Foreword – I’ve had this document since January 17th, and it has taken some time to get it properly reproduced here in full due to formatting issues. Some equations have to be converted to images, and I have to double check every superscript, subscript, and symbol for accuracy, then re-insert/re-format many manually since they often don’t reproduce properly in WordPress. WordPress doesn’t manage copy/paste of complex documents well. I hope that I have everything correctly reproduced, if not, please leave a note. A PDF of the original is here: UTC_Blog_Reply_Part1 This is a contentious issue, and while it would be a wonderful revelation if it were proven to be true, I personally cannot see any way it can surmount the law of conservation of energy. That view is shared by others, noted in the opening paragraph below. However, I’m providing this for the educational value it may bring to those who can take it all in and discuss it rationally, with a caution – because this issue is so contentious, I ask readers to self-moderate so that the WUWT moderation team does not have to be heavy handed. I invite you take it all in, and to come to your own conclusion. Thank you for your consideration. – Anthony
Part 1: Magnitude of the Natural ‘Greenhouse’ Effect
Ned Nikolov, Ph.D. and Karl Zeller, Ph.D.
- Introduction
Our recent paper “Unified Theory of Climate: Expanding the Concept of Atmospheric Greenhouse Effect Using Thermodynamic Principles. Implications for Predicting Future Climate Change” spurred intense discussions at WUWT and Tallbloke’s Talkshop websites. Many important questions were raised by bloggers and two online articles by Dr. Ira Glickstein (here) and Dr. Roy Spencer (here). After reading through most responses, it became clear to us that that an expanded explanation is needed. We present our reply in two separate articles that address blog debate foci as well as key aspects of the new paradigm.
Please, consider that understanding this new theory requires a shift in perception! As Albert Einstein once noted, a new paradigm cannot be grasped within the context of an existing mindset; hence, we are constrained by the episteme we are living in. In that light, our concept requires new definitions that may or may not have exact counterparts in the current Greenhouse theory. For example, it is crucial for us to introduce and use the term Atmospheric Thermal Effect (ATE) because: (a) The term Greenhouse Effect (GE) is inherently misleading due to the fact that the free atmosphere, imposing no restriction on convective cooling, does not really work as a closed greenhouse; (b) ATE accurately coveys the physical essence of the phenomenon, which is the temperature boost at the surface due to the presence of atmosphere; (c) Reasoning in terms of ATE vs. GE helps broaden the discussion beyond radiative transfer; and (d) Unlike GE, the term Atmospheric Thermal Effect implies no underlying physical mechanism(s).
We start with the undisputable fact that the atmosphere provides extra warmth to the surface of Earth compared to an airless environment such as on the Moon. This prompts two basic questions: (1) What is the magnitude of this extra warmth, i.e. the size of ATE ? and (2) How does the atmosphere produce it, i.e. what is the physical mechanism of ATE ? In this reply we address the first question, since it appears to be the crux of most people’s difficulty and needs a resolution before proceeding with the rest of the theory (see, for example, Lord Monckton’s WUWT post).
- Magnitude of Earth’s Atmospheric Thermal Effect
We maintain that in order to properly evaluate ATE one must compare Earth’s average near-surface temperature to the temperature of a spherical celestial body with no atmosphere at the same distance from the Sun. Note that, we are not presently concerned with the composition or infrared opacity of the atmosphere. Instead, we are simply trying to quantify the overall effect of our atmosphere on the surface thermal environment; hence the comparison with a similarly illuminated airless planet. We will hereafter refer to such planet as an equivalent Planetary Gray Body (PGB).
Since temperature is proportional (linearly related) to the internal kinetic energy of a system, it is theoretically perfectly justifiable to use meanglobal surface temperatures to quantify the ATE. There are two possible indices one could employ for this:
- The absolute difference between Earth’s mean temperature (Ts) and that of an equivalent PGB (Tgb), i.e. ATE = Ts – Tgb; or
- The ratio of Ts to Tgb. The latter index is particularly attractive, since it normalizes (standardizes) ATE with respect to the top-of-atmosphere (TOA) solar irradiance (So), thus enabling a comparison of ATEs among planets that orbit at various distances from the Sun and receive different amounts of solar radiation. We call this non-dimensional temperature ratio a Near-surface Thermal Enhancement (ATEn) and denote it by NTE = Ts / Tgb. In theory, therefore, NTE should be equal or greater than 1.0 (NTE ≥ 1.0). Please, note that ATEn is a measure of ATE.
It is important to point out that the current GE theory measures ATE not by temperature, but by the amount of absorbed infrared (IR) radiation. Although textbooks often mention that Earth’s surface is 18K-33K warmer than the Moon thanks to the ‘greenhouse effect’ of our atmosphere, in the scientific literature, the actual effect is measured via the amount of outgoing infrared radiation absorbed by the atmosphere (e.g. Stephens et al. 1993; Inamdar & Ramanathan 1997; Ramanathan & Inamdar 2006; Houghton 2009). It is usually calculated as a difference (occasionally a ratio) between the total average infrared flux emanating at the surface and that at the top of the atmosphere. Defined in this way, the average atmospheric GE, according to satellite observations, is between 157 and 161 W m-2 (Ramanathan & Inamdar 2006; Lin et al. 2008; Trenberth et al. 2009). In other words, the current theory uses radiative flux units instead of temperature units to quantify ATE. This approach is based on the preconceived notion that GE works by reducing the rate of surface infrared cooling to space. However, measuring a phenomenon with its presumed cause instead by its manifest effect can be a source of major confusion and error as demonstrated in our study. Hence, we claim that the proper assessment of ATE depends on an accurate estimate of the mean surface temperature of an equivalent PGB (Tgb).
- Estimating the Mean Temperature of an Equivalent Planetary Gray Body
There are two approaches to estimate Tgb – a theoretical one based on known physical relationships between temperature and radiation, and an empirical one relying on observations of the Moon as the closest natural gray body to Earth.
