Foreword – I’ve had this document since January 17th, and it has taken some time to get it properly reproduced here in full due to formatting issues. Some equations have to be converted to images, and I have to double check every superscript, subscript, and symbol for accuracy, then re-insert/re-format many manually since they often don’t reproduce properly in WordPress. WordPress doesn’t manage copy/paste of complex documents well. I hope that I have everything correctly reproduced, if not, please leave a note. A PDF of the original is here: UTC_Blog_Reply_Part1 This is a contentious issue, and while it would be a wonderful revelation if it were proven to be true, I personally cannot see any way it can surmount the law of conservation of energy. That view is shared by others, noted in the opening paragraph below. However, I’m providing this for the educational value it may bring to those who can take it all in and discuss it rationally, with a caution – because this issue is so contentious, I ask readers to self-moderate so that the WUWT moderation team does not have to be heavy handed. I invite you take it all in, and to come to your own conclusion. Thank you for your consideration. – Anthony
Part 1: Magnitude of the Natural ‘Greenhouse’ Effect
Ned Nikolov, Ph.D. and Karl Zeller, Ph.D.
- Introduction
Our recent paper “Unified Theory of Climate: Expanding the Concept of Atmospheric Greenhouse Effect Using Thermodynamic Principles. Implications for Predicting Future Climate Change” spurred intense discussions at WUWT and Tallbloke’s Talkshop websites. Many important questions were raised by bloggers and two online articles by Dr. Ira Glickstein (here) and Dr. Roy Spencer (here). After reading through most responses, it became clear to us that that an expanded explanation is needed. We present our reply in two separate articles that address blog debate foci as well as key aspects of the new paradigm.
Please, consider that understanding this new theory requires a shift in perception! As Albert Einstein once noted, a new paradigm cannot be grasped within the context of an existing mindset; hence, we are constrained by the episteme we are living in. In that light, our concept requires new definitions that may or may not have exact counterparts in the current Greenhouse theory. For example, it is crucial for us to introduce and use the term Atmospheric Thermal Effect (ATE) because: (a) The term Greenhouse Effect (GE) is inherently misleading due to the fact that the free atmosphere, imposing no restriction on convective cooling, does not really work as a closed greenhouse; (b) ATE accurately coveys the physical essence of the phenomenon, which is the temperature boost at the surface due to the presence of atmosphere; (c) Reasoning in terms of ATE vs. GE helps broaden the discussion beyond radiative transfer; and (d) Unlike GE, the term Atmospheric Thermal Effect implies no underlying physical mechanism(s).
We start with the undisputable fact that the atmosphere provides extra warmth to the surface of Earth compared to an airless environment such as on the Moon. This prompts two basic questions: (1) What is the magnitude of this extra warmth, i.e. the size of ATE ? and (2) How does the atmosphere produce it, i.e. what is the physical mechanism of ATE ? In this reply we address the first question, since it appears to be the crux of most people’s difficulty and needs a resolution before proceeding with the rest of the theory (see, for example, Lord Monckton’s WUWT post).
- Magnitude of Earth’s Atmospheric Thermal Effect
We maintain that in order to properly evaluate ATE one must compare Earth’s average near-surface temperature to the temperature of a spherical celestial body with no atmosphere at the same distance from the Sun. Note that, we are not presently concerned with the composition or infrared opacity of the atmosphere. Instead, we are simply trying to quantify the overall effect of our atmosphere on the surface thermal environment; hence the comparison with a similarly illuminated airless planet. We will hereafter refer to such planet as an equivalent Planetary Gray Body (PGB).
Since temperature is proportional (linearly related) to the internal kinetic energy of a system, it is theoretically perfectly justifiable to use meanglobal surface temperatures to quantify the ATE. There are two possible indices one could employ for this:
- The absolute difference between Earth’s mean temperature (Ts) and that of an equivalent PGB (Tgb), i.e. ATE = Ts – Tgb; or
- The ratio of Ts to Tgb. The latter index is particularly attractive, since it normalizes (standardizes) ATE with respect to the top-of-atmosphere (TOA) solar irradiance (So), thus enabling a comparison of ATEs among planets that orbit at various distances from the Sun and receive different amounts of solar radiation. We call this non-dimensional temperature ratio a Near-surface Thermal Enhancement (ATEn) and denote it by NTE = Ts / Tgb. In theory, therefore, NTE should be equal or greater than 1.0 (NTE ≥ 1.0). Please, note that ATEn is a measure of ATE.
It is important to point out that the current GE theory measures ATE not by temperature, but by the amount of absorbed infrared (IR) radiation. Although textbooks often mention that Earth’s surface is 18K-33K warmer than the Moon thanks to the ‘greenhouse effect’ of our atmosphere, in the scientific literature, the actual effect is measured via the amount of outgoing infrared radiation absorbed by the atmosphere (e.g. Stephens et al. 1993; Inamdar & Ramanathan 1997; Ramanathan & Inamdar 2006; Houghton 2009). It is usually calculated as a difference (occasionally a ratio) between the total average infrared flux emanating at the surface and that at the top of the atmosphere. Defined in this way, the average atmospheric GE, according to satellite observations, is between 157 and 161 W m-2 (Ramanathan & Inamdar 2006; Lin et al. 2008; Trenberth et al. 2009). In other words, the current theory uses radiative flux units instead of temperature units to quantify ATE. This approach is based on the preconceived notion that GE works by reducing the rate of surface infrared cooling to space. However, measuring a phenomenon with its presumed cause instead by its manifest effect can be a source of major confusion and error as demonstrated in our study. Hence, we claim that the proper assessment of ATE depends on an accurate estimate of the mean surface temperature of an equivalent PGB (Tgb).
- Estimating the Mean Temperature of an Equivalent Planetary Gray Body
There are two approaches to estimate Tgb – a theoretical one based on known physical relationships between temperature and radiation, and an empirical one relying on observations of the Moon as the closest natural gray body to Earth.
According to the Stefan-Boltzmann (SB) law, any physical object with a temperature (T, oK) above the absolute zero emits radiation with an intensity (I, W m-2) that is proportional to the 4th power of the object’s absolute temperature:
where ϵ is the object’s thermal emissivity/absorptivity (0 ≤ ϵ ≤ 1 ), and σ = 5.6704×10-8 W m-2 K-4 is the SB constant. A theoretical blackbody has ϵ = 1.0, while real solid objects such as rocks usually have ϵ ≈ 0.95. In principle, Eq. (1) allows for an accurate calculation of an object’s equilibrium temperature given the amount of absorbed radiation by the object, i.e.
