Notes on the February Global Temperature Anomaly

Guest post by John Kehr

With two completed months of the year there is starting to be discussion of how 2013 is shaping up for the annual anomaly.  Several comments around the web have caught my attention as they demonstrate a basic misunderstanding of how the Earth’s climate is behaving.  This is one of those articles that may seem OCD, but this one misunderstanding is what allows warmists to get away with as much as they do when it comes to climate.

I am going to pick on Anthony Watts and Roy Spencer for this one.  The article in question was the one where Roy Spencer provided an update of the UAH anomaly.  Here is a screen shot of the article.

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From March 4th, 2013

The title states that there was a big drop in surface temperature in the month of February from ~ 0.5 to 0.2 °C.  This is correct for the anomaly, but it has nothing to do with the Earth’s temperature.  The reality is the Earth warmed up, but the anomaly dropped.

Let me explain.  January is the coldest month of the year for the planet as a whole.  Depending on the source, the average temperature is between 12.0 and 12.5 °C for the month.  February is on average 0.18 °C warmer than January, also source dependent.  Here is what the basic generic behavior of the Earth is on an annual basis.

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Illustration 1: Annual Temperature of the Earth and the Northern and Southern Hemispheres. The average temperature of the Earth is different for each month of the year.

This is based on the average from the 1900-1990 data and I have used this extensively as the baseline behavior for the Earth today.  Anomaly has no place on this chart because this shows the actual temperature of the Earth and each hemisphere.  How the seasons affect the global average is readily apparent.  To me it also shows how many factors can influence the global anomaly.  January and February are perfect examples of this.

If I switch to Weatherbell I can show some cool graphics that they produce.

Here is January and February of 2013 from their site.

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Notice that the Earth is  about 0.25 °C warmer in February, but since it was closer to average the anomaly was much less.  Climate scientists hate it when people show real temperature because it is impossible to see much warming when you look at the seasonal changes in the actual temperature.

Now for something interesting.  In January the anomaly in the Arctic was well above average.  By simple physics that meant the Arctic was losing energy to space at a much higher rate than average.  Normally the Arctic is losing energy at a rate of 163 W/m^2.  In January of 2013 it was losing energy at a rate of 173 W/m^2.  That 6% increase in rate of energy loss meant that the Arctic ended up with a negative anomaly in February.  The dramatic change in Arctic anomaly played a big role in the drop of the global anomaly in February.

The rate of energy loss is a self-correcting mechanism.  Physics don’t allow it to operate in any other way.  As a whole the Earth lost ~ 4 W/m^2 more than average over the entire surface in the month of January.  Data for February is not yet available, but it will be close to average because the anomaly was closer to average.  The higher rate of energy loss in January resulted in a more average February.  That is how the climate operates.

Finally I have to get a dig in at CO2.  In January of 2013 it was 395 ppm and in 1985 it was 50 points lower at 345 ppm.  So despite the fact that CO2 was higher, the Earth was losing energy at a higher rate to space.  CO2 was not blocking the energy from escaping despite all the claims that increased CO2 prevents heat from escaping the Earth.  The Earth 30 years later was losing a significantly larger amount of energy to space than it was in the past.

Science, ignore at your own peril.

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rgbatduke
March 11, 2013 8:22 pm

Complete fraud. The up and down of CO2 was caused BY the up and down of temperature. Everyone knows that CO2 lags temperature and therefore isn’t a cause to temperature. Read Bart’s recent posts. There are still people who believe Al Gore? Amazing.
Obviously I needed to put a tag in front of my comment. Let me remind you that I’m a skeptic. This was a sarcastic joke.
But by all means, take it seriously.
Sheesh.
rgb

rgbatduke
March 11, 2013 8:37 pm

RBG, The radiation from an ice cube does not warm you up or make you hotter. Please stop denying the origin of quantum theory, and thinking that just because something has a spectrum, it must be heating you up. Stand in front of a mirror and watch nothing happen to your skin temperature. Radiation trapped inside a cavity or returned from the source does not heat the source up some more. Stating the S-B Equation doesn’t change that – Planck’s Law and the S-B Law which comes from it do not say that trapped radiation causes an increase in its own frequency distribution and temperature.
Are you completely insane? Let me try one more time.
It is not radiation trapped in a cavity — it is radiation trapped in a cavity WITH A SOURCE THAT KEEPS ADDING MORE ENERGY.
Sheesh again, is this really so difficult to grasp? Which one is hotter? A 100 watt light bulb sitting in outer space where 100% of its outgoing radiation simply departs, or a 100 watt light bulb inside a partially reflective cavity that only lets 1/2 of the radiation incident on it escape?
In both cases, precisely 100 watts of power must be radiated away to keep the system in detailed balance, not net heating or cooling. In the latter, however, the integrated power of the radiation inside the cavity incident on the inside surface of the partial reflector has to be 200 watts for 100 watts to escape. The light bulb will absolutely be hotter in temperature at the same power in order to sustain the increased energy density inside the cavity.
As for the mirror: When I was a kid, growing up in India, we had these nifty radiant space heaters that were basically a coil with a parabolic reflector behind it. Curiously, they were a lot hotter in front of the reflector than behind them.
Or here’s a really nifty experiment — take two ordinary incandescent 100 watt light bulbs. Place a suitable thermometer on the surface of both. Cover one tightly with aluminum foil. Turn them both on. See which one sets your house on fire (I wouldn’t recommend doing this one unattended). Note well that the foil has excellent conductivity — better than the glass — so obstructing heat conduction isn’t a major factor, and both bulbs have the same shape before and after so neither is variation of convection.
rgb