According to the Stefan-Boltzmann (SB) law, any physical object with a temperature (T, oK) above the absolute zero emits radiation with an intensity (I, W m-2) that is proportional to the 4th power of the object’s absolute temperature:
where ϵ is the object’s thermal emissivity/absorptivity (0 ≤ ϵ ≤ 1 ), and σ = 5.6704×10-8 W m-2 K-4 is the SB constant. A theoretical blackbody has ϵ = 1.0, while real solid objects such as rocks usually have ϵ ≈ 0.95. In principle, Eq. (1) allows for an accurate calculation of an object’s equilibrium temperature given the amount of absorbed radiation by the object, i.e.
The spatially averaged amount of solar radiation absorbed by the Earth-Atmosphere system (Sα ̅̅̅, W m-2) can be accurately computed from TOA solar irradiance (Sα ̅̅̅, W m-2) and planetary albedo (αp) as
where the TOA shortwave flux (W m-2) incident on a plane perpendicular to the solar rays. The factor ¼ serves to distribute the solar flux incident on a flat surface to a sphere. It arises from the fact that the surface area of a sphere (4πR2) is 4 times larger than the surface area of a disk (πR2) of the same radius (R). Hence, it appears logical that one could estimate Earth’s average temperature in the absence of ATE from using the SB law. i.e.
Here (TeK) is known as the effective emission temperature of Earth. Employing typical values for S0 =W m-2 and αp = 0.3 and assuming, ϵ = 1.0 Eq. (3) yields 254.6K. This is the basis for the widely quoted 255K (-18C) mean surface temperature of Earth in the absence of a ‘greenhouse effect’, i.e. if the atmosphere were missing or ‘completely transparent’ to IR radiation. This temperature is also used to define the so-called effective emission height in the troposphere (at about 5 km altitude), where the bulk of Earth’s outgoing long-wave radiation to space is assumed to emanate from. Since Earth’s mean surface temperature is 287.6K (+14.4C), the present theory estimates the size of ATE to be 287.6K – 254.6K = 33K. However, as pointed out by other studies, this approach suffers from a serious logical error. Removing the atmosphere (or even just the water vapor in it) would result in a much lower planetary albedo, since clouds are responsible for most of Earth’s shortwave reflectance. Hence, one must use a different albedo (αp) in Eq. (3) that only quantifies the actual surface reflectance. A recent analysis of Earth’s global energy budget by Trenberth et al. (2009) using satellite observations suggests αp≈ 0.12. Serendipitously, this value is quite similar to the Moon bond albedo of 0.11 (see Table 1 in our original paper), thus allowing evaluation of Earth’s ATE using our natural satellite as a suitable PGB proxy. Inserting= 0.12 in Eq. (3) produces Te = 269.6K, which translates into an ATE of only 18K (i.e. 287.6 – 269.6 = 18K).
In summary, the current GE theory employs a simple form of the SB law to estimate the magnitude of Earth’s ATE between 18K and 33K. The theory further asserts that the Moon average temperature is 250K to 255K despite the fact that using the correct lunar albedo (0.11) in Eq. (3) produces ≈270K, i.e. a15K to 20K higher temperature! Furthermore, the application of Eq. (3) to calculate the mean temperature of a sphere runs into a fundamental mathematical problem caused by Hölder’s inequality between non-linear integrals (e.g. Kuptsov 2001). What does this mean? Hölder’s inequality applies to certain non-linear functions and states that, in such functions, the use of an arithmetic average for the independent (input) variable will not produce a correct mean value of the dependent (output) variable. Hence, due to a non-linear relationship between temperature and radiative flux in the SB law (Eq. 3) and the variation of absorbed radiation with latitude on a spherical surface, one cannot correctly calculate the mean temperature of a unidirectionally illuminated planet from the amount of spatially averaged absorbed radiation defined by Eq. (2). According to Hölder’s inequality, the temperature calculated from Eq. (3) will always be significantly higher than the actual mean temperature of an airless planet. We can illustrate this effect with a simple example.
Let’s consider two points on the surface of a PGB, P1 and P2, located at the exact same latitude (say 45oN) but at opposite longitudes so that, when P1 is fully illuminated, P2 is completely shaded and vice versa (see Fig. 1). If the PGB is orbiting at the same distance from the Sun as Earth and solar rays were the only source of heat to it, then the equilibrium temperature at the illuminated point would be (assuming a solar zenith angle θ = 45o), while the temperature at the shaded point would be T2 = 0 (since it receives no radiation due to cosθ < 0). The mean temperature between the two points is then Tm = (T1 + T2)/2 = 174.8K. However, if we try using the average radiation absorbed by the two points W m-2 to calculate a mean temperature, we obtain = 234.2K. Clearly, Te is much greater than Tm (Te ≫ Tm), which is a result of Hölder’s inequality.
Figure 1. Illustration of the effect of Hölder’s inequality on calculating the mean surface temperature of an airless planet. See text for details.
The take-home lesson from the above example is that calculating the actual mean temperature of an airless planet requires explicit integration of the SB law over the planet surface. This implies first taking the 4th root of the absorbed radiative flux at each point on the surface and then averaging the resulting temperature field rather than trying to calculate a mean temperature from a spatially averaged flux as done in Eq. (3).
Thus, we need a new model that is capable of predicting Tgb more robustly than Eq. (3). To derive it, we adopt the following reasoning. The equilibrium temperature at any point on the surface of an airless planet is determined by the incident solar flux, and can be approximated (assuming uniform albedo and ignoring the small heat contributions from tidal forces and interior radioactive decay) as
where is the solar zenith angle (radian) at point , which is the angle between solar rays and the axis normal to the surface at that point (see Fig. 1). Upon substituting , the planet’s mean temperature () is thus given by the spherical integral of , i.e.
