When (a+b)^5 is expanded using the Binominal Theroem for certain values of a and b, the second term is 15, and the third term is 60. Find the first term

1

1 1

1 2 1

1 3 3 1

1 4 6 4 1

1 5 10 10 5 1

(a+b)^5 = a^5 + 5a^4b + 10a^3b^2 + 10a^2b^3 + 5ab^4 + b^5

5a^4b = 15

10a^3b^2 = 60

Can you take it from here?

=^._.^=