Visualizing the "Greenhouse Effect" – A Physical Analogy

File:RHSGlasshouse.JPG
Image from Wikipedia - The "greenhouse effect" is named by analogy to greenhouses. The greenhouse effect and a real greenhouse are similar in that they both limit the rate of thermal energy flowing out of the system, but the mechanisms by which heat is retained are different. A greenhouse works primarily by preventing absorbed heat from leaving the structure through convection, i.e. sensible heat transport. The greenhouse effect heats the earth because greenhouse gases absorb outgoing radiative energy and re-emit some of it back towards earth.

Guest post by Ira Glickstein

Albert Einstein was a great theoretical physicist, with all the requisite mathematical tools. However, he rejected purely mathematical abstraction and resorted to physical analogy for his most basic insights. For example, he imagined a man in a closed elevator being transported to space far from any external mass and then subjected to accelerating speeds. That man could not tell the difference between gravity on Earth and acceleration in space, thus, concluded Einstein, gravity and acceleration are equivalent, which is the cornerstone of his theory of relativity. Einstein never fully bought into the mainstream interpretation of quantum mechanics that he and others have called quantum weirdness and spooky action at a distance.

So, if some Watts Up With That? readers have trouble accepting the atmospheric “greenhouse” effect because of the lack of a good physical analogy, you are in fine company.

For example, in the discussion following Willis Eschenbach’s excellent People Living in Glass Planets, a commenter “PJP”, challenged the atmospheric “greenhouse” effect:

“The incoming energy (from the sun) you express in w/m^2, lets simplify it even more and say that energy is delivered in truckloads. Lets say we get 2 truckloads per hour. … when we come to your semi-transparent shell [representing greenhouse gases (GHG) in the atmosphere], you are still getting two truckloads per hour, but you say that these two truckloads are delivered to both the earth and to the shell — that makes 4 truckloads/hr. Where did the extra two truckloads come from?”

In that thread, I posted a comment with an analogy of truckloads of orange juice, representing short-wave radiation from Sun to Earth, and truckloads of blueberry juice, representing longwave radiation between Earth and the Atmosphere and back out to Space. A later commenter, “davidmhoffer” said “Ira, That was a brilliant explanation. …”

This Post is a further elaboration of my physical analogy, using a pitching machine and yellow and purple balls in place of the truckfulls of juice.

Graphic 1 shows the initial conditions. The Sun is a ball pitching machine that, when we turn it on, will throw a steady stream of yellow balls towards the tray of a weight scale, which represents the Earth. The reading on the scale is analogized to “temperature” and, with the Sun turned off, reads “0” arbitrary units.

TURN ON THE “SUN”

Graphic 2 shows what happens when the Sun is turned on and there are no GHG in the Atmosphere. The stream of yellow balls impact the tray atop the weight scale and compress the springs within the well-damped scale until equilibrium is reached. The scale reads “1”. This is analogous to the temperature the Earth would reach in the absence of GHG.

The balls bounce off the tray and, for illustrative purposes, turn purple in color. This is my way of showing that Sun radiative energy is mostly in the “shortwave” visible and near-visible region (about 0.3μ to 1μ) and that radiative energy from the warmed Earth is mostly in the “longwave” infrared region (about 6μ to 20μ). The Greek letter “μ” (mu) stands for a unit of length called the “micron” which is a millionth of a meter.

Since, at this stage of my physical analogy, there are no GHG in the Atmosphere, the purple balls go off into Space where they are not heard from again. You can assume the balls simply “bounce” off like reflected light in a mirror, but, in the actual case, the energy in the visible and near-visible light from the Sun is absorbed and warms the Earth and then the Earth emits infrared radiation out towards Space. Although “bounce” is different from “absorb and re-emit” the net effect is the same in terms of energy transfer.

If we assume the balls and traytop are perfectly elastic, and if the well-damped scale does not move once the springs are compressed and equilibrium is reached, there is no work done to the weight scale. Therefore, Energy IN = Energy OUT. The purple balls going out to Space have the same amount of energy as the yellow balls that impacted the Earth.