Comparing the final form of Eq. (5) with Eq. (3) shows that Tgb << Te in accordance with Hölder’s inequality. To make the above expression physically more realistic, we add a small constant Cs =0.0001325 W m-2 to So, so that when So = 0.0, Eq. (5) yields Tgb = 2.72K (the irreducible temperature of Deep Space), i.e:
In a recent analytical study, Smith (2008) argued that Eq. (5) only describes the mean temperature of a non-rotating planet and that, if axial rotation and thermal capacity of the surface are explicitly accounted for, the average temperature of an airless planet would approach the effective emission temperature. It is beyond the scope of the current article to mathematically prove the fallacy of this argument. However, we will point out that increasing the mean equilibrium temperature of a physical body always requires a net input of extra energy. Adding axial rotation to a stationary planet residing in a vacuum, where there is no friction with the external environment does not provide any additional heat energy to the planet surface. Faster rotation and/or higher thermal inertia of the ground would only facilitate a more efficient spatial distribution of the absorbed solar energy, thus increasing the uniformity of the resulting temperature field across the planet surface, but could not affect the average surface temperature. Hence, Eq. (6) correctly describe (within the assumption of albedo uniformity) the global mean temperature of any airless planet, be it rotating or non-rotating.
Inserting typical values for Earth and Moon into Eq. (6), i.e. So = 1,362 W m-2, αo = 0.11, and ϵ = 0.955, produces Tgb = 154.7K. This estimate is about 100K lower than the conventional black-body temperature derived from Eq. (3) implying that Earth’s ATE (i.e. the GE) is several times larger than currently believed! Such a result, although mathematically justified, requires independent empirical verification due to its profound implications for the current GE theory. As noted earlier, the Moon constitutes an ideal proxy PGB in terms of its location, albedo, and airless environment, against which the thermal effect of Earth’s atmosphere could be accurately assessed. Hence, we now turn our attention to the latest temperature observations of the Moon.
- NASA’s Diviner Lunar Radiometer Experiment
In June 2009, NASA launched its Lunar Reconnaissance Orbiter (LRO), which carries (among other instruments) a Radiometer called Diviner. The purpose of Diviner is to map the temperature of the Moon surface in unprecedented detail employing measurements in 7 IR channels that span wavelengths from 7.6 to 400 μm. Diviner is the first instrument designed to measure the full range of lunar surface temperatures, from the hottest to the coldest. It also includes two solar channels that measure the intensity of reflected solar radiation enabling a mapping of the lunar shortwave albedo as well (for details, see the Diviner Official Website at http://www.diviner.ucla.edu/).
Although the Diviner Experiment is still in progress, most thermal mapping of the Moon surface has been completed and data are available online. Due to time constraints of this article, we did not have a chance to analyze Diviner’s temperature data ourselves. Instead, we elected to rely on information reported by the Diviner Science Team in peer-reviewed publications and at the Diviner website.
Data obtained during the LRO commissioning phase reveal that the Moon has one of the most extreme thermal environments in the solar system. Surface temperatures at low latitudes soar to 390K (+117C) around noon while plummeting to 90-95K (-181C), i.e. almost to the boiling point of liquid oxygen, during the long lunar night (Fig. 2). Remotely sensed temperatures in the equatorial region agree very well with direct measurement conducted on the lunar surface at 26.1o N by the Apollo 15 mission in early 1970s (see Huang 2008). In the polar regions, within permanently shadowed areas of large impact craters, Diviner has measured some of the coldest temperatures ever observed on a celestial body, i.e. down to 25K-35K (-238C to -248C). It is important to note that planetary scientists have developed detailed process-based models of the surface temperatures of Moon and Mercury some 13 years ago (e.g. Vasavada et al. 1999). These models are now being successfully validated against Diviner measurements (Paige et al. 2010b; Dr. M. Siegler at UCLA, personal communication).
What is most interesting to our discussion, however, are the mean temperatures at various lunar latitudes, for these could be compared to temperatures in similar regions on Earth to evaluate the size of ATE and to verify our calculations. Figure 3 depicts typical diurnal courses of surface temperature on the Moon at four latitudes (adopted from Paige et. al 2010a).
Figure 2. Thermal maps of the Moon surface based on NASA’s Diviner infrared measurements showing daytime maximum and nighttime minimum temperature fields (Source: Diviner Web Site).
Figure 3. Typical diurnal variations of the Moon surface temperature at various latitudes. Local time is expressed in lunar hours which correspond to 1/24 of a lunar month. At 89◦ latitude, diurnal temperature variations are shown at summer and winter solstices (adopted from Paige et al. 2010a). Dashed lines indicate annual means at the lunar equator and at the poles.
Figure 4. Temperature maps of the South Pole of the Moon and Earth: (A) Daytime temperature field at peak illumination on the Moon; (B) Nighttime temperature field on the Moon; (C) Mean summer temperatures over Antarctica; (D) Mean winter temperatures over Antarctica. Numbers shown in bold on panels (C) and (D) are temperatures in oK. Panels (A) and (B) are produced by the Diviner Lunar Radiometer Experiment (Paige et al. 2010b). Antarctica maps are from Wikipedia (http://en.wikipedia.org/wiki/Antarctic_climate). Comparison of surface temperatures between Moon’s South Pole and Antarctica suggests a thermal enhancement by the Earth atmosphere (i.e. a ‘Greenhouse Effect’) of about 107K in the summer and 178K in the winter for this part of the Globe.
Figures 4A & 4B display temperature maps of the Moon South Pole during daytime peak illumination and at night (Paige et. al 2010b). Since the Moon has a small obliquity (axial tilt) of only 1.54o and a slow rotation, the average diurnal temperatures are similar to seasonal temperature means. These data along with information posted at the Diviner Science webpage indicate that mean temperature at the lunar-surface ranges from 98K (-175C) at the poles to 206K (-67C) at the equator. This encompasses pretty well our theoretical estimate of 154.7K for the Moon mean global temperature produced by Eq. (6). In the coming months, we will attempt to calculate more precisely Moon’s actual mean temperature from Diviner measurements. Meanwhile, data published by NASA planetary scientists clearly show that the value 250K-255K adopted by the current GE theory as Moon’s average global temperature is grossly exaggerated, since such high temperature means do not occur at any lunar latitude! Even the Moon equator is 44K – 49K cooler than that estimate. This value is inaccurate, because it is the result of an improper application of the SB law to a sphere while assuming the wrong albedo (see discussion in Section 2.1 above)!