RACookPE1978
Editor
March 11, 2013 9:07 pm

rgbatduke says:
March 11, 2013 at 8:37 pm (and)
MiCro says:
March 11, 2013 at 8:39 pm
Let me distract both of you from what I know is a frustrating effort, and – instead! – ask a more difficult question about radiation heat losses. Radiation heat absorption from nearby cooler objects will be completely ignored for a bit …. Except not really. 8<)
1. Assume you have a one square meter of 4 C water radiating into a cloudy sky at night; air temperature = -10 C.
2. Same water temperature, but now a clear sky also at -10 C air temp at 2 meters.
Water temperature is 4 degrees C, or 277 K, right? Emissivity of water = e= 0.97. S-B would tell us it is radiating at = e * S-B*(T^4).
Except the water is not radiating into "space at 3 degrees K, but into air at -10 C, 263 K. Emissivity air = .62, according several papers. But what is the "shape factor" between the two "objects? One a dome at – what? 2 km up? One a flat "object" at sea level.
Or are we supposed to use the 2 km air temperature if that is how far the water's IR radiation goes to into the air? Or does the air's IR wavelength (its initial energy) determine ITS wavelength frequency and wavelength distance, thus its penetration ability, and thus the temperature of the air that is radiating? After all, the further that the air's IR radiation must come from, the higher the air level that is on average is radiating, and the lower that air's temperature. On the other hand, the higher the air mass, the colder the air, the lower the frequency of the IR emitted from that air, and the shorter its effective range.
On any calm clear night, the temperature of the air on ground level by morning is much colder than on cloudy nights that start at the same point. I've stood too, too many night shifts not to recognize radiation cooling! But what is the equation "proving" that a pond or a car window will freeze over on a clear night, compared to a cloudy night?

Reply to  RACookPE1978
March 12, 2013 5:29 am

RACookPE1978 says:
March 11, 2013 at 9:07 pm
I got my initiation standing outside setting up my telescope, logging temps and seeing pretty large drops as the Sun went down.
I went and bought a IR thermometer (which I have returned, I’m going to build one that has a usb port so I can data log it), clear sky 35F day, the zenith was ~-41F, 75F colder. Clouds were warmer, overcast even warmer, but that wasn’t my interest so I can only remember seeing 0 to -20F temps or so. It was also fixed at .95 e, so I think .63 would mean the temp was even lower.
At 10C, there’s going to be more water vapor it will be so it won’t as cold either, but I never measured temps that warm. But it won’t be as cold as at 1.6C is.
I also logged air and ground temps one night, while the air dropped into the 20’s, we had frost on the grass, the dirt between the bricks in my patio were still about 34-35F.
Lastly, shape factor, I don’t know, but for the equations I’m working on I’m using a half hemisphere which I think is the default 2 body shape.

March 11, 2013 10:14 pm

@Micro: This is fact.
“Some people see that cooler object as an energy source, when in fact it is not.”
I stand corrected… I should have written “that the cooler object as an energy source that heats the warmer object.” But then again, if it slows the heat transfer from the warmer object, the rate of cooling of the warmer object can be seen as mitigated by the energy of the cooler object. So mathematically, it would work as a relative energy source, which it is. Got it.

March 12, 2013 6:23 am

Joseph E Postma says:
March 11, 2013 at 5:41 pm

Keeping them warm is not the GHE. A space blanket doesn’t heat you when you stand beside it, only when you’re wrapped in it. It does the same thing as a blanket but even better because it is impermeable.

Sure it does, it does so by reflecting some of the ir your body is radiating back to you, reducing your heat loss. Blankets work more like Co2 does, the blanket itself warms some, re-radiating some of your heat back at you.

March 12, 2013 6:30 am

rgbatduke says:
March 11, 2013 at 5:21 pm

Hell, you can go back over the last million years and CO_2 is solely responsible for all of the ups and downs.

I have a modification to this. At temps above say freezing, water vapor controls temps, below that is the domain of gaseous Co2. So on an ice ball earth, Co2 will build up in the atm (since the oceans are froze over and can’t sink Co2) from volcano’s. At some point the ice starts melting Co2 sinks into the oceans, water vapor collects in the atm, increasing temps. As it gets warmer, we start getting precipitation regulating the max temp water vapor will support.

March 12, 2013 6:49 am

RGB: Radiation trapped inside a cavity *with a source* is the only way to trap radiation inside a cavity. That is how it is done. And this is exactly what produces a blackbody spectrum and Planck’s Law. Standing in front of a mirror doesn’t warm you up. You’re assuming your result in your argument and then concluding that the assumed result must be true. Alas, radiation trapped inside a cavity with a source only produces a blackbody spectrum – it doesn’t heat itself up indefinitely, by a factor 2, 10%, or at all.

March 12, 2013 6:51 am

RGB: “I’m a skeptic. This was a sarcastic joke.”
My mistake. Easy to make given that you hysterically support the basis of climate alarm.

March 12, 2013 6:53 am

I am glad RGB and PR have found each other. It is interesting watching these relationships develop as revolving around ad-hom antagonisms toward a skeptical scientist.

