited public comment, saying that they would consider the comments before publishing it. I and a number of others put a lot of time into it, uncovered serious scientific flaws in the claims, and then they just blew us off and published anyhow. Plenty of information here on their scientific malfeasance.

So I’ll pass on that one too. It’s just another puff piece from UMich, repeating their claim of a tenth of a degree accuracy a half a millennium ago. That claim doesn’t pass the smell test, and I’m astounded that you would recommend a paper claiming that accuracy.

Finally, I note that your borehole reconstruction shows the Medieval Warm Period, and theirs shows nothing of the sort … which one is wrong? Yours is about a degree different from theirs back 500 years, and they claim an error of 0.1°C … I’m sure you can see the problem.

323. Willis Eschenbach says:

Joel Shore (19:30:38)

Joel, the 150 W/m2 is what I estimate as the TOA downwelling forcing. See Figure 1 above. Kiehl/Trenberth give a higher figure, but their diagram is not physically possible. But use either number, it doesn’t matter.

This number perforce includes everything. It includes whatever water vapor feedback (or forcing) exists at the current earth temperature. It includes the cloud feedbacks (or forcings) that exist at the current earth temperature. By definition, it includes each and every feedback that exists, known and unknown, measured and unmeasured.

Since the sensitivity for a doubling of CO2 is 3.7*?T/?F, that gives on the order of half a degree for a doubling of CO2.

Ah…but therein lies the problem. All those enter into what you are saying the forcing is…but then when it comes time to calculate how this relates to CO2, you say that doubling CO2 produces a forcing of 3.7 W/m^2. That is not correct. In your first calculation (the 20 C divided by 150 W/m^2), you have called everything a forcing whereas in the second calculation you have called everything a feedback except for the change in CO2.

Let me give you a concrete example: Suppose that the increase in CO2 directly is responsible for 30 W/m^2 of forcing in the current climate due to CO2’s IR absorption and the water vapor is responsible for the other 120 W/m^2 due to its IR absorption (and, for simplicity, we just ignore everything else). Now, suppose that the water vapor feedback works in such a way that if we removed all the CO2, the feedback processes would be such that all of the water vapor also disappears (again, I am not claiming this is true…but just supposing so).

In that case, then to get the climate sensitivity due to changing CO2, I think you would agree that you should divide the 20 C change by 30 W/m^2, not the full 150 W/m^2. But, alas, that is not what you have done.

If I am following your argument, you misunderstand the “per CO2 doubling”. This is just how the IPCC tends to measure climate sensitivity. It has nothing to do with how much of any given forcing is from CO2. It is merely a unit of measurement.

For example, we could say that climate sensitivity is 1°C/W-m2, or we could say that climate sensitivity is 3.7°C / CO2 doubling. There is absolutely no difference between those statements. They are just expressed in different units. The conversion factor is

1 CO2 doubling = 3.7 W/m2

or

1 W/m2 = 0.27 CO2 doublings

So we can convert from one unit to the other, and it means nothing about whether we are talking about cloud forcing or H2O forcing or CO2 forcing. It’s just different units.

324. Willis Eschenbach says:

Brian G Valentine (22:12:19)

I understand where this is coming from, Bill, but where I … have the worst difficulty, is accepting the idea that the “atmosphere” is “warming” the “surface”.

Once again, see my post, “The Steel Greenhouse”. It shows that the greenhouse effect has nothing to do with gas, or lapse rate, or any of that. If you have problems with the concepts there, let me know.

w.

325. Joel Shore (17:27:26) :

daniel says:

As to Joel Shore announcement of a peer reviewed “comment on G&T” paper, will this be more successful that Smith tentative ? anyway is the paper already available through Arxiv ?……

Looking forward to reading your paper but I have to agree with Daniel that the previous so called refutations of G&T have backfired.
I would invite anyone who has any doubts on the matter to go to Arthur P Smith website and the thread “the arrogance of Physicists”.
Arthur has great difficulty coping with Fred Staples and Terry Oldberg never mind G&T

326. Willis Eschenbach (01:56:43) :
“That’s where careful cherry picking comes in.”
I don’t know if that’s humor or not … I hope it is.

It was not. You can [and did] pick two close boreholes that give different results. That is the cherry. For it not to be cherry picking you will have to show that any two close boreholes are always wildly different, which they are not.

Finally, I note that your borehole reconstruction shows the Medieval Warm Period, and theirs shows nothing of the sort … which one is wrong?
One only went back to 1500, so cannot show the MWP.
The error bar is probably calculated from the spread of the 837 individual reconstructions. Let that be, typically [go look at several] 3 degrees, then the usual 1-sigma error of the mean would be 3/sqrt(836) = 0.10 degrees. You can find the individual reconstructions here http://www.ncdc.noaa.gov/paleo/borehole/core.html

I do believe [Red Queen-like] the borehole technique is sound. This does not guarantee that all applications of it are.

327. beng says:

********
HankHenry (19:12:32) :

Willis tells us “The average temperature of the planet is about 14°C.” Of course that’s disregarding the massive cold of the ocean which is more like 4°C – averaged out. What is it that makes the oceans so cold? Two miles down on the continents the earth is quite warm, but two miles down in the oceans it’s quite cold. It suggests to me there is a refrigeration process of some sort extracting heat from the depths. Also, do I remember my grade school science correctly when I say the total mass of the atmosphere is represented by the mass of just 33 feet of water – the theoretical lifting limit of a suction pump?
********

No, it’s rather simple physics — the earth’s crust (in this case, the sea bottom) is a very good insulator because of its thickness. And, surprisingly, the warmer water above the cold-water layer is also a good insulator because of its thickness and also the water’s general stratification (little mixing).

The cold water is there because cold meltwater from glaciers and exposure to arctic air causes it to sink, and is then preserved below by the insulation above and below it. The cold water would eventually warm up, but it’s being replaced by more cold water continuously, so a equilibrium situation arises such as we observe. The cold deep-water is a reminent of the previous ice-ages.

Heat conduction is a feeble way to transfer heat compared to convection and even radiation, especially when there is little mixing (stratified).

328. Dave Springer says:

Brian Valentine

I don’t understand why you responded since you had nothing to offer in way of explanation why the constant subsurface temperature of lunar regolith in the middle latitudes agrees very closely with the oft-cited figure of the earth being heated approximately 30 degrees celsius through greenhouse gases.

There are many studies of the optical properties of lunar regolith available. It isn’t exotic material of any sort and that shouldn’t be surprising given the moon is made of the same material as the earth. Lunar regolith is generally darker than earth surfaces because “space weathering” of the soil darkens it. Fresh impact craters have bright rays coming out from them because it is newly exposed regolith which has yet to be darkened by space weathering.

I believe the data from the Apollo experiments thoroughly disproves Willis’ hypothesis of only 8 degrees celsius heating from GHG. His continued silence on it I’m taking as a tacit admission that he can’t account for it and rather than admit an error is choosing to simply ignore the inconvenient data. I had thought hiding contrary data that doesn’t agree with theoretical model predictions was a tactic used by the AGW alarmists. I’m very disappointed to see it being employed by the anti-alarmists.

329. Francisco says:

Joel Shore (18:35:55) :

Well I should have emphasized that I find it “surprising” only if I force myself to look at things in a certain innocent way.

Regarding our release of carbon that had been locked away… just like you point out that our energy use is tiny compared with what we get from the Sun, I shall point out that our release of carbon is also tiny compared with the vast transactions between the different parts of the system. This NASA chart of the carbon cycle is illustrative for piece of mind, if viewed with proper calm:
http://nasascience.nasa.gov/earth-science/oceanography/ocean-earth-system/ocean-\carbon-cycle

From that chart, you see that total amount of carbon in the extant fossil fuels still in the ground is roughly 1/8 the amount of carbon in the active system. The amount we are recycling annually back into the system is about 0.015% of the total carbon in the system.

The cause for alarm, it seems to me, comes only if you adopt the assumption that our modest recycling program represents a very grave disturbance to a static and balanced system, whose balance coincides with its state around 1850. I consider this assumption to have no rational or scientific basis whatsoever. It is merely ideological.

To begin with, the carbon we are releasing was once part of that dynamic system. We are recycling it back into life at what appears like a reasonable rate.

A few years ago there was some talk of a “missing sink” to refer to the apparently surprising fact that about half the CO2 we release does not accumulate in the atmosphere. This nonsensical phrase has now been sensibly dropped. How can sinks be missing? The surprise came only from the unwarranted assumption that the other entities that hold CO2 should refuse to take any extra amounts, on some kind of unwritten principle of carbon austerity by plants and oceans.

But why on earth would it be surprising that the plants take notice of variations in what is available for them to take – and proceed take it – as they are indeed taking it. Didn’t they once hold much of the very carbon we are now putting back in circulation? And why would it be surprising that the oceans also “take notice” of variations in the partial pressure of this gas in the atmosphere, and open their huge arms accordingly?

Alternatively, for illustrative purposes, you could look at the atmosphere as a giant pool with huge drains and pipes leading in and out of two other giant pools represented by the oceans and the plants/soil. So now we add our own little dripping faucet contribution to this giant global commerce, and we take ourselves so seriously that we assume the huge drains of this pool will be overwhelmed by our contribution, which will thus accumulate indefinitely. There are ribald jokes about ants having grandiose perceptions of their sanitary relations with elephants, or ants standing on a railway track and worried sick that they may cause a catastrophic derailment of the next train. I find them appropriate, sometimes, to the AGW discussions.

I think it could probably be demonstrated that even a doubling of CO2 concentrations from current levels is extremely unlikely, if not impossible, as a strict consequence of our contribution.

330. Brian G Valentine says:

Thank you Anna. Somebody tried to tell me that the “work” expended to accomplish this is the pV work done “by” the atmosphere; that certainly cannot be. One could in principle write down quantum statistical conservation and evolution conditions I suppose; don’t know how much meaning that would have on getting some numbers out of it unless some dramatic simplifications could be made (like if it was near zero Kelvin).

Thank you Willis for your most enlightening construct. I might have normalized to radiance quantities energy/unit area/unit if solid angle to possibly avoid some difficulty of interpretation of conserved quantities.

Wonderful weather here on the Mid Atlantic region this past week! I just can’t WAIT for some watermelons to start howling that it’s “too warm” and can’t we pass an energy and climate bill to fix this problem?

(You think I’m kidding? I’m not kidding one bit.)

331. Brian G Valentine says:

Professor Kramm sent to me that response, I would hope this appears someplace else other than good old arXiv

Anyway I still believe Gerlich and Tscheuschner,

… they oughta take me outside, and shoot me …

332. JAE says:

Can anyone tell me why it is not hotter in the desert on a humid day (when there is a lot of the best GHG) than on a very dry day?

333. Steve Goddard says:

The greenhouse effect is due to the fact that the atmosphere has a finite temperature and therefore emits radiation towards the surface. The surface receives more radiation from the atmosphere than it does from the sun.

The amount of warming generated by the atmosphere is about 7C per kilometer or 70-80C. This is well established, and as Feynman said :

It doesn’t matter how beautiful your theory is, it doesn’t matter how smart you are. If it doesn’t agree with experiment, it’s wrong.

334. beng says:

********
Brian G Valentine (06:06:09) :

Thank you Anna. Somebody tried to tell me that the “work” expended to accomplish this is the pV work done “by” the atmosphere; that certainly cannot be.
********

I had alittle trouble w/this issue until I thought alittle.

Work compressing a gas does cause it to rise in temp. But once the compression is finished, the gas will cool back to ambient. So a gas under static conditions (even at an extremely high pressure) w/no further work being done on it , doesn’t produce any heat & will return to ambient temp. Standard gas cylinders of compressed H2 are @ 2000 psi, but they’re at ambient temp once the heat of filling it (work) transfers away.

The earth does in fact do “work” of compression on descending air masses (high-pressure systems) & Chinook-type winds, but since the atmosphere is of a fixed mass & volume, air will have to rise somewhere else & then “cooling” occurs, as in low-pressure systems. The temp effects balance out & for the whole earth are zero. The earth as a whole isn’t doing any net “work” on the atmosphere.

335. JAE says:

“The amount of warming generated by the atmosphere is about 7C per kilometer or 70-80C. This is well established, and as Feynman said :

It doesn’t matter how beautiful your theory is, it doesn’t matter how smart you are. If it doesn’t agree with experiment, it’s wrong.”

For Feynman’s sake where is the empirical evidence that “well-establishes” this?

336. JAE says:

beng: what you say is accurate. But don’t forget that a gas at, say 20 C, possesses a lot of potential and kinetic energy. This is stored energy, which manifests itself as heat and causes the thermometer to read 20 C. A column of air several miles high has to have a lot of stored heat in it to exist. In fact, the amount of such stored heat is probably equivalent to the “greenhouse effect.”

337. Steve Goddard says:
338. Steve Goddard says:

JAE,

Nights in the desert are much warmer when it is humid, due to the increased GHG.

339. Willis Eschenbach says:

Leif Svalgaard (05:01:34)

Willis Eschenbach (01:56:43) :

“That’s where careful cherry picking comes in.”

I don’t know if that’s humor or not … I hope it is.

It was not. You can [and did] pick two close boreholes that give different results. That is the cherry. For it not to be cherry picking you will have to show that any two close boreholes are always wildly different, which they are not.

Boreholes like this are fairly common.I found a number of them very quickly. Unfortunately, most boreholes are a ways from each other, so it’s hard to tell.

But if the boreholes are connected to temperature, temperature is well correlated at distances up to about 1,000 km, and falls off fairly linearly. I have never seen a borehole study that claimed that, and I doubt it greatly.

Finally, I note that your borehole reconstruction shows the Medieval Warm Period, and theirs shows nothing of the sort … which one is wrong?

One only went back to 1500, so cannot show the MWP.

Oh, please. Yours shows that 500 years ago was a full degree warmer than theirs. You claim this is from the MWP, which in your reconstruction is about 600 years ago. Stop tap dancing and answer the question — why is your reconstruction a degree warmer than theirs 500 years ago if their error bar is only a tenth of a degree?

The error bar is probably calculated from the spread of the 837 individual reconstructions. Let that be, typically [go look at several] 3 degrees, then the usual 1-sigma error of the mean would be 3/sqrt(836) = 0.10 degrees. You can find the individual reconstructions here http://www.ncdc.noaa.gov/paleo/borehole/core.html

I do believe [Red Queen-like] the borehole technique is sound. This does not guarantee that all applications of it are.

Yes, I know that’s how the error bar is constructed. I just don’t believe it is meaningful. Let me see if I can explain why.

Suppose we have a thermometer, and the actual temperature is 10.55°C. I ask people to read it to the nearest degree. I have ten thousand people read it. As you might expect, about half of them say the temperature is 10C, and the other half say it is 11C. We end up with an average of 10.5°, and an actual error of 0.05°C

OK. The standard error of a group of observations is the standard deviation divided by the square root of the number of observations N. In this situation, we end up with the numbers saying that the temperature is 10.5C with a standard error of ± 0.005°C … which is clearly wrong, because the real temperature is no less than ten, count them, ten standard errors away from the calculated value.

But wait, it gets worse. What if the errors are asymmetrical, that is to say biased to one side or the other? For example, if it is very very cold, people will tend to round their temperature off to the cold side. It’s only human.

Suppose that because of that tendency, instead of the readings coming back 50/50 above and below the real temperature, that the split is 60/40 to the cooler side. Not much of a change.

But in that case, the result is no less than 29 standard errors away from the true value.

So there are two problems. The first one is the inherent accuracy of the measurement technique. My rule of thumb is that no matter how many measurements we take, we can’t gain more than one decimal of accuracy over the original measurements. In other words, if we are measuring to the nearest degree, our error can never be less than a tenth of a degree, no matter how many measurements we take. And when two adjacent boreholes give widely varying answers as to the temperature 500 years ago, we are using a very crude measuring stick.

The second one is asymmetrical errors. For boreholes the main one of these is plain old water. I used to make my living drilling water wells, so I’m more than a bit familiar with this.

As a borehole goes down into the earth, we expect it to get warmer. This is because the core of the earth is really hot, and the heat slowly flows upwards.

Now, if there is water coming out of the side of the borehole anywhere, it will cool the borehole. And because gravity only goes one direction, it will cool the part of the borehole which is deeper, but not the shallower part.

This, of course, introduces an asymmetrical error into the data, with more boreholes expected to show spurious warming because the older (deeper) parts are cooler.

Now, these problems with error calculations have been known for centuries. For the borehole folks to ignore them and claim that they can measure the global temperature a half a millennium ago with a smaller error than we can do with 1850 temperature records tells me one thing …

We’re not dealing with borehole scientists. We’re dealing with borehole acolytes.

340. Steve Goddard
How can you separate out the radiation from the Sun from the radiation from the atmosphere?

341. Willis Eschenbach says:

Dave Springer (05:37:48)

Brian Valentine

I don’t understand why you responded since you had nothing to offer in way of explanation why the constant subsurface temperature of lunar regolith in the middle latitudes agrees very closely with the oft-cited figure of the earth being heated approximately 30 degrees celsius through greenhouse gases.

There are many studies of the optical properties of lunar regolith available. It isn’t exotic material of any sort and that shouldn’t be surprising given the moon is made of the same material as the earth. Lunar regolith is generally darker than earth surfaces because “space weathering” of the soil darkens it. Fresh impact craters have bright rays coming out from them because it is newly exposed regolith which has yet to be darkened by space weathering.

I believe the data from the Apollo experiments thoroughly disproves Willis’ hypothesis of only 8 degrees celsius heating from GHG. His continued silence on it I’m taking as a tacit admission that he can’t account for it and rather than admit an error is choosing to simply ignore the inconvenient data. I had thought hiding contrary data that doesn’t agree with theoretical model predictions was a tactic used by the AGW alarmists. I’m very disappointed to see it being employed by the anti-alarmists.

First, my “continued silence” on this is because (as I said I would) I’ve been skipping over anything containing the word “moon”. I only caught this one by chance. So you can stuff your “tacit admission” where the sun don’t shine, it is unpleasant, unwarranted, and untrue.

Next, why is the regolith the temperature it is? I don’t know … what temperature is it? Probably somewhere in one of the moon posts I skipped over, hang on, let me look … OK, here we go:

“Lunar Surface Temperatures

Temperatures on the Lunar surface vary widely on location. Although beyond the first few centimeters of the regolith the temperature is a nearly constant -35 C (at a depth of 1 meter), the surface is influenced widely by the day-night cycle. The average temperature on the surface is about 40-45 C lower than it is just below the surface.

In the day, the temperature of the Moon averages 107 C, although it rises as high as 123 C. The night cools the surface to an average of -153 C, or -233 C in the permanently shaded south polar basin. A typical non-polar minimum temperature is -181 C (at the Apollo 15 site).

Well, that’s plenty confusing. First, the surface “averages” 40-45°C cooler than it is a metre down … why would that be? I mean, why would the interior of the moon be warmer than the surface, when it is well known that it doesn’t have a molten core? Can you explain that one, Dave? Or is your continued silence on that one a tacit admission that rather than admit an error you are choosing to simply ignore the inconvenient data?

And the regolith a meter down is a “nearly constant -35°C” … oh really? They know this from the hundreds of metre-deep holes we’ve drilled at various widely-separated locations to randomly sample the lunar sub-surface and then monitor its changes over time? …

Next, they give “average” temperatures. But when we are dealing with long, slow swings of 300°C in an environment where radiation is the only way to gain or lose heat, you can’t just “average” the temperatures, that’s nonsense. You have to convert them to the equivalent radiation temperatures, average their integrals over time, and convert back.

So as far as your question about the regoliths goes, until we have some real figures, I’m going to pass on guessing, and so should you. Those figures are from folks who think you can “average” lunar temperatures … riiight.

342. Willis Eschenbach says:

JAE (09:17:27)

Can anyone tell me why it is not hotter in the desert on a humid day (when there is a lot of the best GHG) than on a very dry day?

If you have data on this question I’d love to see it …

w.

343. Willis Eschenbach says:

Bryan (12:02:11)

Steve Goddard
How can you separate out the radiation from the Sun from the radiation from the atmosphere?

Take the measurements at night …

w.

344. Willis Eschenbach (12:01:17) :
why is your reconstruction a degree warmer than theirs 500 years ago if their error bar is only a tenth of a degree?
There are random errors and systematic errors [e.g. depending on site distribution]. The systematic error is unknown and can [and probably does] explain the difference.

We’re not dealing with borehole scientists. We’re dealing with borehole acolytes.
I think you have a bad case of ‘confirmation basis’ [actually anti-confirmation], but to each his own bias :-)
I would separate the technique [I think it will be useful on the Moon too – also no water :-) ] from current practitioners [or at least the ones you have had a run-in with].

345. HankHenry says:

Beng-
“The cold deep-water is a remnant of the previous ice-ages. ”

This occurred to me but I find it surprising. If heat were able to conduct through seawater at just 1 meter per year and the average ocean depth is just 3.7 km that would only take us back to a couple thousand BC, and I usually think of the last ice age as ending something like 10,000 BC. I wonder if there could be another phenomenon having to do with a pressure gradient and/or density at work “fighting” against downward heat conduction in the ocean?

If it is true that deep ocean coldness is an ice age remnant, it raises more questions. Now I wonder in maintaining the equilibrium you mention how much heat is extracted in a year and whether it is something worth putting into the models…. or is it all a subsystem that can be disregarded?

346. JAE says:

Steve Goddard:

“Nights in the desert are much warmer when it is humid, due to the increased GHG.”

Some data would be nice here. In summertime, it is much warmer at night in the dry desert (say, Phoenix) than it is at humid areas at the same lat. and long. (say Atlanta). Why?

347. JAE says:

Steve Goddard (10:57:07) :

?? I fail to see how the lapse rate supports your position. I don’t understand the other reference, so if it proves anything, I cannot tell.

348. JAE says:

Willis:

“If you have data on this question I’d love to see it …”

It’s mostly from experience that I say it. I don’t know where to get long-term daily temp., humidity, and cloud-cover records. However, if you look at the Phoenix weather for February and the first 18 days of this month, selecting only those days which have a cloud cover of 0 or 0.1 (11 days during the period), you will find that the high daily temperature varies betwee 85 F to 46 F, and the daily low relative humidity readings vary from 13-29 percent. There is a slight NEGATIVE correlation between the high temp. and humidity (r^2 = 0.33). At night there is also a negative correlation–it is generally warmer when the r.h. is LOWER (r^2 = 0.46). Not a lot of data, I know, but something to start with….

349. JAE says:

Nuts, I used relative humidity, rather than absolute humidity. When abs. humidity values are used there is essentially no correlation between daytime high temperatures varying between 66-85 and daytime low abs. humidities varying from 2.9-5.9 (essentially a doubling of the amount of water in the air had no discernable effect on temperatures). Same with nighttime.

350. kwik says:

Doesnt the earth surface, and all the layers upwards obey Zeroth Law of Thermodynamics?

http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/thereq.html

And doesnt that mean CO2 cannot increase the temperature?

Except, say if Co2 increased to the double amount overnight, the temperature would increase for a short time, and then fall back to the original value?

Or have I totally misunderstood the situation?

351. Willis Eschenbach says:

Willis Eschenbach (12:01:17) :

why is your reconstruction a degree warmer than theirs 500 years ago if their error bar is only a tenth of a degree?

There are random errors and systematic errors [e.g. depending on site distribution]. The systematic error is unknown and can [and probably does] explain the difference.

In other words, their error estimate is nonsense … which is what I said.

We’re not dealing with borehole scientists. We’re dealing with borehole acolytes.

I think you have a bad case of ‘confirmation basis’ [actually anti-confirmation], but to each his own bias :-)
I would separate the technique [I think it will be useful on the Moon too – also no water :-) ] from current practitioners [or at least the ones you have had a run-in with].

Anti-confirmation bias? That’s when results don’t agree with what we know about the past (e.g. no sign of a Little Ice Age in their records, when it is well documented by a host of proxies and contemporary accounts), so we should look on the results with suspicion? Yeah, I have that, so should you. The anti-confirmation bias motto is “extraordinary claims require extraordinary evidence” …

Regarding current practitioners, remember that these are the ones you recommended. These are the ones whose results differ from yours by 1°C, at a time when they are claiming a standard error of a tenth of a degree. My run-in with them establishes a history of scientific malfeasance, but that’s not why I think their results are bogus. I think they are bogus because a) they don’t show the LIA and b) their claimed accuracy is a joke.