ADD GHG TO THE “ATMOSPHERE”

Graphic 3 shows what happens when we introduce GHG into the Atmosphere. The yellow balls, representing shortwave radiation from the Sun to which GHG are transparent, whiz right through and impact the weight scale and push it down as before.

However, the purple balls, representing longwave radiation from the Earth, are intercepted by the Atmosphere. In my simplified physical analogy, the Atmosphere splits each purple ball in two, re-emiting one half-ball back towards the Earth and the other half-ball out to Space. Again, you can assume that half of the balls “bounce” off the Atmosphere back to Earth like reflected light from a half-silvered mirror and the other half pass through out towards Space. In the actual case, it is “absorb and re-emit half in each direction” but the net effect is the same in terms of energy transfer.

OK, here is the part where you should pay close attention. The purple half-balls that are re-emitted by the Atmosphere towards Earth impact the tray of the weight scale and press against the springs with about half the force of the original yellow balls. So, at this stage, when equilibrium is reached, the well-damped scale reads “1.5” arbitrary units.

But, we are not done yet. The purple half-balls are absorbed by the Earth, and re-emitted towards Space. Then they are re-absorbed by the Atmosphere and once again split into quarter-balls, half of which head back down to Earth and re-impact the weight scale. Now it reads “1.75”. As you can see, the purple balls continue to get split into ever smaller balls as they bounce back and forth and half head out to Space. The net effect on the weight scale is the sum of 1 (from the yellow balls) + 1/2 + 1/4 + 1/8 + 1/16 and so on (from the purple balls). That expression has a limit of “2”, which is approximately what the scale will read when equilibrium is reached.

Again, the well-damped scale does not move once the springs are compressed and equilibrium is reached, so there is no work done to the weight scale. Therefore, Energy IN = Energy OUT. The purple balls going out to Space have the same amount of energy as the yellow balls that impacted the Earth. But the “temperature” of the Earth, as analogized by the reading on the weight scale, has increased.

DOUBLE THE GHG IN THE “ATMOSPHERE”

Graphic 4 is the final step in my physical analogy. Let us double the GHG in the Atmosphere. (NOTE: I am assuming that the doubling includes ALL the GHG, most especially water vapor, and not simply CO2!) This is represented by putting a second layer of Atmosphere into the physical analogy.

The purple balls emitted towards Space by the first layer of the Atmosphere are intercepted by the second layer, where they are absorbed, and smaller balls are re-emited in each direction. The downward heading balls from the upper atmosphere are intercepted by the lower Atmosphere and half is re-emitted down towards the weight scale that represents Earth. Once again, they compress the springs in the weight scale increasing the reading a bit, and are re-emitted back up. The purple balls get halved and bounce around up and down between Earth and the two layers of the Atmosphere, further increasing the reading on the scale once equilibrium is reached.

Again, the well-damped scale does not move once the springs are compressed and equilibrium is reached, so there is no work done to the weight scale. Therefore, Energy IN = Energy OUT. The purple balls going out to Space have the same amount of energy as the yellow balls that impacted the Earth. But the “temperature” of the Earth, as analogized by the reading on the weight scale, has increased due to the doubling of GHG in the Atmosphere.

WHAT I LEFT OUT OF THE PHYSICAL ANALOGY

Any simplified analogy is, by its very nature, much less than the very complex situation it is meant to analogize. Here is some of what is left out:

  1. My purple balls are re-emitted in only two directions, either up or down. In the real world, longwave radiation is emitted in all directions, including sideways.
  2. My purple balls are all totally absorbed by the Atmosphere and re-emitted. In the real-world, a substantial amount of longwave radiation is re-emitted from the Earth and the Atmosphere in the 9μ to 12μ band where the Atmosphere is nearly-transparent. A substantial portion of the radiation from Earth and the Atmosphere thus passes through the Atmosphere to Space without interception.
  3. My physical analogy addresses only radiative energy transfer. In the real-world, energy transfer from the Sun to Earth and Earth to Space is purely radiative. However, the Earth transfers a considerable amount of energy to the Atmosphere via convection and conduction, in the form of winds, precipitation, thunderstorms, etc. These effects are absent from my analogy.
  4. I represent the Atmosphere as a single shell, when, in fact, it has many layers with lots of interaction between layers.
  5. I represent doubling of GHG as adding another shell, when, in fact, doubling of GHG, if it occured (and if it included not just CO2 but also a doubling of water vapor and other GHG) would increase the density of those gases in the Atmosphere and not necessarily increase its height significantly.
  6. In my analogy, all the energy from the Sun strikes and is absorbed by the Earth. In the real-world, up to a third of it is reflected back to Space from light-colored surfaces (albedo) such as snow, ice, clouds, and the white roof of Energy Secretary Chu’s home :^). If a moderately warmer Earth, due to increased GHG, evaporates more water vapor into the atmosphere, and if that causes more clouds to form, that could increase the Earth’s albedo to counteract a substantial portion of the additional warming.