March 12, 2013 6:59 am

“Solid” tin foil wrapped around a lightbulb has nothing to do with the atmospheric and “GHE”.
Three analogous laws of physics:
a = 1/m * (F2 – F1)
I = 1/R * (V2 – V1)
q = k (T2 – T1)
The presence of a force differential doesn’t cause the stronger force to increase; the presence of a voltage differential doesn’t cause the stronger voltage to increase; the presence of a temperature differential doesn’t cause the warmer temperature to increase – whether conductively or radiatively. Planck’s Law isn’t the GHE; the S-B Law isn’t the GHE. Radiation from a source trapped inside a cavity produces a blackbody spectrum, not a GHE.

March 12, 2013 7:03 am

Mircro: “Sure it does, it does so by reflecting some of the ir your body is radiating back to you, reducing your heat loss. Blankets work more like Co2 does, the blanket itself warms some, re-radiating some of your heat back at you.”
Hold a thermometer between you and the blanket, or you and the mirror, and see if it raises in temperature. It doesn’t. It only does if you’re wrapped in it, which means that it is the reduction of convective loss which makes the air warm up. A wool blanket works this way too. It is similar to an actual real greenhouse. Open air and CO2 can’t physically trap itself. The analogy to radiative trapping is *just* an analogy, and it is false, because that process actually just creates a blackbody spectrum and forms the basis of quantum theory.

March 12, 2013 7:44 am

Joseph E Postma says:
March 12, 2013 at 7:03 am
“Hold a thermometer between you and the blanket, or you and the mirror, and see if it raises in temperature.”
If you point a IR thermometer at your reflection in an ir reflecting surface, it will read your surface temperature. Space heaters have a reflector behind the heat source, which reflects the heat out of the heater, reducing the parasitic heating of the heater itself. Astronauts helmet face plates are flashed in gold, because gold is the best ir reflector (better than silver/aluminum reflectors). IR mirrors are gold. Some Spacecraft thermal blankets are gold foil.
A thermometer is not a sensitive measurement device, your 98 degree temp in a 70 degree room isn’t a large source of IR, but it is a source.
An ice cube is a ir heat source, it’s much much warmer than 0K. It is however colder than you are.
If you don’t believe this, go to your local Lowes, or Home Depot, buy an IR thermometer and take some measurements. When you’re done, return it if you want. Only cost you the gas there and back.

March 12, 2013 7:52 am

Hi Robert (rgb),
On 11th March 11 at 8:20 p.m. you made reference to “Slayer”/PSI founding member FauxScienceSlayer Joseph A. Olson (see Section 3.4 of http://globalpoliticalshenanigans.blogspot.co.uk/2012/06/spotlighton-principia-scientific.html). I have had the “pleasure” of numerous exchanges with Joe since 2010 and it is my humble opinion that he is the relatively “silent partner” in the PSI background. I believe that it was Joe who encouraged PSI “CEO and Legal Consultant” John O’Sullivan to pursue his “vision” of setting up PSI as a private company purporting to have charitable objectives.
There is that saying “Charity begins at home” which in my opinion is what remains the prime motivator for those founding members in trying to “ .. recruit the thousands of paid up members necessary to turn noble words into actions .. ” (http://globalpoliticalshenanigans.blogspot.co.uk/2012/06/psi-due-diligence-20102011-selected-e.html).
I am drafting an update to “SpotlightOn – Principia Scientific International .. Section 7.0 “Financial Aspects” pulling together all of the information that I have relating to this aspect of PSI founding member motivation. Until I have completed the update anyone interested can find most of it already distributed within that article and the associated E-mail exchanges, etc.
Your comment that “ .. I’ve had spectacular offline discussions with other slayers as well. No argument however cogent in support of the GHE is ever listened to and taken seriously .. “ has relevant significance. I do not agree that in the case of the PSI founding members “ .. It has become the primary battlefield of a modern religious war .. ”. In my opinion for several of them it is a much more base (adjective definition 7 at http://www.merriam-webster.com/dictionary/base) motivation than that. There is another relevant saying “Follow the money” – or perhaps in their case the lack thereof.
As for you comment on 11th March at 8:22 pm that “ .. This was a sarcastic joke .. ” I doubt that anyone so arrogant and consumed with self-importance understands satire.
I’ve just spotted Joe Postma’s comment “ .. voltage differential doesn’t cause the stronger voltage to increase .. ”. What on the surface totally escapes him (but more likely he is being his usual sophistic self) is that in an electrical circuit the addition of another EMF that OPPOSES the larger original EMF does indeed REDUCE the current flowing through the circuit, just as back-radiation reduces the energy radiating from the Earth’s surface to space.
No doubt Joe will provide some sophistic response to that.
BTW, I hope that you are prepared to contribute to the exchanges that I copied you on today about the extent of that “greenhouse effect” which Joe Postma and associates at PSI deny the existence of. Contrary to what the power-hungry, the UN, the politicnas, the environmental activists and th erenewable energy industry would have us believe, the science is far from settled and the debate is far from over.
Best regards, Pete Ridley (http://globalpoliticalshenanigans.blogspot.co.uk)