The spatially averaged amount of solar radiation absorbed by the Earth-Atmosphere system (Sα ̅̅̅, W m-2) can be accurately computed from TOA solar irradiance (Sα ̅̅̅, W m-2) and planetary albedo (αp) as
where the TOA shortwave flux (W m-2) incident on a plane perpendicular to the solar rays. The factor ¼ serves to distribute the solar flux incident on a flat surface to a sphere. It arises from the fact that the surface area of a sphere (4πR2) is 4 times larger than the surface area of a disk (πR2) of the same radius (R). Hence, it appears logical that one could estimate Earth’s average temperature in the absence of ATE from using the SB law. i.e.
Here (TeK) is known as the effective emission temperature of Earth. Employing typical values for S0 =W m-2 and αp = 0.3 and assuming, ϵ = 1.0 Eq. (3) yields 254.6K. This is the basis for the widely quoted 255K (-18C) mean surface temperature of Earth in the absence of a ‘greenhouse effect’, i.e. if the atmosphere were missing or ‘completely transparent’ to IR radiation. This temperature is also used to define the so-called effective emission height in the troposphere (at about 5 km altitude), where the bulk of Earth’s outgoing long-wave radiation to space is assumed to emanate from. Since Earth’s mean surface temperature is 287.6K (+14.4C), the present theory estimates the size of ATE to be 287.6K – 254.6K = 33K. However, as pointed out by other studies, this approach suffers from a serious logical error. Removing the atmosphere (or even just the water vapor in it) would result in a much lower planetary albedo, since clouds are responsible for most of Earth’s shortwave reflectance. Hence, one must use a different albedo (αp) in Eq. (3) that only quantifies the actual surface reflectance. A recent analysis of Earth’s global energy budget by Trenberth et al. (2009) using satellite observations suggests αp≈ 0.12. Serendipitously, this value is quite similar to the Moon bond albedo of 0.11 (see Table 1 in our original paper), thus allowing evaluation of Earth’s ATE using our natural satellite as a suitable PGB proxy. Inserting= 0.12 in Eq. (3) produces Te = 269.6K, which translates into an ATE of only 18K (i.e. 287.6 – 269.6 = 18K).
In summary, the current GE theory employs a simple form of the SB law to estimate the magnitude of Earth’s ATE between 18K and 33K. The theory further asserts that the Moon average temperature is 250K to 255K despite the fact that using the correct lunar albedo (0.11) in Eq. (3) produces ≈270K, i.e. a15K to 20K higher temperature! Furthermore, the application of Eq. (3) to calculate the mean temperature of a sphere runs into a fundamental mathematical problem caused by Hölder’s inequality between non-linear integrals (e.g. Kuptsov 2001). What does this mean? Hölder’s inequality applies to certain non-linear functions and states that, in such functions, the use of an arithmetic average for the independent (input) variable will not produce a correct mean value of the dependent (output) variable. Hence, due to a non-linear relationship between temperature and radiative flux in the SB law (Eq. 3) and the variation of absorbed radiation with latitude on a spherical surface, one cannot correctly calculate the mean temperature of a unidirectionally illuminated planet from the amount of spatially averaged absorbed radiation defined by Eq. (2). According to Hölder’s inequality, the temperature calculated from Eq. (3) will always be significantly higher than the actual mean temperature of an airless planet. We can illustrate this effect with a simple example.
Let’s consider two points on the surface of a PGB, P1 and P2, located at the exact same latitude (say 45oN) but at opposite longitudes so that, when P1 is fully illuminated, P2 is completely shaded and vice versa (see Fig. 1). If the PGB is orbiting at the same distance from the Sun as Earth and solar rays were the only source of heat to it, then the equilibrium temperature at the illuminated point would be (assuming a solar zenith angle θ = 45o), while the temperature at the shaded point would be T2 = 0 (since it receives no radiation due to cosθ < 0). The mean temperature between the two points is then Tm = (T1 + T2)/2 = 174.8K. However, if we try using the average radiation absorbed by the two points W m-2 to calculate a mean temperature, we obtain = 234.2K. Clearly, Te is much greater than Tm (Te ≫ Tm), which is a result of Hölder’s inequality.
Figure 1. Illustration of the effect of Hölder’s inequality on calculating the mean surface temperature of an airless planet. See text for details.
The take-home lesson from the above example is that calculating the actual mean temperature of an airless planet requires explicit integration of the SB law over the planet surface. This implies first taking the 4th root of the absorbed radiative flux at each point on the surface and then averaging the resulting temperature field rather than trying to calculate a mean temperature from a spatially averaged flux as done in Eq. (3).
Thus, we need a new model that is capable of predicting Tgb more robustly than Eq. (3). To derive it, we adopt the following reasoning. The equilibrium temperature at any point on the surface of an airless planet is determined by the incident solar flux, and can be approximated (assuming uniform albedo and ignoring the small heat contributions from tidal forces and interior radioactive decay) as
where is the solar zenith angle (radian) at point , which is the angle between solar rays and the axis normal to the surface at that point (see Fig. 1). Upon substituting , the planet’s mean temperature () is thus given by the spherical integral of , i.e.
Comparing the final form of Eq. (5) with Eq. (3) shows that Tgb << Te in accordance with Hölder’s inequality. To make the above expression physically more realistic, we add a small constant Cs =0.0001325 W m-2 to So, so that when So = 0.0, Eq. (5) yields Tgb = 2.72K (the irreducible temperature of Deep Space), i.e:
In a recent analytical study, Smith (2008) argued that Eq. (5) only describes the mean temperature of a non-rotating planet and that, if axial rotation and thermal capacity of the surface are explicitly accounted for, the average temperature of an airless planet would approach the effective emission temperature. It is beyond the scope of the current article to mathematically prove the fallacy of this argument. However, we will point out that increasing the mean equilibrium temperature of a physical body always requires a net input of extra energy. Adding axial rotation to a stationary planet residing in a vacuum, where there is no friction with the external environment does not provide any additional heat energy to the planet surface. Faster rotation and/or higher thermal inertia of the ground would only facilitate a more efficient spatial distribution of the absorbed solar energy, thus increasing the uniformity of the resulting temperature field across the planet surface, but could not affect the average surface temperature. Hence, Eq. (6) correctly describe (within the assumption of albedo uniformity) the global mean temperature of any airless planet, be it rotating or non-rotating.