Can boreholes give us a thermal history? Assuredly. Can we use them without a complete record of the underground geology at the site, particularly including water seeps? No way, and that’s what they’re doing.

Can we use them with such a record? Possibly, but even then it is difficult. How much water is leaking down the borehole, not just at a given instant, but on average over the year? Exactly what is the rate of heat loss through a given geological layer? What is is rate of heat loss at the boundaries between the layers? Until we can answer these questions very exactly, the results are very suspect.

So I agree with you that yes, theoretically, borehole records could give us historical temperature records. But as always, the devil is in the details, and with boreholes there are a lot of details, those details are often unknown, and are always way underground where we can only measure them indirectly. Not a good combination.

352. Willis Eschenbach says:

JAE (14:35:49)

Willis:

“If you have data on this question I’d love to see it …”

It’s mostly from experience that I say it. I don’t know where to get long-term daily temp., humidity, and cloud-cover records. However, if you look at the Phoenix weather for February and the first 18 days of this month, selecting only those days which have a cloud cover of 0 or 0.1 (11 days during the period), you will find that the high daily temperature varies betwee 85 F to 46 F, and the daily low relative humidity readings vary from 13-29 percent. There is a slight NEGATIVE correlation between the high temp. and humidity (r^2 = 0.33). At night there is also a negative correlation–it is generally warmer when the r.h. is LOWER (r^2 = 0.46). Not a lot of data, I know, but something to start with….

Thanks, JAE. It’s very hard to prove that way. The difficulty is that deserts get rain. When the residual moisture in the soil evaporates, we get water vapour, which tends to hold the heat in.

However, as you point out, at those times we also get evaporation and sometimes clouds … which makes it very hard to separate out the effects.

353. Willis Eschenbach says:

kwik (14:56:35)

Doesnt the earth surface, and all the layers upwards obey Zeroth Law of Thermodynamics?

http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/thereq.html

And doesnt that mean CO2 cannot increase the temperature?

This is a common misconception. The zeroth law only applies to net flows, not individual flows. So while CO2 cannot increase the temperature, it can reduce the drop in temperature, which comes to the same thing. See my post above on the difference between net and individual flows.

354. JAE says:

Willis:

“However, as you point out, at those times we also get evaporation and sometimes clouds … which makes it very hard to separate out the effects.”

I hope you noticed that these were all virtually cloudless days (less than 10% cloud cover). And most of the days were in sequential periods, indicating no rainy periods.

“Thanks, JAE. It’s very hard to prove that way. The difficulty is that deserts get rain. When the residual moisture in the soil evaporates, we get water vapour, which tends to hold the heat in.”

Within this small amount of data, there is certainly no indication that more water vapor meant more heat, either in the day or the night. I’ll try to get more data somewhere.

Note, also that the amount of water vapor in the air down where you are is about 6-7 times what it is in Phoenix this time of year (during the day). Yet your temperatures are about the same… The negative feedbacks evidently keep any “greenhouse effects” well in check.

355. Colin Davidson says:

Apologies if this has already been covered.

Joel Shore (19:30:38, 18MAR10) wrote:
“What they are saying is that the direct effect of the IR absorption by CO2 will be to increase the TOA downwelling radiation by 3.7 W/m^2 but that the total increase, once you consider all the feedback effects will be an increase in the TOA downwelling radiation by almost 3 times this (where I am using the result that a 3.7 W/m^2 increase in TOA downwelling radiation produces a temperature rise of about 1 C, as calculated by the S-B Equation). ”

and Bill Illis (21:46:42, 18MAR10) wrote:
“- then there is feedbacks from increased water vapour and albedo which add another 6.5 to 7.4 W/m^2 after this initial forcing;

– the layer now increases in temperature by 3.0C (11.5 extra watts on top of the original 240 watts).

– the layer where the equilibrium emission temperature of 255K occurs is now 461 Metres higher.

– the adiabatic lapse rate of 6.5C/km stays intact and the surface warms by the same 3.0C.

So, the sensivitiy is calculated as 4.0 extra watts of GHG forcing eventually results in an increase of 11.5 watts (once all feedbacks occur) and temperatures rise 3.0DegC”

I don’t agree with either of these statements.
The Surface Balance Equation at Equilibrium (I’m not claiming we are ever at equilibrium, this is the simple KT model) is:
Absorbed Solar Radiation + Back IR Radiation from the Atmosphere = IR Radiation from the surface + Latent Heat in Evaporated Water Vapour + Direct Conduction to the Air from the Surface.

Differentiating, again at equilibrium,
Change in Forcings (absorbed solar +back Radiation) = Change in Radiation from the surface + Change in Evaporation + Change in conduction (assumrd to be nil, as at equilibrium the relationship between the surface and the boundary layer is likely to be unaltered for any small change in temperature).

Cranking in the numbers:
Change in Forcing = 4sT^3dT + 78xdT. (s is 5.67×10^-8, dT is change in temperature, x is percentage increase in evaporation per DegC).
The big unknown in this equation is x, the increase in ebaporation. The Clausius-Clapyeron equation gives an upper limit of 6.5%, and some scientists think it is as low as 2%. It’s not 0%.

For x=2% the surface sensitivity is 0.15DegC/W/m^2, and the Change in Forcing is 22W/m^2 if the temperature rises by 3DegC.
For x=6.5% the surface sensitivity is 0.095DegC/W/m^2 and the Change in Forcing is 32W/m^2 for a temperature rise of 3DegC.

I don’t know what the relationship of the forcing at the tropopause (11.5 W/m^2 according to Bill) is to Surface Forcing. But to get 3DegC at the surface you need to double or triple that already trebled Radiative Forcing. (The assumption that the Lapse Rate stays constant is no help – the Surface is massively imbalanced. It cannot maintain the 3DegC increase without additional flux, and it can’t get that from an inflexible Lapse Rate.)

I don’t know what forcing was assumed by Joel. If it’s say 12W/m^2, then you get around 1DegC at the surface. But again you need to double or treble that to get 3DegC.

What am I missing here? I get a really insensitive surface and a large mismatch in surface forcing to tropopausal “Radiative Forcing”. Is there a problem with the no-change-in-conduction assuption (It would have to decrease by 50%)?

356. Alan D McIntire says:

Regarding Pollock and his boreholes:
Here’s a 1997 paper reporting boreholes showing an early holocene climate optimum, medieval warm period, and little ice age

a summary from 1998 addressing only the 20th century

http://www.sciencemag.org/cgi/content/abstract/282/5387/279

and a summary of a paper from 1999 addressing only the warming since the Little ice age

http://www.nature.com/nature/journal/v403/n6771/abs/403756a0.html

It looks like an example of “playing to the global warmers”, papers since 1998 only address the period since the little ice age
– evidently these warming results more easily make it iinto the approved journals

357. Bill Illis says:

“HankHenry (12:54:15) :

Beng-
“The cold deep-water is a remnant of the previous ice-ages. ” ”

The deep ocean temperature is a reflection of the past several hundred years of the coldest, densest ocean water there is on the planet.

The coldest densest ocean water occurs in the thermohaline ocean sinking regions near the sea ice pack and under the sea ice pack in the Arctic and around Antarctica.

Ocean water is most dense at about 1.0C with high saline content. Fresh water is most dense at 4.0C but with the introduction of very high salt content, the density can maximize close to 0.0C.

If ocean water gets colder than the maximum density combination of temperature and saltiness, it becomes less dense and rises. If it gets warmer than this or less salty than this, it also becomes less dense and rises. If it freezes, it becomes the least dense water of all and it floats to the top or it only occurs at the surface in the first place. The saline content will then fall out of it as well and it becomes even less dense.

Even in the ice ages, the deep ocean temperature probably did not go much lower, maybe 0.0C, and it has never, ever in the history of the planet, been lower than this. The entire ocean has to warm up, especially in the polar regions for the deep ocean temperature to go higher than today. In other words, there can be no sea ice, even in the winter, to increase much from today’s level.

In the paleoclimate, there are estimates of the deep ocean temperature being as high as 10C above today’s level. That means, even in the winter, the poles did not go below 10C.

358. Steve Goddard says:

JAE,

One reason Phoenix is warm at night is because of the humidity from lawns, golf courses, etc. I have seen dew points in excess of 70 degrees there.

Also, why do you think it is extremely cold on the top of Mt. Everest? Could it have anything to do with the lack of atmosphere?

359. Joel Shore says:

Willis Eschenbach says:

If I am following your argument, you misunderstand the “per CO2 doubling”. This is just how the IPCC tends to measure climate sensitivity. It has nothing to do with how much of any given forcing is from CO2. It is merely a unit of measurement.

For example, we could say that climate sensitivity is 1°C/W-m2, or we could say that climate sensitivity is 3.7°C / CO2 doubling. There is absolutely no difference between those statements. They are just expressed in different units. The conversion factor is

1 CO2 doubling = 3.7 W/m2

or

1 W/m2 = 0.27 CO2 doublings

So we can convert from one unit to the other, and it means nothing about whether we are talking about cloud forcing or H2O forcing or CO2 forcing. It’s just different units.

I suggest you read what Bill Illis wrote in his comment on 18/03/2010 (21:46:42). At the end of the day, the original forcing of ~4 W/m^2 from doubling CO2 results in another ~7 W/m^2 of “forcing” (in the sense of change in downwelling radiation at the TOA).

The IPCC is not saying that ~4 W/m^2 increase in downwelling radiation at the TOA leads to a 3 C temperature rise…They are saying that ~4 W/m^2 of forcing results in feedback that increase the downwelling radiation by considerably more than that.

360. Joel Shore says:

Francisco says:

From that chart, you see that total amount of carbon in the extant fossil fuels still in the ground is roughly 1/8 the amount of carbon in the active system. The amount we are recycling annually back into the system is about 0.015% of the total carbon in the system.

That is not really relevant as the rate of transfer to the deep ocean reservoir is rather small. So, you have to consider the amount we are adding to the other reservoirs (that exchange fast enough that they can be thought of as a rapidly-equilibrating subsystem that exchanges carbon only very slowly with the deep oceans. Also, note that if you add only 1% annually to a reservoir that is not able to get rid of it, you will double the amount in that reservoir in 100 years.

The cause for alarm, it seems to me, comes only if you adopt the assumption that our modest recycling program represents a very grave disturbance to a static and balanced system, whose balance coincides with its state around 1850. I consider this assumption to have no rational or scientific basis whatsoever. It is merely ideological.

Ah…Do you mean no basis beside the overwhelming empirical evidence that we have increased the levels of CO2 in the atmosphere from the pre-industrial baseline of 280ppm to the current ~390ppm?

To begin with, the carbon we are releasing was once part of that dynamic system. We are recycling it back into life at what appears like a reasonable rate.

Reasonable compared to what? And, the fact is that CO2 levels on geological timescales has been much higher than they are now, with the correlated effects of warmer temperatures, higher sea levels and everything else.

A few years ago there was some talk of a “missing sink” to refer to the apparently surprising fact that about half the CO2 we release does not accumulate in the atmosphere.

I think you are woefully misunderstanding the science. There was some confusion regarding exactly what fraction of that carbon that is not accumulating is going into the ocean and what part into the biosphere (and soils). There was not confusion about the basic fact that about half of it was not remaining in the atmosphere.

I think it could probably be demonstrated that even a doubling of CO2 concentrations from current levels is extremely unlikely, if not impossible, as a strict consequence of our contribution.

Well, you are welcome to believe what you want to believe but it certainly isn’t a belief based on the scientific evidence.

361. Joel Shore says:

Brian G Valentine says:

I understand where this is coming from, Bill, but where I (and apparently Gerlich and Tscheuscher and a lot of others) have the worst difficulty, is accepting the idea that the “atmosphere” is “warming” the “surface”.

Either that idea violates the Second Law or it doesn’t. If someone could just present ONE parallel example to show this is at least possible, then I would not say that Gerlich and Tscheusher’s analysis is as good as anyother application of the Second Law

Debunking of G&T’s Second Law argument in 3 easy steps:

(1) The Second Law statement about heat flowing from hotter to colder applies to net flows; it does not mean that no heat can be radiated by a colder body and absorbed by a hotter one. This should be obvious from an understanding of the basic statistical physics from which the Second Law derives, but even if one is ignorant of that, we know that all bodies radiate when they are at a nonzero temperature; if you have a hotter body near a colder body, the colder body is not going to magically detect the hotter body and stop radiating. The Second Law is not about magic. The Second Law means simply that the colder body will absorb more radiation emitted by the hotter body than the hotter body will absorb radiation emitted by the colder body.

(2) All reasonable models of the atmospheric greenhouse effect, whether toy models like Willis’s steel greenhouse or Trenberth and Kiehl’s energy budget diagrams or line-by-line radiative transfer calculations, have the net flow of heat being from the warmer earth to the colder atmosphere, as the Second Law requires. If you believe otherwise, show us.

(3) Despite the fact that the net flow is from earth to atmosphere, the effect of an IR-active atmosphere is still to produce warming relative to the case of an IR-transparent atmosphere. This may be the point that trips the most people up….It seems like an almost unstated assumption in many arguments of a Second Law violation that in order for the greenhouse effect to occur, the net flow must be from atmosphere to Earth. ****THIS IS WRONG.**** The reason that this is wrong is because in the comparison case, of an IR-transparent atmosphere, all the radiation emitted by the earth escapes into space. Hence, anything that causes some of that radiation to be returned to the earth will cause warming relative to that case. The greenhouse effect just says that SOME of the radiation that would otherwise escape from the Earth into space finds its way back to the Earth; it makes no claim that the amount that finds its way back is greater than the amount that the atmosphere absorbs from the earth, as such a claim would be a violation of the Second Law (and just plain silly to boot).

362. Joel Shore says:

Bryan:

I would invite anyone who has any doubts on the matter to go to Arthur P Smith website and the thread “the arrogance of Physicists”.
Arthur has great difficulty coping with Fred Staples and Terry Oldberg never mind G&T

Arthur has troubles with them in the same way that I would have troubles with a particularly dense and opinionated student who had all sorts of wrong-headed ideas about physics and did not have the necessary combination of knowledge, intellect, and ability to listen to things that go against what they want to believe to understand when I tried to explain things to them. I suppose that someone reading the exchange who does not have the necessary background to evaluate the scientific arguments might find Fred Staples or Terry Oldberg’s arguments compelling; those of us who do, do not find them at all compelling and are actually somewhat amused to hear that people take them at all seriously.

363. Brian G Valentine says:

Joel, I appreciate very much your understanding and interest of the forcings at the tropopause and the associated feedbacks. I really do, I know you have labored and contributed extensively. Your understanding of the climate sensitivity corollaries is as extensive as anyone I know.

But if we come back to the same old problem above, Joel, this trying to move heat from cold to hot without compensating work … we know that space is something of a homogeneous radiation source or sink at a temperature of like 2.9K – one looks at that and thinks, the heat has to be going the other way …

The bottom like to all the feedback stuff, Joel, is that it doesn’t look right, what more can anyone say?

364. JAE says:

Steve Goddard (18:48:19) :

“One reason Phoenix is warm at night is because of the humidity from lawns, golf courses, etc. I have seen dew points in excess of 70 degrees there.

Also, why do you think it is extremely cold on the top of Mt. Everest? Could it have anything to do with the lack of atmosphere?”

Well, forget Phoenix. and look at Daggett, California, then: http://rredc.nrel.gov/solar/old_data/nsrdb/redbook/sum2/23161.txt

You won’t find many lawns there.

I don’t understand the comment about Mt. Everest.

365. Steve Goddard says:

JAE,

The reason it is cold at high elevation is because there is less atmosphere above to keep it warm.

366. JAE says:

Folks, MY bottom line is that I have been looking for an empirical demonstration of the “atmospheric greenhouse effect” for a long time, and I still have found absolutely NO empirical demonstration of the phenomenon, despite the fact that many learned scholars have expounded upon the theory for over 100 years. I see a lot of really cool ideas, including the K&T diagram that Willis provided above. The theory looks good and offers a nice tidy way to explain some things. The problem is that it does NOT explain many other things, which I mentioned in my earlier posts. It is simply not any hotter in areas that have copious amounts of greenhouse gases than it is in areas which have very minor amounts of greenhouse gases. WHY? Ahrrenius provided a THEORY, not a FACT. And nobody to my knowledge has done better.

367. anna v says:

You say elsewhere that the temperature on the moon is measured at -23C at a depth of 50cm.

All black body calculations have to do with skin surface temperatures. Even a few mm down from the skin, be it water or ground, infrared is blocked and only convection/contact works.

Thus one should go from the average skin temperature and calculate how long it takes to heat a body at near absolute zero up to -23C by conduction from a surface heated by the sun with an average ( day night year) temperature of “xx” which you do not quote.

This is not a simple problem, for all I know it might take a billion years, as regolith is a good insulator. I was not able to find a global skin surface temperature for the moon, only calculations.

My point is that the -23C at 50cm argument is not relevant to the discussion.

368. anna v says:

The amount of warming generated by the atmosphere is about 7C per kilometer or 70-80C. This is well established,

I am puzzled. Not by the temperature gradients, but of the claim it is the atmosphere that is generating the heat to produce the gradient. Link please?

369. gbaikie says:

“Once again, see my post, “The Steel Greenhouse”. It shows that the greenhouse effect has nothing to do with gas, or lapse rate, or any of that. If you have problems with the concepts there, let me know.”

I don’t think it would be it would be twice the temperature on surface planet as compared to the temperature of the outer shell. As you said:

“Figure 1. Building a steel greenhouse. (A) Planet without greenhouse. Surface temperature is 235 W/m2 heated from the interior. (B) Planet surrounded by steel greenhouse shell. Shell radiates the same amount to space as the planet without the shell, 235 W/m2. It radiates the same inward, which warms the planet to 470 W/m2 (29 C, 83°F, 302 K).

I agree the that outer shell radiates the same amount of energy. And we will disregard the rather insignificant increase of the area of the outer shell.
Instead the surface temperature could depend upon how the energy is conducted to the outer shell- conduction, convection, and/or radiation.
It make simple; let’s assume it’s a complete vacuum- and so only allowing radiation.
In that case the surface of the planet should be the same temperature as the shell.

Now, let’s return to the Moon- which is a nearly perfect vacuum.
What temperature would the moon surface have if it was a light year or two from the Sun?

I would say the surface temperature would be close to the present temperature in it’s deep polar craters which are never exposed to sunlight. This surface temperature is well above the temperature of 4 kelvin which is said the be the universe’s temperature. I don’t want to argue about what the temperature exactly is- say somewhere around 20 to 100 kelvin and say that at least 20 Kelvin of that heat is from the Moon’s core heat.
So if we put the Moon a couple light years from the Sun and say it’s surface is somewhere around 20 to 30 K. And then we put a steel shell around it- the shell would be around 20 to 30 K and the surface would remain at 20 to 30 K. And it doesn’t matter how many shells you put around it, it will still be 20 or 30 K at the surface. And you hang a mile of fiberglass insulation from the sphere- it of course wouldn’t make any difference. Or if you made a perfect mirror inside the sphere it would not make any difference.
But if you increase the surface area on the outside of the sphere- put spikes on it, or simply have bumpy surface- and that could make a difference [you could double or triple the surface area]- so you could lower the outside temperature of the sphere. Though of course it can not get below 4 Kelvin.

Though, since a sphere can be made into a smooth exterior surface and the Moon [or any planet] would be rougher surface [and therefore more surface area], such reduction in surface area would reduce it’s ability to radiate heat and therefore increase the temperature on the lunar surface.

370. Spector says:

I would think that one possible indicator of changes in the ground-level greenhouse effect, if any, would be a year-by-year listing of the coldest near sea-level temperature recorded for each of those years in the Arctic dark zones. I believe it would be the clear cold quiet periods in this region that would be most affected by changes in the classical greenhouse effect.

371. gbaikie says:

Said differently make a box a meter cubed. Have it have a sandwich of vacuum and thin sheets of metal. Say have sheet 2 mm thick separated by 2 mm of vacuum- so that gives you 250 “shells”. Put this on the ground on the moon in the shade- and it will not increase the temperature of the ground it is on.

372. Steve Goddard says:

anna,

The only significant heat source in the climate system is the sun. A coat keeps you warm without generating any heat.

Why are you puzzled by my statement, but apparently not by the premise of this article?

This means that the warming due to the complete atmospheric system (greenhouse gases, clouds, aerosols, latent and sensible heat losses, and all the rest) is about 20°C over no-atmosphere earth albedo conditions.

373. Joel Shore (19:32:16) :
we know that all bodies radiate when they are at a nonzero temperature
I was being lectured that a white body [emissivity = 0] does not radiate at any temperature [100C, 400C or millions of degrees] …

374. Joel Shore (19:36:57) :

Bryan:

I would invite anyone who has any doubts on the matter to go to Arthur P Smith website and the thread “the arrogance of Physicists”.

Joel, Arthur was asked by Fred what difference would be made to the thermodynamics of the atmosphere if it was composed entirely of N2 and O2 and he replied that he thought it would be ISOTHERMAL from the surface up to a height of 30Km.
Not only does Arthur seek to contradict the 2nd law of THD but now also the Ist law of THD and the slight matter of abolishing gravity thrown in for good measure.

Yet you find this type of Physics perfectly OK!
Fred Staples and Terry Oldfield have a background in heat transfer thermodynamics.
I would suggest that before Arthur writes more nonsense he should attend some thermodynamics classes

375. Correction

Name above should read Terry Oldberg not Terry Oldfield

376. beng says:

********
Bill Illis (18:46:57) :

“HankHenry (12:54:15) :

Beng-
“The cold deep-water is a remnant of the previous ice-ages. ” ”

The deep ocean temperature is a reflection of the past several hundred years of the coldest, densest ocean water there is on the planet.
*******

That’s prb’ly right, Bill, tho I’ve read it takes a couple thousand yrs for the deep ocean to recycle. So the cold deep water isn’t exactly a remanent of the last ice-age (10000 yrs ago), but it is of the last thousand or so yrs of cold polar weather and sinking cold water there, which continues today. Some study I read said that before Antarctica was glaciated (before 35 mil yrs ago), the deep water was as warm as 60F (15C).

*******
HankHenry (12:54:15) :

Beng-
“The cold deep-water is a remnant of the previous ice-ages. ”

This occurred to me but I find it surprising. If heat were able to conduct through seawater at just 1 meter per year and the average ocean depth is just 3.7 km that would only take us back to a couple thousand BC, and I usually think of the last ice age as ending something like 10,000 BC. I wonder if there could be another phenomenon having to do with a pressure gradient and/or density at work “fighting” against downward heat conduction in the ocean?

If it is true that deep ocean coldness is an ice age remnant, it raises more questions. Now I wonder in maintaining the equilibrium you mention how much heat is extracted in a year and whether it is something worth putting into the models…. or is it all a subsystem that can be disregarded?
*******

Hank, read my response to Bill above — the cold deep-water is prb’ly no more than a thousand or so yrs old, but still is an accumulated remanent of cold polar regions & resulting sinking water. So your thermal-conduction rate is prb’ly pretty close. But more cold water is sinking & replacing it in polar regions even now in the interglacial.

As far as “fighting” conduction — no such action is necessary, just relatively simple heat-transfer laws. Thickness of the insulating layer is the key — kilometer-thick, static layers slow down conduction to a crawl. That’s the same reason the ground isn’t hot — a few kilometers of insulating crust keep us shielded from 2000C molten rock.

And as far as I know, the deep cold-water isn’t included in GCM models — even ocean-heat content (OHC) measurements only go down several hundred meters (700 meters?), so basically water below that is ignored. Not sure if this is reasonable or not.

377. Joel Shore says:

Brian G Valentine says:

But if we come back to the same old problem above, Joel, this trying to move heat from cold to hot without compensating work

No, it is not, as I explained in my post of (19:32:16). You can’t just assert that something violates the Second Law because you just feel that it does. You have to demonstrate that it does. I have explained why it doesn’t.

Leif Svalgaard says:

I was being lectured that a white body [emissivity = 0] does not radiate at any temperature [100C, 400C or millions of degrees] …

Do you know of any object in nature that is an ideal white body? At any rate, I don’t think it is vital to my argument that such an ideal white body (or something very close to it) exists does not exist. I was just interested in the transfers of radiation between two bodies at different temperatures.