rgbatduke
March 12, 2013 8:41 am

I would have to agree… otherwise, one could trap a photon of light in a mirrored room and the room would heat up with all that reflected energy… then we could harness all that free energy from time to time.
Except that this is a completely false analogy and not what I described. The Earth is not a passively cooling object. It is actively being heated by the Sun. Put an energy source inside a perfectly mirrored room inside a vacuum and yes, the source will heat up from all of that reflected energy considerably more than it would if the photons it emitted all went away in a single pass.
In fact, you can easily take the description I gave in the previous post and compute how much a given heat source will have to warm in order to be in equilibrium if you do nothing but surround it with a perfectly absorbing thin layer of matter, e.g. a piece of foil painted black on both sides. The foil has to heat until its temperature permits it to radiate energy away at an integrated power P. It radiates a roughly equal amount of radiation back into the cavity at this temperature — it doesn’t know which is the “inside” and which is the “outside”, only that it is made of matter and is hot. The radiative energy density inside the cavity is, in fact, then strictly larger than it would be without the foil, and the temperature of the heated object in the middle increases in order to balance both the continuously delivered external power and the extra heat it absorbs from the radiation in the cavity.
That’s enough for you to take a spherical heated object of radius R and with power input P, assume unit emissivity (why not?) and compute its dynamical equilibrium temperature in a perfect vacuum at 0 K (so that radiation it emits goes directly away). Now imagine that a thin shell of unit emissivity material surrounds it at 2R. The same formula will give you the equilibrium temperature of that shell, and will tell you that the this shell is radiating a total power P back into the cavity. Some of this power will fall on the central heated object and constitutes additional power from radiative feedback. It now has to lose both P (its continuing input) and the additional energy radiated back onto it by the surrounding passive black body. Its temperature therefore has to increase until detailed balance is again achieved.
A mirror, of course, is a lot worse. A mirror has high albedo and reflects all of the power incident on it (assuming a perfect mirror in all frequencies, a bit of a stretch I admit but doable in a wide range of optically relevant frequences down into the IR). A mirror instantly boosts the energy density in the cavity WAY up because it only loses energy on the outside when it heats enough from its inefficiency so that it radiates P on the outside in thermal radiation (and still, on the inside too) plus all of the directly reflected energy. The temperature of a heat source inside a reflective cavity builds up rapidly. Building fire codes, electrical wiring codes, and more, all reflect (so to speak) this simple fact, but you can demonstrate it by burning out a bulb with a simple radiative feedback reflector whenever you like.
rgb

rgbatduke
March 12, 2013 8:56 am

Radiation from a source trapped inside a cavity produces a blackbody spectrum, not a GHE.
The temperature of a constant power source inside a cavity depends on two things. One is the temperature of the walls of the cavity. The other is the specific electromagnetic character of those walls, their albedo if you like.
Put the power source inside a zero albedo zero temperature cavity (e..g outer space) and it will equilibrate at one temperature.
Put it inside a zero albedo nonzero temperature cavity and it will be strictly warmer than it is in the zero temperature case, and its temperature will monotonically increase with the temperature of the cavity wall.
Put it inside a zero temperature nonzero albedo cavity and its temperature will be strictly higher than it is in the zero temperature zero albedo case, because even a very cold mirror can reflect broadband light and return it to the source.
All of these statements respect the laws of thermodynamics. There is no heat transfer from colder to warmer, only variation of the temperature of the dynamical equilibrium of the heated reservoir with the temperature of its surroundings or with the elastic (non-thermal) return of some of its emitted energy in the latter case.
But the case of interest in the GHE is the second one. Interpolating a perfect absorber between a heated source and outer space effectively places the source inside a warmer cavity than outer space alone. You persist in ignoring the heat source, because not even Planck computes a result for a heat source inside an adiabatic cavity with a hole drilled in it — the whole point of drilling only a hole was to make the energy loss of the cavity interior through the hole negligible compared to its otherwise constant enthalpy content.
Put a nontrivial heat source into the cavity and it will heat up until the energy loss through the hole balances the energy production in the cavity, always, unless you are fond of violations of the first law of thermodynamics. Make the hole bigger (for a constant power source) and the equilibrium temperature will decrease. Make it smaller and it will increase. Remove the hole, and the temperature in the cavity will diverge as its enthalpy content increases without bound.
rgb

Bart
March 12, 2013 10:18 am

Mario Lento says:
March 11, 2013 at 4:23 pm
“So you are saying that the equation predicted flat temperatures for the past 15 years? In other words, CO2 drove the temperatures flat from 1998, but upwards before that period?”
Hmm, what? No! CO2 isn’t affecting temperatures at all (or, at least, hardly at all, not to a significant degree). Something is driving temperatures, producing a trend plus ~60 year cycle, and temperatures are driving CO2.
Joseph E Postma says:
March 11, 2013 at 5:49 pm
“Read Bart’s recent posts.”
Oooh, I didn’t want to get dragged into this particular fracas. So far, I have to agree with rgbatduke – there appears to be a sound basis to expect that a so-called greenhouse gas (GHG) will impede the transfer of heat from the heated body, and all things being equal, that should produce an increase in temperature on the surface.
I have, however, made the observation that there appears to be no effect on surface temperatures over the last century despite a significant increase in CO2 concentration. Therefore, it behooves us to determine precisely where that seemingly compelling argument fails to reflect observational reality.
There are two particular weaknesses which I see in the GHE argument:
1) A general statement that a GHG causes retention of more heat than otherwise would be the case without it does not imply or require in any way that the function be monotonic, i.e., it can have local dips and curves. Indeed, if you consider the bounding cases where the GHG is not present, and where it is so dense that it is in direct, conductive contact with the surface, then there is no greenhouse effect (GHE) at the boundaries. It follows that the function much achieve its maximum somewhere between the two boundaries, and that there are regions where the partial derivative of temperature relative to increase in the GHG will be negative, i.e., in which additions to the GHG will provide cooling.
In a previous thread on Willis Eschenbach’s “Steel Greenhouse”, I showed one way in which such local reversal of the heating tendency could occur. If the GHG could be considered to be a solid, efficiently heat conducting shell surrounding the planet, then increasing its depth would produce cooling. This effect comes about because increasing the thickness of the shell decreases the surface area radiating back to the planet and increases the surface area radiating to cold space.
2) The statement “all things being equal” is a significant qualifier. In general, all things are not equal, and feedback effects can sharply attenuate, or even nullify, the initial impetus to warming.
I thought it possible that Joe had some specific quantum mechanical effect in mind, but if so, he hasn’t really explicated it that I have seen.