Inserting typical values for Earth and Moon into Eq. (6), i.e. So = 1,362 W m-2, αo = 0.11, and ϵ = 0.955, produces Tgb = 154.7K. This estimate is about 100K lower than the conventional black-body temperature derived from Eq. (3) implying that Earth’s ATE (i.e. the GE) is several times larger than currently believed! Such a result, although mathematically justified, requires independent empirical verification due to its profound implications for the current GE theory. As noted earlier, the Moon constitutes an ideal proxy PGB in terms of its location, albedo, and airless environment, against which the thermal effect of Earth’s atmosphere could be accurately assessed. Hence, we now turn our attention to the latest temperature observations of the Moon.
- NASA’s Diviner Lunar Radiometer Experiment
In June 2009, NASA launched its Lunar Reconnaissance Orbiter (LRO), which carries (among other instruments) a Radiometer called Diviner. The purpose of Diviner is to map the temperature of the Moon surface in unprecedented detail employing measurements in 7 IR channels that span wavelengths from 7.6 to 400 μm. Diviner is the first instrument designed to measure the full range of lunar surface temperatures, from the hottest to the coldest. It also includes two solar channels that measure the intensity of reflected solar radiation enabling a mapping of the lunar shortwave albedo as well (for details, see the Diviner Official Website at http://www.diviner.ucla.edu/).
Although the Diviner Experiment is still in progress, most thermal mapping of the Moon surface has been completed and data are available online. Due to time constraints of this article, we did not have a chance to analyze Diviner’s temperature data ourselves. Instead, we elected to rely on information reported by the Diviner Science Team in peer-reviewed publications and at the Diviner website.
Data obtained during the LRO commissioning phase reveal that the Moon has one of the most extreme thermal environments in the solar system. Surface temperatures at low latitudes soar to 390K (+117C) around noon while plummeting to 90-95K (-181C), i.e. almost to the boiling point of liquid oxygen, during the long lunar night (Fig. 2). Remotely sensed temperatures in the equatorial region agree very well with direct measurement conducted on the lunar surface at 26.1o N by the Apollo 15 mission in early 1970s (see Huang 2008). In the polar regions, within permanently shadowed areas of large impact craters, Diviner has measured some of the coldest temperatures ever observed on a celestial body, i.e. down to 25K-35K (-238C to -248C). It is important to note that planetary scientists have developed detailed process-based models of the surface temperatures of Moon and Mercury some 13 years ago (e.g. Vasavada et al. 1999). These models are now being successfully validated against Diviner measurements (Paige et al. 2010b; Dr. M. Siegler at UCLA, personal communication).
What is most interesting to our discussion, however, are the mean temperatures at various lunar latitudes, for these could be compared to temperatures in similar regions on Earth to evaluate the size of ATE and to verify our calculations. Figure 3 depicts typical diurnal courses of surface temperature on the Moon at four latitudes (adopted from Paige et. al 2010a).
Figure 2. Thermal maps of the Moon surface based on NASA’s Diviner infrared measurements showing daytime maximum and nighttime minimum temperature fields (Source: Diviner Web Site).
Figure 3. Typical diurnal variations of the Moon surface temperature at various latitudes. Local time is expressed in lunar hours which correspond to 1/24 of a lunar month. At 89◦ latitude, diurnal temperature variations are shown at summer and winter solstices (adopted from Paige et al. 2010a). Dashed lines indicate annual means at the lunar equator and at the poles.
Figure 4. Temperature maps of the South Pole of the Moon and Earth: (A) Daytime temperature field at peak illumination on the Moon; (B) Nighttime temperature field on the Moon; (C) Mean summer temperatures over Antarctica; (D) Mean winter temperatures over Antarctica. Numbers shown in bold on panels (C) and (D) are temperatures in oK. Panels (A) and (B) are produced by the Diviner Lunar Radiometer Experiment (Paige et al. 2010b). Antarctica maps are from Wikipedia (http://en.wikipedia.org/wiki/Antarctic_climate). Comparison of surface temperatures between Moon’s South Pole and Antarctica suggests a thermal enhancement by the Earth atmosphere (i.e. a ‘Greenhouse Effect’) of about 107K in the summer and 178K in the winter for this part of the Globe.
Figures 4A & 4B display temperature maps of the Moon South Pole during daytime peak illumination and at night (Paige et. al 2010b). Since the Moon has a small obliquity (axial tilt) of only 1.54o and a slow rotation, the average diurnal temperatures are similar to seasonal temperature means. These data along with information posted at the Diviner Science webpage indicate that mean temperature at the lunar-surface ranges from 98K (-175C) at the poles to 206K (-67C) at the equator. This encompasses pretty well our theoretical estimate of 154.7K for the Moon mean global temperature produced by Eq. (6). In the coming months, we will attempt to calculate more precisely Moon’s actual mean temperature from Diviner measurements. Meanwhile, data published by NASA planetary scientists clearly show that the value 250K-255K adopted by the current GE theory as Moon’s average global temperature is grossly exaggerated, since such high temperature means do not occur at any lunar latitude! Even the Moon equator is 44K – 49K cooler than that estimate. This value is inaccurate, because it is the result of an improper application of the SB law to a sphere while assuming the wrong albedo (see discussion in Section 2.1 above)!
Similarly, the mean global temperatures of Mercury (440K) and Mars (210K) reported on the NASA Planetary Fact Sheet are also incorrect, since they have been calculated from the same Eq. (3) used to produce the 255K temperature for the Moon. We urge the reader to verify this claim by applying Eq. (3) with data for solar irradiance (So) and bond albedo (αo) listed on the fact sheet of each planet while setting ϵ = 1. This is the reason that, in our original paper, we used 248.2K for Mercury, since that temperature was obtained from the theoretically correct Eq. (6). For Mars, we adopted means calculated from regional data of near-surface temperature and pressure retrieved by the Radio Science Team at Stanford University employing remote observations by the Mars Global Surveyor spacecraft. It is odd to say the least that the author of NASA’s Planetary Fact Sheets, Dr. David R. Williams, has chosen Eq. (3) to calculate Mars’ average surface temperature while ignoring the large body of high-quality direct measurements available for the Red Planet!?