I am sure WUWT readers will find other issues with my physical analogy. However, the point of this posting is to convince those WUWT readers, who, like Einstein, need a physical analogy before they will accept any mathematical abstraction, that the atmospheric “greenhouse” effect is indeed real, even though estimates of climate sensitivity to doubling of CO2 are most likely way over-estimated by the official climate Team. When I was an Electrical Engineering undergrad, I earned a well-deserved “D” in Fields and Waves because I could not create a physical analogy in my overly-anal mind of Maxwell’s equations or picture the “curl” or any of the other esoteric stuff in that course. Therefore, those WUWT readers who need a physical analogy are in great company – Einstein and Glickstein :^).

I plan to make additional postings in this series, addressing some implications of the 9μ to 12μ portion of the longwave radiation band where the Atmosphere is nearly-transparent, as well as other atmospheric “greenhouse” issues. I look forward to your comments!

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Stephan
February 20, 2011 8:02 pm
Brian H
February 20, 2011 8:08 pm

Eric;
Hmmm … 2 empty greenhouses (no plants), one with atmospheric atmosphere, the other with, say 2,000ppm CO2 atmosphere. Insert thermometers, check periodically.

KR
February 20, 2011 8:10 pm

Ira I sympathize about “curl”. I remember when electromagnetic influences were introduced in physics with the ‘right-hand rule’; one of my classmates said quite loudly that “This doesn’t make sense!”. I looked at him, saw the thumb, index, and middle finger of his left hand extended, and gently corrected him…

Ableken
February 20, 2011 8:22 pm

Could you tell me what happens to the momentum of your purple balls that are re-directed towards earth. If one uses kinetic theory as an analogy, there is a momentum change of 2 units in this reversal of direction, and the net momentum of the system has increased by one unit (due to the recoil experienced by the emitting molecule). In kinetic theory this momentum change exerts a pressure on the walls of the container. Do CO2 molecules experience a pressure acting away from earth when they absorb a purple ball (or photon) moving away from earth and then re-direct it towards earth?

Master of Obvious
February 20, 2011 8:22 pm

Shouldn’t we be able to observe the “darkening” of Earth in the IR spectrum from a satellite looking down? If the reflection into space is turned into heat on Earth, then there must be lower observed IR from space. Thus in addition to direct temperature observations, we should have direct IR observations which would correlate. Unless the phenomenon does not really exist — my bet.

AJB
February 20, 2011 8:23 pm

DocMartyn says February 20, 2011 at 5:13 pm

Why are not pairs of … glass panes in houses filled with CO2?

We have smart glass coatings using the same principle that are far more effective. A better question is why do we keep water out.

commieBob
February 20, 2011 8:29 pm

Ken Coffman says:
February 20, 2011 at 5:15 pm
…. Cold rarefied gases measurably increase the earth’s surface temperature? No, sorry, I don’t buy it.

Those cold gases are a lot warmer than absolute zero which is the temperature of outer space.
Imagine, if you will, a layer of solid insulation on the outside of your house. The inner side of the insulation will be at the temperature of your living room. The outer side of the insulation will be at the outside temperature. The temperature within the insulation will be according to how close to the outside you measure. The closer you are to the outside, the colder it will be.
Nine tenths of the way through the insulation, it will be nearly as cold as it is outside. So, my question to you is: how is it that this very cold insulation manages to measurably increase the temperature in your living room?
(In this argument, you have to assume that your furnace is operating with a constant output rather than being controlled by the thermostat. Actually, the insulation merely decreases your fuel consumption.)