Reply to  Bart
March 12, 2013 10:47 am

Well, the QM effect is the creation of a blackbody spectrum – that is specifically a QM effect and only exists due to quantum mechanics. The shell just comes to the same temperature as the source, and then the shell emits the energy of the source. It doesn’t require the source getting hotter.

March 12, 2013 10:56 am

“Remove the hole, and the temperature in the cavity will diverge as its enthalpy content increases without bound”
If this occurred, we could smelt steel with a 100W light bulb. It doesn’t occur.

Kelvin Vaughan
March 12, 2013 11:37 am

Construct a pie chart with all the consituents of the atmosphere. Now find the CO2. Cant find it?
If you can’t find it what is the chance of radiation finding it on it’s way out of the atmosphere?

Bart
March 12, 2013 12:03 pm

Joseph E Postma says:
March 12, 2013 at 10:47 am
“The shell just comes to the same temperature as the source, and then the shell emits the energy of the source. It doesn’t require the source getting hotter.”
I think that would not be an equilibrium condition, because the shell has greater than twice the surface area of the planet, as it has an inside, and an outside. If we assume the shell is transparent to incoming radiation, and opaque to outgoing radiation, then we can effectively move the energy source inside the planet without changing the result, and the problem becomes analogous to Willis’ “Steel Greenhouse”. I wrote up the math for equilibrium conditions here.
The final formula I came up with was this:

T_planet_with_shell = T_planet_without_shell * ( 1 + (R_inner/R_outer)^2)^0.25

where the “T” variables are surface temperatures and R_inner and R_outer are the inner and outer radius of the shell. In equilibrium, the temperature of the shell is less than the temperature of the planet, and net energy is flowing outward, so there is no contradiction of the laws of thermodynamics. But, there was a very interesting thing about this formula…
Let

R0 = f*R_inner + (1-f)*R_outer

where f is a number between 0 and 1. Then, if the depth “d” is d = R_outer – R_inner,

T_planet_with_shell = T_planet_without_shell * ( 1 + ((R0-(1-f)*d)/(R0+f*d))^2)^0.25

The partial derivative of this with respect to d is negative, i.e., locally, the surface temperature decreases as the thickness of the shell increases, and this holds for any R0 defined by the relationship above, i.e., for any situation in which there is a constant radius which remains inside the shell as it expands.
This is very simplistic, of course, but it illustrates one of the ways in which a counter-intuitive result, local surface cooling the in face of increasing GHG, can come about. It does not contradict the GHE – the surface temperature is always greater than it would be without the GHG – but, there can be conditions in which incremental increase in concentration can produce cooling.
My advice is: assault the weak points in the fortification. If you mass your forces where the walls are thickest, you are going to suffer heavy losses, and probably fail to take the castle. Assaulting the basic so-called “greenhouse” effect is sort of like carrying pictures of Chairman Mao – you ain’t gonna’ make it with anyone anyhow. At least until you have solid evidence to back up the claim that it does not exist at all.

March 12, 2013 12:40 pm

The shell and planet would just come to the same temperature. Between the shell and planet would be a blackbody radiation spectrum of whatever the source was – the planet. As the shell emits to outerspace, this energy gets replaced by the source. No heat is transferred from the shell to the planet – the shell is either cooler or at the same temperature, and therefore doesn’t transfer heat to the planet. Remember, the presence of a temperature differential does not mean that the hotter side has to warm up – neither in conduction or radiation. It just means that the cooler side warms up, and if very close to the source, to the same temperature as the source. The shell just becomes the new planetary surface, and like the surface before it, doesn’t require a hotter source. Alarmism will exist as long as the GHE does, and I criticize the GHE because it is wrong, not because it is convenient. The quantum effect of the radiation trapped between the planet and shell is to produce a blackbody spectrum. In order to cause an increase in temperature, reflected/reabsorbed light would have to shift to higher frequencies, but this isn’t what happens. Planck figured out what happens and birthed quantum mechanics with his discovery.

Bart
March 12, 2013 12:57 pm

Joseph E Postma says:
March 12, 2013 at 12:40 pm
My comments are disappearing, too. Must be something with the site. I just wait, though, and they eventually appear.
I think Dr. Brown’s earlier analogy was very effective. When you put on a coat in cold weather, the coat doesn’t heat you up, your internal heat mechanisms do. All the coat does is inhibit the convective loss of that heat. Similarly, here, the shell does not warm the planet, it just inhibits the radiative loss of heat.
I don’t know if it can be made any simpler than that. If you still disagree, we will just have to agree to disagree.