So, what is the real magnitude of Earth’s Atmospheric Thermal Effect?
Table 1. Estimated Atmospheric Thermal Effect for equator and the poles based on observed surface temperatures on Earth and the Moon and using the lunar surface as a proxy for Earth’s theoretical gray body. Data obtained from Diviner’s Science webpage, Paige at al. (2010b), Figure 4, and Wikipedia:Oymyakon.
Figure 5. Earth’s mean annual near-surface temperature according to Wikipedia (Geographic Zones: http://en.wikipedia.org/wiki/Geographical_zone).
Table 1 shows observed mean and record-low surface temperatures at similar latitudes on Earth and on the Moon. The ATE is calculated as a difference between Earth and Moon temperatures assuming that the Moon represents a perfect PGB proxy for Earth. Figure 5 displays a global map of Earth’s mean annual surface temperatures to help the reader visually verify some of the values listed in Table 1. The results of the comparison can be summarized as follows:
The Atmospheric Thermal Effect, presently known as the natural Greenhouse Effect, varies from 93K at the equator to about 150K at the poles (the latter number represents an average between North- and South- Pole ATE mean values, i.e. (158+143)/2 =150.5. This range encompasses quite well our theoretical estimate of 133K for the Earth’s overall ATE derived from Eq. (6), i.e. 287.6K – 154.7K = 132.9K.
Of course, further analysis of the Diviner data is needed to derive a more precise estimate of Moon’s mean surface temperature and verify our model prediction. However, given the published Moon measurements, it is clear that the widely quoted value of 33K for Earth’s mean ATE (GE) is profoundly misleading and wrong!
- Conclusion
We have shown that the SB Law relating radiation intensity to temperature (Eq. 1 & 3) has been incorrectly applied in the past to predict mean surface temperatures of celestial bodies including Mars, Mercury, and the Moon. Due to Hölder’s inequality between non-linear integrals, the effective emission temperature computed from Eq. (3) is always significantly higher than the actual (arithmetic) mean temperature of an airless planet. This makes the planetary emission temperature Te produced by Eq. (3) physically incompatible with any real measured temperatures on Earth’s surface or in the atmosphere. By using a proper integration of the SB Law over a sphere, we derived a new formula (Eq. 6) for estimating the average temperature of a planetary gray body (subject to some assumptions). We then compared the Moon mean temperature predicted by this formula to recent thermal observations and detailed energy budget calculation of the lunar surface conducted by the NASA Diviner Radiometer Experiment. Results indicate that Moon’s average temperature is likely very close to the estimate produced by our Eq. (6). At the same time, Moon measurements also show that the current estimate of 255K for the lunar average surface temperature widely used in climate science is unrealistically high; hence, further demonstrating the inadequacy of Eq. (3). The main result from the Earth-Moon comparison (assuming the Moon is a perfect gray-body proxy of Earth) is that the Earth’s ATE, also known as natural Greenhouse Effect, is 3 to 7 times larger than currently assumed. In other words, the current GE theory underestimates the extra atmospheric warmth by about 100K! In terms of relative thermal enhancement, the ATE translates into NTE = 287.6/154.7 = 1.86.
This finding invites the question: How could such a huge (> 80%) thermal enhancement be the result of a handful of IR-absorbing gases that collectively amount to less than 0.5% of total atmospheric mass? We recall from our earlier discussion that, according to observations, the atmosphere only absorbs 157 – 161 W m-2 long-wave radiation from the surface. Can this small flux increase the temperature of the lower troposphere by more than 100K compared to an airless environment? The answer obviously is that the observed temperature boost near the surface cannot be possibly due to that atmospheric IR absorption! Hence, the evidence suggests that the lower troposphere contains much more kinetic energy than radiative transfer alone can account for! The thermodynamics of the atmosphere is governed by the Gas Law, which states that the internal kinetic energy and temperature of a gas mixture is also a function of pressure (among other things, of course). In the case of an isobaric process, where pressure is constant and independent of temperature such as the one operating at the Earth surface, it is the physical force of atmospheric pressure that can only fully explain the observed near-surface thermal enhancement (NTE). But that is the topic of our next paper… Stay tuned!
- References
Inamdar, A.K. and V. Ramanathan (1997) On monitoring the atmospheric greenhouse effect from space. Tellus 49B, 216-230.
Houghton, J.T. (2009). Global Warming: The Complete Briefing (4th Edition). Cambridge University Press, 456 pp.
Huang, S. (2008). Surface temperatures at the nearside of the Moon as a record of the radiation budget of Earth’s climate system. Advances in Space Research 41:1853–1860 (http://www.geo.lsa.umich.edu/~shaopeng/Huang07ASR.pdf)
Kuptsov, L. P. (2001) Hölder inequality. In: Encyclopedia of Mathematics, Hazewinkel and Michiel, Springer, ISBN 978-1556080104.
Lin, B., P. W. Stackhouse Jr., P. Minnis, B. A. Wielicki, Y. Hu, W. Sun, Tai-Fang Fan, and L. M. Hinkelman (2008). Assessment of global annual atmospheric energy balance from satellite observations. J. Geoph. Res. Vol. 113, p. D16114.