Similarly, the mean global temperatures of Mercury (440K) and Mars (210K) reported on the NASA Planetary Fact Sheet are also incorrect, since they have been calculated from the same Eq. (3) used to produce the 255K temperature for the Moon. We urge the reader to verify this claim by applying Eq. (3) with data for solar irradiance (So) and bond albedo (αo) listed on the fact sheet of each planet while setting ϵ = 1. This is the reason that, in our original paper, we used 248.2K for Mercury, since that temperature was obtained from the theoretically correct Eq. (6). For Mars, we adopted means calculated from regional data of near-surface temperature and pressure retrieved by the Radio Science Team at Stanford University employing remote observations by the Mars Global Surveyor spacecraft. It is odd to say the least that the author of NASA’s Planetary Fact Sheets, Dr. David R. Williams, has chosen Eq. (3) to calculate Mars’ average surface temperature while ignoring the large body of high-quality direct measurements available for the Red Planet!?
So, what is the real magnitude of Earth’s Atmospheric Thermal Effect?
Table 1. Estimated Atmospheric Thermal Effect for equator and the poles based on observed surface temperatures on Earth and the Moon and using the lunar surface as a proxy for Earth’s theoretical gray body. Data obtained from Diviner’s Science webpage, Paige at al. (2010b), Figure 4, and Wikipedia:Oymyakon.
Figure 5. Earth’s mean annual near-surface temperature according to Wikipedia (Geographic Zones: http://en.wikipedia.org/wiki/Geographical_zone).
Table 1 shows observed mean and record-low surface temperatures at similar latitudes on Earth and on the Moon. The ATE is calculated as a difference between Earth and Moon temperatures assuming that the Moon represents a perfect PGB proxy for Earth. Figure 5 displays a global map of Earth’s mean annual surface temperatures to help the reader visually verify some of the values listed in Table 1. The results of the comparison can be summarized as follows:
The Atmospheric Thermal Effect, presently known as the natural Greenhouse Effect, varies from 93K at the equator to about 150K at the poles (the latter number represents an average between North- and South- Pole ATE mean values, i.e. (158+143)/2 =150.5. This range encompasses quite well our theoretical estimate of 133K for the Earth’s overall ATE derived from Eq. (6), i.e. 287.6K – 154.7K = 132.9K.
Of course, further analysis of the Diviner data is needed to derive a more precise estimate of Moon’s mean surface temperature and verify our model prediction. However, given the published Moon measurements, it is clear that the widely quoted value of 33K for Earth’s mean ATE (GE) is profoundly misleading and wrong!
- Conclusion
We have shown that the SB Law relating radiation intensity to temperature (Eq. 1 & 3) has been incorrectly applied in the past to predict mean surface temperatures of celestial bodies including Mars, Mercury, and the Moon. Due to Hölder’s inequality between non-linear integrals, the effective emission temperature computed from Eq. (3) is always significantly higher than the actual (arithmetic) mean temperature of an airless planet. This makes the planetary emission temperature Te produced by Eq. (3) physically incompatible with any real measured temperatures on Earth’s surface or in the atmosphere. By using a proper integration of the SB Law over a sphere, we derived a new formula (Eq. 6) for estimating the average temperature of a planetary gray body (subject to some assumptions). We then compared the Moon mean temperature predicted by this formula to recent thermal observations and detailed energy budget calculation of the lunar surface conducted by the NASA Diviner Radiometer Experiment. Results indicate that Moon’s average temperature is likely very close to the estimate produced by our Eq. (6). At the same time, Moon measurements also show that the current estimate of 255K for the lunar average surface temperature widely used in climate science is unrealistically high; hence, further demonstrating the inadequacy of Eq. (3). The main result from the Earth-Moon comparison (assuming the Moon is a perfect gray-body proxy of Earth) is that the Earth’s ATE, also known as natural Greenhouse Effect, is 3 to 7 times larger than currently assumed. In other words, the current GE theory underestimates the extra atmospheric warmth by about 100K! In terms of relative thermal enhancement, the ATE translates into NTE = 287.6/154.7 = 1.86.
This finding invites the question: How could such a huge (> 80%) thermal enhancement be the result of a handful of IR-absorbing gases that collectively amount to less than 0.5% of total atmospheric mass? We recall from our earlier discussion that, according to observations, the atmosphere only absorbs 157 – 161 W m-2 long-wave radiation from the surface. Can this small flux increase the temperature of the lower troposphere by more than 100K compared to an airless environment? The answer obviously is that the observed temperature boost near the surface cannot be possibly due to that atmospheric IR absorption! Hence, the evidence suggests that the lower troposphere contains much more kinetic energy than radiative transfer alone can account for! The thermodynamics of the atmosphere is governed by the Gas Law, which states that the internal kinetic energy and temperature of a gas mixture is also a function of pressure (among other things, of course). In the case of an isobaric process, where pressure is constant and independent of temperature such as the one operating at the Earth surface, it is the physical force of atmospheric pressure that can only fully explain the observed near-surface thermal enhancement (NTE). But that is the topic of our next paper… Stay tuned!
- References
Inamdar, A.K. and V. Ramanathan (1997) On monitoring the atmospheric greenhouse effect from space. Tellus 49B, 216-230.
Houghton, J.T. (2009). Global Warming: The Complete Briefing (4th Edition). Cambridge University Press, 456 pp.
Huang, S. (2008). Surface temperatures at the nearside of the Moon as a record of the radiation budget of Earth’s climate system. Advances in Space Research 41:1853–1860 (http://www.geo.lsa.umich.edu/~shaopeng/Huang07ASR.pdf)
Kuptsov, L. P. (2001) Hölder inequality. In: Encyclopedia of Mathematics, Hazewinkel and Michiel, Springer, ISBN 978-1556080104.
Lin, B., P. W. Stackhouse Jr., P. Minnis, B. A. Wielicki, Y. Hu, W. Sun, Tai-Fang Fan, and L. M. Hinkelman (2008). Assessment of global annual atmospheric energy balance from satellite observations. J. Geoph. Res. Vol. 113, p. D16114.