Physics Major
February 20, 2011 8:33 pm

Dr Glickstein,
You seem to be equating energy to temperature. You are weighing all those balls of energy and getting a temperature reading. I give this analogy an F.

Andrew30
February 20, 2011 8:34 pm

This is deceptive labeling and presentation.
It should be “ANALOGOUS TO [DAYTIME] SURFACE TEMPERATURE INCREASE CAUSED BY CO2”
For example, in keeping with the simplisic presentation:
Normal summer high temp in LA with no layer = 299 Kelvin + 0 CO2 degree (80 degrees Fahrenheit)
With 1 CO2 Layer:
Normal summer high temp in LA with one layer = 299 Kelvin + 1 CO2 degree (81.8 degrees Fahrenheit)
With 2 CO2 Layers
Normal summer high temp in LA with one layer = 299 Kelvin + 1.5 CO2 degrees (82.7 degrees Fahrenheit)
This would help the people that can actually tell the difference between 80 and 82.7 degrees while they are outside, during the day.
Deceptive graphic. Easy to [miss] understand. Pseudo-Science for the masses.

John F. Hultquist
February 20, 2011 8:40 pm

Eric #49
. . . is anyone putting CO2 in greenhouses to make them warmer?
See Ira’s comment at #45 with respect to the logarithmic effect. At the amounts used, say 800 to 1,000 you will get about all the warming there is to get. Even then the air as to be put in motion (small fan) or the heavier than oxygen CO2 will settle. A person could kneel down to clean up a mess on the floor and the air might not have enough O2. Bummer.

Gary Hladik
February 20, 2011 8:40 pm

Very good article by Dr. Glickstein, within the stated limitations.
My favorite simplification of the so-called greenhouse efffect is still Willis Eschenbach’s “Steel Greenhouse” article from November 2009:
http://wattsupwiththat.com/2009/11/17/the-steel-greenhouse/

February 20, 2011 8:47 pm

You have made a graphical model of the so called Greenhouse Effect but is it a faithful model of the actual atmosphere with real world physics at work?
When you are discussing the real world, you don’t start from an arbitrary theory and dictate to the real world how it works. You start with the real world and DISCOVER how it works. The real world is what it is and it does not pay the slightest attention to what you think it is no matter what your credentials, the number of papers you have published, nor how many scientific societies you belong to.
I suggest you need to study the science of Thermodynamics in some significant detail before you create any more pretty pictures. That way you might have a chance of saying something worth listening to. As it is, any one of Aesop’s Fables is far more instructive about the real world than your presentation on this blog.

John F. Hultquist
February 20, 2011 8:50 pm

For awhile there I had numbered comments. A flaky system tonight. I tried to send the following and it blew Google Chrome off the desktop.
So, I’ll try again:
At 8:40 pm: That’s “the air has to be. . ”
Ira,
Drop the degree symbol on the kelvins, please.

Jim Macdonald
February 20, 2011 8:50 pm

Since IR radiation is a finite amount equal to the short wave energy reaching the earth, how much CO2 does it take to absorb/intercept/deplete all the IR in the narrow bands representing 15-20% of the spectrum. It’s like a greenhouse with 80% of the glass missing. Most non-scientists are misled by the impression (not corrected by the pro-wraming crowd) that CO2 acts in a linear fashion, with each additional amount (ppm) causing a commensurate amount of warming.
One may dispute the exact amount, but due to the efficiency of CO2 in absorbing IR radiation, and using Beer’s law, Professor James Barrante and others have calculated that half the available IR is absorbed by as little as 80 ppm. After that less and less IR is available as it is depleted logarithmically by additional CO2, until most all is gone by the time CO2 reaches 250-300 ppm. Little more warming can occur.
So, how can it be said, without decieving people, that ever increasing CO2 will cause more and more warming?