Paige, D.A., Foote, M.C., Greenhagen, B.T., Schofield, J.T., Calcutt, S., Vasavada, A.R., Preston, D.J., Taylor, F.W., Allen, C.C., Snook, K.J., Jakosky, B.M., Murray, B.C., Soderblom, L.A., Jau, B., Loring, S., Bulharowski J., Bowles, N.E., Thomas, I.R., Sullivan, M.T., Avis, C., De Jong, E.M., Hartford, W., McCleese, D.J. (2010a). The Lunar Reconnaissance Orbiter Diviner Lunar Radiometer Experiment. Space Science Reviews, Vol 150, Num 1-4, p125-16 (http://www.diviner.ucla.edu/docs/fulltext.pdf)
Paige, D.A., Siegler, M.A., Zhang, J.A., Hayne, P.O., Foote, E.J., Bennett, K.A., Vasavada, A.R., Greenhagen, B.T, Schofield, J.T., McCleese, D.J., Foote, M.C., De Jong, E.M., Bills, B.G., Hartford, W., Murray, B.C., Allen, C.C., Snook, K.J., Soderblom, L.A., Calcutt, S., Taylor, F.W., Bowles, N.E., Bandfield, J.L., Elphic, R.C., Ghent, R.R., Glotch, T.D., Wyatt, M.B., Lucey, P.G. (2010b). Diviner Lunar Radiometer Observations of Cold Traps in the Moon’s South Polar Region. Science, Vol 330, p479-482. (http://www.diviner.ucla.edu/docs/paige_2010.pdf)
Ramanathan, V. and A. Inamdar (2006). The Radiative Forcing due to Clouds and Water Vapor. In: Frontiers of Climate Modeling, J. T. Kiehl and V. Ramanthan, Editors, (Cambridge University Press 2006), pp. 119-151.
Smith, A. 2008. Proof of the atmospheric greenhouse effect. Atmos. Oceanic Phys. arXiv:0802.4324v1 [physics.ao-ph] (http://arxiv.org/PS_cache/arxiv/pdf/0802/0802.4324v1.pdf ).
Stephens, G.L., A. Slingo, and M. Webb (1993) On measuring the greenhouse effect of Earth. NATO ASI Series, Vol. 19, 395-417.
Trenberth, K.E., J.T. Fasullo, and J. Kiehl (2009). Earth’s global energy budget. BAMS, March:311-323
Vasavada, A. R., D. A. Paige and S. E. Wood (1999). Near-surface temperatures on Mercury and the Moon and the stability of polar ice deposits. Icarus 141:179–193 (http://www.gps.caltech.edu/classes/ge151/references/vasavada_et_al_1999.pdf)
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To calculate this average surface temperature, you need to consider not only the surface element with null heat capacity, but the column below, and apply Fourier’s heat conduction law with heat capacity.
This way, the temperature of a soil column around it’s one day trip is the solution of a differential equation Ti(theta, t, depth). This solution shows the heat stored below surface is responsible for the 100K on the dark side of the moon.
T can be expressed using phi and angular rotation speed of earth.
You get Ti(theta, phi, depth) to integrate over the sphere for depth=0.
gnarf says:
January 23, 2012 at 11:26 pm
To calculate this average surface temperature, you need to consider not only the surface element with null heat capacity, but the column below, and apply Fourier’s heat conduction law with heat capacity.
This way, the temperature of a soil column around it’s one day trip is the solution of a differential equation Ti(theta, t, depth). This solution shows the heat stored below surface is responsible for the 100K on the dark side of the moon.
T can be expressed using phi and angular rotation speed of earth.
You get Ti(theta, phi, depth) to integrate over the sphere for depth=0.
What you say is correct here. The question is, how much difference does it make?
I don’t think it’s going to get you back up to 255K or anywhere near it. Do you?
We have the Apollo results, from mid latitudes, which give readings over depths down to a metre or so, which should be enough.
So let us know when you’ve done the calcs. I assume you now accept that Ned’s integral for the very surface is correct and you were wrong about that?
tallbloke says: January 24, 2012 at 12:36 am
“What you say is correct here. The question is, how much difference does it make?
I don’t think it’s going to get you back up to 255K or anywhere near it.”
Yes, it does. A solid in contact with an oscillatory surface temperature has a decaying oscillation at depth, about a fairly constant (with depth) mean. And for the Moon that mean is about 255K.
Nothing is to be gained by Willis or Ned attempting to denigrate each other. Ned has some good ideas but I disagree with his conclusions, as obviously does Willis.
My summarised thoughts are that there are two broad situations in a simple model of the Earth. a) the 30% of the Earth with no clouds and b) the 70% with clouds.
a) If a packet of air containing IR absorbing gases is considered, it will exchange heat with its surroundings by evaporation/condensation, convection, conduction and radiation. The closer to the earth’s surface, the smaller the significance of radiative transfer, yet at high altitudes, radiation is the dominant mechanism. The IPCC view is that only radiative heat transfer takes place and clouds are effectively ignored.
b) For the 70% of the Earth’s surface covered by clouds, radiation from the Earth’s surface is irrelevant. Heat is transferred primarily by evaporation/condensation and convection. Cloud temperature is mainly set by the lapse rate. Heat is absorbed from the sun and lost to space mainly by radiation, from the tops of clouds. IR absorbing gases have little impact on heat transfer.
My view is that overall the impact of IR absorbing gases is far less than that claimed by IPCC but not zero as claimed by Ned.
Looking forward to any constructive criticism.
My mistake, Willis, regarding use of the word “Zenith”. Thanks for pointing that out (we can all learn from each other). Try this corrected version:
The inner (μ) limits for the integration steps leading to equation 5 run along a meridian through the N pole, i.e. from the “sunlit equator on the left of Figure 1” (theta = 0) to the point diametrally opposite that point, on the equator on the dark side (theta = pi). Thus the “μ” limits are from μ1 {= cos (0) = 1} to μ2 {= cos (pi) = -1}.
The outer (psi) limits are from 0 to 2 pi, i.e. one complete circuit around the equator, closing the hemispherical area of their integration.
So I believe my primary statement stands:
… I read them as covering the top (Northern?) hemisphere only. The assumption is that the average for the top and bottom hemispheres will be identical, and I agree with that assumption.
Are we on the same page now?
>>What you say is correct here. The question is, how much difference does it make?
I don’t think it’s going to get you back up to 255K or anywhere near it. Do you?
Yes, that’s enough to change the average surface temperature a lot.
In this article, the author calculates average temperature for a single point on moon surface, using different values for the heat capacity. He does not model the underground surface…he simply considers the surface element has the heat capacity of the entire soil column below.
From 169K with null heat capacity it goes to 247K and more. Increasing heat capacity leads to increased average temperature.
The last curve giving Taverage=247K uses a heat capacity of 5MJ/K/M2 which is lower than earth ground capacity (5MJ/K/M2 is the heat capacity of earth atmosphere in fact).
http://scienceofdoom.com/2010/06/03/lunar-madness-and-physics-basics/
So yes, introducing heat capacity in these formulae gives you a temp in the 250K range.