Paige, D.A., Foote, M.C., Greenhagen, B.T., Schofield, J.T., Calcutt, S., Vasavada, A.R., Preston, D.J., Taylor, F.W., Allen, C.C., Snook, K.J., Jakosky, B.M., Murray, B.C., Soderblom, L.A., Jau, B., Loring, S., Bulharowski J., Bowles, N.E., Thomas, I.R., Sullivan, M.T., Avis, C., De Jong, E.M., Hartford, W., McCleese, D.J. (2010a). The Lunar Reconnaissance Orbiter Diviner Lunar Radiometer Experiment. Space Science Reviews, Vol 150, Num 1-4, p125-16 (http://www.diviner.ucla.edu/docs/fulltext.pdf)
Paige, D.A., Siegler, M.A., Zhang, J.A., Hayne, P.O., Foote, E.J., Bennett, K.A., Vasavada, A.R., Greenhagen, B.T, Schofield, J.T., McCleese, D.J., Foote, M.C., De Jong, E.M., Bills, B.G., Hartford, W., Murray, B.C., Allen, C.C., Snook, K.J., Soderblom, L.A., Calcutt, S., Taylor, F.W., Bowles, N.E., Bandfield, J.L., Elphic, R.C., Ghent, R.R., Glotch, T.D., Wyatt, M.B., Lucey, P.G. (2010b). Diviner Lunar Radiometer Observations of Cold Traps in the Moon’s South Polar Region. Science, Vol 330, p479-482. (http://www.diviner.ucla.edu/docs/paige_2010.pdf)
Ramanathan, V. and A. Inamdar (2006). The Radiative Forcing due to Clouds and Water Vapor. In: Frontiers of Climate Modeling, J. T. Kiehl and V. Ramanthan, Editors, (Cambridge University Press 2006), pp. 119-151.
Smith, A. 2008. Proof of the atmospheric greenhouse effect. Atmos. Oceanic Phys. arXiv:0802.4324v1 [physics.ao-ph] (http://arxiv.org/PS_cache/arxiv/pdf/0802/0802.4324v1.pdf ).
Stephens, G.L., A. Slingo, and M. Webb (1993) On measuring the greenhouse effect of Earth. NATO ASI Series, Vol. 19, 395-417.
Trenberth, K.E., J.T. Fasullo, and J. Kiehl (2009). Earth’s global energy budget. BAMS, March:311-323
Vasavada, A. R., D. A. Paige and S. E. Wood (1999). Near-surface temperatures on Mercury and the Moon and the stability of polar ice deposits. Icarus 141:179–193 (http://www.gps.caltech.edu/classes/ge151/references/vasavada_et_al_1999.pdf)
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tallbloke
Here’s the bottom line, first principle from which you must start to understand this.
-a gravity field cannot maintain an energy gradient at equilibrium
The presense of an energy gradient means work can be extracted from it and if gravity restores the gradient you have then just violated conservation of energy and have an infinite energy source because in the process of extracting useful work from the gradient you do nothing to diminish the force of gravity.
This is the knee-jerk reaction to this theory from anyone with an intuitive understanding of thermodynamic principles. They know there cannot be an energy gradient maintained by gravity in equilibrium. That’s just SO perpetual motion. What most people cannot do, including Duke physicist Robert Brown, is describe how the energy is equally distributed. Brown says the system must be isothermal at equilibrium. That’s his gut talking but this will not happen in a gravity induced pressure gradient. What happens in the gravitational field with a compressible gas. Kinetic energy density is concentrated in the lower regions while gravitational potential energy is concentrated in the higher regions at equilbrium. Willis actually described this to Brown then let Brown somehow convince him he wasn’t right. Willis shouldn’t have rolled over.
In the end there is NO mechanism introduced by gravity to increase the total energy capacity of the column nor to give any horizontal layer a greater capacity than any other. Any gain in kinetic energy capacity in a lower layer at equilibrium has an opposing higher gravitational energy capacity in a higher layer resulting in an isoenergetic system at equilibrium. This requirement for isoenergetic system at equilibrium is not negotiable as it would be a blatant violation of first principles in thermodynamics and, quite frankly, the kind of thing upon which crank science is built.
Mark my words, this IS crank science and it WILL NOT get anywhere even near as much traction as P&F cold fusion. It’s much easier to show in this case to show what the authors propose is simply not possible.
BenAW says:
January 22, 2012 at 4:44 pm
“I made this comment @Tallblokes
Imo it is absolutely WRONG to use the blackbody approach for waterplanet earth.
It’s base temperature is 275K, not 0K.
Reason of course being the oceans, and no, I’m not assuming any heat exchange between the hot core and the oceans, just radiative balance for planet earth with incoming solar, so no temperature change for the whole system, just internal distribution of heat.”
Ben it is not only redistribution of heat. The oceans work like a heat pump. Incomming sun radiation by day of 800-1000 W/m2 and radiating 300-400 W/m2 in the night will not cool enough the oceans to freeze at the equator and tropics.
As I specified above the oceans are not warmed only at the surface to radiate the heat like solid rock but to the depth – much less escaping radiation.
The warmth accumulated this way will be redistributed to the north and south areas above where the sun insulation would be less.
At the extremes Nordpole and Southpole where the oceans freeze at the surface, they lose only minimal heat as water is almost as cold as ice and ice does not transmit heat. So ice above will be much cooler then the ocean and radiate very little and not really heat from the ocean.
This all functions like a heat pump as I explained above.
It is the oceans that drive the temperature of the atmosphere and not vice versa.
I further think that the radiation from “greenhouse” is wrongly computed as net radiation. This is Prevost heat exchange and should be substracted from earth or ground radiation causing a net heat transfer from ground to the atmosphere.
Only the sun can be computed as net heat transfer as the heat exchange from earth to sun through radiation can be ignored.
Here a nice example of solar versus greenhouse:
http://climaterealists.com/index.php?id=9004
The oceans are the heat pump. It is the water in the bath that heat the air and not the other way around.