March 12, 2013 1:19 pm

Yes but a coat and the physical blockage of convective cooling is not what the atmospheric GHE is – it is what a real greenhouse does, but a real greenhouse is not the atmospheric GHE. The analogy of this to trapping radiation is only an *analogy*, but it isn’t correct, because radiation trapped inside a cavity (with its source) produces a blackbody spectrum, not heat itself up. To get higher temperature the photons need to shift to higher frequency; but, photons interacting with themselves don’t change their frequency, and photons which come back to their source only interact with matter vibration frequencies which produced them in the first place, and this can’t cause a shift to higher frequencies either.
Someone named Bryan wrote this to me:
Consider the planet to have a high metal expansion coefficient, and the sphere a small one. There is a small distance between them. When the planet heats up to 470, it will expand and touch the shell. Now the shell will heat up to 470. Whereas before we couldn’t, say, create steam to drive a generator turbine, now we can (using the relevant values). You get the idea I hope. The system might cool and stop touching but then it would just heat up again and touch again. With an intrinsic source that couldn’t create steam in the first place, with a system of shells the system can now do more work than it could have in the first place, if the input energy was just used directly. Just by using a passive shell. Obviously that has problems of the thermodynamics type.

rgbatduke
March 12, 2013 1:56 pm

I do not agree that in the case of the PSI founding members “ .. It has become the primary battlefield of a modern religious war .. ”.
Even in the case of founding members, I’d probably exclude Tim Ball from this list. I actually find a lot of his writing on this issue to be well informed and quite compelling, in general agreement with my own opinions. But Dr. Ball doesn’t deny the existence of the GHE at all, he merely argues — correctly IMO — that we cannot naively claim that we understand all of the nonlinear and nontrivial feedbacks associated with the climate system well enough to assert that a change in CO_2 concentration will lead to any particular change in global average temperature or heat distribution. In my own opinion the null hypothesis here is the roughly 1-1.5 C expected from e.g. doubling CO_2 alone without any feedback at all, and the honest truth is that we have no real idea (yet) of the feedbacks sufficient to even give us a certain prediction of their sign. The last fifteen years of increasing divergence between UAH or even GISS from the rising CO_2 levels is not strong evidence for large positive feedback, to say the least.
BTW, I hope that you are prepared to contribute to the exchanges that I copied you on today about the extent of that “greenhouse effect” which Joe Postma and associates at PSI deny the existence of. Contrary to what the power-hungry, the UN, the politicnas, the environmental activists and th erenewable energy industry would have us believe, the science is far from settled and the debate is far from over.
To a limited extent, sure. As I commented in reply to the email, I’m already “on” the list of exchanges within this group, although I’m still not convinced that there is any real point to it all. IIRC Grant Petty tried to push the boulder over that hill for quite some time and finally gave up. Where the guru cannot succeed, how can then the chela? I can’t even get Joe Postma — who as I said is I think both honest and moderately educated — to understand the difference between a classical passive black body cavity at a fixed, fully equilibrated temperature with a tiny hole and an isolated actively heated spherical body in dynamical equilibrium with a “black body” perfect absorber Universe. Nor can I get him to buy or work through Petty’s book on his own, although the physics in it is pretty straightforward.
The problem is that I’m not a believer in grand conspiracies. Never explain by a grand conspiracy what is adequately explained by sheer human greed and incompetence — a contemporary version of Ockham’s razor. In the end, though, science does not care about belief, greed, or even incompetence. If Hansen himself is right, and we’re going to experience 5 meter SLR over the next 80 years and 3-5 C of temperature increase, my beliefs about this will not change the facts. If Hansen is wrong and temperatures go up only 1 C, or remain about the same, or go down some, well, neither his beliefs nor mine will change that.
In the meantime, it seems pretty harmless to let the null hypothesis stand, at least compared to the enormous cost of taking the wrong action at this time. SLR is an order of magnitude shy of the rate needed for Hansen’s publicly stated belief to be correct. That doesn’t mean he’s wrong, only that there isn’t any believable evidence that he’s right, yet. The pattern of global temperature change — even allowing for what a cynic might call deliberate thumbs on the scales — is not one that can easily be explained by the anthropogenic CO_2 hypothesis, where paradoxically there has been no warming at all since slightly before the 2001 events that led to Mann’s elevation from unheard of nobody to the prophet of the age, because he finally gave them the desired MWP-free prophecy where perhaps more honest scientists could not or would not or at the very least did not. The last 15 or 16 years are not disproof of the CAGW hypothesis, but they are not strong evidence in favor of it, either. The good news, then, is that there is no reason to panic, no reason to spend order of a trillion dollars on measures that even the proponents of those measures agree will not make a whit of difference in the outcome as things stand. We can afford to wait and see, and in the meantime think up some sort of measures that might actually work — such as building nuclear power plants wholesale, developing LFTR, and so on — in the event that SLR suddenly does jump up to the inch plus per year necessary to fuel Hansen’s “overheated” doomsday scenario.
And if this never happens? Perhaps we can use some of the trillions of dollars saved to fix the economic, social and education problems of the poorest people in the world and usher in a era of peace and globe-spanning civilization. Right now, we don’t have to wait for 2100 for a catastrophe. By diverting hundreds of billions of elective dollars towards measures that even on paper are totally inadequate to prevent a highly uncertain disaster, we are guaranteeing a catastrophe right now whose price will be paid, as usual, by the poorest people in the world.
Energy is civilization. By energy standards, well over half the people of the world are essentially uncivilized, still living in 18th or 19th century levels of poverty and misery. This is the missing half of the political dialogue. The countries that are being played for suckers are the countries that can least afford it, countries where people already go to be every night with the sun because they have no electrical lights, where they wash clothes by hand as they lack washing machines, where they cook on animal dung as they lack the energy resources and economy that might enable them to cook on an electrical or natural gas stove instead. People are starving and dying every day because there is no medicine, no refrigeration for medicine or food, no electricity, no energy-based transportation that can carry the simplest necessities of civilization from the industrial nations where these things are all abundant and cheap (because energy is abundant and cheap) to where they are infinitely expensive by the only standard that matters — a complete dearth, at any price anyone can afford.
In the meantime, nobody alive seems to have learned anything from the story of Chicken Little, or any of the other cautionary folk tales that once constituted a fund of simple wisdom for our species. The flames of religious passion that once might have been devoted to Jesus, or Allah, or Krishna, are now diverted towards Saving the Environment, always in capital letters, where the unwritten extreme of saving the environment is nothing less than the extinction of (most of) humanity, because otherwise we live in it and leave our mark. In defense of the Gods, no lie, no misstatement, no overstatement of the certainty of our knowledge is too much because the cause itself is pure, because the ends justify any means, especially if we can arrange for the 3/4 of humanity we wish to slate for extinction to be the other 3/4, the one that doesn’t include ourselves, our friends, our children, our loved ones. O Lord, inflict on the world a universal plague to save the world from us only — Lord, would you really mind inflicting the plague on everybody else?
In the teeth of this sort of passion — or the equally religious passion of the Other Side, the side that is certain that it is impossible for catastrophic warming to occur no matter what we do, that the environment can recover from any shock humans inflict on it and if it doesn’t, screw it, it is our environment to screw up as we like — where can mere common sense reside? The “Show Me” sort of mind that doesn’t listen to one-sided presentations of the evidence, that remains dubious that asserting that a “super storm” is caused by climate change means that that storm was in any way whatsoever connected to climate change, or that climate change (to the extent that the climate is always changing!) is necessarily connected to human activity — this sort of mind is somewhat rare today. There is too much to know, it is too difficult to form a considered, well-informed judgment about things like the climate, so if Hansen speaketh, who will gainsay him? Especially if he partners with many who would profit from he prophecy… because there is, indeed, a sucker born every minute, and two to take him.
rgb