Graeme
February 20, 2011 8:54 pm

I hate to appear dumb but I don’t follow this.
The sun heats the earth – OK (warms). The earth then loses heat – (cools by radiation).
The CO2 (and water vapour etc.) gains heat and but can’t store it (except by transfer to O2 & N2 which are poor radiators) so must radiate.
But a colder surface can’t radiate to a hotter surface, so the earth and the CO2 have to be equal in temperature, so the minor difference (a purple ball) can bounce back and forth between them. If the earth warms, then there is no balance, so the atmosphere can’t radiate back to it, so the extra heat radiated from the earth and absorbed by the greenhouse gases must go elsewhere (e.g. convection) until such time as the atmosphere warms up to the new temperature.
But in this scheme the earth isn’t warmer because it emits everything it absorbs. And at the end of the day you’ve put 100 units of heat into the earth and a 100 units have left the earth. If the heat absorbed is boosted by your purple ball series, so too is the amount of heat radiated into space.
It seems to me that these radiative models are merely counting the same heat twice.
You might say that “extra” heat is stored in the atmosphere because it hasn’t radiated out yet, and may warm the earth slightly at night. But the heat capacity of the atmosphere is so much less than that of the earth, that any warming must be minimal before it all radiates out to space.

Charles Higley
February 20, 2011 9:10 pm

Three important things missing here.
1) The purple ball shield is full of holes as CO2 can only absorb over a couple of narrow IR ranges. Thus, the efficiency falls drastically. The big argument would be how much this would impact the balance. In reality, its very small and likely undetectable in the changes we are seeing in CO2.
2) Beer’s Law is not addressed as the effect of warming plateaus as CO2 increases. It’s effect is 90-95% expended.
3) “doubling of GHG, if it occured ( . . . ) would increase the density of those gases in the Atmosphere and not necessarily increase its height significantly”
Zagoni and Miskolczi have shown quite elegantly that, as CO2 rises, absolute water in the upper troposphere decreases (already observed in real measurements). You cannot just add density to the atmosphere, something has to give. Here, it is water vapor that is replaced by an inferior heat-trapping gas, creating an atmosphere with less “greenhouse” effect. A tiny bit of cooling is in order.

Jim Cook
February 20, 2011 9:11 pm

I think you skipped over 2 major steps even in your simplified version. The first being that your initial premise does not start as a black body condition, the second add you add atmospheric variations your failing to absorb your initial source. This would be a reduction (in your simplified diagram) to .7 difference from initial non atmospheric to atmospheric variations.
In other words, its not a one way mirror.

February 20, 2011 9:13 pm

Leonard Weinstein says:
February 20, 2011 at 7:11 pm
does more CO2 increase the atmospheric greenhouse effect? The answer is yes, it slightly raises the location of outgoing radiation to space…. The main question is how much, and this is not clear. My best guess based on historical and recent data supports a raise of between 0.1 and o.5 C per doubling of CO2, with cloud negative feedback being a major controlling factor. This is much smaller than the CAGW estimates.>>>
Leonard, your numbers may be closer than you think to the CAGW estimates. Buried in the fine print if IPCC AR4 is a note explaining that the temperature increases they arrive at from their models are calculated at the EFFECTIVE black body temperature of earth, NOT the surface temperature. They use (if I recall correctly) -20 C as the effective black body temperature rather that the +15 C usually quoted as the average surface temperature.
So… apply Stefan-Boltzman to the whole mess. They calculate doubling of CO2 = 3.7 w/m2 = +1 degree. But that’s at -20 C. Since the SB Law is that
Power in watts = constant times temperature in degrees Kelvin raised to the power of four
or
P=(5.76*10^-8)*T^4
One can then extrapolate their calculation to the surface temperature. Too tired to do math at the moment, but you get a lot smaller number at surface than you do at effective black body using the IPCC’s own science! .6 or around there.
Further, the use of 15 C as an average is VERY deceptive. If the night time low in a given area is 10 C, and the day time high is 20 C, does that mean that the average temperature of the day was 15 C? HIGHLY unlikely. But if by some miracle it was, you STILL can’t assign a temperature increase from CO2 that is meaningful. Back to Stefan-Boltzman again! The temperature increase from an additional 3.7 w/m2 will be smaller for the day time high than for the night time low. And summers don’t get much warmer, but winter lows become milder. And valleys dont get much warmer but the mountain tops next to them warm a bit more. And the poles warm more than the temperate zones and the tropics warm hardly at all.
If you break down NASA/GISS or HadCrut by latitude and season, you’ll see exactly what Stefan-Boltzman says.
As for the IPCC and doubling CO2 = +1 degree? Absolutely correct. And totaly meaningless.