Bryan says:

Joel, Arthur was asked by Fred what difference would be made to the thermodynamics of the atmosphere if it was composed entirely of N2 and O2 and he replied that he thought it would be ISOTHERMAL from the surface up to a height of 30Km.

Well, I would have to think more about whether I agree with Arthur on it being isothermal (if that is really what he said). However, the important point is that some people seem to think that one can create higher temperatures at the earth’s surface simply by virtue of the pressure, even if the atmosphere is transparent to IR radiation. And, the point is that this is wrong. The earth still has to satisfy the first law of thermodynamics, which means that in steady-state the amount it radiates away has to be equal to the amount of energy it receives and this is what would determine the temperature at the surface in an IR-transparent atmosphere where all of the radiation from the surface will escape into space.

378. Brian G Valentine says:

“I suppose that someone reading the exchange who does not have the necessary background to evaluate the scientific arguments might find Fred Staples or Terry Oldberg’s arguments compelling; those of us who do, do not find them at all compelling”

The same old worn out thing, thrown at people who disagree, I hate that, damn it

379. Joel Shore says:

Brian G Valentine:

The same old worn out thing, thrown at people who disagree, I hate that, damn it

Well, look at it from our point of view: There are some people who, by virtue of their lack of background combined with their own preconceptions based on strongly-held beliefs, one seems unable to reach by scientific arguments, no matter how hard we try. When they say, “Convince me that…” they are asking us to do the impossible, which essentially means they are just wasting our time.

In the end, many people will believe what they want to believe…and there is only so much one can do to change minds.

380. anna v says:

I have expressed my questions with respect with assumptions in posts up ways.

The coat keeps me warm because I am the heat source and it is an insulating body, i.e. its heat capacity and conductivity of heat and permeability to air currents is such that it delays the cooling of my body by radiation, conduction and convection (lets not enter into the biological system that keeps me at 37C playing havoc with entropy).
Generally insulation delays equilibrium with ambient temperature, but if there is no heat source, ambient wins.

The difference between moon conditions and earth conditions makes it self evident that the atmosphere plays such a function for the surface of the earth, miss named “a greenhouse effect”, and misused with CO2 runaway imaginations.

In the same way that the coat does not heat me, the atmosphere does not heat nor create the temperature gradients. It is gravity and the thermodynamic and dynamical properties of atmospheric gases (including convection precipitation evaporation etc) that define the temperature gradients that the input sun energy and radiating earth generate in the atmosphere.

381. Gerlich and Tscheuschner have further developed their ideas regarding atmospheric physics. March 2010

Readers will require a background in Physics to follow the article completely. Consensus advocates are now getting a bit reluctant to fully engage G&T on matters such as heat transfer and radiative balance.

arxiv4.library.cornell.edu/pdf/1003.1508

382. HankHenry says:

Beng – Thank you for the knowledgeable and thoughtful response. I started my comments in this thread with the remark, “Two miles down on the continents the earth is quite warm, but two miles down in the oceans it’s quite cold.” I think that is a true statement based on things I read about boreholes, the thermal gradient, and deep mines in South Africa. My comment probably doesn’t bear directly on the article at the top of the thread about radiative heat. It just strikes me as a peculiar phenomenon that nature presents us. Perhaps something of as much interest as the much vaunted and misnamed “greenhouse effect.” I also want to say there must be more at play than insulation. There seems to be some process actively removing heat from the deep ocean. I think that process is probably the “sinking and replacing” that you mention.

383. Joel Shore (06:58:15) :
“I was being lectured that a white body [emissivity = 0] does not radiate at any temperature [100C, 400C or millions of degrees] …”
Do you know of any object in nature that is an ideal white body?

A black hole is perhaps the closest to a perfect white body [as its emissivity is zero – quantum effects aside], although the concepts of temperature and entropy begin to lose their meaning here. There are also no ideal blackbodies.

At any rate, I don’t think it is vital to my argument
You are quite correct.

384. Joel

……The earth still has to satisfy the first law of thermodynamics, which means that in steady-state the amount it radiates away has to be equal to the amount of energy it receives and this is what would determine the temperature at the surface in an IR-transparent atmosphere where all of the radiation from the surface will escape into space…….

There is no such law as the conservation of radiation.
The energy that the Earth receives from the Sun can be accounted for in a number of ways for instance Chemical Potential Energy (Plants included), stored as internal energy in the oceans etc

The Planet can warm up and cool down over periods lasting several centuries and still be in harmony with the Ist law of THD if the Suns energy is stored as other energy forms on Earth.

385. Brian G Valentine says:

Well, look at it from my point of view: There are some people who, by virtue of their lack of background combined with their own preconceptions based on a strongly-held need to believe in AGW, one seems unable to reach by scientific arguments, no matter how hard I try. When they say, “Convince me that…” they are asking me to do the impossible, which essentially means they are just wasting my time.

In the end, many people will believe what they want to believe…and there is only so much I can do to change minds. But I’m not going to let nonsense and paranoia about AGW cause other people to suffer if I can help it.

386. Steve Goddard says:

anna,

If there was no atmosphere, there would be no temperature gradient through the atmosphere. Without a blanket you are cold. The sun warms the earth, and the atmosphere keeps the temperature up. Both are required to keep the earth livable.

387. Dave Springer says:

@anna v

Of course the lunar regolith temperature at 50cm is relevant. The surface temperature in full sunlight fluctuates by hundreds of degrees C from day to night. Every centimeter you drop below the surface the fluctuation decreases. By the time you get to 50cm there is no more measurable diurnal fluctuation and so what you’re measuring is predominantly the average surface temperature.

Lunar regolith is, by the way, a much better insulator than typical earth soil. You have to go much deeper into the earth before diurnal temperature swings become too small to measure.

388. anna v says:

Relevant to what?

The moon radiates heat in the infrared according to the formula flux= CxT^4
and that T must be the temperature of the first mm of surface . Because infrared does not penetrate either way more than the skin.

The temperature at 50cm is irrelevant to the heat radiated out. It is heat that is important, not a steady temperature. It fluctuates widely on the skin surface? Too bad for the calculations, but those are the numbers that take part in the problem.

The shell at 50cm, is isolated from the skin surface because the regolith is such a good insulator.

389. Dave Springer says:

willis

The accusation of ignoring evidence was a device to goad you into responding. It worked and I’m not apologizing for it.

The main problem with your post is that you begin it with the impossible situation of the earth being a perfect black body with no atmosphere and say it would be “only” 8C cooler.

Yeah, but so what? The earth isn’t a perfect black body. Albedo plays a huge role in surface temperature. The heat flow experiments in Apollo 15 and 17 are excellent points of reference for what temperature realistic chunks of airless rock with non-zero albedos will attain at approximately 93 million miles from the sun.

Now you’re reduced to nit-picking by saying that two experiments deployed at mid-latitudes in full sun on the lunar surface aren’t enough to warrant consideration.

Well, here’s the deal with that. That’s still a heck of lot more warrant than your completely imaginary situation of a perfect black body. So there.

390. Dave Springer says:

willis

To address your question of what’s up with the average between max daytime and nighttime surface temperatures being markedly different than subsurface average…

Someone else posted that and I’m not at all familiar with the reference it came from. The Apollo 15 and 17 heat flux experiments showed no such thing.

In fact there was no attempt to measure surface temperature in the heat flow rigs. It was only inadvertantly measured in the A15 setup because the astronaut couldn’t drill deep enough to bury all the thermocouples in one of the boreholes. As a result there were thermocouples (encased in a fiberglass rod) riding up a meter above the surface. Those above ground thermocouples yielded interesting information but it wasn’t regolith temperature, it was fiberglass temperature. In fact the most interesting thing they measured was a very small but gradual increase in nighttime minimum temperature. Several researches have speculated that the observed increase is due to increasing intensity of earthshine over the 5 years of data acquisition (1972 to 1977).

One might be interested in that as I believe back here on terra firma we had global cooling going on between 1972 and 1977. Increased earth albedo would give us global cooling and at the same time increase the intensity of earthshine on those inadvertantly exposed Apollo 15 ALSEP thermocouples.

Albedo in my opinion is what is really playing the big role in so-called climate change and a lot of the albedo change is in fact man-made by the deposition of black carbon (soot). Black carbon fits all the observations:

– it generates more heating at the surface than at altitude
– it has a limited range of effect of up to a few thousand kilometers from the source
– the sources are almost all in the northern hemisphere
– its effect is amplified by permanent snow cover as even during partial melts it floats to the surface getting darker and darker with each passing year
– recent experiments measuring earthshine on the moon show it decreasing

Even more interesting is the political ramifications of black carbon. The United States cleaned up its act with regard to black carbon decades ago. The primary offenders are Europe with their love of dirty deisel engines and poor countries that utilize slash/burn agriculture, heat their homes and cook their food by burning anything combustable in individual stoves and furnaces, and things of that nature. The United States then can’t be used for a scapegoat for global warming and in fact we would be the heroes instead of the villians. But NOooooooooooo. CO2 has to be the bogeyman so that the big wealthy United States gets the blame for it.

391. Colin Davidson says:

Is The Surface Unbalanced?

In my previous offering (Colin Davidson 18:18:13, 19MAR10) I used the Surface Balance equation to derive the sensitivity of the surface to “Surface Forcing”, and also calculated what that “Surface Forcing” must be to maintain a surface temperature which is 3DegC warmer.
The numbers turn out to be: a sensitivity between 0.095 and 0.15 DegC/W/m2, and an increase in “Surface Forcing” of between 22 and 32W/m2.
Joel Shore (19:04:26, 19MAR10) said:
“At the end of the day, the original forcing of ~4 W/m^2 from doubling CO2 results in another ~7 W/m^2 of “forcing” (in the sense of change in downwelling radiation at the TOA).The IPCC is not saying that ~4 W/m^2 increase in downwelling radiation at the TOA leads to a 3 C temperature rise…They are saying that ~4 W/m^2 of forcing results in feedback that increase the downwelling radiation by considerably more than that.”
As I understand this statement, the additional TOA “Radiative Forcing” at equilibrium for a 3DegC warmer planet is in the region of 12W/m2.
But this is nowhere near enough to keep the surface at an additional 3DegC warmer. Even if there is no additional evaporation, there needs to be 16W/m2 of additional downwelling radiation at the surface to cover the increased Stephan Boltzmann IR radiation.
And it is unrealistic to assume no increase in evaporation if the surface temperature increases. After all, my limited understanding is that the feedbacks invoked by the IPCC rely on increased water vapour.
So the additional amount of downwelling radiation, 12W/m2 is completely inadequate to maintain a 3DegC increase in surface temperature. It is between half and a third of what is required.
If you don’t get 22-32W/m2 you don’t get 3DegC. If you only have 12W/m2 you get between 1 to 1.5DegC.
Are all the models perpetually unbalanced at the surface? This seems quite likely based on the numbers cited by Joel.

392. Dave Springer says:

anna v

“relevant to what?”

Relevant to the average surface temperature of an airless rock with an albedo around 10% orbiting around 93 million miles from the sun.

Why would you think that NOT relevant to a discussion of what the temperature of the earth’s surface would be absent an atmosphere?

I can’t help you out if you don’t understand why a thermocouple buried just deep enough in the moon so that there are no variations in it from day to day or year to year is not indicating the average surface temperature.

393. Joel Shore says:

Brian G. Valentine says:

Well, look at it from my point of view: There are some people who, by virtue of their lack of background combined with their own preconceptions based on a strongly-held need to believe in AGW, one seems unable to reach by scientific arguments, no matter how hard I try.

Well, I understand that in your state, you might feel that way. But, there are accepted ways that have worked well for our societies to distinguish between science and nonsense…and those scientific authorities have clearly come down on one side of the argument. And, in fact, you are so far out in the weeds on issues like G&T that even many who share your general view about AGW can’t stomach such nonsense.

Bryan says:

There is no such law as the conservation of radiation.
The energy that the Earth receives from the Sun can be accounted for in a number of ways for instance Chemical Potential Energy (Plants included), stored as internal energy in the oceans etc

The Planet can warm up and cool down over periods lasting several centuries and still be in harmony with the Ist law of THD if the Suns energy is stored as other energy forms on Earth.

Ah…240 W/m^2 is an awfully lot of energy to store away by the methods that you are proposing. Besides which, the various energy flows can be measured, maybe not down to the fractions of a W/m^2 that one might ideally like, but certainly well enough to dismiss any notions that the earth’s temperature can grossly violate the constraints of radiative balance at will.

394. HankHenry says:

anna v

I worked my way through the video presentation on stefan boltzmann for undergraduates of Dr. David Archer over at realclimate. In those lectures he throws in this discussion about how much time it takes for energy (I’m not sure if you’d call it heat or radiation) to work its way through the atmosphere. I gathered those considerations were something apart and supplementary to just a discussion of stefan boltzmann proper. Is this as much as saying the earth’s atmosphere has an R value? I wonder what that value would be like – on an averaged out basis?

395. Joel Shore says:

Colin Davidson: There is a reason why climate scientists like to talk in terms of the top-of-the-atmosphere and that is because the temperature at the surface is really governed by the top-of-the-atmosphere radiative balance and the processes that set the thermal structure of the atmosphere with height.

For example, in the book “Global Warming: The Hard Science” by L.D. Danny Harvey, he does a calculations where he shows that if you increase the downward infrared flux from the atmosphere at the earth’s surface by 10 W/m^2, you would only warm the surface by ~0.1 C (while cooling the atmosphere by 0.3 C). However, an externally-imposed 10 W/m^2 change in the greenhouse gas forcing produces (in his estimate, using an ~2 C per CO2 doubling climate sensitivity) about a 5 C surface temperature increase, i.e., a 50X larger response. The reason has to do with the atmospheric response: In the former case, the response is governed by turbulent heat exchange, which is very efficient in neutralizing the effect. However, in the latter case, the response is governed by the radiative damping to space, which is much weaker.

396. Brian G Valentine says:

A thought experiment:

Joel, there was a day that you knew nothing about AGW. You never heard of it, but you had rational thought.

At that time, I held up a picture of the Earth and atmosphere in outer space. I pointed out temperatures to you at tropopause, Earth, and outer space. Then I asked, “which way is heat at the tropopause going?”

When you gave me the answer, “to space,” I corrected you, saying, “the downwelling radiation is an exchange with the warmer Earth, and increases the average surface temperature due to forcing at the tropopause”

… you would have taken me for a fool, trying to beguile you with misinformation

But then, Joel, people who you admired and evidently sympathized with, have sold you on an argument that you (I feel sure) would have taken for complete and utter nonsense.

Right out in the weeds, Joel

397. anna v says:

Lets try again:

Temperature is what enters the radiation flow equations.

The temperature of the skin.

Temperature is not conserved. Energy is conserved. The -23- degrees 50cm in the ground have a deformed and unknown connection with whatever the average of the skin is: conduction equations and constants.

Take the average numbers in
107C daytime
-153 night average
add and divide by two, as is done in the GISS records of earth temperature, and you find: -28C.

The actual average will be different, integrated correctly, but not the -23C 50cm in the ground.

398. Colin Davidson says:

Joel wrote (17:12:14, 20MAR10):
“Colin Davidson: There is a reason why climate scientists like to talk in terms of the top-of-the-atmosphere and that is because the temperature at the surface is really governed by the top-of-the-atmosphere radiative balance and the processes that set the thermal structure of the atmosphere with height. ”

Don’t the energy fluxes at both boundaries have to be in balance? There is no mechanism for the TOA to warm the Surface. It has no thermal mass to speak of, and is at a very feeble temperature. Declaring that the Surface is warmed by “the processes that set the thermal structure of the atmosphere with height” is akin to saying that the surface temperature is created by magic.

The Atmosphere is mostly warmed from the surface upwards. It is not warmed from the TOA downwards. At the surface (in a Kiehl & Trenberth Diagram, and at equilibrium – both these things are simplifications so that the Physics does not get bogged down in all the other variables) only two forcings are available – absorption of solar radiation, and back-radiation from the atmosphere. If you increase the temperature of the surface, how does one balance the new KT diagram at the elevated temperature?

Only by increasing the sum of the two forcings by a massive 22 to 32 W/m^2 can the surface remain balanced. If it is not balanced then it will cool down or heat up until it is balanced, regardless of what the TOA is doing. Allowing for the (very disputed) IPCC positive feedbacks, Joel has indicated that the additional downwelling radiation is 12W/m^2 or so. That’s not enough to maintain the surface at an additional 3DegC. The most you get is 1.5DegC.

There may be something I have missed here (most likely) but I don’t think Joel has identified what it is. At present I am forced to conclude that anyone who predicts more than 1.5DegC for a doubling of CO2 has a surface imbalance hidden in his model.

399. lgl says:

Joel Shore (17:12:14) :

“if you increase the downward infrared flux from the atmosphere at the earth’s surface by 10 W/m^2, you would only warm the surface by ~0.1 C”

This sounds very strange. Has he developed a service pack for the S-B law?

Colin Davidson (00:21:13) :

How do you arrive at “a massive 22 to 32 W/m^2” ?

400. Joel Shore says:

Brian G Valentine says:

At that time, I held up a picture of the Earth and atmosphere in outer space. I pointed out temperatures to you at tropopause, Earth, and outer space. Then I asked, “which way is heat at the tropopause going?”

When you gave me the answer, “to space,” I corrected you, saying, “the downwelling radiation is an exchange with the warmer Earth, and increases the average surface temperature due to forcing at the tropopause”

… you would have taken me for a fool, trying to beguile you with misinformation

Yes, and if by heat you mean net heat (which is really the only logical thing you could talk about as flowing only in one direction) then I would to this day say that you are wrong. The net heat flow is in fact to space. It is in Willis’s steel greenhouse, it is in the Trenberth & Kiehl diagram, and it is in any other explanation of the greenhouse effect that I have seen.

It is just that the heat flow into space is less than it would be if the atmosphere were transparent to IR radiation (and the Earth’s surface were still at its current temperature).

401. Dave Springer says:

anna v

You don’t know what a thermocouple is? That is taught in high school physics. Very basic stuff. What grade are you in?

402. Joel Shore says:

Igl says:

This sounds very strange. Has he developed a service pack for the S-B law?

No…It is just that the earth’s surface can exchange heat with the atmosphere by other processes besides radiation. However, the earth system as a whole can only exchange radiation with space by radiation.

403. Joel

I take it you agree with me that there is no law of conservation of radiation!

……..but certainly well enough to dismiss any notions that the earth’s temperature can grossly violate the constraints of radiative balance at will….

But then you try to bend it back to some kind of law that does not hold unless you try to grossly violate it!

My boat uses a solar panel to keep my batteries charged up until I need to convert the chemical potential energy into some other form of energy of my choosing.
The coal that I use in my fire releases energy that was stored over 400 million years.
You could yourself think of countless other examples of EM radiation being converted into other energy forms.
Also on the topic of the millions of scientists beavering away fully united in support of a co2 greenhouse effect is as bogus as the effect itself.
What any sceptic finds is this theory is like an inverted triangle balanced on a tiny base.
The three sets of so called independent data supporting the theory is reduced to two because of the Phil Jones affair.
We then find that the other two were not as independent as claimed.
The sceptics choose a variety of methods to test the AGW theory.
Some do it by actually checking the data to see it it supports the theory.
Some do it by providing an alternative theory such as solar flares.
Some(mainly geologists) take a historical approach to find out if the present time is highly unusual.
Others like G&T check to see if the Physics behind AGW theory stacks up.
To expect all sceptics to be in total agreement with one another is really stupid.
I am from a Physics background and I must say I am much more impressed by G&T than any counter argument.
In fact some of those attacking G&T show serious signs of scientific ignorance.
If say a Physics Professor specialising in Heat Transfer Thermodynamics was to criticise their paper, I’m sure they would regard that as a serious challenge, but as yet this has not happened.

404. Brian G Valentine says:

Dave Springer, I don’t exactly care for that kind of tone directed at Anna because you’ve got no basis for it

405. Dave Springer says:

anna v

Take the average numbers in
107C daytime
-153 night average
add and divide by two, as is done in the GISS records of earth temperature, and you find: -28C

diurnal mean temperature swing = 107+153 = 260

half of diurnal change = 260 / 2 = 130

half of diurnal change added to nightime mean = -153 + 130 = -23

half of diurnal change subtracted from daytime mean = 107 – 130 = -23

Actual measured regolith temperature at 50cm depth was, unsurprisingly, a constant -23C.

QED

406. Joel Shore says:

Bryan says:

I take it you agree with me that there is no law of conservation of radiation!

My boat uses a solar panel to keep my batteries charged up until I need to convert the chemical potential energy into some other form of energy of my choosing.
The coal that I use in my fire releases energy that was stored over 400 million years.
You could yourself think of countless other examples of EM radiation being converted into other energy forms.

Look, you could also complain that climate scientists don’t include the effects of quantum gravity or the relativistic corrections to the speeds of winds and ocean currents. The question is whether this is at all relevant. I haven’t done the calculation myself but I’ll give you a hint from what I do know: All those fossil fuels that accumulated over hundreds of millions of years that we are now burning very rapidly (relative to the time that it took them to form) amounts to an energy usage averaged over the earth’s surface of ~0.02 W/m^2.

And, by the way, your solar panel only successfully converts a small fraction of that energy and what it stores gets converted eventually into heat when you run your boat. In the end, the net amount of energy you store in that battery averaged over the course of year will be very small (and will be either negative or positive depending on whether the battery is in a more or less charged state at the beginning of the year as at the end).

We are also measuring the various energy fluxes and, while we can’t yet measure them to the fraction of a W/m^2 that would be necessary to directly measure what radiative balance there is, I believe that they are measured accurately enough to say empirically that there is radiative balance within at least a few W/m^2.

I am from a Physics background and I must say I am much more impressed by G&T than any counter argument.
In fact some of those attacking G&T show serious signs of scientific ignorance.
If say a Physics Professor specialising in Heat Transfer Thermodynamics was to criticise their paper, I’m sure they would regard that as a serious challenge, but as yet this has not happened.

There are so many things I could say to this that I don’t know where to start:

(1) One doesn’t need to be a specialist in heat transfer thermodynamics to understand that G&T is nonsense.

(2) Most “skeptics” like to say that it is not the credentials that matter but rather the argument. So, why should G&T only take seriously those with such credentials?

(3) G&T are hardly the ones in the position to be deciding what constitutes a serious challenge to their paper. The fact that it was published at all is an extreme embarrassment and nobody in the field is taking it seriously. In fact, one of my motivations for participating in the comment debunking it was the notion that it was a public service so that the climate scientists themselves could focus on real science rather than wasting their time dealing with such nonsense. (I also felt a sense of duty as a physicist since the paper appeared in a physics journal and G&T make much of the fact that their physics viewpoint somehow allows them to see what others have missed.)

(4) As it happens, I am a physicist who has published papers in the area of statistical physics (which really provides the underlying foundations for thermodynamics) in some of the top physics journals in the world (e.g., Physical Review Letters). I have also done some heat transfer calculations in a more practically-oriented corporate research and development environment.

407. anna v says:

Well, I did make an arithmetic mistake

(-153+107)/2 makes -23.

(I was hurrying to keep an appointment, if that is an excuse for bad arithmetic)

I consider it serendipitous, or maybe the choice of 50cms was made because of the coincidence of the numbers ?

Temperatures on the Lunar surface vary widely on location. Although beyond the first few centimeters of the regolith the temperature is a nearly constant -35 C (at a depth of 1 meter), the surface is influenced widely by the day-night cycle.

so -23 is a choice, why not -35 as this reference says?

BTW, I am a retired particle physicist doctorate and all.

408. lgl says:

Joel Shore (06:50:50) :

But only 20% of the energy transport from the surface is non-radiative. Why would suddenly most of the added 10 W be returned as non-radiative? Still sounds very strange.

409. lgl says:

… and 5 C after a CO2 doubling?? That’s 27.8 W/m2 more from the surface + the non-radiation, or a 7.5 amplification of the 3.7 W. I really don’t understand any of this …

410. Joel

I can hardly believe some of the things you are writing.
You claim to be a Physicist yet you think there is such a thing as conservation of radiation.