Bart
March 12, 2013 2:06 pm

Joseph E Postma says:
March 12, 2013 at 1:19 pm
“To get higher temperature the photons need to shift to higher frequency…”
Or, you can simply absorb more of them, can’t you? There are more coming in every second from the original heat source. If they are delayed from exiting, are they not going to start piling up?

Reply to  Bart
March 12, 2013 5:09 pm

“Or, you can simply absorb more of them, can’t you? There are more coming in every second from the original heat source. If they are delayed from exiting, are they not going to start piling up?”
Yes but photons are bosons – they don’t “pile up”, they pass right through each other. Absorption of a photon can’t induce higher temperature, i.e., material vibration frequencies, than the photon actually is. That’s not sensical or possible, by definition. Photons don’t induce or create higher temperatures than they are in the first place, because they don’t have the energy or frequency components to do so. When they come back to their own source, they only encounter matter which is vibrating at the same frequencies which produced them. These frequencies then resonate, not increase in frequency. When two photons of the same wavelength interact, they *do not* change each other’s frequency, which would correspond to a temperature increase. Likewise, if a reflected photon spectrum comes back to its source, it only encounters a material vibration frequency spectrum of the same character. These photons, being of the same vibration frequencies of the material, can not induce a higher temperature in the material because this requires a higher frequency component inputs. This is how and why radiation obeys the 2nd Law of Thermodynamics, and why radiation inside a cavity doesn’t heat itself up, but produces a blackbody spectrum, as Planck proved along ago in his discovery of quantum mechanics. It all works perfectly together to create a sane world.
Consider “Bryan’s” comment to me which I had in one of my last posts, and understand that the system of shells being theorized here then obviously violates thermodynamics & etc. I will repeat it here:
Consider the planet to have a high metal expansion coefficient, and the shell a small one. There is a small distance between them. When the planet heats up to 470, it will expand and touch the shell. Now the shell will heat up to 470. Whereas before we couldn’t, say, create steam to drive a generator turbine, now we can (using the relevant values). You get the idea I hope. The system might cool and stop touching but then it would just heat up again and touch again. With an intrinsic source that couldn’t have create steam in the first place, with this system of shells the system can now do more work than it could have in the first place, than if the input energy was just used directly. Just by using a passive shell. Obviously that has problems of the thermodynamics type.

Reply to  Joseph E Postma
March 12, 2013 5:31 pm

Joseph E Postma says:
March 12, 2013 at 5:09 pm

Yes but photons are bosons – they don’t “pile up”, they pass right through each other. Absorption of a photon can’t induce higher temperature.