>>I assume you now accept that Ned’s integral for the very surface is correct and you were wrong about that?
Yes, wrote it yesterday, Sir.
>>So let us know when you’ve done the calcs.
What do you think if people who built an entire theory based on a null heat capacity do the calcs? Afer all it’s their job and they are better at maths than me as shown here.
— —
Sure. I see that, the alternate geometry. Just look at this on 12/30: http://wattsupwiththat.com/2011/12/30/feedback-about-feedbacks-and-suchlike-fooleries/#comment-848611 . Is that not your geometry? Mine too. That is the first thing I had to verify, take the opposite geometry and quickly verify a point for point integration to satisfy myself. The only thing you should find with your direct integration equation above is you are missing one more integral to account for the decreased area as the latitudes decrease toward each pole (see the third cos term in the ‘c’ code? yours would be a sine).
Still, either way, you should end up with: 2/5*(1362*(1-0.11)/(0.955*5.67e-08))^(1/4) = 154.723 on a perfect sphere or you slipped somewhere.
Anthony,
Thank you for your appended reply on my comment above:
REPLY: Read Willis latest on the front page of WUWT about equation 8 – Anthony; link:
http://wattsupwiththat.com/2012/01/22/unified-theory-of-climate-reply-to-comments/#comment-873764
If you have been following the maths issues on this thread, you will see that Willis has not demonstrated a great understanding of it here, sometimes one would think almost to the point of ego damage when he acknowledges corrections, for instance this latest link:
http://wattsupwiththat.com/2012/01/22/unified-theory-of-climate-reply-to-comments/#comment-874022
Since you asked, I had a quick look at his new article, but have no interest in it, and anyway, the point I was making is independent of the maths. It will be interesting to see how it goes, and I can just follow the reports over at Tallbloke’s, without risking breaking out in hives visiting a Willis thread.
George E. Smith; says: January 23, 2012 at 10:18 pm
please look at my referenced documents about measuring LWE IR upwards.
In both documents the night time downward LW IR is about 75% of the daytime IR.
There is no sun at night! Where is this IR coming from?
Add a cloud and there will be more re-emission of IR at the cloud level. 50 % will be returned to the earth. CO2 and H2) do not share all the same Spectra. Hence the rate of loss of radiation upwards will be less. There is ample proof that clouds keep the ground warmer at night. NOTE that they do not add energy to the night just slow its cooling.
LW IR in the arctic (North Slope of Alaska (NSA) in Barrow) there is this document :
http://www.slf.ch/ueber/mitarbeiter/homepages/marty/publications/Marty2003_IPASRCII_JGR.pdf
140W/m^2 night
150W/m^2 day
For Southern Great Plains in Oklahoma
http://www.patarnott.com/atms749/pdf/LongWaveIrradianceMeas.pdf
Day=260W/m^2
night=400W/m^2
In both these documents this LW IR is in good agreement with Modtran Models based soley on GHGs
Note this last sentence. Using theoretical models of GHGs the same values of radiation are calculated as are measured.
Does this not show proof of GHG theory?
Also see this:
Please look at the spectra shown in slide 9 of:
http://www.patarnott.com/atms749/powerpoint/ch6_GP.ppt
This shows ground and TOA spectra GHG bands mising from TOA and present in upward looking ground spectra. What is not being lost to space is actually hitting the ground and some is being absorbed.
Since this LWIR originated on the ground and was radiated upwards, but is now hitting the ground again, a pretty simple sum shows that the ground is loosing less energy and must therefore be warmer than withourt GHGs
Joel Shore: “The subsurface averages out the variations that occur at the surface.”
Then you can’t have a subsurface that averages out to 40C warmer than what the surface averages out to. Because if it did you would have an average temperature gradient that would need to be maintained by an internal heat source. And if that gradient was 40C over a few centimeters, then that would have to be one hell of an internal heat source.
Joules Verne: “The pressure is fixed.”
By what? Are you claiming that adding atmosphere would not change the pressure? Are you claiming that increasing the gravitational field would not increase the pressure? Are you claiming that more molecules in a smaller area would not capture more radiative energy than less molecules in the same area?
Fellows,
I understand that the vast majority of you are not scientists, and do not know certain facts. For example, the debate about the effect of clouds on surface temperature was settled many years ago. The net effect of clouds (averaged over night and day) on surface temperature is COOLING, not warming! For those of you, who gets confused by the often sited ‘warming effect’ of clouds at night, understand the following:
Clouds do NOT provide ‘insulation’ to the outgoing IR radiation in the sense that they act as a ‘blanket’ stopping the IR flux emitted. That’s a misconception! Clouds only increase the downward IR flux due to their higher long-wave emissivity compared to regular air. This causes the NET loss of thermal radiation by the surface to become less. In other word, the IR flux coming from the surface gets absorbed by clouds and passed on along the attitudinal temperature gradient. Clouds do NOT return or reflect IR radiation emitted from the ground! That’s a common misconception. that laymen have about LW radiative transfer. Objects of high LW emissivity/absorptivity do NOT reflect IR radiation. They absorb the IR flux coming to them with whatever original intensity, but emit a flux that’s only proportional to the 4th power of their own temperature. In order to reflect IR radiation in the true sense of the word (like a mirror reflecting sunlight), the object must have very LOW emissivity, because IR Reflectivity = 1 – IR emissivity. Clouds have high emissivity (>0.9), and hence low IR reflectivity. Materials of high IR reflectivity (that actually reflect LW radiation) are for example aluminum, polished silver, and polished brass. This is why specially processed aluminum folio has been used by NASA for over 40 years to construct high-efficiency thermal insulation for astronauts and equipment in space. It is known as ‘radiant barrier technology‘, which specifically insulates against thermal radiation losses. In other words, materials of high thermal emissivity such as water vapor and CO2 CANNOT provide thermal insulation, since they do not reflect IR radiation. Only materials of extremely low emissivity such as aluminum can do that!
JJThoms,
No one argues that the atmosphere emits a substantial flux of IR radiation towards the surface. The question is – does this flux on average cause any increase (warming) of the surface temperature? There answer is NO, because this flux gets neutralized (cancelled out) completely by the convective cooling at the surface. This can be easily proven using an energy balance model that couples convection and radiative transfer and solves simultaneously for both. The confusion comes from climate models, which do not solve for those two modes of heat exchange simultaneously!