Point me in the direction of one Physics book to back up your claim

….We are also measuring the various energy fluxes and, while we can’t yet measure them to the fraction of a W/m^2 that would be necessary to directly measure what radiative balance there is, I believe that they are measured accurately enough to say empirically that there is radiative balance within at least a few W/m^2………..

The total energy stored in fossil fuels over millions of years can be ignored apparently

… I haven’t done the calculation myself but I’ll give you a hint from what I do know: All those fossil fuels that accumulated over hundreds of millions of years that we are now burning very rapidly (relative to the time that it took them to form) amounts to an energy usage averaged over the earth’s surface of ~0.02 W/m^2…….

Please send this information to the IPCC

I have pointed you to elementary mistakes by A. P. Smith and you just brush them aside

You are completely contemptuous of G&T yet all you produce is a string of insults with no serious attempt to deal with any of the many points they make.
You claim to have produced more papers than Rupert Murdoch, so we will just have to take that on trust.
When and if your refutation is published we can then check just what the qualities of the papers were.
On present evidence of yourself, A.P.Smith, Eli Rabett and so on I think that G&T will not be losing any sleep.
The usual way to resolve matters of scientific fact is to point to some experimental proof rather than a computerised projection.
The ability to hurl insults is inversely proportional to scientific proof.

411. Joel Shore says:

Igl: No…In that calculation, Harvey assumed a 5 C increase from an imagined 10 W/m^2 forcing. Since a CO2 doubling is ~4 W/m^2 forcing, he is assuming a sensitivity of ~2 C per doubling.

412. Brian G Valentine says:

Thank you, Joel.

So then at the tropopause, to make the surface temperature higher, the radiant heat of the Earth is

– reflected back to Earth at the tropopause (nope)

– absorbed by some molecules there and re-radiated …

… Which way. You tell me which way the radiation is going – up, or down.

The answer is: The radiation at the tropopause is going the opposite direction that AGW theory is going

413. Willis –

I have to say I have read through this entire thread (I’m home sick with a bad cold), and I am impressed at how calm and professional you remain in the face of many reasons not to.

Great job.

In the interest of transparency, I will say that I have a PhDEE, I love Physics, have read several books on the subject of “Global Warming” including the CRUTAPE letters and very much appreciate this website. Hats off to all of you guys who work to stay objective.

Thanks,
Mike

414. Joel Shore says:

Brian: I suggest that you re-read my post of (19:32:16) 19 March. It is actually not that difficult to understand if your mind is at all open to new things even if they go against your ideological predispositions.

To summarize: The net flow of terrestrial radiation is out. This still makes the temperature higher due to the greenhouse effect than it would be in an IR-transparent atmosphere because the net flow is less than it would be in that case.

I don’t know how I can explain it any simpler. There are also various toy models that you can play with to get the picture. Willis’s steel greenhouse is one. Another one, which is admittedly more abstracted from the actual system in question but is kind of fun is where you have a blackbody sphere representing the sun that is at a constant temperature T_s and then you have it surrounded by one or two blackbody concentric spherical shells (A and B, which are analogs…in a very abstract way…of the earth and the atmosphere, respectively, with the radius of B slightly larger than A). There is empty space (assumed to be at zero temperature) beyond that. The question is then: What is the steady-state temperature of spherical shell A when shell B is absent and what is the temperature of shell A when shell B is present? Also, when Shell B is present, which way is the net radiative heat flow, from A to B or B to A? (These questions can be answered exactly by a simple calculation if you assume that the radii of the sphere and the two shells are close enough that one can neglect any “self-view” that the inner surface of shell A or B has of itself.)

415. Joel Shore says:

You claim to be a Physicist yet you think there is such a thing as conservation of radiation.

That’s not what I said; I suggest you might try reading it again.

The total energy stored in fossil fuels over millions of years can be ignored apparently

The point is that such energy storage happens only very slowly. Even though we are burning those fuels at a rate that far exceeds the rate at which they were formed, we are still producing only about 0.02 W/m^2 of direct heat by doing so.

Please send this information to the IPCC

The IPCC already knows this, which is why the current concern is over the changes that we are making to the chemistry of the atmosphere by burning fossil fuels that cause it to retain more of the sun’s energy rather than concern about the effect of the waste heat that we are producing by burning fossil fuels.

I have pointed you to elementary mistakes by A. P. Smith and you just brush them aside

I don’t see where you pointed to any such mistakes. The one specific thing that you questioned is whether Arthur is correct when he asserted that he thought an IR-transparent atmosphere would be isothermal. I would have to think more about that, but it is irrelevant to the main issue because, whether or not it is isothermal, we know in the case of an IR-transparent atmosphere what the surface temperature has to be.

You are completely contemptuous of G&T yet all you produce is a string of insults with no serious attempt to deal with any of the many points they make.

I guess you too missed my post of (19:32:16) 19 March where I explained very clearly where G&T go wrong in their claim of a violation of the Second Law. It seems strange to me that neither you nor Brian Valentine have been interested in engaging me on those points, seeming to prefer instead to go around attacking strawmen.

You claim to have produced more papers than Rupert Murdoch, so we will just have to take that on trust.

I don’t see where I gave you a specific number. But, if you want to see my papers, all you have to do is a simple google scholar search since I post under my real name here. (Additional fact: Middle initial is D.)

416. Colin Davidson says:

Igl (03:59:11) asked: “How do you arrive at “a massive 22 to 32 W/m^2″ ?

Please see my post at 18:18:13, 19MAR10. In part:
“Cranking in the numbers:
Change in Forcing = 4sT^3dT + 78xdT. (s is 5.67×10^-8, dT is change in temperature, x is percentage increase in evaporation per DegC).
The big unknown in this equation is x, the increase in ebaporation. The Clausius-Clapyeron equation gives an upper limit of 6.5%, and some scientists think it is as low as 2%. It’s not 0%.

For x=2% the surface sensitivity is 0.15DegC/W/m^2, and the Change in Forcing is 22W/m^2 if the temperature rises by 3DegC.
For x=6.5% the surface sensitivity is 0.095DegC/W/m^2 and the Change in Forcing is 32W/m^2 for a temperature rise of 3DegC.”

The sensitivity at the hot, massive Surface is very different to the sensitivity of the thin cold atmosphere at the Tropopause. The system has to work much harder to heat the surface and keep it hot than it does at the Tropopause.

417. Colin Davidson says:

Joel Shore (06:46:04, 21MAR10) said:

“It is just that the heat flow into space is less than it would be if the atmosphere were transparent to IR radiation (and the Earth’s surface were still at its current temperature).”

I think that statement may be wrong. At equilibrium (planetary and atmospheric temps stable) the energy flux radiated to space equals the energy flux received from space (neglecting any flux from the centre of the planet.), regardless of the state of the greenhouse.

My understanding is: Some of the radiated energy from the Earth (according to KT around 40W/m^2) is at the “window” frequencies and passes directly out to space. The rest of the energy which is going into the atmosphere (a small amount of net radiated energy, about 25W/m^2, plus the directly conducted energy about 25W/m^2 plus the latent heat in evaporated water about 80W/m^2, plus the absorbed sunlight about 75W/m^2) can only leave the planet by radiation. It gets radiated from two primary bands:
1. The band of water vapour. The effective level is somewhere near the top of the clouds. Most of the radiation (at least two thirds) is from here.
2. The CO2 in the mid Tropopause to Stratosphere. About 20-25% comes from here.

418. Brian G Valentine says:

Here’s an even simpler toy model from about p200 of An Inconvenient Truth (and about all he has to say about how it works):

“CO2 acts like a blanket that keeps the Earth too warm.”

419. Brian G Valentine says:

Folks, if some fish that Al Gore or Joel want to sell you don’t smell too good,

420. Brian –

I know I am new to this thread – and to this site (I have been lurking for awhile while studying), but you cannot be seriously quoting Al Gore on thermodynamics or physics, rght? I mean really?

This is a guy who shows a glass of water with Ice in it, that does not protrude above the rim of the glass, and then shows it melting with the result that the water flows out of the glass onto the table the glass sits on…really? Hardly Mr. Wizard, I don’t think he is worth a quote. A Nobel Prize maybe, but that’s politics, not what is being discussed here.

Mike

421. anna v says:

Joel I agree with 1) and 2)

For
(3) Despite the fact that the net flow is from earth to atmosphere, the effect of an IR-active atmosphere is still to produce warming relative to the case of an IR-transparent atmosphere. This may be the point that trips the most people up….It seems like an almost unstated assumption in many arguments of a Second Law violation that in order for the greenhouse effect to occur, the net flow must be from atmosphere to Earth. ****THIS IS WRONG.**** The reason that this is wrong is because in the comparison case, of an IR-transparent atmosphere, all the radiation emitted by the earth escapes into space. Hence, anything that causes some of that radiation to be returned to the earth will cause warming relative to that case.

I come to think that it is the semantics that causes the confusion at this point.
The active energy role given to the atmosphere . Instead of “returned” one should state “retained” .

This misuse, as standard thermodynamics goes, is enhanced by the terminology of “forcings”.

Radiation is the dominant way energy leaves this ball and enters this ball, and can be used instead of total energy balance with small errors.

Within this ball, earth, the equivalence given and imposed to think in terms of “radiations” and “forcings” when a multitude of other heat transport involving processes exist, leads to errors, ( at least in temperature estimates) imo . It is wrong to state the problem in terms of Watts/m^2 as if all processes are perpendicular to the surface of the earth.

It is true that when one integrates to solve a problem, one can turn it into shells dx and consider the forces acting on this , but one does not go around making a terminology : the central part of the earth give A contribution to gravity, the magma adds B, the mantle C, in order to describe to the layman scientist how gravity works on the surface. ( remember the mechanics problem of a marble falling in hole that goes completely through the center of the earth to the other side?) It would be confusing and not useful for calculations involving gravity on the surface where people need a formula.

I believe this sort of confusion has been introduced by the climate terminology and makes it difficult to see the forest for the trees and introduces errors in actual calculations.

One, imo, should be saying: the heat capacity of the atmosphere is increased by the existence of H20 and CO2 etc, from x to y, and thus heat transport to space is delayed by z , instead of handwaving watts/m^2.

So it may only be semantics, but thermodynamics says that a cooler body cannot warm a hotter body unless work is done. I can imagine the gigantic system of convection precipitation evaporation etc in the atmosphere/ocean system to be described as an equivalent heat pump where the energy is supplied by the sun and the the work is done by the winds gravity tides and the chemistry. A passive ball as is described with forcings and watts/m^2 and an atmosphere actively warming violates the second law , imo always of course.

CO2 has maybe a tiny role in this heat engine, by changing the heat capacity.

422. Colin Davidson says:

Igl wrote(06:50:50, 21MAR10):
“But only 20% of the energy transport from the surface is non-radiative. Why would suddenly most of the added 10 W be returned as non-radiative? Still sounds very strange.”

It is important to note that it is the NET radiative transfer (absorbed – radiated) which heats the air, not the absorbed radiation. So the actual transfer of energy from the Surface into the Atmosphere is:
Net Absorbed Radiation (= IR Radiated from the Surface(390) – The portion which is not absorbed and escapes straight to space (40) – The Back Radiation (324), the figures come from K&T 1997 from the IPCC AR4, Chapter 1) = 26W/m^2
+ Direct Conduction into the air = 24W/m^2
+ Latent Heat in Evaporated Water = 78W/m^2

So about one fifth of the energy transferred from the surface is radiated,
one fifth conducted,
and three fifths is in water vapour as latent heat.

When the surface warms further, evaportion increases, and the NET surface radiation absorbed by the atmosphere falls by exactly the same amount. At a 3 DegC increase, the evaporation increases by between 6 and 16 W/m^2 (scientists are unsure) to 84 to 94W/m^2, and the NET radiation drops by that amount to between 10 and 20W/m^2.

423. Colin Davidson says:

Joel Shore wrote (19:16:13, 21MAR10)
“The net flow of terrestrial radiation is out. This still makes the temperature higher due to the greenhouse effect than it would be in an IR-transparent atmosphere because the net flow is less than it would be in that case”

That is incorrect I think.
The net flow is identical in all cases of the atmosphere. Neglecting the flows into and out of the solids/liquids of the planet, (which for clarity only I ignore by claiming an equilibrium which I acknowledge never exists in practice) the incoming solar radiation is always balanced by the outgoing radiation.
This outgoing radiation comprises reflected sunlight, IR “through the window” direct from the surface, and IR from the gases in the atmosphere, primarily Water Vapour, and to a considerably less extent, CO2.

It is reasonably obvious that the higher one goes in the atmosphere the more chance a photon emitted by a water molecule will have of NOT being absorbed by a higher water molecule. If one is very low down then any radiation from water molecules is completely blocked by the overlying water molecules. It is only where the water vapour thins out (top of the clouds) that emissions from water vapour have a good chance of making it to space. (Note that the intensity from this layer is much higher than from the CO2, as it is relatively warm – around minus10DegC and water vapour has a much more exrensive spectrum).

Similarly for CO2, but in this case the extinction horizon is deep in the Tropopause, and the majority of emissions are coming from the stratosphere. (The gas is much colder, around -45DegC, and CO2 has less spectrum, so it emits much less energy than the water vapour).

If you increase the concentration of either gas, the level at which extinction occurs changes. For an increase in gas concentarition this is higher in the atmosphere. The resultant energy imbalance is called “Radiative Forcing” (or “Feedback” in the case of water vapour, which the IPCC doesn’t like very much). That imbalance causes local cooling or heating of the atmosphere until a balance is restored. This is called the “Greenhouse Effect”.

That’s my understanding, which means it is probably wrong!

424. Joel

Here is the direct link you require I hope you read the whole piece so as not to say I pulled this out of context.
Its easy to make a slip when responding in a blog but what alarms me is that Arthur did not take the chance to set the record straight.
It seems an elementary mistake – draw your own conclusions.
Try to cut down on the insult throwing.
If you think about it it is more the language of the football terraces than of science.
Rational debate and adherence to the scientific method is the only way to make progress.

…..In fact, I stated earlier that the atmosphere would be essentially isothermal, at the surface temperature. So your claim that I think the “temperature at top of the N2/O2 atmosphere would be about 30 degrees C below the surface” is wrong. Not that I see any significant logical conclusion you are drawing from the issue. http://arthur.shumwaysmith.com/life/content/the_arrogance_of_physicists

425. Colin Davidson says:

Anna V(22:13:06, 21MAR10) wrote:
“One, imo, should be saying: the heat capacity of the atmosphere is increased by the existence of H20 and CO2 etc, from x to y, and thus heat transport to space is delayed by z , instead of handwaving watts/m^2.”

I think that is only partially correct. The “heat capacity” is presumably the amount of energy it takes to heat a certain mass of air by a certain amount. The concentrations of Water vapour and CO2 in the air make almost no difference to the heat capacity.

But I said partially correct. Where I think the statement is sort of correct is that if water vapour concentration is increased then the air is actually carrying much more energy – due to the increased latent heat.

So I think it is untrue to say that if CO2 concentration is increased the heat capacity of the air is increased.

But if the surface temperature goes up and as a result there is more evaporation, then the air is holding more energy.

It’s quite interesting – as the surface temperature increases, less energy is being transported into the lowest levels of the atmosphere (by radiation and convection), and more is going to the middle levels (the clouds) in evaporated water vapour.

426. lgl says:

Colin Davidson (20:21:36) :

Then we pretty much agree. Correcting for the evaporation I’m ending in the area 1.3 C per CO2 doubling. So if K/T budget is right then IPCC is wrong. Cleary it can’t be us two being wrong :-)
But I totally disagree with your (01:01:42) …

427. Dave Springer says:

anna v

I have no idea where they get the lunar temperate data in those quotes you keep using. The reference is not published by NASA and it contains no references to the actual data returned by the sensors in the boreholes.

The full data record is not public yet but NASA says it will be available for anonymous FTP download “soon”. If you had checked my original comment on this you’d find I got my data from the link below which has the data plotted at low resolution for Apollo 15 & 17. Apollo 17, by the way, recorded a constant regolith temperature of 18C. 23C was the constant temperature recorded at the Apollo 15 site. Apollo 17 was closer to the moon’s equator (20 degrees n. latitude vs. 26) and the regolith there was also darker, both of which combine to make the average surface temperature there 5C warmer. I used the Apollo 15 site as it’s more representative of the typical lunar surface in albedo and equidistant between pole and equator.

http://education.ksc.nasa.gov/esmdspacegrant/LunarRegolithExcavatorCourse/Chapter5.htm#OtherPhysicalProperties

That said, there should be no argument from any physicist that once the borehole depth is deep enough to smooth out the diurnal heating/cooling fluctuations the constant temperature obtained is the average of the surface temperature. This is pretty simple stuff. The calculations are not simple if you are trying to go backward from watts/meter^2 at the surface to the temperature at any particular depth. Then you need to know the thermal diffusion characteristics of the substrate and because any real world substrate is not going to be homogenous the calculated result will never be quite as good as a measured result. When you have a thermocouple buried at a certain depth you don’t need to do any calculations as the thermocouple is giving you the correct result of those calculations with the actual dirt doing the integration of the heat flow equations for you. The actual dirt does the calculation for every quantum particle in the whole system which is something you cannot hope to do on paper. The best you can do on paper is use statistical thermodynamics to predict bulk behaviors of systems with many many particles. This is how experimental science works. You produce hypothetical results based on your perception of how things work then you obtain actual results from the real world and compare to your hypothetical results. Experiments can yield bogus data of course but in this case (the Apollo heat flux experiment) the results are quite reliable as the instrumentation was nothing new, the deployment rather simple, and no uncontrolled variables of any significance to worry about (the interior of the moon is geologically dead, no atmosphere, no water transport of heat through the soil, no seasons, etc.)

Evidently you’ve never worked on the experimental side or it’s been so long you’ve forgotten what it’s like because a thermocouple is as basic a piece of lab equipment as test tubes, centrifuges, litmus paper, and bunsen burners. The principle of operation of thermocouples is basic high school physics and, if nowhere else, you had to have used thermocouples in high school and college science courses where there was any laboratory work included in the course. I was shocked when you didn’t know what one was.

Anyhow, if you want the equations which apply to soil physics and heat flow I suggest going here:

http://soilphysics.okstate.edu/software/SoilTemperature/index.html

The above is a downloadable software package that does the math for you, either calculating average surface air temperature taken from from soil temperature readings at depth or going the other way and predicting soil temperature at depth from average air temperature. The documentation with the software lays out the equations used by the software. This is important stuff when doing things like designing energy efficient earth-insulated buildings and using heat pumps with heat exchangers in boreholes. For instance, if you’re in upstate New York the constant soil temperature, when you have enough thermal mass to smooth out seasonal temperature change, is about 52 degrees. In south-central Texas where I’m at the average soil temperature is 72 degrees. That’s a big difference if you’re sinking a house in the ground or piling dirt around it to leverage the thermal inertia of the earth for heating/cooling or drilling a hole in the ground to drop an HVAC heat exchanger into. Same goes for the moon should we ever start having buildings there. It’s a very handy fact to know that burying a habitat one meter deep at 26 degrees north latitude on the moon with regolith similar to Apollo 15 landing site would produce a stable inside temperature of -23C absent any internal heating or cooling or -18C for a similar habitat at 20 degrees north latitude under regolith with an albedo like that at Apollo 17 landing site.

And back to the main point – if the earth didn’t have an atmosphere it would be quite similar to the moon as far as average surface temperature. I’m sure Willis knows this even if he won’t admit it and now he appears to be sulking. What the heck is it about the internet that makes people so unwilling to admit mistakes?

428. Joel Shore says:

Colin Davidson says:

That is incorrect I think.
The net flow is identical in all cases of the atmosphere. Neglecting the flows into and out of the solids/liquids of the planet, (which for clarity only I ignore by claiming an equilibrium which I acknowledge never exists in practice) the incoming solar radiation is always balanced by the outgoing radiation./blockquote>

Colin,

Yeah…There is always some confusion when talking about the greenhouse effect regarding at what point in time one is talking about. When I said that the net flow out is reduced, I am imagining instantaneously “turning on” the greenhouse effect and seeing the immediate result. But, of course, once the net flow out of the system is reduced, the result will be that the earth heats up until radiative balance is restored. And, once that occurs, what you have is, as you note, that the net terrestrial radiation that escapes is the same as before but the earth has to be warmer in order to produce this result.

That’s my understanding, which means it is probably wrong!

No, I think what you describe is (at least essentially) correct.

Bryan says:

Here is the direct link you require I hope you read the whole piece so as not to say I pulled this out of context.
Its easy to make a slip when responding in a blog but what alarms me is that Arthur did not take the chance to set the record straight.

At this point, I am confused about what in Arthur’s piece you feel is incorrect (since you seem to say that you don’t really disagree with the isothermal part).

Brian G Valentine says:

Here’s an even simpler toy model from about p200 of An Inconvenient Truth (and about all he has to say about how it works):

“CO2 acts like a blanket that keeps the Earth too warm.”

Brian, I don’t understand why you want to quote Al Gore rather than discuss the science. The question I thought we were talking about is whether the atmospheric greenhouse effect violates the Second Law not whether Al Gore’s analogy is perfect or not.

429. anna v says:

I am tired of this one upmanship.

I was not questioning the term “thermocouple”. I was questioning your assigning it to the 50cm layer of the moon surface.

from wiki
A thermocouple is a junction between two different metals that produces a voltage related to a temperature difference.

Which is what I remembered and has nothing to do with your model of the ground integrating global temperatures of the moon.

It must be the “couple” that is confusing.

That there will be a functional connection, there will be. But until one integrates the skin surface temperatures ( which are the ones responsible for radiation and its balance) and has the average moon temperature I will not be convinced that the 50cm layer temperature gives the average moon temperature, and not the 1m or 2m. The steadiness in day night changes is a necessary condition if you are talking of an integrator, but not a sufficient one, always in my opinion. It is the differences that are eliminated but that does not fix the absolute value.

After all, if the regolith were a complete insulator, the 50cm layer would be at close to 0K while the average skin surface would still be -23 ( with the numbers above for the sake of argument ). Raise the heat conductivity incrementally and the temperature will rise correspondingly, but in no way it will be the surface average energy, though the change will be functionally connected ( if the average temperature became -20C correspondingly the 50cm level would rise by a calculable increment).

430. anna v says:

That said, there should be no argument from any physicist that once the borehole depth is deep enough to smooth out the diurnal heating/cooling fluctuations the constant temperature obtained is the average of the surface temperature.

This is one physicist who doubts it, as I explained in my previous post.

There are more with me I guess.
If this were true, why go through the trouble of surface thermometers and not grid the land with boreholes?

Our disagreement lies in the absolute value of the temperature, when first the seasonal/time variation stops being evident. You are saying it is the average temperature over the seasons/times and I am doubting this identity.

For example, in:
http://www-personal.umich.edu/~shaopeng/science98.pdf

They are talking of deltaT. Not absolute T. I have no quarrel with that.

431. Brian G Valentine says:

“The question I thought we were talking about is whether the atmospheric greenhouse effect violates the Second Law ”

The answer is, I can’t go any farther to convince you, and apparently, conversely.

If you really think about it this greenhouse gas idea causing global warming in the sense that it applied has to be completely erroneous. CO2 has been in the air since the Earth had an oxidizing atmosphere, probably less than a billion years after the first appearance of life on Earth, and and from all appearances of the geologic record, the rise and fall of CO2 in the air has never been associated with true climactic change. It has been the result of it, related to ocean solubility of it.

From a phenomenological standpoint, it MUST violate the second law Joel OR CLIMACTIC CHANGE FROM CO2 IN THE AIR WOULD HAVE HAPPENED IN THE PAST

can’t you see that? It’s Cold Fusion all over again. If Cold Fusion were possible at anything exceeding quantum tunneling there would be no such thing as an ocean.

If greenhouse CO2 were possible at ANY level the atmosphere would have saturated with water vapor long ago. There is no way it could be stopped

Don’t you have any appreciation for what three billion years of geologic history is?

Fleishman and Pons could be stopped because nobody could build their little cold fusion test tube thing (not that anybody need to try). This AGW thing cannot be so easily stopped because there is nothing but rational thought to counter it and that’s JUST NOT ENOUGH for some folks who for one reason or another actually like the idea and will go to the end of the Earth to defend it

432. Colin Davidson says:

Igl wrote (02:38:39, 22MAR10):
“Then we pretty much agree. Correcting for the evaporation I’m ending in the area 1.3 C per CO2 doubling. So if K/T budget is right then IPCC is wrong. Cleary it can’t be us two being wrong :-)
But I totally disagree with your (01:01:42) …”

I think what Igl may disagree with is my statement that the atmosphere is heated by NET absorbed surface radiation, rather than the actual amount of radiation absorbed.