>>>>kdk33 says: January 23, 2012 at 10:09 am
KDK, the warming of the atmosphere cannot be solely due to conduction and convection, and we know this because when it is cloudy overnight, even a thin layer of cloud can ‘warm’ the atmosphere by 10 – 15 oc. The cloud layer is acting like GHGs, and reraditing the LW back to the surface, reducing the heat-loss to space, making the surface warmer than it would be otherwise.
If clouds can do this, and we know they can, then so can GHGs, because we know that (like clouds), they can absob and reemit LW radiation.
We don’t notice the GHGs doing this, because they do it all the time. But the intermittent appearance of clouds and their huge effect on night temperatures proves that an ‘insulator’ (an absorber and reemitter) can reduce surface and atmospheric heat loss.
Note also that clouds can do this at a very low level. An ‘insulating’ cloud layer at just 1,500 ft can keep the surfsce much warmer, and so this is not simply a matter of increasing the emmision height in the atmosphere.
.
Hey Joules Verne (luv that name),
What is the proper constraint to apply to the near surface atmosphere. It isn’t isothermal. It isn’t isobaric. Is it at equilbirium? Is it isentropic? If so, how high into the atmosphere does the assumption hold.
Joules Verne says:
January 23, 2012 at 3:11 pm
Joules – Ok, but why is it that the denser atmosphere cannot provide an increased insulative ‘effect’ and thereby increased temperature? – by the action of simply having more material around at a given atmospheric depth, the kinetic energy is logically ‘more concentrated’ and ergo, the apparent temperature is higher? So, to my (admittedly) limited logic, in the gas phase, a denser gas has more kinetic energy than a lighter gas at the same volume. I don’t see from the N&Z theory that they are insisting on extra energy being introduced – just that, if you like, the energy thats around is more concentrated within the denser gas zone (and thus temps are higher).
tallbloke says:
January 23, 2012 at 12:43 pm
George E. Smith; says:
January 23, 2012 at 12:05 pm
There will be no permanent increase in the Temperature following a pressure increase; uinless that cooling is somehow prohibited…
My understanding of what N&Z are saying is way simpler than what most people seem to be assuming. It’s quite possible that I’m wrong and if so, please point out where I am.
The best I can come up with is a thought experiment regarding a wandering planet that is coated with a layer of frozen N2. The planet gets captured by a sun and assumes a stable circular orbit a fixed distance from the sun. Over time, the planet absorbs radiation from the sun, heats up, and eventually achieves thermal equilibrium. At some point in that process, the N2 becomes gaseous and an atmosphere forms. Conditions are such that none of this atmosphere escapes. Because of the ideal gas law (PV=nRT), a pressure P will develop and remain constant because the planet’s gravity is constant and n does not change. Using eighth grade algebra (third grade in the U.K.), we can show that the relationship between pressure, volume, and temperature will be
P = T / V
OK, now run the same scenario except this time the wandering planet has enough extra frozen nitrogen such that P will be exactly double the first scenario. This will be slightly more than 2n since the planet is spherical. The planet gets captured by the sun, etc. and achieves thermal equilibrium.
Now since we’ve doubled P, we can show the effect of the extra atmosphere compared to the first scenario by
2P = 2T / V
meaning that if the atmosphere expands to take up the exact same volume as in the first case, then the average temperature (K) will be twice as high. Arguably, the volume would be larger than V, but then T would have to be higher by the same factor, implying that this process is non-linear with respect to T vs P.
That’s my elevator version and it doesn’t involve compressing gas. Whether I’m representing N&Z or not, and if so whether they are right or not, is the question.
“-a gravity field cannot maintain an energy gradient at equilibrium”
You are conflating energy and temperature.
All molecules of a gas have energy so the more densely they are packed the more energy they carry per unit volume.
However one unit of volume can have the same temperature as another unit of volume containing less molecules.
Gravity therefore DOES maintain an energy gradient by causing more dense molecular packing at the base of a column.
It does not in itself maintain a temperature gradient as far as I know but some have been arguing that it might do that as well to a small degree.
The biggie is then what happens if an external energy source is played onto a column with greater density at the bottom.
Obviously it will generate more heat in the denser gases. There is 150 years of science to that effect and I cannot understand the intransigence here of those who really should know that to be true.
George E. Smith; says:
January 23, 2012 at 1:52 pm
“”””” tallbloke says:
January 23, 2012 at 12:43 pm
George E. Smith; says:
January 23, 2012 at 12:05 pm
yes I undertand how gravity creates a pressure gradient.
I also understand that it is generally colder, at higher altitudes, so there is also a Temperature gradient, neglecting for the moment the stratospheric regions, where the Temperature goes up again,
So of course we should have the exact same conditions in the earth’s oceans; perhaps our two PhDs, can apply their equations and integrals to the earth ocean to calculate how much hotter it is down at the bottom, compared to the surface Temperature.
George: Water is not compressible. Air is.
And then there were three independent papers drawing the same essential conclusion!
Larry
tallbloke
One might next ask what is different about CO2 from, say, nitrogen. How does CO2 raise the equibrium temperature where N2 cannot when everything else is equal.
CO2 in effect lowers the albedo of the surface (land-only). The ground soaks up shortwave energy from the sun, reemits it as longwave energy, CO2 absorbs a portion of the LW energy in it’s absorption band, and reflects about half of it back at the ground. In effect this forces the ground to absorb more energy which in turn raises its equilibrium temperature.
There’s a another big misconception floating around here as well in this regard. It’s not possible to attain a higher equilibrium temperature than the S-B temperature for an ideal blackbody. All greenhouse gases can do is raise surface temperature closer to ideal blackbody S-B temperature. There is no way to attain a higher temperature than can be obtained by a perfect absorber. The perfect absorber by definition is, well, perfect and will attain the highest possible temperature for the given energy input – anything less than perfect can only result in a lower temperature.
Joules, maybe you didn’t see my followup comment.
We are in violent agreement.