Technically correct, but most things are not at their internal temperature because they constantly radiate heat away, measure the temp on the back of you hand and see what it is. Wouldn’t reducing it’s cooling rate cause it to become warmer?
What’s the difference in the temp of your hands on a bitterly cold day with and without gloves? Are they not warmer with gloves?

rgbatduke
March 12, 2013 2:49 pm

The shell and planet would just come to the same temperature.
Now we are getting somewhere, as this is simply incorrect. The shell is just a shell. It radiates blackbody radiation both inside and outside, as it has no idea what is the inside and what is the outside — those are human assignments. Its radiation can be measured. In dynamic equilibrium, it has a larger surface area than the planet. It must lose the power P in the outward direction only. The expression for dynamical thermal equilibrium for a closed spherical surface is:
P = \epsilon \sigma T_e^4 (4 \pi R^2)
(or do you disagree with the Stefan-Boltzmann equation, in which case you have rejected basic physics and you are right, we’ll have to agree to disagree). A blackbody shell with unit emissivity being uniformly heated at a rate P placed in empty space so that energy radiated outwards is lost at integrated rate P when the shell is in equilibrium well be at temperature:
T_e = (\frac{P}{\sigma 4 \pi R^2})^{1/4}
Period. Otherwise it won’t be in detailed balance. Surely you agree?
But the planet inside the shell will not be at this temperature. First of all, its equilibrium temperature in the absence of the shell would be higher than the temperature of the shell, as it has to lose the same power but through a smaller surface. Before, it was surrounded by a perfect absorber at 3 K, so basically every outgoing photon was lost to infinity. Now, however, it is surrounded by a shell of matter only a bit cooler than it would have been without it. This shell radiates just as much power back into the cavity containing the central sphere as it radiates outward, in the limit of a very thin shell. After all, its temperature is the same (it is thin) and the inner and outer surface areas are the same.
The inner sphere is now a complete distinct problem in heat flow. Now you have a sphere of radius R_0 (say) being heated at a constant rate P surrounded by a perfect blackbody shell at radius (say) R_1 > R_0 which is in turn surrounded by outer space, effectively a 3 K perfect absorber, a photonic roach motel where photons check in but don’t check out, one way ticket.
Photons on the inside do not have a one way ticket. They are emitted by the central sphere, absorbed by the shell, and have roughly an even chance of being reradiated back inside the cavity as outside (and lost). Of the photons that are reradiated back into the cavity, some of them miss the central sphere and are absorbed again by some other part of the shell, others hit the central sphere and constitute an additional source of backradiated power that has to be lost by that sphere in equilibrium.
The rate at which the inner sphere loses energy is completely independent of whether or not it is in a cavity. It depends only on Stefan-Boltzman and hence \epsilon, \sigma, its area and its temperature. With unit emissivity it absorbs all photons incident on it, and they add to the net power it must reject to remain in dynamical equilibrium. Its temperature therefore rises, because P has gone up, but everything else is unchanged.
You actually understand this perfectly well now. If you beamed a laser at the central sphere to deliver the power P to it in the first place (and the sphere were a good conductor so it remained at a reasonably uniform surface temperature) it wouldn’t change T_e from S-B above. If you increased the laser power to 1.4P, all that would do is increases T_e — the sphere doesn’t know anything about the spectrum or origin of photons incident on its surface, it just absorbs 100% of them because its emissivity is one (it is dead, flat black). Similarly it doesn’t know or care if some of the photons delivering power to it are energy it gave off before that was absorbed by the shell and partially reradiated back to fall on the sphere once again. All it knows is that the total power it has to reject in equilibrium is now larger.
There are a number of other ways of working through the logic and the heat flow, and absolutely all of them will yield the same result — the inner, uniformly heated sphere will get warmer when it is surrounded by ANY sphere at ANY radius that is warmer than 3 K, compared to its temperature when surrounded by a 3 K perfect absorber at “infinity”.
This must be so — if you think about it — so that the second law of thermodynamics can be satisfied. The net rate of radiative heat flow between two reservoirs has to be a function of the temperature difference, all other things being equal. In particular, it has to vanish when the two reservoirs are at the same temperature, and go from hotter to cooler where either reservoir could be the hotter or cooler one. Clearly to at least a first approximation, the rate of heat flow has to be proportional to the temperature difference between the two reservoirs and has to be directed from hotter to colder.
However, both reservoirs radiate like blackbodies. There is always radiation going in both directions. The net transfer above is a question of detailed balance between the two. Neither reservoir knows what the other one is doing, it just receives the radiation it gives off and uses it as part of its dynamical heat budget, warming and cooling until the net radiation rate matches the input power and detailed balance is achieved.
Hence we can conclude that — just as is the case for the basic heat equation and heat conductivity — interpolating matter of any sort at (necessarily) intermediate temperatures between two reservoirs alters the relative rates of heat flow. You acknowledge that wrapping a coat around a heat source interpolated between that heat source and a surrounding cold reservoir warms the inside of the coat and causes the dynamic equilibrium temperature of the heat source to go up (which is why we insulate our houses and our bodies). Wrapping any sort of barrier around a heat source being cooled only via radiation to a colder reservoir causes that barrier to attain an intermediate temperature and causes the heat source’s temperature to go up to maintain the requisite level of net heat transfer.
rgb