You are standing in a room. It feels neither hot or cold. You are receiving around 325 W/m^2 of radiation from all directions. Why don’t you warm up? Because you are also radiating about the same out to your surroundings.

Replace the person with some air. looking to the side, the air absorbs about the same radiation as it emits, so it does not heat or cool from that source. Looking down at the ground however, it absorbs somewhat more than it emits, so it warms slightly. It is not the absolute anmount of radiation but the NET which counts.

In my post I calculated the relative strengths of the surface fluxes which heat the atmosphere. These are:
CONDUCTION (24W/m^2) which heats the air in direct contact with the surface
NET ABSORBED RADIATION (26W/m^2) which heats the air up to about 500m, but over half that radiation is absorbed within the first 50m
LATENT HEAT IN WATER VAPOUR (78W/m^2) which heats the air when the water vapour condenses into water droplets, ie in the clouds.

If the surface temperature increases by 3DegC, these values alter and become:
CONDUCTION (24W/m^2)
NET ABSORBED RADIATION (Between 10 and 20 W/m^2)
LATENT HEAT IN WATER VAPOUR (Between 84 and 94W/m^2)

433. Colin Davidson says:

I must point out that my posts are really only trying to explain and extend the physics of the ficticious world depicted by Kiehl &Trenberth, particularly their 1997 version which is the one used by the IPCC AR4 Chapter 1. The reason for doing this is to remove all of the variables (non-equilibrium, night/day, cloud/not, land/sea, latitude, season, wind, precipitation, altitude, sea currents, energy from the centre of the earth) from the discussion so that the basic physics can be explored without the complications that these other factors involve.

Going back to that ficticious world, I have a problem, enunciated in my posts at (14:10:34, 20MAR10) and (00:21:13, 21MAR10). That is that the additional downwelling radiation in a 3DegC higher temperature world, is much less than what is required to keep the surface at a 3DegC higher temperature. The surface is much less sensitive to downwelling radiation than the air at the tropopause for two major reasons:
1. It is much hotter than the Tropopause , so the increase in temperature yields a much greater increase in surface radiation.
2. Any temperature increase increases the rate of evaporation, so there is an additional flux required to supply the energy of latent heat in the evaporated water.

The IPCC claims that a doubling of CO2 prodduces an additional 4W/m^2 of “Radiative Forcing”, which through the controversial positive feedback due to water vapour and clouds turns into about 12W/m^2. It claims this warms the upper atmosphere by about 3DegC, and that this local warming gets transmitted to the surface by the magic of constant lapse rate. OK, suppose all that is true.

Where does the additional 22 to 32 W/m^2 downward radiation required to maintain the surface temperature at an additional 3DegC come from? (I note in passing that these are minimum, not maximum estimates, as the additional cloud produced due to the additional evaporation would tend to increase these figures).

434. Joel
You either did not follow the link or you failed to understand it.
The link shows that Arthur Smith thinks that if CO2 and H20 vapour were removed from the atmosphere.
The atmosphere would then become isothermal from the surface to a height of 30Km.
I certainly do not believe in such nonsense.
Any person that had a clue about the Kinetic Theory (and/or ) had climbed a hill would be in no doubt that the temperature drops steadily.
I thought that he would correct the record once someone had pointed out how foolish it was.
There was no correction and perhaps he still believes it!
Since you are a friend of his perhaps you could have a word with him and explain why this is physical nonsense.

435. Joel Shore says:

Brian G Valentine says:

From a phenomenological standpoint, it MUST violate the second law Joel OR CLIMACTIC CHANGE FROM CO2 IN THE AIR WOULD HAVE HAPPENED IN THE PAST

One doesn’t “prove” 2nd Law violations from a phenomenological standpoint (especially when one’s interpretation of the phenomenology disagrees with most of the the people who, you know, actually publish in the field).

Fleishman and Pons could be stopped because nobody could build their little cold fusion test tube thing (not that anybody need to try). This AGW thing cannot be so easily stopped because there is nothing but rational thought to counter it and that’s JUST NOT ENOUGH for some folks who for one reason or another actually like the idea and will go to the end of the Earth to defend it

Or maybe it is because those who who are arguing against it don’t really have very coherent scientific arguments and just put up a bunch of nonsense, like G&T did, that then gets swallowed by people who want to believe it even though it is easy to demonstrate what nonsense it is. If that is “rational thought”, I think you should try something else!

436. Brian G Valentine says:

Joel, the only suggestion I have right now is to go “prove” your point with some more condescension and arrogance at people who write papers you don’t like and who question you on the web logs.

With some practice, maybe you can get as arrogant as Eli Rabbit!

Hey – maybe you and Eli can do some joint research together to answer the question

Which of the following is the stinkiest fraud?

– Gerlich and Tscheuschner
– Gerhard Kramm
– Brian Valentine

Publish your results in a reputable journal

437. Colin Davidson says:

Joel Shore (05:15:45, 22MAR10) wrote:
“Yeah…There is always some confusion when talking about the greenhouse effect regarding at what point in time one is talking about. When I said that the net flow out is reduced, I am imagining instantaneously “turning on” the greenhouse effect and seeing the immediate result. But, of course, once the net flow out of the system is reduced, the result will be that the earth heats up until radiative balance is restored. And, once that occurs, what you have is, as you note, that the net terrestrial radiation that escapes is the same as before but the earth has to be warmer in order to produce this result.”

I would like to thank Joel for his answer.

I have a problem with”Radiative Forcing” which is described as a step change to a stable system (The imbalance at the Tropopause if all change in the Stratosphere is complete but no change has happened to the Troposphere). This is because we are imposing a step change on the static, imperfect model that is described by K&T.

I want to understand, instead, the final state, not the transition. I want to see the K&T diagram for a +3DegC world, and I want the surface balance explained in detail. For example, I want to know what the REDUCTION in sunlight absorbed by the Surface is (because it’s cloudier). I want to know how much extra back radiation there is due to a warmer atmosphere. I want to know how much surface radiation is predicted to escape direct to space. I want to know what the amount of direct conduction there is, and if it has changed from the +0DegC world, why. I want to know how much evaporation there is going to be, and why. I want to know how much extra back radiation there is due to the increase in concentration of the two main gases, with a justification.

I guess it’s not really important, because we are only talking about the really simplified, unrealistic model. But I’m curious. I can’t get a surface balance in that world – not one that’s driven by 2xCO2, unless the First or Second Laws are in abeyance.

438. Joel Shore says:

Bryan:

I don’t see how the climbing a hill notion proves anything: Arthur is talking about a hypothetical case. He knows that the lapse rate exists in our current atmosphere. I also am not clear as to what kinetic theory dictates as to the thermal structure of the atmosphere. Care to enlighten me?

I honestly don’t have a “dog in this fight”. What the thermal structure of the atmosphere would be in the absence of IR-absorbing gases is not obvious to me. However, the one thing that I do know is that the temperature of the surface would be dictated by radiative balance, which I think was Arthur’s main point, the entire thermal structure being somewhat of a side discussion.

Brian Valentine:

It is certainly a bizarre world we live in where those people who call others “arrogant” are those like you and G&T who somehow feel that they know climate science much better than most of the world’s climate scientists. I sort of associated arrogance with having a sense of the correctness and importance of one’s own ideas that is way out of balance relative to the ideas of those who have clearly studied these things much more closely and have the track record of accomplishments to show for this. But, perhaps you have a very different definition.

439. cba says:

so joel shore, what is the specific sources and amounts of the additional w/m^2 after a 3.7 w/m^2 increase due to doubling the co2?

since the total w/m^2, including cloud cover, is around 150 w/m^2 and the total rise in temperature is 33 deg C, it should take a new total of about 13.6 w/m^2 to achieve a 3 deg C rise and your co2 is only going to contribute 3.7 so effectively, there must be 10 w/m^2 additional coming from somewhere.

440. Joel Shore says:

cba: First, I might quibble with your estimate of 13.6 W/m^2 for a 3 C rise…I think that since the accepted value for the no-feedback case of doubling CO2 is ~1.0-1.1 C, then you need about 11 W/m^2 total to get to 3 C.

But, that is a small point of contention, and in answer to your basic question, these other amounts presumably come from the water vapor feedback, the ice-albedo feedback, and…with the most variation from model-to-model…the cloud feedback.

My basic point is just this: Willis believes that he has shown that the climate sensitivity is small. What I think he has actually shown is that the climate sensitivity in the absence of feedbacks is fairly small and hence it is the estimated positive feedbacks that make the sensitivity large, which is something that we already knew. (Although, like I said, I am still confused as to why his calculation got a climate sensitivity of about half the accepted “absence-of-feedbacks” value when I think, if correctly done, it should get something close to the “absence-of-feedbacks” value. One thing I have been wondering about is how the lapse rate feedback fits into this scenario, but I don’t think it is large enough to account for the discrepancy.)

441. Brian G Valentine says:

Believe me, Joe, I’m not doing half a good a job at dispelling the notions of the World’s Leading Climate Scientists as the World’s Leading Climate Scientists are doing for themselves:

The Trenbeth “sulfate aerosol” negative feedback modulation of IR that are not observed from satellites in the IR; or the purloined “heat” from GHG warming unobserved in sea or air

The unobserved Santer predicted tropopause altitude response or tropopause warming magnification in the Tropics

The GISS climate modeling managed by Hansen that, by force fitting feedback over a thirty year period, can match observed temperatures but the predictions of climate bear no relation to natural climate particularly in the Tropics

At some point, these folks might step back and say to themselves, “the assumptions behind all this might not be right.”

Nope. They continue to press Government for drastic changes that will send the Free World back to the stone age.

That’s where my squeaky little barely heard voice comes in to say: stop

442. anna v says:

Re: Colin Davidson (Mar 22 01:42),

“Anna V(22:13:06, 21MAR10) wrote:
“One, imo, should be saying: the heat capacity of the atmosphere is increased by the existence of H20 and CO2 etc, from x to y, and thus heat transport to space is delayed by z , instead of handwaving watts/m^2.””

I think that is only partially correct. The “heat capacity” is presumably the amount of energy it takes to heat a certain mass of air by a certain amount. The concentrations of Water vapour and CO2 in the air make almost no difference to the heat capacity.

There is no presumption. Heat capacity is the way the heat content of any material is parametrized. From Wiki:

The equation relating heat energy to thermal mass is:

Q = C_\mathrm{th} \Delta T\,

where Q is the heat energy transferred, Cth is the thermal mass of the body, and ΔT is the change in temperature.

In thermodynamic terms this is the way to describe a mass system in a heat environment. Heat is energy and temperature its proxy. When we say that the atmosphere’s temperature has increased by deltaT because of the introduction of extra mass it means the heat capacity has changed by this delta Mass (CO2 in this case).

443. Colin Davidson says:

Joel,
Can you educate me? What exactly is “Lapse Rate Feedback”?

444. cba says:

joel shore

well joel, the numbers I showed are quite simple but they use the entire actual Earth values. 150w/m^2 = difference between the 239 w/m^2 actual mean radiated amount from the Earth that balances the incoming (after albedo) value for solar. divide that into the actual 33 deg C rise in T provides the mean sensitivity.

the h2o vapor feedback can be estimated as well. with only a small increment in T – like 5 deg c along the entire atmospheric column, if one held the relative humidity constant – as is usually assumed, one finds one can have only about a 30% increase in the h2o vapor. Running a 1-d model, one can find that this amounts to a little over 3 w/m^2 increase in total forcing which is less than that of the co2 doubling in the first place, making the combined value equivalent to a mere 1 degree or so.

I note there is a big fat PRESUMABLY in the area of your post talking about other factors. You use ice – albedo as one. Note that although there is a big problem with Khiel and Trenberth’s estimates, they call for 0.08 total surface fraction and 0.22 cloud (and atmospheric) fraction of the 0.3+ total albedo. Considering that ocean makes for around 70% of the surface total for a surface albedo of somewhat under 0.08, land accounts for a bit under 0.2 albedo, including all that snow & ice, at least for that part of the surface that isn’t ocean that is visible under about a 62% average cloud cover. That should provide an excellent hint that the small area currently covered in ice and snow on average accounts for very little of the actual albedo. Now an ice age with glaciation is going to make a bit of a difference but that isn’t what we have currently.

That leaves clouds. And you’re trying to tell me that somehow or another, adding an additional 30% h2o vapor to the mix is going to result in a decrease in cloud cover and hence, in albedo and also, presumably in a decrease in convection via the water vapor cycle.

just off hand, I can’t think of a portion of the h2o vapor cycle that is going to offer positive feedback when taken in the context of that cycle. h2o vapor is a lighter molecule than any other predominant molecule in the atmosphere. That alone creates less density and adds buoyancy to moist parcels. In general, lifting air to higher altitudes and lowering air parcels to lower altitudes is rather the zero sum game until one adds in h2o vapor which caries with it heat of evaporation (and sometimes also heat of fusion) and this is carried from lower to upper atmosphere. As the altitude rises, the moist air eventually gives up most of the h2o vapor in the form of liquid h2o and solid h2o particles – giving up the hts of evaporation and fusion to the upper atm. These either precipitate down or form clouds as having supersaturated air is just not acceptable for any length of time. In either case, more surface heat gets transferred up. While it appears that clouds forming is a poorly understood subject, there’s plenty of evidence that pollution, volcanic ejecta, and even cosmic rays contribute to the formation of clouds and provide a mechanism for external involvement in the climate for such things, albeit in a round about fashion.

it makes far more sense for this than does the presumption that heat gets trapped in the oceans. IR is blocked quickly by liquid h2o. Except in very limited circumstances, warm h2o liquid rises. While solar radiation can penetrate well below the surface, even many dozens of meters, IR is trapped at the surface – and that is what increases with increase ghgs. Like trying to boil a pot of water by putting a heating element on top, one has all of the facets working in opposition to bringing heat downward in water.

perhaps one should rethink the status quo when it comes to the actual mechanisms presumed to raise temperature rather than lowering temperature. After all, you’re still a far cry from explaining just how something that should further reduce waming with negative feedback is somehow or another being assumed to increase it with postive feedback and that it’s in an area that is very poorly understood.

445. lgl says:

Colin,
I see what they are doing now. A CO2 doubling gives 3.7 W/m2 at TOA (or actually at the 255 deg C layer) which is amplified by the existing GH effect by 2.45 to get 9 W/m2 at the surface. This will increase the surface temp 1 C and produce enough water vapor to give another 3.7 W forcing at TOA, which of course is also amplified to 9 W to the surface. These 18 W will lead to reduced snow and ice cover ++ to produce the third 3.7 W at TOA. Then we have 27 W at the surface and can subtract a few W for evaporation.

446. Joel

Regarding the mistake of Arthur P Smith

I presume you attended classes where the Kinetic Theory was explained to you!
One familiar equation should be

Average KE of molecule =1/2 mv^2 =3/2kT

v is the RMS speed, T is the Kelvin Temperature the other quantities should be familiar to you if you attended an elementary KT class.

What happens if you throw a ball up in the air in a gravitational field?
Yes that’s right the speed decreases until it stops.

If the molecule moves up its speed and its KE decreases .
The KE changes into GPEnergy(mgh)

If the KE decreases then by equation above its Temperature DECREASES.
This gives rise to the lapse rate.

This elementary derivation does not involve the question of whether or not the molecule is radiative or not.
That someone who considers himself to be a Physicist does not seem to be aware of this is unusual.
I thought it was a momentary lapse and he would correct the record but he has not.
This is most disappointing as apparently he is a co author with you in the attempt to refute G&T.
I was hoping that G&T were going to be given a more rigorous testing than has been the case up till now.
It looks that this is now unlikely to be the case.

447. lgl says:

lgl (01:32:52) :

The water vapor forcing is a feedback loop so it was a bit silly of me describing it the way I did. It is of course the resulting 3 deg C that produces enough vapor to give the additional 3.7 W.

448. anna v says:

I had to look up R value. It seems it is thermal resistance, and it is a measure of insulation

here is a calculation of the atmosphere,
though I have not checked it. It says that in the units used in the US the value for the atmosphere is 0.8, where fiber glass is 11.

449. cba says:

anna,

the R value also roughly approximates thickness of plywood equivalent. 0.8 is around 3/4″ of plywood. The fiberglass reduces convection and radiation making it an R-11 for a 3 1/2 inch void, roughly equivalent to 11 inches of plywood – which is conduction only. It’s a totally ‘engineering’ type of number and applied to the atmosphere essentially gives the equivalent thickness of plywood necessary to achieve the same heat flow per area – which should be ft^2 rather than m^2. Not sure why anyone would do that other than to just compare the lack of insulation factor is present in the atmosphere. BTW R-12 is rather pathetic for walls too,

450. Brian G Valentine says:

Note that buoyancy forces of air are directly proportional to the volume coefficient of expansion (which, for ideal gases, is the reciprocal of the absolute temperature). This is well known to helicopter pilots, who are well aware that colder air has a lot more lift than warm air.

There is a lot we don’t know that we could all study together, but “global warming” has become the Civil War amongst those who seek to increase knowledge of atmosphere and climate.

Moving away from global warming, and climate modeling is still very weak, and we don’t even know the origins of phenomena such as El Nino.

We don’t know how the historical climate is influencing the present climate via movement of heat in the oceans, and I think we have to move away from GHG modeling someday.

We have a lot more in common than we do differences, and it starts with the motivation to be of use and benefit to humanity in some way

I’m moving away from this discussion, salutations to Joel

bgvavlentine@verizon.net

451. Brian – I might add *to all pilots*…Lift of rotary wings, fixed wings, even displacement of hot air balloons is proportional to density of the gas they are in, which is inversely proportional to temperature of that gas. I’m not sure most pilots think of the “coefficient of expansion” of the gas, and least not most pilots.

452. Colin Davidson says:

cba (23:44:32, 22MAR10) wrote, in an interesting and thought provoking post (much of the thrust of which I agreed with):
“In either case, more surface heat gets transferred up.”
I don’t agree with that statement. The surface is powered by the sun. It has to get rid of all the energy it receives from the sun, any way it can – otherwise it adjusts its temperature until it does.
What happens if the back-radiation increases is that the surface temperature rises, evaporation increases and surface radiation increases to bbalance (in sum) the change. As far as the atmosphere is concerned there is the same amount of net flux from the surface.

However cba’s comment is partly correct. If the surface temperature rises, the balance of flux transfer is tipped even more heavily in favour of the latent heat carried by water vapour. So less flux enters the atmosphere near its base and more enters at the clouds.

The rough numbers from the K&T diagram are:
AT 15DEGC:
CONDUCTION (24W/m^2) which heats the air in direct contact with the surface
NET ABSORBED RADIATION (26W/m^2) which heats the air up to about 500m, but over half that radiation is absorbed within the first 50m
LATENT HEAT IN WATER VAPOUR (78W/m^2) which heats the air when the water vapour condenses into water droplets, ie in the clouds.

If the surface temperature increases by 3DegC, these values alter and become:
CONDUCTION (24W/m^2)
NET ABSORBED RADIATION (Between 10 and 20 W/m^2)
LATENT HEAT IN WATER VAPOUR (Between 84 and 94W/m^2)

453. Joel Shore says:

Colin Davidson says:

Joel,
Can you educate me? What exactly is “Lapse Rate Feedback”?

Short answer: Because of what is caused the moist adiabatic lapse rate, the warmer the air at the surface, the less fast the temperature drops with height. What this means is that warming at the surface is expected to get magnified as you go up in the tropical troposphere. Since the layer from which most of the radiation escapes into space is well up in the troposphere, that is the layer that must rise in temperature by a certain amount in order to restore radiative balance after the GHGs cause their forcing. So, the air temperature at the surface does not have to rise as much as one predicts that the temperature at that level in the atmosphere has to rise. Hence, it is a negative feedback in the sense that it reduces the expected surface temperature rise relative to what one predicts by just applying the Stefan-Boltzmann Equation.

454. Joel Shore says:

Bryan says:

v is the RMS speed, T is the Kelvin Temperature the other quantities should be familiar to you if you attended an elementary KT class.

What happens if you throw a ball up in the air in a gravitational field?
Yes that’s right the speed decreases until it stops.

If the molecule moves up its speed and its KE decreases .
The KE changes into GPEnergy(mgh)

If the KE decreases then by equation above its Temperature DECREASES.
This gives rise to the lapse rate.

Actually, Arthur addresses this quite directly. He points out that the assumption in this is that the system is adiabatic, i.e., a parcel of air is not exchanging energy with its surroundings. In some contexts, such as during convection, it is a reasonable approximation that a rising parcel of air does not have the time to have significant energy exchange with its surroundings; however, in other contexts, it is not. In particular, the equation for the lapse rate that is derived from that analysis gives a stability limit: If the lapse rate is greater than that, a parcel of air that starts to rise in the atmosphere will continue to rise and hence the air is unstable. The tendency in this situation is then to get convective mixing, which tends to reduce the lapse rate. (The convective processes happen quite quickly in comparison to heat conduction and thus the adiabatic approximation is pretty good here.) This is all well-known and well-understood in the meteorological and climate science communities.

However, if you have a lapse rate smaller than the stability limit, the air is stable and such convective processes are suppressed. In that case, and in the absence of an IR-active atmosphere, Arthur argues that the adiabatic approximation is not a good one and the atmosphere will actually tend towards being isothermal, as is true of a system in thermal equilibrium.

Having not thought about this that much myself, I can’t say that I am yet convinced that Arthur is right. But, his argument seems very reasonable to me…and Arthur is a very smart guy whose scientific intuition I respect a lot.

And, at any rate, the larger point is that some people seem to think that arguing that the lapse rate is determined by physics other than radiation somehow negates the argument that invoking the greenhouse effect is necessary to explain the high surface temperature of the Earth. It does not. Regardless of the temperature distribution of the atmosphere with height, if the atmosphere is transparent to infrared radiation, all of the radiation from the Earth will escape to space and radiative balance will determine the surface temperature. You cannot magically create a warmer surface of the earth by invoking this argument.

455. Joel Shore says:

Bryan:

It might be instructive for you to read Roy Spencer here http://www.drroyspencer.com/2009/12/what-if-there-was-no-greenhouse-effect/ , who seems to agree with Arthur on this point about the temperature profile of the atmosphere in the absence of the greenhouse effect:

So, let’s imagine an extremely cold Earth and atmosphere, without any water vapor, carbon dioxide, methane or any other greenhouse gases – and with no surface water to evaporate and create atmospheric water vapor, either. Next, imagine the sun starts to warm the surface of the Earth.

And what happens when there is a temperature difference in a material? Heat flows by thermal conduction, which would then gradually warm the upper atmosphere to reduce that temperature difference. The process would be slow, because the thermal conductivity of air is quite low. But eventually, the entire atmosphere would reach a constant temperature with height.

Only the surface and a shallow layer of air next to the surface would go through a day-night cycle of heating and cooling. The rest of the atmosphere would be at approximately the same temperature as the average surface temperature. And without a falloff of temperature with height in the atmosphere of at least 10 deg. C per kilometer, all atmospheric convection would stop.

Thus, it is the greenhouse effect that continuously de-stabilizes the atmosphere, ‘trying’ to create a temperature profile that the atmosphere cannot sustain, which then causes all different kinds of weather as the atmosphere convectively overturns. Thus, the greenhouse effect is actually required to explain why weather occurs.

456. Willis Eschenbach says:

Joel Shore (19:04:26) : edit

I suggest you read what Bill Illis wrote in his comment on 18/03/2010 (21:46:42). At the end of the day, the original forcing of ~4 W/m^2 from doubling CO2 results in another ~7 W/m^2 of “forcing” (in the sense of change in downwelling radiation at the TOA).

The IPCC is not saying that ~4 W/m^2 increase in downwelling radiation at the TOA leads to a 3 C temperature rise…They are saying that ~4 W/m^2 of forcing results in feedback that increase the downwelling radiation by considerably more than that.