Peter, George, Willis, et al:
The integral is correct. The average is taken over the surface of a sphere. i.e. they are averaging over the solid angle 4pi, hence the reason they divide by 4pi outside the integral. What everyone is missing is that the integral is NOT being done in cartesian coordinates but in SPHERICAL coordinates. The integral is done as follows:
Set the z-axis of the system pointing towards the sun at the equator, thus their theta angle corresponds to the usual theta in the spherical corrdinate system. At a constant radius, the element of solid angle d(omega) is given by sin(theta)d(theta)d(phi), the integral we are thus calcuating is
INT cos(theta)^.25 sin(theta)d(thetad(phi) from zero to pi
mu = cos(theta) then d(mu) = -sin(theta) d(theta) subbing in gives:
INT mu^.25 (-d(mu)) d(phi) = – 2pi INT mu^.25 d(mu) = -2pi (4/5) mu^5/4 =
-2pi (4/5) cos(theta)^5/4 evaluated from zero to pi
The limit evaluation just gives a factor of -1 so the net result is 2pi (4/5)
Now divide by 4pi and you get exaclty their value of 2/5.
I’m surprised no other physicists has caught this before (rgb??) It’s standard physics from the junior year in college.
hotrod (larry L) says:
January 23, 2012 at 3:32 pm
“And then there were three independent papers drawing the same essential conclusion!”
Three wrongs don’t make a right but as PT Barnum said there’s a sucker born every minute. Lord only knows how many people contrived and believed in a carbuerator that would give their big block Chevy 100 miles per gallon fuel efficiency but the oil companies made sure none are for sale. Undoubtedly the next step for the junk science in the OP will be a claim that they can’t get it published in a reputable journal with a significant impact factor because of a similar conspiracy. Wait for it. In the meantime I’m sure it’s a great source of page views for blogs that dally and dance with crank science because they don’t have anyone on staff who can tell the wheat from the chaff so they print anything that looks remotely feasible to them.
Nature prints all the science that’s fit to print. Watt’s Up With That prints everything else.l Joel Shore sure got one thing right – taking this seriously makes all skeptics of the ridiculous CAGW narrative look bad. There’s a boatload of reasons why CAGW boffins are nutters but them not acknowledging crank science that violates the most basic principles of thermodynamics is not one of those things.
Lars P. says:
January 23, 2012 at 1:01 pm
Hi Lars, seems nobody wants to see this elephant, I called it a 600 pound gorilla on another blog.
See: http://wattsupwiththat.com/2012/01/22/unified-theory-of-climate-reply-to-comments/#comment-873088
I think that the oceans make the use of any blackbody approach to the temperature on waterplanet earth nonsense. Still it is the basic premise in the theory we are discussing, which starts with:
“We start with the undisputable fact that the atmosphere provides extra warmth to the surface of Earth compared to an airless environment such as on the Moon.” The temp of the moon is arrived at by using a blackbody approach.
The only thing the sun is heating directly is the ocean layer above the thermocline, just ~200m in the tropics, reducing to 0m around the polar circles, depending on the seasons.
This is a direct GHE killer since the GHE is supposed to explain the difference between the blackbody 255K temp and our 288K.
If this reasoning is totally wrong, let somebody at least explain why, but I would be amazed.
>>>Kev-in-UK says: January 23, 2012 at 3:23 pm
>> – Ok, but why is it that the denser atmosphere cannot provide
>>an increased insulative ‘effect’ and thereby increased temperature? … ,
>> in the gas phase, a denser gas has more kinetic energy than a lighter
>>gas at the same volume. … the energy thats around is more concentrated
>>within the denser gas zone (and thus temps are higher).
Because without warming, such an atmosphere would continue to cool until you are left with puddles of liquid oxygen and nitrogen (and thus no adiabatic lapse rate whatsoever). (Depensing on the strength of the insolation and the rate of rotation of the planet.)
To maintain its depth and pressure gradien an atmosphere needs energy, and you can only get that through surface conduction and LW absorption. Does the latter happen, as well as the former? Yes, of course it does, and we know this because a thin cloud layer can ‘insulate’ (absorb and reemit) the surface and lower atmosphere for some considerable time.
.
jjthoms,
Thanks for your response…very helpful. Perhaps they only want to talk about airless planetoids, but for a “Unifed” Theory of Climate, for them to restrict it to bodies which have no climate, seems a bit…odd…and not much to “unify”.
Seems a basic question to them: Downwelling LW from clouds at night…measured all over the world…without the need for atmospheric pressure theory. Basic greenhouse gas physics works quite well, so WUWT?
tallbloke says:
January 23, 2012 at 3:35 pm
“Joules, maybe you didn’t see my followup comment. We are in violent agreement.”
My apologies. I had a hard time believing we were somehow not in agreement in the first place because as far as I know this would be first time in the couple of years since I first saw your writing I’d ever read anything you wrote without nodding my head and thinking “Hallelujah, at least one person has a clear understanding of the big picture”. I still think the most pithy comment I’ve seen is yours: “In the big picture the sun heats the ocean and the ocean heats the atmosphere”. If more people would start from that big picture and work backwards filling in the details there would be a lot less misunderstanding of what drives the climate. Climate boffins do it ass backwards starting from the rarefied gases in the top of the atmosphere and working down to the surface from there and the ocean then becomes a detail instead of the biggest single factor other than the sun.
paulhan says:
January 23, 2012 at 3:03 pm
I’d have a lot more respect for Mr Nikolov and his theory if he would stop with the insults
Heh. Where have you been for the last fortnight?
Joules: “Here’s the bottom line, first principle from which you must start to understand this.
-a gravity field cannot maintain an energy gradient at equilibrium”
But it can and does maintain a temperature gradient at equilibrium. The potential energy contained by a quantity of gas is not measured as a part of temperature – only the kinetic energy is. So how does the potential energy have any relevance in a discussion of temperature versus pressure?
A few here seem to have a problem with how to perform this spherical integration… this may help.
To be brief, look up at the top-posted article for any parameters you may not understand.
A spherical integration of the per-point average temperature field:
T.gb = ¼π ∫[0,2π] ∫[0,1] T.i dμ dφ
or even clearer:
T.gb = ½ * ½π ∫[0,2π] ∫[0,1] T.i dμ dφ
As for μ = cos(θ.i), this will only need to be evaluated at two locations, 0 & π/2; first is when the sun is directly above and the second at the 360° terminator that is 90° from the first. So the ultimate results of these two evaluations are cos(0)=1 & cos(π/2)=0.