Also, how do you explain this fact? Globally, the atmosphere emits on average 343 W m-2 of LW radiation towards the surface, while the total radiation absorbed from the Sun by the ENTIRE Earth-atmosphere system is only 238.3 W m-2, i.e. the atmosphere emits down 44% more radiation than the total amount provided by the Sun!! These are real measurements! Does this not tell us that there is MORE energy in the lower atmosphere that the Sun can account for? It does! And it raises the question where is that extra energy coming from? The answer is – from pressure! Pressure provides a thermal enhancement through its physical characteristic called FORCE. This enhancement is demonstrated in the empirical relationship we have found between the NTE factor (Ts/Tgb) and mean surface pressure across a wide range of planets in the solar system. See Eq. 7 and Fig. 5 in our original paper:
http://tallbloke.wordpress.com/2011/12/28/unified-theory-of-climate-nikolov-and-zeller/
Arguing against relationships derived from real empirical data is unscientific and silly! That’s because science is about developing theories based on actual OBSERVATIONS, not on ‘thought experiments’.
An appeal to rationality
Can somebody point at the process how ATE or GE warms the oceans? I would like to learn and understand.
Over 90% of the Earth energy budget runs through the oceans. If the oceans average temperature changes with 0.1°C we have a new ice age or a new climate optimum. And yet the great majority of climate scientists ignore the oceans when discussing earth energy budget and talk only of the solid ground and atmosphere. It is that greenhouse gase which traps energy. That 99% of the captured energy is in the oceans is no problem for them.
The oceans are opaque to downward LW IR.
It took long until people realised that the weather is run by the oceans and we need to understand such phenomenon as La Nina and El Nino to understand how weather happens. And yet the climatologists keep ignoring the oceans and make energy budgets only above them. They keep looking at the tail and wonder why is it whacking.
Any energy budget of the Earth which does not describe the oceans energy budget is doomed to fail.
Ned Nikolov says:
Every time you say this, I am going to point out that you have been shown to be absolutely wrong on this:
http://wattsupwiththat.com/2012/01/22/unified-theory-of-climate-reply-to-comments/#comment-873587
http://wattsupwiththat.com/2012/01/22/unified-theory-of-climate-reply-to-comments/#comment-873709
There is no ambiguity…You made a huge mistake here. You have not bothered to defend what you have done because there is no defense…You implicitly admitted that your way of adding in convection yields a result in contradiction to reality in your description of what happened. Admit it and come clean rather than continuing to deceive people on this point!
Tilo Reber says:
Yeah…As I noted to Robert Brown last night http://wattsupwiththat.com/2012/01/22/unified-theory-of-climate-reply-to-comments/#comment-873702 , my statement about the subsurface having the same average T^4 rather than the same average T as the surface may have been wrong…although we are still left with the empirical mystery (at least claimed) that “the average temperature on the surface is about 40-45 C lower than it is just below the surface” ( http://www.asi.org/adb/m/03/05/average-temperatures.html ).
I did notice that the thermal conductance of the lunar surface materials is a function of temperature and I think this could lead to an asymmetry whereby the temperature below the surface is not equal to the average at the surface. However, from what I have seen of these thermal conductances, I keep getting the effect going in the other direction.
Nikolov said above: “Arguing against relationships derived from real empirical data is unscientific and silly! That’s because science is about developing theories based on actual OBSERVATIONS, not on ‘thought experiments’.”
Well, one of the greatest of all, Einstein, used both observations and thought experiments with amazing results. So I’m with Willis Eschenbach – a good thought experiment can tease out limits of scientific understanding. So please try this one for size, Ned.
Imagine the Earth as it is except with no clouds. Its albedo will be lower, so it will be hotter, and your equations can show by how much. Now for the kicker, imagine that iall over the ever changing night side, and only there, a 1000 metre thick layer of cloud forms at altitude 1000 metres. Under the N-Z model, the mean temperature of the Earth will not be changed by this blanket of greenhouse clouds. But experience tells me that the night will not get so cold, and so the Earth will warm up – unless of course the clouds are radiating as much heat upwards as the ground would have through clear air (but I don’t think so, as the clouds are cooler).
It’s not that I don’t believe that the N-Z theory gives a good first order estimate of the temperature of a planet or moon, but that greenhouse gases will give a non-negligible second order effect. I don’t think it’s huge, but I’d be surprised if it wasn’t worth at least 10K on Earth.
Rich.
Ned Nikolov says:
January 24, 2012 at 8:47 am
“In order to reflect IR radiation in the true sense of the word (like a mirror reflecting sunlight), the object must have very LOW emissivity, because IR Reflectivity = 1 – IR emissivity.”
Sir, I would amend this slightly (if my heat transfer prof was right) that higher energy state objects donot absorb lower energy radiation. ie it is reflected.
Thanks for your interaction.
mkelly says:
Either your heat transfer prof was severely incompetent or (more likely) you misunderstood him.
We start with the undisputable fact that the atmosphere provides extra warmth to the surface of Earth compared to an airless environment such as on the Moon. This prompts two basic questions: (1) What is the magnitude of this extra warmth, i.e. the size of ATE ? and (2) How does the atmosphere produce it, i.e. what is the physical mechanism of ATE ? In this reply we address the first question, since it appears to be the crux of most people’s difficulty and needs a resolution before proceeding with the rest of the theory
Unfortunately N&Z used a model where they introduced an additional change, namely the assumption of negligible surface thermal capacity. Most of the large difference that they calculate results from this assumption (if they hadn’t made this assumption there would still be a discrepancy due to non-uniformity but it wouldn’t be as large), the remainder results from the radiative exchange characteristics of GHGs.
Dr Burns says:
January 24, 2012 at 1:14 am
“My view is that overall the impact of IR absorbing gases is far less than that claimed by IPCC but not zero as claimed by Ned.
Looking forward to any constructive criticism.”
Seems to me that large values are indeed being ruled out by the models themselves.
The amount of effort put into them to model backradiation as the primary means of the GHE appears to have failed. So have the efforts to minimize natural variation. Its in your face now and I assign a close to zero probability what we are currently seeing is anthropogenic in origin.