Bill Illis (21:46:42) : edit

The 3.0C per doubling sensitivity comes from the following:

– doubled CO2/GHGs add 3.7 to 4.0 W/m2 of forcing at the tropopause emission layer where it is 255K (sometimes they call this the TOA forcing but the top of the atmosphere is much warmer than this level – it is really the tropopause at about 5 kms up but they often mix this up to keep people off balance);

TOA in the climate science CO2 forcing context almost always means the tropopause.

There is a clear distinction made in the literature between Fi, the instantaneous forcing at the tropopause, and Fs*, the same forcing after ten years of adjustment. For a doubling of CO2, these are given by Hansen et al. as

Fi = 4.52 W/m2

Fs* = 3.95 W/m2 ± 0.11

– then there is feedbacks from increased water vapour and albedo which add another 6.5 to 7.4 W/m^2 after this initial forcing;

Not according to anyone I’ve read. I’d need a citation for that, especially since increased albedo will decrease the tropospheric forcing, not increase it. Hansen et al. (ibid) give a temperature change of ~ 2°C for a doubling of CO2. The IPCC says the models incorporate a feedback of 2 W/m2 per °C, which would give an increase in forcing of 4 W/m2.

– the layer now increases in temperature by 3.0C (11.5 extra watts on top of the original 240 watts).

The TOA forcing is only on the order of 150 – 160 W/m2, not 240 W/m2. See Kiehl/Trenberth or my budget in the head post. The 240 W/m2 is the total forcing coming from the sun, and is thus the total amount being radiated to space from all levels of the climate system including the surface. In equilibrium, this will never increase or decrease. This statement doesn’t make sense.

– the layer where the equilibrium emission temperature of 255K occurs is now 461 Metres higher.

Assuming blackbody conditions, 255K = 240W/m2. This is the total radiation from the entire planet, not the emission from any layer. There is no atmospheric layer where there is an “equilibrium emission temperature of 255K”. Again, this statement doesn’t make sense.

– the adiabatic lapse rate of 6.5C/km stays intact and the surface warms by the same 3.0C.

So, the sensivitiy is calculated as 4.0 extra watts of GHG forcing eventually results in an increase of 11.5 watts (once all feedbacks occur) and temperatures at the surface rise 3.0C.

Not true, for all of the reasons given above. Hansen et al. (ibid) says that the ~ 2°C for a doubling of CO2 is after all feedbacks, and that the net change in the TOA forcing after all feedbacks is ~ 4 W/m2 …

Joel, you are usually more skeptical than this …

457. Willis Eschenbach says:

Joel Shore (19:14:09)

Francisco says:

From that chart, you see that total amount of carbon in the extant fossil fuels still in the ground is roughly 1/8 the amount of carbon in the active system. The amount we are recycling annually back into the system is about 0.015% of the total carbon in the system.

That is not really relevant as the rate of transfer to the deep ocean reservoir is rather small. So, you have to consider the amount we are adding to the other reservoirs (that exchange fast enough that they can be thought of as a rapidly-equilibrating subsystem that exchanges carbon only very slowly with the deep oceans. Also, note that if you add only 1% annually to a reservoir that is not able to get rid of it, you will double the amount in that reservoir in 100 years.

While the 1% = double in 100 years number is tempting, in fact the climate system sequesters a large amount of what is emitted. Simple calculations show that if we increase the amount emitted by 1% of the 2010 emissions, we will not double the atmospheric concentration for a long, long time. By 2100, the concentration will only be about 35% more than at present. And it won’t double until about 2275.

This is because the amount sequestered is a percentage of the “excess” carbon dioxide in the air. As airborne CO2 concentration increases, the amount sequestered also increases. This slows the rise of the atmospheric concentration.

The cause for alarm, it seems to me, comes only if you adopt the assumption that our modest recycling program represents a very grave disturbance to a static and balanced system, whose balance coincides with its state around 1850. I consider this assumption to have no rational or scientific basis whatsoever. It is merely ideological.

Ah…Do you mean no basis beside the overwhelming empirical evidence that we have increased the levels of CO2 in the atmosphere from the pre-industrial baseline of 280ppm to the current ~390ppm?

Here, I agree with Joel. There is plenty of evidence, not computer model results but evidence, that the recent increase in CO2 is from human activities. I don’t agree that a change in CO2 concentration from 0.03% of the atmosphere to 0.04% of the atmosphere (as happened over the last 200 years) has measurably changed the temperature, but I do agree that the CO2 rise is from human industry.

458. Willis Eschenbach says:

Joel Shore (19:32:16)

Brian G Valentine says:

I understand where this is coming from, Bill, but where I (and apparently Gerlich and Tscheuscher and a lot of others) have the worst difficulty, is accepting the idea that the “atmosphere” is “warming” the “surface”.

Either that idea violates the Second Law or it doesn’t. If someone could just present ONE parallel example to show this is at least possible, then I would not say that Gerlich and Tscheusher’s analysis is as good as anyother application of the Second Law

Debunking of G&T’s Second Law argument in 3 easy steps: …

Couldn’t have said it better. I agree 100%. See my Steel Greenhouse post for the illustrated version.

459. Willis Eschenbach says:

Bryan (16:37:47)

Joel

….
… I haven’t done the calculation myself but I’ll give you a hint from what I do know: All those fossil fuels that accumulated over hundreds of millions of years that we are now burning very rapidly (relative to the time that it took them to form) amounts to an energy usage averaged over the earth’s surface of ~0.02 W/m^2…….

Please send this information to the IPCC

The IPCC, like almost everyone in the field, knows that the thermal energy from the burning of fossil fuels is quite small. In the most recent year for which I have data (2003), the global consumption of fossil fuels was about 8,500 million tons of oil equivalent (mTOE).

1 TOE is 42 gigajoules. That gives a yearly consumption of 7.6e20 joules, which is about 1.1e13 joules per second, which is 1.1E13 watts instantaneous.

The surface area of the earth is 5.1e14 square metres, so the thermal energy from fossil fuel burning is about 0.02 W/m2 …

You are completely contemptuous of G&T yet all you produce is a string of insults with no serious attempt to deal with any of the many points they make.

Absolutely not true. Joel has given you a clear and comprehensive explanation of why G&T are wrong.

You claim to have produced more papers than Rupert Murdoch, so we will just have to take that on trust.

He made no such claim, that’s a straw man.

When and if your refutation is published we can then check just what the qualities of the papers were.

Nope. The only way to check what the qualities of his previous published works are is to look at them.

The ability to hurl insults is inversely proportional to scientific proof.

Sometimes yes, sometimes no. Sometimes I get angry enough at some blockhead to hurl insults, but that means nothing about whether my scientific work is any good.

Bryan, Joel has been even tempered here. He laid out a clear explanation of why he thinks G&T is wrong. You have not said a single word about that. Instead, you raise straw men and make accusations about his past work. You even imply that his statement about his past work is fictional, rather than simply google his name and see.

If you want to get some traction, show us where you think Joel’s explanation above is incorrect. Anything else is just wasting words.

460. Joel and Willis

A P Smith and it now appears Roy Spencer think that an atmosphere without CO2 and H2O would become isothermal to a height of 30km at the surface temperature.
Stop and think about the enormity of such nonsense.
The surface temperature would be much higher than now because of failure to absorb much of the Suns IR.
Lets say surface temperature rises to 300K on average.
Outside of the atmosphere the temperature drops to near absolute zero.
Gravity still exists, day and night still exist, surface temperatures will still vary widely.
Tidal currents will still flow,winds will still exist etc.
Look again at the proposition at the top and see how silly it is.
Joel you seem to think that quoting Roy Spencer is a clincher.
I pointed out earlier that sceptics will come at a theory from different directions and will not necessarily agree with each other on all things.
There is no Church of the Latter Day Sceptic.
However I am glad that you have distanced yourself from Arthur on the point above.

Willis
You seem to think I know who Joel is, your wrong.
G&T make 16 separate points of disagreement with Greenhouse Theory.
Opponents of G&T have used the tactic of smear and innuendo instead of reasoned argument and rarely address any of the 16 points.
I have no particular reason to support G&T other than looking at the case they present and looking at the alternatives presented by their critics.
I would urge anyone interested to go to the critics sites such as Arthur’s with an open mind and draw your own conclusions.
Joel is part author of a proposed paper covering the G&T topic so I think its a good idea to wait and focus that discussion there.
I followed your comments in Barts blog yesterday and found them interesting.
Earlier VS welcomed the intervention of G&T into the debate and hoped that other Physicists would make a contribution to this important debate.
He was particularly scornful of those who depart from reasoned debate.
Why am I on this particular thread?
I think that the K&T diagram is very ambiguous however that was not my original question still unanswered so I will rephrase it.
What would be regarded as a minimum value for atmospheric backradiation and under what conditions would this occur?

461. Brian G Valentine says:

“I’m not sure most pilots think of the “coefficient of expansion” of the gas, and least not most pilots.”

You’re probably right there, I think of “coefficient of expansion” of the (fluid) because, that is proportional to the buoyancy (forces) responsible for natural convection and that is important to me in heat transfer.

I rode on helicopters all the time while in Iraq and those things are hell on fuel because of the heat there.

So far, from what I read here, the following people believe Gerlich and Tscheuschner are correct

– Gerlich and Tscheuschner
-Kramm
-Me
– Brian W

So, according to Joel, we’re “fringe.”

Tough luck.

462. anna v says:

Let me give another example of why I think talking of back radiation etc , even though it is a way of looking at the fine detail, is wrong thermodynamically.

Take the law of increasing entropy and disorder.

This law is violated by an individual living organism: it increases its order thus decreasing the entropy of the organism. Thus one is forced to talk of “closed systems” where the total disorder is increased even though locally the biological organism violates the law.

In a closed system, for every process that occurs the entropy of the system will either increase or remain constant .

We see then that the second law, in its entropy form above, can be violated locally in an open system, which a biological organism is, while it exchanges energy with its surroundings ( second law takes over at death).The whole closed system has to be taken into account.

The second law is also formulated as:
No process is possible whose sole result is the removal of heat from a reservoir at one temperature and the absorption of an equal quantity of heat by a reservoir at a higher temperature.

Which is the form that G&T, and I, are saying is being violated by this back radiation concept.

The crucial words in this Clausius statement of the law is “sole”, and “equal quantity of heat”. The closed system is implied.

So the atmosphere as a reservoir of heat is at temperature T1, and the surface is at temperature T2>T1.

I am now trying to think how, in analogy to the entropy violation of a biological organism, a local violation of the Clausius statement would be permissible .

Let us forget the constant radiation coming from the sun. Let us say that somehow the sun suddenly turns into dark matter giving no radiation, and think what governs the ground reservoir and the atmospheric reservoir isolated in the cold of space as it cools off.
Would not this be the classic illustration of the Clausius statement of the second law? The atmosphere cannot transfer heat to the ground without violating the second law.

I cannot see why the introduction of a radiant sun by enlarging the “closed system” would change this.

463. lgl says:

http://www.realclimate.org/index.php/archives/2007/08/the-co2-problem-in-6-easy-steps/

“[Response: Feedbacks work for everything. That’s why the ‘radiative forcing’ concept works – it doesn’t matter if the initial push is from greenhouse gases or the sun. The change in temperature you’d need to balance a forcing of 4 W/m2 with no feedbacks is around 1.2 ºC and the difference between that and the real sensitivity (around 3 ºC) is a measure of how strong the net feedbacks are. – gavin]”

“For the response to 2xCO2, (around 3 deg C) you would expect an increase of about 30% in water vapour amounts. -gavin]”

“An instantaneous forcing calculation for 1.4xH2O over the whole globe gives a forcing of 5.5 W/m2 – demonstrating that over the whole spectrum, water is not saturated. – gavin]”

and then there is supposed to be a third 3.7 W/m2 after slow feedbacks.

464. lgl says:

http://www.junkscience.com/ipcc_tar/wg1/044.html

“If the amount of carbon dioxide were doubled instantaneously, with everything else remaining the same, the outgoing infrared radiation would be reduced by about 4 Wm-2. In other words, the radiative forcing corresponding to a doubling of the CO2 concentration would be 4 Wm-2. To counteract this imbalance, the temperature of the surface-troposphere system would have to increase by 1.2°C (with an accuracy of ±10%), in the absence of other changes. In reality, due to feedbacks, the response of the climate system is much more complex. It is believed that the overall effect of the feedbacks amplifies the temperature increase to 1.5 to 4.5°C”

465. JAE says:

Joel Shore (19:12:16) :

“Thus, it is the greenhouse effect that continuously de-stabilizes the atmosphere, ‘trying’ to create a temperature profile that the atmosphere cannot sustain, which then causes all different kinds of weather as the atmosphere convectively overturns. Thus, the greenhouse effect is actually required to explain why weather occurs. ”

No. You are ignoring thermalization, which is facilitated by CO2 and HOH and which would produce “weather,” even without any “greenhouse effect.”

466. Joel Shore says:

JAE says:

No. You are ignoring thermalization, which is facilitated by CO2 and HOH and which would produce “weather,” even without any “greenhouse effect.”

I’m not sure I understand your point, but the main thing I wanted to note is that you are not quoting me directly; you are quoting Roy Spencer (as quoted by me).

anna v says:

The atmosphere cannot transfer heat to the ground without violating the second law.

I cannot see why the introduction of a radiant sun by enlarging the “closed system” would change this.

It doesn’t. However, the 2nd Law applies to the NET flow of heat…which, as I noted, is clear once you realize that all bodies at non-zero temperature radiate heat and a colder body next to a hotter body is not going to magically stop radiating heat to the hotter body. Rather, the 2nd Law just tells you that the hotter object will absorb less heat from the colder object than the colder object will absorb from the hotter object.

So, what your statement should say is, “The atmosphere cannot IN NET transfer heat to the ground without violating the second law.” And, the answer is: It doesn’t. The net flow is from ground to atmosphere as the 2nd Law requires. However, this still leaves the ground warmer than the comparison case of an IR-transparent atmosphere, in which case ALL of the heat that the earth radiates escapes into space and NONE of it makes it back to the earth.

467. Joel Shore says:

Willis Eschenbach says:

There is a clear distinction made in the literature between Fi, the instantaneous forcing at the tropopause, and Fs*, the same forcing after ten years of adjustment. For a doubling of CO2, these are given by Hansen et al. as

Fi = 4.52 W/m2

Fs* = 3.95 W/m2 ± 0.11

Yes, but these numbers are talking about stratospheric adjustment. They are not talking about feedbacks. (And, at any rate, what Hansen et al. are concerned with is the forcing, so they don’t talk about the effect of the feedbacks on the TOA radiation balance.)

Assuming blackbody conditions, 255K = 240W/m2. This is the total radiation from the entire planet, not the emission from any layer. There is no atmospheric layer where there is an “equilibrium emission temperature of 255K”. Again, this statement doesn’t make sense.

What Bill is talking about is the “effective radiating layer”. Of course, in reality what you have is a distribution function, i.e., if you looked at the emission that escapes into space and at what height in the atmosphere it originated, you would have a continuous function but it would have a peak and the location of that peak is, roughly speaking, the effective radiating layer. And, Bill is right that the effect of an increase in greenhouse gases is to raise that effective radiating layer to higher levels where the atmosphere is colder, which then means the amount of radiation emitted is less. See here for more discussion: http://www.aip.org/history/climate/simple.htm#L_0623

Not true, for all of the reasons given above. Hansen et al. (ibid) says that the ~ 2°C for a doubling of CO2 is after all feedbacks, and that the net change in the TOA forcing after all feedbacks is ~ 4 W/m2 …

No…That is not what Hansen is talking about. He is talking only about the forcing due to CO2 after stratospheric adjustment. That is not something you measure after all feedbacks because, by definition, it doesn’t include the effect of feedbacks.

Think of it this way: How do you imagine that the water vapor feedback works? The way it works is by creating an additional imbalance in the TOA radiation balance. However, that change, by definition, is not considered part of the forcing…It is considered part of the feedbacks.

468. Joel Shore says:

Willis Eschenbach says:

The IPCC says the models incorporate a feedback of 2 W/m2 per °C, which would give an increase in forcing of 4 W/m2.

Actually, that is not how you calculate the effect of the feedback. I’ve always wondered what a feedback parameter expressed in (W/m^2) per °C means and I have finally figured it out. You have to use the formula that is in footnote 6 of the IPCC AR4 WG1 Chapter 8 on p. 631. Basically, the amplification of the temperature change relative to that predicted in the absence of feedbacks is 1 / (1 + lambda/lambda_0) where lambda is the total feedback and lambda_0 is approximately –3.2 (W /m^2) per °C. Note that the lambda_0 is -1/S where S = the sensitivity in the absence of feedbacks (i.e., basically that derived from the Stefan-Boltzmann Equation). Hence, a 2 W/m^2 per °C feedback yields about a 2.67 magnification of the no-feedback temperature response. And, in the limit that the feedbacks approach 3.2 W/m^2 per °C, the magnification diverges because this means the feedbacks are sufficiently strong to cause a runaway effect.

It is actually not too hard to derive that formula in footnote 6, by the way. I just did it on a piece of paper, although I am not sure I yet understand what I did quite well enough to explain it…at least without writing down the equations.

469. sky says:

I’m still waiting for some indication that the radiation-fixated discoursers on this thread have any grasp of the enthalpy of gases and of the fact that convection and the creation of pressure gradients (which drive the geaostrophic winds) involve WORK done by the atmosphere. It is such lapses, along with neglect of biological dissipation of radiation that render the usual “energy budgets” an unrealistic exercise in number juggling.

470. JAE says:

“JAE says:

No. You are ignoring thermalization, which is facilitated by CO2 and HOH and which would produce “weather,” even without any “greenhouse effect.”
I’m not sure I understand your point, but the main thing I wanted to note is that you are not quoting me directly; you are quoting Roy Spencer (as quoted by me).”

Wow! If you don’t understand this point, then I don’t think you should not be discussing this subject and you should read a physics book.
Here is the story: when the GHG molecules (HOH and CO2) absorb IR, they get all excited (vibrational, rotational, translational) and they strike the O2 and N2, which are the bulk of the atmosphere, thereby energizing (heating) them. This “heats them,” and spreads the “wealth.” This is LTE, which you should look up at Wicki. This is the real function of GHGs, IMHO (not radiation). There are far too many people that completely ignore this inconvienient physical fact and try to explain everything with radiation (including Willis), again IMHO.
Why will NOBODY try to explain to me why it is only 85 F where Willis lives, when that area has 6-7 times as much greenhouse gases as Phoenix, Arizona, which routinely has 110 F and higher in the summer.
Where is the empiricism, which is the FUNDAMENTAL pillar of science?

471. anna v says:

Joel, I am not being confrontational on this, I want to clear it up, and your statement does not clear it.

So, what your statement should say is, “The atmosphere cannot IN NET transfer heat to the ground without violating the second law.” And, the answer is: It doesn’t. The net flow is from ground to atmosphere as the 2nd Law requires. However, this still leaves the ground warmer than the comparison case of an IR-transparent atmosphere, in which case ALL of the heat that the earth radiates escapes into space and NONE of it makes it back to the earth.

All the terminology of back radiation and multiplication talks of heat transfer from the atmosphere to the ground. What is NET? a million years? a microsecond?

Reservoir1 + Reservori2 is NET ? Then the classic Clausius formulation has no meaning, because from the first law NET does not change or decreases by radiation anyway.

I would also like to see you point the finger where the image by Peden,
http://www.vermonttiger.com/content/2008/07/nasa-free-energ.html
which creates a paradoxical device from back radiation, is getting off track.

472. Willis Eschenbach says:

Joel Shore (17:55:41)

Willis Eschenbach says:

There is a clear distinction made in the literature between Fi, the instantaneous forcing at the tropopause, and Fs*, the same forcing after ten years of adjustment. For a doubling of CO2, these are given by Hansen et al. as

Fi = 4.52 W/m2

Fs* = 3.95 W/m2 ± 0.11

Yes, but these numbers are talking about stratospheric adjustment. They are not talking about feedbacks. (And, at any rate, what Hansen et al. are concerned with is the forcing, so they don’t talk about the effect of the feedbacks on the TOA radiation balance.)

Not true at all. From Hansen et al. cited above:

Gregory et al. [2004] suggest that calculations of the forcing can be obviated in cases for which a climate model run exists in which the forcing was added suddenly to a model control run and then held constant for a long simulation. An estimate of the forcing is obtained by regressing the flux at the top of the atmosphere against the change in surface air temperature, with the flux at zero temperature change being the estimated forcing. This approach allows both stratospheric, tropospheric, and land surface feedback mechanisms to operate. Thus the forcing so obtained, which we designate Fs*, is an approximation of Fs.

Note that this says “this approach allows both stratospheric, tropospheric, and land surface feedback mechanisms to operate.” So your claim above that “They are not talking about feedbacks.” is falsified.

473. Willis Eschenbach says:

JAE (20:04:31)

Why will NOBODY try to explain to me why it is only 85 F where Willis lives, when that area has 6-7 times as much greenhouse gases as Phoenix, Arizona, which routinely has 110 F and higher in the summer.
Where is the empiricism, which is the FUNDAMENTAL pillar of science?

Because they are in different climate zones, and because of the high humidity in the South Pacific.

The South Pacific is tempered by, and stays at about the temperature of, the surrounding ocean. A combination of evaporation, cumulus clouds, and thunderstorms caps the high temperatures, preventing them from rising too far. As a result, the average temperature rarely exceeds 30° C (86°).

Hot moist air near the equator rises in the thunderstorms and drives the “Hadley circulation”. This air has the moisture stripped out of it as it rises and moves towards the poles. The air, now dry, descends at about 30°N and 30°S. As it descends, it warms. This creates the great bands of desert which circle the earth at ~ 30°N and 30°S.

Finally, because the air is dry, there is much less “greenhouse effect” and little cloud in the desert belts. As a result, there are much greater day/night swings. For example, tomorrow in Honiara, Solomon Islands, the forecast is for a high of 90°F and a low of 74°F (average 82°F), a 16° swing. In Phoenix, on the other hand, tomorrow is slated to have a high of 80°F and a low of 53°F, a 27° swing.

474. Joel and Willis

This is the fourth time I have asked this question with no reply even though I have rephrased it

What would be regarded as a lower measured value for atmospheric backradiation and under what conditions would this occur?

Given that the backradiation shown in KT diagram is twice the incoming solar EMR to the surface this should be easy to measure and a rough estimate is all I’m looking for.

Joel
I must say I agree with anna v ‘s comments above regarding the 2nd Law of TD.
I did not want to stray too far away from the main points of the thread namely the science behind the KT diagram and whether Willis’s attempts to tweak it are justified.
Regarding G&T (and refutations thereof) I have simply referred people to the Arthur P Smith site where exactly the difficulty for Arthur in the use of the word “heat” is well illustrated.

Joel you should think long and hard about whether this is your settled position

….”applies to net flows; it does not mean that no heat can be radiated by a colder body and absorbed by a hotter one.”
If so, define heat in the sense that Physicists use when communicating with one another.

Somewhat off topic…. A P Smith , Roy Spencer and adiabatic expansion.
What they refer to is free adiabatic expansion which is isothermal
In a Gravitational Field the expansion is NOT FREE.
Any molecule moving up has to overcome gravity.
The system( gas particles) in moving up has to supply work against gravity.
Where does this work come from?
It can only come from one place the internal energy of the system(gas particles).
They lose heat and their temperature drops.
And as we all know this is exactly what happens.

475. Willis Eschenbach says:

Joel Shore (19:36:51) : edit

Willis Eschenbach says:

The IPCC says the models incorporate a feedback of 2 W/m2 per °C, which would give an increase in forcing of 4 W/m2.

Actually, that is not how you calculate the effect of the feedback. I’ve always wondered what a feedback parameter expressed in (W/m^2) per °C means and I have finally figured it out. You have to use the formula that is in footnote 6 of the IPCC AR4 WG1 Chapter 8 on p. 631. Basically, the amplification of the temperature change relative to that predicted in the absence of feedbacks is 1 / (1 + lambda/lambda_0) where lambda is the total feedback and lambda_0 is approximately –3.2 (W /m^2) per °C. Note that the lambda_0 is -1/S where S = the sensitivity in the absence of feedbacks (i.e., basically that derived from the Stefan-Boltzmann Equation). Hence, a 2 W/m^2 per °C feedback yields about a 2.67 magnification of the no-feedback temperature response. And, in the limit that the feedbacks approach 3.2 W/m^2 per °C, the magnification diverges because this means the feedbacks are sufficiently strong to cause a runaway effect.