T.gb = ½ * ½π * ∫[0,2π] ∫[0,1] root4( S.0 (1-α.0) μ / (εσ) ) dμ dφ
T.gb = ½ * ½π * root4(S.0(1-α.0)/(εσ)) ∫[0,2π] ∫[0,1] μ^(1/4) dμ dφ
First integrate ∫ [0,1] μ^(1/4) dμ:
= 4/5 * ( cos(0)^(5/4) – cos(π/2)^(5/4) )
= 4/5 * ( 1^(5/4) – 0^(5/4) )
= 4/5 * 1^(5/4)
= 4/5
Giving:
T.gb = 4/5 * ½ * ½π * root4(S.0(1-α.0)/(εσ)) ∫[0,2π] 1 dφ
T.gb = 4/5 * ½ * ½π * root4(S.0(1-α.0)/(εσ)) ∫[0,2π] dφ
Next integrate ∫[0,2π] 1 dφ
2π*1 – 0*1
2π
T.gb = 2π * 4/5 * ½ * ½π root4(S.0(1-α.0)/(εσ)) * 1
Simplifying:
T.gb = 8π/20π root4(S.0(1-α.0)/(εσ))
T.gb = 2/5 root4(S.0(1-α.0)/(εσ))
or
T.gb = 2/5 (S.0(1-α.0)/(εσ))^0.25
If any one out there disagrees with this derivation, lay out yours step-by-step and most here would like to see your expertise.
I have also personally numerically integrated this using two separate geometries, one as stated above and the other by a front facing latitude band view… both verify the above math … in Earth’s case 154.7 K. I also further extended this numeric integration to address other configurations that Dr. Brown raised in a prior article here at WUWT. Those too have also been double-checked and all appear correct.
Some here, including Anthony have asserted that N&Z must be wrong because their hypothesis surmounts conservation of energy. However, that may be through a misunderstanding of what N&Z have theorised. Tallbloke, has elaborated on that potential misunderstanding here:
http://wattsupwiththat.com/2012/01/22/unified-theory-of-climate-reply-to-comments/#comment-873608
Another way of looking at it is that the consensus community is quite happy to accept that under the GHE, (including any feedbacks), it is currently argued that there is ~150 W/m^2 more energy at the surface than leaves at TOA. So, is this extra energy, offending conservation of energy? Clearly, it cannot be. Somewhat similarly, N&Z are proposing that the surface of a planet will be warmer with an atmosphere, than with an airless one, by virtue of a different mechanism. They are not claiming that the air pressure creates energy, but that the pressure enhances the uptake of the energy source near the surface. These two physics PhDs have probably heard about conservation of energy maybe?
Maybe the critics here are putting the cart before the horse without understanding the hypothesis?
REPLY: Read Willis latest on the front page of WUWT about equation 8 – Anthony
Stephen Wilde says:
January 23, 2012 at 3:30 pm
“-a gravity field cannot maintain an energy gradient at equilibrium”
“You are conflating energy and temperature.”
Absolutely not. Temperature is a measure of kinetic energy. There are other forms of energy. You are conflating temperature with all forms of energy.
“All molecules of a gas have energy so the more densely they are packed the more energy they carry per unit volume.”
All molecules of gas have mass and in a gravity well have potential energy such that when they move outboud they lose kinetic energy and gain gravitational potential energy and when the move inbound they lose gravitational potential energy and gain kinetic energy. That’s how a motionless rock dropped from a 10th floor window gains a lot of kinetic energy by the time it lands and hopefully it lands on a crank scientist’s head and knocks some sense into them so the energy isn’t wasted. Molecules of air are like little bitty rocks. Gravity sorts them out into a pile where the lowest ones have a lot of kinetic energy and the highest ones have a lot of potential energy – just like a rock. Capicse?
“”””” tallbloke says:
January 23, 2012 at 3:30 pm
George E. Smith; says:
January 23, 2012 at 1:52 pm
“”””” tallbloke says:
January 23, 2012 at 12:43 pm
George E. Smith; says:
January 23, 2012 at 12:05 pm
yes I undertand how gravity creates a pressure gradient.
I also understand that it is generally colder, at higher altitudes, so there is also a Temperature gradient, neglecting for the moment the stratospheric regions, where the Temperature goes up again,
So of course we should have the exact same conditions in the earth’s oceans; perhaps our two PhDs, can apply their equations and integrals to the earth ocean to calculate how much hotter it is down at the bottom, compared to the surface Temperature.
George: Water is not compressible. Air is. “””””
Gee ! I’ll have to check my Timoshenko, and get back to you on that. I thought that everything; even Neutron Stars are compressible; they squish down to black holes, if you squeeze hard enough.
That’s two things I’ve learned here at WUWT. Gases can’t emit thermal radiation; but they are the only things you can squeeze; simply amazing !
@Stephen Fisher Wilde
“It does not in itself maintain a temperature gradient as far as I know but some have been arguing that it might do that as well to a small degree.”
You still don’t get it. Gravity maintains TWO energy gradients. One kinetic and one potential. The kinetic gradient decreases with altitude and the potential gradient increases with altitude. The two opposing gradients cancel out and the column is isogenergetic. This is how you can have a perpetual temperature gradient yet not be able to extract any work from it for a perpetual motion machine – a temperature gradient can be nullified by an equal but opposite gradient of energy in a different form. You can’t connect the cold and hot sides of the atmosphere without climbing up in a gravity well and the useful energy represented by the change in temperature is exactly used up by the energy required to climb uphill against gravity. The books thus balance and conservation of energy is once again safe from the abuses of junk science.
scf says:
theta (or mu) and phi are independent variables. Come on guys…Nikolov and Zeller have made huge conceptual errors that render their conclusions completely incorrect, but let’s not bludgeon them about the things that they have done right. It just gives them the opportunity to show that you are wrong and thus to avoid discussing the fatal errors in their theory. You are playing into their hands.