Whats left in the absence of significant investment in non-anthropogenic causes being less than catastrophic is really too small to rule out either gentle warming or gentle cooling influences. I that range of possibilities zero seems as likely as any other explicit figure.
I am not sure but there are a lot of calculations with radiation that go absolutely nowhere. Heat loss with conduction equals heat gain from conduction just as it does for radiation. It seems with either you have to postulate some unphysical backradiation or back conduction in order to get cold objects to warm warm objects.
I look to the evolution of passive solar water heating as an answer to this conundrum. If you put a black can of water out in the sun on top of a shower enclosure you can get warm showers in the evening but not in the morning. Early solar water heaters put the cans in greenhouses and by the restrictions on convection got better performance to the point that patents were awarded I think in the late 19th century. The final evolution of the totally passive water heating system was to greenhouse the collector system and put them below the storage system to which insulation was added. Actually a potentially ideal analogy to our earth surface and poorly emissive atmosphere heat storage system where convection is the single imbalanced heat exchange medium brought to us 100% by gravity.
Turn off gravity and the black painted can would work as well as the older patented systems and both of those would work a lot better than the final evolution of the system with collectors placed remote to and below the storage system (though a small pump would fix that specific problem, it would be the least of our problems with either the system or anything else).
Climate models represent a huge waste of tax payer dollars. They are completely incompetent and probably never will be useful until we actually understand better how the surface warms, which will probably end up mostly entailing knowing more about solar variability. Before the models will be useful we need to gain some confidence we know the cause and have some idea of what drives the cause.
What needs to be done are some more far more practical experiments with say a solar gas heating system built on the principles of the passive solar water heating system to demonstrate how the system actually operates with various levels of emissivity using say shiny radiators above and below the insulated storage tank to mimic various combinations of surface, atmospheric and cloud emissivities. Anybody who has a two story house knows a little about it and heating contractors building forced air systems know a bit more. One detect it in a single floor home but putting thermometers at various levels in a room. A lot of work is put into design efficiency to not waste heat from convection.
Also, there actually is some work thats been done on that in the passive solar industry with underground and greenhouse convection driven systems using ordinary air.
Put the whole apparatus in a large climate controlled room and apply a variable energy source from above that can mimic the diurnal cycle at various latitudes and seasons. Kind of like what the GCR advocates were directed to do and Cloud 9 came into being.
Joel Shore @ur momisugly January 24, 10:47 am
In your rant against Ned Nikolov, concerning the GHE, you wrote in part:
Perhaps you should read more carefully what Ned wrote. I understand it to mean that he accepts that there is what is called a greenhouse effect, but that in context, it is neutralized by other effects. In the case of the Earth, and in the context of his hypothesis, even Trenberth says so in his 2009 Earth’s Energy Budget cartoon, giving these numbers for heat loss from the surface (W/m^2):
• Evapotranspiration = 80
• Thermals = 17
• Radiative absorbed (GHE) = 23 (14%)
• Radiative direct to space = 40
• Disappeared = 1
Yet again you have lowered your credibility, maybe because you are too ready to criticise, and lack in comprehension of what has been said.
Bob Ferney-Jones says:
No…It is you who have failed to read and comprehend what I have written on this subject in many previous comments, some even linked to in the comment of mine that you quote. You have also failed to read and comprehend Nikolov and Zeller’s own paper where they say: “Equation (4) dramatically alters the solution to Eq. (3) by collapsing the difference between Ts, Ta and Te and virtually erasing the GHE (Fig. 3).” In other words, they have added convection into the model in a way that drives the temperature distribution in the vertical to be isothermal.
In case you don’t know, the troposphere actually has a significant lapse rate in the vertical, the reason being that convection can only drive the temperature distribution down as far as the adiabatic lapse rate because beyond that the atmosphere is stable and convection is suppressed. (And, as Nick Stokes has pointed out, to the extent that some forced motions cause a “heat pump” effect, this effect actually can drive the lapse rate back up to a steeper value if it is below the adiabatic lapse rate.)
Yes, Trenberth et al. acknowledge a role for convection and, yes, convection reduces the radiative greenhouse effect from the magnitude it would have if convection were not present and lapse rates steeper than the adiabatic lapse rate were stable. (As I recall, a purely radiative calculation gives a greenhouse effect about twice as large as the value once convection in included.) ****However, convection can only partially cancel the radiative greenhouse effect precisely because convection cannot drive the lapse rate all the way down to zero, i.e., an isothermal distribution with height.**** Read that last sentence several times until you understand it.
In fact, it is you (and Nikolov and Zeller) who have lowered your credibility by showing your lack in comprehension of what has been said.
I had a go at the puzzle of the airless planet mean temperature using a simple numerical simulation model to figure out the temperatures on the surface as it rotated and re-radiated heat and conducted it into the ground. It was a bit rough and ready, but here’s my results. First the changing temperatures throughout the day:
And then the mean temperature of the planet over the day:
247 degrees K.
>>Ned Nikolov says: January 24, 2012 at 8:47 am
I understand that the vast majority of you are not scientists, and do not know certain facts. For example, the debate about the effect of clouds on surface temperature was settled many years ago. The net effect of clouds (averaged over night and day) on surface temperature is COOLING, not warming! For those of you, who gets confused by the often sited ‘warming effect’ of clouds at night, understand the following.
—————–—————————————————–
Ned, it is you who is confused here. We all know the overall net effect of clouds is cooling, but we are not talking about net effect here.
The reason we are talking about clouds ONLY at night, is because these night clouds PROVE that the Greenouse Effect is real (since you do not seem to believe in it). Forget the day. At night, clouds will always make the surface warmer, because of their absorption and reemision of LW. This is a known meteorological effect, look it up.
Thus a LW absorber and emitter will reduce the cooling of the surface at night. Fact.
Ok, so during the day, a LW absorber and emitter will similarly reduce the cooling of the surface. And if the incomming daytime SW radiation remains constant, the daytime effect will be a warmer surface temperature than if there was no LW absorber and emitter sitting above it. Thus gasses that provide this ‘service’, like H2O and CO2, will make the surface warmer than if they were not present.
Perhaps we need a name for this effect. I know, let’s call it the Greenhouse Effect.
.