It is actually not too hard to derive that formula in footnote 6, by the way. I just did it on a piece of paper, although I am not sure I yet understand what I did quite well enough to explain it…at least without writing down the equations.

Yes, I know that. It has to do with the fact that if there is a feedback, the feedback is also amplified.

Now, back to what I had said:

– then there is feedbacks from increased water vapour and albedo which add another 6.5 to 7.4 W/m^2 after this initial forcing;

Not according to anyone I’ve read. I’d need a citation for that, especially since increased albedo will decrease the tropospheric forcing, not increase it. Hansen et al. (ibid) give a temperature change of ~ 2°C for a doubling of CO2. The IPCC says the models incorporate a feedback of 2 W/m2 per °C, which would give an increase in forcing of 4 W/m2.

The total of the water vapor and the albedo forcings given in the citation I gave above is about 1.6 Wm-2 °C-1. Using the formula you reference gives a total forcing of 2 Wm-2 °C-1, which is what I quoted.

However, I still don’t see what this has to do with my underlying calculation, which is that a change of about 150 W/m2 leads to a warming of about 20°C. This includes all of the feedbacks. And as I understand it, the IPCC warming expected from a doubling of CO2 (climate sensitivity) includes all of the feedbacks as well.

The IPCC figure is 3°C for an increase of 3.7 W/m2, or about 3°C / 3.7W/m2 = ~ 0.8°C/Wm-2.

My numbers give 20°C / 150Wm2 = ~ 0.1°C/Wm2.

Since both numbers include all possible feedbacks, I don’t see why feedback calculations are relevant to the discussion.

476. JAE says:

Willis Eschenbach (00:42:35) :

Thank you, but no. What you say is correct, but it all ignores the question. If the GHE is a determinant of temp., then more GHE amounts = more back-radiation = more heat. Instantly. Now, if evaporation and convection keep this heat in check, fine. Then let’s stop worrying about adding more GHEs to the atmosphere.

477. Joel Shore says:

anna v says:

What is NET? a million years? a microsecond?

I don’t understand the question. NET means you take the difference between the heat transferred from A to B and that transferred from B to A. It doesn’t matter over what time you consider and, in fact, if you measure in Watts, you are doing it in terms of power (i.e., energy per second). No matter what time period you measure it over, the net heat flow will be from hot to cold.

I would also like to see you point the finger where the image by Peden,
http://www.vermonttiger.com/content/2008/07/nasa-free-energ.html
which creates a paradoxical device from back radiation, is getting off track.

It gets off track because in the case of the chicken, you don’t have an input source of energy, as you do from the sun in the case of the earth. However, consider if there was an input heat source for the chicken. Do you think it might get hotter if it were in a well-insulated oven that reflected some of the heat back than it would if the insulation were not there?

Also, do you think that some hot liquid in a thermos might stay hotter for longer in the thermos than not in the thermos?

478. Joel I just read this

Apparently Chris does not think that you or Arthur are prominent Physicists.

I see it it required six of you to comment on what you regard as rubbish.
I just hope the committee approach does not lead to lack of clarity.
I look forward to reading it and no doubt it will be commented on.

…………………Well, word has just come through so I’m going to announce it here. I’m now officially a published physicist! If you really go into the details it isn’t quite as impressive as might appear at first glance, but hey. I’ll accept congratulations in any case!

I’m very pleased, but to keep this in perspective, it is in a comparatively minor journal, and the accepted paper is a “comment” on a preceding paper, and the paper we comment on is an oddity which has no real scientific influence, and the content of our paper is easily within what is accessible to an undergraduate studying the relevant aspects of thermodynamics. Originally I had felt it wasn’t even worth writing a paper on it, but I was persuaded to join in the project. None of my co-authors are prominent as physicists.

The reference is:
Joshua Halpern, Christopher M. Colose, Chris Ho-Stuart, Joel D. Shore, Arthur P. Smith, Jörg Zimmermann (2010) Comment On “Falsification of the Atmospheric CO2 Greenhouse Effects within the Frame of Physics”, (to appear in) International Journal of Modern Physics (B), Vol 24, Iss 10, March 30 2010.

479. anna v says:

It gets off track because in the case of the chicken, you don’t have an input source of energy, as you do from the sun in the case of the earth.

But you agreed that in my example of turning off the radiation from the sun the two reservoirs R1 R2 , T1>T2 , turning it on would make no difference in the thermodynamic picture?

The chicken would radiate as a black body, the radiation would be reflected by the reflector ( not by a complicated CO2 logic) etc. and with the logic of adding the back radiation that is used in the CO2 problem, one would get a runaway heating problem!

It is all those additions of watts/m^2 that are double counting in my opinion of course in the greenhouse expositions. A delay of cooling is fine, but it cannot be represented by adding watts/m^2 at imaginary boundaries.

I think what happens in this case solved correctly is that the chicken stays at its temperature, if the oven is isolated. The thermos effect as you observe.

Let me rephrase it. If you consider as “net” the combined R1 R2 energy balance , the Clausius formulation of the second law becomes moot and void, in my opinion.

480. Joel Shore says:

Willis Eschenbach says:

Note that this says “this approach allows both stratospheric, tropospheric, and land surface feedback mechanisms to operate.” So your claim above that “They are not talking about feedbacks.” is falsified.

I would have to read the Hansen paper in more detail (and perhaps the Gregory paper too) to understand what they are getting at. A lot of different things are called feedbacks and it is not clear which are included. What I would call your attention to is this sentence that you quoted:

An estimate of the forcing is obtained by regressing the flux at the top of the atmosphere against the change in surface air temperature, with the flux at zero temperature change being the estimated forcing.

Note that by looking at the flux in the limit of zero temperature change, you can’t be seeing any feedbacks, such as the water vapor feedback, that depend on the temperature…because you are looking at the zero temperature change limit.

I am still confused about what you are even claiming: Are you claiming that the ~4 W/m^2 forcing due to doubling CO2 means a 4 W/m^2 change in the TOA flux because it already includes the water vapor feedback. Or, are you arguing that the water vapor feedback somehow doesn’t affect the TOA flux? I don’t think either of these claims is correct but I am not really sure at this point which one you believe to be correct.

481. Joel Shore says:

anna v says:

But you agreed that in my example of turning off the radiation from the sun the two reservoirs R1 R2 , T1>T2 , turning it on would make no difference in the thermodynamic picture?

InRe: Joel Shore (Mar 24 17:40),

No…What I said is that having the sun in the picture does not then make it possible for there to be net radiation transfer from the (cooler) atmosphere to warmer earth. That is very different than saying the sun makes no difference to what would happen to the whole system…It makes a huge difference obviously. You turn off the sun and the earth will cool to a ridiculously low temperature (probably until internal processes producing heat in the earth, e.g., due to radioactive decay balanced the radiant loss out into space).

The chicken would radiate as a black body, the radiation would be reflected by the reflector ( not by a complicated CO2 logic) etc. and with the logic of adding the back radiation that is used in the CO2 problem, one would get a runaway heating problem!

It is all those additions of watts/m^2 that are double counting in my opinion of course in the greenhouse expositions. A delay of cooling is fine, but it cannot be represented by adding watts/m^2 at imaginary boundaries.

You are basically running yourself around in circles by choosing analogies that are nowhere near analogous (e.g., no heat source like the sun present). I suggest you go and solve the problem that I described in a previous post:

You have a blackbody sphere representing the sun that is at a constant temperature T_s and then you have it surrounded by one or two blackbody concentric spherical shells (A and B, which are analogs…in a very abstract way…of the earth and an IR-active atmosphere, respectively, with the radius of B slightly larger than A). There is empty space (assumed to be at zero temperature) beyond that. The question is then: What is the steady-state temperature of spherical shell A when shell B is absent and what is the temperature of shell A when shell B is present? Also, when Shell B is present, which way is the net radiative heat flow, from A to B or B to A? (These questions can be answered exactly by a simple calculation if you assume that the radii of the sphere and the two shells are close enough that one can neglect any “self-view” that the inner surface of shell A or B has of itself.)

I’ll even give you the answers:

T_A = [(1/2)^(1/4)] T_s ~= 0.84 T_s when shell B is absent.
T_A = [(2/3)^(1/4)] T_s ~= 0.90 T_s and
T_B = [(1/3)^(1/4)] T_s ~= 0.76 T_s when shell B is present.
With B present, the net flow of radiation between B and A is (1/3)*sigma*(T_s^4) from A to B.

This simple example illustrates all the features of the greenhouse effect: The presence of Shell B causes Shell A to be at a higher temperature than when Shell B is absent. However, Shell B is at a lower temperature than Shell A…and the net flow of radiation is from the warmer A to the cooler B. If you understand this example, then you will basically understand the greenhouse effect and also why the claim that it violates the 2nd Law is WRONG, WRONG, WRONG.

482. Joel Shore says:

Bryan says:

Apparently Chris does not think that you or Arthur are prominent Physicists.

Well, I would tend to agree with Chris, depending on what is meant by the word “prominent”. Certainly, if you surveyed 100 random physicists, I doubt many (maybe even any) of them would have heard of us. However, by that standard, G&T aren’t very prominent either. And, in terms of publication record, from what I’ve seen, I think that I would stack up very favorably with them.

I see it it required six of you to comment on what you regard as rubbish.

I’ll tell you a little story. I once was part of a comment on a paper in Physical Review Letters (PRL), where papers are limited to 4 pages in length. I was subsequently told by someone that the paper’s main author had bragged about how wonderful his paper was and said that he really could have gotten several papers in PRL out of that work but had chosen instead to put it all into one. When I heard this, my reaction was, “Well…In a bizarre way I sort of agree with him because comments on papers in PRL are limited to one page and it was very difficult to explain all of the errors that he had made in that one paper in just a one-page comment. So, he really did have at least several PRL-length-paper’s worth of errors crammed into that one paper.”

And, so it is with G&T…There is so much wrong in there that it is hard for just one person to tackle it all. I would also add that all of us were doing this basically in our “free time” so it was also a case of “many hands make light work”. Personally, I think that Arthur’s original unpublished paper in response to G&T is considerably more elegant than our 6-author comment although ours is a more comprehensive litany of the errors in G&T, whereas Arthur picked mainly one issue to focus on.

483. Joel Shore

Will it be published in arXiv. form ?
Perhaps one of the main platforms such as WUWT or Realclimate will host a feature on it to facilitate an in depth discussion on its merits!

Will it contain gems such as

….”applies to net flows; it does not mean that no heat can be radiated by a colder body and absorbed by a hotter one.”

484. Willis Eschenbach says:

JAE (06:30:00)

Willis Eschenbach (00:42:35) :

Thank you, but no. What you say is correct, but it all ignores the question. If the GHE is a determinant of temp., then more GHE amounts = more back-radiation = more heat. Instantly. Now, if evaporation and convection keep this heat in check, fine. Then let’s stop worrying about adding more GHEs to the atmosphere.

I think that evaporation and convection do keep this heat in check. See here for the details.

485. Willis Eschenbach says:

Joel Shore (19:42:48)

anna v says:

But you agreed that in my example of turning off the radiation from the sun the two reservoirs R1 R2 , T1>T2 , turning it on would make no difference in the thermodynamic picture?

InRe: Joel Shore (Mar 24 17:40),

No…What I said is that having the sun in the picture does not then make it possible for there to be net radiation transfer from the (cooler) atmosphere to warmer earth. That is very different than saying the sun makes no difference to what would happen to the whole system…It makes a huge difference obviously. You turn off the sun and the earth will cool to a ridiculously low temperature (probably until internal processes producing heat in the earth, e.g., due to radioactive decay balanced the radiant loss out into space).

[lots of other good stuff snipped]

Joel is right. You chould look at the diagrams and follow the math at my post, The Steel Greenhouse, for a simpler explanation of why he is right.

Again, folks seem to think that a colder object cannot radiate heat to a warmer object. It most definitely can. The constraint from the Second Law is only that the net flow has to be from the warmer to the colder object. It says nothing about the individual flows except that the flow from warm to cold has to be greater than the flow from cold to warm.

486. Willis Eschenbach says:

Joel Shore (19:17:27)

Willis Eschenbach says:

Note that this says “this approach allows both stratospheric, tropospheric, and land surface feedback mechanisms to operate.” So your claim above that “They are not talking about feedbacks.” is falsified.

I would have to read the Hansen paper in more detail (and perhaps the Gregory paper too) to understand what they are getting at. A lot of different things are called feedbacks and it is not clear which are included.

Joel, you are correct that the definitions are not always clear. Here is the IPCC FAR definition:

The definition of RF from the TAR and earlier IPCC assessment reports is retained. Ramaswamy et al. (2001) define it as ‘the change in net (down minus up) irradiance (solar plus longwave; in W m–2) at the tropopause after allowing for stratospheric temperatures to readjust to radiative equilibrium, but with surface and tropospheric temperatures and state held fixed at the unperturbed values’.

However, the differences between the various forcings Fi, Fa, Fg, Fs, and Fs* are not large. Hansen defines these forcings as follows:

Fi, instantaneous forcing

Fg, fixed Tg [ground temperature] forcing, which allows atmospheric temperature to adjust

Fs, fixed SST forcing, which allows atmospheric temperature and land temperature to adjust

Fs* [equilibrium flux from a situation in which] a climate model run exists in which the forcing was added suddenly to a model control run and then held constant for a long simulation. An estimate of the forcing is obtained by regressing the flux at the top of the atmosphere against the change in surface air temperature, with the flux at zero temperature change being the estimated forcing.

The Hansen paper cited above gives the following values in W/m2 for the forcings resulting from a doubling of CO2:

Fi: 4.52
Fa: 4.12
Fg: 4.08
Fs: 4.11
Fs* 3.95 ± 0.11

Note that the final value, Fs* includes all possible feedbacks/forcings from a model which is run until such time as the surface temperature is no longer changing.

I used the IPCC canonical value of 3.7 W/m2 for the equilibrium value of the change in forcing from a doubling of CO2. However, if I use 3.95 W/m2 from Hansen’s paper it makes no difference. Here are the results using the IPCC midrange sensitivity of 3°C from a doubling of CO2:

With 3.95 W/m2 change in equilibrium TOA forcing per doubling, we get 3°C/3.95Wm-2 = 0.75°C/Wm-2.

With 3.7 W/m2, we get 3°C/3.95Wm-2 = 0.81°C/Wm-2.

With real world measurements, we get 20°C/150Wm-2 = 0.13°C/Wm-2.

That’s why I say this whole question of feedbacks is a red herring. The problem is the huge difference between theory and measurement, regardless of which exact forcing we use for a doubling of CO2.

Note also that sensitivity is dependent on temperature, because parasitic losses and tropical cloud albedo both increase with temperature. So the equilibrium sensitivity that I calculate above from the real world numbers is going to be higher than the equilibrium sensitivity.

So … having disposed of the feedback question, I am still very interested if you have other objections to my analysis, and what those might be.

487. Invariant says:

Joel Shore,

One of the most annoying things with the climate models is the assumption of thermal equilibrium. Based on the “forcings” in GISS climate model,

we may erroneously get the impression that the global temperature would be completely constant in a world without humans. This is particularly peculiar since we know that Milankovitch cycles, ocean cycles and other cycles may lead to severe fluctuations – it is usually not the case that the criterion of thermal equilibrium is satisfied. So what is the magnitude of the natural oscillations the last 10 000 years, in a world without humans, both from a model and empirical point of view?

A) T = 287 ± 0.1 K
B) T = 287 ± 1.0 K
C) T = 287 ± 2.0 K
D) T = 287 ± 3.0 K

What is your opinion here Joel?

488. Invariant says:

Joel Shore,

Take a close look at this:

(click the curves to see papers)

It is quite evident that there is no thermal equilibrium, but that the temperature oscillates significantly. Then the question becomes, given that the temperature oscillates significantly, what is the climate sensitivity to CO2? Surely this is not the problem Trenberth is addressing, in his world the energy budget is nearly balanced all the time.

Possibly natural climate oscillations may be an order of magnitude larger than the climate changes due to increased CO2.

How can we be certain that natural climate oscillations are insignificant?

489. Willis

…Again, folks seem to think that a colder object cannot radiate heat to a warmer object. It most definitely can. The constraint from the Second Law is only that the net flow has to be from the warmer to the colder object. It says nothing about the individual flows except that the flow from warm to cold has to be greater than the flow from cold to warm……….

A cold object can radiate to a hotter object.
Heat has the thermodynamic property of the capacity to do Work.
Ask yourself if this applies to the above statement.
Look at the definition of HEAT in any physics textbook.

490. Guenter Hess says:

Anna V,
I totally agree with you that there is a lot of confusion because of semantics.
In climate science heat and heat radiation are sometimes used as synonyms.
This is sloppy language and creates statements that apparently violate the 2nd law. If one applies the correct language everything is fine.
Per example one reads sentences like:
“all bodies at non-zero temperature radiate heat according to their temperature…”
Such sentences are wrong and incomplete. In physics heat is defined as energy transport from warm to cold. Therefore such sentences need to read:
“all bodies at non-zero temperature radiate heat radiation according to their temperature and emissivity”
If physics is phrased correctly and the word radiation is used, confusion is minimized.
Best regards
Guenter

491. lgl says:

Willis,

Where is TOA in a world without an atmosphere?

492. Joel Shore says:

Bryan says:

A cold object can radiate to a hotter object.
Heat has the thermodynamic property of the capacity to do Work.
Ask yourself if this applies to the above statement.
Look at the definition of HEAT in any physics textbook.

You may be right about the technical definition. These sort of things are why I have never been a big fan of thermodynamics and always try to think in terms of the underlying statistical physics. However, as Guenter Hess notes, what you are then quibbling over is just semantics. It does not in any way change our argument.

For example, here is a discussion by retired meteorology professor who is really militant on these issues of semantics and pedogagy: http://www.ems.psu.edu/~fraser/Bad/BadGreenhouse.html However, note that unlike you and G&T, he doesn’t jump to the conclusion that because the semantics are arguably not perfect, therefore the phenomenon does not exist. He just argues for a better way to describe the phenomenon.

Invariant says:

Based on the “forcings” in GISS climate model,

we may erroneously get the impression that the global temperature would be completely constant in a world without humans. This is particularly peculiar since we know that Milankovitch cycles, ocean cycles and other cycles may lead to severe fluctuations – it is usually not the case that the criterion of thermal equilibrium is satisfied.

Well, if you erroneously get that impression, it is your own erroneous conclusion. Hansen et al. very well understand that there are forcings that occur from natural causes too. In fact, that is how they have arrived at one estimate of the climate sensitivity: They have looked at the estimated forcings during the Ice Age – interglacial cycles (triggered by the Milankovitch cycles of which you speak) and at the resulting temperature change. Forcings and temperature change due to volcanic eruptions like Mt. Pinatubo in the early 1990s provides another piece of empirical data to estimate the climate sensitivity.

You are confusing two different things here:

(1) Changes in temperature due to changes in natural forcings (such as the ones that I have listed above).

(2) Changes in temperature due to internal variability.

The latter are NOT assumed not to exist and, in fact, there has been quite a bit of study of such internal variability using climate models and comparing to the real world. Unfortunately, however, this can be hampered a bit by the fact that we don’t have very accurate estimates for forcings in the past, particularly during times when the forcings were fairly small (e.g., changes in solar forcing over the last couple thousand years) and, of course, our estimates of the temperature changes themselve is more difficult once we go back to before the instrumental record.

Possibly natural climate oscillations may be an order of magnitude larger than the climate changes due to increased CO2.

We know quite accurately (within about 10% or so) the radiative forcing due to a given increase in CO2. We can also estimate the radiative forcing due to past events such as the last glacial maximum and the Mt Pinatubo eruption. This allows us to calculate what the effect of CO2 should be. So, in fact, it is the past climate changes…particularly the significant ones for which we can get the best estimates of temperature change and forcings…that allow us to estimate how large a change in climate will be produced by the known radiative effect of increasing greenhouse gases.

493. Joel Shore says:

Willis Eschenbach says:

So … having disposed of the feedback question, I am still very interested if you have other objections to my analysis, and what those might be.

Willis,

I don’t think you have really disposed of the question at all. In fact, you haven’t really addressed the questions from the last post: I.e., I still don’t understand what your argument is. Are you claiming (1) that the ~4 W/m^2 number includes the effects of feedbacks such as the water vapor feedback, or (2) that it doesn’t but somehow the water vapor feedback doesn’t change this number?

Also, how do you feel that an estimate of forcing discussed in the way that Gregory et al. define it (by this regression to zero temperature change) could possibly include the effects of the water vapor feedback, which only operates when there is a nonzero temperature change?

And, I still don’t understand the mechanism by which you imagine the IPCC would claim that a ~4 W/m^2 change in the TOA radiation would lead to such a large surface temperature change. The only mechanism that I could see for that happening is if there were a huge amplification of the surface temperature relative to that higher up in the troposphere and, in fact, we know that the prediction is for the amplification to go the other way (although on a global scale it is not that large).

When you find yourself arguing against what is clearly a fallacious argument…particularly one that you think has been embraced by a very large community of scientists, that is a sign that you may be arguing against a “strawman” that you have created rather than their actual argument. I am afraid that this is indeed true in this case.

494. Joel

You may be right about the technical definition. These sort of things are why I have never been a big fan of thermodynamics and always try to think in terms of the underlying statistical physics. However, as Guenter Hess notes, what you are then quibbling over is just semantics. It does not in any way change our argument…….

The matter of whether one is a big fan of one branch or physics or not we must use the language developed within the discipline or it will lead to all sorts of confusion.
For instance I have never been completely comfortable with Quantum Mechanics yet I use its methods and language until some better explanation comes along.
I hope that in your new paper you will use language that is consistent within the Framework of Physics after all that is what the article is meant to be addressing.

495. Invariant says:

> Unfortunately, however, this can be hampered a bit by the fact that we don’t have very accurate estimates for forcings in the past, particularly during times when the forcings were fairly small (e.g., changes in solar forcing over the last couple thousand years) and, of course, our estimates of the temperature changes themselve is more difficult once we go back to before the instrumental record.

Thanks Joel for comments. I am honestly trying to figure out what is your point of view – disagreements pave the road to progress!

Now, from what you state, do you argue that any change in global temperature need to be caused by an internal or external force?

496. Guenter Hess says:

Joel,
I agree with Bryan.

Semantics in this context is very important, since your statement implied to the reader a violation of the 2nd law of thermodynamics.

I made my statement because I find the confusion between heat and heat radiation or thermal radiation in popular books about climate change written by prominent physicists like Schellnhuber and Rahmstorf.

Such a confusion suggests to many scientists that the grasp of thermodynamics by the author, who uses the technical words wrongly, is not sufficient to talk about issues like global warming with expertise.

I do not assume that Rahmstorf or Schellnhuber do not know this. However, I do think one should strive to phrase the physics correctly.
G&T refuted wrong statements like yours and in that they were right in some particulars.
You in turn tried to refute G&T in turn with the same wrong statement they already refuted. This is a waste of time. Therefore, lets strive to phrase correct statements about physics.
By the way I am a big fan of thermodynamics classical and statistical. Both branches augment each other and are necessary to describe the physical world within any field of science.

Best regards
Guenter

497. Invariant says:

Joel,

I would argue that transitions from one climate state to another do not have to be caused by any particular change in an external driver. In driven, non-equilibrium systems such changes may occur even though a specific cause can not be identified. If the temperature is not in equilibrium, the right hand side of the heat balance is non-zero,

m c dT/dt = Qin – Qout

and the temperature may change even though Qin and Qout is constant. In fact the temperature may change both for constant and variable values of Qin and Qout, but not if the difference, Qin – Qout, is identically equal to zero.