Fred Souder
February 20, 2011 9:14 pm

Ira,
You should include the diminishing returns from each doubling in your analogy. This is an absolutely critical aspect of the greenhouse effect that is overlooked by the general population. Somehow it also seems to be overlooked by some climatologists (sigh). Maybe have the scale go from 1 to 1.5. Then to 1.75, then to 1.875, etc. Also it would be good to show how close to 100% absorption we are at.
Oh, one more detail that is also overlooked. The CO2 cannot radiate heat back toward the earth if the Earth’s temperature is warmer than the gas. It can only radiate heat in a direction that is colder (see Laws of Thermodynamics).

timheyes
February 20, 2011 9:16 pm

Kinda O/T. Snip of you must.
I’ve heard the elevator acceleration/gravity example given before but disagree with it due to remembering something from school. My teacher gave the example of a elevator in free fall (accelerating under gravity) towards the Earth. If you had 2 oranges which you placed a certain distance apart in falling with you in the elevator, they would move towards each other the closer to the planet you got due to tidal forces. (The oranges are drawn towards the gravitation centrepoint of the Earth and therefore if they could fall right to this centrepoint they would eventually touch each other). This is not true of a constantly accelerating elevator in free space.

February 20, 2011 9:18 pm

“dt3 says:
February 20, 2011 at 7:03 pm
According to the law of “Conservation of Momentum” your analogy is wrong!
After the initial absorption by the CO2 of the longwave radiation from the earth, most of the re-emitted longwave radiation should be emitted upward into space.”
The momentum of a 15 micron wavelength radiation is 4.4 x 10^-29 kgm/s using p = hf/c. So it would change the speed of a CO2 molecule by 6 x 10^-4 m/s. This is totally negligible compared to the average speed of about 400 m/s for a CO2 molecule. Molecules go in all directions, but if the upward component increases by 6 x 10^-4 m/s, there is no reason why radiation cannot then be emitted in any direction without violating the law of Conservation of Momentum. To really change the speed of something via a photon, you would need something light like an electron. (See the Compton effect.)

J. Felton
February 20, 2011 9:22 pm

Ira, thank you for an excellent and clear analogy that anyone could follow.
Etudiant said
“First, the predominant greenhouse gas is water vapor, with CO2 a bit player. So the focus on CO2 seems questionable, even recognizing that CO2 does not freeze out like water vapor.
Second, the effect of successive doublings of any GHG declines to an asymptote, maxing out with a completely closed spectrum at the absorbed frequencies.
Third, the earth has a very dynamic and turbulent atmosphere, whose dissipative mechanisms are not well categorized.
These factors make it challenging to estimate the impact of increases in GHGs.”
This is another excellent point.
There is just too many uncertainties ( I even quoted the IPCC just now 🙂 ) to be able to accurately estimate the amount of rising tempature due to GHG’s.
Myself and a friend of mine, (myself, a skeptic, and him, an believer in AGW) were having a conversation about this. I told him I didn’t believe that the small amount of CO2 in GHG’s, ( compared to Water Vapour, which has been estimated to be around 90% of GHG’s), could have such a high effect as the IPCC and others claim.
He responded by reminding me that a cold virus is a tiny organism, yet still able to do large damage to anyone who catches it, and similarly, CO2 works the same way.
I then argued if that analogy was completely accurate, then every single person ever exposed to the virus would catch it immediately, and experience the exact same amount of symptoms, hangtime of the cold, and so on. Yet it isnt. Some of us get sick, some dont. Some are healthier then others, some get sick from one cough nearby, and some seem to be as fit as a fiddle.
The fact is, there are just so many variables and uncertainties that we cant accurately admit that we know exactly how AGW works. Even the IPCC admits there is much they dont know.
Yet trillions of dollars are being allocated and millions of policy decisions are being made on it.
This is what I debate. My friend, in fact, did not have an answer.
P.S. I apologize if my description is overtly simplistic, physics were never my strong point. Feel free to point out any I may have made. 🙂