Most of the arguments I have seen from the AGW community seems to assume that there is always equilibrium, in order for the temperature to change, something has to change it…. This is clearly nonsense, in particular when the AGW community argues that something has to have caused the warming from the little ice age. Well, do they argue that there was equilibrium during the little ice age in 1750 when the world was much colder? If there is also equilibrium today this clearly does not make sense since the earth is warmer today… We know from the heat balance that the last term Qout is temperature dependent (Stefan Boltzmann radiation), so it’s impossible that two different temperatures at the same time can be the equilibrium temperature for our planet! Then the question is, given that the temperature has changed a lot the last 1000 years,

http://pages.science-skeptical.de/MWP/MedievalWarmPeriod1024×768.html

would it be possible to argue that the climate behaves as an oscillator, with normal fluctuations in temperature around equilibrium?

m c dT/dt = Qin – Qout

Look at the heat balance; wouldn’t it be fantastic if the temperature fluctuations would be zero? A perhaps more realistic result would be, given the Milankovitch cycles, ocean cycles and other cycles, that the temperature would oscillate a couple of Kelvin?

What is your gut feeling Joel? That the temperature fluctuations are small or large?

498. Invariant says:

The question to Joel is, given that the temperature has changed a lot the last 1000 years,

http://pages.science-skeptical.de/MWP/MedievalWarmPeriod1024x768.html

would it be possible to argue that the climate behaves as an oscillator, with normal fluctuations in temperature around equilibrium?

m c dT/dt = Qin – Qout

Look at the heat balance; wouldn’t it be fantastic if the temperature fluctuations would be zero? A perhaps more realistic result would be, given the Milankovitch cycles, ocean cycles and other cycles, that the temperature would oscillate a couple of Kelvin?

What is your gut feeling Joel? That the temperature fluctuations are small or large?

499. Joel Shore says:

Invariant: Yes, it is quite possible that there has been a negative internal fluctuation in temperatures over the last century that has partially masked the warming due to greenhouse gases which otherwise would have been larger.

Actually, I am being somewhat facetious in the above. However, my point is that internal variability doesn’t only occur in one direction. And, more important than that is the fact that saying that internal variability exists doesn’t repeal the fact that climate responds to forcings too…and that we have estimates for its sensitivity to such forcings.

And, by the way, there is quite a bit of work within the climate science community in characterizing internal variability…so it is not like it is something that they haven’t thought about, or that the climate models themselves don’t show. And, as I understand it, the estimates are that the internal variability is pretty small.

A perhaps more realistic result would be, given the Milankovitch cycles, ocean cycles and other cycles, that the temperature would oscillate a couple of Kelvin?

What evidence do you have for such numbers? And, why are you including Milankovitch cycles at all…Those provide a forcing; they are not internal variaibility.

500. Invariant says:

Invariant: Yes, it is quite possible that there has been a negative internal fluctuation in temperatures over the last century that has partially masked the warming due to greenhouse gases which otherwise would have been larger.

OK. Agreed!

Actually, I am being somewhat facetious in the above. However, my point is that internal variability doesn’t only occur in one direction.

Sure! Oscillations go both ways, just like a pendulum.

And, more important than that is the fact that saying that internal variability exists doesn’t repeal the fact that climate responds to forcings too…and that we have estimates for its sensitivity to such forcings.

OK. Agreed!

And, by the way, there is quite a bit of work within the climate science community in characterizing internal variability…so it is not like it is something that they haven’t thought about, or that the climate models themselves don’t show

OK. I think I have to learn your language, it is internal variability I should state when I mean internal oscillations not caused by an (external) force.

And, as I understand it, the estimates are that the internal variability is pretty small.

Now, this is interesting. What is regarded as large and small interests me a lot. Compared to what? What is the evidence for this? And is it easy to tell internal variability from increased CO2 or other external variations? Sometimes I tend to listen more to what people have experienced in historical times than dubious climate reconstructions…

“Comparatively rapid variations of climate, of the order of a century, have presumably always occurred…”
(p. 379)

What evidence do you have for such numbers?

Well, I have no experience in climate science, however I have a Ph.D. in Physics with specialization in non-equilbrium thermodynamics, and I suspect that it is unlikely that internal fluctuations (as you like to call them) are negligible. I do not regard a couple of Kelvin as much since the climate never has a chance to reach equilbrium.

And, why are you including Milankovitch cycles at all…Those provide a forcing; they are not internal variaibility.

I know, but I think the internal fluctuations may be triggered by external fluctuations. Think of an harmonic dissipative oscillator RLC circuit with many resonsance frequencies that is driven by oscillations on many frequencies due to Milankovitch cycles and/or oscillations between

1. day and night,
2. summer and winter,
3. ice ages and warmer periods

The fact that the equilbrium temperature is not fluctuating more than 287 ± 1-2 K is quite impressive. A process engineer would be very happy with a regulator that manages to keep the temperature that stable…

501. Willis Eschenbach says:

Joel Shore (07:13:15)

We know quite accurately (within about 10% or so) the radiative forcing due to a given increase in CO2.

Cite? (Please don’t cite climate models, I’m looking for evidence …)

502. Willis Eschenbach says:

Joel Shore (07:27:58)

Willis Eschenbach says:

So … having disposed of the feedback question, I am still very interested if you have other objections to my analysis, and what those might be.

Willis,

I don’t think you have really disposed of the question at all. In fact, you haven’t really addressed the questions from the last post: I.e., I still don’t understand what your argument is. Are you claiming (1) that the ~4 W/m^2 number includes the effects of feedbacks such as the water vapor feedback, or (2) that it doesn’t but somehow the water vapor feedback doesn’t change this number?

The number Hansen quotes is obtained by doubling the CO2 in a model, and then holding all other conditions the same until the surface temperature stops changing. Presumably, this includes the effects of all feedbacks such as water vapour, as all modern climate models include them. So I am claiming (1).

Also, how do you feel that an estimate of forcing discussed in the way that Gregory et al. define it (by this regression to zero temperature change) could possibly include the effects of the water vapor feedback, which only operates when there is a nonzero temperature change?

I think that you misunderstand the situation. The CO2 was doubled, increasing the forcing in the model. The modelled surface temperature then started to rise, with all of the relevant feedbacks that implies. The model was run until there was no further temperature change. At that point, the net change in TOA forcing (and surface temperature) was calculated.

So it is not a situation of a zero temperature change, as you seem to think. The CO2 was doubled, surface temperature started to rise, and the model was run until the temperature stopped rising.

And, I still don’t understand the mechanism by which you imagine the IPCC would claim that a ~4 W/m^2 change in the TOA radiation would lead to such a large surface temperature change. The only mechanism that I could see for that happening is if there were a huge amplification of the surface temperature relative to that higher up in the troposphere and, in fact, we know that the prediction is for the amplification to go the other way (although on a global scale it is not that large).

Heck, I don’t know what mechanisms the IPCC claims. All I know is that they claim that a doubling of CO2 leads to an equilibrium TOA forcing change of 3.7 W/m2, and that the doubling will result in a temperature change of 3°C. Hansen (op cit) says the doubling leads to an equilibrium change of 3.95 ± 0.11 W/m2, and a surface temperature change of 1.96 ± 0.02°C.

When you find yourself arguing against what is clearly a fallacious argument…particularly one that you think has been embraced by a very large community of scientists, that is a sign that you may be arguing against a “strawman” that you have created rather than their actual argument. I am afraid that this is indeed true in this case.

You’ll have to be more clear about what you think is a “fallacious argument”. The IPCC numbers basically agree with Hansen’s numbers. The IPCC says an increase in forcing of 3.7 W/m2 (a doubling of CO2) will lead to a 2 – 4.5°C temperature increase. Hansen says an increase in forcing of 3.95 W/m2 (a doubling of CO2) will lead to a 2C temperature increase.

Where is the fallacy?

503. Willis Eschenbach says:

lgl (02:51:47)

Willis,

Where is TOA in a world without an atmosphere?

The more relevant question is, how much TOA forcing (downwelling longwave radiation) is there in a world without an atmosphere. The answer, of course, is zero.

504. anna v says:

Joel and Willis,

I do not doubt that the calculations of shells and temperatures are correct. Of course there is a “greenhouse effect”, we are here, aren’t we?

The classical thermodynamic view of “reservoir1” and “reservoir2” and the second law should be working on a ball with an atmosphere whether there is an extra heat source or not. Otherwise the Clausius formulation of the second law is defied.

My point is that talking of “back radiation”, adding watts/m^2 all over the place is not within classical thermodynamics, it mixes in quantum statistical terms and leads to confusion and I suspect double counting in the famous energy budgets.

The chicken in the oven
http://www.vermonttiger.com/content/2008/07/nasa-free-energ.html
being an illustration of double counting.

So it is semantics, but it is easy to make logical errors when the semantics is confused.

505. lgl says:

Willis Eschenbach (17:32:57) :

The relevance is that you put the 0 W at surface altitude and the 150 W at 6 km altitude in your equation.
And the 3.7 W is without feedbacks.

anna v

“I suspect double counting in the famous energy budgets.”

There is double counting. That’s how feedback loops work. If 59% of the LW from surface is back radiated, the resulting gain is 1/(1-0.59)=2.44 and the 200 W solar input becomes 490 W at the surface.

506. Joel Shore says:

By the way, Willis, the Hansen et al. paper is very clear that the forcing definition used by the IPCC does not include feedbacks other than those due only to the STRATOSPHERIC temperature change:

[17] The adjusted radiative forcing, Fa, might be expected to be a good measure of the radiative forcing acting on the climate system and relevant to long-term climate change. The reason to anticipate this is that the stratospheric temperature adjusts rapidly, in comparison with the response time of the troposphere, which is tightly coupled to the ocean, and most forcing agents are present longer than the stratospheric radiative relaxation time. Thus Fa, the flux at the top of the atmosphere and throughout the stratosphere after the stratospheric temperature has come to radiative equilibrium, is the principal measure of climate forcing employed in RFCR and by IPCC [2001].
[18] Ultrapurists may object to calling Fa a forcing, and object even more to forcings defined below, because they include feedbacks. Fa allows only one climate feedback, the stratospheric thermal response to the forcing agent, to operate before the flux is computed.

507. Dave F says:

@ Joel Shore:

Models could only simulate temperatures in the 1990s by adding forcing from GHGs. Why does Earth return to pre-Pinatubo temperature so quickly if lags and feedbacks are involved in GHG forcing? ~.4C swing both directions in a matter of 3 years. Does this not suggest climate seeks to stabilize?

508. Invariant says:

And, as I understand it, the estimates are that the internal variability is pretty small.

Could you please be a little more specific. I would really appreciate to know what is the current state of the art knowledge here. Does it mean that internal variability may cause the temperature to fluctuate something like T = 287 ± 0.4 K?

509. cba says:

invariant,

the current state of knowledge? That’s been summed as “natural variation? we don’t need no stinkin’ internal variability!”

Of course, this is the same crew that presumes constant albedo in order to estimate sensitivities. Well, constant expect for the usual man-made surface changes.

seems like the closest to measuring albedo for any time period (about 20 yrs) came up with peak to peak variations of around 10%. That’s about 10w/m^2 average.

510. cba says:

ooops! sorrry – that’s 10w/m^2 averaged p-p power difference for that event.

511. Invariant says:

cba (04:34:41) :

Sure. However, I would very much like to know what they think, not necessary to determine if it makes sense, but merely to figure out what is going on inside their head. I do not think most of the climate scientists deliberately are cheating, and I think it is fortunate that Joel is contributing to WUWT.

So, with state of the art knowledge, I really mean what most of the scientists developing climate models think! Possibly Mojib Latif think internal variability is larger, however, that’s not what I intend to find out, what is the opinion of the main stream climate scientists?

I think this is relevant for the whole climate sensitivity discussion too; imagine that we knew that the internal variability was T = 287 ± 1.6 K with a characteristic cycle length of ~330 years. Then we could argue that the sensitivity of the climate would be less – it is harder to influence an oscillating system than a system at (or close to) equilibrium.

512. Pamela Gray says:

Internal variability is what destroys farmers into bankruptcy. The condition of the Pacific Ocean, combined with both the Arctic Oscillation and the Jet Stream can cause the inland northwest area of the US to freeze sewer tanks. Or allow us to grow something. Not a small percentage of crops are planted in the fall or once very few years, so a deep freeze will kill these kinds of plants. And if these weather pattern variables are oscillating in the cold mode and in tandem for a few years, you can kiss your farm subsidies, let alone your crops, goodby. It is a decidedly no small thing and exposes the fact that armchair and Ivory tower climate warming believers haven’t a clue about the strength of internal variability, in one season, and over several seasons.

513. Pamela Gray says:

Addendum, internal variability cannot be “averaged”. Internal variability is a climate zone specific entity. Some zones are stable to variability, and some are not. A calculated average lulls everyone into unpreparedness. And many deaths. Anyone here who is willing to state such a mathematical calculation as a single application to climate modeling is guilty by association to such nonsense and engages in dangerous propositions.

514. Invariant says:

Pamela Gray (06:55:38) :Addendum, internal variability cannot be “averaged”.

Then internal variability is not what I have in mind. What would you call PDO Pamela?

515. Joel Shore says:

Invariant says:

I do not think most of the climate scientists deliberately are cheating, and I think it is fortunate that Joel is contributing to WUWT.

Thanks. You should keep in mind though that I am not a climate scientist by any stretch of the imagination. I am a physicist who has been studying climate science as a “hobby”.

In terms of internal variability, I don’t really know although my general impression is that the belief is that completely unforced variability (i.e., not due to major volcanic eruptions, changes in solar forcing, …) is pretty small…probably a few tenths of a degree. But, if I get the chance, I’ll try to see where they talk about this in the IPCC report and point you in that direction.

516. Invariant says:

Joel Shore (11:08:43) : I am a physicist who has been studying climate science as a “hobby”.

Thanks.

Me to, I am also a physicist who has been studying climate science as a “hobby”.

Looking forward to hear from you! Why cannot the climate equilibrium oscillate a couple of Kelvin? I’ve never heard a good reason! Since you are a physicist, you know that all fluxes are instantaneously given by the gradients, meaning that the reach for equilibrium one day may be pointless the next day. Although the forces point toward equilibrium, it is missed over and over again… And thinking of the yearly fluctuations does not make the issue easier either, I mean, a yearly variation of ~90 W/m² is quite astonishing, the forces discussed here are almost negligible in comparison.

517. Invariant (12:37:49) :
a yearly variation of ~90 W/m² is quite astonishing, the forces discussed here are almost negligible in comparison.
A pet peewee of mine too. People fight over the [purported] effects of a 0.1 W/m2 solar cycle variation and ignore the 90 W/m2 beam in their eyes.

518. Invariant says:

Leif Svalgaard (13:23:15) : A pet peewee of mine too. People fight over the [purported] effects of a 0.1 W/m2 solar cycle variation and ignore the 90 W/m2 beam in their eyes.

Well you told me this Leif! :-) (I did not know).

Do you have some emprical data showing this?

God påske! :-)

519. Invariant (13:59:55) :
Well you told me this Leif! :-) (I did not know).
Do you have some emprical data showing this?

Here is the past 15 [or so] years of actually measured TSI [normalized to SORCE]:

You can see that all curves fall just on top of one another [showing that the orbit is very stable – no barycenter nonsense] and that there are tiny wiggles from time to time. Those are the biggest solar active regions. The solar cycle variation is smaller than the thickness of the lines.

God påske! :-)
Tak og til dig såvel.

520. cba says:

gee leif – but that’s peak to peak, LOL. the RMS difference is less.

Invariant, the 90W/m^2 difference is due to the orbital distance – aphelion to perihelion distances. December is perihelion – meaning that the peak incoming power to the southern hemisphere summer is actually 90W/m^2 more than the peak power coming to the northern hemisphere during its summer.

What’s more interesting to me is that the SH temperatures tend to be slightly lower than the NH temperatures, despite this massive difference in forcing. The difference is evidently that the NH has most of the land surface while the SH has most of the ocean surface. Considering that ocean albedo is much lower than land albedo, something like less than 0.04 versus something in the realm of 0.15 to 0.19, not only does the SH summer have more power (90w/m^2 peak to peak) at the TOA than the NH, ignoring cloud cover, there would be another 34 w/m^2 of absorbed power ignoring also additional differences in TOA power.

Of course, if one insists on ignoring cloud cover albedo changes, one is then faced with massive increases in absorbed power resulting in lower temperatures. LOL.

What has to be going on is something in the line of LIndzen’s iris effect where the added forcing, especially over water, is resulting in more water vapor cycle and cloud cover albedo reduction of incoming power to the surface.

521. cba (14:45:21) :
gee leif – but that’s peak to peak, LOL.
So is the solar cycle effect…
the RMS difference is less.
I don’t know what you mean, or rather it doesn’t make much sense to compute RMS over a smooth curve…

December is perihelion
January 4th.

What has to be going on is something in the line of LIndzen’s iris effect
And yet, in spite of all that, the 1 W/m2 solar cycle effect manages to sneak by the 90 W/m2 and make LIAs etc. :-)

522. Joseph says:

A very interesting plot Leif! Thank you for that. Now I have a question.

Do you have any idea what that plot might look like over the course of the glacial/interglacial cycles?

What I am getting at is this: Is the effect of the Milankovitch cycles limited to a change in the latitudinal distribution of solar radiation that reaches the surface, or does the TSI that reaches the TOA change as well?

This has been bugging me for a long time (I can’t find any info) and I would appreciate anything you could contribute.

523. Invariant says:

Leif Svalgaard (14:42:18) :The solar cycle variation is smaller than the thickness of the lines.

Thanks a lot Leif! Really appreciate it! :-) Regarding the 1 W/m² TSI variation, perhaps some people thinks that our climate can be charged like a capacitor over many cycles by this extra offset? You know, if you have a simple RLC oscillatory circuit, the capacitor and the inductance can be charged and discharged each cycle. However, increasing 1365 W/m² to 1366 W/m² is not a big increase (in magnitude) after all, and I doubt that the capacitor wil notice the difference.

Regarding my proposed climate variation of T = 287 ± 1.6 K with a characteristic cycle length of ~330 years, perhaps this is not so unlikely after all? I mean, we know that the climate is chaotic, and chaos almost always means scale invariance, implying that the rapid oscillations we see at a short timescale (years) also must be visible on a larger timescale (decades, centuries). Whether the magnitude of the variations also must be scale invariant is an interesting question, because if they are, then small oscillations (in amplitude) on a short timescale may be invariant with large oscillations (in amplitude) on longer timescales.

524. Joseph (15:53:09) :
What I am getting at is this: Is the effect of the Milankovitch cycles limited to a change in the latitudinal distribution of solar radiation that reaches the surface, or does the TSI that reaches the TOA change as well?

The average TSI [and all that reaches the TOA] over the year will not change measurably [as the average distance to the Sun is nearly constant]. The eccentricity of the orbit will change so the peak-to-peak swing will change [smaller the more circular the orbit is]. Another important changes will be in the phase of the curve, that is: when does it peak? A glaciation may hinge on the insolation at 65 degrees North during Northern summer.

525. Invariant (16:38:38) :
Regarding my proposed climate variation of T = 287 ± 1.6 K with a characteristic cycle length of ~330 years, perhaps this is not so unlikely after all?
If that 3.2 degree swing were due to TSI, it would mean a 60 W/m2 swing in TSI, which is not very likely. At least 100 times larger than what we would expect.

526. Invariant says:

Leif Svalgaard (17:11:57) : If that 3.2 degree swing were due to TSI, it would mean a 60 W/m2 swing in TSI, which is not very likely. At least 100 times larger than what we would expect.

Wow! Then the interal variations must be powerful… What could it be? Monster PDO? ….

527. cba says:

“Leif Svalgaard (14:52:12) :

cba (14:45:21) :
gee leif – but that’s peak to peak, LOL.
So is the solar cycle effect…
the RMS difference is less.
I don’t know what you mean, or rather it doesn’t make much sense to compute RMS over a smooth curve…

December is perihelion
January 4th.

What has to be going on is something in the line of LIndzen’s iris effect
And yet, in spite of all that, the 1 W/m2 solar cycle effect manages to sneak by the 90 W/m2 and make LIAs etc. :-)

the RMS I’d use to get an average power difference over half a cycle so as to get a number related to how much more power goes to the SH in their summer versus to the NH in our summer time. This 90w/m^2 peak to peak annual variation looks like it corresponds to a sine function.

the solar cycle effect is a bit longer than the few months of seasonal change which means it should have more of an effect due to the total energy, but still, it’s and order of magnitude less than the seasonal.

528. Willis Eschenbach says:

anna v (23:40:42)

My point is that talking of “back radiation”, adding watts/m^2 all over the place is not within classical thermodynamics, it mixes in quantum statistical terms and leads to confusion and I suspect double counting in the famous energy budgets.

anna, I hate to say it, but that paragraph is entirely content-free. If you (or anyone else) have a problem with the numbers that I laid out in The Steel Greenhouse or in this post, or that Joel laid out, you’ll have to:

a) quote (not paraphrase or interpret but quote) the offending words and numbers, and

b) tell us exactly what is wrong where.

Because I can’t respond to a claim that there may be double counting somewhere in some unspecified “famous energy budget”, that’s far from enough information.

Thanks,

w.

529. cba (20:02:25) :
the RMS I’d use to get an average power difference over half a cycle
Just integrate over the half-cycle to get a physically meaningful number. But, no matter what, the yearly variation completely swamps the solar cycle variation, which is why Milankovitch works so well, because it exploits that fact.

530. Willis Eschenbach says:

lgl (03:42:02)

Willis Eschenbach (17:32:57) :

The relevance is that you put the 0 W at surface altitude and the 150 W at 6 km altitude in your equation.

I’m not sure why that’s relevant. First, it’s not “at 6 km”, it is at the tropopause, which varies in altitude. The point is that ∆W, the change in radiation between the two situations, is 150 W/m2

And the 3.7 W is without feedbacks.

My understanding is that that is the equilibrium forcing, and that the feedbacks are taken up in the temperature response. This is supported by the Hansen figure (which is clearly including all feedbacks) of 3.95 W/m2, and a temperature response of about 2°C.

But if you have a citation to say otherwise, bring it forwards, that’s how science works.

531. Willis Eschenbach says:

Joel Shore (07:02:54)

By the way, Willis, the Hansen et al. paper is very clear that the forcing definition used by the IPCC does not include feedbacks other than those due only to the STRATOSPHERIC temperature change:

[17] The adjusted radiative forcing, Fa, might be expected to be a good measure of the radiative forcing acting on the climate system and relevant to long-term climate change. The reason to anticipate this is that the stratospheric temperature adjusts rapidly, in comparison with the response time of the troposphere, which is tightly coupled to the ocean, and most forcing agents are present longer than the stratospheric radiative relaxation time. Thus Fa, the flux at the top of the atmosphere and throughout the stratosphere after the stratospheric temperature has come to radiative equilibrium, is the principal measure of climate forcing employed in RFCR and by IPCC [2001].
[18] Ultrapurists may object to calling Fa a forcing, and object even more to forcings defined below, because they include feedbacks. Fa allows only one climate feedback, the stratospheric thermal response to the forcing agent, to operate before the flux is computed.

I understand that very well, Joel. My point is that the forcing Fs* is one of the “forcings defined below”, and it does include feedbacks of all types. That’s why I used the Fs* numbers …

It is also why I say it makes little difference which one you choose, because the difference between Fa and Fs* is only a few tenths of a Watt/m2 (Fa = 4.12, Fs* = 3.95 W/m2).

532. cba says:

Richard,
Just went over Lubos article (5 minutes worth at 6am) and there’s much to be said for it – not that I fully gleaned all of it at this hour of the day in such a short time. I do have some problems with it though.

Clear skies with surface radiation only account for about half of the Earth’s surface. Clouds block the rest with substantial ability. Clouds are not water vapor but are particles of liquid and solids which are no longer behaving as single molecules with well defined spectrums but are rather continuum radiators like larger solid and liquid objects. These are blocking the surface outgoing radiation and absorbing it. They are also radiating back down and radiating outbound at their characteristic temperature. However, this radiation outbound is a continuum at a lower temperature and it is above most all of the h2o vapor in the atmosphere and above both a good bit of the co2 AND it’s starting at pressures that are lower than the surface value and pressure is an important requirement for ghg absorption as it is required to spread the spectral lines out so as to permit greater capture.

Another problem with Lubos’ presentation is that the atmosphere in clear sky conditions is going to block about 30% of the radiation emitted from the surface. One needs just a bit more T to compensate.

For clear skies, radiation out of the atmosphere calculates to be around 270w/m^2, significantly more than a BB radiator around 288k. For an overall balance with 235 or 239 w/m^2 absorbed incoming solar, that means the cloud cover portion must radiate less than that through the balance of the atmosphere above t